Two things metal and nonmetals have in common are: 1.Metals and nonmetals are elements and thus are made of atoms.
2. The atomic structures of metals and nonmetals are similar as they have a nucleus with orbiting electrons.
a. A mass, m2, is initially at rest. A mass, m1, traveling with velocity, v1, collides with m2 in an elastic collision. After the collision, the two objects move with final velocities, v1f and v2f respectively. Using the laws of conservation of energy and momentum, show that the ratio of the final velocities in terms of m1 and m2 is given by: (v2f/v1f) = (2m1/m1 −m2) b. Linearize the expression in Exercise 1 by making the following substitutions: y≡m2/m1 andx≡v1f/v2f If y is plotted as a function of x, what values do you expect for the slope and intercept? c. Based on your result from Exercise2, what ratio of masses, m2/m1,results in final velocities, v1f andv2f that are equal in magnitude and opposite in direction?
Conservation of kinetic energy, v2f/v1f = (2m1/m1 −m2),
ratio of masses, m2/m1 = 3.
By conservation of momentum,
m1v1 + 0 = m1v1f + m2v2f
=> v1 = v1f + (m2/m1)v2f
By conservation of kinetic energy,
(1/2)m1v1^2 + 0 = (1/2)m1v1f^2 + (1/2)m2v2f^2
m1v1^2 = m1v1f^2 + m2v2f^2
m1[v1f + (m2/m1)v2f]^2 = m1v1f^2 + m2v2f^2
m1[v1f^2 + (m2/m1)^2*v2f^2 + 2v1f.(m2/m1)v2f] = m1v1f^2 + m2v2f^2
m1v1f^2 + (m2^2/m1)v2f^2 + 2m2.v1f.v2f = m1v1f^2 + m2v2f^2
(m2^2/m1)v2f^2 + 2m2.v1f.v2f = m2v2f^2
(m2^2/m1)v2f + 2m2.v1f = m2.v2f
v2f[1 - m2/m1] = 2v1f
v2f/v1f = (2m1/m1 −m2)
b. From 3,
v1f/v2f = 1/2 - (1/2)(m2/m1)
Now y≡m2/m1 andx≡v1f/v2f
=> x = 1/2 - 1/2y
=> 2x = 1 - y
=> y = -2x + 1 ------------4
Comparing with y = mx + c,
Slope is m = -2 and intercept is c = 1
c. Now putting v1f = -v2f means x = -1
Therefore, from 4,
m2/m1 = y = -2*-1 + 1 = 3
=> m2/m1 = 3.
Every moving item possesses kinetic energy, which can be characterized as such. The energy that results from motion is simply referred to as kinetic energy. On the basis of the kind of motion that the objects are in, kinetic energy can be further divided into numerous sorts. For instance, rotational kinetic energy is the energy that a body with circular motion possesses, such as planets orbiting the sun; vibrational kinetic energy is the energy that an object has due to vibration, such as a vibrating phone; and translational kinetic energy is the energy that a body with motion possesses, such as a moving object from one location to another. Our daily lives make it simple to see translational kinetic energy in action.
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A wire moving at right angles to a magnetic field has NO induced voltage if the wire is covered with insulation if it is moving very fast. if it is moving slowly. if it is made of copper. None of the above choices are correct.
D) None of the options above is the proper response. Option (D)
describes the movement of a wire perpendicular to a magnetic field with no induced voltage.
If the wire has insulation surrounding it, then there will also be some induced voltage present in the wire.
It will also have some induced voltage if it is moving very quickly or vibrating back and forth.
The wire induced voltage will also be low if the wire is moving slowly.
It also induces voltage if it is composed of copper.
There is just one situation where the wire is stationary and does not produce induced voltage.
hence the appropriate choice is Alternative (d) None of the above
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coherent light that contains two wavelengths, 660 nm (red) and 470 nm (blue), passes through two narrow slits that are separated by 0.450 mm. their interference pattern is observed on a screen 4.10 m from the slits.What is the distance on the screen between thefirst-order bright fringes for the two wavelengths?
First-order brilliant fringes for the two wavelengths are separated on the screen by a distance of 0.00254 m, or 2.54 mm.
How wide is the screen's fringe separation?The breadth or gap between two subsequent brilliant or dark fringes is referred to as the fringe.
y = Fringe distance
d= Distance between slits = 0.3 mm
L = Screen distance = 4 m
λ = Wavelength
When constructive interference occurs
Y/L = mλ/d
For first order wavelength
y1 = 4 × 1×660 ×10^-9 / 0.3×10^-3
y1 = 0.0088m
y2 = 1×450 ×10^10-9 / 0.3×10^10-3
y2 = 0.00626
distance between the fringes is given:
y1 +y2 = 0.0088+0.00626 = 0.00251m
First-order brilliant fringes for the two wavelengths are separated on the screen by a distance of 0.00254 m, or 2.54 mm.
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A simple pendulum of length L is mounted in a massive cart on a plane inclined at an angle \Theta with the horizontal. The coefficient of kinetic friction is 3/4. The cart slides down the incline after released from rest. Find the period T of small oscillations of the pendulum.
This system's period (time between oscillations) is T=2=2Lg.
What is the period t formula?The period, which is the length of each full oscillation, is constant. T = 2 Square root of L/g, where L is the pendulum's length and g is the acceleration brought on by gravity, is the formula for a pendulum's period.
What is the motion's oscillation period T?The time it takes an object to complete one oscillation and return to its initial position is measured in terms of a period, or T. The formula for the angular frequency is = 2/T. T = 1 / f, where "T" stands for period, or the length of time it takes for one cycle to complete, and "f" stands for frequency, is the formula for period.
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a 36 n crate starting at rest slides down a ramp set a 37 degrees before continuing to slide an additional 3.3 meters along the ground. the coefficient of kinetic friction between the crate and the surface of the ramp/ground is 0.19.
A 36 n crate starting at rest slides down a ramp set a 37 degrees before continuing to slide an additional 3.3 meters along the ground. So, the coefficient of kinetic friction between the crate and the surface of the ground is 0.19.
By applying newtons laws of motion we know, ∑Fy = n–mgcosθ=0.
Hence, n = mgcosθ.
Now, f = μkn
Now, μk = f/mgcosθ.
By calculating by the above formula coefficient of kinetic friction comes out to be 0.19.
Kinetic friction - Kinetic friction is the name given to the force that exists between moving surfaces. The movement of a body on the surface is opposed by a force that is perceived. The magnitude of the force will depend on the kinetic friction coefficient between the two materials. Friction is simply the force that prevents something from slipping. Every object suffers kinetic friction, which prevents two or more things from moving at the same time. The force acts in the opposite direction from the direction that an object wants to slide as it slides. Friction also plays a significant role in routine tasks like rubbing two things together. In some instances, the heat generated by the ensuing motion ultimately starts a fire. Oil is required to lubricate machine parts because it reduces friction, which also contributes to wear and tear. When two objects rub against one another, the frictional force that results is converted into thermal energy, which occasionally starts a fire Machine parts need to be lubricated with oil to prevent wear and tear caused by kinetic friction.
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A ray of light traveling in air strikes the surface of mineral oil at an angle of
23.1° with the normal to the surface. If the light travels at 2.17 x 108 m/s
through the oil, what is the angle of refraction?
In order to determine the angle of refraction, we first need to determine the index of refraction of the mineral oil. The index of refraction is defined as the ratio of the speed of light in a vacuum to the speed of light in the medium, so we can calculate the index of refraction of the mineral oil using the formula:
n = c / v
where n is the index of refraction, c is the speed of light in a vacuum (2.99 x 108 m/s), and v is the speed of light in the mineral oil (2.17 x 108 m/s). Plugging in the given values, we get:
n = 2.99 x 108 m/s / 2.17 x 108 m/s = 1.38
Now that we know the index of refraction of the mineral oil, we can use Snell's Law to calculate the angle of refraction. Snell's Law states that the ratio of the sines of the angles of incidence and refraction is equal to the reciprocal of the index of refraction, so we can use the formula:
sin(θi) / sin(θr) = n
where θi is the angle of incidence (23.1°), θr is the angle of refraction, and n is the index of refraction (1.38). Solving for θr, we get:
sin(θr) = sin(θi) / n
Plugging in the given values, we get:
sin(θr) = sin(23.1°) / 1.38 = 0.4
Since the sine of the angle of refraction must be between 0 and 1, we know that the angle of refraction must be less than 90°. To find the exact value of the angle of refraction, we can use the inverse sine function (arcsin) to find the angle whose sine is equal to 0.4. This gives us:
θr = arcsin(0.4) = 23.8°
Therefore, the angle of refraction is 23.8°.
Air at 200 kPa, 52°C, and a velocity of 330 m/s enters an insulated duct of varying cross-sectional area. The air exits at 100 kPa, 82°C. At the inlet, the cross-sectional area is 16.57 cm2.Assuming the ideal gas model for the air, determine:(a) the exit velocity, in m/s.(b) the rate of entropy production within the duct, in kW/K.
The rate of entropy is 0.337Kw/ K.
What is enthalpy ?
Chemists generally use a quantity known as enthalpy to describe the thermodynamics of chemical and physical processes (H). Enthalpy is determined using the formula H = U + PV, where PV stands for the system's volume and U for its internal energy.
What is entropy ?
Entropy is essentially a measurement of the amount of energy that molecules and atoms disperse during a process. It can be described in terms of the other thermodynamic quantities or in terms of the statistical probability of a system.
Take enthalpy from ideal gas properties of all tables at
T₁= 52°C = 325 K
i.e. h₁= 325.31 KJ/ Kg
T₂ = 82°C = 355K
h₂= 355.535 KJ/ Kg
applying energy rate balance eq
Gev = Wev + m [ (h₁-h₂)+ v₁²-v₂²/2 + g ( 21- 2g )]= 1
= m( h₂-h₁) + v₁²-v₂²/2) = 0
= v₁²-v₂²/2= h₂-h₁
= v₁²-v₂²-2 ( h₂-h₁)
= (330) ²- 2( 355.535- 325.31) * 10⁻³
v₂= [tex]\sqrt{108900- 60450}[/tex]
V₂= 220.11 m/s
Continuing equation
m= A₁V₁/V₁
m= A₁V₁/ RT₁/P₁ = P₁/RT₁= A₁V₁
= 200*10³/ 287 (52+273) * 16.57 *10⁻⁴*330
= 1.17 KG/S
Entropy value from the ideal gas properties of air at
T₁ = 52° = 325 K S₁= 1.78248 KJ/ Kg.k
T₂= 82°= 325 K S₂= 1.871255 KJ/ Kg.k
Rate of entropy production within the drift
cv = m [ s₂-s₁ - Rln ( p₂/ p₁)
= 0.337Kw/ K
Therefore, rate of entropy is 0.337Kw/ K.
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an inclined ramp is set up on your table. from the top of the ramp, you release a disk, hoop, and solid sphere at the same time. all objects are well manufactured with exactly the same mass. they are completely uniform and roll without slipping. which object reaches the bottom of the ramp first, second and third? select from the following, which are listed in order of first, second, third.
By evaluating the moment of inertia of the bodies, we get that the Solid Sphere will reach first, followed by the disk and hoop respectively.
Torque is the product of the moment of inertia and angular acceleration.
If torque is constant, the angular acceleration will be less for a large moment of inertia.
So, the object will smaller moment of inertia (I), the acceleration will be more, and thus, it will reach the bottom of the ramp first.
The given objects are disk, hoop, and solid sphere.
The moment of inertia of the Hoop = [tex]MR^{2}[/tex]
The moment of inertia of the Disk = [tex]\frac{1}{2} MR^{2}[/tex]
The moment of inertia of a solid sphere = [tex]\frac{2}{5} MR^{2}[/tex]
So, the moment of inertia for the hoop is greater than the disk and solid sphere.
[tex]I_{s} < I_{d} < I_{h}[/tex]
Thus, Solid Sphere will reach first, followed by disk and hoop respectively.
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the input time domain signal you are provided contains the vocalization signals of a fin whale (20 hz centered calls) and a humpback whale song (50 hz to 700 hz) received simultaneously by a hydrophone (underwater microphone). the objective of this project is to isolate the fin whale call by filtering out the humpback whale song. you will need a low pass filter of sufficiently high- order (> 2) to eliminate the humpback whale song sufficiently in the output signal.
To filter out the humpback whale song from the input signal and isolate the fin whale call, you will need to use a low pass filter. A low pass filter allows low frequency signals to pass through while attenuating higher frequency signals.
To sufficiently eliminate the humpback whale song in the output signal, you will need to use a high-order low pass filter. A high-order filter has a steeper roll-off, which means that it is more effective at attenuating higher frequency signals. A filter with an order of 2 or higher should be sufficient for this purpose. To design the low pass filter, you will need to determine the cut-off frequency at which the filter will begin to attenuate the humpback whale song. The cut-off frequency should be set slightly lower than the lowest frequency of the humpback whale song (50 Hz) to ensure that the song is completely eliminated in the output signal. Once you have determined the cut-off frequency and the order of the filter, you can use standard techniques to design the filter. This may involve calculating the filter coefficients using a mathematical formula or using software to design the filter based on the desired specifications. Once the filter is designed, you can apply it to the input signal to obtain the filtered output signal. The output signal should contain only the fin whale call, with the humpback whale song sufficiently eliminated.
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the variable resistor r in the circuit of fig. 11.50 is adjusted until it absorbs the maximum average power. find r and the maximum average power absorbed.
The load impedance ZL must be equal to the complex conjugate of the Thevenin impedance ZTh for maximum average power transfer. This indicates that the load impedance (or resistance) must be equal to the magnitude of the Thevenin impedance for the highest average power transfer to a fully resistive load.
How is the average amount of energy absorbed determined?
As a result, the total power used by a circuit over the course of one full cycle is the sum of the power saved and the power returned.
How do you calculate average power?
The formula for average power in mathematics is: Average power = Total energy consumed Average amount of time spent P = W t.
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consider an earthquake to be a three-dimensional wave traveling through the earth's crust. the intensity of the earthquake passing through the earth is measured to be 11000 j/(m2*sec) at a distance 35 km from the source. the earthquake lasts for 14 seconds. ef picup part description answer save status a. determine the intensity at 1.3 km from the source. (include units with answer) format check click here to check your answer 6.25 pts.75% 2% try penalty 1 hint available
The intensity of the earthquake at 1.3 Km from the source is 8 x 10⁹ W/m².
r₁ = distance of the point from the source = 35 km = 35000 m
I₁ = intensity of earthquake wave at distance "r₁" = 1.1 X 10⁶ W/m²
r₂ = distance of the point from the source = 1.3 km = 1300 m
I₂ = intensity of earthquake wave at distance "r₂"
We know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .
= I α 1/r²
where I = intensity of wave , r = distance from source
Hence we can write,
= I₁/I₂ = r₂²/r₁²
Substituting the values,
= 1.1 X 10⁶ /I₂ = (1300/35000)²
= I₂ = 8 x 10⁹ W/m²
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By 2020, experts project that _____ of children at 30 years of age will still have living grandparents. 60% 40% 20% 80%. 80%.
In 2020, 80% of youngsters who are 30 years old will still have living grandparents, according to experts.
The majority of adults under the age of 40 believe adult children have a duty to help out ageing parents. Eight in ten (81%) of this age group, compared to 75% of middle-aged individuals and 68% of those 60 and older, feel this is a responsibility. Parental caregiving enables them to continue working. They frequently play a crucial role following family catastrophes. The interactions between grandparents and their adult grandchildren are typically centred on financial support. The likelihood of adult children and their parents spending their golden years together is rising as people live longer. Middle age, the stage of adulthood for humans that occurs just before the onset of old age.
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Answer: 80
Explanation:
the circuit in fig. 32-31 consists of switch s, a 12.0 v ideal battery, a 20.0 m resistor, and an air-filled capacitor. the capacitor has parallel circular plates of radius 5.00 cm, separated by 3.00 mm. at time t 0, switch s is closed to begin charging the capacitor. the electric field between the plates is uniform. at t 250 ms, what is the magnitude of the magnetic field within the capacitor, at radial distance 3.00 cm?
The electric field between the plates is uniform. at t 250 ms, 4.78 x 10^-7 T is the magnitude of the magnetic field within the capacitor, at radial distance 3.00 cm.
The magnitude of the magnetic field within the capacitor at a given time, you need to know the current flowing through the circuit at that time. The current flowing through the circuit is given by Ohm's Law:
I = V / R
Where I is the current, V is the voltage across the resistor (which is the same as the voltage of the battery), and R is the resistance of the resistor. Putting values from the problem gives:
= I = 12.0 V / 20.0 mΩ
= 0.600 A
Once you have the current, you can use the right-hand rule to find the direction of the magnetic field within the capacitor. The right-hand rule states that if you point your right thumb in the direction of the current, your fingers will curl in the direction of the magnetic field.
To find the magnitude of the magnetic field, you can use the equation:
= B = μ0 x I / 2πr
Where B is the magnitude of the magnetic field, μ0 is the permeability of free space (a constant equal to 4π x 10^-7 T*m/A), I is the current, and r is the radial distance from the center of the current-carrying wire (in this case, the resistor). Putting the values from the problem gives:
= B = 4π x 10^-7 T x m/A x 0.600 A / (2π x 3.00 cm)
= 4.78 x 10^-7 T
So, the magnitude of the magnetic field within the capacitor at a radial distance of 3.00 cm, 250 ms after the switch is closed, is approximately 4.78 x 10^-7 T.
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Cepheid variables are valuable as distance markers because they are ________ and their period of brightening is directly related to their ________________
a. bright; absolute magnitude
b. bright; apparent magnitude
c. dim; apparent magnitude
d. dim; absolute magnitude
Cepheid variables are valuable as distance markers because they are bright and their period of brightening is directly related to their absolute magnitude.
What is Cepheid variable?Cepheid variable is one of a class of variable stars whose periods (the time for one cycle) of variation are closely related to their luminosity and that are therefore useful in measuring interstellar and intergalactic distances.
Cepheids are special in which the period at that Cepheids pulse is related to their average intrinsic luminosity. More luminous Cepheids pulse more slowly. By measuring the period of a Cepheid, we can calculate its intrinsic luminosity, and also its distance.
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the temperature of the photosphere is about the temperature of the photosphere is about 3,200 k. one million k. ten million k. 11,000 k. 5,800 k.
The photosphere has a temperature of approximately 5,800 k.
What does the photosphere do in the Sun?The photosphere is the deepest layer of the Sun that we are able to directly observe. It extends about 250 miles (400 km) above the solar disk's visible surface at its center.
The level of the solar atmosphere from which we receive light and heat is called the visible photosphere, also known as the sphere of light, and it is the area that is visible to human eyes. Above the apparent sharp edge of the photosphere, there is a thin chromosphere and a large corona.
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the concentration of particles (assume neutral hydrogen atoms) in interstellar gas is 1 particle/cm3, and the average temperature is about 3 k.
The pressure of the interstellar gas is 2.76*10-16 pascal.
What are interstellar gasses?
Most of the gas between stars in our galaxy and other galaxies is hydrogen and helium, which is dispersed at different densities between the stars. The gas ratios are comparable to those of the Sun. Star formation starts with interstellar gas as its raw material.
PV = nRT
V = 10-6 m3
n = 1/NA ; NA = avagadro number = 6.022*1023
n = 1.66*10-24
R = 8.314 J/K/mole
T = 20K
P = 1.66*10-24*8.314*20 / 10-6
P = 2.76*10-16 pascal
Therefore, the pressure of the interstellar gas is 2.76*10-16 pascal.
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Complete question:
The concentration of particles (assume neutral hydrogen atoms) in interstellar gas is 1.0 particle/cm3, and the average temperature is about 3 K .
1. What is the pressure of the interstellar gas? (please give units)
The figure above represents two charged, concentric conducting shells with radii R_1 and R_2. The space between the shells is filled with air. The dashed lines represent equipotentials. The electric field just outside the inner shell has magnitude E_1, and the electric field just inside the outer shell has magnitude E_2. Which of the following statements is true of the magnitude E of the electric field at point P? (a) E = 0 (b) E_1 > E > E_2 (c) E = E_1
The electric field just outside the inner shell has magnitude E1, and the electric field just inside the outer shell has magnitude E2, True for the magnitude E of the electric field at point P is The correct answer is (b) i.e. E1 > E > E2
Since the shells are conducting and the space between them is filled with air, the electric field must be perpendicular to the surface of the shells at all points. This means that the equipotential lines as assumed must be perpendicular to the shells as well. At point P, the equipotential lines are closer together than they are at the outer shell, but farther apart than they are at the inner shell. This means that the electric field at point P must have a magnitude that is between E1 and E2, but closer to E1 than to E2. Therefore, the correct answer is (b) E1 > E > E2. The term "electric field" refers to the physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field (also known as an E-field). It can also refer to the physical field surrounding a system of charged particles. Electric fields are composed of electric charges and time-varying electric currents. Both electric and magnetic fields are manifestations of the electromagnetic field, one of the four fundamental interactions of nature.
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mass and weight the standard metric unit for mass is and the stanard metric unit for weight is worksheet. t/f
The standard metric unit for mass is kilogram and the standard metric unit for weight is Newton.
There are two type of quantities in the physical world one are derived quantities and the seconds are fundamental quantities. Mass is a fundamental quantity and weight is a derived quantity that is a combination of acceleration due to gravity and mass.
These quantities are measured with respect to a standard System of units.
These units are decided by International organisations.
As per the latest update to the units the standard metric unit for mass for decided to be kilogram and the standard metric unit decided for weight was Newton.
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the figure(figure 1) shows a particle of mass m at distance x along the axis of a very thin ring of mass m and radius r. calculate the gravitational potential energy of these two masses. use what you know about the relationship between force and potential energy to find the magnitude of the gravitational force on m when it is at position x>0 .
Gravitational potential energy of these two masses is -2GM ((√r²+x²)-x)
r²
What is gravitational potential energy?
Potential energy is accumulated as a result of the work required to displace a mass (m) from infinity to a position inside the gravitational field of a source mass (M) without accelerating it. These are referred to as gravitational potential energies. The sign Ug is used to denote it.
We are aware that a body's stored energy in a certain position is what is meant by the term potential energy of a body. The change in potential energy is equal to the amount of work done on the body by the applied external forces if the body's position changes as a result of the application of those forces.
Let's break the disc into small rings
dm− mass of the ring,
So. dm=2πrdr× M
πr²
So, potential dP= −Gdm
√(x² +r²)
So, dP= G.2πxtanϕxsec 2 ϕdϕ
(x√( 1+tan 2 ϕ )) πr²
⇒P= −2GMx ∫ tan (R/x) tanϕsecϕdϕ
r²
⇒P= −2GMx {1− 1 }
r² cos(tan 2 (R/x))
⇒P= -2GM((√r²+x²)-x)
r²
Hence, gravitational potential energy of these two masses is -2GM((√r²+x²)-x)
r²
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the surface of venus is permanently covered by a thick layer of clouds, so astronomers have studied the surface by manned missions to the surface. images sent back by spacecraft that have landed on the surface. radar from spacecraft that have landed on venus' largest moon. telescope observations in visible light.
Venus has a very hot, dense atmosphere. You couldn't breathe the atmosphere, you would be crushed under the weight of the atmosphere, and you would burn up in temperatures
on the surface that were hot enough to melt lead. After the Sun and the Moon, Venus is the brightest object in the sky. In the morning or evening sky, Venus can occasionally be mistaken for a bright star. The planet is comparable to Earth on the inside and is a tad smaller than Earth. Venus's surface is atmosphere by dense clouds, so we can't see it from Earth.
The NASA spacecraft Mariner 2 successfully flew by and examined Venus, the first planet to be explored by a spacecraft.
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what would be the difference between proper length l0l0l 0 and the length lll measured by an observer moving at 30 m/sm/s for a proper length of 5 mm (a reasonable proper length for a car)? use a similar procedure to the one you used in the previous part. express your answer in meters to three significant figures. use c=3×108m/s.
The difference is 2.5 x 10^-14 which is smaller than the diameter of an atom. For everday situations, it is a very good approximation to assume that all measured lengths are equal to their proper lengths
Calculation :
L = Lo*sqrt(1-(v/c)^2)
by solving this
Lo-L = 2.5 x 10^-14
notice this difference, which is much smaller than the diameter of an atom. For everday situations, it is a very good approximation to assume that all measured lengths are equal to their proper lengths.
A measurement is a quantification of an attribute of an object or event that can be used to compare it with other objects or events. [1][2] In other words, a measurement is a way of determining how large or small a physical quantity is compared to a base reference quantity of the same kind. The scope and application of measurements are situation and field dependent. In science and engineering, measurement does not refer to the nominal properties of an object or event, consistent with the guidelines of the International Glossary of Metrology published by the International Bureau of Weights and Measures.
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Two protons (charge q = 1.602·10-19 C) move at the same speed v= 1.6 ·105 m/s in opposite directions parallel to the x-axis. At the instant when they are at the same x-position, the proton moving in the negative direction is at distance r= 0.7 m in the positive y-direction with respect to the one moving in the positive direction.
What is the magnetic field direction at the point of the proton moving in the negative direction?
What is the magnetic force direction experienced by the proton moving in the negative direction?
This is due to the fact that the electron's charge has a sign that is the polar opposite of that of the proton. In this instance, the magnetic force will be applied along the z-negative axis's side.
What magnetic field and force experienced by the proton?Since the charge is travelling in the direction of the observer, pointing the thumb in that direction will cause the fingers to curl counterclockwise. However, since this charge is negative, the magnetic field line will be moving in the opposite direction for the observer.
Therefore, the electric charge will travel in a circle around a fixed point. Positive charges move in a counterclockwise manner when the magnetic field is pointing into the page, whereas negative charges move in a clockwise direction.
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when the right kidney is obstructed, the nephrons in the left kidney increase in size to compensate. TRUE OR FALSE?
When the right kidney is obstructed, the nephrons in the left kidney increase in size to compensate. This statement is true.
When the right kidney is obstructed because of any reason, the nephrons of the left kidney increase in size to compensate.
Nephrons are basically the basic building blocks of the kidney. Nephron's help in filtering the fluid of the body.
Normally when both the Kidneys work efficiently then both the Kidneys have normal size.
But a one of the kidney is obstructed then the nephron size of the Other kidney increases in order to compensate the loss for the lack of use of nephrons of the obstructed kidney.
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page 85 of geography 1st high school
On page 85 and following of the first year high school geography book, the subject on the study of the earth and the universe is shown, and the technologies used for their study.
We relate the name with its definitionGeographic Information System: uses the overexposure of layers with geographic information to generate maps.Satellite network: set of space machines to obtain images of the earth's surface.Computers: machines used on earth to process information from satellite sensors.Satellites: spatial objects that provide information to the GPS.¿What use can be given to GIS and satellite technology?Be located geographically.Send directions with GPS included.Ease of searching for information, investigating and contrasting geographic data.Photographs of the planet from satellites.Preparation of maps.We observe the images of a GIS and choose the correct optionFour illustrations are shown in the book and we must choose the one most similar to the images generated by a GIS, in this case the correct answer is figure 2, which shows an area with its irrigation availability.
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A 65 kg person is running at 5 m/s. What is her momentum?
325 kg m/s
70 kg m/s
O 1625 kg m/s
Answer:
325 kg m/s
Explanation:
m=momentum
w=weight of the person in kg
s=speed of the person in m/s
m=w*s
m=65 kg*5 m/s
m=65*5 kg m/s
m=325 kg m/s
g assuming that eq. 37-36 holds, find how fast you would have to go through a red light to have it appear green. take 620 nm as the wavelength of red light and 540 nm as the wavelength of green light
2.9 x 10^8 m/s fast would have to go through a red light to have it appear green. Taking 620 nm as the wavelength of red light and 540 nm as the wavelength of green light.
The speed at which light appears to change color depends on the relative motion between the observer and the source of light. When an observer is moving towards a source of light, the light appears to shift towards shorter wavelength (blue shift), and when an observer is moving away from a source of light, the light appears to shift towards longer wavelengths (red shift). To make red light appear green, an observer would need to be moving away from the source of red light at a speed such that the light appears to shift towards a wavelength of 540 nm, the wavelength of green light.
The amount of shift in the wavelength of light due to relative motion is given by the formula:
= Δλ
= λ0 x v/c
Where Δλ is the change in wavelength, λ0 is the rest wavelength of the light, v is the speed of the observer relative to the source of light, and c is the speed of light. In this case, the rest wavelength of the light is 620 nm (the wavelength of red light), and we want to find the speed at which the light would appear to have a wavelength of 540 nm (the wavelength of green light).
Substituting these values into the formula, we get:
= Δλ
= 620 nm x v/c
= 540 nm
Solving for v, we get:
= v
= c x Δλ / λ0
= 3 x 10^8 m/s x 540 nm / 620 nm
= 2.9 x 10^8 m/s
So to make red light appear green, an observer would need to be moving away from the source of light at a speed of about 2.9 x 10^8 m/s. This is about 99% of the speed of light, which is not possible for any object with mass.
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a double pendulum consists of two simple pendula, with one pendulum suspended from the bob of the other. if the two pendula have equal lengths, $l$, and have bobs of equal mass, $m$, and if both pendula are confined to move in the same vertical plane, find lagrange's equations of motion for the system. use $\theta $ and $\phi$--the angles the upper and lower pendulums make with the downward vertical (respectively)--as the generalized coordinates. do not assume small angles.
Lagrange's equations of motion for the system is d(ml³Ф2 + ml²Ф1 cos (Ф1-Ф2)) − (−ml³Ф1Ф2 sin (Ф1-Ф2)-mgl sinФ2 )/dt = 0.
Newton’s method of developing equations of motion requires taking elements apart. When forces at interconnections are not of primary interest, more advantageous to derive equations of motion by considering energies in the system
Lagrange’s equations is Indirect approach that can be applied for other types of systems (other than mechanical) Based on calculus of variations.
A plane pendulum (length l and mass m), restrained by a linear spring of spring constant k and a linear dashpot of dashpot constant c. The upper end of the rigid massless link is supported by a frictionless joint.
A mass spring dashpot subsystem in a falling container of mass m1. The system is subject to constraints that confine its motion to the vertical direction only. The mass m2 linear spring of undeformed length l0 and spring constant k, and the linear dashpot of dashpot constant c of the internal subsystem.
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a certain heat engine does 12.0 kj of work and 8.00 kj heat transfer occurs to the environment in a cyclical process.
Heat transfer in to engine 20Kj
Work done by heat engine W = 12Kj
Heat transfer to environment is Qc = 8kj
(a) Heat transfer in to engine
Qh = W + Qc = 12kj + 8 kj = 20Kj
Thermal engineering's field of study known as "heat transfer" deals with the production, application, conversion, and exchange of thermal energy (heat) across physical systems. The classification of heat transmission into different methods includes thermal conduction, thermal convection, thermal radiation, and energy transfer by phase changes. Engineers also take into account the advection of mass, either hot or cold, made up of various chemical species while attempting to transfer heat. Even though these mechanisms have unique traits, they frequently take place at the same time in the same system.
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In the United States, barometric pressures are generally reported in inches of mercury (in Hg). On a beautiful summer day in Chicago, the barometric pressure is 30.45 in Hg.
A) Convert this pressure to torr.
B) Convert this pressure to atm.
As a result, the pressure in atm is equal to 0.0400atm and the barometric pressure in torr is 773.43 torr.
What is barometric pressures?In a nutshell, barometric pressure is the measurement of air pressure in the atmosphere, more precisely, the measurement of the force that air molecules exert at a specific location on Earth. Wherever the reading is taken, the barometric pressure is always different since it is always fluctuating.
How does barometric pressure affect humans and what type of barometric pressure causes pain?Our bodies experience increased pressure from high barometric pressure, which limits how much tissues can expand. On the other side, when the air pressure in the atmosphere is low, our body's tissues can expand more, which increases pressure on our nerves and other body parts.
Low barometric pressure can make your body's tissues bulge and irritate sensitive nerves. It causes discomfort in the joints by causing your muscles, tendons, and any scar tissue to contract and expand.
Briefing:(A) Convert this pressure to torr:
Pressure (in inHg) = 30.45 inHg
Pressure (in torr) =?
The following steps can be used to convert 30.45 inHg to torr:
1 inHg = 25.4 torr
Therefore,
30.45 inHg = 30.45 inHg × 25.4 torr / 1 inHg
30.45 inhg = 773.43 torr
Thus, 30.45 inhg is equivalent to 773.43 torr
B) Convert this pressure to atm:
Therefore,
1atm=760mmHg
=30.45(1atm/760mmHg)
=0.0400atm
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In a symphony a single violin produces 25.0 dB sound intensity, if the conductor desires a robust
sound intensity of 70.0 dB from violin section, how many violin players does he employ?
He has to employ 31623 violin players.
What is intensity of sound in dB?The SI unit for sound intensity is W/m^2, although considering how humans hear sounds, the decibel (dB) scale of sound intensity is more useful. The logarithm of the intensity of a sound, as opposed to the intensity of a sound directly, is a better indicator of how human ears perceive sound.
Ten decibels (dB) are equal to every factor of ten in intensity.
For this case, a 70.0 dB sound is 45 dB louder than a 60 dB sound, 4.5 factors of 10 (10^4.5) as intense.
Hence, if a single violin produces 25.0 dB sound intensity, to produce a robust sound intensity of 70.0 dB from violin section, he has to employ 10^4.5 = 31623 violin players.
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