One endpoint of a line segment has coordinates represented by (x+4,1/2y). The midpoint of the line segment is (3,−2).

How are the coordinates of the other endpoint expressed in terms of x and y?

Answer:

[tex]\displaystyle \left(-x+2, -\frac{1}{2}y-4}\right)[/tex]

Step-by-step explanation:

We are given that one of the endpoints of the line segment is:

[tex]\displaystyle \left( x + 4, \frac{1}{2}y\right)[/tex]

And that the midpoint of the line segment is (3, -2).

And we want to find the other coordinates in terms of x and y.  

We can consider using the midpoint formula:

[tex]\displaystyle M = \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)[/tex]

We are given that the midpoint is (3,-2). Substitute:

[tex]\displaystyle (3, -2) = \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)[/tex]

We can solve for each coordinate independently.

x-coordinate:

We have:

[tex]\displaystyle 3=\frac{x_1+x_2}{2}[/tex]

One of the two endpoints is (x + 4, 1/2y). Hence, we can substitute x + 4 for x₁:

[tex]\displaystyle 3=\frac{(x+4)+x_2}{2}[/tex]

Solve for the second x-coordinate x₂:

[tex]\displaystyle \begin{aligned} 6 & = x+4 + x_2 \\ \\ x_2 + x & = 2 \\ \\ x_2 & = -x +2 \end{aligned}[/tex]

Hence, the x-coordinate of the second point is -x + 2.

y-coordinate:

We have:

[tex]\displaystyle -2=\frac{y_1+y_2}{2}[/tex]

We can substitute 1/2y for y₁. This yields:

[tex]\displaystyle -2=\frac{\dfrac{1}{2}y+y_2}{2}[/tex]

Solve for y₂:

[tex]\displaystyle \begin{aligned} -4 & = \frac{1}{2}y + y_2 \\ \\ y_2 & = -\frac{1}{2}y - 4\end{aligned}[/tex]

In conclusion, the other coordinate expressed in terms of x and y is:

[tex]\displaystyle \left(-x+2, -\frac{1}{2}y-4}\right)[/tex]

Answer:

This is for a different question the answer above is correct because I used it steps. Now the question below is similar and is on the test.

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