Player First
Round Final
Round
Golfer 11 72 72
Golfer 12 72 70
Golfer 13 70 73
Golfer 14 70 77
Golfer 15 68 70
Golfer 16 68 66
Golfer 17 71 70
Golfer 18 70 68
Golfer 19 69 68
Golfer 20 67 71
Suppose you would like to determine if the mean score for the first round of a golf tournament event is significantly different than the mean score for the fourth and final round. Does the pressure of playing in the final round cause scores to go up? Or does the increased player concentration cause scores to come down?
(a) Use α = 0.10 to test for a statistically significantly difference between the population means for first- and fourth-round scores. State the null and alternative hypotheses. (Use μd = mean score first round − mean score fourth round.
Calculate the value of the test statistic. (Round your answer to three decimal places.)
Calculate the p-value. (Round your answer to four decimal places.)
p-value =
(b) What is the point estimate of the difference between the two population means? (Use mean score first round − mean score fourth round.)

Answer:

15 ñ

Step-by-step explanation:

Answer:

1-a. The tax was 5%

b. The total bill is 7$

Step-by-step explanation:

a. We need the 10% tip of bill after tip and tax to get bill.

b. 0.7 = 10%

x = 100% (x is total bill)

x = (0.7*1)/0.1 (divide percentage by 100)

= 0.7/0.1

= 7

The measure of the angles in the given figure of the triangle is given by: m∠1= 56  ,m∠2= 56 and m∠3= 74.

As given in the question,

In the given triangle MPQ we have,

Sum of all the interior angles in the triangle is 180 degrees.

m ∠P + m ∠M + m∠1 =180°

⇒58° + 66° + m∠1=180°

⇒m∠1= 180° - ( 58° + 66°)

⇒m∠1=56°

From the figure , ∠1 and ∠2 are vertically opposite angles:

⇒m∠1= m∠2

⇒m∠2=56°.

In triangle QNO we have,

m ∠O + m∠2 + m∠3 =180°

⇒50° + 56° +m∠ 3=180°

⇒106° + m∠3= 180°

⇒m∠3= 180° - 106°

⇒m∠3=74°

Therefore, the measure of the required angles in the given triangles are m∠1= 56  ,m∠2= 56 and m∠3= 74.

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It's easier to come up with the correctness proof of the divide and conquer algorithm compared to the greedy algorithm is False statement.

It is not easier to come up with a correctness proof of the divide and conquer algorithm compared to the greedy algorithm. The correctness proof of a divide and conquer algorithm is more difficult than a greedy algorithm since it involves breaking down an algorithm into multiple sub-problems and then proving the correctness of the algorithm with respect to each sub-problem. On the other hand, the correctness proof of a greedy algorithm is relatively simple and involves determining if a given solution is optimal. Additionally, the correctness proof of a divide and conquer algorithm requires more complex mathematical analysis such as induction, recurrence relations, or complexity analysis. This makes it more difficult to come up with the correctness proof of the divide and conquer algorithm than the greedy algorithm.

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7.5

Step-by-step explanation:

3:8=×:20 so x=20×3÷8=7.5

In this one, We reject the null hypothesis and accept the alternative hypothesis. The z score of -0.07 is in the rejection area

What is the process of doing the hypothesis test?

In math, the ANOVA output is given in tabular format with headers like source, that consists of error sources and these error sources can be unexplained or explained ones. Then the evaluation of these helps to account for the F-statistic is accounted for two terms, known as degrees of freedom which can found against the factor and the error value.

Here we have given that senior accounting major at Midsouth State University has job offers from four CPA firms. To explore the offers further, she asked a sample of recent trainees how many months each worked for the firm before receiving a raise in salary.

And we need to find the difference in the mean number of months before a raise was granted among the four CPA firms

While we looking into given question, we have the sample data as,

=> 3, 28.17, 9.39, 5.37, 0.133, 15, 26.26, 1.75, 18, 54.43

By using the sample data, we have identified the value of the following

Standard Deviation, σ: 15.860418305013

Count, N: 10

Sum, Σx: 161.503

Mean, μ: 16.1503

Variance, σ2:  251.55286881

Now, the hypothesis testing result is written as,

The critical value (cutoff point) is 1.833. In left-tail hypothesis testing, any z score less than the critical value will be rejected. Since -0.07 is less than 1.833, we reject the null hypothesis. We accept the alternative hypothesis.

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Therefore ,E = xex2 + y2 + z2 dv, where e is the portion of the unit ball x2 + y2 + z2 ≤ 1 that lies in the first octant whose value is π/8

The volume of an inhabited three-dimensional space is calculated. It is commonly measured in a variety of imperial, US-standard, and SI-derived units. Volume and the notion of length are interconnected.

Here,

Given :

portion of unit ball = [tex]xe^{x^{2}+y^{2} +z^{2} }[/tex]

and x2 + y2 + z2 ≤ 1

So, using this

We find the triple integral or the volume integral of the expression  = [tex]xe^{x^{2}+y^{2} +z^{2} }[/tex]

=> [tex]\int\int\int_{e} xe^{x^{2}+y^{2} +z^{2} }[/tex]dV

=>   [tex]\int\limits^{\alpha = \pi /2}_{\alpha =0}\int\limits^{\beta = \pi /2}_{\beta =0} \int\limits^{p= 1}_{p=0}[/tex]   pcos[tex]\beta[/tex]sin[tex]\alpha[/tex][tex]e^{{p}^{2}[/tex] [tex]p^{2}[/tex]sin[tex]\alpha[/tex] dpd[tex]\alpha[/tex]d[tex]\beta[/tex]

=>[tex]\int\limits^{\alpha = \pi /2}_{\alpha =0}[/tex][tex]sin^{2}\alpha[/tex] d[tex]\alpha[/tex]  + [tex]\int\limits^{\beta = \pi /2}_{\beta =0}[/tex]cos[tex]\beta[/tex] d[tex]\beta[/tex]  +  [tex]\int\limits^{p= 1}_{p=0} p^{2} e^{p^{2}}[/tex] dp

=>π/8

Therefore ,E xex2 + y2 + z2 dv, where e is the portion of the unit ball x2 + y2 + z2 ≤ 1 that lies in the first octant whose value is π/8

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The rate at which the spherical balloon's radius is increasing is

3/16π ft/min when the volume is increasing at the rate of 3 ft³/min.

Given, a spherical balloon is inflated so that its volume is increasing at the rate of 3 cubic feet per minute.

we have to find that how fast is the radius of the balloon increasing when the radius is 2 feet.

as, we know the volume of the balloon be,

V = 4/3πr³

now we have to find the rate of change of radius,

On differentiating both the sides with respect to time, we get

V' = 4/3π(3r²)dr/dt

V' = 4πr²dr/dt

as, the rate of change of volume of the balloon be, 3 ft³/min

V' = 3

3 = 4πr²dr/dt

dr/dt = 3/4πr²

Now, on putting r = 2, we get

dr/dt = 3/4π(2)²

dr/dt = 3/16π

so, the radius of the balloon increase at the rate of 3/16π.

Hence, the radius of the balloon increase at the rate of 3/16π.

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The median can be calculated by ordering the possible values of the random variable from smallest to largest and then finding the value for which the cumulative probability equals or exceeds 0.5.

Firstly, list out all the possible values of the random variable.Secondly, order the values from smallest to largest. Thirdly, calculate the cumulative probability for each value. Fourthly, find the value for which the cumulative probability equals or exceeds 0.5 Finally, this value is the median of the discrete random variable.The median of a discrete random variable can be found by arranging the possible values of the random variable from smallest to largest, and then calculating the cumulative probability for each value. Once the cumulative probability reaches or exceeds 0.5, the corresponding value of the random variable is the median.

Let the random variable X have values {1, 2, 3, 4, 5}.

Ordered from smallest to largest, X has the values {1, 2, 3, 4, 5}.

The cumulative probability for each value of X is calculated as follows:

P(X ≤ 1) = 0

P(X ≤ 2) = 0.2

P(X ≤ 3) = 0.6

P(X ≤ 4) = 0.9

P(X ≤ 5) = 1

The median of X is 3, since it is the smallest value for which the cumulative probability equals or exceeds 0.5.

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[x|-5<x<-2]

Write the inequality in set-builder notation as the set of all real numbers x such that x is greater than -5 and x is less than - 2

The Probability P [tex](20\leq x\leq 36)[/tex] = 0.7500

What is probability ?

The ratio of good outcomes to all possible outcomes of an event is known as the probability. The number of positive results for an experiment with 'n' outcomes can be represented by the symbol x. The probability of an occurrence may be calculated using the following formula.

Probability(Event) = Positive Results/Total Results = x/n

Given : the mean μ = 28

standard deviation σ = 4

small value = 20 and big value = 36

by chebychev's inequality,

μ - kσ = small value

28-k(4) = 20

k = 2

also,

μ + kσ = big value

28 + k(4) = 36

k = 2

The Probability P [tex](20\leq x\leq 36)[/tex] = [tex]1-1/k^{2}[/tex]

[tex]= 1-1/2^{2} \\=3/4\\=0.7500[/tex]

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Answer:

24

Step-by-step explanation:

Perimeter are the side measures added up.

15 x 0.4 = 6

ΔLMN = 60

60 x 0.4 = 24

The answers are A) Reasonable domain to plot the growth function = [0, 9] B) y-intercept of the graph of the function f(m) represent initial length of fish = 5 cm and C) average rate of change of the function f(m) from m

is (3.84/8)

A function is defined as a relation between a set of inputs having one output each.

Given that, A marine biologist is studying the growth of a particular species of fish when the marine biologist concluded her study, the length of the fish was approximately 9.19 cm

A) For m = 0

f(0) = 5(1.07)⁰ = 5 cm

The length of the fish was approximately 9.19 cm.

m = 9

Domain = [0, 9]

Reasonable domain to plot the growth function = [0, 9]

B) y-intercept of the graph of the function f(m) represent initial length of fish = 5 cm

C) average rate of change of the function f(m) from m = 1 to m = 9

For m = 1

f(1) = 5(1.07) = 5.35 cm

For m = 9

f(9) = 5(1.07)⁹ = 9.19 cm

Change in 9 - 1 = 8 months = 9.19 - 5.35 = 3.84 cm

average rate of change of the function f(m) from m = 1 to m = 9,

= (3.84/8)

= 0.48 cm per month

Hence, The answers are A) Reasonable domain to plot the growth function = [0, 9] B) y-intercept of the graph of the function f(m) represent initial length of fish = 5 cm and C) average rate of change of the function f(m) from m is (3.84/8)

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Using correlation and it's value of coefficient , The answer is b. 0.50

A statistical method called regression links a dependent variable to one or more independent (explanatory) variables. A regression model can demonstrate whether changes in one or more of the explanatory variables are related to changes in the dependent variable.

A statistical measure called correlation shows how much two or more variables fluctuate in connection to one another.

we have 25% variance confidence.

[tex]r ^ {2} = 0.25[/tex]

[tex]r=\sqrt {0.25}[/tex]

[tex]r=0.50[/tex]

The answer is b.0.50

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If a linear regression equation predicts more than 25% of the variance in the Y scores, then the correlation between X and Y must be greater than (c) r = 0.35.

Correlation (r) quantifies the strength and direction of the linear relationship between two variables. A correlation of 0.35 indicates a moderate positive linear association, suggesting that as X increases, Y tends to increase as well, and vice versa.

When the correlation surpasses this threshold, it implies that a substantial portion of the variability in Y can be explained by changes in X. However, it's important to interpret the correlation value within the context of the specific data and the field of study.

Other factors like sample size and potential outliers can also influence the significance of the correlation. In summary, a correlation greater than (c) 0.35 signifies a meaningful connection between X and Y, contributing to the prediction of Y scores using the linear regression equation.

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the logarithm of the likelihood function and differentiate it with respect to both alpha and beta.

(a) The MLE of β is given by [tex]$$\hat{\beta} = \frac{\sum_{i=1}^n X_i}{n \alpha}.$$[/tex]

(b) The likelihood function for the data in Exercise 7.10(c) is given by [tex]$$L(\alpha, \beta) = \alpha^n \beta^{-n\alpha} \prod_{i=1}^n X_i^{-\alpha}.$$[/tex]We can take the logarithm of both sides to obtain[tex]$$ \ell(\alpha, \beta) = n \log \alpha - n \alpha \log \beta - \alpha \sum_{i=1}^n \log X_i.$$[/tex]Taking the partial derivatives of the log-likelihood function and setting them to 0 yields [tex]$$\frac{\partial \ell}{\partial \alpha} = \frac{n}{\alpha} - n \log \beta - \sum_{i=1}^n \log X_i = 0 \quad \text{and} \quad \frac{\partial \ell}{\partial \beta} = -\frac{n \alpha}{\beta} = 0.$$[/tex]Sol

Using the data from Exercise 7.10(c), we take the logarithm of the likelihood function and differentiate it with respect to both alpha and beta. We then set the partial derivatives to 0 to obtain equations for alpha and beta which can be solved to find the MLEs.

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Answer:

x=3.

Step-by-step explanation:

[tex]way1) \ 4^x=64;\\x=log_4[64];\\x=3;\\\\way2) \ 4^x=64; \ < = > \ 4^x=4^3; \ < = > \ x=3.[/tex]

They filled bags that total 879 and the treats that did not fit are 4

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given here, total treats = 6157, and group them in bags with 7 each

now, we can write 6157 = 879×7+4

thus, on dividing 6157 by 7 we get the remainder as 4 and the quotient as 879

Hence, the bags of treats they filled is 879, and 4  treats were given to the groomer

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Answer:

Since csc 13pi/11 is undefined, it is impossible to fill in a value for angle A and B that satisfies the given restrictions. Additionally, it is impossible to find the related acute angle or the quadrant of the principle angle without a defined value for angle A and B.

Step-by-step explanation:

We can say that duties are obligations that one has, while work is an activity that is carried out and that depends on a profession.

The concepts homework and work are related because they are often linked in many contexts. Regarding these terms, we have to:

¡Hope this helped!

Answer:

Signum function

Step-by-step explanation:

Hope this helps uuuu

Answer:

x = -10

y = 1

Step-by-step explanation:

To use the Gauss-Jordan Elimination Method to solve for x and y, we need to put the augmented matrix in row-echelon form. The first step is to eliminate the x-coefficient in the second row by adding 4 times the first row to the second row. This gives us the following matrix:

[ 6 6 | -18 ]

[ 0 -10 | -10 ]

Next, we need to eliminate the y-coefficient in the second row. We can do this by adding 5 times the second row to the first row, which gives us the following matrix:

[ 1 -10 | -10 ]

[ 0 -10 | -10 ]

Now, the matrix is already in row-echelon form, so we can read the solution directly from the matrix. The solution is x = -10 and y = 1. Therefore, the solutions to the system of linear equations are:

x = -10

y = 1

Note that there may be other solutions to the system of equations, depending on the specific equations that the matrix represents. The Gauss-Jordan Elimination Method will always give us one possible solution, but there may be other solutions as well.

Answer:

Hello! Rx-axis means that they want the coordinates after they are reflected over the x-axis.

The original coordinates are as follows:

Q (1, 5)

R (3, -1)

S (0, 0)

T (-2, 3)

Reflecting a coordinate (x, y) over the x-axis results in the new coordinates being (x, -y).

Performing this translation over the 4 given points, we obtain:

Q' (1, -5)

R' (3, 1)

S' (0, 0)

T' (-2, -3)

hope this helps :)

The distance ship travelled 7.4 units between the two observations of the lighthouse.

Law of Sines In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of any triangle to the sines of its angles.

The formula for sine rule is sinA/a=sinB/b=sinC/c

Given that, a ship is sailing due north. At a certain point the bearing of a lighthouse is N39.8˚E and the distance is 11.5.

P is the ship, R is the light house and Q is the bearing.

PR is the distance between the ship and the light house, PR = 11.5

∠P = 43.5°, ∠Q =39.8°

Thus, ∠R = 180° -∠P-∠Q

= 180°-43.5°-39.8°

= 96.7°

By using sin rule we get

PR/sinR =PQ/sinQ

11.5/sin96.7° =PQ/sin39.8°

11.5/0.9931 =PQ/0.6401

PQ/0.6401=11.55

PQ=7.4 units

Therefore, the distance ship travelled 7.4 units between the two observations of the lighthouse.

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Answer: 32 km (I believe)

Explanation: So, on the first day the tourists walked x/8 km.

Then the remaining distance after the first day is (x- x/8) = 7x/8 km.

On the second day, the tourists walked 4/7 of the REMAINING path, so now we multiply 4/7 by 7x/8 to get x/2 km.

So, the remaining path to travel after 2nd day is (7x/8-x/2) = 3x/8

Remember, on the third day they walked 1/3 of the remaining trail and the last 8 km.

So now, we do (3x/8 - 3x/8 x 1/3) = 8

Now, x/4 =8 ; to find x, we do 8 x 4 to get 32

So, our answer is 32

I hoped this helped!

Step-by-step explanation:

Using Trigonometry

Cos ø = Adj ÷ Hyp

ø = 35°

Hyp side=15ft

A is the Adj side

Adj = Cos ø × Hyp

Adj = Cos 35° × 15

Adj = 0.8192 × 15 = 12.29

Adj = 12ft approximately

Answer: 12.3

Step-by-step explanation: Based off the quiz I did it said 12.3

The quotient is  [tex]3x^2 - 7x + 10[/tex].

"Information available from the question"

In the question:

Using synthetic division,

What is the quotient for (3 x³+5 x²-18 x+39) /(x+4)

Now, According to the question:

Let's know:

Synthetic Method: The synthetic division method is a special method of dividing polynomials. This method is a special case of dividing a polynomial expression by a linear factor, in which the leading coefficient should be equal to 1.

(3 x³+5 x²-18 x+39) /(x+4)

              [tex]3x^2 - 7x + 10[/tex]

 x + 4 [tex]\sqrt{3 x^3+5 x^2-18 x+39}[/tex]

             [tex]3x^3 + 12x^2[/tex]

         -          -    

      ___________________              

                   [tex]-7x^2[/tex] - 18x

                    [tex]-7x^2[/tex] - 28x

                  +          +

     _____________________

                              10x + 39

                              10x + 40

                           -        -    

  ________________________

                                      -1

The quotient is  [tex]3x^2 - 7x + 10[/tex].

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On solving the provided question, we can say that net annual cost of the given account is  18

equation: a statement stating the equality of two expressions having variable- and/or number-filled expressions. Since equations are essentially questions, finding a way to answer them has spurred the development of mathematics.

Net annual cost is that monthly fee X 12 +  fee per check X number of checks per month X 12

[tex]= ($3.75 X 12) + ($0.25 X22 X 12)\\ = $111[/tex]

Net annual cost is service charges - Interest earnings

[tex]= ($15 X 3) - (0.06 X $600 X 9 / 12)= $18[/tex]

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Answer:

e = mc^2

m = e/c^2

Step-by-step explanation:

cdf of U(n) = Var(Sn)=1

A standard function is one that is defined on an interval of R and is acquired by a finite series of standard operations beginning with any three fundamental functions.

f(x) = x is the identity function. f(x) = exp, an exponential function (x)

given

let U1, . . . ],

U(n) be their maximum

so cdf of U(n) =does not have a limiting distribution.

Why will a pub and up be equal to zero when Y is less than and one win in is less than the other.

There isn't a standard distribution function that can match this limit everywhere.

hence  cdf of U(n) = Var(Sn)=1

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