PLEASE HELP IT’S DUR TMR

Answer:

2 is the correct answer

Answer:

B)120º

Step-by-step explanation:

70+50=x

120=x

Sum of two interior angles=exterior angle

[tex]\\ \sf\longmapsto 50+70=x[/tex]

[tex]\\ \sf\longmapsto x=120[/tex]

Option B

Answer:

Any number in the form of p/q where p and q are integers and q is not equal to 0 is a rational number.

So, 323.2685109 is IRRATIONAL number.

Answer:

1/4

Step-by-step explanation:

Slope = (change in the y-values)/(change in the x-values)

Slope = (4 - 2)/(1 - (-7) )

Slope =  (4 - 2)/(1 + 7)

Slope = 2/8

Slope = 1/4

Answer:

7!!

Step-by-step explanation:

Answer:

Step-by-step explanation:

A= W*L

A= 31/3*21/4

A=10.3*5.25

A=54.075cm^2

Answer:

7 1/2in^2

Step-by-step explanation:

LxW=A

2 1/4 x 3 1/3 = A

A = 7 1/2

Answer:

i think the answer is 171,500 i don't know i am trying.

Step-by-step explanation:

first you multiply 35 times 3 you will get 85,750 then you multiply 10 times 2 you will 20 and multiply both of them and you will get 171,500.

Answer:

our vertex for f(x) = 3x² + 18x + 32 = (-3, 5 )

Step-by-step explanation:

let me write the standard form of a quadratic equation

[tex]a {x}^{2} + bx + c[/tex]

Now let me rewrite the original equation

[tex]3 {x}^{2} + 18x + 32[/tex]

Now we use this simple formula to find the vertex (h, k)

[tex]x = h = - \frac{b}{2a} \\ = - \frac{18}{2(3)} = - \frac{18}{6} = - 3 \\ h = - 3[/tex]

substitute -3 for x back into our original equation to solve for y our k value of our vertex

[tex]y = 3 ({ - 3})^{2} + 18( - 3) + 32 \\ = 3(9) - 54 + 32 \\ = 27 + 32 - 54 \\ = 59 - 54 \\ k = 5[/tex]

our vertex for f(x) = 3x² + 18x + 32 = (-3, 5 )

Simple the answer is: n=14

Answer:

Step-by-step explanation:

Use the given formula and substitute the value of x:

f(1)

Done

Answer:

1st: $50 2nd: $250 3rd: $85

Answer:

(f ∘ g) (3) = 22

Step-by-step explanation:

f( x + 3x - 5; g (x) = x² ∴ g ( 3 ) = 3² = 9

( f ∘ g ) ( 3 ) = f(g(3)) = f ( 9 ) =  3 · 9 - 5 = 27 - 5 = 22 [Ans]

Answer:

Answer 1 is 4:2 or also write as 2:1.

Answer:

Every point of a number line is assumed to correspond to a real number, and every real number to a point. The integers are often shown as specially-marked points evenly spaced on the line.

Answer:

Emily has a higher relative score since her z-score is higher. This would mean she scored further above the mean than Xiaoyu.

Step-by-step explanation:

Find the z-scores by subtracting the score they got by the mean and then dividing by the standard deivation of their respective exams.

Xiaoyu:

z = [tex]\frac{27 - 18}{6}[/tex] = 1.5

Emily:

z = [tex]\frac{720 - 500}{100}[/tex] = 2.2

______

Emily has a higher relative score since her z-score is higher. This would mean she scored further above the mean than Xiaoyu.

Answer:

If you mean percent, its 350%

Answer:

1134

Step-by-step explanation:

1134/63=18

Answer: 1/4

Given : On average, Carson spends about 26% of his allowance each month on candy and soft drinks.  

To Find : When creating a circle graph of what Carson does with his money, which of the following fractions would be the best to represent how much he spends on food?

If these are your Choices:

A) 1/4

B) 1/3

C) 3/4

D) 1/2

Solution:

To Convert fraction into % multiply by 100  

(1/4) * 100 = 25 %

(1/3) * 100  = 33.33 %

(3/4) * 100 = 75 %

(1/2) * 100 = 50 %

Therefore 1/4 fraction best represent how much he spends on food

Answer:

64, -64, -64

-27, 27, 27

Step-by-step explanation:

If x = 4,

x³ = 4³ = 64

-x³ = -4³ = -64

(-x)³ = (-4)³ = -64

If x = -3,

x³ = -3³ = -27

-x³ = -(-3)³ = 27

(-x)³ = (-(-3))³ = 27

Answer:

12

Step-by-step explanation:

the answer is just 12.

Answer:

see explanation

Step-by-step explanation:

substitute the values of x in the table into g(x)

Using the rule of exponents

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

g(- 2) = [tex]4^{-2}[/tex] = [tex]\frac{1}{4^{2} }[/tex] = [tex]\frac{1}{16}[/tex]

g(- 1) = [tex]4^{-1}[/tex] = [tex]\frac{1}{4}[/tex]

g(0) = [tex]4^{0}[/tex] = 1

g(1) = [tex]4^{1}[/tex] = 4

g(2) = 4² = 16

Answer:

no, it is incorrect it is 1-100 the value

Step-by-step explanation:

0.006×10= 0.06

0.006×100=0.6

Answer:

15×15×16=3600

15×15=225

225×16=3600

Answer:

N0O0O0O0O0O0O0O0O0O0O

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

Given function is

[tex]\rm \longmapsto\:f(x) = \dfrac{1}{ \sqrt{ |cosx| + cosx} } [/tex]

Now,

[tex]\rm \longmapsto\:f(x) \: is \: defined \: if \: |cosx| + cosx > 0[/tex]

We know,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |x| = \begin{cases} &\sf{ - x \: \: when \: x < 0} \\ \\ &\sf{ \: \: x \: \: when \: x \geqslant 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |cosx| + cosx = \begin{cases} &\sf{ \: \: 0 \: \: when \: cosx \leqslant 0} \\ \\ &\sf{ \: \: 2 \: cosx \: \: when \: cosx > 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\rm\implies \:f(x) \: is \: defined \: when \: cosx > 0[/tex]

So, from graph we concluded that cosx > 0 in the following intervals.

[tex]\begin{gathered}\boxed{\begin{array}{c|c} \bf cosx & \bf \: x \: \in \: \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf + ve & \sf \bigg( - \dfrac{\pi}{2} ,\dfrac{\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{3\pi}{2} ,\dfrac{5\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{7\pi}{2} ,\dfrac{9\pi}{2} \bigg) \end{array}} \\ \end{gathered}[/tex]

So, if we generalized this we get

[tex]\rm\implies \:cosx > 0 \: when \: x \: \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z[/tex]

Hence,

Domain of the function is

[tex]\red{\rm\implies \boxed{\tt{ \: x \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z}}}[/tex]

[tex]\textsf{More to know :-} \\[/tex]

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf T-eq & \bf Solution \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf sinx = 0 & \sf x = n\pi \: \forall \: n \in \: Z\\ \\ \sf cosx = 0 & \sf x = (2n + 1)\dfrac{\pi}{2}\: \forall \: n \in \: Z\\ \\ \sf tanx = 0 & \sf x = n\pi\: \forall \: n \in \: Z\\ \\ \sf sinx = siny & \sf x = n\pi + {( - 1)}^{n}y \: \forall \: n \in \: Z\\ \\ \sf cosx = cosy & \sf x = 2n\pi \pm \: y\: \forall \: n \in \: Z\\ \\ \sf tanx = tany & \sf x = n\pi + y \: \forall \: n \in \: Z\end{array}} \\ \end{gathered}\end{gathered}[/tex]

The upper bound means the highest number that you can round up to the nearest unit, in this case meters. So the upper bound for the distance of 100 meters is 100.4 meters.

Answer:

bye

Step-by-step explanation: