Given: f(x) = 2×+ 4, g(×) = ײ +4×+4 and h(×)= ײ-4
Find:
1. (fg) (×)
2. (hg) (×)
3. (fh) (2)
4. (gf) (×)
5. (gh) (×)
6. (fh) (×)
7. (hg) (1)
The results of the operation of multiplication between two functions are, respectively:
2 · x³ + 12 · x² + 24 · x + 16 x⁴ + 4 · x³ - 16 · x - 16 - 32 2 · x³ + 12 · x² + 24 · x + 16 x⁴ + 4 · x³ - 16 · x - 16 2 · x³ - 4 · x² - 8 · x - 16 - 27How to find the product of two functions
According to function theory, there are five operations between two functions to create resulting functions:
Addition - f(x) + g(x) = (f + g) (x).Subtraction - f(x) - g(x) = (f - g) (x).Multiplication - f(x) · g(x) = (f · g) (x).Division - f(x) / g(x) = (f / g) (x).In this problem we must use the operation of multiplication between two functions.
Case 1
(f · g)(x) = (2 · x + 4) · (x² + 4 · x + 4)
(f · g)(x) = (2 · x + 4) · x² + 4 · (2 · x + 4) · x + 4 · (2 · x + 4)
(f · g)(x) = 2 · x³ + 4 · x² + 8 · x² + 16 · x + 8 · x + 16
(f · g)(x) = 2 · x³ + 12 · x² + 24 · x + 16
Case 2
(h · g)(x) = (x² - 4) · (x² + 4 · x + 4)
(h · g)(x) = (x² - 4) · x² + (x² - 4) · (4 · x) + (x² - 4) · 4
(h · g)(x) = x⁴ - 4 · x² + 4 · x³ - 16 · x + 4 · x² - 16
(h · g)(x) = x⁴ + 4 · x³ - 16 · x - 16
Case 3
(f · h)(x) = (2 · x + 4) · (x² - 4)
(f · h)(x) = 2 · x³ - 8 · x + 4 · x² - 16
(f · h)(x) = 2 · x³ - 4 · x² - 8 · x - 16
(f · h)(2) = 2 · 2³ - 4 · 2² - 8 · 2 - 16
(f · h)(2) = - 32
Case 4
(g · f)(x) = (x² + 4 · x + 4) · (2 · x + 4)
(g · f)(x) = 2 · x³ + 12 · x² + 24 · x + 16
Case 5
(g · h)(x) = (x² + 4 · x + 4) · (x² - 4)
(g · h)(x) = x⁴ + 4 · x³ - 16 · x - 16
Case 6
(f · h)(x) = (2 · x + 4) · (x² - 4)
(f · h)(x) = 2 · x³ - 4 · x² - 8 · x - 16
Case 7
(h · g)(x) = (x² - 4) · (x² + 4 · x + 4)
(h · g)(x) = x⁴ + 4 · x³ - 16 · x - 16
(h · g)(1) = 1⁴ + 4 · 1³ - 16 · 1 - 16
(h · g)(1) = - 27
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50% of $99.97
Two answers
Answer:
Step-by-step explanation:
you would cut 99 in half and make your way down until nothing left which gives you 48.985 or
49.99$ rounded
*4) The image of the origin under a certain translation is (5,-6). The
image of point (-4,2) under the same translation is which?
(1) (1,-4)
(3) (-5,6)
4).
(2) (9,8)
(4) (-9,8)
3. Ross wrote a check for $124 and received a notice 4.
from the bank stating he was $51 overdrawn. His
account now shows a negative balance. How much
money did he have in his account before writing the
check?
SC
1
3
Answer:
$73
Step-by-step explanation:
The following is a list of 4 measurements.10, 11, 15, 6Send data to calculatorSuppose that these 4 measurements are respectively labeled X1, X2, ..., *4. Compute the following.4Σi=1
Given the measurements:
x1 = 10
x2 = 11
x3 = 15
x4 = 6
We're asked to find:
[tex]\sum ^4_{i=1}(x_i)^2=x^2_{1^{}}+x^2_2+x^2_3+x^2_4[/tex]Which is
100+121+225+36
=482
A uniform continuous distribution has a maximum of 14 and a minimum of 2. Samples of size 36 are drawn from the distribution. What is the variance of the sample means?.
The variance of the sample mean is 12/35 = 0.3429.. This is a result of uniform distribution.
The uniform distribution is a continuous probability distribution and is concerned with events that are equally likely to occur. When working out problems that have a uniform distribution, be careful to note if the data is inclusive or exclusive.
According to the question, we have
Sample size (n) = 36; uniform continuous distribution has a maximum of 14 and a minimum of 2.
The notation for the uniform distribution is
X U(a,b), where a= the lowest value of x and b= the highest value of x. The probability density function is f(x) = 1/(ba ) fo axb .
b = 14 and a = 2.
Variance in uniform distribution = (b-a)² / 12.
Put the value of a and b,
Variance = ( 14-2)²/12 = 12
Sample variance is used to calculate the variability of sample sets.
The variance of the sample means = variance / (sample size- 1) 9= (b-a)²/ (n-1)
= 12/35= 0.342
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Dividing decimals by whole numbers !pls helpp divide 4./280.8
When dividing 4 by 280.8, the answer gotten is 0.014245.
What are decimals?It should be noted that decimal numbers are numbers that have whole numbers as well as fractional parts. One of the number types in algebra that has a whole integer and a fractional portion separated by a decimal point is a decimal. The decimal point is the dot that appears between the parts of a whole number and a fraction. An example of a decimal number is 34.5. Examples are 2.4 and 9.34.
To divide a decimal by a whole number, follow these steps.
Directly above the decimal point in the dividend, place the decimal point in the quotient.Divide using full numbers in the same way as you would.Divide until there is no remainder or until a pattern emerges in the quotient. Whenever necessary, annex zeros.In this case, Dividing 4 by 280.8 will give a value of 0.014245.
Therefore the value is 0.014245.
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Dividing 4 by 280.8 gives
How to divide 4 by 280.8given data
4 ÷ 280.8
4 ÷ 280.8 = 4 / 280.8
= 4 / 280.8
= [tex]\frac{4}{\frac{2808}{10} }[/tex]
= 4/1 * 10 /2808
= 40 / 2808
= 20 / 1404
= 10 / 702
= 5 / 351
5//351 is the lowest form of the fraction and in decimal it is solved as
= 5 / 351
= 0.01424501425
= 0.0142 ( to 4 decimal place )
What are decimals?Decimals refers to number types which are displayed using points. The points used here is called decimal points.
Numbers appearing after the decimal point is not a whole number. If the set of number bearing decimal point has zero as the first and only number, then the whole number is not up to a whole number.
This is synonymous to the case of the solved problem. The number 0.0142 does not have a whole number part. Hence the number is less than 1
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chegg a 12 ft ladder is leaning against a wall. if the top of the ladder slides down the wall at a rate of 4 ft/s, how fast (in ft/s) is the bottom moving along the ground when the bottom of the ladder is 6 ft from the wall?
The bottom is moving at a rate of [tex]4\sqrt{3}[/tex] ft/s along the ground when the botton of the ladder is at a distance of 6 ft from the wall.
Here we have been mentioned that a 12 feet ladder is leaning against the wall which is represened by AC in the below given triangle.
We have AB = y = distance of top of the ladder from the wall
BC = x = distance of bottom of the ladder from the wall
AC = z = height of the ladder = 12 ft (given)
The top of the ladder AB is sliding down at a rate of 4 [tex]ft/s[/tex]
∴ [tex]\frac{dy}{dt}[/tex] = - 4 ft/s (negative sign indicates that the top is sliding downwards)
Let the rate at which the bottom of the ladder is sliding be [tex]\frac{dx}{dt}[/tex]
Now in the right angled triangle [tex]ABC[/tex] by using Pythagoras theorem we have,
[tex]AB^{2} + BC^{2} =[/tex][tex]AC^{2}[/tex]
[tex]y^{2} +x^{2} = z^{2}[/tex] (equation 1)
When x = 6ft and z = 12 ft,
[tex]y^{2} +6^{2} = 12^{2}[/tex]
⇒ [tex]y^{2} = 144 - 36[/tex]
⇒ [tex]y^{2} = 108[/tex]
⇒ y = √108
⇒ y = 6 √3 ft
Differentiating equation 1 with respect to [tex]time[/tex] we get,
[tex]\frac{d}{dt} (y^{2} +x^{2} ) = \frac{d}{dt} (z^{2})[/tex]
⇒ 2y[tex]\frac{dy}{dt}[/tex] + 2x[tex]\frac{dx}{dt}[/tex] = 2z[tex]\frac{dz}{dt}[/tex]
Putting the values of dz/dt = 0 (as the height is constant) , dy/dt = - 4 ft/s , y = 6 √3 ft, x = 6ft and z = 12ft we have,
∴ 2(6√3) (-4) + 2(6)[tex]\frac{dx}{dt}[/tex] = 2(12)(0)
⇒ -48√3 + 12[tex]\frac{dx}{dt}[/tex] = 0
⇒ 12[tex]\frac{dx}{dt}[/tex] = 48√3
⇒ [tex]\frac{dx}{dt} = \frac{48\sqrt{3} }{12}[/tex]
⇒ [tex]\frac{dx}{dt} = 4\sqrt{3}[/tex] ft/s
Hence the rate at which the bottom of the ladder is sliding is [tex]\frac{dx}{dt} = 4\sqrt{3}[/tex] ft\s
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100!/12^50
Solve! Thanks.
After solving : 100!/12^50, we get 1.025513e+104
Here, 100 factorial or 100!
Describe Factorial.The result of multiplying an integer by each natural number below it is the factorial of that number.
A factorial can be symbolically denoted by the sign "!"
The first n natural integers are added together to form "n factorial," which is represented by the number n.
100! = 100 × 99 × 98 × .... × 3 × 2 × 1 = 9.332621544 E+157.
This product is too big to calculate manually and hence a calculator is used.
Now, 9.332621544 E+157 / 12 ^ 50 = 1.025513e+104
Hence, after solving 100!/12^50, we get 1.025513e+104
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The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (-1,8). The ball reaches the hole 1 second after it is hit. What is the equation of the parabola, in vertex form, that represents the ball's distance, y, from the hole, x seconds after the ball is hit?
The equation of the parabola, in vertex form, that represents the ball's distance, y, from the hole, x seconds after the ball is hit is
y = (-2m/s²)t² + (-2m/s)t + 6m.
Given:
Let's assume that the hole is at y = 0m, with x seconds as the time.
The vertex of the parabola can be written as (-1s, 8m) where the time variable, x, is supposed to be in seconds, while the distance variable, y, is supposed to be in meters.
The ball reaches the hole at x = 1s, so we have point (1s, 0m)
The vertex of the parabola y = ax² + bx + c is known to be at
x = -b/2a,
So, -1 = -b/2a
We have the following equations,
8m = a(-1s)² + b(-1s) + c
0m = a*(1s)² + b(1s) + c
-1s = -b/2a
b = 2a × 1s
Substituting the value of b in the equations and simplifying them,
8m = a×1s² - 1s×2a×1s + c
⇒ 8m = a( 1s² - 2s²) + c = -a×1s² + c.
0m = a×1s² + 1s×2a×1s + c
⇒ 0m = a(1s² + 2s²) + c = a×3s² + c
Deriving the value of c from the second equation we put it in the first equation,
c = - a×3s²
The first equation is as,
8m = -a×1s² - a×3s² = -a×4s²
a = 8m/-4s² = -2m/s²
From the value of a we can calculate the values of b and c.
c = -a×3s² = -(-2m/s²)×3s²= 6m.
b = 1s×2a = 1s×(-2m/s²) = -2m/s.
Then the equation is:
y = (-2m/s²)t² + (-2m/s)t + 6m
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Which expressions are equivalent to 211? Select all that apply.
What do the answer?
Answer:
A,B,C
Step-by-step explanation:
Multiply or divide.write the productor quotient in simplest form. 1 4/9 (-2 4/7
Answer:
-3 [tex]\frac{5}{7}[/tex]
Step-by-step explanation:
Is this the problem?
1 4/9 (-2 4/7)
[tex]\frac{13}{9}[/tex][tex](\frac{-18}{7})[/tex] = [tex]\frac{-26}{7}[/tex]
-3 [tex]\frac{5}{7}[/tex]
find two consecutive integers such that 3 times the larger exceeds twice the smallest by 34
Answer:
31 & 32
Step-by-step explanation:
3 x 32 = 96
2 x 31 = 62
62 + 34 = 96
if 333.33...points is 1 dollar, how much is 100points
Answer:
0.30 dollar
Step-by-step explanation:
333.33 points == 1 dollar
: 333.33
1 points == 0.003 dollar
* 100
100 points == 0.30 dollar
Carla wants to buy a set of dishes. The sale price is $72. What was the original price if it was %10 off
The original price of the dishes is $80
How to calculate the original price of the dishes ?
The sale price is $72
10% was off from the original price to get the sale price
The original price can be calculated as follows
100-10
= 90%
Let y represent the original price
72 ÷ 90/100
= 72 ÷ 0.9
= 80
Hence the original price of the dishes before 10% was taken off is $80
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From a temperature of -29.03° F, a solution heats up 26.5° F.
What is the resulting temperature of the solution?
Think about the situation. What operation does the situation require?
Drag a word to the box to correctly complete the statement.
Answer:
Remember, a positive and a negative while being added is always a negative outcome, so when you add -29.03 + 26.5, you get -2.53
2x + 8 = -4 I NEED ALL PLS
Answer:
Answer down below!
Step-by-step explanation:
Let's write out the equation!
2x + 8 = -4
To solve this, you have to subtract the 8 and bring it over to -4
That would look something like:
2x -(+8) = -4 -8
That leaves you with 2x = -12
Now you divide 2 and -12 which will give you
-6
Answer:X= - 6
Step-by-step explanation:
MOVE +8 to the right which would make it negative so -8-4.You would add both numbers which would be -12 and then u divide -12 with 2 so
-12/2 is -6
y= 24 will this be a vertical or horizontal line?
It will be a horizontal line
Please please help me with this I’ll give brainly
Hello!
The ratio between pig and other animals
==> looks like [tex]\text{number of pigs}: \text{ number of other animals}[/tex]
Since there are 8 pigs and 11 other kind of animals
⇒ the ratio is ⇒ 8: 11
Hope that helps!
[tex]2-\frac{x+1}{x-2} -\frac{x-4}{x+2}[/tex] can be written as a single fraction in the form [tex]\frac{ax+b}{x^{2} -4}[/tex] where a and b are integers.
work out the value of a, and the value of b
Answer:
a = 3 , b = - 18
Step-by-step explanation:
2 - [tex]\frac{x+1}{x-2}[/tex] - [tex]\frac{x-4}{x+2}[/tex]
express as a fraction with common denominator (x - 2)(x + 2)
= [tex]\frac{2(x-2)(x+2)-(x+1)(x+2)-(x-4)(x-2)}{(x-2)(x+2)}[/tex]
= [tex]\frac{2(x^2-4)-(x^2+3x+2)-(x^2-6x+8)}{x^2-4}[/tex]
= [tex]\frac{2x^2-8-x^2-3x-2-x^2+6x-8}{x^2-4}[/tex]
= [tex]\frac{3x-18}{x^2-4}[/tex]
compare to [tex]\frac{ax+b}{x^2-4}[/tex]
with a = 3 and b = - 18
Miranda and Lily both bought a used car on the same day. Miranda's used car has 5,132 miles on it already, and she drives 525 miles per month. Lily's car has 4,789 miles on it already, and she drives 723 mile per month.
The months will they have same number of miles. is 1.732 months.
How to illustrate the information!Miranda's used car has 5,132 miles on it already, and she drives 525 miles per month. This will be expressed as y = 5132 + 525x
Lily's car has 4,789 miles on it already, and she drives 723 mile per month. This will be:
y = 4789 + 723x
x = number of months
y = miles
The number of months will be gotten by equating the equations. This will be:
5132 + 525x = 4789 + 723x
Collect like terms
198x = 343
Divide
x = 343 / 198
x = 1.732 months.
The number of months is 1.732.
The complete question is written below.
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Miranda and Lily both bought a used car on the same day. Miranda's used car has 5,132 miles on it already, and she drives 525 miles per month. Lily's car has 4,789 miles on it already, and she drives 723 mile per month. How many months will they have same number of miles.
when Mrs. Smith makes chocolate-chip cookies, she uses 3/8 cup of chocolate chips for every 2 cups of flour. How many cups of chocolate chips would she use for 12 cups of flour?
In 12 cups of flour,we are going to have 2 cups of flour in six(6) places.
Thus, for 12 cups of flour, Mrs Smith will use:
[tex]\begin{gathered} \frac{3}{8}\times6\text{ cup of chocolate chips} \\ \Rightarrow\frac{18}{8}=\frac{9}{4\text{ }}cup\text{ of chocolate chips} \end{gathered}[/tex]In parallelogram ABCD, AB = 3 cm and the diagonals AC and BD are 5.8 cm and 4.2 cm respectively. If the diagonals AC and BD intersect at O, then the perimeter of ∆AOB is
In parallelogram ABCD, AB = 3 cm and the diagonals AC and BD are 5.8 cm and 4.2 cm respectively. If the diagonals AC and BD intersect at O, then the perimeter of ∆AOB is 8 cm
How to find the perimeterperimeter of a triangle = length 1 + length 2 + length 3
assuming
length 1 = AB = 3 cm
length 2 = 5.8 / 2
length 3 = 4.2 / 2
Reason for length 2 and length 3 is when the diagonal of a parallelogram intersect they bisect each other. bisect means divide each other into two equal parts
substituting the values
perimeter of the triangle = 3 + 5.8 / 2 + 4.2 / 2
= 3 + 2.9 + 2.1
= 8 cm
The perimeter of the triangle formed is 8 cm
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Draw the graph of y=2x+1
Answer: Here you go
Step-by-step explanation:
I need to write an solve an inequality that describes the width of the lot in terms of w
Given:
The length of the rectangle is 50 yards. The perimeter is less than 180 yards.
Required:
Write the solution inequality in terms of width w.
Explanation:
Let the width of the rectangle is w.
The perimeter of the rectangle is given by the formula:
[tex]P=2(length+width)[/tex][tex]\begin{gathered} 2(50+w)<180 \\ 50+w<90 \\ w<90-50 \\ w<40 \end{gathered}[/tex]Final Answer:
The first option is the correct answer.
A biologist is studying the growth of a particular species of algae. She writes the following equation to show the radius of the algae, f(d), in mm, after d days:
f(d) = 7(1.06)d
Part A: When the biologist concluded her study, the radius of the algae was approximately 13.29 mm. What is a reasonable domain to plot the growth function? (4 points)
Part B: What does the y-intercept of the graph of the function f(d) represent? (2 points)
Part C: What is the average rate of change of the function f(d) from d = 4 to d = 11, and what does it represent? (4 points)
From the given function, it is found that:
a. A reasonable domain for the function is of 0 ≤ d ≤ 11.
b. The y-intercept of the graph represents that the initial radius of the algae is of 7 mm.
c. The average rate of change between the 4th and the 11th day of the function means that the radius of the algae grew by an average of 0.64 mm a day.
What does the function represent?The function is modeled according to the following rule:
f(d) = 7(1.06)^d
In which:
d is the number of days.f is the radius of the algae.When the biologist concluded her study, the radius of the algae was approximately 13.29 mm, hence the upper bound of the domain is found as follows:
[tex]13.29 = 7(1.06)^d[/tex]
[tex](1.06)^d = \frac{13.29}{7}[/tex]
[tex]\log{(1.06)^d} = \log{\left(\frac{13.29}{7}\right)}[/tex]
[tex]d\log{1.06} = \log{\left(\frac{13.29}{7}\right)}[/tex]
[tex]d = \frac{\log{\left(\frac{13.29}{7}\right)}}{\log{1.06}}[/tex]
d = 11.
The smallest possible number of days is of 11, hence a reasonable domain for the function is:
0 ≤ d ≤ 11.
The y-intercept of the graph represents that the initial radius of the algae, as it is calculated when d = 0, hence it's value is given by:
[tex]f(0) = 7(1.06)^0 = 7[/tex]
The average rate of change of a function is given by the change in the output divided by change in the input, hence:
[tex]f(11) = 7(1.06)^{11} = 13.29[/tex][tex]f(4) = 7(1.06)^{4} = 8.84[/tex]r = (13.29 - 8.84)/(11 - 4) = 0.64 mm a day.
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9. Find the area of the shaded region.
22 cm
10 cm
7cm
Using the area of triangles and rectangles, we know that the area of the shaded region is 255cm².
What is the formula for the area of a rectangle and triangle?Area of rectangle = length x widthArea of triangle = 1/2 x base x heightIn the given shaded region there is one rectangle and one triangle.
First, find the area of the shaded rectangle.
Here, length = 22 cm and width = 10 cm.So, Area of rectangle = length x width = 22 x 10Area of rectangle = 220 square cm.Now find the area of the shaded triangle.
Here, base = 10 cm and height = 7 cm.So, the Area of the triangle is:
Area = 1/2 × 10 × 7= 35cm²Therefore, the total area of the shaded region is:
Area of shaded region = Area of rectangle + Area of triangle= 220 + 35Area of shaded region = 255 square cm.Therefore, using the area of triangles and rectangles, we know that the area of the shaded region is 255cm².
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ANSWER QUICK FOR BRAINIEST!
Solve the equation for x. −0.28x − 15.3 = 1.92 x = 61.5 x = −61.5 x = 47.8 x = −47.8
The value of x is −61.5 . option B
What is an algebraic expression?An algebraic expression is simply seen as one with terms, factors, variables, coefficients, constants.
These expressions may also consist of arithmetic operations, some of which includes;
AdditionDivisionSubtractionMultiplicationBracketParentheses, among others.Based on the information given, we have;
−0.28x − 15.3 = 1.92
To determine the value of the variable 'x' we need to take the following steps;
collect like terms from the equation
-0. 28x = 1. 92 + 15. 3
Add like terms
-0. 28x = 17.22
Divide both side by the coefficient of x
x = 17. 22/-0.28
x = - 61. 5
Hence, the value is - 61. 5
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i do NOT understand at all desperate need of help !!
Lets first look at the cost per round with the 25 round pass
Take the total cost and divide by the number of rounds
$84 / 25 rounds
$ 3.36 per round
OR
They can pay 3.25 per round with the single pay
$3.25 is less than 3.36 so it is cheaper ( less per round) to pay the single round price
Option 2 $3.25 is cheaper
Kaitlin has a bookcase with books. There are 50 shelves in the bookcase. Each shelf has the same number of 5 books. How many books does each shelf have?