Answer:
Part A: By using the formula, distance = speed x time
Part B: By using the formula, time = distance ( calculated in the first part) ÷ speed
Ex 1) A Major League baseball pitcher throws a baseball straight up into the air and the ball travels for 4
seconds reaching a height of 52 m before returning to the pitchers hand exactly at the height that he released
it. With what velocity does the baseball strike the pitchers hand on the way back down?
Answer:
52 / 4 = 13 m/s
Explanation:
Car A uses tires for which the coefficient of static friction is 0.384 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is 16.7 m/s. Car B uses tires for which the coefficient of static friction is 0.809 on the same curve. What is the maximum speed at which car B can negotiate the curve
A closed, uninsulated system fitted with movable piston, so no matter is exchanged with the surroundings, was assembled. Introduction of 430 J of heat caused the system to expand, doing 238 J of work against a constant pressure of 101 kPa. What is the value of for this process
Answer: You do not specify what is being asked for. ∆E? ∆H?
∆E = (430 - 238) J = 192 J
∆H = 430 J
Explanation:
If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.
Therefore ∆H = 430 J
If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w
The question states that 238 J of work are done AND the system expanded
(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)
Therefore, ∆E = (430 - 238) J = 192 J
The gas state of water
Answer:
The gas state of water is water vapour. It is formed by boiling liquid water or from the sublimation of ice (sublimation is the process of converting a solid to a liquid). Hope this helps!
A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary on a surface with a coefficient of kinetic friction of 0.15 when hit, how far does it move after the bullet emerges?
The distance traveled by the wood after the bullet emerges is 0.16 m.
The given parameters;
mass of the bullet, m = 23 g = 0.023 gspeed of the bullet, u = 230 m/smass of the wood, m = 2 kgfinal speed of the bullet, v = 170 m/scoefficient of friction, μ = 0.15The final velocity of the wood after the bullet hits is calculated as follows;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s[/tex]
The acceleration of the wood is calculated as follows;
[tex]\mu = \frac{a}{g} \\\\a = \mu g\\\\a = 0.15 \times 9.8\\\\a = 1.47 \ m/s^2[/tex]
The distance traveled by the wood after the bullet emerges is calculated as follows;
[tex]v^2 = v_0^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\s = \frac{v^2}{2a} \\\\s = \frac{(0.69)^2}{2(1.47)} \\\\s = 0.16 \ m[/tex]
Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.
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tính chỉ số ampe kế thay ampe kế bằng vô kế có điện trở rất lớn thì vô kế chỉ bao nhiêu
Answer:
I don't understand it.....
I need help ASAP please.....
Suppose a ball is dropped from a building. What is the change of velocity between the first and fifth seconds of its flight
Answer: 39.2m/s
Explanation:
Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.
V(t) = g*t
The change of velocity from t=1 to t=5:
Delta V = 9.8*(5-1) = 39.2 m/s
HELP! I need some assistance
Answer:
I'm a Filipino hahahah I'm not
Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?
Answer:
Explanation:
My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.
Una masa de aire de 20g absorbe 780 cal. Teniendo en cuenta que su temperatura inicial es de 30°C. Calcular la
temperatura que alcanzo al absorber el calor. Ce:0,24 cal/g °C
Answer:
sorry I don't know the answer
Which term describes energy stored in the bonds between atoms?
A. Nuclear energy
B. Chemical energy
O C. Thermal energy
D. Sound energy
Answer:
B. Chemical energy
Explanation:
chemical energy is the energy stored in the bonds between atoms
define potential difference as used in electricity
Answer:
Explanation:
Testing answer please do not delete
the diffrence in potential betwen two points that represents the work involved or the energy relesed in the transfe of a unit quantity of electicity from one point to the other
Am I correct? Plz answer ASAP! I will give brainilest:D (Science)
Answer:
I would agree with your selection.
Explanation:
4. What is the density of a block with a mass of 36 g and a volume of 9 cm?
O A 45 g/cm3
O B.27 g/cm
O 0.4 g/cm
O D. 0.25 g/cm
Answer:
0.4 g/cm
Explanation:
density (g cm ³) = mass (g)
÷
volume (cm³)
Answer:
C. 4 g/cm
Explanation:
Use the formula:
density = mass ÷ volume
mass = 36volume = 9Sub in the values:
density = 36 ÷ 9 = 4 g/cm
Answer = 4 g/cm
The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force on the rocket if it is now accelerating at 12mls²??
From your previous question
Mass=30kgAcceleration=12m/s^2[tex]\\ \sf\longmapsto F=ma[/tex]
[tex]\\ \sf\longmapsto F=30(12)[/tex]
[tex]\\ \sf\longmapsto F=360N[/tex]
Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
What is the maximum height of the cannonball?
Explanation:
The final velocity at the cannon ball's maximum height is zero ([tex]v_y = 0[/tex]). We can use the equation
[tex]v_y^2 = 0 = v_{0y}^2 - 2gy_{max}[/tex]
[tex]\Rightarrow y_{max} = \dfrac{v_{0y}^2}{2g}[/tex]
[tex]y_{max} = \dfrac{(25\:\text{m/s})^2}{2(9.8\:\text{m/s}^2)}[/tex]
[tex]\:\:\:\:\:\:\:=31.9\:\text{m}[/tex]
The volume of an ideal gas is increased from 0.6 m3 to 2.4 m3 while maintaining a constant pressure of 1000 Pa (1000 N/m2). Determine, in J, the amount of work done by the gas in this expansion.
The amount of work done by the gas in the given expansion is 1800 J.
The given parameters;
initial volume of the ideal gas, V₁ = 0.6 m³final volume of the ideal gas, V₂ = 2.4 m³constant pressure of the gas, P = 1000 PaThe amount of work done by the gas in the given expansion is calculated as follows;
W = PΔV
where;
ΔV is the change in volume of the gasSubstitute the given parameters and solve for the work done;
W = 1000(2.4 - 0.6
W = 1800 J
Thus, the amount of work done by the gas in the given expansion is 1800 J.
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A 3000 kg car stops at a red light, and is rear-ended by a 5000 kg truck traveling at 20m/s. In the collision, the two cars stick together. What is the final speed of the two cars just after the collision in m/s (Numeric Answers only)
Explanation:
this is actually not as simple as it sounds here.
quite some energy is lost in the deformation of the bodies of car and truck, and it also needs more energy to get a standing object going than to accelerate an already moving object.
but assuming the simple described circumstances, then the energy and impulse of the moving truck of 5000 kg is transferred to a new combined system of car and truck of now 5000 + 3000 = 8000 kg.
so, the 20m/s inertia energy of the truck is now distributed to the truck/car combination.
since the same energy has to move now more mass, it is clear that the combined speed will be lower.
20×5000 = x×8000
20×5 = x×8
x = 100/8 = 12.5 m/s
that is the resulting speed of the combined truck/car object.
What is an involuntary and a voluntary muscle action?
Answer:
Involuntary muscle action are muscles that move WITHOUT conscious control, and voluntary muscle action are muscles that move WITH conscious control.
Explanation:
A example of a involuntary muscle action would be your heart. Your heart is a muscle beats without you thinking about it and is very vital to your body. A example of a voluntary muscle would be the muscles that are attached to your bones and allow you to move your body, and it's voluntary because your body won't move on it's own.
Hope this helps.
A car with a mass of 1500 kg is pulled by a rope that is horizontal to the ground. The tension in the rope is 2000 N and a friction force of 350 N opposes the car's motion. What is the magnitude of the car's acceleration?
Answer:
Explanation:
Assuming the ground is level as well.
F = ma
a = F/m
a = (2000 - 350) / 1500
a = 1.1 m/s²
The acceleration of the car is 1.1 m/s².
To calculate the magnitude of the acceleration of the car, we use the formula below.
F-F' = ma................ Equation 1Where:
F = Tension in the ropeF' = Friction forcem = mass of the cara = acceleration of the carMake a the subject of the equation
a = (F-F')/m................. Equation 2From the equation,
Given:
F = 2000 NF' = 350 Nm = 1500 kgSubstitute these values into equation 2
a = (2000-350)/1500a = 1650/1500a = 1.1 m/s²Hence, the acceleration of the car is 1.1 m/s².
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What will be the current through a resistance of 50Ω if the applied voltage across the resistance is 117V?
Formulas: V=IR, I=V/R, R=V/I
Note: No need to write the unit of your answer.
2.34 A
Explanation:
[tex]V = IR \Rightarrow I = \dfrac{V}{R} = \dfrac{117\:\text{V}}{50\:Ω} = 2.34\:\text{A}[/tex]
There are 6 foundation of sports and which one you think is the most important?
I just need the points
Explanation:
But just pick any and say something like "it stans out to me most/more" or "it sounds/looks more intristing to me"
Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?
Explanation:
s=(v^2-u^2)/2g
=(0-3^2)/2*10
= 0.45m
I NEED A 100% ACCURATE ANSWER FOR THIS QUESTION ASAP NO LINKS !!!
What describes the pressure in a contained fluid?
1: unknown as long as the fluid is contained
2: the same throughout the fluid
3: higher in some places and lower in other places
Answer:
3) higher in some places nd lower In other places
Explanation:
The pressure in a fluid is given by the law
p = p0 + pgh
where
p0 is the atmospheric pressure
p is the fluid's density
g is the acceleration of gravity
h is the depth at which the pressure is calculated
As we see, the pressure depends on the value of h (depth): therefore, points which are located at more depth experience a larger pressure than points located near the fluid's surface.
A spring of spring constant k = 200 N m−1 is slowly extended from an extension of 3.0 cm to an extension of 5.0 cm. Calculate the work done by the extending force. 60
Answer:
31
Explanation:
No need
HELPPP
Which of the following statements about friction is FALSE .
1 ) Friction involves objects that are in physical contact .
2) Friction is less if surfaces are very smooth .
3 ) Friction is always in the direction of the motion .
4) Friction is caused by the uneven surfaces of touching objects
In 1962 measurements of the magnetic field of a large tornado were made at the Geophysical Observatory in Tulsa, Oklahoma. If the magnitude of the tornado's field was B = 17.50 nT pointing north when the tornado was 9.10 km east of the observatory, what current was carried up or down the funnel of the tornado? Model the vortex as a long, straight wire carrying a current. A (conventional current) flowing ---Direction--- the tornado.
Answer:
796.25 A
Explanation:
B= (μI)/(2πr)
I= (B*2πr)/(μ)
μ= 4π*10^-7
I= ((17.50*10^-9)(2π)(9.10*10^3)) / (4π*10^-7)
= 796.25 A
A (conventional current) flowing "DOWN" the tornado.
*Sorry for the bad quality picture!*
A frictionless pendulum with a mass of 0.4 kg and a length of 2.1 m starts at point A, at an angle 0 of 60°. As it swings downward, it passes through point B, which is 30 degrees from equilibrium. What is the kinetic energy of the pendulum at point B?
A) 3.9 J
B) 3.0 J
C) 1.1 J
D) 4.1 J
The conservation of mechanical energy allows finding the result for the speed of the pendulum when it is at 30º is:
The speed is: 3.88 m / s
The conservation of mechanical energy is a theorem of greater importance in physics and ordinary life, it states that if there is no friction force the total mechanistic energy remains constant at all points.
Mechanical energy is the sum of kinetic energy plus all potential energies. In the attachment we see a diagram of the pendulum's movement at the two points of interest.
They indicate that the pendulum is released from an initial angle of θ₁ = 60º, let's find the mechanical energy at that point.
Em₀ = U = m g h
Where the height is measured from the lowest point of the movement.
h = L - L cos tea1 = L (1 cos tea1)
The second point of interest occurs for θ₂ = 30º.
At this point part of the energy is indica and part gravitational potential.
[tex]Em_f[/tex] = K + U₂
[tex]Em_f[/tex] = ½ m v² + m g h ’
There is no friction in the system, therefore mechanical energy is conserved.
Em₀ = Em₀_f
mg L (1 - cos θ₁) = ½ m v² + m g L (1 - cos θ₂)
v² = 2g L (cos θ₂ - cos θ₁)
Let's calculate.
v² = 2 9.8 2.1 (cos 30 - cos 60)
v² = 41.16 0.366
v = 3.88 m / s
In conclusion using the conservation of mechanical energy we can find the result for the speed of the pendulum when it is at 30º is:
The speed is: 3.88 m / s
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Answer:
3.0 J
Explanation:
Just took the test
A massive launcher sends a projectile vertically upwards from the surface of a planet of mass M and radius R. You may assume that this planet has no atmosphere. Part A If the projectile is launched at the escape speed, how do the magnitudes of its initial KE and gravitational potential energy (GPE) compare
Answer:
It can be shown that the potential energy of an object at the surface of the planet would be -G M / R if the potential at infinity is chosen to be zero.
Kinetic energy of G M / R would be required for the escape speed of such an object. The total energy in all such cases is zero.
This can easily be seen by considering the speed of an object falling from infinity towards the planet - the total energy will remain zero if it was zero when the object started to fall.
The potential at infinity is set to zero while the kinetic energy will be [tex]\rm \frac{GM}{R}[/tex] and total energy will be zero.
What is escape speed?Escape speed is the minimum speed required for a free, non-propelled object to escape from the gravitational pull of the main body and reach an infinite distance from it in celestial physics.
It is proven that if the potential at infinity is set to zero, the potential energy of an item on the planet's surface is [tex]\rm \frac{-GM}{R}[/tex].
The escape speed of such an item would necessitate kinetic energy will be [tex]\rm \frac{GM}{R}[/tex]. In all of these circumstances, the total energy is zero.
Consider the speed of an item falling from infinity towards the planet: if the total energy was zero before the thing began to descend, the total energy will stay zero.
Hence the potential at infinity is set to zero while the kinetic energy will be [tex]\rm \frac{GM}{R}[/tex] and total energy will be zero.
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