The change in Mary’s potential energy is - 3412.5 Joule.
What is gravitational potential energy?
The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
Given that:
Weight of Marry: W = 525 N.
She walks down a flight of stairs to a level 6.5 m.
Hence, decrease in potential energy of her = Wh
= 525 N × 6.5 m
= 3412.5 Joule.
Hence, the decrease in potential energy of her is 3412.5 Joule.
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if the ball is released from rest at a height of 0.91 m above the bottom of the track on the no-slip side, what is its angular speed when it is on the frictionless side of the track? assume the ball is a solid sphere of radius 2.1 cm and mass 0.14 kg .(figure 1)How high does the ball rise on the frictionless side?
Angular speed when it is on the frictionless side of the track is 89.7 rad/s
Given that, mass, m=0.14 kg
Ball is released. from rest. at a height. of, h= 0.83 m
Solid sphere of radius, R = 3.8 cm
=0.038 m
From the conservation of energy
ΔK = ΔU
1/2 mv2 + 1/2 Iω2 = mgh
Here, I=2/5MR2 , v=Rω
1/2 mv2 + 1/2 (2/5mR2)(v/R)2 =mgh
1/2 [v2 +2/5 v2] =gh
7/10 v2 = gh
0.7v2 = gh
v =√ [gh / (0.7) ]
=√ [(9.8 m/s2)(0.83 m) / (0.7) ]
= 3.408 m/s
Consequently, angular speed on the frictionless side of the rail,
ω = v/R
= (3.408 m/s)/(0.038 m)
= 89.7 rad/s
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A ball rolls down a curved ramp as shown in the diagram below. Which dotted line best represents the path of the ball after leaving the ramp? A) A B) B C) C D) D
The movement of the ball down the ramp can be shown by option B.
What is the path of the ball?We know that the question has clearly said that the ramp was curved and this is going to help in shaping our discussion. In this case, it is clear that the the ball rolls down a curved ramp as shown. The movement of the ball can be typified by the use of dotted lines.
In this case, we can see that the ball is going to continue to move in a curved path as the ball is moving down the ramp as has been shown in the image.
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which of the following statements is correct about mohr's circle. select all correct ones. group of answer choices mohr's circl is a graphical solution to state of stress that allows the evaluateof normal and shear stresses on an inclined plane (at an angle
Mohr's circle can be used to calculate the stresses on an oblique section if the stress condition on two planes and the angle between those planes are known. The correct option to this question is C.
An illustration of the transformation equations for plane stress problems is Mohr's circle. The relationships between the normal and shear loads operating on a stress element at any desired orientation can be visualized using this technique.
A Mohr's circle must have a diameter, and in order to draw the diameter, two straight line endpoints' coordinates are needed. Apply the principles on Planes A1 and B1 to obtain the stress locations for Mohr's circle diameter if the shear axis is positive upwards.
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Complete question: Consider the following statements:
Mohr's Circle is used to determine the stress on an oblique section of a body subjected to
1. direct tensile stress on one plane accompanied by a shear stress.
2. direct tensile stresses in two mutually perpendicular directions accompanied by a simple shear stress.
3. direct tensile stress in two mutually perpendicular directions.
4. A simple shear stress
Select the correct answe using the codes given below:
A 1 and 4
B 2 and 3
C 1, 2, 3 and 4
D 1, 2 and 3
ucy has three sources of sound that produce pure tones with wavelengths of 36 cm , 60 cm , and 92 cm . she also has an assortment of narrow tubes that are closed off at one end but open at the other. after experimenting, lucy notices that each tone will resonate with tubes of some lengths but not with others.for each wavelength, determine which tube lengths, if any, will resonate with sound of that wavelength.
The tubes with lengths of 15, 45, and 75 cm are found to resonate with this wavelength. Additionally, resonance is seen for tubes with lengths of 25 and 75 cm and 31 and 93 cm.
For this reason, at the place where the tube is closed, we have a node, and at the open point, we have a belly; in this case, the fundamental wave is = 4L. To determine the length of the tube that has resonance, we must establish the natural frequencies of the tubes.
The following resonance, known as the first harmonic, is 3 = 4L / 3.
The next fifth harmonic resonance is 5 = 4L / 5, and we can see that its general form is n= 4L / n, where n = 1, 3, and 5.
Let's apply these terms to the issue at hand.
Start with the wavelength that is the shortest.
Lam equals 60 cm.
Let's determine the length of the tube this harmonica provides.
L = λ n / 4
n = 1 L = 60 will yield the shortest tube length. 1/4\s L = 15 cm
For n = 3 L = 60 3/4\s L = 45 cm
For n = 5 L = 60 5/4\s L = 75 cm
For n = 7 L = 60 7/4\s L = 105cm
We can see that the harmonics 1, 3 and 5 of the tubes with lengths 15, 45, and 75 resonate with this wavelength.
b) λ = 100 cm
For n = 1 L = 100 1/4\s L = 25 cm
For n = 3 L = 100 3/4\s L = 75 cm
For n = 5 L = 100 5/4\s L = 125 cm
There is resonance in the fundamental and third ammonium frequencies for lengths of 25 and 75 cm. L = 124 1/4 L = 31 cm
In the case of the second resonance, L = 124 3/4 L = 93 cm.
For tubes with lengths of 31 and 93 cm, resonance occurs in the fundamental and third harmonics.
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The rate per hundredweight is usually based on the shipment origin and destination, although the actual price charged for a particular shipment is normally subject to a minimum charge and may also be given a(n) ____
surcharge
The rate per hundredweight is usually based on the shipment origin and destination, although the actual price charged for a particular shipment is normally subject to a minimum charge and may also be given a(n) surcharge.
A surcharge is any additional fee, tax, or charge that is tacked onto the cost of a good or service above and above the initial price that was provided. The advertised price of the commodity or service does not include a surcharge, which is frequently added to an already-applied tax. The cost of a surcharge can range and be either a set sum or a percentage of A governing body may apply this fee in order to raise additional funds or cover the expense of rising commodity prices. Consumers who purchase specific goods and services may be subject to surcharges, which are additional fees and/or taxes. At the moment of sale, they are included in the cost of the purchase. Thus, whenever you buy something,
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1. which of the following is the speed of light? 300,000 km/sec 186,283 kilometers per second 186,283 meters per second 186,283 meters per hour 300,000 km/hr
Speed of light, is generally 299,792,458 m/s. The appropriate choice is "186,283 kilometers per second.
The speed of light is approx. 299,792,458 m/s. This is equal to approximately 186,282.397 miles per second or approximately 300,000 kilometers per second.
Therefore, the correct answer is "186,283 kilometers per second" or "300,000 km/sec". The other choices are incorrect because they are not the correct units for the speed of light. Visible light is an example of electromagnetic radiation that moves at the speed of light. Light and other electromagnetic waves appear to move instantly for many practical uses, but their finite speed has dramatic implications for vast distances and particularly sensitive measurements. The starlight that can be seen from Earth has been out there for a very long time, allowing people to view far-off objects and learn about the evolution of the universe. It can take minutes to hours for signals to reach from Earth to a spacecraft when corresponding with far-off space missions. The absolute shortest communication delay between computers, to computer memory, and within a CPU is fixed in computing at the speed of light.
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a satellite of mass m is in an elliptical orbit around the earth, which has mass me and radius re. the orbit varies from a closest approach of distance a at point a to maximum distance of b from the center of the earth at point b. at point a, the speed of the satellite is vo. assume that the gravitational potential energy ug = 0 when masses are an infinite distance apart. Express your answers in terms of a, b, m, Me, Re, vo, and G.
a. Determine the total energy of the satellite when it is at A. b. What is the magnitude of the angular momentum of the satellite about the center of the Earth when it is at A? c. Determine the velocity of the satellite as it passes point B in its orbit.
The velocity of the satellite as it passes point B in its orbit is vᵇ = v₀a/b
The angular momentum of a inflexible item is described as the made of the moment of inertia and the angular velocity. it's miles analogous to linear momentum and is challenge to the essential constraints of the conservation of angular momentum principle if there's no outside torque at the item.
The belongings of any rotating object given by using moment of inertia times angular velocity. it's miles the assets of a rotating frame given by way of the fabricated from the instant of inertia and the angular speed of the rotating object.
(a) the total energy of the satellite when it is at A:-
E = PE + KE = - G*Me*M/a + 1/2mv₀²
(b) the magnitude of the angular momentum of the satellite about the center of the Earth when it is at A:-
L = mvr = mv₀a
(c) Conservation of angular momentum gives,
mv₀a = mvᵇb, or vᵇ = v₀a/b
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Show schematically and discuss how several semiconductor materials might be used together to obtain a more efficient solar cell.
A semiconductor material is a kind of electronic material they have semiconductor properties and can be used to make a different type of semiconductor devices and integrated circuits.
Other external factors such as light, heat, magnetism, and electricity will act on semiconductors and raise some physical effects and phenomena, which can be referred to as the semiconductor properties. Most of the base materials constituting solid-state electronic devices are semiconductors.
Different types of semiconductor devices have different types of functions and characteristics because of the various semiconductor properties.
Silicon is, by far, the most commonly used semiconductor material used in solar cells, representing approximately 95% of the modules sold today. It is also the second most abundant material on Earth (after oxygen) and the most common semiconductor used in computer and mobile chips.
Working of solar When light shines on a photovoltaic (PV) cell also called a solar cell that light may be reflected, absorbed, or pass right through the cell.
The photovoltaic cell is composed of semiconductor material; the “semi” means that it can conduct electricity better than an insulator but not as well as a good conductor like a metal. There are several different semiconductor materials used in PV cells.
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a) Traveling waves propagate with a fixed speed usuallydenoted as v(but sometimes c). The waves are called _______________ if their waveformrepeats every time interval T.
The fundamental relationship among frequency, wavelength, andvelocity is
v = f \lambda.
This relationship may be visualized as follows: In 1 s, f\cdot(1\;{\rm s}) cycles of the wave move past an observer. In thissame second the wavetrain moves a distance v\cdot(1\;{\rm s}).
c) If the velocity of the wave remains constant, then as thefrequency of the wave is increased, the wavelength___________.
d) The difference between the frequency f and the frequency omega is that fis measured in cycles per second or hertz (abbreviated Hz) whereasthe units for \omega are _______ per second.
e) Find an expression for the period of a wave T in terms of other kinematic variables.
f) What is the relationship between omega and f?
g) What is the simplest relationship between the angularwavenumber kand just one of the other kinematic variables?
The waves are called periodic wave if waveform repeats in time interval T. A wave is said to be periodic if its duration of transmission is infinity. In a periodic wave wavelength and frequency is regulated. In a given time interval the wave completes one cycle.
For a periodic wave the wave function is y(x,t) = A sin2(x -vt) .The term 2 scales the wave to the natural period of the sin function. The term A gives the amplitude of the wave which is the maximum displacement of the wave.
If the velocity of the wave remains constant, then as the frequency of the wave is increased, the wavelength decreases
The phase difference between any two points on a wave is found as follows:-At P1 the phase is 1 = kx1- t1 +,
At P2 the phase is 2 = kx2- t2 +.
So the phase difference is = 2-1 = k(x2 - x1)- (t2 - t1) The wave speed is given by:- v=k=2f2/=f
Examples of periodic wave can be seen in:-
1.Electromagnetic wave in optical fibre
2.Sound from a guitar string
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In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the following expression, where x is in centimeters and t is in seconds.x=(4.00cm)cos(3t+π/6)(a) At t=0, find the position of the piston.(b) What is its velocity?(c) What is its acceleration?(d) Find the period and amplitude of the motion.
The position of the piston is 3.785 cm. The velocity of the piston is -2.585 cm/s. The acceleration of the piston is −15.14 cm/s The period of piston is 3.14 s and the amplitude of piston is 4 cm.
It is a kind of periodic motion bounded between two extreme points. For example, Oscillation of Simple Pendulum, Spring-Mass System. The object will keep on moving between two extreme points about a fixed point is called the mean position (or) equilibrium position along any path.
(a) The equation for the piston's position is given as
= x=(4.00 cm)cos(3t+6π )
At t=0,
= x =(4.00 cm)cos(6π )
= x = 3.785 cm
(b) Differentiating the equation for position with respect to time gives us the piston's velocity:
= v = dt/dx = −(8.0 cm/s)sin(2t+ 6π )
At t=0,
= v = dt/dx = −(8.0 cm/s)sin(6π )
= v = -2.585 cm/s
(c) Differentiating again gives its acceleration:
= a = dv/ dt =−(16.0 cm/s 2 )cos(2t+ 6π )
At t=0,
= a = −(16.0 cm/s 2 )cos(6π )
= a = −15.14 cm/s
(d) The period of motion is = T
= T = ω/2π
= T = 2/2π
= T = 3.14 s
and,
The amplitude directly from the equation for x =
= A = 4 cm
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A 10.0-kg microwave oven is pushed 8.00 m up the sloping surface of a loading ramp inclined at an angle of above the horizontal, by a constant force \vec{F} F with a magnitude 110 N and acting parallel to the ramp. The coefficient of kinetic friction between the oven and the ramp is 0.250. (a) What is the work done on the oven by the force ? (b) What is the work done on the oven by the friction force? (c) Compute the increase in potential energy for the oven. (d) Use your answers to parts (a), (b), and (c) to calculate the increase in the oven’s kinetic energy. (e) Use \Sigma \vec{\boldsymbol{F}}=m \vec{\boldsymbol{a}}Σ F =m a to calculate the acceleration of the oven. Assuming that the oven is initially at rest, use the acceleration to calculate the oven’s speed after traveling 8.00 m. From this, compute the increase in the oven’s kinetic energy, and compare it to the answer you got in part (d)
(a) Work done on the oven = 110J
(b) Work done by the friction force =250J
(c) Increase in PE =1000J
(d) Increase in KE = 640J
(e) Acceleration of the oven =14.9 m/s² And KE =74.5J
Given
g = 10
mass = 10kg
distance = 8 m
Magnitude of force = 110 N
Kinetic friction = 0.250 N
A
The work done on the oven by the force is given by
W = F.d
W = 110*14cos(0)
It is a Horizontal component
W = 110 J
B
Now to calculate the work done by the friction force
Frictional force = μ * N
Frictional force = 0.25*10*10
Frictional force = 25 N
Frictional work = frictional force . d
work(f) = 25 * 10cos(0)
Work(f) = 250 J
C
Increase in the Potential energy
PE = mgh
PE = 10*10*10cos(0)
PE = 1000 J
D
The increase in the oven's kinetic energy
PE₁ = KE₁ + W = PE₂ + KE₂
110 - 260 - 1000 = KE₂
KE₂ = 640J
E
The acceleration of the oven
Force - frictional force = ma
a = 110 -250/10 = 14 m/s²
Now to calculate KE we should know the velocity
V(f)² = v(i)² + 2ad
v(f)² = 2(14)(8) = 224
v(f) = 14.9 m/s
Now KE will be given as
(1/2)mv²
KE = (1/2)(10)(14.9)
KE = 74.5 J
Therefore, we got to know the work done, PE and KE just by the force applied.
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what must the emf e of the battery be in order for a current of 2.00 a to flow through the 5.00 v battery, as shown?
The battery's emf has to be -108.75 volts for a 2a current to pass through a 5.00 v battery.
Kirchhoff's Voltage Law states that for any closed network, the voltage around a loop is equal to the total of all voltage drops in that loop and is equal to zero. The conservation of energy, or to put it another way, is the characteristic of Kirchhoff's law which states that the algebraic sum of each voltage in the loop must equal zero.
Do a series/parallel reduction first. Apply Kirchhoff's laws now to get the answer.
ΔV adefa =0 or − (20Ω) × (2A) × 5V − (20Ω) × I2
= 0 or I2
= −2.25A
I1 + I2 = 2A or I1 = 2A − ( −2.25A ) = 4.25A
ΔV adefa = 0 or (15Ω) × (4.25A) + ϵ − (20Ω) (−2.25A) = 0
ϵ = −108.75V; Reversing polarity is necessary.
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the figure shows the net force exerted on the satellite by the moon and the direction of the tangential velocity of the satellite at time t0. which of the following statements is true regarding the motion of the satellite?
The statement which is true regarding the motion of the satellite is D) The tangential velocity of the satellite does not remain constant.
Any object in orbit around the earth, the sun, or another large body is considered a satellite.
The satellite is able to maintain orbital motion even as gravity pulls it inward thanks to its tangential velocity. The necessary centripetal force is provided by gravitational attraction.
Newton was the first to say that a projectile launched with sufficient speed would actually orbit the earth.
The satellite moves faster when it is close to the earth and slows down while moving away to the top of the ellipse.
The question is incomplete. The complete question is ' A) The gravitational force exerted on the satellite by the moon will increase after time t0.
B) The satellite accelerates in a direction that is parallel to the direction of the tangential velocity.
C) The satellite will move toward the moon after time t0.
D) The tangential velocity of the satellite does not remain constant.'
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A 64 kg box is pushed at a constant speed up a frictionless plane for a distance of 18 m by a force parallel to the plane. If the plane makes an angle of 24 degrees above the horizontal, how much work was done?
1500 j,1200j,4600j,2900j,8800j
4600 j work is done.
To find the amount of work done, the equation for work must be used. This equation is Work = Force x Distance. Force is equal to the mass of the box multiplied by the acceleration due to gravity, and the distance is 18 meters. The angle of 24 degrees above the horizontal must also be taken into account, therefore the cosine of 24 degrees must be used. The mass of the box is 64 kg and the acceleration due to gravity is 9.8 m/s2. After plugging in all the values, the work done is 4600 J.
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two forces, f1 and f2, act on a particle. as a result the speed of the particle increases. which one of the following is not possible?two forces, f1 and f2, act on a particle. as a result the speed of the particle increases. a. The work done by F1 is positive, and the work done by F2 is zero b. The work done by each force is positive. c. The work done by F1 is positive, and the work done by F2 is negative. d. The work done by each force is negative. e. The work done by F1 is zero, and the work done by F2 is positive.
Each force produces a negative amount of effort (option d). Whenever there are two opposing forces, the net force will always be negative, no matter how strong one force is compared to the other. Reduced kinetic energy of the particle is indicated by a negative force.
How do forces work?When an object interacts with another object, it experiences a push or pull that is known as a force. Any instant two things connect, a force is transmitted to each one of them.
Force and example are defined.In daily life, forces can take many different forms. a bat's force on the ball is equal to its weight. the amount of pressure used by the hair brush to brush hair.
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What is the wave phenomena that occurs whey a wave passes you and the pitch seems to change?
Answer:
The wave phenomenon that you are describing is known as the Doppler effect. The Doppler effect occurs when a wave, such as a sound wave, passes by an observer and the pitch of the wave seems to change. This is because the frequency of the wave changes as it moves closer to or farther away from the observer. The pitch of a sound wave is directly related to its frequency, so when the frequency of the wave changes, the pitch will also change. This effect is commonly observed with sound waves, but it can also occur with other types of waves, such as light waves.
Platinum is FCC and has a lattice constant of 0.39239 nm
Yes, that's correct. The FCC (face-centered cubic) crystal structure is a common structure for many metals, including platinum. The lattice constant is a measure of the distance between the atomic planes in a crystal structure. It is equal to the distance between two adjacent atoms in the lattice and is typically measured in nanometers (nm). The lattice constant for platinum is approximately 0.39239 nm.
Platinum is a dense, ductile, and malleable metal with a high melting point and good electrical and thermal conductivity. It is resistant to corrosion and is often used in catalytic converters, jewelry, and electronic components. It is also used in the production of chemicals, pharmaceuticals, and other industrial applications.
through a refinery, fuel ethanol is flowing in a pipe at a velocity of 1 m/s and a pressure of 101300 pa. the refinery needs the ethanol to be at a pressure of 2 atm (202600 pa) on a lower level. how far must the pipe drop in height in order to achieve this pressure? assume the velocity does not change. (hint: use the bernoulli equation. the density of ethanol is 789 kg/m3 and gravity g is 9.8 m/s2. pay attention to units!)
The pipe must drop in height by 13.101 m in order to achieve this pressure.
Bernoulli stated that at whatever point along the fluid flow, the total amount of pressure, kinetic energy and potential energy per unit volume is the same.
P + 1/2 ρv² + ρ* g* h = constant
Given that, v = 1 m/s
P₁ = 101300 Pa
P₂ = 202600 Pa
ρ ethanol = 789 kg/m³
g = 9.8 m/s²
Now, let us write the bernoulli equation,
ρ*g*h₁ + P₁ = ρ*g*h₂ + P₂
P₁ - P₂ = ρ*g*h₂ - ρ*g*h₁
( h₂ - h₁) = (P₁ - P₂)/ρ*g
Δh = (P₁ - P₂)/ρ*g
Δh = -101300 / ( 789 * 9.8) = -13.101 m
Minus sign indicates that height must be reduced.
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Yvette does not understand why her plant is not growing. Through observation of the care she gave it, she decided, if I increase the water from 1 cup a week to 2 cups a week, then it will grow. What has she just proposed?
Answer:
Yvette has just proposed a hypothesis. A hypothesis is a proposed explanation for a phenomenon or observation. In this case, Yvette has observed that her plant is not growing and has proposed that increasing the amount of water it receives will cause it to grow. To test this hypothesis, Yvette could try increasing the amount of water the plant receives and observe whether it starts to grow. If the plant does start to grow, this would provide support for Yvette's hypothesis. However, if the plant does not start to grow, this would suggest that the hypothesis is incorrect and Yvette would need to come up with a new explanation for why the plant is not growing.
quasars may result from the very energetic merging of in condensing galaxies. quasars may result from the very energetic merging of in condensing galaxies. black holes suns stars dark matter
Quasars may result from the very energetic merging of dark matter in condensing galaxies.
Quasars may result from the very energetic merging of gas spiraling at high velocity in condensing galaxies.
What is a quasar?
A quasar forms can be regarded as one that the material that falls into the accretion disc which is seen in supermassive black hole at the center of a galaxy.
A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.
Not only does the central engine of active galaxies and quasars require a black hole, Accretion disk of matter is also needed to provide the energy radiated. Dust, other stellar debris, and gas that has come near to a black hole but fallen into it yet forms a flattened band of spinning matter around the event horizon called the accretion disk (or disc).
Therefore, quasars may result from the very energetic merging of dark matter in condensing galaxies.
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Quasars may result from the very energetic merging of dark matter in condensing galaxies.
Quasars may result from the very energetic merging of gas spiraling at high velocity in condensing galaxies.
What is a Quasar?
A quasar forms can be regarded as one that the material that falls into the accretion disc which is seen in supermassive black hole at the center of a galaxy.
A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.
Not only does the central engine of active galaxies and quasars require a black hole, Accretion disk of matter is also needed to provide the energy radiated. Dust, other stellar debris, and gas that has come near to a black hole but fallen into it yet forms a flattened band of spinning matter around the event horizon called the accretion disk (or disc).
Therefore, quasars may result from the very energetic merging of dark matter in condensing galaxies.
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A uniform conducting rod is fixed and allowed to pivot about its center, as shown in the figure. A uniform, positively charged conducting sphere is brought near the upper end of the rod, and the rod rotates clockwise. The rod is then reset to the position shown. The sphere is then brought to point X near the lower end of the rod, and the rod rotates counterclockwise. Which of the following could be true of the charge on the rod? Select two answers.
The rod is positively charged.
The rod is uncharged.
The rod has no net charge until the sphere is brought near it.
The rod is negatively charged.
The correct answers are: a) The rod is negatively charged and d) The rod is positively charged.
When the sphere is brought near the upper end of the rod and the rod rotates clockwise, this indicates that the sphere has a positive charge.
When the sphere is brought to point X near the lower end of the rod and the rod rotates counterclockwise, this also indicates that the sphere has a positive charge.
The other two options are not correct. The rod is not uncharged, because it has a charge when the sphere is brought near it. The rod also does not have no net charge until the sphere is brought near it, because it has a charge when the sphere is brought near it.
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A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine that the isotope is unstable and half of their sample will decay in 17.0 months. The scientists need a new laboratory to properly conduct measurements on the isotope. If a laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 29.0 months to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00×108 m/s. If they place their sample of the isotope on the spaceship, at what speed u must it travel in order for the new laboratory to be completed on Earth by the time half of the isotope on the spaceship decays? Assume that it took one month for the scientists to actually start construction and launch the spaceship so half the sample will remain in 16.0 months but it will still take 29.0 months to build the new lab.A) At what speed u must the spaceship travel for the scientists to have enough time to complete their laboratory by the time half of the isotope has decayed?
'u' must the spaceship travel for the scientists to have enough time to complete their laboratory by the time half of the isotope has decayed at speed of 2.416*10⁸ m/s .
Calculation :
[tex]29 = \frac{16}{1-\frac{c}{v} ^{2} }[/tex]
v = 0.805 * C
V = 0.805 * 3*10*⁸
= 2.146*10⁸ m/s
Isotopes are two or more types of atoms that have the same atomic number (number of protons in the nucleus) and position in the periodic table (and thus belong to the same chemical element), but that differ because of their nucleon number (mass number). The number of neutrons in the core is different. All isotopes of a particular element have approximately the same chemical properties, but they have different atomic masses and physical properties
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Electromagnetic radiation is moving to the right, and at this time and place the electric field is horizontal and points out of the page (see the figure). The magnitude of the electric field is E = 2600 N/C.
t is the magnitude of the associated magnetic field at this time and place?
B = __________T
The magnetic field at this time and place is 8.667 µT
Electromagnetic radiation consists of space-propagating electromagnetic field waves that carry momentum and electromagnetic radiation energy. These include radio waves, microwaves, infrared rays, light, ultraviolet rays, X-rays, and gamma rays.
Microwave is a form of electromagnetic radiation with wavelengths starting from approximately one meter to one millimeter corresponding to frequencies among 300 MHz and 300 GHz respectively. different assets define extraordinary frequency stages as microwaves.
Calculation:
Electric field E = 2600 N / C
Required magnetic field B = E / c
Where c = speed of EM radiation = 3 * 10 ^ 8 m / s
Plug the values weget B = 8.667* 10 ^ -6 T
= 8.667 µT
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suppose you observe a binary system containing a main-sequence star and a brown dwarf. the orbital period of the system is 1 year, and the average separation of the system is 1 au . you then measure the doppler shifts of the spectral lines from the main-sequence star and the brown dwarf, finding that the orbital speed of the brown dwarf in the system is 23 times greater than that of the main-sequence star.1. How massive is the brown dwarf?
Mdwarf = ? KG
The Mass of the Brown dwarf's star,M₂ = 4.132 * 10²⁷ kg
Let M₁ be the mass of the main-sequence star
M₂ be the Mass of the brown dwarf
v₁ be the speed of the main-sequence star
v₂ be the speed of the brown dwarf
The system's typical separation is 1 AU, where r₁ = r₂
The brown dwarf's orbital speed is 22 times that of the main-sequence star.
Therefore, v₂ = 22 v₁
As a main sequence star, the sun
The Mass of the main-sequence star is 2 * 10³⁰ kg
Centripetal force, F = Mv²/r
M₁v₁²/r₁² = M₂v₂²/r²
M₁v₁² = M₂v₂²
M₂/M₁ = v₁²/v₂²
M₂/M₁ = (1/22)²
M₂/M₁ = 0.002066
M₂ = 0.002066M₁
M₂ = 0.002066 * 2 * 10³⁰
M₂ = 4.132 * 10²⁷ kg
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Select the higher harmonics of a string fixed at both ends that has a fundamental frequency of 80 Hz 280 Hz b. 400 Hz 160 Hz 200 Hz e.180 Hz
160 Hz is the higher harmonics of a string fixed at both ends that has a fundamental frequency of 80 Hz.
According to this option c) is correct answer.
A string's fundamental frequency, succeeding frequencies, and two ends are defined as the sum of the entire depending on the number of harmonics. In other words, higher harmonics specify the frequencies that follow under the functions 2f, 3f, 4f, 5f, etc.
As a result, the higher harmonics would be:
1 x 80 Hz Equals 80 Hz (1st harmonic and Fundamental Frequency)
2 × 80Hz Equals 160Hz (2nd harmonic) (2nd harmonic)
3 x 80Hz Equals 240Hz (3rd harmonic)
4 × 80Hz = 320Hz (4th harmonic)
5 x 80Hz Equals 400Hz (5th harmonic)
As a result, the two higher harmonics of a string with an 80Hz fundamental frequency are 160Hz and 240Hz.
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I understand that the question you are looking for is:
Select the higher harmonics of a string fixed at both ends that has a fundamental frequency of 80 Hz.
a)280 Hz
b) 400 Hz
c) 160 Hz
d) 200 Hz
e) 180 Hz
the electromagnetic spectrum displays electromagnetic waves in order of their wavelengths and frequencies. according to this diagram, what approximate range of wavelengths are visible to the human eye?
Gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves are the components of the electromagnetic spectrum, listed in order of decreasing energy.
What are the 7 different wavelength types?The parts of the electromagnetic spectrum are designated as follows, from highest to lowest energy: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, & radio waves. The radio wave region of the electromagnetic spectrum includes microwaves.
What is the name of wavelength 1?When wavelength is expressed in metres, 1/ stands for the number of waves that can be found in a wave train that is one metre long, or for the number of waves that can be found in a wave train that is one centimeter long. The wavenumber of the spectrum line is this number.
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Which statement is a correct definition of a material’s strength?
A.
the ability to deflect sound
B.
the ability to resist radiation
C.
the ability to withstand stress
D.
the ability to resist magnetism
E.
the ability to expand with heat
Answer:
i think its stress (c) hope this helpa
Answer:
C. the ability to withstand stress
Explanation:
The strength of a material refers to its ability to withstand stress. Stress is a measure of the force applied to a material, and it can be either tensile (stretching) or compressive (squeezing). A material's strength is typically measured by its ability to resist deformation or failure under a given amount of stress.
At the time of its discovery, 3C 273 was the most ____________________ object in the universe.
3C 273 was the most luminous object in the universe at the discovery time.
What are stars?An illuminated sphere of plasma that is held together by its gravity is a star.
The Sun is the star that is closest to Earth. Due to their enormous distance from Earth, many more stars are also visible at night to the unaided eye from Earth, appearing as a multiplicity of stationary light dots in the sky.
In the past, the brightest stars were assigned names and grouped into constellations and asterisms.
Star catalogs have been put out by astronomers that list the known stars and offer standardized stellar labels.
All stars outside of our galaxy, the Milky Way, and the majority of other stars in the universe are, nevertheless, invisible to the human eye from Earth.
Even the most powerful telescopes cannot see the majority of them from Earth.
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A 0.45 kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by
x = (12 cm)cos[(17 rad/s)t + p/2 rad]
(a) What is the oscillation frequency (in Hz)? (b) What is the maximum speed acquired by the block? (c) At what value of x does this occur? (d) What is the magnitude of the maximum acceleration of the block? (e) At what positive value of x does this occur? (f) What force, applied to the block by the spring, results in the given oscillation?
Give your answers in centimeter-based units, where applicable.
(a) The angular frequency is 2.7 Hz
(b) The maximum speed is 2.04 m/s
(c) The maximum value is occur at mean position
so the dispalcement is zero
(d) The maximum acceleration is 34.68 m/s^2.
(e) The acceleartion should be maximum at extrem positions
so the position x = A = 12 cm
( f ) The force on the block 15.6 N
Calculation :
The mass of the block m = 0.45 kg
The dispalcement of the block
x = 12cm cos [(17 rad/s) t + (π/2 rad)]
(a) The angular frequency
ω = 17 rad/s
2πf = 17 rad/s
then the frequency
f = 17 / 2π = 2.7 Hz
(b) The maximum speed
v max = Aω = (12 cm) (17 rad/s)
= 2.04 m/s
(c) The maximum value is occur at mean position
so the dispalcement is zero
(d) The maximum acceleration
a max = Aω^2
= (0.12 m) (17)^2 = 34.68 m/s^2
(e) The acceleartion should be maximum at extrem positions
so the position x = A = 12 cm
(f) The force on the block
F = ma = (0.45 kg) (34.68 )
= 15.6 N
Force or Energy Exercised or Applied: Cause of Movement or Change: Active Force. force of nature
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which of the following statements is correct about mohr's circle. select all correct ones. group of answer choices mohr's circl is a graphical solution to state of stress that allows the evaluateof normal and shear stresses on an inclined plane (at an angle
An angle '[tex]\Theta[/tex]' on the circle Corresponds to an angle 2[tex]\Theta[/tex] on the part.
On the Mohr, the circle has a positive counterclockwise rotation, similar to the physical space convention for shear stress. is the clockwise shear stress and both are plotted. Mohr's circle is a graphical representation of the general state of stress at a point.
This is a graphical method for evaluating principal and maximum shear stresses. Normal and tangential stress in any plane. Soil mechanics use Mohr's circles to visualize the relationship between normal and shear stresses, and to estimate the maximum stress based on three or more soil samples taken from a site.
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