The molecular mass of the given compound using the given mass of element is 40g/mol.
Given Molar Mass
T 10g/mol
P 1 g/mol
L 2g/mol
Molecular formula → T2P10L5
(i)The Molecular Mass of the given Molecule is: →
= (2x10 g/mol) + (10x1 g/mol) + (5×2g/mol)
= (2 + 10 + 10)g/mol
= 40g/mol
(ii) Mass percent of T = /[tex]\frac{Mass of T in comparing}{Molecular Mass of comperend} *100[/tex]
= 20/40 = 1/2 %The mass percent of T = 1/2 %
(iii) Mass percent of P = 10/40 = 1/4%
(iv) Mass percent of L = 10/40 = 1/4%
(V) When you add up Mass percents = 1/2 + 1/4 + 1/4 = 2+1+1/4 = 4/4 = 1.
The composition percentage indicates what types of atoms are present in the molecule and at what level. Percent composition also tells us about the various elements present in ionic compounds. The composition of a solution can be expressed in mass percent and indicates the mass of solute present in a given mass of solution.
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In a set of experiments on a hypothetical one-electron atom, you measure the wavelengths of the photons emitted from transitions ending in the ground state (n=1) as shown in the energy-level diagram in the figure (Figure 1). You also observe that it takes 17.50 eV to ionize this atom.
The wavelength of the photon that is emitted from transitions ending in the ground state is 397.56 nm
E(n) = - k/n^2
In fact, since the ionization energy (from ground state) is:
-E(1), E(n) = - (17.5 eV)/n^2
E(1) = -17.5 eV
E(2) = -4.375 eV
E(3) = -1.94 eV .
E(4) = -1.094 eV
E(5) = - 0.7 eV
The change in energy going from n = 4 to n = 2 will be:
E(4) - E(2) = 3.281 eV
The change in energy = hc/∧, so
∧ = h/energy-change
= 6.626 x 10-34 x 3 x 108 /(3.281 x 1.6022 x 10-19 J)
= 397.56 x 10-9 m
= 397.56 nm
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How many grams are in 0.500 mol Co?
Which Ocean currents are mostly affecting container ships?
Answer:
Ocean currents can affect the movement of ships in different ways, depending on the direction and strength of the current. In general, the most important ocean currents for container ships are the warm, eastward-flowing currents and the cold, westward-flowing currents. These currents are important because they affect the speed and direction of ships as they travel across the ocean. Some of the major ocean currents that are known to affect container ships include the Gulf Stream, the Kuroshio Current, and the Humboldt Current. These currents can have a significant impact on the route and speed of container ships, and ship operators must take them into account when planning their journeys.
Explanation:
A cook heats water from 22 o C to 50 o C. Calculate the mass of water that could be warmed by the addition of 10.00kJof heat
Answer:
Explanation:
Q=M*C*ΔT
Where,Q=Required heat
C=Specific heat of water
ΔT=Temperature change
[tex]M=\frac{Q}{C*T}[/tex]
[tex]M=\frac{10000}{4.184*28}[/tex]
[tex]M=\frac{10000}{117.15}[/tex]
[tex]M=85.3g[/tex]
Q = mcT, where Q is the heat provided, m is the mass of water, and c is the temperature change, may be used to determine how much water can be warmed by the addition of 10.00kJ of heat.
What happens in this instance ?In this instance, the water's beginning temperature is 22°C, and its ultimate temperature is 50°C, meaning that there has been a 28°C change in temperature.
Water has a heat capacity of 4.184 J/g°C, therefore m = Q / (cT) = 10.00kJ / (4.184 J/g°C x 28°C) = 7.08kg is the mass of water that can be warmed by the addition of 10.00kJ of heat. As a result, 7.08 kg of water may be warmed with the addition of 10.00 kJ of heat.
Considering that heat immediately proportionate to the water's bulk and temperature. The amount of heat needed to warm the water increases with the bulk of the water and the temperature change.
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9. Which of the following best explains why a hot air balloon rises and floats in air?
A. Air particles inside the balloon are farther apart, causing its density to be higher than the density of air outside the balloon.
B. Air particles inside the balloon are farther apart causing its density to be less than the density of air outside the balloon.
C. Air particles inside the balloon are closer together, causing its density to be higher than the density of the air outside the balloon.
D. Air particles inside the balloon are closer together, causing its density to be lower than the density of the air outside the balloon.
a solution of the chloride salt, hbcl, of the weak base b will have a. a ph less than 7 b. greater than 7 c. equal to 7
Strong bases and weak acids can hydrolyze into salts, raising the pH level over 7. Ammonium chloride (NH 4 Cl) is a salt whose solution has a pH of less than 7.
The pH will be less than seven when the solution is acidic and higher than seven when the solution is basic. Because Na2CO3 is a salt comprising a strong base and a weak acid, it will produce the highest pH in water. The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.
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the electron geometry of a moeluclar who has a central atom with four single bonds and one lone pair of electrons is which of the following
The molecular geometry of a molecule whose central atom has four single bonds and two lone pairs of electrons is square planar.
The shape of the orbitals is octahedral. Two orbitals contain lone pairs of electrons on opposite sides of the central atom. The remaining four atoms connected to the central atom give the molecule a square planar shape. If there are only two bonds and one lone pair of electrons holding the place where a bond would be then the shape becomes bent. For sp3 hybridized central atoms the only possible molecular geometry is tetrahedral. If all the bonds are in place the shape is also tetrahedral.
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A student determines the value of the equilibrium constant to be 6.54×103 for the following reaction. CO(g) + H2O(l)CO2(g) + H2(g) Based on this value of Keq: G° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 2.32 moles of CO(g) at standard conditions at 298K. G°rxn = kJ
A. Co + H₂O ⇄ co₂+ H₂
= -8.314[tex]\frac{J}{K.mol}[/tex] x298k x In (6.54x16³)
= -21.77 kJ/m0/
for 2.32 molco, A = -21.77×2-32
= -50.51kj/mol
B. Fe₂03(5) +3H₂(9) ⇄ 2 Fe(s) + 3H₂0(9)
= -8.314 × 298x/n (2.47x10⁻¹⁰)
= +54.807 kJ/mol
for 1.61 mol fe₂03, Δ4= 54.807 X 1.61 mol
= 88.24 kJ/mol.
Equilibrium constant numbers are obtained by allowing a single reaction to reach equilibrium and measuring the concentrations of each substance involved in the reaction. The ratio of product concentration to educt concentration is calculated. A mathematical ratio indicating product concentration divided by reactant concentration.
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which of the following represents the reaction of a strong acid with water? a generic acid, ha, is used in the reactions.
The chemical equation of the generic acid is
HA(aqueous) + H2O(liquid) → H3O⁺(aqueous) + A⁻(aqueous)
The generic acid formula is H₂GO₃, formed from two hydrogen ions (2 H⁺) and one product ion (GO₃²⁻). It is liquid at room temperature. Being generic, it does not have a defined melting point or boiling point, molar mass, pH, LD50, or many other properties. However, it is a weak acid. If you want a stronger acid, the hydrogen acid is stronger. It is the most famous generic compound. It's often used in fiction when writers don't want to indicate a certain kind of acid. Fictitious generic acids may have unrealistic properties, and using generic acids prevents authors from claiming that real substances do the impossible. The reaction of the generic acid is given above.
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5. Use the following chemical equations to answer the questions below.
Mg(s) + AgNO3(aq) ->Ag(s) + Mg(NO3)2
Na₂SO4 (aq) + BaCl₂(aq) –>
BaSO4(s) + NaCl(aq)
a) Identify each type of reaction.
b) Write the balanced chemical equation
for each.
The reaction: Mg(s) + 2AgNO₃(aq) → Mg(NO₃)₂(aq) + 2Ag(s) it represents the single replacement reaction.
Na₂SO4 (aq) + BaCl₂(aq) → BaSO₄(s) + 2NaCl(aq) it represents the Double displacement reaction.
What is single replacement reaction and double displacement reaction?A simple exchange reaction is one in which a more reactive element displaces a less reactive element from brine. Compared to silver, magnesium easily loses electrons, leading to the formation of magnesium nitrate and silver.
A double displacement reaction is a chemical reaction in which ion exchange occurs. Na₂SO₄ reacts with BaCl₂ to produce BaSO₄ and sodium chloride.
The balanced equation becomes:
Mg(s) + 2AgNO₃(aq) → Mg(NO₃)₂(aq) + 2Ag(s)
Na₂SO4 (aq) + BaCl₂(aq) → BaSO₄(s) + 2NaCl(aq)
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The particulate model below represents the redox reactions that produce energy from fuel cells. Use the model to answer the following questions.Part 1 Write a balanced half-cell equation for the reaction occurring at the anode. Ignore phases in the reaction.
Part 2 Write a balanced half-cell equation for the reaction occurring at the cathode. Ignore phases in the reaction.
Assuming excess oxygen, how many moles of electrons would be transferred if 3 moles of H2 were reacted. moles of electrons
Answer:
To answer this question, you need to first write the balanced half-cell equations for the reactions occurring at the anode and the cathode.
At the anode, the reaction is:
H2 → 2H+ + 2e-
At the cathode, the reaction is:
1/2O2 + 2H+ + 2e- → H2O
Then, assuming that there is excess oxygen, we can calculate the number of moles of electrons that would be transferred if 3 moles of H2 were reacted. To do this, we need to first determine how many moles of H+ ions are produced when 3 moles of H2 are reacted at the anode. This can be calculated using the balanced half-cell equation for the anode reaction, which shows that 2 moles of H+ ions are produced for every mole of H2 reacted. Therefore, 3 moles of H2 would produce 6 moles of H+ ions.
Next, we can use the balanced half-cell equation for the cathode reaction to calculate how many moles of electrons are transferred when 6 moles of H+ ions are reacted. This equation shows that 2 moles of electrons are transferred for every mole of H+ ions that is reacted. Therefore, 6 moles of H+ ions would result in the transfer of 12 moles of electrons.
Therefore, the final answer is:
12 moles of electrons would be transferred if 3 moles of H2 were reacted.
the fundamental particles of matter are:atoms and molecules. quarks and leptons. electrons, protons, and neutrons.
Quarks and leptons are considered fundamental particles of matter. Therefore, option 2 is correct.
An elementary particle, also known as a fundamental particle, is a subatomic particle that is not connected to any other particle. Leptons and quarks are two significant elementary particles. There are six different types of quarks and leptons as well as three generations of matter. Protons and neutrons, on the other hand, are no longer regarded as fundamental particles. Instead, it is now thought that they are composed of smaller, more fundamental particles of matter, known as quarks. Leptons are elementary particles because they don't seem to be made of any other subatomic particles. Leptons can exist in two states: neutral or charged with one unit of electricity. The electrons, muons, and taus are considered charged leptons.
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Answer: What is an Atom? The answer is the fundamental unit of matter
Explanation: EDG2023
out of the following elements which has the 3s orbital furthest from the nucleus? bromine selenium arsenic germanium all the same
Bromine, selenium, arsenic, germanium has 4 shells around the nucleus.
What is the periodic table?The chemical elements are arranged in rows and columns in the periodic table, which is also known as the periodic table of the (chemical) elements.
It is commonly regarded as an icon of chemistry and is utilized extensively in physics, chemistry, and other sciences.
The periodic law, which asserts properties of chemical elements display a roughly periodic dependency on their atomic numbers, is graphically expressed in this way.
Four blocks, or roughly rectangular sections, make up the table. Periods and groups are the names of the table's rows and columns, respectively.
The chemical properties of elements in the same group on the periodic table are similar. The periodic table shows trends, with the proportion of non-metallic elements rising from left to right over time.
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HELP PLEASE
Draw the atomic structure (nucleus and electron orbitals) for the following atoms and label the valence electrons in each sodium chlorine carbon
The atomic structure for the following atoms is attached below and number of valence electrons in sodium, chlorine,carbon are 1,7,4 respectively.
What is an atom?An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.
The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.
Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.
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A zinc sample (work function is 4.3 eV) is struc k by light at 200 nm. What happens if the intensity of the light is tripled O The number of ejected electrons is tripled O The kinetic energy of the ejected electrons is tripled O The number of ejected electrons decreases by 1/3 O No change is observed because light at 200 nm is not enough to cause electrons to be ejected O The kinetic energy of the ejected electrons decreases by 1/3
If the intensity of the light is tripled, then the number of ejected electrons decreases by 1/3.
The energy E of a photon is equal to hv = hc/λ, where v is the frequency of the electromagnetic radiation and λ is its wavelength.
The given parameter is:
lambda = 2*10^-7 m
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(2*10^-7 m)
= 9.939*10^-19 J
E = 9.939*10^-19 J
= 9.939*10^-19/(1.602*10^-19) eV
= 6.204 eV
Since, this is more than 4.3 eV, electron will be ejected.
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propose a solution to decrease the total amount of chemical pesticides used in britain for agriculture.
What is genetic modified organisms?
genetically modified organism (GMO) is associate animal, plant, or germ whose DNA has been altered victimization gene-splicing techniques. For thousands of years, humans have used breeding ways to change organisms.
Many GMO crops are wont to create ingredients that Americans eat adore cornstarch, corn syrup, corn oil, soybean oil, canola oil, or coarse sugar. many contemporary fruit and vegetables are on the market in GMO varieties, together with potatoes, summer squash, apples, papayas, and pink pineapples
Hence solutions are:
The response proposes an answer such as the subsequent for decreasing the full quantity of chemical pesticides employed in United Kingdom of Great Britain and Northern Ireland for agriculture:
Use genetically changed organisms () that are designed for gadfly resistance. observe integrated pest-management techniques to regulate pests.
Hence use of Genetic modified organisms is solution.
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write the word equation for reactions 3 and 4, using ammonium carbonate, calcium carbonate, and hydrochloric acid.
With ammonia bicarbonate, calcium, and hydrochloric acid, the word equation for processes 3 and 4 is. 2NH4Cl + H2O + CO2 = 2HCl + (NH4)2CO3.
What takes place when calcium carbonate and hydrochloric acid interact?Chloride, carbon dioxide gas, and water are the byproducts of the reaction between calcium and hydrochloric acid. The unbalanced equation reads like this.
What happens when hydrogen ions and carbonate react chemically?When its hydrogen ion interacts with the carbonate ions, carbonic acid is created. However, because carbonic acid is very unstable at standard atmospheric pressure and breaks down into both water and carbon dioxide, carbonate drinks release gas when they are opened. The metal ions then undergo a reaction with the chloride ions to create salts.
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balance the equation representing the reaction between iron(iii) oxide, fe2o3, and carbon monoxide (co) to yield iron (fe) and carbon dioxide (co2). do not include the states of matter.
The balanced chemical equation for above chemical reaction is given as,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
There are several ways to balance a chemical equation. In this above case case, we will see the algebraic method.
The first step is of assigning a letter to each compound:
a Fe₂O₃ + b CO → c Fe + d CO₂
Then, we must write the balance equations for each atom, thus:
Fe: 2a = c
C: b = d
O: 3a + b = 2d
The last step is of assigning a value to a letter. For example, we will say that a is 1, and then find the values for the others letters,
Fe: 2a = c if a=1; c=2
O: 3a + b = 2d if a=1 → 3+b = 2d
As b = d → 3+d = 2d; 3 = 2d - d; 3=d and 3=b
Thus, the balanced equation is given as,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
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Write the formula of the conjugate base of the Brønsted-Lowry acid, HBrO₂
Considering the Brønsted–Lowry theory, the conjugate base of HBrO₂ is BrO₂⁻.
Brønsted–Lowry theoryA Brønsted-Lowry acid is any species capable of donating a proton (H⁺).
A Brönsted-Lowry base is a substance capable of gaining or accepting a proton (H⁺).
Then a proton transfer occurs that requires the presence of a proton donor, that is, an acid and a base that accepts them.
When an acid donates H+, the species that remains is called the conjugate base of the acid because it reacts as a proton acceptor in the reverse reaction. Likewise, when a base accepts H+, it becomes its conjugate acid.
Conjugate base of HBrO₂Considering the definition of conjugate base, the conjugate base of HBrO₂ will be BrO₂⁻ because the Brønsted-Lowry acid, HBrO₂, donates an H⁺.
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place the following in order of increasing bond length. c-fc-sc-cl a) c-s < c-cl < c-f b) c-cl < c-f < c-s c) c-f < c-s < c-cl d) c-f < c-cl < c-s e) c-s < c-f < c-cl
The order of increasing bond length is d) c-f < c-cl < c-s
The bond length of a covalent bond is determined by the size of the atoms involved and the strength of the bond. The size of the atoms involved in the c-f, c-s, and c-cl bonds are carbon, fluorine, sulfur, and chlorine, respectively. Carbon and fluorine are smaller atoms, while sulfur and chlorine are larger atoms. Therefore, the c-f bond will be the shortest bond.
The strength of the covalent bond is determined by the electronegativity of the atoms involved. Fluorine has the highest electronegativity of all the elements, followed by chlorine and then sulfur. Therefore, the c-f bond will be the strongest bond. The c-cl bond will be the second strongest bond, and the c-s bond will be the weakest bond.
Given these facts, the order of increasing bond length is c-f < c-cl < c-s. The c-f bond will be the shortest and strongest bond, followed by the c-cl bond and then the c-s bond.
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how many of the following salts are expected to be insoluble in water sodium sulfate barium nitrate ammonium sulfate potassium phosphate
The Insoluble Substance is Barium Nitrate
BANO4
Solubility rules for chromate (CrO₄²⁻) are all chromate are insoluble, except for ions group 1 (Li⁺, Na⁺, K⁺). So soluble chromate are
Li₂CrO₄
Na₂CrO₄
K₂CrO₄
Potassium chromate K₂CrO₄ is soluble.
A substance is said to be insoluble if it doesn't change when placed in water.
When introduced to water, soluble compounds typically form one continuous phase (eg when salt is added to water).
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because of the difference in molar masses, any particle of gas a will be moving slower than any particle of gas b at the same temperature. True or False
True : Because of the difference in molar masses, any particle of gas a will be moving slower than any particle of gas b at the same temperature.
The molar mass of a chemical compound is determined in chemistry by dividing the mass of a sample of that compound by the quantity of that compound, which is the number of moles in that sample, measured in moles. A substance's molar mass is a bulk attribute rather than a molecular one. The compound's molar mass is an average over multiple samples, each of which will likely have a different mass because of the existence of isotopes. The molar mass is most frequently calculated from the standard atomic weights, making it a terrestrial average and a function of the relative abundance of the constituent atoms' isotopes on Earth. For converting between the mass of a material and the amount of a substance for bulk amounts, use the molar mass.
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n outer space the density of matter is about one atom per cm3, mainly hydrogen atoms, and the temperature is about 2.3 k.
Space is generally thought of as a vacuum, but it isn't, not completely. The density of matter is extremely low, but it still exists. The interstellar medium is mainly made of lone hydrogen atoms. The density of hydrogen as it exists in interstellar space is on average about 1 atom per cubic centimeter.
In the extremes, as low as 0.1 atom per cubic centimeter has been found in the space between the spiral arms, and as high as 1000 atoms per cubic centimeter are known to exist near the galactic core. The baseline temperature of outer space, as set by the background radiation from the Big Bang, is 2.7 kelvins. However, there are areas in space where the temperature is extremely hot, reaching into the millions.
The bottom line: the temperature of outer space is brutally cold.
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Choose The Most Appropriate Reagent(S) For The Conversion Of 2-Methylcyclohexanol To 2- Methylcyclohexanone. Он 1. BH3 2. H20
The Most Appropriate Reagent(S) For The Conversion Of 2-Methylcyclohexanol To 2- Methylcyclohexanone is (A) PCC, CH₂Cl₂.
It is possible that carbonyl compounds will be produced as a byproduct of the oxidation of alcohols using pyridinium chlorochromate in CH₂Cl₂, however, this will depend on the specific type of alcohol. Primary alcohols will react with PCC to produce aldehydes while secondary alcohols will react with PCC to produce ketones, and tertiary alcohols will not react with PCC. So the most appropriate reagents for the conversion of 2-methylcyclohexanol to 2- methylcyclohexanone are (A) PCC, CH₂Cl₂. The reaction scheme along with the structures of reagents and products are attached.
The complete question is attached.
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When nitrogen-14 is bombarded with an alpha particle, a proton ( ) is ejected and a new nuclide is formed. Balance the equation and identify the nuclide formed.
When nitrogen-14 is bombarded with an alpha particle, a proton is ejected and oxygen is formed.
Equation of the reaction is :
₇N + ₂alpha particle → ₁P + ᵃX
Balance the atomic number of the equation:
7 + 2 = 1 + a
a = 8
Balance the atomic mass of the equation:
14 + 4 = 1 + b
b = 17
So, the element with atomic number 8 is oxygen and its mass is 17.
Alpha particle, also referred to as alpha rays or alpha radiation, encompass protons and neutrons bound collectively into a particle same to a helium-4 nucleus. they're generally produced within the technique of alpha decay, but will also be produced in other approaches.
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an alkene reacts with a strong protic acid to form a carbocation. in part 1 draw the curved arrow notation for the reaction between an alkene and hcl. however, an alkene will react with a halogen electrophile to form a cyclic intermediate. in part 2 draw the curved arrow notation for the reaction between an alkene and cl2.
When 1-propene and HBr are combined in the first reaction, an ionic mechanism drives the production of 2-bromo propane. When 1-propene and a bromine molecule interact for the second time.
Are bases and alkenes compatible?Most often, molecules with excellent leaving groups connected to sp3 carbons are eliminated processes to produce alkenes. Examples of these reactions are the dehydrohalogenations with strong bases and the alcohol dehydrations catalyzed by acids.
How do alkenes typically respond?Although alkenes can react in many different ways, electrophilic addition reactions are by far the most frequent. In an addition reaction, two smaller molecules are combined to form one larger molecule.
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List the following transition metal cations by their d electron count, with the highest at the top and the lowest at the bottom. 1. Zn2+ 2. Co2+ 3. Ru4+ 4. Mo4+ 5. Pt2+.
The transition metal cations by their d electron count, with the highest at the top and the lowest at the bottom is A > E > B > C > D.
D8 Metals was founded in 2004 as a company specializing in aluminum and steel fabrication, architectural metals and claddings, and custom electromechanical projects. Instead of an 8-electron rule or octet, transition metals follow an 18-electron rule. The easiest way to count electrons is to break down the complex and count the electrons apart.
There are 40 elements in the d block of the periodic table. Four rows of transition elements make up the d block. The d-electron number is a chemical formalism used to describe the electronic configuration of the valence electrons of the transition metal centers of coordination complexes. The d electron number is an effective way to understand the shape and reactivity of transition metal complexes.
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Choose the pair of substances that are most likely to form a homogeneous solution.? a. CCl4 and SCl2 b. NF3 and SO2 c. CO and C6H6 d. NH2CH3 and CH4 e. None of thesse pairs will form a homogeneous solution.
Among the given options, the pair that is most likely to form homogenous solution is NF₃ and SO₂.
A homogenous solution is a solution that has a uniform distribution of the particles all over the solution.
Basically, to be a homogenous solution, both the solute and the solvent has to be in the same state and both of the has to be of the same nature i.e. Polar or Non-Polar.
Among the given options are CCl₄ and SCl₂, NF₃ and SO₂, CO and C₆H₆, NH₂CH₃ and CH₄.
Only the pair of NF₃ and SO₂ are polar and found in same state at room temperature.
So, NF₃ and SO₂ are most likely to form a Homogenous solution.
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which of the following characteristics best determines the composition of the initial filtrate produced in the nephron? group of answer choices only water enters the nephron only large molecules enter the nephron only small molecules enter the nephron only wastes enter the nephron all molecules freely enter the nephron
Characteristics best determines the composition of the initial filtrate produced in the nephron Only small molecules enter the nephron.
The filtrate produced by the glomerulus moves directly from the glomerulus to Bowman's capsule. The filtrate contains some small molecules present in the blood. So, in addition to waste products, there are nutrient molecules and water, which are also removed by the nephron as filtrate.
Small molecules can pass through the intercellular space of the glomerulus and Bowman's capsule. These small molecules can pass through as filtrate, and some specific molecules within them are reabsorbed by the body as they are required for specific bodily functions.
Internal filtrate molecules are made up of these chemical elements in the body, only the larger molecules from the blood cannot enter the system.
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For each of the following categories of compounds, indicate the type of liquid chromatography that could be used to separate analytes in that category. (Drag the appropriate chromatography label to the blank next to the category. Only one label applies to each category, but a label may be used more than once).
Seperation Mode Analyte Category
Fm>2000,soluble in octane,size10 nm
Fm>2000, soluble in butanol, size 100 nm
Fm>2000, soluble in water,nonionic,size 10 nm
Fm<2000, soluble in in ethanol
Fm<2000 , soluble in water, ion-paired
Fm<2000, soluble in water, ionic
Choices:
ion -exchange
Bonded-reverse phase
Adsorption
Bonded normal phase
Molecular exculsion
The appropriate types of chromatography for the labels are:
Fm>2000, octane soluble, size 10 nm: Bonded normal phase
Fm>2000, butanol soluble, size 100 nm: Bonded normal phase
Fm>2000, water soluble, non-ionic, size 10 nm: Adsorption
Fm<2000, ethanol soluble: Bonded reverse phase
Fm<2000, water soluble, ion paired: Ion exchange
Fm<2000, water soluble, ionic: Ion exchange
Liquid chromatography is a separation technique that uses liquid stationary and mobile phases to separate and purify compounds. There are many different types of liquid chromatography, each with different stationary phases and separation mechanisms.
In ion-exchange chromatography, the stationary phase consists of ionizable groups that interact with ions in the mobile phase. This type of chromatography is used to separate charged molecules such as ions and ion-pair compounds.
In adsorption chromatography, the stationary phase consists of solid adsorbents like Silica or alumina that interacts with the analyte via van der Waals forces, dipole-dipole interactions, or hydrogen bonding. This type of chromatography is used to separate compounds based on their affinity for the stationary phase.
In normal-phase chromatography, the stationary phase is a non-polar material such as silica or alumina, and the mobile phase is a polar solvent such as water or methanol. This type of chromatography is used to separate non-polar compounds based on their affinity for the stationary phase.
In reversed-phase chromatography, the stationary phase is a polar material such as octadecyl silica or cyanide-bonded silica, and the mobile phase is a non-polar solvent such as hexane or methylene chloride. This type of chromatography is used to separate polar compounds based on their affinity with the stationary phase.
Molecular exclusion chromatography, also called size exclusion chromatography, is a type of chromatography that separates molecules based on their size. The stationary phase consists of porous spheres with different pore sizes, and molecules are separated based on their ability to penetrate the pores. This type of chromatography is used to separate molecules with molecular weights greater than 2,000 Daltons.
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