PLS HELP The average atomic mass of carbon is 12.01 amu. Based on the atomic
masses of the two isotopes of carbon, how do the relative abundances of the
isotopes compare?

Answer:

See explanation and image attached

Explanation:

The reaction between benzophenone and phenylmagnesium bromide is a Grignard reaction.

A Grignard reagent is any alkyl magnesium halide compound. In this case, the Grignard reagent is phenylmagnesium bromide.

Reaction of Grignard reagent with a ketone yields all alcohol. Thus, the reaction of benzophenone with phenylmagnesium bromide yields triphenyl methanol.

The mechanism of the reaction and all electron movements are shown in the image attached to this answer.

Answer:

H

Explanation:

try not to put your hands on him

Answer:

Sound travels through the air in approximately 332 metres per second?

Explanation:

is this what you are looking for>

Answer:

Wearing goggles or other eye protection will remove the risk or danger for these students

Explanation:

Soft contact lenses are usually worn in the eyes and Ammonia compound may fog the lens thereby retaining the particles of ammonia which could spread to the eye and cause a lot of damage to it.

Using a goggle is usually more effective in dealing with the risks involved as they prevent the Ammonia from having any contact at all with the eyes due to the far proximity to the eyes when compared to contact lenses.

Answer:

[tex]T_F=77.4\°C[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

[tex]Q_1=-Q_2[/tex]

In terms of mass, specific heat and temperature change is:

[tex]m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)[/tex]

Now, solve for the final temperature, as follows:

[tex]T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}[/tex]

Then, plug in the masses, specific heat and temperatures to obtain:

[tex]T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C[/tex]

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

Answer:

pa helpppp

Explanation:

pleseee need answerrrr

The correct relations for exothermic and endothermic reactions from the given relations is  H Products > H Reactants in exothermic reactions. Hence, Option (D) is Correct.

In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative." Exothermic reactions usually release heat.

Therefore, The correct relations for exothermic and endothermic reactions from the given relations is  H Products > H Reactants in exothermic reactions. Hence, Option (D) is Correct.

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Answer:

Rust forms on iron filings faster than on a large iron block

Explanation:

Because the surface area exposed to air in the refrigerator is greater than its area by mass, the rust-forming reaction occurs faster.

Answer:

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Explanation:

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Answer:

C. 2.70 g/mL

Explanation:

Density is the ratio between the mass of a substance and the volume it occupies. Based on Archimedes' volume, the displaced volume of the aluminium is the volume it occupies. To solve this question we must find the difference in volume between initial volume of water = 30mL and final volume of water + aluminium = 39.26mL. This difference is the volume of the aluminium. With its mass we can find density:

39.26mL - 30mL = 9.26mL

Density = 25.00g / 9.26mL =

2.70g/mL

Right answer is:

Answer:

B

Explanation:

C and D is correct

To be clear that electrochemical is science that study the exchange conversion of chemical energy and electric energy through redox reaction

As c is salt bridge

And d is electrochemical define

A is correct as the electricity transfer in electric wire not in solution so its B) un correct

The statement which is not true about the electrochemical cell is option B, the metals that form the electrodes cannot be identical.

In an electrochemical cell, two different metals or metal ions are typically used as the electrodes. These electrodes are placed in separate compartments, which contain the reaction solutions and are connected by a salt bridge or porous membrane.

During the cell's operation, electrons flow through an external wire or circuit, from the anode (where oxidation occurs) to the cathode (where reduction occurs), and nonparticipating ions flow through the salt bridge or porous membrane to maintain charge neutrality.

An oxidation-reduction reaction must occur to generate an electrical potential difference between the two electrodes, driving the flow of electrons through the external circuit. Therefore, options A, C, and D are true for an electrochemical cell. Hence, B is incorrect.

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Answer:

[tex]1 {s}^{2} 2 {s}^{2} 2 {p}^{4} [/tex]

OR

[tex]2 : 6[/tex]

Answer:

If we look at the ground state (electrons in the energetically lowest available orbital) of oxygen, the electron configuration is [tex]1s^{2} 2s^{2} 2p^{4}[/tex] . If the element were to become excited, the electron could occupy an infinite number of orbitals. However, in most texts, the example will be the next available one. So for oxygen, it might look like this:  [tex]1s^{2} 2s^{2} 2p^{3}3s^{1}[/tex]  - where the valence electron now occupies the 3s orbital in an excited (i.e. not ground) state.

So, the electron configuration of oxygen in its excited state​ is [tex]1s^{2} 2s^{2} 2p^{3}3s^{1}[/tex].

Answer: hello your question has some missing data attached below is the complete question.

answer:

attached below

Explanation:

Attached below is the mechanism for proton transfer

a) HBr

H₃O + Br⁻

b) attached below

c) attached below

Answer: The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Explanation:

There are 4 quantum numbers:

Berylium (Be) is the 4th element of periodic table having electronic configuration of [tex]1s^22s^2[/tex]

For first electron:

[tex]n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}[/tex]

For second electron:

[tex]n=1\\l=0\\m=0\\s=-\frac{1}{2}[/tex]

For first electron:

[tex]n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}[/tex]

For second electron:

[tex]n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}[/tex]

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Answer:

to remove any remaining 2,4-dinitrophenylhydrazone

Explanation:

Usually, when an organic compound is synthesised, traces of impurities such as excess reagents or solvent remain in the product.

It is therefore imperative that these contaminants are removed so that the product can attain a very high degree of purity.

Hence, during the synthesis of 2,4-dinitrophenylhydrazone derivative, 10 mL of 2 M hydrochloric acid is titrated against the crude product so that any remaining 2,4-dinitrophenylhydrazone is removed.

Answer:

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Explanation:

Explanation:

The atomic number is equal to the number of protons in an atom's nucleus. Hydrogen's atomic number is 1 because all hydrogen atoms contain exactly one proton.

Answer:

the Rhyniognatha hirsti

Explanation:

at age 400 million years old

Answer: The bond present in given compounds is as follows-

Explanation:

An ionic bond is always formed between a metal and a non-metal atom.

For example, MgF has metal magnesium and non-metal fluorine. So, an ionic bond is there in the compound MgF.

When sharing of electrons occur between atoms of different electronegativity then the bond formed is called a polar covalent bond.

For example, C-O has a polar covalent bond.

For example, Cl-Cl is a non-polar covalent bond.

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Answer:

Solubility indicates the maximum amount of a substance that can be dissolved in a solvent at a given temperature. Such a solution is called saturated. Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solubility of solute:

To calculate the solubility in g/100g:

Solubility of NaNO₃=[tex]\frac{21.9g*100g}{25 g} =87.6[/tex]

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Answer: pH = 2,897 , basic[tex][H+][OH-] = 10^{-14} ==> [H+] = \frac{10^{-14}}{7,89*10^{-12} } =\frac{1}{789} \\pH= -lg([H+]) = 2,897 \\pH<7 ==> basic[/tex]

Explanation:

Answer:

The maximum theoretical percent recovery from the recrystallization of 1.00 g of benzoic acid from 15 mL of water = 94.9%

Note: The question is incomplete. A similar but complete question is given below:

The solubility of benzoic acid in water is 6.80g per 100mL at 100 degrees C and 0.34 g per 100mL at 25 degrees C.

Calculate the maximum theoretical percent recovery from the recrystallization of 1.00 g of benzoic acid from 15 mL of water, assuming the solution is filtered at 25 degrees C.

Explanation:

Solubility of benzoic acid in water at 100 degrees C = 6.80g per 100mL

Solubility of benzoic acid in water  at 25 degrees C =  0.34 g per 100mL

Mass of benzoic acid to be theoretically recovered from 100 mL of water = 6.80 g - 0.34 g = 6.46 g

At 25 degrees;

0.34 g of benzoic acid is present in 100 mL of water

x g of  benzoic acid will be present in 15 mL of water

x = 0.34 × 15 / 100 = 0.051 g

Mass of benzoic acid to be theoretically recovered from 25 mL of water = 1.00 g - 0.051 g = 0.949 g

Maximum theoretical percent recovery = (mass recovered / original mass dissolved) x 100%

Maximum theoretical percent recovery =  (0.949 / 1.00) × 100% = 94.9 %

Therefore, the maximum theoretical percent recovery from the recrystallization of 1.00 g of benzoic acid from 15 mL of water = 94.9%

Answer:

Chlorine gas reacts with potassium bromide to form potassium chloride in solution and liquid bromine.

Answer:

DDDDD

Explanation:

Answer:

Talc powder suspended in air

Answer: 26 moles of [tex]PH_3[/tex] are required for the reaction.

Explanation:

We are given:

Moles of [tex]P_4O_{10}[/tex] = 6.5 moles

The given chemical reaction follows:

[tex]4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)[/tex]

By the stoichiometry of the reaction:

If 1 mole of [tex]P_4O_{10}[/tex] is produced by 4 moles of [tex]PH_3[/tex]

So, 6.5 moles of [tex]P_4O_{10}[/tex] will be produced by = [tex]\frac{4}{1}\times 6.5=26mol[/tex] of [tex]PH_3[/tex]

Hence, 26 moles of [tex]PH_3[/tex] are required for the reaction.

Answer:

[tex]m_{KMnO_4}=90.9gKMnO_4[/tex]

Explanation:

Hello there!

In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:

[tex]m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2} *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4[/tex]

Regards!

Answer:

The more concentrated acetic acid buffer has a better buffer capacity because requires more moles of acid or base to change the pH than a more diluted acetic acid buffer.

Explanation:

Buffer capacity is defined as the moles of an acid or base that are needed to change the pH of a buffer in 1 unit.

A more concentrated solution of acetic buffer contains more moles of the acid per liter of solution. A solution that contains more moles of the acetic ion or the acetic acid requires more moles of base or acid to change the pH, that means:

The more concentrated acetic acid buffer has a better buffer capacity because requires more moles of acid or base to change the pH than a more diluted acetic acid buffer.

Answer:

Q was < K. Partial pressure of hydrogen decreased, iodine increased

Explanation:

After iodine was added the Q was [Select] K so the reaction shifted toward the Products [Select] ,The partial pressure of hydrogen [Select], Iodine [Select] |,and hydrogen iodide Decreased

Based on the equilibrium:

H2(g) + I2(g) ⇄ 2HI(g)

K of equilibrium is:

K = [HI]² / [H2] [I2]

Where [] are concentrations at equilibrium

And Q is:

Q = [HI]² / [H2] [I2]

Where [] are actual concentrations of the reactants.

When the reaction is in equilibrium, K=Q.

But as [I2] is increased, Q decreases and Q was < K

The only concentration that increases is [I2], doing partial pressure of hydrogen decreased, iodine increased