PLSSS HELP IF YOU TURLY KNOW THISS

Answer:

3 × 3 × 3 × 5 × 7

Answer:

First Figure:

Do you see the right triangle in the first figure? It is bisected by the angle x° and 68°. Since all right triangles add to 90°, this makes x° = 90° - 68°.

E.) x° = 90° - 68°  -----> x° = 22°

Do you see how you now know the values of 3 out of 4 angles on the straight line? Since all lines add to 180°, the value of y° = 180° - 90° - 22°. Remember, the entire angle value for all right triangles is 90°.

H.) y° = 180° - 90° - 22°  ----->  y° = 68°

Second Figure:

A similar process can be taken for the second figure.

T.) x° = 180° - 90° - 74°  ----->  x° = 16°

E.) y = 90° - 50°  ----->  y° = 40°

Third Figure:

Again, remember that right triangles = 90° and lines = 180°.

C.) w° = 180° - 90° - 31°  ----->  w° = 59°

R.) x° = 90° - 28°  -----> x° = 62°

H.) y° = 180° - w°  ----->  y° = 180° - 59°  ----->  y° = 121°

the amount of maturity is 254583

Answer:

Total Ratio = 2+4

=6

Striped blankets = 2/6 × 12

= 4 Striped Blankets

Step-by-step explanation:

Can't really explain

Answer:

25

Step-by-step explanation:

..............

Answer:

126

Step-by-step explanation:

Answer:

the answer us 140

Step-by-step explanation:

the answer is 140 because if you add them all the answer will come 140 but if we divide it or multiply it the answer will not come so the answer is 140

There are 20 possible different combination of meals

The given parameters are:

Drinks = 4

Main dishes = 5

The number of different meals is calculated as:

Meals = Drinks * Main dishes

So, we have:

Meals = 4 * 5

Evaluate

Meals = 20

Hence, there are 20 possible different combination of meals

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

As we know, Area of a square can be represented as :

[tex]\qquad \sf  \dashrightarrow \:area = side {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a = s {}^{2} [/tex]

now, we have been given that area of a particular square is 16 square feet. so, let's calculate its sides

[tex]\qquad \sf  \dashrightarrow \:s {}^{2} = 17[/tex]

[tex]\qquad \sf  \dashrightarrow \:s = \sqrt{17} [/tex]

[tex]\qquad \sf  \dashrightarrow \:s \approx4.12 [/tex]

so, the closest value is : B. 4.1 feet

Answer:

b.42

Step-by-step explanation:

the ratiois is 3 to 4 .So every 4 snakes is to 3 frogs so since there are 24 snakes devide the 24 by 4 which will give u 6 then multiply the answer by 3 which will give u 18 which represents the total number of frogs then add 18 +24 which is 42.

so then total number of frogs is 42.

Answer:

Range & Isabella

Step-by-step explanation:

Part A:

Definitely not range mean or median, as that'll give you their average, not consistency.  None of their tables show any repeating values, so not mode either, and range would be the most hopeful for this.

Part B:

The results with the smallest range would be the most consistent:

Charles:
Lowest value = 39 and Highest Value = 57
Range = 57-39 = 18

Isabella:
Lowest value = 62 and Highest value = 71
Range = 71-62 = 9

Naomi:
Lowest value = 61 and Highest value = 94
Range = 94-61 = 33

Isabella achieved the most consistent results.  Hope this helps

Answer:

Step-by-step explanation:

15^2 - 12^2 = a^2

225 - 144 = 81

a^2 = 81

a=9

Hey ! there

Answer:

Step-by-step explanation:

In this question we are given area of rectangle that is 60 inches square and its breadth is 5 inch . We are asked to find the length of breadth in ft .

SOLUTION : -

For changing " in " into " ft " we need to divide the given inch value by 12. So Dividing 5 inches by 12 :

[tex] \quad \dashrightarrow \qquad \: \dfrac{5}{12} [/tex]

We get :

[tex]\quad \dashrightarrow \qquad \: \purple{\underline{\boxed{\frak{0.416 \: ft}}}} \quad \bigstar[/tex]

Using the concept of a proportional relationship, it is found that the correct option regarding the graph is given by:

No, it is not a proportional relationship because the graph does not go through the origin.

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

From the equation above, the first step is that in a proportional relationship, the map must go through the origin, that is, it must pass through the point (0,0). In this problem, it does not passes through the origin, as it passes in (0,2), hence the correct option is given by:

No, it is not a proportional relationship because the graph does not go through the origin.

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Answer:

y = -x + 1

Step-by-step explanation:

I just checked it in the desmos graphing calculator and it was correct.

Answer:

y = -x + 1.

Step-by-step explanation:

The graph rises to the left so has a negative slope.

slope  = -1 and y-intercept = 1

The length of lines UV, VW, WX, and UX are: = √65 units, 10 units,√65 units and 10 units respectively.

Algebraic expression that gives the distances between pairs of points in terms of their coordinates

Given that:  U(7,9), V(0,5), W(-6,-3) ,X(1,1)

The length can be find by using Distance Formula,

Length of UV,

= [tex]\sqrt{(0-7)^{2} + (5-9)^{2}}[/tex]

= [tex]\sqrt{49+16}[/tex]

= √65 units

Length of VW,

= [tex]\sqrt{(-6-0)^{2}+(-3-5)^{2}}[/tex]

= [tex]\sqrt{36 + 64}[/tex]

=√100 units

= 10 units

Length of WX,

=[tex]\sqrt{(1-(-6))^{2}+(1-(-3))^{2}}[/tex]

= √49+ 14

= √65 units

Length of XU,

= [tex]\sqrt{(7-1)^{2}+(9-1)^{2}}[/tex]

= √36+64

=√100 units

= 10 units

Length of UW,

= [tex]\sqrt{(-6-7)^{2}+(-3-9)^{2}}[/tex]

= √169+144

=√313 units

Length of VX,

= [tex]\sqrt{(1-0)^{2}+(5-1)^{2}}[/tex]

= √1+16

=√17 units

Thus, Length of opposite sides are equal but the length of diagonals are not Equal. So, the quadrilateral is a parallelogram.

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Answer:

  $0.88/lb

Step-by-step explanation:

The end result of this units conversion is found by multiplying the fractions in the usual way. The numerator is the product of the numerators; the denominator is the product of the denominators. Of course, the division must be carried to completion to arrive at the unit price.

__

  [tex]=\dfrac{26.29\times0.074\times1}{1\times1\times2.2}\ \dfrac{\text{dollars}}{\text{lb}}=\dfrac{1.94546}{2.2}\ \dfrac{\text{dollars}}{\text{lb}}\approx\boxed{0.88\ \dfrac{\text{dollars}}{\text{lb}}}[/tex]

Answer:

A.

Step-by-step explanation:

2×sqrt(48) - (2 + sqrt(12))(5 - sqrt(12))

2×sqrt(16×3) - (2 + sqrt(4×3))(5 - sqrt(4×3))

2×4×sqrt(3) - (2 + 2×sqrt(3))(5 - 2×sqrt(3))

8×sqrt(3) - (10 - 4×sqrt(3) + 10×sqrt(3) - 4×3)

8×sqrt(3) - 10 - 6×sqrt(3) + 12

2×sqrt(3) + 2

Answer:

[tex]\log_3(27)=x[/tex]

Step-by-step explanation:

[tex]a^x=b[/tex] is equivalent to [tex]\log_a(b)=x[/tex] in logarithmic form, so [tex]3^x=27[/tex] is equivalent to [tex]\log_3(27)=x[/tex]

Answer:

Step-by-step explanation:

Answer:

1. False

2. True

3. true

Step-by-step explanation:

The first answer is false, the second one is true and the third is true

Answer:

45 ft²

Step-by-step explanation:

Logo 2 comprises 5 congruent squares with side length 1/2 in

Given scale:  1 in = 6 ft

⇒ 1/2 in = 3 ft

Area of a square = s²  (where s is the side length)

⇒ area of one of the squares of logo 2 = (3 ft)² = 9 ft²

Therefore, the total area is:

⇒ area = 5 × 9 ft² = 45 ft²

In equation form:

A = 5(6s)²

where:

Answer:

There are 32 marbles. 11 are red. So odds of a red on the first are 11/32.

Now there are 31 marbles left. 10 are red. So odds of a red on the second is 10/31.

Probability both are red, just multiply …. 11/32x 10/31 = 110/992 or 0.111.

plane PBC is right answer.

it's a logical answer....

Answer:

Plane PBC

Step-by-step explanation:

Plane PBC contains 4 points : P, B, C, and Q.

The question asks which contains all three of C, Q, and P.

300 written in scientific notation is 3 × 102.

hope this was helpful.

Step-by-step explanation:

Answer:

estimate the probability that angad wins

The value of the quotient expression [tex]\frac{4f^2}{3} \div \frac{1}{4f}[/tex] is [tex]\frac{16f^3}{3}[/tex]

The quotient of numbers or expressions is the division of a number or expression by another

The expression is given as:

[tex]\frac{4f^2}{3} \div \frac{1}{4f}[/tex]

Rewrite as a product expression

[tex]\frac{4f^2}{3} \times \frac{4f}{1}[/tex]

Evaluate the product of 3 and 1

[tex]\frac{4f^2}{3} \times 4f[/tex]

Evaluate the product of 4f^2 and 4f

[tex]\frac{16f^3}{3}[/tex]

Hence, the value of the quotient expression [tex]\frac{4f^2}{3} \div \frac{1}{4f}[/tex] is [tex]\frac{16f^3}{3}[/tex]

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Answer:

its A

Step-by-step explanation:

On edge its the first answer

Because [tex]a_1[/tex] through [tex]a_{10}[/tex] are in arithmetic progression, there is some fixed number [tex]d[/tex] between consecutive terms. This means we have

[tex]a_2 = a_1 + d[/tex]

[tex]a_3 = a_2 + d = a_1 + 2d[/tex]

[tex]a_4 = a_3 + d = a_1 + 3d[/tex]

and so on, with the general [tex]n[/tex]-th term

[tex]a_n = a_1 + (n-1) d[/tex]

Then we can write each given equation in terms of [tex]a_1[/tex] and [tex]d[/tex] :

[tex]a_1 + a_3 + a_5 + a_7 + a_9 = 17[/tex]

[tex]\implies a_1 + (a_1+2d) + (a_1+4d) + (a_1 + 6d) + (a_1 + 8d) = 17[/tex]

[tex]\implies 5a_1 + 20d = 17[/tex]

and

[tex]a_2 + a_4 + a_6 + a_8 + a_{10} = 15[/tex]

[tex]\implies (a_1+d) + (a_1+3d) + (a_1+5d) + (a_1+7d) + (a_1+9d) = 15[/tex]

[tex]\implies 5a_1+25d= 15[/tex]

Eliminate [tex]d[/tex] and solve for [tex]a_1[/tex] :

[tex]5 (5a_1 + 20d) - 4 (5a_1 + 25d) = 5\times17-4\times15[/tex]

[tex]\implies 5a_1 = 25[/tex]

[tex]\implies \boxed{a_1 = 5}[/tex]

The two-way table that shows the joint and the marginal relative frequencies is:

            Aerobic          Anaerobic     Total

Male       0.48              0.63               0.55

Female   0.52             0.37               0.45

Total         1                    1                      1

The table is given as:

            Aerobic     Anaerobic

Male       88               104

Female  96                62

The column total are:

Aerobic = 88 + 96 = 184

Anaerobic = 104+ 62 = 166

So, we have:

            Aerobic                        Anaerobic

Male       88/184 = 0.48              104/166 = 0.63

Female  96/184 =  0.52             62/166 = 0.37

The total count of the table is

Total = 184 + 166 = 350

So, we have:

            Aerobic          Anaerobic     Total

Male       0.48              0.63              (88 + 104)/350 = 0.55

Female   0.52             0.37               (96 + 62)/350 = 0.45

Hence, the two-way table that shows the joint and the marginal relative frequencies is:

            Aerobic          Anaerobic     Total

Male       0.48              0.63               0.55

Female   0.52             0.37               0.45

Total         1                    1                      1

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Based on the number of males and females doing aerobic and anaerobic respiration, the relative and marginal frequencies can be shown as:

                           Aerobic                     Anaerobic                        Total

Male                     47.8%                          62.7%                            54.9%

Female                 52.2%                          37.3%                            45.1%

                            100%                             100%                             100%

The frequencies for males are:

Aerobic = 88 / (88 + 96)                                    Anaerobic = 104 / (104 + 62)

= 47.8%                                                                                 = 62.7%

For females:                      

Aerobic = 100% - 47.8%                                    Anaerobic = 100 - 62.7%

= 52.2%                                                                                 = 37.3%

Total males frequency:                                Total females
= (88 + 104) / (88 + 104 + 96 + 62)               = 100% - 54.9%

= 54.9%                                                          = 45.1%

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Using the normal distribution, it is found that about 81.8% of Internet users spend between 78 minutes and 174 minutes on social networking platforms each day.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem, the mean and the standard deviation are given, respectively, by:

[tex]\mu = 142, \sigma = 32[/tex].

Th proportion of Internet users spend between 78 minutes and 174 minutes on social networking platforms each day is the p-value of Z when X = 174 subtracted by the p-value of Z when X = 78, hence:

X = 174:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{174 - 142}{32}[/tex]

Z = 1

Z = 1 has a p-value of 0.841.

X = 78:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{78 - 142}{32}[/tex]

Z = -2

Z = -2 has a p-value of 0.023.

0.841 - 0.023 = 0.818 = 81.8%.

81.8% of Internet users spend between 78 minutes and 174 minutes on social networking platforms each day.

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