The initial speed of the car with a length of the skid mark of about 64 m long and kinetic friction of 0.70 is 29.63 m/s.
A force that acts between moving surfaces is referred to as kinetic or sliding friction. It is the frictional force that prevents relative motion between surfaces in contact. The formula to calculate this kind of friction is, [tex]f _k =\mu_kN[/tex] where uk is the coefficient of friction and N is the normal force.
Given the length of the skid mark (Δd) is 64 m and the coefficient of kinetic friction is 0.70. The final velocity vf is 0 because the car stops.
Let us assume the initial velocity vi, mass m, and deceleration a. Then, the normal force acting on the car is N = mg. The kinetic friction will be,
[tex]f _k =\mu_kN\\f_k=\mu_kmg[/tex]
Let's assume the only force acting on the system is kinetic friction, then friction force=ma. Solve this equation with the above equation,
[tex]\begin{aligned}ma&=\mu_kmg\\a&=\mu_kg\end{aligned}[/tex]
Then, the initial speed is calculated as follows
[tex]\begin{aligned}v_f^2&=v_i^2-2a\Delta d\\0&=v_i^2-2\mu_kg\Delta d\\v_i^2&=\mathrm{2\times0.70\times9.80\;m/s^2\times64\;m}\\v_i^2&=\mathrm{878.08\;m^2/s^2}\\v_i&=\mathrm{29.63\;m/s}\end{aligned}[/tex]
The answer is 29.63 m/s.
The complete question is -
Police investigators, examining the scene of an accident involving two cars, measured 64 m long skid marks on one of the cars, which nearly came to a stop before colliding. The coefficient of kinetic friction between rubber and the pavement is about 0.70. Estimate the initial speed of that car, assuming a level road.
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you hang a 65.0 kg mass from an ideal spring having negligible mass. the mass stretches the spring 0.180 m. the mass is now pulled down 0.050 m and released. the period of oscillation of the mass is
The force constant of the spring is 3.53 * 10^3 N/m, the period of oscillation of the fish is 0.115 s and the maximum speed it will reach is 0.869 m/s
Hook's law states that:
where F is the force applied on the spring, k is the spring constant, x is the stretching of the spring.
In this problem, we have
Solving the equation for k, we find the spring constant: k = 3539 N/m
The period of oscillation of a spring-mass system is
T= 2π√M/K
In this case,
m = 65.0 kg
T=2π√(65/3539) = 0.869s
k = 3539 N/m
Substituting into the formula, the period of oscillation of the mass is 0.869 sec.
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write a statement about the relationship between the diameter of a pipe and the speed of the fluid flowing through it.
Through the equation of Continuity, The diameter of the pipe and the speed of the fluid are inversely proportional to each other.
According to the equation of Continuity,
Area multiplied by velocity results in a constant., A*v = Constant
Thus, the Area or diameter is inversely proportional to the speed or flow of the fluid.
The cross-sectional area of the pipe has an inverse relationship with flow velocity at any given flow rate.
Higher flow rates result from smaller pipes; slower speeds result from larger pipes. According to the continuity equation, we can increase the volume flow rate, or the velocity of the fluid passing through the pipe, by reducing the pipe's diameter. The fluid velocity is unaffected by the pipe's length, whether it is longer or shorter.
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Two blocks A and B of masses 5 kg and 1 kg are connected with the help of massless strings
The system is just at the verge of slipping. The coefficient of static friction between the block A and surface below it is
Answer:
The coefficient of friction between all contact surfaces is 0.4. The force, necessary to move the block B with constant velocity, will be (g = 10 m/s)
The coefficient of friction between all contact surfaces is 0.4. The force, necessary to move the block B with constant velocity, will be (g = 10 m/s).
In which condition block B moves?Two blocks A and B of masses 5 kg and 1 kg are connected with the help of massless strings and the system is just at the verge of slipping. The coefficient of static friction between the block A and surface below it is necessary to move the block B.
Static friction is the friction that exists between two surfaces that are not trying to move over each other and which must be overcome before one object starts moving the other.
Two blocks are static equilibrium indicates that the force acting on both blocks is equal.
The frictional force acting on block A is calculated as follows:
Frictional force = coefficient of static friction * normal reaction
Normal reaction on Block A = 30 * 9.8
The coefficient of static friction between block A and the surface = 0.55
Frictional force = 30 * 9.8 * 0.55
Force on Block B = 161.7
Mass of Block B = 161.7 / 9.8
Mass of Block = 18 kg
Therefore, The coefficient of friction between all contact surfaces is 0.4. The force, necessary to move the block B with constant velocity, will be (g = 10 m/s).
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if a particle undergoes shm with amplitude 0.11 m , what is the total distance it travels in one period? express your answer using two significant figures. s
The total distance it travels in one period is 0.44m
Distance is a numerical or every so often qualitative size of how some distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.
The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.
It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.
Calculation:
amplitude = 0.11m
total distance (s) = 4 (amp)
4 × 0.11 = 0.44m
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A bowling ball of mass 5.8 kg moves in a
straight line at 1.82 m/s.
How fast must a Ping-Pong ball of mass
3.276 g move in a straight line so that the two
balls have the same momentum?
Answer in units of m/s.
Answer:
v = 3231.09887 m/s
Explanation:
The attached image includes the steps to get to the answer provided.
determine the horizontal velocity va of a tennis ball at a so that it just clears the net at b.
Upon calculation the horizontal velocity of the tennis ball at A so that is just clears the net at B is found to be 39.7 ft/s
This question can be solved using newton's equation of motion.
Equations of motion in physics are equations that explain how a physical system behaves in terms of how its motion changes over time. The behavior of a physical system is described in further detail by the equations of motion as a collection of mathematical functions expressed in terms of dynamic variables. Typically, these variables are time and geographical coordinates, but they might also have momentum components.
Applying newton's equation of motion in vertical direction,
[tex]s_{y}= s_{0y} +ut+\frac{1}{2}gt^{2}+ut[/tex]
Here, u= 0
[tex]s_{y}=3ft\\ s_{0y}=7.5ft[/tex]
g= -32.2 fts⁻²
Putting in equation
3= 7.5+0-[tex]\frac{1}{2}[/tex]×32.2×[tex]t^{2}[/tex]
t= 0.5287 seconds
Applying newtons's equation in horizontal direction
[tex]s_{x}=s_{0x}+u_{x}t[/tex]
Here,
[tex]s_{x}= 21 ft\\s_{0x}= 0\\ t= 0.5287 seconds[/tex]
21= 0+[tex]u_{x}[/tex]×0.5287
[tex]u_{x}= 39.72 ft/s[/tex]
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calculate the synodic periods of venus and mars relative to earth. what are the implications of these periods for space missions to those planets?
21 and 7 years make up the Earth-Mars synodic period. The ecliptic plane is where the orbits of Earth, Mars, and the cycler trajectory are located.
What makes synodic periods significant?Synodic times are significant because they frequently correspond to direct observables, but physical rotation periods do not. This significance was crucial for determining the planets' orbital periods throughout the history of astronomy.
What exactly is a synodic period?Synodic period: The amount of time it takes for a body in the solar system, such as a planet, the Moon, or a man-made satellite to return to the same or nearly the same location with respect to the Sun as seen from the Earth.
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a red indicator light on a dashboard indicates a. a serious vehicle malfunction needs to be addressed immediately. b. a vehicle malfunction that needs to be addressed but is not urgent. c. a vehicle system that is operating. d. a minor vehicle malfunction.(1 point)
The correct answer is option a. A red indicator light on a dashboard typically indicates a serious vehicle malfunction that needs to be addressed immediately.
This type of light is usually used to indicate a problem that could cause damage to the vehicle or affect its safety if not addressed promptly. It is important to pay attention to a red indicator light and to have the vehicle checked by a mechanic as soon as possible to diagnose and fix the problem.
A red indicator light on a dashboard typically indicates a serious or critical issue with the vehicle that requires immediate attention. Ignoring this light could lead to further damage or safety concerns. It is important to have the vehicle checked by a mechanic as soon as possible.
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A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 225Hz . A person on the platform right next to the speaker detects the sound waves reflected off the wall and those emitted by the speaker.How fast should the platform move, vp, for the person to detect a beat frequency of 1.00Hz ?
The speed of the platform so that the person detects a beat frequency of 1.00 Hz is 5.286m/s.
The speaker moving towards the wall is emitting the sound of frequency of 115Hz and the platform right next to the speaker is detecting the sound reflected by the wall and emitted by the speaker.
Now, to find the speed of the platform so that the person here the beta frequency pf 1.00Hz, we will use the relation,
F = (c+v/c-v)f
c = Speed of waves in the medium
u = Speed of the receiver relative to the medium
v = Speed of the source relative to the medium
f = emitted frequency
Our values are given,
Beat frequency = 7Hz
Reflective Doppler frequency = 225+7=232Hz
Putting values,
232 = (c+v/c-v)225
solving further,
v = 5.286 m/s.
So, the speed of the platform shoud be 5.286m/s.
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A bungee jumper of 68 kg is attached to a bungee cord with an unstretched length of 20 m. He jumps off a bridge and when he finally stops, the cord has a stretched length of 50.0 m. Treat the stuntman as a point mass, and disregard the weight of the bungee cord. Assuming the spring constant of the bungee cord is 82.6 N/m, what is the total potential energy relative to the water when the man stops falling if the distance between the man and the water is 6m?
Answer:
Below
Explanation:
The man will have Gravitational POTENTIAL energy due to Earth's gravity of mgh
mgh = 68 kg * 9.81 m/s^2 * 6m = 4002 J
The bungee has ELASTIC potential energy of 1/2 k x^2
where x = stretch distance and k = spring constant
= 1/2 (82.6 N/m) ( 50-20 m)^2 = 37170 J
Total = 4002 + 37170 = 41172 J
a runner running the 100 m dash starts from rest and accelerates at a rate of 3 m/s^2 for 6.4s until reaching their maximum speed. they continue for the remainder of the race at the same speed. how long did it take them to complete the entire race
The runner takes 11.61 s to complete the entire race when they continue with same speed.
If the runner accelerated for 6.4 s, the velocity at which they accelerated will be:
Acceleration = velocity/time
3 = V/6.4
Making V the subject and by cross multiplying,
V = 3 × 6.4
V = 19.2 m/s
The runner maintains the speed through out the journey.
Speed = distance/time
Making time as the subject of formula,
Time = distance/speed
Time = 100 / 19.2
Time = 5.21 s
Therefore, a runner will complete the entire race in 6.4 + 5.21 = 11.61 s
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One of the most efficient heat engines ever built is a coal-fired steam turbine in the Ohio River valley, operating between 1870 C and 430 C. (a) What is its maximum theoretical efficiency? (b) The actual efficiency of the engine is 42.0%. How much mechanical power does the engine deliver if it absorbs 1.40×10 ^5 J of energy each second from its hot reservoir?
Maximum theoretical efficiency is 67.2%.
What is Maximum theoretical efficiency?
The utmost efficiency that a heat engine may achieve when working
between two temperatures is known as the Carnot Efficiency.
The degree of heat that the high temperature reservoir runs at ( T Hot ).
The degree of heat in the low temperature reservoir ( T Cold ).
The two temperatures in the case of a car are:
the temperature of the engine's combustion gases ( T Hot ).
The temperature at which the engine's gases are released ( T Cold ).
The maximum theoretical efficiency of this engine is the efficiency of a Carnot engine connected between the same two reservoirs, found from Equation
e C=1− T h
Substitute numerical values:
e C =1− 2143.15
703.15
=0.672
=67.2%
Maximum theoretical efficiency is 67.2%.
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A constant net force of 520n is applied onto a 180kg oil drum. If this force causes the drum to accelerate up to a speed of 3.0m/s from rest, how far did the drum go?
the oil drum traveled a distance of approximately 1.56 meters.
To find the distance that the oil drum traveled, we need to use the equation for average acceleration:
d = (vf^2 - vi^2) / 2a
where d is the distance traveled, vf is the final velocity, vi is the initial velocity, and a is the acceleration.
In this case, we are given that the final velocity is 3.0 m/s, the initial velocity is 0 m/s, and the acceleration is 520 N / 180 kg = 2.89 m/s^2. Substituting these values into the equation, we get:
d = (3.0^2 - 0^2) / 2 * 2.89
= 9 / 5.78
= 1.56 m
Therefore, the oil drum traveled a distance of approximately 1.56 meters.
Lab Report( 80 )
Energy
It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U1_ Lab_Energy_Alice_Jones.doc).
Introduction
1. What was the purpose of the experiment?
Type your answer here:
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for the first part of the experiment.
Type your answer here:
Experimental Methods
1. What tools did you use to collect your data?
Type your answer here:
2. Describe the procedure that you followed to collect the data for the first part of the experiment.
Type your answer here:
Data and Observations
1. Record your observations in the data table.
Type your answer here:
Table 1. Measurements Taken from a Simulation of a [insert mass value] kg Ball Released from Various Heights on a Ramp
Mass of ball (kg) Drop height on ramp (m) Potential energy (J) Time to travel 1.0 m (s) Speed (m/s) Kinetic energy (J)
0.5
1.0
1.5
2.0
2.5
3.0
Conclusions
1. What conclusions can you draw about how the amount of potential energy stored in a system changes as a ball is placed at varying heights on a ramp? Write an evidence-based claim.
Type your answer here:
2. Develop a model (diagram) that shows how different amounts of gravitational potential energy (GPE) are stored in the earth-ball system when the ball is raised to different heights on the ramp.
Type your answer here:
3. How did you use what you learned from the first part of the experiment to design a marble run?
Type your answer here:
Pls answers all of these questions quickly
Answer:
Is this a research paper?
if 54 j of work is needed to stretch a spring from 10 cm to 16 cm and another 90 j is needed to stretch it from 16 cm to 22 cm, what is the natural length (in cm) of the spring? cm
The natural length of the spring is 4cm.
Solution:
15/9 = 19k - ka/13k - ka
15/9 = 19 - a/13 - a
195 - 15a = 171 - 9a
24 = 6a
a = 4cm
The term equilibrium length is sometimes used to describe stationary modal distributions. H. Length of multimode optical fiber required to achieve static mode distribution from given excitation conditions. Spring Balance The balance length of a spring is the length when no force is acting.
This is the natural state of spring. Spring constant A measure of elasticity. There is a point where the force and weight of the spring are equal and the directions are opposite. This point is called the equilibrium position. If the masses are in different positions, a net force called the restoring force is directed toward the equilibrium position.
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A bowling ball rolls without slipping up a ramp that slopes upward at an angle β to the horizontal. treat the ball as a uniform, solid sphere, ignoring the finger holes.
a. What is the acceleration of the center of mass of the ball?
b. What minimum coefficient of static friction is needed to prevent slipping?
The acceleration of the center of mass of the ball is a =g*sin(β)/1.4 and K=tanβ is the absolute minimum of the static friction coefficient.
A sort of opposition force known as frictional force attempts to counteract the motion of the body by acting on the surface of the body. Newton is its unit (N). It is described mathematically as the sum of the normal reaction and the coefficient of friction.
(a) A solid sphere rolling uphill has the equation of motion
M*g sinβ-(2/5)M*a = M*a, where an is the acceleration of the center of mass and mgcosβ = R.
We know that the static friction F=μR
By rearranging above formulas we get
2/5M*a + M*a = Mgsinβ
7/5a = gsinβ
Then a = gsinβ/1.4
(b) In the meantime, the normal force or maximum static friction force is equal to kmgcosβ, where k is the static friction's minimum coefficient. To prevent slippage, the frictional force must be less than the maximum static friction force.
Equating the two terms, we get: mgsinβ = kmgcosβ, k = (sinβ/cosβ) = tanβ.
As a result, k=tanβ is the lowest static friction coefficient.
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what is the mass of the air in a room measuring sm x 2m x 3m? density of the air is 1.3kg/m³
Answer:
The mass of the air in a room can be calculated by multiplying the volume of the room by the density of the air. The volume of the room can be calculated by multiplying its length, width, and height. So, if the room has dimensions of 1m x 2m x 3m, its volume would be 1m x 2m x 3m = 6 cubic meters. If the density of the air in the room is 1.3kg/m³, the mass of the air in the room would be 6m³ x 1.3kg/m³ = 7.8kg.
a constant horizontal force is applied to a block initially at rest on a flat frictionless surface. after the block has traveled a distance d, its speed is v. by the time it has traveled an additional distance 8d, how fast is it moving?
It is moving with a speed of 3v.
What is the straightforward meaning of velocity?The primary indication of an object's position and speed is its velocity. It is the distance that an item travels in one unit of time. The displacement of such item in one unit of time is the definition of velocity.
How to calculate velocity of block?Given, initial velocity, u = 0
velocity at distance d = v
by applying the concept of equation of motion,
v² = u² + 2as
v² = 0+2a×d
a = v²/2d
now, velocity at distance 8d, v°² = v² + 2a×8d
v°² = v² + 2×v²/2d×8d
v°² = v² + 8v²
v° = √9v²² = 3v
It is moving with a speed of 3v.
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which law states that an object will continue at its current velocity unless acted upon by an unbalanced force?
Answer:
Newton's First Law of Motion (aka Law of Inertia)
Explanation:
When you drop a 0.4 kg apple, Earth exerts a
force on it that accelerates it at 9.8 m/s
2
toward the earth’s surface. According to Newton’s third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 × 1024 kg, what
is the magnitude of the earth’s acceleration
toward the apple?
Answer in units of m/s
Answer:
Explanation:
a = ΣF/m
a = (0.4kg * 9.8m/s^2)/(5.98 * 10^24kg)
a = 6.56 * 10^-25 m/s^2
A 90 kg fullback is running at 5 m/s and is stopped by a tackler. The tackle lasts for 0.5 second.
a. What is the original momentum of the fullback?
b. What is the impulse imparted on the fullback?
c. What is the force exerted on the fullback?
d. What is the force exerted on the tackler?
A. The original momentum of the fullback is 450 Kg.m/s
B. The impulse imparted on the fullback is 450 Ns
C. The force exerted on the fullback is 900 N
D. The force exerted on the tackler is -900 N
A. How do I determine the original momentum?
The original momentum of the fullback can be obtained as follow:
Mass of fullback = 90 KgVelocity of fullback = 5 m/sMomentum of fullback =?Momentum = mass × velocity
Momentum of fullback= 90 Kg × 5 m/s
Momentum of fullback = 450 Kg.m/s
B. How do I determine the impulse imparted?
The impulse imparted, can be obtained as shown below:
Mass (m) = 90 KgInitial velocity = 5 m/sFinal velocity = 0 m/sImpulse =?Impulse = m(v + u) since the came to rest
Impulse = 90 × (0 + 5)
Impulse = 90 × 5
Impulse = 450 Ns
C. How to determine the force exerted on the fullback?
The force exerted on the fullback can be obtain as follow:
Impulse = 450 NsTime = 0.5Force (F) = ?Impulse = force × time
450 = Force × 0.5
Divide both sides by 0.5
Force = 450 / 0.5
Force = 900 N
D. How to determine the force exerted on the tackler?
Force exerted on the fullback = 900 NForce exerted on the tactkler = 900 NFrom Newton's 3rd law of motion which states that to every action, there is an equal an opposite reaction.
Since the force exerted on the fullback is 900 N. Thus, the force exerted on the tackler will be -900N
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A bicyclist traveling at 24 km/h squeezes the brakes and slows down to a stop in 2.5 seconds. Which of the following statements best describes what happened to the energy of the moving bicycle? A The kinetic energy was converted to thermal energy. B The chemical energy was converted to mechanical energy. C The kinetic energy was converted to chemical energy. D The chemical energy was converted to thermal energy.
Answer:
A The kinetic energy was converted to thermal energy
Explanation:
Friction braking is the most commonly used braking method in modern vehicles. It involves the conversion of kinetic energy to thermal energy by applying friction to the moving parts of a system. The friction force resists motion and in turn generates heat, eventually bringing the velocity to zero.
Answer:
The correct answer is A: The kinetic energy was converted to thermal energy.
When a bicyclist squeezes the brakes and slows down to a stop, the kinetic energy of the moving bicycle is converted to thermal energy. This is because the brakes on a bicycle work by converting the kinetic energy of the moving bike into heat energy through friction. When the brakes are applied, the brake pads clamp down on the brake rotor, which is attached to the wheel. The friction between the brake pads and the brake rotor slows the wheel down and converts the kinetic energy of the moving bicycle into heat energy. This heat energy can then be dissipated through the brake pads and the brake rotor, causing the bicycle to come to a stop.
Explanation:
is there evidence of the diffusion of starch molecules? if so, what evidence and in which direction did starch molecules diffuse?
Iodine molecules are small enough to pass freely through the membrane however, starch molecules are complex and too large to pass through the membrane. Initially, there was a higher concentration of iodine outside than inside the tube.
Thus iodine diffused into the tube with the starch. Iodine is able to pass through the membrane while starch is not. The Glucose-testing strips indicate that glucose has been able to pass out of the tubing and into the external fluid. Thus proving the tubing allows movement in both directions.
Iodine was able to diffuse across the membrane because it is small and hydrophobic and starch was not because it is too large The Dialysis tubing provides a semi-permeable membrane. Only allowing smaller molecules to pass through it. Iodine molecules are small enough to pass freely through the membrane, however, starch molecules are complex and too large to pass through the membrane.
The iodine is a small molecule and can move from outside the tubing to inside it. To test whether iodine or starch has crossed the synthetic membrane, you will look for color change. A solution of iodine is tan and a solution of starch is milky white; when iodine and starch are together in the same solution, they react and the solution turns purple, dark blue, or black.
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Johnny finds it difficult to play catch on a planet Binu because the planets escape speed is only 5.00m/s and if jonny throws the ball too hard, it flies away. If planet Binu has a mass of 1.56x10^15kg, what is the radius
Answer:
Approximately [tex]4.16 \times 10^{3}\; {\rm m}[/tex] (or equivalently, [tex]4.16\; {\rm km}[/tex]) assuming this planet is spherical.
Explanation:
Let [tex]m[/tex] denote the mass of the ball. If the speed of the ball is [tex]v[/tex], the kinetic energy of the ball will be [tex](\text{KE}) = (1/2)\, m\, v^{2}[/tex].
Assume that the planet is spherical. Let [tex]r[/tex] denote the radius of the planet. Let [tex]M[/tex] denote the mass of this planet, and let [tex]G[/tex] denote the gravitational constant.
On the surface of this planet, the gravitational potential energy [tex](\text{GPE})[/tex] of this ball will be [tex](\text{GPE}) = (-G\, M\, m) / (r)[/tex]. (Note the negative sign. The ball is trapped inside the gravitational field of the planet, and it takes energy input to bring the ball out of this field.)
The ball is at its escape speed [tex]v_{e}[/tex] if the sum of [tex](\text{KE})[/tex] and [tex](\text{GPE})[/tex] at the surface of the planet is [tex]0[/tex]. In other words:
[tex](\text{KE}) + (\text{GPE}) = 0[/tex].
[tex]\begin{aligned}\frac{1}{2}\, m\, v^{2} + \frac{- G\, M\, m}{r} = 0\end{aligned}[/tex].
Rewrite this equation and solve for radius [tex]r[/tex].
[tex]\begin{aligned}\frac{G\, M\, m}{r} = \frac{1}{2}\, m\, v^{2}\end{aligned}[/tex].
[tex]\begin{aligned}r &= \frac{v^{2}}{2\, G\, M}\end{aligned}[/tex].
[tex]\begin{aligned}r &= \frac{2\, G\, M}{{v_{e}}^{2}} \\ &= \frac{2\, (6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1} \cdot s^{-2})\, (1.56 \times 10^{15}\; {\rm kg})}}{(5.00\; {\rm m\cdot s^{-1}})^{2}} \\ &\approx 8.32 \times 10^{3}\; {\rm m}\end{aligned}[/tex].
a local am radio station broadcasts at an energy of kj/photon. () calculate the frequency at which it is broadcasting.
The frequency at which it is broadcasting is 875 KHz for a local am radio station broadcasts at an energy of kj/photon
Given,
Energy of a photon = 5.80 x 10-31 kJ x ( 1000 J / 1kJ) = 5.8 x 10-28 J
We know,
E = hv
Here,
"h" is the plank's constant = 6.626 x 10-34 J.s
v = frequency in Hz
Now, rearranging the formula,
v = E / h
Substituting the values,
v = 5.8 x 10-28 J / 6.626 x 10-34 J.s
v = 875340 s-1 or Hz
Now, converting Hz to kHz,
Given, 1kHz = 103 Hz
= 875340 Hz x ( 1 kHz / 103 Hz)
= 875.3 kHz
Frequency = 875 kHz [3S.F]
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an eyepiece with a 2.00 cm focal length is placed 19.0 cm from the objective. where is the final image? (enter the image distance in cm.)
The final image is found to be 2.37cm in front of the eyepiece.
The focal length of the eyepiece is 2.00 cm and it is placed at a distance of 19.00 cm in front of the objective lens.
Now, we can use the lens formula to find the position of the image,
1/v - 1/u = 1/f
Where,
v is the position of the image,
u is the position of the objective in front of the eyepiece,
f is the focal length of the eyepiece.
Now, putting values,
1/v - 1/(-19) = 1/(-3)
The focal length and u are taken negative because of the sign standard sign convention of the lens.
1/v+1/19 = -1/3
Solving further,
v = -2.38 cm
So, the final image is 2.38 cm in front of the eyepiece.
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you do more work on yourself against gravity when you run up the stairs than when you walk slowly. true false
False; running up stairs really requires less exertion against gravity than leisurely walking up them.
Gravity, which means "weight" in Latin, is a basic interaction in physics that causes all objects with mass or energy to be attracted to one another. By far the weakest of the four basic interactions, gravity is 1038 times weaker than the strong interaction, 1036 times weaker than the electromagnetic force, and 1029 times weaker than the weak interaction. As a result, it has no discernible impact on the level of subatomic particles. The motion of planets, stars, galaxies and even light are all governed by gravity, which is the most important interaction between things at the macroscopic level.
On Earth, gravity imparts weight to tangible objects, and the Moon's gravity is what causes sublunar tides in the seas.
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when a nucleus of 235u undergoes fission, it breaks into two smaller, more tightly bound fragments. - Calculate the binding energy per nucleon for ^235U? (Express with appropriate units)- Calculate the binding energy per nucleon for the fission product ^137 Cs? (Express in appropriate units)
The binding energy per nucleon of 235-U and 137-Cs is given below when a nucleus of 235u undergoes fission
235-U = 7.6 MeV
137-Cs = 8.39 MeV
What is the 235-U and 137-Cs nucleons' binding energy?
The following equation gives a nucleus' binding energy:
mc2 = BE, where BE is the binding energy.
m is a mass defect.
For 235U, c = 931.49 MeV/u is the speed of light.
A=235 m=1.9150664 BE=1.9150664 *931.49 MeV/u BE=1783.8648 MeV
The equation BE/A BE/A = 1738.648 MeV / 235 BE/A = 7.6 MeV determines the binding energy per nucleon.
Binding energy for 137-Cs is:
BE = 1.23383 u * 31.49 MeV/u, where m is the mass defect, giving 1149.3003 MeV.
The binding energy per nucleon, BE/A, is as follows:
A is 137 in the instance of 137-Cs, hence BE/A equals 1149.3003 MeV / 137 BE/A is 8.39 MeV.
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A small tropical fish is at the center of a water-filled spherical fishbowl 28.0 cm in diameter.a. Find the apparent position of the fish to an observer outside the bowl. The effect of the thin walls of the bowl may be ignored.b. Find the magnification of the fish to an observer outside the bowl.
To find the apparent position of the fish to an observer outside the bowl, we can use the lens equation:
1/p + 1/q = 1/f
where p is the distance from the object (the fish) to the center of the lens (in this case, the center of the fishbowl), q is the distance from the image to the center of the lens, and f is the focal length of the lens.
The focal length of a lens is given by the formula:
f = (n-1)R/2(n-1)
where R is the radius of the lens (in this case, the radius of the fishbowl) and n is the refractive index of the lens material (in this case, water).
Since the diameter of the fishbowl is 28.0 cm, the radius is 14.0 cm. The refractive index of water is approximately 1.33, so the focal length is approximately 8.5 cm.
To find the apparent position of the fish, we need to find p and q. If we let q be the distance from the image to the center of the lens, then the distance from the fish to the center of the lens is p = R - q.
Substituting these values into the lens equation, we get:
1/p + 1/q = 1/f
1/(R-q) + 1/q = 1/f
Solving this equation for q, we find that q = R/2 = 14.0 cm/2 = 7.0 cm.
This means that the apparent position of the fish is 7.0 cm from the center of the fishbowl.
To find the magnification of the fish to an observer outside the bowl, we can use the formula:
m = -q/p
Substituting the values we found above, we get:
m = -7.0 cm / (14.0 cm - 7.0 cm) = -1/2 = -0.5
This means that the fish is magnified by a factor of -0.5, or half its size.
what is the minimum distance, in au and in miles, for an object to be considered a potentially hazardous object?
An object must have a MOID of 0.05 AU or less in order to be considered a potentially hazardous object. This distance is equivalent to 4.65 million miles. Objects with a MOID between 0.05 and 0.25 AU are considered Near Earth Objects and could potentially become potentially hazardous object (PHOs) in the future.
A potentially hazardous object (PHO) is an asteroid or comet that has an orbital path that comes close enough to Earth to pose an impact hazard. The minimum distance that an object must be from Earth to be considered a PHO is defined by the International Astronomical Union (IAU). The IAU defines a PHO as an object whose Minimum Orbit Intersection Distance (MOID) with Earth's orbit is 0.05 AU or less.
In astronomical units (AU), the minimum distance for an object to be considered a PHO is 0.05 AU. An AU is equivalent to the average distance from Earth to the Sun, or about 93 million miles. Therefore, the minimum distance for an object to be considered a PHO is about 4.65 million miles.
The MOID is the closest approach an object can make to Earth’s orbit. The MOID of an asteroid or comet is calculated based on its orbital elements, such as its semi-major axis and eccentricity. An object with a MOID of 0.05 AU or less is considered to have a close enough approach to Earth’s orbit to pose an impact hazard.
The IAU also defines an object as a “Near Earth Object” (NEO) if its MOID is between 0.05 and 0.25 AU. NEOs are objects that could potentially come close enough to Earth to cause an impact hazard, but are not considered to be PHOs because the risk is not as high.
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