Answer:
It means when you look into the lens your vision magnifies by x1
Explanation:
How much work does a 50.0kg person do in walking up one flight of stairs, equivalent to 3.0m?
Answer:
1470J
Explanation:
Given parameters:
Mass of the person = 50kg
height = 3m
Unknown:
Work done = ?
Solution:
To solve this problem, we use the expression below:
Work done = mass x acceleration due gravity x height
So;
Work done = 50 x 9.8 x 3 = 1470J
what is momentum of a train that is 60,000 kg that is moving at velocity of 17m/s?
explain your answer
The bowling ball has starts out at rest (0= speed m/s) at the top of the building (height 40 m). How much potential energy does the ball have?
How much Kinetic energy does the bowling ball have?
How much total energy (Potential energy & Kinetic) does the bowling ball have?
Of the bowling ball's total energy, is more in the form of potential or kinetic energy?
Answer:
it has 40 potential/ 20 kinetic energy/ do the math
Explanation:
energy
A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave perspective, the antenna is a circular aperture through which the microwaves diffract. What is the diameter of the radar beam at a distance of 30 km
Answer:
915m
Hope this helps.
What kind of scattering (Rayleigh, Mie, or non-selective) would you expect to be most important when radiation of the specified wavelength encounters the following natural or anthropogenic particles?
Wavelength O2molecules Smoke particles Cloud droplets Rain droplets
(size 10-10m) (size 0.3 mm) (size 20 mm) (size 3 mm)
200 nm
0.6 mm
10 mm
1.0 mm
1.0 km
Answer:
hello your question is not properly arranged attached below is the arranged table and solution
answer : attached table below
Explanation:
Given data:
02 molecules size = 10^-10m
smoke particles size = 0.3 mm
cloud droplets size = 20 mm
Rain droplets size = 3 mm
Attached below is a table showing the kind of scattering that is expected to occur at various wave lengths
Note : For Rayleigh scattering the wave particle is smaller than the wave length while for Non-selective scattering the wave particle is greater than the wavelength.
and For Mie scattering the wavelength is the same as the wavelength.
What happens to kinetic energy when you decrease the velocity of a moving object?
In an Ohmic conductor when voltage is increased what happens to
current?
Answer: If you increase the voltage across a component, there will be more current in the component .
Why does the sky change colors at sunset?
The atmosphere reflects colors.
The atmosphere bends light.
The sun changes colors.
The sky changes colors at sunset because the atmosphere ABSORBS some colors of light more than other colors.
The second choice ("The atmosphere bends light") is a correct statement, but it's not the reason that the sky changes colors at sunset.
Answer:
The atmosphere bends light.
Explanation:
I got the test, and passed! =)
what is energy? list the three mechanical forms of energy and their associated equations.
Answer:
See the explanation below.
Explanation:
Energy is the ability of bodies to perform work and produce changes in themselves or other bodies.
There are several types of energy, but let's talk specifically about mechanical energy.
Mechanical energy is associated or subdivided into kinetic, potential, and elastic energies.
Kinetic energy
[tex]E_{kin}=\frac{1}{2}*m*v^{2}[/tex]
Potential energy
[tex]E_{pot}=m*g*h[/tex]
Elastic Energy
[tex]E_{elas}=\frac{1}{2} *k*x^{2}[/tex]
An atom undergoes nuclear decay, but its atomic number is not changed.
What type of nuclear decay did the atom undergo?
A. Gamma decay
B. Beta decay
C. Nuclear fission
D. Alpha decay
Answer:
A. Gamma decay
Explanation:
A form of nuclear decay in which the atomic number is unchanged is a gamma decay.
The atom has undergone a gamma decay.
In a gamma decay, no changes occur to the mass and atomic number of the substance.
Gamma rays have zero atomic and mass numbers. When they cause decay, they cause no change to the mass and atomic numbers. They simply produce gamma rays during such reactions and these rays are very energetic.. A string with both ends held fixed is vibrating in its third harmonic. The waves have a speed of 192 m>s and a frequency of 240 Hz. The amplitude of the standing wave at an antinode is 0.400 cm. (a) Calculate the amplitude at points on the string a distance of (i) 40.0 cm; (ii) 20.0 cm; and (iii) 10.0 cm from the left end of the string. (b) At each point in part (a), how much time does it take the string to go from its largest upward displacement to its largest downward displacement
Answer:
Explanation:
The formula holding the relationship between wavelength and frequency of a wave can be expressed as:
[tex]\lambda = \dfrac{v}{f}[/tex]
where;
[tex]\lambda =[/tex] wavelength
v = speed
f = frequency
Given that:
v = 192 m/s and f = 240Hz
Then;
[tex]\lambda = \dfrac{192 \ m/s}{240 \ Hz}[/tex]
[tex]\lambda = 0.800 \ m[/tex]
Now, to estimate the respective amplitude of the string, we need to approach it by using the concept of wave equation which is:
y = A sin kx
here;
A = amplitude of the standing wave
k = wave number
x = maximum displacement
y = distance from center
recall that:
[tex]k = \dfrac{2 \pi}{\lambda}[/tex]
∴
[tex]y = A sin \dfrac{2 \pi}{\lambda }x[/tex]
Now;
for A = 0.400 cm ; [tex]\lambda[/tex] = 0.800 m ; k = 40 cm
Then;
[tex]y =(0.400 \ cm ) \ sin \dfrac{2 \pi}{0.800 m }\times (40 \ cm \times \dfrac{10^{-2} \ m}{1 \ cm } )[/tex]
y = 0.400 sin π
y = 0 cm
At distance 40 cm; the amplitude = 0 cm
Thus, it is a node.
For k = 20cm
Then:
[tex]y =(0.400 \ cm ) \ sin \dfrac{2 \pi}{0.800 m }\times (20 \ cm \times \dfrac{10^{-2} \ m}{1 \ cm } )[/tex]
y = 0.400 sin π/2
y = 0.400 cm
At distance 20 cm; the amplitude = 0.400 cm
Thus, it is antinode.
For k = 10cm
Then:
[tex]y =(0.400 \ cm ) \ sin \dfrac{2 \pi}{0.800 m }\times (10 \ cm \times \dfrac{10^{-2} \ m}{1 \ cm } )[/tex]
4y = 0.400 sin π/2
y = 0.283 cm
At distance 10 cm; the amplitude = 0.283 cm
b)
The required time taken to go through the displacement( i.e. from largest upward to downward) is the time required to cover half of the wavelength.
This is expressed as:
[tex]T = \dfrac{1}{2} \times \dfrac{1}{f}[/tex]
[tex]T= \dfrac{1}{2} \times \dfrac{1}{240 \ Hz}[/tex]
T = 0.00208
T = 2.08 × 10⁻³ s
Like charges will exert a force of
a. positive
b. negative
c. attraction
d. repulsion
e. neutral
Answer:
D- Repulsion
Explanation:
A positively charged object will exert a repulsive force upon a second positively charged object.
3. A 200-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. a. Determine the change in momentum of the ball.. b. If the ball is in contact with the floor for 0.02 ms (milliseconds), what is the average force applied to the ball
Answer:
Explanation:
A 200-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. a. Determine the change in momentum of the ball.. b. If the ball is in contact with the floor for 0.02 ms (milliseconds), what is the average force applied to the ball
Given data
mass= 200g= 0.2kg
initial velocity= 2.5m/s
final velocity= 2m/s
time= 0.02ms
time= 0.00002 seconds
ΔP= mΔv
ΔP= 0.2*2.5-2
ΔP= 0.2*0.5
ΔP=0.1kgm/s
F= mv/t
F=0.1/0.00002
F=5000N
I want the answer, Due Today
Answer:
The process of distillation begins with heating a liquid to boiling point. The liquid evaporates, forming a vapor. The vapor is then cooled, usually by passing it through pipes or tubes at a lower temperature. The cooled vapor then condenses, forming a distillate
I hope it helps mate
I will always help you understand your assignments
enjoy your day
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You are moving a wagon with a friend's help you push on the left side of the wagon with 25 of force while your friend pulls from the right side of the wagon with a force of 15N,
What is the net force?
Answer:
10N to the left side towards you
Explanation:
The net force is the resultant force that acts on a body.
Force is a push or pull on a body.
Push to left side = 25N
Pull to the right = 15N
Net force = Push to left side - Pull to the right = 25N - 15N
Net force = 10N to the left side towards you
The net force is therefore 10N to the left side towards you
What energy store is in the hammer
BEFORE it hits the nail?
Answer:
mechanical energy
Explanation:
when raised up has potential energy
Answer:
potential energy
Explanation:
potential energy
Which statements correctly describe the formula or name of a compound? Select all that apply.
A. The formula of nitrogen trifluoride is NF 3
OB. The formula of ammonia is NH3
OC. The name of AlF3 is trialuminum fluoride.
D. The formula of calcium chloride is cach,
DE The name of Lise is lithium selenate.
F. The formula of dinitrogen monoxide is NO
G. The formula of sulfur trioxide is so
H. The formula of magnesium hydroxide is Mg(OH)2
Answer:
The formula of nitrogen trifluoride is NF 3
The formula of ammonia is NH3
The formula of magnesium hydroxide is Mg(OH)2
Explanation:
The formula of a compound refers to the correct representation of the compound using appropriate chemical symbols.
The formula of a compound is derived from the symbols of its constituent elements. The formula of the compound must correctly show the number of atoms of each element in one formula unit of the compound.
In the answer section, the correct names or formulas of some compounds have been shown
Answer:
A. The formula of nitrogen trifluoride is NF3.
B. The formula of ammonia is NH3.
D. The formula of calcium chloride is CaCI2.
H. The formula of magnesium hydroxide is Mg(OH)2.
Explanation:
How much work is done in pushing a 10kg box, 2.0m to the right
with a force of 20.0N?
Answer:
40J
Explanation:
Given parameters:
Mass of box = 10kg
distance moved = 2m
Force applied = 20N
Unknown:
Work done in pushing the box = ?
Solution:
The work done in moving a body is a function of the force applied to move it through a particular distance.
Work done = Force x distance
So;
Work done = 20 x 2 = 40J
The impulse given to a body of mass 1.5 kg, is 6.0 kg • m•s? If the body was initially at rest what will its resulting kinetic energy be? Give your answer in J without units.
(Show Work)
Answer:
108J
Explanation:
Given parameters:
Mass the body = 1.5kg
Impulse = 6kgm/s
Initial velocity = 0m/s
Unknown:
Kinetic energy of the body = ?
Solution:
The kinetic energy of a body is the energy due to the motion of the body.
To solve this problem, we use the expression below:
K.E = [tex]\frac{1}{2}[/tex] m (V - U)²
m is the mass
V is the final velocity
U is the initial velocity
From;
Impulse = m V
6 = 1.5 x V
V = [tex]\frac{6}{1.5}[/tex] = 4m/s
So;
K.E = [tex]\frac{1}{2}[/tex] x 6 x (6 - 0)² = 108J
Two objects moving at the same speed can have different velocities.
True or False
Answer:
True
Explanation:
Objects have the same velocity only if they are moving at the same speed and in the same direction.
How could a change in straight line motion due to unbalanced forces be predicted from an understanding of inertia?
Answer:
If the force goes in the direction of movement, the speed must increase and if the net force goes in the opposite direction, the speed must decrease.
Explanation:
The principle of inertia or Newton's first law states that every body remains static or with constant velocity if there is no net force acting on it.
Based on this principle, if we have a net force, the velocity of the body changes by having an unbalanced force acting.
If the force goes in the direction of movement, the speed must increase and if the net force goes in the opposite direction, the speed must decrease.
On March 27, 2004, the United States successfully tested the hypersonic X-43A scramjet, which flew at Mach 7.0 (seven times the speed of sound) for 11 seconds. (A scramjet gets its oxygen directly from the air, rather than from fuel.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Swim competition. Part A At this rate, how many minutes would it take such a scramjet to carry passengers the approximately 5000 kmkm from San Francisco to New York? (Use 331 m/sm/s for the speed of soun
Answer:
Explanation:
Speed of sound = 331 m /s
speed of jet = 7 .00 Mach = 7 times speed of sound
= 7 x 331 = 2317 m /s
distance to be covered = 5000 x 1000 = 5 x 10⁶ m
Time taken = distance / speed of jet
= 5 x 10⁶ / 2317
= 2.158 x 10³ s
= 35.96 minutes .
What is the 59th element
Answer:
The 59th element is Praseodymium it's symbol is Pr.
What is the work required to stretch a spring with a spring constant k of 2500 N/m by 8 cm?
Answer:
the work required to stretch the spring is 8 J.
Explanation:
Given;
spring constant, k = 2500 N/m
extension of the spring, x = 8 cm = 0.08 m
The work required to stretch the spring is calculated as;
[tex]W = \frac{1}{2} kx^2\\\\W = \frac{1}{2} \times 2500 \times 0.08^2\\\\W = 8 \ J[/tex]
Therefore, the work required to stretch the spring is 8 J.
What do you think about the attached scenario?
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Part APart complete How far does the elevator move while accelerating to full speed from rest? Express your answer with the appropriate units. 12.5 m Previous Answers Correct Part B How long does it take to make the complete trip from bottom to top? Express your answer with the appropriate units.
Answer:
45 s .
Explanation:
The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .
displacement s = ?
acceleration a = 1 m /s²
Final speed v = 5 m/s
initial speed u = 0
v² = u² + 2as
5² = 0 + 2 x 1 x s
s = 12.5 m
B) Let time of acceleration or deceleration be t
v = u + a t
5 = 0 + 1 t
t = 5 s
Similarly displacement during deceleration = 12.5 m
Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) = 175 m .
velocity of uniform motion = 5 m /s
time during which there was uniform velocity = 175 / 5 = 35 s
Total time = 5 + 35 + 5 = 45 s .
a graduated cylinder.measures 15.3 mL. Convert this measurement to DaL
Answers:
A. 0.0153
B. 0.00153
C. 0.000153
D. 0.153
Answer:
0.000153DaL
Explanation:
We have been given:
15.3mL to convert to DaL
DaL is a unit of volume which indicates a decaliter.
This implies that;
1 Da L = 1 x 10²L
So:
1 mL = 1 x 10⁻³L
So 15.3mL will give 15.3 x 10⁻³L
So;
1 x 10²L = 1 DaL
15.3 x 10⁻³L will give [tex]\frac{15.3 x 10^{-3} }{1 x 10^{2} }[/tex] = 15.3 x 10⁻⁵DaL
Therefore, this is 0.000153DaL
Match each vocabulary word with the correct definition. 1. measure of how quickly velocity is changing 2. speed in a given direction 3. force that resists moving one object against another 4. measure of the pull of gravity on an object 5. tendency of an object to resist a change in motion 6. size friction acceleration velocity magnitude inertia weight friction
1. measure of how quickly velocity is changing . . . acceleration
2. speed in a given direction . . . velocity
3. force that resists moving one object against another . . . friction
4. measure of the pull of gravity on an object . . . weight
5. tendency of an object to resist a change in motion . . . inertia
6. size . . . magnitude
1. measure of how quickly velocity is changing is acceleration.
2. speed in a given direction is velocity.
3. force that resists moving one object against another is friction.
4. measure of the pull of gravity on an object is weight.
5. tendency of an object to resist a change in motion is inertia.
What is acceleration?Acceleration has the term used in mechanics to describe the pace at which the velocity of an object varies over time. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it.
It is a vector quantity with an SI unit is m/s² and the dimension formula is LT⁻². A massive body will accelerate or alter its velocity at a constant rate when a constant force is applied to it, according to Newton's second law. In the simplest case, when a force is applied to an object at rest, it accelerates in the force's direction.
Therefore, 1. measure of how quickly velocity is changing is acceleration.
2. speed in a given direction is velocity.
3. force that resists moving one object against another is friction.
4. measure of the pull of gravity on an object is weight.
5. tendency of an object to resist a change in motion is inertia.
Learn more about friction on:
https://brainly.com/question/13000653
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A Boeing 787 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the engines give the plane a constant acceleration of 1.9 m/s2. The plane then travels a distance of 1700 m down the runway before lifting off. How long does it take from the application of the acceleration until the plane lifts off, becoming airborne
Answer:
39.26 s
Explanation:
From the question given above, the following data were obtainedb
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Distance travelled (s) = 1700 m
Time (t) =?
Next, we shall determine the final velocity of the plane. This can be obtained as follow:
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Distance travelled (s) = 1700 m
Final velocity (v) =?
v² = u² + 2as
v² = 6² + (2 × 1.9 × 1700)
v² = 36 + 6460
v² = 6496
Take the square root of both side
v = √6496
v = 80.6 m/s
Finally, we shall determine the time taken before the plane lifts off. This can be obtained as follow:
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Final velocity (v) = 80.6 m/s
Time (t) =?
v = u + at
80.6 = 6 + 1.9t
Collect like terms
80.6 – 6 = 1.9t
74.6 = 1.9t
Divide both side by 1.9
t = 74.6 / 1.9
t = 39.26 s
This, it will take 39.26 s before the plane lifts off.
A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at rest. (a) Find the velocity of each object after the collision. -6.67 Correct: Your answer is correct. cm/s (5.00 g object) 13.33 Correct: Your answer is correct. cm/s (10.0 g object) (b) Find the fraction of the initial kinetic energy transferred to the 10.0 g object. 88.44 Correct: Your answer is correct. %
Answer:
a) [tex]v_{1f}=-6.67\: cm/s[/tex]
[tex]v_{2f}=13.33\: cm/s[/tex]
b) [tex]n=88.84\: \%[/tex]
Explanation:
a) Applying the conservation of momentum, we have:
[tex]p_{i}=p_{f}[/tex]
p(i) is the initial momentum. In our case is due to the 5 g object.
p(f) is the final momentum. Here, both objects contribute.
[tex]m_{1i}v_{1i}=m_{1f}v_{1f}+m_{2f}v_{2f}[/tex]
Where:
m(1) is 5 gm(1) is 10 gv(1i) is the initial velocity 20 cm/s or 0.2 m/sTo find both final velocities we will need another equation, let's use the conservation of kinetic energy.
[tex]m_{1i}v_{1i}^{2}=m_{1f}v_{1f}^{2}+m_{2f}v_{2f}^{2}[/tex]
So we have a system of equations:
[tex]5*0.2=5v_{1f}+10v_{2f}[/tex] (1)
[tex]5*0.2^{2}=5v_{1f}^{2}+10v_{2f}^{2}[/tex] (2)
Solving this system we get:
[tex]v_{1f}=-6.67\: cm/s[/tex]
[tex]v_{2f}=13.33\: cm/s[/tex]
b) The fraction of the initial kinetic energy transferred is:
[tex]n=\frac{m_{2}v_{2f}^{2}}{m_{1}v_{1i}^{2}}[/tex]
[tex]n=\frac{10*13.33^{2}}{5*20^{2}}[/tex]
[tex]n=88.84\: \%[/tex]
I hope it helps you!