nothing changes with tangent

Answers

Answer 1

hello

to solve this question, we have to use trigonometric ratios and in this case, it was specified to use tangent

from the image above, we can see that we have the value of angle and opposite and we need to look for adjacent

trigonometric ratio is given as SOH CAH TOA

[tex]\begin{gathered} \text{soh}=\text{sin}\theta=\frac{opposite}{\text{hypothenus}} \\ \text{cah}=\cos \theta=\frac{adjacent}{hypothenus} \\ \text{toa}=\tan \theta=\frac{opposite}{adjacent} \end{gathered}[/tex]

now, let's use the formula of tangent to solve this problem

[tex]\begin{gathered} \tan \theta=\frac{opposite}{adjacent} \\ \text{opposite}=42 \\ \theta=64^0 \\ \text{adjacent}=x \\ \tan 64=\frac{42}{x} \\ x=\frac{42}{\tan 64} \\ x=20.48 \end{gathered}[/tex]

from the calculations above, the value of x is equal to 20.48

Nothing Changes With Tangent

Related Questions

how do I put 5/7-i in standard form?

Answers

To put

[tex]\frac{5}{7-i}[/tex]

In the standard form, we must multiply the numerator and denominator by the complex conjugate of (7-i), it means

[tex]\frac{5}{7-i}\cdot\frac{7+i}{7+i}[/tex]

And now we solve it, therefore

[tex]\frac{5}{7-i}\cdot\frac{7+i}{7+i}=\frac{5(7+i)}{7^2-i^2}[/tex]

Remember that

[tex]i^2=-1[/tex]

Then

[tex]\begin{gathered} \frac{5(7+i)}{7^2-i^2}=\frac{5(7+i)}{49+1} \\ \\ \frac{5(7+i)}{49+1}=\frac{5(7+i)}{50} \end{gathered}[/tex]

Now we can simplify it

[tex]\frac{5(7+i)}{50}=\frac{7+i}{10}[/tex]

And we have it in the standard form

[tex]\frac{7}{10}+\frac{1}{10}i[/tex]

If translation T maps point A(-3, 1) onto point A'(5, 5),
which is the translation T?

Answers

Answer:  [tex](x,y) \to (x+8, y+4)[/tex]

==================================================

Explanation:

The x coordinate of A and A' are -3 and 5 respectively.

This is an increase of +8 since -3+8 = 5

Therefore, we shift the preimage 8 units to the right to get the image point.

That explains how x turns into x+8.

-------------

The y coordinates of A and A' are 1 and 5 respectively.

This is an increase of +4, so we shift the preimage up 4 units.

This signals that y turns into y+4

--------------

To recap we found that,

x becomes x+8y becomes y+4

Therefore we get to the answer [tex](x,y) \to (x+8, y+4)[/tex]

--------------

To check the answer, let's apply this translation to point A(-3,1) and we should get (5,5) as the result.

[tex](\text{x},\text{y})\to(\text{x}+8,\text{y}+4)\\\\(-3,1)\to(-3+8,1+4)\\\\(-3,1)\to(5,5)\\\\[/tex]

This confirms the answer is correct.

please help me work through this if you can, thank you!

Answers

Given:

[tex]C=\frac{x^4}{4}-\frac{4}{3}x^3-\frac{35}{2}x^2+150x[/tex]

Let's solve for the following:

• (a). Find C'(x).

Here, we are to find the derivative of C(x).

Apply the sum rule:

[tex]\begin{gathered} C^{\prime}=\frac{d}{dx}(\frac{x^4}{4})+\frac{d}{dx}(-\frac{4}{3}x^3)+\frac{d}{dx}(-\frac{35}{2}x^2)+\frac{d}{dx}(150x) \\ \\ C^{\prime}=x^3-4x^2-35x+150 \end{gathered}[/tex]

• (b). The critical numbers of C(x).

The critical numbers will be the points where the graph changes direction.

Using the derivative, let's solve for x.

[tex]x^3-4x^2-35x+150=0[/tex]

Factor the left side using the rational root test:

[tex](x-5)(x^2+x-30)=0[/tex]

Now factor using the AC method:

[tex]\begin{gathered} (x-5)((x-5)(x+6))=0 \\ \\ (x-5)(x-5)(x+6)=0 \end{gathered}[/tex]

Equate each factor to zero and solve for x:

[tex]\begin{gathered} x-5=0 \\ \text{ Add 5 to both sides:} \\ x-5+5=0+5 \\ x=5 \\ \\ \\ x-5=0 \\ x-5+5=0+5 \\ x=5 \\ \\ \\ x+6=0 \\ x+6-6=0-6 \\ x=-6 \end{gathered}[/tex]

Therefore, the critical numbers of C(x) are:

x = -6, 5

• (C). Increasing interval.

Use the critical points to find the increasing and decreasing intervals.

Using interval notation, the increasing interval is:

[tex](-6,5)\cup(5,\infty)[/tex]

• D. Decreasing interval:

Using interval notation, the decreasing interval is:

[tex](-\infty,-6)[/tex]

ANSWER:

(a). C'(x) = x³ - 4x² - 35x + 150

(b). x = -6, 5

(c). Increasing: (-6, 5) U (5,∞)

Decreasing: (-∞, -6)

Find the solution.7 · x = 8412139177

Answers

We need to find the value for x using the inverse operation:

Then:

[tex]\begin{gathered} 7-x=84 \\ \end{gathered}[/tex]

Let us solve for x:

The x is subtracting, so it will add up to the other side:

[tex]7=84+x[/tex]

Now, the 84 is positive, so it will be negative on the other side:

[tex]\begin{gathered} 7-84=x \\ x=-77 \end{gathered}[/tex]

Hence, the solution for x is -77.

Given that f ( x ) = 3 x − 6 f ( x ) = 3 x - 6 and g ( x ) = 2 − x 2 g ( x ) = 2 - x 2 , calculate

Answers

If it is given  f(x) = 3x− 6 and g(x) = 2- x² then f(g(x)) = -6x².

To solve this problem we have to know more about mathematical functions.

What is a mathematical function?

A mathematical function is a such type of mathematical device as it establishes a special type of relation which provides an output concerning an input.

Example:  f(x) = x²+ 2 where f(x) is a function of x where x is the input. If x = 3 then the output value of f(x) = 3²- 2 = 9-2 = 7.

Here we have to calculate, f(g(x)) where f is a function of g(x) and g(x) is a function of x.

g(x) = 2- x².

f(x) = 3x - 6.

Therefore,

f(g(x)) = 3( 2- x² ) - 6.                 [where g(x) = 2- x²]

So,  f(g(x)) = 3( 2- x² ) - 6 = 6 -6x² -6 = -6x²

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The complete question:

Given that f(x) = 3x − 6 and g(x) = 2 - x² , calculate f(g(x))

An air traffic controller spots two planes flying at the same altitude. Their flight paths form a right angle at point P. One plane is 150 miles from point P and is moving at 440 miles per hour. The other plane is 200 miles from point P and is moving at 440 miles per hour. Write the distance s between the planes as a function of time t.

Answers

The distance s as a function of time is  s = 50√(162t² -126t +25)

Take miles and hours to be the problem's units.

The distance of the first plane from point p is provided by

x = 150 -450t

The distance of the second plane from point p is given by

y = 200 -450t

The Pythagorean theorem can be used to calculate the distance between them because their flight trajectories are at right angles (s).

s² = x² + y²

s² = (150 -450t) (150 -450t)

² + (200 -450t)² = 22500 -135000t +202500t² +40000 -180000t +202500t²

... s² = 40500t² -315000t +62500 = 2500(162t² -126t +25)

... s = 50√(162t² -126t +25)

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Victor earns 19% commission as a salesperson. He sold a microscope that cost $368.84. How much commission did Victor earn? Round your answer to the nearest cent: $

Answers

Victor earns 19% commission

He sold a microscope that cost $368.84.

so, the commission = 19% of $368.84 = 0.19 * 368.84 = 70.0796

Rounding to the nearest cent

So,

the commission = $70.08

. Which units can be used to measure distance?
A. seconds
B. cubic centimeters
C. meters
D. liters

Answers

Answer:

c

Step-by-step explanation:

The metre or meter, symbol m, is the primary unit of length in the International System of Units, though its prefixed forms are also used relatively frequently.

I don’t know how to find the median and the mode HELPP

Answers

First, let's write the data set in crescent order:

[tex]35,35,44,50,50,50,56,60,65,70,86,90,110[/tex]

The mean is given by the sum of all values divided by the number of values:

[tex]\begin{gathered} mean=\frac{35+35+44+50+50+50+56+60+65+70+86+90+110}{13}\\ \\ mean=\frac{801}{13}\\ \\ mean=61.62 \end{gathered}[/tex]

The median is given by the central value of the set in crescent order. Since this set has 13 values, the median is the 7th value:

[tex]median=56[/tex]

The mode is the value that repeats the most. Looking at the set, the value that repeats the most (three times) is 50, so the mode is 50.

Which of the following hypotheses is not a valid null hypothesis?a.H0: µ = 0b.H0: µ ≥ 0c.H0: µ ≤ 0d.H0: µ < 0

Answers

Given:

a. H0: µ = 0

b. H0: µ ≥ 0

c. H0: µ ≤ 0

d. H0: µ

Required:

To choose the hypotheses that is not valid.

Explanation:

The null hypothesis: It is a statement of no difference between sample means or proportions or no difference between a sample mean or proportion and a population mean or proportion. In other words, the difference equals 0.

Here the option d is not valid.

Final Answer:

The option d is not valid.

H0: µ < 0

7. 200 is the ? th term of 24, 35, 46, 57, ..

Answers

200 is the 17th term of the progression

What is arithmetic progression?

Arithmetic progression or arithmetic sequence (AP) is a numerical series in which the difference between subsequent terms is constant. The sequence 5, 7, 9, 11, 13, 15,..., for example, is an arithmetic progression with a common difference of 2. A finite arithmetic progression, or simply an arithmetic progression, is a finite section of an arithmetic progression. An arithmetic series is the sum of a finite arithmetic progression. An arithmetic series is the sum of the elements of a finite arithmetic progression. A closed expression determines the product of the members of a finite arithmetic progression with a beginning element a1, common differences d, and n elements in total.

This can be solved using arithmetic progression

Aₙ = a + (n - 1)d

where, Aₙ = 24, d = 35 - 24 = 11

so, n = (Aₙ - a)/d + 1 = (200-24)/11 + 1 = 17

Hence, 200 is the 17th term of the progression

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What is the volume, in cubic inches, of a rectangular prism with a height of 19in, a width of 8in, and a length of 17in?

Answers

The volume of a rectangular prism is given by

[tex]V=L\times W\times H[/tex]

Where L is the length, W is the width, and H is the height of the rectangular prism.

For the given case, we have

Length = 17 in

Width = 8 in

Height = 19 in

Let us substitute these values into the above formula

[tex]\begin{gathered} V=L\times W\times H \\ V=17\times8\times19 \\ V=2584\: in^3 \end{gathered}[/tex]

Therefore, the volume of the given rectangular prism is 2584 cubic inches.

Give the standard form of the given equation below. If it is a quadratic equation, then give the a, b, and c coefficients. 3x2-2x-5x(x-7)=(x-2)(x+4)+1

Answers

Answer:

[tex]\begin{gathered} -3x^2+31x+7=0 \\ a=-3 \\ b=31 \\ c=7 \end{gathered}[/tex]

Step-by-step explanation:

The quadratic equation in standard form is represented by:

[tex]ax^2+bx+c=0[/tex]

For the following equation;

[tex]\begin{gathered} 3x^2-2x-5x(x-7)=(x-2)(x+4)+1 \\ 3x^2-2x-5x^2+35x=x^2+4x-2x-8+1 \\ -2x^2-2x+35x=x^2+2x-7 \end{gathered}[/tex]

Compute all the terms on the left side, equalizing 0:

[tex]\begin{gathered} -3x^2+31x+7=0 \\ \text{Then, the a,b and c coefficeints would be:} \\ a=-3 \\ b=31 \\ c=7 \end{gathered}[/tex]

Solve the problems fill in the blanks show you work I NEED HELP!

Answers

The fill in the blanks (that uses division) can be filled as -1.2([tex](\frac{2}{5} )[/tex] ÷ -2, -0.48÷-2 and 0.24.

According to the question,

We have the following information:

-1.2 [tex](\frac{2}{5} )[/tex] ÷ -2

Now, we have to solve this problem and fill the blanks at the same time.

Now, the first step would be to write the question.

So, for the first blank we have:

-1.2 [tex](\frac{2}{5} )[/tex] ÷ -2

Now, the required number is (2/5).

Now, the next step is to multiply -1.2 with 2/5:

-2.4/5

-0.48

So, the second blank can be filled by -0.48.

Now, the third step would be to divide -0.48 by -2:

-0.48÷-2

0.24

So, the next blank can be filled by 0.24.

Hence, the numbers in the blanks are [tex]\frac{2}{5}[/tex], -0.48 and 0.24 respectively.

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Is -36/6 a integer number

Answers

Answer:

Yes

Step-by-step explanation:

-36/6 = -6

Integers are the whole numbers (0.1.2.3.4.5....) and their opposites ...-4,-3,-2,-1

Help need please!!!!!!!factorize 36a-12b-60c

Answers

Solution:

Given:

[tex]36a-12b-60c[/tex]

The greatest common factor (GCF) is factored out of the expression.

The GCF is 12.

Hence,

[tex]36a-12b-60c=12(3a-b-5c)[/tex]

Therefore, the factorization of the given polynomial 36a - 12b - 60c is;

[tex]12(3a-b-5c)[/tex]

111 pointFind cot(1.570/7.3). Round to 3 decimal places.Type your answer...

Answers

[tex]\cot (\frac{1.5\pi}{7.3})=\tan ^{-1}(\frac{1.5\pi}{7.3})\text{ = }32.844[/tex]

Number 6. Find the missing measure and round to nearest 10th

Answers

Note that Cosine law can be used if three sides of the triangle are given in order to get the angles.

For example, in getting the measurement of angle C

[tex]\cos C=\frac{a^2+b^2-c^2}{2ab}[/tex]

Then take the arccos to get the angle C.

From the problem, we have :

We need to find the measurement of angle F using the same formula above.

[tex]\begin{gathered} \cos F=\frac{16^2+12^2-18^2}{2(16)(12)} \\ \cos F=\frac{19}{96} \end{gathered}[/tex]

Taking the arc cosine :

[tex]\begin{gathered} \angle F=\arccos (\frac{19}{96}) \\ \angle F=78.58 \end{gathered}[/tex]

The answer rounded to the nearest 10th is

What is 3+2? and add 7 then subtract 4

Answers

the answer is 8

add 3+2, that gives u 5, add 7+5 which is 12, do 12-4 its equal to 8

p and q are both prime numbers. They are each less than 22 Give an example where p + q is odd but not prime. You must only write the two numbers in the answer box. Type here to search O RI e Total ma​

Answers

Answer:

See below

Step-by-step explanation:

2 + 7  = 9       2 and 7 are prime     the answer is odd but not prime

Why did the turkey volenteer to be the drummer in the popular bird band? only 2.1 section

Answers

Answer:

I eat birds tasty

#3 TV Aspect RatioUsing your knowledge of aspect ratios, find the difference between the actualscreen size or area of an older style TV with an aspect ratio of 4:3 and a newer TVwith an aspect ratio of 16:9. Assume that both TV's are 52 inches in height. Whatis the difference in the areas of the two TV's? (show all work and justify youranswer) (8 points)

Answers

3:4 ratio

height: 52 in

width: height * 4/3 = 52*4/3 = 208/3 in

Area of the TV: height*width = 52*208/3 = 3605 1/3 square inches

9:16 ratio

height: 52 in

width: height * 16/9 = 52*16/9 = 832/9 in

Area of the TV: height*width = 52*832/9 = 4807 1/9 square inches

Then, the difference in the areas is: 4807 1/9 - 3605 1/3 = 1201 7/9 square inches

What is the answer to this question?

Answers

The probability of drawing a blue socks and white socks is 1/12.

Given that, a drawer contains 10 red socks, 6 white socks and 8 blue socks.

What is probability of an event?

Probability is a type of ratio where we compare how many times an outcome can occur compared to all possible outcomes.

As we know the probability of an event = Number of favorable outcomes/Total number of outcomes

Total number of outcomes = 10+6+8=24

Probability of getting blue socks = 8/24 = 1/3

Probability of getting white socks = 6/24 =1/4

Now, probability of an event = 1/3 × 1/4 = 1/12

Therefore, the probability of drawing a blue socks and white socks is 1/12.

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The quadrilateral RSTU is inscribed in the circle shown below. S R U Jake wants to prove the theorem that says that the measure of the quadrilateral's opposite angles add to 180°. He knows that the measure of angle Ris half the measure of are STU and that the measure of angle T is half the measure of arc SRU. Which of the following is an appropriate step to prove that ZR + ZT =180°?

Answers

Arc STU and arc SRU can form the complete circle. Therefore

[tex]Therefore,[tex]\begin{gathered} 2R+2T=360^0 \\ \text{factorize left hand side} \\ 2(R+T)=360^0 \end{gathered}[/tex]

Dividing both sides by 2, we have

[tex]Hence, the appropriate steps are: Assume that the measure of arcs STU and SRU add up to 360 degrees

Also, substitute 2 m

pick yes in options 2 and 3

pick no in options 1 and 4

Here’s the question to solve. Just do the question that has the chart

Answers

Step 1:

Write the equation

[tex]x^4-x^3+3x^2\text{ - 9x }-\text{ 54 = 0}[/tex]

Step 2:

Use trial and error to find one the the factor

x - 3 is a factor

Because when you substitute x = 3, the result is zero

Hence, 3 is zero of the polynomial

Step 3

Use the long division

If the proportion of the total disposable income spent on consumer goods and services is 91.6 percent and if consumers spend 82.0
percent of each additional dollar, what is
Instructions: Round your responses to three decimal places.
a. the APC?
b. the APS?
c. the MPC?
d. the MPS?

Answers

a) The Average Propensity to Consume (APC), rounded to three decimal places, is 0.916.

b) The Average Propensity to Save (APS), rounded to three decimal places, is 0.084.

c) The Marginal Propensity to Consume (MPC), rounded to three decimal places, is 0.820.

d) The Marginal Propensity to Save (MPS), rounded to three decimal places, is 0.180.

What do these economic indexes mean?

The average propensity to consume is the ratio of consumption expenditures to the total consumers' disposable income.

The average propensity to save is the inverse of the APC. It shows the rate of or total disposable income reserved instead of being consumed.

The marginal propensity to consume is the ratio of consumption based on additional income.

The marginal propensity to save is the inverse of the MPC, showing the percentage of the additional income saved instead of being consumed.

APC = 91.6%

= 0.916

APS = 1 - APC

= 0.084 (1 - 0.916)

MPC = 82%

= 0.820

MPS = 1 - MPC

= 0.180 (1 - 0.820)

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please help me out fr

Answers

Christian, this is the solution to the problem:

p = 2l + 2w

Solving for l, we have:

2l = p - 2w

Dividng by 2 at both sides:

2l/2 = (p - 2w)/2

l = (p - 2w)/2

The correct answer is D.

Need some guidance and reassurance because I am not getting full points on my homework. Thanks.

Answers

Given the parent function:

[tex]y=x^3[/tex]

If y is shifted right by 7 units, we obtain:

[tex]Option\text{ D: }y=(x-7)^3[/tex]

If y is compressed horizontally by a factor of 7, we have:

[tex]Option\; E\colon y=(7x)^3=7^3x^3[/tex]

If y is stretched vertically by the factor 7, we obtain:

[tex]\text{Option H: }y=7x^3[/tex]

A shift downwards by 7 units gives:

[tex]\text{Option A: }y=x^3-7[/tex]

Point B is located at (-5, -5) on the coordinate plane. Point B is reflected over thex-axis to create point B'. What ordered pair describes the location of B'?

Answers

SOLUTION

If a coordinate is refleted over the x-axis, the formula to apply is

[tex](x,y)\rightarrow(x,-y)[/tex]

So for B(-5, -5), this becomes

[tex]\begin{gathered} B\mleft(-5,-5\mright)\rightarrow(-5,-(-5) \\ \\ the\text{ answer becomes } \\ \\ B(-5,-5)\rightarrow B^{\prime}(-5,5) \end{gathered}[/tex]

Solve the trigonometric equation for all values 0 ≤ x < 2π.tan x - 1 = 0

Answers

[tex]undefined[/tex]

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