Let h be a function defined for all x not equal to 0 such that h(4) = - 3 and the derivative of h is given by h'(x) = (x∧2 - 2)/x for all x not equal to 0.a. Find all values of x for which the graph of h has a horizontal tangent , and determine whether h has a local maximum, local minimum of neither at each of these values. Justify your answers.b. On what intervals, if any, is the graph of h concave up? Justify your answer.c. Write an equation for the line tangent to the graph of h at x = 4.d. Does the line tangent to the graph of h at x = 4 lie above or below the graph of h for x > 4? Why?

Answers

Answer 1

For a function h such that h(4) = -3 and h'(x) = (x² - 2)/ x for all x∈R-{0}, the function has two local minima at x = -2 and x = 2. The local maxima is not determined implying it would be at the critical value x = 0.

A graph has a horizontal tangent at a local minimum or local maximum and the slope is zero at that point. That is at points which has horizontal tangent. h'(x) = 0.

(x² - 2)/ x = 0

Thus x = 2 or x = -2

At the local minimum or local maximum, the slope is zero or tangent is horizontal as the graph change from decreasing to increasing or increasing to decreasing.

h''(x) = 1 + 2/x²

h"(2) = 1 + 2/ 4 > 0

h''(-2) = 1 + 2/ 4 > 0

Therefore at x = 2 and x = -2 we have local minimum.

The graph of h will be concave up between two local minimum. So graph is concave up in the interval -2<x<2.

Let us assume the tangent line is y = mx + c.

m = h'(4) = (4² - 2)/ 4

m = 3.5

we know h(4) = -3, that is

-3 = m×(4) + c

c = -3 - 4×3.5 = -17

Therefore the tangent line is y = 3.5x - 17.

The line tangent to the graph of h at x = 4 lie below the graph of h at x = 4 as x = 2 is a minimum and thus the slope is increasing for x>2.

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Related Questions

there are about 1,265 school districts in the state of texas that generate an equivalent expression using prime factorization for the number 1,265

pls, help whoever answers first gets brainliest!!

Answers

Answer:

1265 = 5*11*23

------------------------------------------

Find prime factors of 1265.

We see it is divisible by 5 since ends with 5:

1265/5 = 253

253 is not divisible by 3 or 9 since the sum of digits is not divisible by 3 or 9. It is not divisible by 7 (since 25 - 3*2 = 19 is not divisible by 7) but divisible by 11, since the sum of digits in odd places is same as the digit in the even place (recall divisibility by 11):

253/11 = 23

23 is a prime number so no more factors.

Hence the prime factorization of 1265 is:

1265 = 5*11*23

If AB has endpoint A(2, 13) and midpoint
(10,-1) then give the coordinate of B.

Answers

Answer:

(18, -15)

Step-by-step explanation:

The vector AB is defined by its starting and endpoints. Usually, B would be at the end, but in this case A is. Since we are given its midpoint, that is, the point equidistant from both the coordinates A and B, we can find coordinate B by simply calculating the distance between A and the midpoint and reapplying this distance to the midpoint.

1. Finding the distance between the midpoint and A:

The distance between two coordinates, from what I can recall, is simply the final coordinate value minus the initial coordinate value, following the form (x2-x1, y2-y1). We know that A comes after the midpoint, because it is the endpoint (so it will be the final coordinate value). Applying this to the context of the question, (2-10, 13+1) = (-8,14).

2. Finding B using the distance between midpoint and A:

B will be the initial coordinate value because it comes before the midpoint. Therefore, giving B the values (x,y):   (10-x, -1-y) = (-8, 14). Separating into two equations (respective to each axis):

10-x=-8

-x=-18

x=18

-1-y=14

-y=15

y=-15

Therefore, the coordinate of B is (18, -15).

Given: Line coordinates P(10,-1) A-------------------------------------------B (2,13) (x, y)
The point P(x', y') divides AB in 1:1 ratio =m:n
So from formula:
x' =(mx1 + nx2)/(m+n) and y' = (my1+ny2)/(m+n) where (x',y')=(10,-1), m:n=1:1 and (x1, y1)=(2,13), (x2,y2)=(x,y)
Put the values in the formula: 10 = 1(2)+1(x)/1+1 = (2+x)/2 =>20=2+x from cross multiplication =>x=20-2=18 from transposition =>x=18 -1=1(13)+1(y)/1+1 =(13+y)/2 =>-2=13+y from cross multiplication =>y=-2-13=-15 from transposition =>y=-15 So coordinates of B (18,-15)

Help me with number two please. It’s asap

Answers

The z-score of the blood pressure readings are:

a = 1.4

b = 0.6

c = 1.2

What is a mean?

It is the average value of the set given.

It is calculated as:

Mean = Sum of all the values of the set given / Number of values in the set

We have,

Mean = 121

Standard deviation = 15

The z-score is given as,

z = (x - mean) / Standard deviation

x = 142

z = (142 - 121) / 15

z = 21/15

z = 7/5

z = 1.4

x = 130

z = (130 - 121) / 15

z = 9/15

z = 3/5

z = 0.6

x = 103

z = (103 - 121) / 15

z = 18/15

z = 6/5

z = 1.2

Thus,

The readings are:

a = 1.4

b = 0.6

c = 1.2

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Marshall is looking at the key on a map. According to the key, 1 inch = 24 miles. Marshall measures the
distance between 2 cities on the map and discovers they are 11.5 inches apart. How many miles apart are the two cities?

A. 276 miles apart
B. 210 miles apart
C. 249 miles apart
D. 294 miles apart

Answers

Answer:

A. 276 miles apart

Step-by-step explanation:

We have the information that if two cities are 1 inch apart then the distance between them is 24 miles.

If it is 11.5 inches apart, then we should multiply the 24 miles per inch by 11.5

24 miles / 1 inch

(24 miles / 1 inch) * 11.5 inches

Inches cancel so you are left with

24 * 11.5 = 276 miles

a manufacturer conducted a survey to determine how many people buy products p and q. what fraction of the people surveyed said that they buy neither product p nor product q ?

Answers

The fraction of the people surveyed that said that they buy neither product p nor product q is 1/6.

It is given to us that -

A survey is conducted with the number of people buying products p and q

We have to find out the fraction of the people surveyed said that they buy neither product p nor product q.

From the given information, the total number of products can be represented as -

[Total products bought] = [p products bought] + [q products bought] - [both p and q bought] + [neither p and q bought] ---- (1)

We have to find out -

[neither p and q bought]/[Total products bought]

Let us assume that the total products bought = 6

It is known that 1/3 of the people surveyed said that they buy product p but not product q.

=> [p products bought] - [both p and q bought] = 1/3 * 6

=> [p products bought] - [both p and q bought] = 2 ------ (2)

From equation (1), we can say that -

[Total products bought] = [p products bought] + [q products bought] - [both p and q bought] + [neither p and q bought]

=> 6 = ([p products bought] - [both p and q bought]) + [q products bought] + [neither p and q bought]

From equation (2), we can write the above equation as -

=> 6 = 2 + [q products bought] + [neither p and q bought]

=> [q products bought] + [neither p and q bought] = 4  ------ (3)

Again, it is also known that 1/2 of the people surveyed said that they buy product q.

=> [q products bought] = 1/2 *6

=> [q products bought] = 3 ---- (4)

From equation (3) and equation (4), we can say that -

[q products bought] + [neither p and q bought] = 4

=> 3 + [neither p and q bought] = 4

=> [neither p and q bought] = 1  ------ (5)

From equation (5) and the total number of products bought, we can say that -

[neither p and q bought]/[Total products bought] = 1/6

(Since, the total number of products bought = 6)

Therefore, the fraction of the people surveyed that said that they buy neither product p nor product q is 1/6.

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Which congruence theorem can be used to prove △abc ≅ △dbc? aas sss hl sas

Answers

The congruence theorem that would best prove the congruence of the triangles is SAS that is Side-Angle-Side.

What is congruence theorem?

Congruent refers to something that is "absolutely equal" in terms of size and form. The shapes hold true regardless of how we rotate, flip, or turn them. Draw two circles with the same radius, for instance, cut them out, then stack them on top of one another.

The figure, in this case a triangle, is congruent if and only if the corresponding sides and angles are equal in measurement. In this case we have BC being common to both triangles. Thus, one pair of corresponding sides is equal. Next, we have another pair of corresponding sides that are equal, AC and DC. Lastly, we have the included angles being equal to each other. Thus, the congruence theorem that would best prove the congruence of the triangles is SAS that is Side-Angle-Side.

Complete question: Triangles ABC and DBC have the following characteristics: BC is a side of both triangles ∠ACB and ∠DCB are right angles AC ≅ DC Which congruence theorem can be used to prove △ABC ≅ △DBC?

AAS

SSS

HL

SAS

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find the value of d in this equality below 5d ÷ 5³=5¹⁸
(the d should be squaring the first five)​

Answers

Answer:

d = 21

Step-by-step explanation:

Given equation:

[tex]5^d \div 5^3=5^{18}[/tex]

Multiply both sides by 5³:

[tex]\implies 5^d=5^{18} \times 5^3[/tex]

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies 5^d=5^{18+3}[/tex]

[tex]\implies 5^d=5^{21}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):[/tex]

[tex]\implies d=21[/tex]

Machine fills rate 135 containers per minute how long will it take to fill 1000 containers at the same rate

Answers

At the rate of 135 containers per minute, it will take approximately 7.4 minutes to fill 1000 containers.

To determine the time it takes to fill 1000 containers, we need to divide the number of containers by the rate at which they are filled. In this case, we have 1000 containers and a filling rate of 135 containers per minute, so we divide 1000 by 135 to find the time it takes to fill the containers:

1000 containers / 135 containers/minute = 7.40740740740741 minutes

Since a minute cannot be divided into fractions, we must round the result to the nearest whole number. This means that it will take approximately 7.4 minutes to fill 1000 containers at a rate of 135 containers per minute.

The machine will take 7.41 minutes (approx) to fill 1000 Containers.

Time taken to fill 135 Containers= 1 minute ...............(Given)

Time taken to fill 1 Container= 1/135 minute

Time taken to fill 1000 Containers = 1000 × 1/135 minutes

                                                         = 1000/135 minutes

                                                         = 200/27 minutes

                                                         ≈ 7.41 minutes​.

Thus, The machine will take 7.41 minutes (approx) to fill 1000 Containers.

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Can someone please help I’ll mark a brain list

Answers

Answer: x = 14

Step-by-step explanation:

3x+9x-5=163

12x-5=163

12x=163+5

12x=168

x=14

find the foci and vertices of an ellipse (x-1)^2/4 + (y+2)^2/9=1​

Answers

Step-by-step explanation:

The equations of axes of ellipse:

y

+

3

=

0

&

x

2

=

0

Plot the axes of ellipse. Specify the center

(

2

,

3

)

, vertices & focii on the corresponding axes. Draw a free hand curve passing through the vertices & the points of intersection of ellipse with coordinate axes to get graph.

hi
If Tessa has carved 24 bird figures, how many figures has she carved altogether?
figures

Answers

Answer:

She has carved 4 times as many bird figures

to use a binomial distribution to approximate the count of successes in an srs, why do we require that the sample size n be less than 10% of the population size n?

Answers

The given population is 10%.

If the 10 % condition is met, a binomial distribution can be used to approximate the number of successes in a simple random sample. The 10% condition requires that the sample represents less than 10% of the population. Despite the fact that the sample size is far too tiny in comparison to the population, it is reasonable to infer that the trials of occurrences are independent. This suggests that the sample size n must be smaller than 10% of the population size N in this situation.

According to the 10% condition, sample sizes shouldn't exceed 10% of the population. Check the condition whenever samples are involved in statistics to make sure your findings are reliable. If you want to employ a typical normal model, some statisticians contend that a condition of 5% is preferable to a condition of 10%.

Hence we get the required answer.

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find an equation of the tangent line to the curve at the given point. y = 6ex cos x, (0, 6)

Answers

y=6x+6 is the equation of the tangent line to the curve at point (0,6)

In order to fing the equation of tangent of any graph we need 2 things.

i . A point on the graph at which tangent need to be drawn.

ii . Slope a line on that point.

solpe of line = [tex]y^'[/tex]  =[tex]\frac{d(y)}{dx}[/tex]

=> d(6[tex]e^xcosx[/tex])/dx

in order to differentiate the above equation we have to use by parts

=> 6([tex]e^xcox-e^xsinx[/tex])

finding the slope at point(0,6)

[tex]y^'[/tex] = 6*(1*1-1*0)

=>6

so slope is 6

now equation of line with slope 6 and point (0,6)

=> y-6 = 6(x-0)

=> y = 6x+6

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in the diagram PQRS is a circle centre O. If angel POQ = 150° angle QSR= 40° and angel SQP= 45° calculate angel RQS.

Answers

Answer:

the angle would be 40 degrees

Step-by-step explanation:

using the alternative angle property the angle is 40

a technician is launching fireworks near the end of a show. of the remaining thirteen fireworks, seven are blue and six are red. if she launches four of them in a random order, what is the probability that exactly two of them are blue ones

Answers

The probability that exactly two of thirteen fireworks are blue ones out of total 4 selections is 63/143.

Define the term probability?Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

The stated data;

Total fire works = 13Blue = 7Red = 6

You want 2 of the 7 items she selects to be blue, leaving 2 to be red.

Selecting 2 blue out of 7 blues is ⁷C₂ = 7!/(5!.2!)  =  21

Selecting 2 red out of 6 red = ⁶C₂ = 6!/(4!2!) = 15

Selecting total of 4 out of 13 ; ¹³C₄ = 13! / (9!.4!) = 715

Thus, probability that exactly two of them are blue ones;

P(2 blue) = 21 x 15 / 715

P(2 blue) = 63/143

Thus, probability that exactly two of them are blue ones out of total 4 selections is 63/143.

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need help can’t figure it out!

Answers

Answer:

Step-by-step explanation:

This is a trick question,  about the red marks again.   those marks are important b/c they tell you that the lengths are the same, so that the angles MUST also be the same.  That is  ,  D and E are equal

so set up your equations with that info

180 = 84 +2p

now use your algebra skillz to solve

180-84 / 2 = p

96/2 = p

48 = p

see??

you make 9.65 per hour as a lifeguard. You work 4.5 hours in one week. How much money did you have

Answers

Answer: $43.43

Step-by-step explanation:

Take 9.65 times 4.5 = $ 43.425

Round up; we will get the answer $43.43

M = -21 divided by 0

Answers

By using the property of division, it can be calculated that M = -21 divided by 0 is not possible

What is division?

Division is the process by which value of single unit can be calculated from the value of multiple unit.

The number to be divided is known as dividend, the number by which the dividend is divided is the divisor, the result obtained is the quotient and the remaining part is the remainder.

There is a well known formula for division

Divisor x Quotient + Remainder = Dividend.

Anything divided by 0 is not possible.

M = -21 divided by 0 is not possible

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original equations: S(p) = -200 + 50p and D(p) = 1060 - 55p please find the equilibrium price and quantity of the two equations. I think I already set up the equation for the equilibrium price here, though no guarantee that I did it right. Qd = 1060 - 55p = Qs = -200 + 50p​

Answers

The equilibrium price is; $12

The quantity for the two equations is; 400

How to find the equilibrium price?

The equilibrium price formula is based on the demand and supply quantities; you will set quantity demanded (Qd) equal to quantity supplied.

The equilibrium price definition above is one that tells us that there is a price point that meets the needs of both supply and demand. In order to understand when those needs are met, we need to know how to find equilibrium price.

We are given;

Quantity supplied; S(p) = -200 + 50p

Quantity demanded; D(p) = 1060 - 55p

Thus, equilibrium price is p when;

S(p) = D(p)

-200 + 50p = 1060 - 55p

1060 + 200 = 55p + 50p

1260 = 105p

p = 1260/105

p = $12

S(p) = -200 + 50(12)

S(p) = 400

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find the volume of the given solid. bounded by the cylinders x2 + y2 = 4r2, y2 + z2 = 4r2

Answers

The volume of cylinders [tex]x^2 + y^2 = 4r^2[/tex] and [tex]y^2 + z^2 = 4r^2[/tex] is 88[tex]r^3[/tex]/3.

How to find the volume using double integrals?

The volume of cylinders can be calculated using integrals from the top curve subtract the bottom curve. For expression above we can convert to find the dimensions of cylinders using Fubini's Theorem. So,

x^2 + y^2 = 4r^2 to x^2 = 4r^2 - y^2

y^2 + z^2 = 4r^2 to z^2 = 4r^2 - y^2

Thus, the volume of the given solid is,

v = [tex]\int r-r\int\sqrt{4r^2-y^2}-\sqrt{4r^2-y^2}\times 2\sqrt{4r^2-y^2} dx dy[/tex]

= [tex]2\int r-r(x\sqrt{4r^2-y^2})(\sqrt{4r^2-y^2})-\sqrt{4r^2-y^2}dy[/tex]

= [tex]2\int r - r[(4r^2-y^2)+(4r^2-y^2)]dy[/tex]

= [tex]2\int r - r[2(4r^2-y^2)]dy[/tex]

= [tex]4\int r - r(4r^2-y^2)dy[/tex]

= [tex]4(4r^2y-y^3/3)r-r[/tex]

= [tex]4(4r^2(r+r)-(r^3+r^3)/3)[/tex]

= [tex]4((4r^2)(2r)-2r^3/3)[/tex]

= [tex]8(4r^3-r^3/3)[/tex]

= [tex](8)(12r^3-r^3)/3[/tex]

= 88[tex]r^3[/tex]/3

Thus, the volume of cylinders is (88r^3)/3.

You question is incomplete, but most probably your full question was

find the volume of the given solid. bounded by the cylinders [tex]x^2 + y^2 = 4r^2[/tex], [tex]y^2 + z^2 = 4r^2[/tex]

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Geometric Transformations Digital Escape

Can you transform each coordinate point and type the correct code? Please remember to type in ALL CAPS with no spaces.

Clear SHORT answers please..

Answers

After a transformation of each coordinate point, the correct code are as follows;

A. (-4, -2).

I. (0, 1).

C. (5, 0).

E. (0, 0).

What is a translation?

In Mathematics, the translation a geometric figure or graph to the left simply means subtracting a digit from the value on the x-coordinate of the pre-image while the translation a geometric figure or graph downward simply means subtracting a digit from the value on the y-coordinate (y-axis) of the pre-image.

Next, we would apply a translation to each of the points as follows;

Point 1 (1, 2) →  (x - 5, y - 4) = (1 - 5, 2 - 4) = Point 1' (-4, -2).

Point 2 (2, 4) →  (x - 2, y - 3) = (2 - 2, 4 - 3) = Point 2' (0, 1).

Point 3 (4, 4) →  (x + 1, y - 4) = (4 + 1, 4 - 4) = Point 3' (5, 0).

Point 4 (3, 2) →  (x - 3, y - 2) = (3 - 3, 2 - 2) = Point 4' (0, 0).

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what lurking variables might be causing the increase in one or both of the variables? explain your answer.

Answers

A lurking variable is an explanatory variable that was not examined in a study but has an effect on the value of the study's response variable.

A concealed variable affects both the dependent and independent variables, resulting in an incorrect connection. Confounding is a causal concept that cannot be expressed using correlations or linkages. Confounders have a significant quantitative role in explaining why correlation does not imply causation.

In the case of risk assessments assessing the degree and form of threat to human health, it is critical to account for confounding in order to isolate the impact of a specific hazard such as a food additive, pesticide, or new drug. It is difficult to recruit and screen volunteers with the same background (age, diet, education, geography, etc.) for prospective studies, and historical investigations can have similar variability.

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find the area of the region enclosed by one loop of the curve. r = 8 sin(5θ)

Answers

16π/5 is the area enclosed by the curve r= 8sin(5θ)

The given curve is polar curve and hence the area of the polar curve is given by:

Let A be the area of the curve so,

A = [tex]\int\limits^a_b {\frac{1}{2} r^2 } \, d\theta[/tex]

where a and b is the boundary at which r=0

so after equation r=0

8sin(5θ) =0

=> sin(5θ) =0

=> 5θ = 0,π

=> θ = 0, π/5

so a=0 , b= π/5

now  

   A = [tex]\int\limits^a_b {\frac{1}{2} r^2 } \, d\theta[/tex]    ------(i)

 so   [tex]r^2[/tex] = (8sin(5θ))^2

=> 64 [tex]sin^2[/tex] ( 5θ )

ans we know that

cos(2α) = 1 -  2[tex]sin^2[/tex] α

so   [tex]r^2[/tex]  =32 (1- cos(10θ) )

putting the value of r in the equation (i) we get :-

A = [tex]\int\limits^a_b {\frac{1}{2} *32(1-cos(10\alpha ) } \, d\alpha[/tex]

=> 16 * [tex]\int\limits^a_b {(1-cos(10\alpha ) } \, d\alpha[/tex]

here a=0 and b=π/5

after putting the value and solving the integral

A = 16π/5

so A is the area enclosed by r=8sin(5θ) is 16π/5

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If f(x) =
√x-10+3, which inequality
x-10+3, which inequality can be used to find the domain of f(x)?
O
0x20
Ox-1020
O √x-10
x-10+320

Answers

Inequality can be used to find the domain of f(x)  is  [tex]$\quad x \geq 20$[/tex]

Interval Notation: [tex]$[20, \infty)$[/tex]

What is Domain definition?

The domain of a function is the set of input or argument values for which the function is real and defined.

Find non - negative values for radicals: [tex]$x \geq 20$[/tex]

The function domain

[tex]$$x \geq 20$$[/tex]

Range of[tex]$\sqrt{\frac{1}{2} x-10}+3:\left[\begin{array}{cc}\text { Solution: } & f(x) \geq 3 \\ \text { Interval Notation: } & {[3, \infty)}\end{array}\right]$[/tex]

Function range definition

The set of values of the dependent variable for which a function is defined

The range of an radical function of the form [tex]$c \sqrt{a x+b}+k$[/tex] is [tex]$f(x) \geq k$[/tex][tex]$k=3$[/tex]

[tex]$f(x) \geq 3$[/tex]

Axis interception points of [tex]$\sqrt{\frac{1}{2} x-10}+3$[/tex] : None

x - axis interception points of [tex]$\sqrt{\frac{1}{2} x-10}+3$[/tex] : None

y - axis interception point of [tex]$\sqrt{\frac{1}{2} x-10}+3$[/tex] : None

None

Extreme Points of [tex]$\sqrt{\frac{1}{2} x-10}+3: \quad$[/tex]Minimum (20,3)

First Derivative Test definition

Suppose that [tex]$x=c$[/tex] is a critical point of f(x) then, If [tex]$f^{\prime}(x) > 0$[/tex] to the left of [tex]$x=c$[/tex]and [tex]$f^{\prime}(x) < 0$[/tex] to the right of x=c then x=c is a local maximum. If [tex]$f^{\prime}(x) < 0$[/tex] to the left of [tex]$x=c$[/tex] and [tex]$f^{\prime}(x) > 0$[/tex] to the right of [tex]$x=c$[/tex] then [tex]$x=c$[/tex] is a local minimum. If [tex]$f^{\prime}(x)$[/tex] is the same sign on both sides of [tex]$x=c$[/tex] then [tex]$x=c$[/tex] is neither a local maximum nor a local minimum.

[tex]$$f^{\prime}(x)=\frac{1}{2 \sqrt{2} \sqrt{x-20}}$$[/tex]

Find intervals: Increasing:20 [tex]$ < x < \infty$[/tex]

Plug [tex]$x=20$[/tex] into [tex]$\sqrt{\frac{1}{2} x-10}+3: \quad 3$[/tex]

Minimum (20,3)

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An equation is shown below.
3x + 4y = 15
Solve the equation for x.

Answers

Answer:

x = [tex]\frac{15-4y}{3}[/tex]

Step-by-step explanation:

3x + 4y = 15 ( subtract 4y from both sides )

3x = 15 - 4y ( isolate x by dividing both sides by 3 )

x = [tex]\frac{15-4y}{3}[/tex]

An office machine purchased new for $3600 loses $400 each year.
Assume the value continues to decrease the same amount
each year. If f(x) represents the value of the office machine
after x years, which linear function models the given situation?

Answers

The linear function models the given situation will be equal to f(x) = $3600 - $400(x).

What is an equation?

Mathematical expressions with two algebraic symbols on either side of the equal (=) sign are called equations.

This relationship is illustrated by the left and right expressions being equal. The left-hand side equals the right-hand side is a basic, straightforward equation.

As per the given information in the question,

Original price of Machine = $3600

Price lost by the machine each year = $400

Then, the equation will be,

f(x) = $3600 - $400(x)

Here, x represents the number of years.

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Answer:

f(x) = −400x + 3600

14)
a) Find the equation of a parabola which has a vertex at (2,-3) and passes through the point
(5,7).

Answers

So we know that the parabola is of the form

a(x-h)²+k where (h,k) is the vertex. The vertex in this case is (2,-3). Therefore

Let h=2 and let k=-3 and let the point (5,7) be of the form (x,y) so let x=5 and y=7

So we have the vertex form as

y=a(x-h)²+k

Substituting y=7 for y, x=5 for x, h=2 for h and k=-3 for k, we get

7=a(5-2)²+(-3)

Which is

7=a(5-2)²-3.

Now we need to solve for a.

So we get the following

7=a(5-2)²-3

Subtracting 5 and 2 we get

7=a(3)²-3

Simplify 3² as 9 we get

7=a(9)-3

So we have the linear equation

7=9a-3

Adding 3 to both sides we get

10=9a

Dividing both sides by 9 we get

a=10/9

So the equation in vertex form for this parabola should be

y=(10/9)(x-2)²-3

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1 balls and bins throw n balls into m bins, where m and n are positive integers. Let x be the number of bins with exactly one ball. Compute var(x). Your final answer should not contain any summations

Answers

Using 1 balls and bins, n balls are thrown into m bins; m and n are positive numbers. the probability of any given bin containing one ball is n/m n * (1 - (1 - 1/m)^n) / m^2

Given that n is the number of balls and m is the number of bins, the probability of any given bin containing one ball is n/m. Therefore, the variance of x is equal to the variance of a binomial random variable with n trials and probability of success p = n/m.

By the formula for the variance of a binomial random variable, the variance of x is equal to n * (1 - (1 - 1/m)^n) / m^2.

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(a) The quadratic equation (x+2)² +3k-1=0 has two real and distinct roots, where k is a constant. Find the range of values of k.​

Answers

Answer: This means that the range of values of k is k ∈ [-1/3, 1/3].

Step-by-step explanation: The quadratic equation (x+2)² +3k-1=0 can be written as (x+2)² = 1-3k. For the equation to have two real and distinct roots, the expression under the square root must be nonnegative. Therefore, we have the inequality 1-3k ≥ 0. Solving this inequality gives us -1/3 ≤ k ≤ 1/3. This means that the range of values of k is k ∈ [-1/3, 1/3].

18. Which is closest to the volume of a ball with a diameter equal to 8.5 inches? Use 3.14 for V=4πTr²³ if 8.5 in is diameter, 3 what radius will you use? A. 285.7 in 3 B 352.4 in 3 C. 300.5 in 3 n 321 1 in 1​

Answers

The closest volume of ball would be 321.4

What is Volume of sphere?

The volume of a sphere is a measure of the space occupied by the sphere, and can be calculated by the formula V = 4/3πr³, where r is the radius of the sphere. In other words, the volume can be found by multiplying 4/3 by π (3.14) by the cube of the radius of the sphere. For example, if the radius is 5, the volume of the sphere would be 4/3π x 5³, or approximately 523.60.

Solution:

Given that:

diameter = 8.5 in

hence, radius would be 4.25 in

                    [tex]Volume\ of \ ball = \frac{4}{3} \pi r^{3} \\\\Volume\ of \ ball = \frac{4}{3} \pi (4.25)^{3}\\\\Volume\ of \ ball = 321.4[/tex]

Hence, The closest volume of ball would be 321.4

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