PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land

Answers

Answer 1

Answer:

Explanation:

It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.

s = s₀ + v₀t + ½at²

vertical analysis with floor level as origin

0 = 1.2 + 5t + ½(-9.8)t²

0 = 1.2 + 5t - 4.9t²

quadratic formula positive answer

t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))

t = 1.22 s is the flight time

horizontal analysis with launcher as origin

s = 0 + 12(1.22) + ½(0)1.22²

s = 14.6517... 15 m


Related Questions

Place the yellow, 25g ball at 60 cm on the ramp. How far did the box move? Measure from the left side of the box.

Answers

Answer: approximately 13-15 centimeters


A toy car is released from rest at the top of a ramp. The car
speeds up as it moves down the ramp. When it reaches the
bottom of the ramp, the toy car rolls across the floor and
eventually stops.
Which two statements identify evidence that energy was conserved?
A. As the car rolls down the ramp, it speeds up because gravitational
potential energy is transformed into kinetic energy.
B. As the car rolls down the ramp, it speeds up because thermal
energy due to friction is transformed into kinetic energy.
m C. As the car rolls across the floor, it stops because its kinetic
energy is transformed into gravitational potential energy,
1 D. As the car rolls across the floor, it stops because its kinetic energy
is transformed into thermal energy due to friction

Answers

Answer:

A and DDD

Explanation:

The two statements identify evidence that energy was conserved are, as the car rolls down the ramp, it speeds up because gravitational

potential energy is transformed into kinetic energy and as the car rolls across the floor, it stops because its kinetic energy is transformed into thermal energy due to friction, therefore the correct answer is option C.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

As given in the problem statement a  toy car is released from rest at the top of a ramp. The car speeds up as it moves down the ramp. When it reaches the bottom of the ramp, the toy car rolls across the floor and

eventually stops.

Thus, it speeds up because gravitational potential energy is transformed into kinetic energy and as the car rolls across the floor, it stops because its kinetic energy is transformed into thermal energy due to friction, therefore the correct answer is option C.

To learn more about mechanical energy here, refer to the link ;

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#SPJ5

feminine of mouse

please let me know​

Answers

Answer:

a Doe

A baby mouse is called a 'pinky', a male is called a 'buck' and a female is called a 'doe'.

(hope that helped)

I’m stuck
Why do I have to run

Answers

Answer: Because

Running can significantly improve physical and mental health. As a form of aerobic exercise, running can reduce stress, improve heart health, and even help alleviate symptoms of depression. Some researchers think running may be so good for us because it's something we evolved to do. lol

Explanation:

how is the shape of an object related to Bernoulli principle

Answers

Answer:

Again, in accordance with Bernoulli's principle, the shape of the airflow facilitates the spread of laminar flow around it. The slower-moving currents beneath the airfoil exert greater pressure than the faster currents above it, giving lift to the aircraft.

Explanation:

a squirrel is 5.0 m away from you while moving at a constant velocity of 3 m\s away from you, how far is the squirrel after 5 seconds?

Answers

Answer: distance travel after 5 seconds = 3×5 =15 m

so squirrel is away from me by distance of 15+ 5 = 20 m

Explanation:

Answer:

I believe 20 is the answer

Which of the following has the greatest momentum? (Hint: momentum = mass x velocity)

a. a 4.0 kg bowling ball moving at 2.0 m/s

b. a 0.15 kg baseball moving at 10.0 m/s

c. a 1.6 x 10^3 kg car moving at 0.5 m/s

d. a 2 kg bullet moving at 950 m/s

Answers

Answer:

therefore, the correct answer is Option D.

Explanation:

a. 4×2=8kgm/s

b. 0.15×10=1.5kgm/s

c. 1.6×10³×0.5=800kgm/s

d. 2×950=1900kgm/s.

hope this helps you

SI unit pf pressure is?

Answers

The SI unit for pressure is the pascal (Pa), equal to one newton per square metre (N/m2, or kg·m−1·s−2).

Pasquale pa there’s the answer

Which model represents a lot of conservation of mass?

Answers

The second one is it I think

Answer:

Only option 2 has the same number of oxygen and hydrogen atoms on each side of the arrow.

Explanation:

Where does the energy of a breaking wave originate?

Answers

Answer:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest.

Explanation:

Help me pls I need to turn this in quick!!!!

Answers

Answer:

C. When the waves overlap, they will cancel eanch other out and disappear

Explanation:

hope its help heart brainliest thnks

A light, inextensible cord passes over a light,
frictionless pulley
with a radius of 7.2 cm
It has a(n) 16 kg mass on the left and a(n)
6.7 kg mass on the right, both hanging freely.
Initially their center of masses are a vertical
distance 4.2 m apart.
The acceleration of gravity is 9.8 m/s^2

The question tied to it is…

What is the tension
in the cord when they
pass each other?
Answer in units of N.

Answers

Answer:          T = 93 N

Explanation:

Assuming the pulley is ideal meaning frictionless as mentioned and also negligible mass.

         ΣF = Σma

Mg - mg = Ma + ma

           a = g(M - m) / (M + m)

Now looking only at the larger mass as it falls

Mg - T = Ma

       T = Mg - Ma

       T = Mg - Mg(M - m) / (M + m)

       T = Mg(1  -(M - m) / (M + m))

       T = 16(9.8)(1 - (16 - 6.7) / (16 + 6.7))

       T = 93 N

or looking only at the smaller mass

T - mg = ma

T = m(g + a)

T = m(g +  g(M - m) / (M + m))

T = mg(1 +  (M - m) / (M + m))

T = 6.7(9.8)(1 +  (16 - 6.7) / (16 + 6.7))

T = 93 N

Figure 10.20 in your textbook shows an energy diagram for a system with total energy E1. Suppose the system's total energy is E2 = (1/3)E1. In what ways could the particle move?
Select all that apply.

a.) It could remain at rest at x3.
b.) It could oscillate between x1 and x5.
c.) It could undergo small oscillations around x2.
d.) It could undergo small oscillations around x3.
e.) It could undergo small oscillations around x4.

Please explain why, I have an exam coming up and want to understand the concept.

Answers

The particles can undergo small oscillations around x₂.

The given parameters;

initial energy of the particles = E₁final energy of the particles, E₂ = 0.33E₁

The movement of the particles depends on the kinetic energy of the particles.

When kinetic energy of the particles is 100%, the particles can oscillate from x₁ to x₅.

However, when the total energy of this particles is reduced to one-third (¹/₃) or 33% of the initial energy of the particle, the oscillation of the particles will be reduced.

The maximum position the particle can oscillate is x₅The half position the particles can oscillate is x₃

Since 33% is less than the half of the energy of the particle, the particle will oscillate between x₁ and x₂.

Thus, we can conclude that the particles can undergo small oscillations around x₂.

Learn more here:https://brainly.com/question/23910777


A car accelerates from 10m/s to 50m/s over a distance of som. What is the
acceleration of the car?

Answers

Answer:

40m/s

Explanation:

50m/s - 10m/s = 40m/s

A jet plane flying 600 m/s experiences an acceleration of 39.24 m/s² when pulling out of the circular section of a dive. What is the radius of curvature of this section of the dive?

The options are:

1.2 km
5.8 km
0.64 km
9.2 km
7.0 km

Answers

Answer:

Explanation:

If we are to assume that the plane is at the bottom of a circular movement and just about to depart in level flight, then

(39.34 - 9.81) = 600²/R

R = 12,190.992211... m

Which is very close to the 1.2 km option

How did kepler develop his second law of motion ?

A. He invented a telescope that was strong enough to view all plants of the solar system along their orbits

B. He compared data of planetary motion at different times along orbits

C. He made accurate measurements of the positions of all the planets over many years

D. He used a telescope to carefully follow and time the orbital motion of mars ​

Answers

He developed his second law of motion by using a telescope to carefully follow and time the orbital motion of mars .

What is a Telescope?

This is a device which is used to form magnified images of distant objects. Kepler used it to observe the orbit motion of mars.

He discovered that planets do not move with constant speed along their orbits which led to his second law of motion.

Read more about Kepler second law of motion here https://brainly.com/question/7540858

A parkour runner is running on top of a building when he comes to the edge; the next building is 5
meters down and 8 meters over. How fast does he need to be running to make the jump?

Answers

Answer:

Explanation:

If we make a rather silly assumption that the runner does not leap upward somewhat as he leaves the edge of the first building, his initial vertical velocity is zero.

The time needed to drop 5 meters from vertical rest is

t = √(2s/g) = √(2(5)/9.8) = 1.01 s

so he needs a horizontal speed of at least

v = d/t = 8 / 1.01 = 7.91959...

v = 7.9 m/s. Better make it 8 m/s to be sure he clears the edge and lands on the roof.

A 77 kg girl and a 62 kg boy face each other on friction free roller skates. The girl pushes the boy, who moves away at a speed of 2.5 m/s. What is the girl's speed? ​

Answers

Answer:

Explanation:

conservation of momentum

Initial momentum is zero

77v + 62(2.5) = 0

77v = -155

   v = -155/77 = -2.0129870...

 |v| = 2.0 m/s

1. What is meant by the phrase, "a sound mind and a sound
body'?

Answers

Answer:

A sound mind in a sound body implies that you're capable of positive thinking for a better quality of life and physical functioning. When you exercise, your body releases endorphins, a chemical that triggers a positive response in the body. This shows that the more you sweat, the better you feel about yourself.

Explanation:

Given the vectors A (-2, 3) and B(4,5) what is the sum of A +B?

Answers

yo ur doing physics too can u help me

5) You are visiting Norway for the winter and driving on a highway where the speed
limit is 80 km/hr. Your car indicates that you are going at a speed of 55 mi/hr. Will
you be arrested? (1 mi = 1.6 km)

Answers

Yes because if the limit is 80KM/hr and your going 55MI/hr that’s way above what the limit is

The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond.​

Answers

Area=1.5(1.5)=2.25m^2Force of gravity=10N

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}[/tex]

[tex]\\ \sf\longmapsto Pressure=4.4Pa[/tex]

Answer:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

A shopper is pushing a cart down a grocery store aisle. Starting from rest, the shopper applies a constant force to the cart for 4.0 s. From t = 4s until t = 4 s until t = 8 s, the shopper applies just enough force to balance the friction on the cart. Finally, the shopper applies a constant force to slow the cart until it comes to rest att = 12 s. The resulting position-time graph is shown below. What is the average acceleration of the shopping cart during its 12s motion?​

Answers

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:

It starts from rest.From t = 0 s to t = 4.0 s it is accelerated with a constant force.From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.From t = 8 s to t = 12 s it is decelerated until it comes to rest.

All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:

[tex]a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s} = 0 m/s^{2}[/tex]

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

Learn more: https://brainly.com/question/16274121

Answer:0 m/s2

Explanation: Cus i said so.

The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond ?​?​

Answers

The pressure caused by water is: P = P0 + bgh = 1.013×10^5 + 10^3×9.81 × 1.5 = 1.18 atm

what greenhouse gasses do for the atmosphere

Answers

Answer:

Explanation:

Earth's atmosphere contains greenhouse gases that trap heat. While they allow sunlight to pass through the atmosphere, they also prevent the heat it brings from leaving it.

A student drops a rock from rest at a distance h above the ground such that the rock hits the ground at a time t0 . At what distance above the ground should the rock be dropped such that it hits the ground at a time 2t0 after it is released.?

Answers

The distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.

The given parameters;

initial velocity of the rock, u = 0height above the ground, = htime of motion of the rock from the height = t₀

The time of motion of the rock from the given height is calculated as;

[tex]h = ut + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt_0^2\\\\h = \frac{1}{2} gt_0^2\\\\t_0^2 = \frac{2h}{g} \\\\t_0 = \sqrt{\frac{2h}{g} }[/tex]

When the time of motion is doubled to 2t₀, the height above the ground should be;

[tex]2(t_0) = 2(\sqrt{\frac{2h}{g} } )\\\\2(t_0) = \sqrt{\frac{4\times 2h}{g} }[/tex]

Thus, the distance above the ground the rock should be raised in order to hits the ground double of initial time is 4h.

Learn more here:https://brainly.com/question/24607640

DUE IN 3 HOURS! PLEASE HELP AND SOLVE A-E.
For a projectile with initial velocity of 51.5 m/s and angle of elevation equal to 4 degrees.
a) Compute the horizontal velocity of the projectile in m/s.
b) Compute the vertical velocity in m/s.
c) Compute the time of flight for the projectile.
d) Compute the distance downrange.
e) Compute the maximum height reached by the projectile.

Answers

Answer:

Below

Explanation:

c) To find the time of flight of a projectile (assuming from the given information that there is no vertical displacement) you can use this formula :

     t = 2(Vi) Sinx / g

     t = 2(51.5m/s) Sin(4) / 9.8 m/s^2

     t = 0.733 seconds

    t = 0.73 seconds

d) To find the displacement in the x-direction you can use this formula :

     dx = vi^2 sin(2x) / g

     dx = (51.5m/s)^2 sin(2(4)) / 9.8m/s^2

     dx = 37.6654 m  

     dx = 37.7 meters

e) To find the peak height of the projectile you can use this formula :

     v^2sin^2(x) = 2gh

     (51.5m/s)^2sin^2(4) = 2(9.8m/s^2)h

     h = 0.658 meters

     h = 0.66 meters

Hope this helps! Best of luck <3

An elevator cable winds on a drum of radius 771 cm that is connected to a motor.
If the elevator moves down 8.60 m, how many revolutions has the drum made?

Answers

The relationship between the length of the circle and its radius allows to find the result for the revolutions turned when the distance decreases  8.60m is:

           Angle = 17.8 rev

The length of a circle is given by the expression.

         L = 2π r

Where L is the length of the circle and r is the radius of the circle.

They indicate the radius of the drum is r = 7.71 cm = 7.71 10⁻² m, let's find the length of the circle.

         Lo = 2 π 7.71 10⁻²

         Lo = 0.4844 m

Let's find the angle that the drum has rotated, using a direct proportional rule. If rotate an angle of 2π radians when you descend 0.4844 m, what angle you rotate when you descend 8.60 m.

          #_ angles =  [tex]8.6 m \ \frac{2\pi \ rev} { 0.4844 m}[/tex]  

          #_angle = 111.55 radians

Let's reduce to revolutions.

         # _angles = 111.55 radians ( [tex]\frac{1 rev }{2\pi rad}[/tex] )

         #_angulo = 17.8 rev

In conclusion, using the relationship between the length of the circle and its radius, we can find the result for the revolutions turned when the distance decreases is:

           Angle = 17.8 rev

Learn more here: https://brainly.com/question/4518309

An ideal gas occupies a volume of 1cm^ atv20°c and atmospheric pressure determine the number of molecules of gas in the container

Answers

Answer:

By Charles Law the volume of 1 cm^3 at standard conditions is

V = V0 * 273 / 293 = 1 cm^3 * .932 cm^3

Reducing the temperature to 0 deg C results in a volume of .932 cm^3

1 mole of gas contains 22.4 L of gas

1 L = 1000 cm^3

1000 cm^3 / L / (.932 cm^3 / container) = 1073   containers / L

So 1 mole of gas = 1073 containers * 22.4 L /container =  24,305 L

6.02E23 molecules / mole * 1 / 24305 molecules / mole = 2.48E19

number of molecules present = 2.48 * 10^19

(Easier to calculate volume of 1 cc

1 cc = 6.02E23 / (1000 * 22.4) = 2.69E19 molecules in 1 cc

Vol of 1cc = 273 / 293 = .932

2.69E19 * .932 = 2.51 * 10^19)

An elevator cable winds on a drum of radius 77.1 cm that is connected to a motor.
If the elevator moves down 8.60 m, how many revolutions has the drum made?

Answers

I would have to wait until after school and then I’ll be home and then I can come get back with me lol





77+ 81= 100
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