Pls help with the questions in the photo, any of them will help :)

Pls Help With The Questions In The Photo, Any Of Them Will Help :)

Answers

Answer 1

Answer: The velocity of the bird is 7m/s

Explanation: Since momentum is the total quantity of the motion which is contained in the body.

It is defined as the multiply of mass and velocity of the body

It is given in the question that mass of bird is 2.5 kg and momentum is 17.5 kg/s.


Related Questions

Guitars have strings of different linear mass density. If the lowest density string and the highest density string are under the same tension, which string would support waves with the higher wave speed?.

Answers

In order to accommodate the increased wave speed, guitars have linear strings with variable linear mass densities, a linear density string and a higher density string under the same tension.

There is a formula for speed velocity. is determined by multiplying the mass of the strength by the square of the attention attention force. As a result, this demonstrates that the investment's velocity accelerated toward the square of the linear identity.

What then is becoming increasingly identity? No. They never fell short to cut. In order to answer the issue, the lesser density string will have a higher velocity if it is under the same strain as the advertising industry.

Lower your pace for the higher density strength and the wave speed.

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Different stars create different elements. Constant how hydrogen, helium, and lithium were formed in the universe versus how lighter elements and heavier elements (up to iron) are formed
1. Hydrogen, helium, lithium -
2. Ni and Cu-
3. Ta and W-

Answers

Hydrogen and helium are formed due to big bang event whereas heavy elements are formed inside very hot environment.

What causes the formation of hydrogen?

The lightest elements i.e. hydrogen, helium, lithium etc were produced in the Big Bang event. According to the Big Bang theory, the temperatures in the early stage of universe were so high that leads to fusion reactions.

Light elements such as hydrogen and helium are formed during the big bang event while on the other hand, the iron molecules are made due to the fusion in the cores of stars. Many heavier elements like gallium and bromine need supernova condition for their formation.

So w can conclude that big bang event is responsible for the formation of  Hydrogen and helium whereas heavy elements are formed inside the supernova.

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a 20. g particle is moving to the left at 30. m/s. how much net work must be done on the particle to cause it to move to the right at 30. m/s?

Answers

The net work done will be zero on moving the ball to the right.

The net work done is equal to the change in kinetic energy. The initial velocity is - 30 m/s and the final velocity is + 30 m/s. Also, the formula for kinetic energy is: K.E. = 1/2m([tex] { v_{f} }^{2} [/tex]

- [tex] { v_{i} }^{2} [/tex]

Keep the values in formula to find the kinetic energy

K.E. = 1/2×20×(30² - (-30)²)

Taking square on Right Hand Side of the equation

K.E. = 10×(900 - 900)

Performing subtraction on Right Hand Side of the equation

K.E. = 0

Thus, the net work done will be zero. The work done on stopping the particle and then moving it to different direction will be equal. Thus, we get the value zero.

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63-kg rock-climber is being pulled up the last 5.9 s of her climb by a rope. Her speed increases from 0 m/s to 2.9 m/s as she is being pulled upward. How much tension force is she applying to the rope?

Answers

The tension force applied to the rope when a rock-climber is being pulled up with an increase in speed of 0 to 2.9 m/s in 5.9 s is 30.97 N.

What is tension force?

Tension force is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.

To calculate the tension force she applied to the rope, we use the formula below.

Formula:

F = m(v-u)/t.......... Equation 1

Where:

F = Tension force applied to the the ropem = mass of the rock climberv = Final velocityu = Initial velocityt = time.

From the question,

Given:

m = 63 kgv = 2.9 m/su = 0 m/st = 5.9 s

Substitute these values into equation 1

F = 63(2.9-0)/5.9F = 30.97 N

Hence, the tension force applied to the rope is 30.97 N.

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How will a strong material differ from a weaker material?

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The greatest stress that a material can withstand before failing is referred to as its strength. Its stiffness describes how much it will flex or bend when pulled. High strength is frequently found in materials with high stiffness. The greatest stress that a material can withstand before failing is referred to as its strength.

Stress is the force applied to a material's unit area. Strain is the term for a body's reaction to stress. The body can distort under stress. Stress units can be used to quantify the amount of force that a material has experienced.Materials science is the study of the characteristics of solid materials and how a material's structure and composition affect those characteristics.Strain is calculated by dividing the amount of deformation the body experiences in the direction of the applied force by the body's starting dimensions.

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What is the resultant of two displacement vectors having the same direction?1) The resultant is the sum of the two displacements having the same direction as the original vectors.2) The resultant is the difference of the two displacements having the same direction as the original vectors.3) The resultant is the sum of the two displacements having the direction opposite to the direction of the original vectors.4) The resultant is the sum of the two displacements having the direction perpendicular to the direction of the original vectors.

Answers

When two vectors have the same direction, they can be added and the direction of the resultant is the same as the direction of the vectors. Additionally, the magnitude of the resultant is simply the sum of the corresponding magnitudes of the vectors.

Therefore, the answer is:

1) The resultant is the sum of the two displacements having the same direction as the original vectors.

In which type of circuit must the current always be the same through each
resistor?
A: Series Circuit
B: Parallel Circuit
C: Both

Answers

Answer:

Since there is only one path for electron flow in a series circuit, the current is the same magnitude at any point in the circuit

Explanation:

The answer is A. Series Circuit

it is A!!! I have been learning this in school

The intensity of an electromagnetic wave is related to which property of the wave squared?.

Answers

The intensity of an electromagnetic wave is related to the amplitude squared.

Electromagnetic wave:

Electromagnetic radiation consists of waves of the electromagnetic field, which propagate through space and carry electromagnetic radiant energy.

The intensity of electromagnetic waves:

The intensity of an electromagnetic wave is defined as the energy crossing per second per unit area held perpendicular to the direction of propagation of electromagnetic waves.

The formula for the intensity of electromagnetic waves:

I = η ε Ε² / 2

E = amplitude

Therefore we get that the intensity of an electromagnetic wave is related to the amplitude squared.

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You have someone in front of you that you are pulling hair samples from pre-emptively—not because you need them right now but just in case they might be relevant later. What is most likely true about the person in front of you?

Answers

The most likely true about the person in front of you is any of the above could be true and is denoted as option D.

What is a Sample?

This is referred to as the matter or substance which is obtained so as to aid investigation processes and examples include hair, blood etc. It is useful as it helps to solve a crime and ensures that the culprit is punished.

Taking hair samples from pre-emptively could be because of any of the reasons listed such as being a suspect or a witness to a crime thereby making option D as the correct choice.

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The options are:

They are a suspect in a police interrogation.They are a witness of a crime.They are dead.Any of the above could be true.

Estamos bajando dos cajas de madera con frutos menores (una encima de la otra) por una rampa con una inclinación de 30 grados con la horizontal. La caja inferior tiene una masa de 80kg y su coeficiente de fricción con el suelo es de 0.3, y la caja superior tiene una masa de 30kg con un coeficiente de fricción con la caja inferior de 0.8. Calcula la fuerza que tenemos que ejercer para que ambas cajas bajen con velocidad constante de 0.5m/s.

Answers

La situación planteada se muestra a continuación:

(El diagrama mostrado es para la caja inferior). A continuación mostramos el diagrama para la caja superior:

Si consideramos el sistema de dos cajas como uno solo tenemos el siguiente sistemas de ecuaciones:

[tex]\begin{gathered} F+F_f-W_x=0 \\ N-W_y=0 \end{gathered}[/tex]

De donde:

[tex]\begin{gathered} F=W_x-F_f \\ F=W_x-\mu N \\ F=W_x-\mu W_y \\ F=(80)(9.81)\sin 30-(0.3)(80)(9.81)\cos 30 \\ F=188.5 \end{gathered}[/tex]

Ahora debemos determinar si la caja de arriba no se resbala al aplicar esta fuerza, para esto debemos recordar que la fricción es máxima con el coeficiente de fricción estático.

Entonces tenemos que la fricción es máxima para el bloque de arriba cuando:

[tex]F_f=(0.8)(30)(9.81)\cos 30=203.89[/tex]

Dado que la fuerza que debemos aplicar no es mayor a la fricción máxima concluimos que ambas cajas bajaran al mismo tiempo. Por lo tanto la fuerza que debemos aplicar es de 188.5 N.

For the velocity-time graph shown, which statement describes what happens to the velocity between approximately 24 s and 25 s?

A) The lander's velocity increases away from the reference.

B) The lander's velocity decreases toward the reference.

C) The lander's velocity decreases away from the reference.

D) The lander's velocity increases toward the reference.

Answers

The velocity–time graph of the Lunar Landing Powered Descent that has a domain of 10 ≤ t ≤ 25, and a range of -2 ≤ v ≤ -40, between the 24th and the 25th seconds gives;

C) The Lander's velocity decreases away from the reference

What is a velocity–time graph?

A velocity time graph is a graph that shows the variation of the velocity of an object with time.

The information with regards to the lunar landing powered descent graph are;

Coordinate points on the graph;

(10, -2); At time t = 10 seconds, the average velocity, v = 0

(10.5, -40); The velocity relative to the starting point changed and decreased from 0 m/s to -40 m/s

(15, -5); The velocity increased from -40 m/s to -5 m/s

(22, -3); The velocity increases from -5 m/s to -3 m/s

(24, -2); The velocity increases from -3 m/s to -2 m/s

(25, -15); The velocity decreases from -2 m/s to -15 m/s

Therefore, taking the reference point as the point where the velocity is zero, 0, we have that between approximately 24 seconds and 25 seconds, the Lander's velocity decreases away from the reference.

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three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 6.99 v battery, which charges the capac

Answers

..............................

The capacitance of each capacitor is 2.1 ×[tex]10^{-5}[/tex]F.

Let

Equivalent capacitance of the circuit = [tex]C_{eq}[/tex]

   [tex]C_{eq}[/tex] =Q/V

where Q is the charge and V is the potential difference.

Q = [tex]3.5[/tex]×[tex]10^{-4[/tex]

V = 5.55 V

Putting the values

   [tex]C_{eq}[/tex] =    [tex]3.5[/tex]×[tex]10^{-4[/tex]/5.5V

                   [tex]C_{eq}[/tex] = [tex]6.4[/tex]×[tex]10^{-5}[/tex]F

The circuit consists of 3 capacitors in parallel, each one having the same capacitance C.

To find C:

C = [tex]C_{eq}[/tex]/3

C = 2.1 ×[tex]10^{-5}[/tex]F

The capacitance of each capacitor is 2.1 ×[tex]10^{-5}[/tex]F.

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The full Question is :

Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.

optimus prime coasts up a hill initially at 11.0m/s. after 9.3s he is rolling back down the slope at 7.3m/s. what is his acceleration?

Answers

The rate at which an object's velocity changes in relation to time is known as acceleration. The vector quantity of accelerations. The acceleration of an object depends on the direction of the net force acting on it.

V up = 11 m/s ; V dwn = 7.3 m/s ; t = 9.3

using, V = u + at [ u = V up]

a = (v - u)/t

a = (-7.3 - 11) / 9.3

  = -2.0 m/s²

Acceleration (a) is defined as the product of the change in velocity (v) and the change in time (t) in the equation a = v/t (t). You can use this to get the change in velocity in m/s2 (meters per second squared).

Acceleration is the rate at which speed changes, whereas speed is the distance traveled in a unit of time. The metric system uses meters per second (m/s) as the unit of speed and meters per second squared (m/s2) as the measure of acceleration. Acceleration is a vector quantity, whereas speed is a scalar quantity.

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a capacitor is charged to a potential of 12.0 vv and is then connected to a voltmeter having an internal resistance of 3.40 mωmω. after a time of 4.00 ss the voltmeter reads 3.5 vv.

Answers

a. capacitance of circuit is C= 0.849 micro farad & b.  time constant of the circuit is t=2.89 sec.

A component or circuit's capacitance is its capacity to accumulate and store electrical charge as a type of energy. Energy-storing devices known as capacitors come in a variety of sizes and forms. A property of an electric conductor, or group of conductors, known as capacitance is determined by how much separated electric charge can be held on it for each unit change in electrical potential. A store of electrical energy is also implied by capacitance. A potential difference between two initially uncharged conductors is created if electrical charge is transferred between them, causing both to become equally charged (one positively, the other negatively). The capacitance C is defined as the product of the charge density q on each conductor and the potential difference V between them, or C = q/V. Only if the charge is kept constant will capacitance drop as potential increases. Less potential difference equals higher capacitance, according to the equation.

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A car coasts into a hill at 16.0 m/s. It slows down with a uniform acceleration of -1.0 m/S/S.

What is the displacement after 5.0s?

What is the displacement after 10.0s?

Answers

In the given question, a car coasts into a hill at 16.0 m/s and it slows down with a uniform acceleration of -1.0 m/S/S.

to find,

the displacement after 5.0s,    s=60m

the displacement after 10.0s,   s=80m

according to the equation of motion,

s=ut+1/2at^2

a) t=5second, u=16m/s

s=ut+1/2at^2

s= 16*5 + 1/2 (-1.6) 5^2

s=80-20

s=60m

b)t= 10second , u=16m/s

s=ut+1/2at^2

displacement s=16*10 + 1/2 (-1.6)*10^2

displacement s=80m

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A motorcycle traveling at 25 m/s accelerates at a rate of 7.0 m/s2 for 6.0 seconds. What is the final speed of the motorcycle?

Answers

The final speed of the motorcycle is 67m/s

The first equation of motion deals with final velocity or speed, initial velocity  (velocity of the object before the effect of acceleration), acceleration (the rate of change of velocity with respect to time) and time. To find out the final speed or velocity of the motorcycle we will use the first equation of motion v = u + at , where

v = final velocity

u = initial velocity

a = acceleration

t = time, put the given values in the equation,

v = 25 + 7.0(6.0)

v = 25 + 42

v = 67 m/s

Thus the final speed of the motorcycle is 67m/s.

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A stone propelled from a catapult with a speed of 50m|s attains a height of 100m. Calculate:
a) the time taken
(b) the angle of projectile
(c) the range attained​

Answers

For the projectile motion of the stone a) The time taken T = 9.04s b) the angle of the projectile = 62.31° c) the Range attained R = 209.923m

A stone propelled from a catapult is an example of projectile motion.

Given, the initial velocity of the stone u = 50 m/s; This initial velocity with which the stone is thrown has two components 1) vertical [tex]u_{y}[/tex] = u sinθ along the Y axis and 2) horizontal [tex]u_{x}[/tex]=u cosθ along the X axis

where θ is the angle of projection

maximum vertical displacement or height attained by stone = H

(Use sign convention +ve for upwards and -ve for downwards)

a) equation for the maximum vertical height reached by a body during projectile motion   [tex]H=\frac{u^{2} sin^{2}\theta }{2g}[/tex]      (1)

equation for the time of flight of projectile motion [tex]T=\frac{2usin\theta}{g}[/tex]           (2)

Given H = displacement in the y direction = height attained = 100m

u =  initial velocity = 50m/s ; acceleration due to gravity g =9.8 m/[tex]s^{2}[/tex]

using equation (1)

[tex]100=\frac{50^{2}sin^{2}\theta }{2*9.8}[/tex]

⇒[tex]sin^{2} \theta= \frac{100*2*9.8}{50^{2} }[/tex]

⇒sinθ[tex]=\sqrt{\frac{10*2*9.8}{50^{2} } }[/tex]

⇒sinθ = 0.885437

⇒θ = [tex]sin^{-1} (0.885437)[/tex]

⇒θ = 62.31°

Hence  from equation (2) time of flight

[tex]T=\frac{2*50*sin\theta}{9.8}[/tex]

⇒[tex]T=\frac{2*50*0.885437}{9.8}[/tex]

⇒T = 9.04 s

Time is taken T =9.04s

b) Angle of projectile θ = 62.31°

c) The range attained [tex]R=\frac{u^{2}sin2\theta }{g}[/tex]

⇒[tex]R = \frac{50^{2}sin(2*62.31)}{9.8}[/tex]

⇒R = [tex]\frac{50^{2}*0.8229}{9.8}[/tex]

⇒R= 209.923m

horizontal range attained R= 209.923m

Components of a projectile motion:

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Which theoretical physicist, cosmologist, and author said, "however difficult life may seem, there is always something you can do and succeed at"?.

Answers

Professor Hawking .

Professor Stephen  Hawking said that "however difficult life may seem, there is always something you can do and succeed at".

Who is Stephen Hawking?Stephen Hawking was widely regarded as one of the greatest theoretical physicists of all time. His work on the origins and structure of the universe, from the Big Bang to black holes, revolutionized the field, and his best-selling books drew readers who did not have Hawking's scientific background."It is possible." These were the final words of physicist Stephen Hawking's message, which was sent to a black hole after his death in 2018. The European Space Agency shared Hawking's narration in a soul-shaking video today to commemorate the 50th anniversary of Earth Day.

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Amber walked to the swimming pool, stopping to talk to Maria on her way there.
Amber walked at a constant speed of 100 m/min for the first four minutes; then she
visited with Maria for three minutes; then walked for two more minutes at a constant
speed of 75 m/min. In words, describe how a distance-versus-time graph of Amber's
progress would look.

Answers

Answer:

Amber use 25m for looking

Answer:

25 min's, that's what Amber used

a 1.0 kg is dropped from a height of 6.0m. at what height is the rock's kinetic energy twice its potential energy?

Answers

Answer:

2.0m

Explanation:

Hello, I am currently stuck on this question and I am very confused as to how to solve it, may I have some help?

Answers

Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as

F = Gm1m2/r^2

where

F is the force in Newton

G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2

m1 and m2 are the masses in kg

r is the distance in meters

From the information given,

r = 1.5

acceleration = 2cm^2/s

Recall, 100 cm = 1m

2 cm = 2/100 = 0.02m

Thus,

acceleration = 0.02m/s^2

Since the masses are identical, then m1 = m2

Each of them is accelerating at 0.02m/s^2

Recall,

Force = mass x acceleration

Force = m1 x 0.02 = 0.02m1 N

By substituting the given values into the formula, we have

0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2

m1 on the left cancels out one m1 on the right. It becomes

0.02 = (6.673 x 10^-11 x m1)/1.5^2

By crossmultiplying,

0.02 x 1.5^2 = 6.673 x 10^-11 x m1

0.045 = 6.673 x 10^-11 x m1

m1 = 0.045/6.673 x 10^-11

m1 = 6.74 x 10^8 kg

The mass of each ball is 6.74 x 10^8 kg

The input force of 11 N acting on the effort arm of a lever moves 0.4 m, which lifts a 40 N weight resting on the resistance arm a distance of 0.1 m.What is the efficiency of the machine

Answers

ANSWER:

90.9%

STEP-BY-STEP EXPLANATION:

Given:

Input force = 11 N

Distance 1 = 0.4 m

Weight = 40 N

Distance 2 = 0.1 m

We calculate the work in each case to then calculate the efficiency of the machine, just like this:

[tex]\begin{gathered} W_1=11\cdot0.4=4.4\text{ J} \\ W_2=40\cdot0.1=4\text{ J} \\ \text{ Therefore:} \\ e=\frac{W_2}{W_1}\cdot100 \\ e=\frac{4}{4.4}\cdot100 \\ e=90.9\% \end{gathered}[/tex]

The efficiency of the machine is 90.9%

1. A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle . Describe how the force components change as the angle increases from 0° to 90° and use your graph to explain your answer. Give a detailed explanation of the forces at . Show a sample calculation at one angle for both components.

Answers

The variation of the components of the force with the angle of inclination of the direction of the applied force, as shown in the graph indicates that the Fₓ has a maximum, while [tex]F_y[/tex] has a minimum value given by Fₓ = 50 N × cos(0°) = 50 N, and [tex]F_y[/tex] = 50 N × sin(0°) at θ = 0°, while at 45°, Fₓ = [tex]F_y[/tex], with [tex]F_y[/tex] having a maximum value of 50 N, and Fₓ = 0 at 90°.

What is a component of a force?

The component of a force are the mutually perpendicular forces to which a force acting at an angle, relative the coordinate axis can be resolved into.

The component of the force applied by the man to the force required to move the box in the horizontal direction, Fₓ, increases as the angle approaches zero, and decreases as the angle approaches, 90°, given that the horizontal component of the force is found from the equation, [tex]F_x = F \times cos(\theta)[/tex], where, [tex]\theta[/tex] is the angle the line of action of the force makes with the horizontal, and F, is the force the man applies' such that we have at θ = 0°, Fₓ = 50 N × cos(0°) = 50 N

When the angle is θ = 45°, Fₓ = 50 N × cos(45°) = 25·√2 N

When the angle θ = 90°, Fₓ = 50 N × cos(90°) = 0

The vertical component of the force applied [tex]F_y[/tex], however, increases as the angle made by the line of force with the horizontal, increases to 90°, as shown in the graph, and decreases to 0 as the inclination angle of the force decreases, such that the have:

When the angle made with the horizontal, θ = 0°, [tex]F_y[/tex] = 50 N × sin(0°) = 0

When the angle made with the horizontal, θ = 45°, [tex]F_y[/tex] = 50 N × sin(45°) = 25·√2 N

At θ = 90°, [tex]F_y[/tex] = 50 N × sin(90°) = 50 N

The graph of both components starts at 50 N and 0 N when θ = 0°, and both intersect when θ = 45°, while the values of the horizontal and vertical component changes, such that at 90°, the vertical force component is the largest.

Please see the attached graph.

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What is the independent variable of Measuring physical properties: the Tiny World

Answers

The independent variables of measuring physical properties are given below -

What is physical properties?

A physical properties in any property that is measurable, whose value describe a state of physical system.

The changes in the physical properties of a system can be used to describe its changes between the  momentary that state of

physical properties are often referred to as observables.

They are not modal properties.

Any variable that can be attributed a value without attributes a value to any to any other variables is called independent variables.

It is a variable that stands alone and isn't changed by other variables you are trying to measure.

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Consider two pieces of the same metal at the same temperature, but one piece is a higher mass than the other. Which piece of metal has more thermal energy?.

Answers

Answer:

The one that has higher mass

Bus A and Bus B leave school on a field trip when a stopwatch reads zero. Bus A travels at a constant 50 km/h, and Bus B travels at a constant 75 km/h. How far are the two buses from school when the stopwatch reads 1.5 h? a. Bus A is 76.5 km from school, Bus B is 51.5 km from school c. Bus A is 75 km from school, Bus B is 112.5 km from school b. Bus A is 112.5 km from school, Bus B is 75 km from school d. Bus A is 51.5 km from school, Bus B is 76.5 km from school

Answers

Answer:bus

Explanation:

a 50.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 n. for the first 11.0 m the floor is frictionless, and for the next 10.0 m the coefficient of friction is 0.20. part a what is the final speed of the crate after being pulled these 21.0 m?

Answers

The final speed of the crate after being pulled these 21.0 m is 12.34  m/sec.

What is speed?

Speed is defined as the SI unit of speed is m/s and is calculated as the product of distance to time.

Mass = 50 kg

Horizontal force = 225 N

Coefficient of friction = 0.20

ΔK1 = F x D1

ΔK1 = 225 x 11

ΔK1 = 2475 J

ΔK2 = F X D2 - umgD2

ΔK2 = 225 x 10 - 0.20 x 50 x 9.8 x 10

ΔK2 = 2250 - 980

ΔK2 = 1270 J

Therefore ,

ΔK = ΔK1 + ΔK2

ΔK = 2475 + 1270

ΔK = 3745 J

As per kinetic equation

KE = 1/2 mv²

3745 = 1/2 x 50 x v²

v² = 149.8

v = 12.34 m/sec

Thus, the final speed of the crate after being pulled these 21.0 m is 12.34  m/sec.

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A ball is released from rest and falls 125 meters in 5 seconds. What was the magnitude of its acceleration?

Answers

The magnitude of the acceleration of the ball is 10 m/s².

What is acceleration of an object?

The acceleration of an object is the change in the velocity of the object with time.

The acceleration of the object is calculated using the following kinematic equation as shown below,

h = vt + ¹/₂at²

where;

h is the height of the objecta is the acceleration of the objectt is the time of motionv is the initial velocity of the ball = 0

Substitute the given parameters and solve for the acceleration of the ball.

125 = 0 +  ¹/₂a(5)²

2(125) = 25a

250 = 25a

a = 250/25

a = 10 m/s²

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In the district soccer championship finals, elizabeth kicks a 0.57 kg soccer ball with a force of 22.8 n. how much does she accelerate the soccer ball from rest in the process?

Answers

acceleration a = F/M therefore acceleration the soccer ball from rest in the process is 40 m/s².

Given

mass of soccer ball, M = 0.57 kg

Force F = 22.8 n

acceleration a = F/M

a = 22.8 n/ 0.57 kg

a = 40m/s²

We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both as velocity is a function of both speed and direction. When two things are moved against one another, instant friction results. The motion will be opposed by the friction, who will also be working against it. When an item is in motion and its velocity changes, the concept of acceleration takes place. Friction, which opposes motion, always lowers acceleration. An object and a surface come into contact and cause friction. The features of the surface and the item as well as whether or not the object is moving determine its magnitude.

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light travels through water with a speed of 2.25x10⁸ m/s. What is refractive index?​

Answers

The refractive index of water is 1.3

Find the refractive index of water.

Lightspeed in water [tex]V_water}[/tex]= 2.25*10^8 m/s

We know that,

Speed of light in vaccum [tex]V_{vaccum}[/tex]=3*10^8 m/s

µ=[tex]\frac{C}{V_{m} }[/tex]

where,

µ= refractive index

C= speed of light in air/vaccum

[tex]V_{m}[/tex]=speed of light in any medium

µ=[tex]\frac{3*10^8 m/s}{2.25*10^8 m/s}[/tex]

µ=1.3

Hence, the refractive index of water is 1.3

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