M is the midpoint of CB, CM = 3x+1, and MB = 5x−9.
Determine the value of x.

M Is The Midpoint Of CB, CM = 3x+1, And MB = 5x9.Determine The Value Of X.

Answers

Answer 1

Answer:

x = 5

Step-by-step explanation:

Since both sides are given, set both sides equal to eachother.

3x + 1 = 5x - 9

Segment CM is on the left and segment MB is on the right. From now on, solve for x.

Step 1: Isolate x by itself by subtracting the lesser value

3x + 1 = 5x - 9

-3x        -3x                     the x's on the left cross out

---------------------

 1 = 2x - 9

+9         +9                      having x on one side

----------------

10 = 2x

__________________________________________________________

Step 2: Divide each side by 2 to get rid of x's coefficient

10 = 2x

/2     /2

----------

5 = x

Solution: x = 5

__________________________________________________________

Solving for CB: Substitute x for both sides since x = 5

3(5) + 1 = side CM

15 + 1 = side CM

16 = side CM

__________________________________________________________

Solving for CB: Solve for the other side (segment MB)

5(5) - 9 = side MB

25 - 9 = side MB

14 = side MB

__________________________________________________________

Solving for CB: Lastly, add up the sides

16 + 14 = segment CB

30 = segment CB

__________________________________________________________

Answer 2

Applying the knowledge of midpoint of a segment, the value of x = 5.

Given:

[tex]CM = 3x+1\\\\MB = 5x-9[/tex]

To solve this, we would apply our knowledge of Midpoint of a Segment to create an equation that will help us solve for the value of x.

Since M as a midpoint of CB, will divide CB into equal segments.

Thus:

Given that M is a midpoint of CB, therefore,

[tex]CM = MB[/tex]

Substitute

[tex]3x + 1 = 5x - 9[/tex]

Collect like terms

[tex]3x - 5x = -1 - 9\\\\-2x = -10[/tex]

Divide both sides by -2

[tex]x = 5[/tex]

Therefore, applying the knowledge of midpoint of a segment, the value of x = 5.

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Answers

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Dada la altura de una pelota que se lanza directamente hacia arriba con una velocidad de 40 pies / modelada por la ecuación y = 40t -16t ^ 2

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Queremos encontrar la altura máxima alcanzada por una pelota que es lanzada hacia arriba. Veremos que la altura máxima es 25 pies.

Encontrando el máximo.

Sabemos que la ecuación de la altura es:

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