PLEASE HELP!!! DUE BY THE END OF NIGHT (LOOK AT PICTURE PLEASE)

Answer:

it's x^2+2x-8

Step-by-step explanation:

-4<x<2. I don't know how to explain since I'm not good at English

[tex]q = \frac{gx {}^{2} - px + 2}{x} \\ [/tex]

[tex]p= \frac{gx {}^{2} - qx + 2}{x} [/tex]

The sequence converges to 5 as n goes to ∞. We can prove this rigorously:

The claim is that, for [tex]n\in\Bbb N[/tex],

[tex]\displaystyle \lim_{n\to\infty} \frac{5n-1}{n+1} = 5[/tex]

By definition of the limit, this means for any ε > 0, there exists some N such that for any n larger than N, we have

[tex]\left| \dfrac{5n-1}{n+1} - 5 \right| < \varepsilon[/tex]

In order to ensure this inequality, we work backwards to find N in terms of ε :

[tex]\left| \dfrac{5n-1}{n+1} - 5 \right| = \left| \dfrac{5n-1 - 5(n+1)}{n+1} \right| = \dfrac4{|n+1|} < \varepsilon[/tex]

n is a natural number, so n + 1 > 0 and |n + 1| = n + 1. Then

[tex]\dfrac4{n+1} < \varepsilon \implies \dfrac{n+1}4 > \dfrac1\varepsilon \implies n+1 > \dfrac4\varepsilon \implies n > \dfrac4\varepsilon - 1[/tex]

Let N be the smallest natural number greater than or equal to 4/ε - 1, i.e.

[tex]N = \left\lceil \dfrac4\varepsilon - 1 \right\rceil[/tex]

Then the proof follows: suppose

[tex]n \ge N = \left\lceil \dfrac4\varepsilon - 1 \right\rceil[/tex]

Then

[tex]n \ge \left\lceil\dfrac4\varepsilon - 1\right\rceil \implies n > \dfrac4\varepsilon - 1 \\\\ \implies n+1 > \dfrac4\varepsilon \\\\ \implies \dfrac4{n+1} < \varepsilon \\\\\implies \left|\dfrac{5n-1}{n+1}-5\right| < \varepsilon[/tex]

as required.

Or we can avoid the rigor and use some facts we know about limits:

[tex]\displaystyle \lim_{n\to\infty} \frac{5n-1}{n+1} = \lim_{n\to\infty} \frac{5-\frac1n}{1+\frac1n} = 5[/tex]

since 1/n converges to 0 as n goes to ∞.

The attributes to each three-dimensional shape that has the cross-section is 4,16 and 4.

Any closed figure made by 4 line segments joined end to end in series is called a quadrilateral.

That quadrilateral in which opposite sides are parallel is called a parallelogram.

Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

Given;

Quadrilateral A: area of 16 square inches

Quadrilateral B: perimeter of 24 inches

Quadrilateral C: perimeter of 16 inches

Now,

Quadrilateral A:

a^2=16

a=4

Quadrilateral B;

4a=24

a=6

Quadrilateral C:

4a=16

a=4

Therefore, the answers of quadrilaterals will be 4,6 and 4.

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Answer: The mean of the data is 278.

Step-by-step explanation:

To the the mean of the data, we’ll have to add all the numbers up and divide it by the amount of data.

275+279+279+276+278+277+280+282+284+270=2780

2780/10=278

Answer:

4

Step-by-step explanation:

Answer:

about 2827cm^3

Step-by-step explanation:

you are looking for the area  

4*pi*r^2

4*pi*15^15

pi*4*225

pi*900

2827.43

Answer: 155°

Step-by-step explanation:

The supplement of 25° is the angle that when added to 25° forms a straight angle (180°).

180°−25°

Subtract 25 from 180.

155°

Hope this helps!

The exponential function that represents a stretch of a decay function is given as follows:

[tex]f(x) = \frac{5}{4}\left(\frac{4}{5}\right)^x[/tex]

An exponential function is modeled by:

[tex]y = ab^x[/tex].

In which:

It represents a stretch if a > 1, and a decay function if b < 1. Researching the problem on the internet, the correct option is given as follows:

[tex]f(x) = \frac{5}{4}\left(\frac{4}{5}\right)^x[/tex]

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Answer:

the answer is C :)

Step-by-step explanation:

Answer:

The amplitude is the highest point that the curve reached

Which is in your case = 2

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[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Given question:-}}}}[/tex]

         11z-6=16, what is z?

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}[/tex]

We need to make sure that all variables are on the left-hand side and the numbers are on the right-hand side.

Since we have a number on the left-hand side, we need to move it to the right-hand side with the opposite operation:-

11z=16+6

[tex]\it{11z=22}[/tex]

Divide by 11 on both sides:-

[tex]\it{z=2}[/tex]

We can check our solution by replacing z with 2 and seeing whether or not we end up with a true statement:-

[tex]\it{11(2)-6=16}[/tex]

[tex]\it{22-6=16}[/tex]

[tex]\it{16=16}[/tex]

So we conclude that our solution, z=2, is correct.

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Answer:

z=2

Step-by-step explanation:

11(2)-6=16

22-6=16

Answer:

7x+2y=18

The first one

Step-by-step explanation:

The equation to be perpendicular switches they numbers before the x and y. Also plugging into a graphing calculator like desmos will show you
that

The THREE statements that would produce the truth value F when p is true and q is false are (a) p → q (b) ¬ p ∧ ¬ q (d) q ∨ ¬ p

To do this, we simply analyze each option

The given parameters are:

p = true

q = false

(a) p → q

This means that:

If p then q

So, we have:

If true then false

The above statement would return false.

(b) ¬ p ∧ ¬ q

This means that:

If not p and not q

So, we have:

If not true and not false

i.e.

If false and true

The above statement would return false.

(c) p → ¬ q

This means that:

If p then not q

So, we have:

If true then not false

i.e.

If true then true

The above statement would return true.

(d) q ∨ ¬ p

This means that:

If q and not p

So, we have:

If false and not true

i.e.

If false and false

The above statement would return false.

Hence, the THREE statements that would produce the truth value F when p is true and q is false are (a) p → q (b) ¬ p ∧ ¬ q (d) q ∨ ¬ p

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Answer:

I worked it out and got C as my answer

Answer:

First one is the answer of the question u asked

Answer:

Option a: ∑⁵(n−1)! is the correct answer.

n=²

Step-by-step explanation:

Option a: ∑n=25(n−1)

By substituting the values of n and expanding the summation, we have,

(2−1)!+(3−1)!+(4−1)!+(5−1)!

Subtracting, we have,

1!+2!+3!+4!

Expanding the factorial,

1+(2∗1)+(3∗2∗1)+(4∗3∗2∗1)

Simplifying, we get,

1+2+6+24

Thus, the summation ∑⁵ (n−1)! represents the

n=2

series 1+2+6+24

Hence, Option a is the correct answer.

Answer:

y=2x+8

Step-by-step explanation:

Move 4x to other side and divide everything by 2

The volume of the cone that has a radius of 8 in. and a height of 10.5 in. is: 703.7 in.³

Volume = 1/3πr²h

Given the parameters:

Volume of the cone = 1/3πr²h = 1/3π(8²)(10.5)

Volume of the cone = 1/3π(64)(10.5)

Volume of the cone = 703.7 in.³

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Answer:

224Pi inches cubed

Step-by-step explanation:

Builder can build 7 one bedroom houses and 5 two bedroom houses.

What is consistent Equation?

A linear or nonlinear system of equations is called consistent if there is at least one set of values for the unknowns that satisfies each equation in the system—that is, when substituted into each of the equations, they make each equation hold true as an identity.

Let x represents the number of one-bedroom houses and y represents the number of two bedroom houses.

According to Question,

Total number of houses is 12 i.e. x + y = 12..........(i)

Total we have 88 windows in which 6 windows can be use in one bedroom house and 9 windows can be used in two bedroom house so,

6x + 9y = 88 ..................(ii)

From Equation (i) and (ii), we get

x = 7 and y = 5

Thus, Builder can build 7 one bedroom houses and 5 two bedroom houses.

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Answer:

1. x = -6

2. x = 2

3. x = 6

4. x = 3

5. x = -5

6. x = -1

7. x = 0

8. x = 9

9. x = -4

10. x = 7

Step-by-step explanation:

1.

2.

3.

4.

5.

6.

7.

8.

9.

10.

Answer:

$0.01

Step-by-step explanation:

Family size rate (per cubic inch)

Regular size rate

Difference in price

Volume of family sized box

Price per inch

Volume of regular size

Price per in

Difference:-

|0.02-0.03|=0.01$

Answer:

-5<x<-3

Step-by-step explanation:

Hope this helps! ;-)

Answer:

b) 7 option B 7 is the answer

Step-by-step explanation:

bidmas rule:

7-2×3

2×3= 6

7-6=1

7×1= 7

therefore the answer is 7.

Answer: The answer is [tex]B. 7[/tex]

Step-by-step explanation:

[tex]7(7-2[/tex] × [tex]3)[/tex]

Simplify the expression.

[tex]7-2= 5[/tex]

[tex]7[/tex] × [tex]3[/tex] = [tex]21[/tex]

[tex]21[/tex] ÷ [tex]3=7[/tex]

Answer:

pls that's the answer to the question. thanks.

Answer:

Table B

Step-by-step explanation:

A function is present when x-value can only have a single y-value.

Answer and step-by-step explanation:

[tex]28v^3 +16v^2-21v-12 =[/tex] collecting [tex]4v^2[/tex] in the first two terms and [tex]-3[/tex] in the last two:

[tex]4v^2(7v+4)-3(7v+4) =[/tex] collecting the bracket

[tex](7v+4)(4v^2-3)[/tex]

Bonus stage: if you are factoring over the real numbers and not over the rational, the second brackets is a difference of squares. Else, you stop  here.

[tex](7v+4)(2v+\sqrt3)(2v-\sqrt3)[/tex]

NEXT!

[tex]49x^3-35x^2+56x-40=[/tex]As before, [tex]7x^2[/tex]in the first two, and [tex]8[/tex] in the last two:

[tex]7x^2(7x-5)-8(7x-5)[/tex] collecting the bracket again

[tex](7x-5)(7x^2-8) =[/tex]again, bonus step

[tex](7x-5)(\sqrt7 x +2\sqrt2) (\sqrt7x-2\sqrt2)[/tex]

FINALLY!

[tex]24r^3-64r^2-21r+56 =\\8r^2(3r-8) -7(3r-8)=\\(3r-8)(8r^2-7) =[/tex]Again, bonus step

[tex](3r-8)(2\sqrt2r+\sqrt7)(2\sqrt2r-\sqrt7)[/tex]

Since usually most courses talk about factorization of polynomials BEFORE talking about real numbers, I would stop at the third stage, skipping the fourth.

From the section formula, it was found that the coordinate for the point S is (12,21).

The coordinates of the point S which divides the line AB into two sections can be found from the application of the Section Formula that is presented below:

[tex]S=(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})[/tex], where

[tex]ratio=\frac{m}{n}[/tex]

[tex]x_1[/tex] and [tex]y_1[/tex] are coordinates of A

[tex]x_2[/tex] and [tex]y_2[/tex] are coordinates of  B

The question gives  r=[tex]\frac{3}{2}[/tex], A=(21,3) and B=(6,33). From the ratio, you can find m=3 and n=2.

Next step, applying the internal section formula. Then, you have:

[tex]S=(\frac{3*6+2*21}{3+2}, \frac{3*33+2*3}{3+2})\\ \\ S=(\frac{18+42}{5}, \frac{99+6}{5})\\ \\ S=(\frac{60}{5}, \frac{105}{5})\\ \\ S=(12, 21)[/tex]

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The integral of [tex]\int {x(25x^2 + 1)} \, dx[/tex] is [tex]\frac{25}{4}x^4 + \frac{x^2}{2} + C[/tex]

The integral expression is given as:

[tex]\int {x(25x^2 + 1)} \, dx[/tex]

Start by expanding the bracket

[tex]\int {25x^3 + x} \, dx[/tex]

Next, we integrate each term in the expression

[tex]\frac{25}{4}x^4 + \frac{x^2}{2} + C[/tex]

Hence, the integral of [tex]\int {x(25x^2 + 1)} \, dx[/tex] is [tex]\frac{25}{4}x^4 + \frac{x^2}{2} + C[/tex]

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