Justin writes the letters ILLINOIS on cars and then places the cards and a hat what is the probability of picking a N? Probability unit test part one

Answer:

10

Step-by-step explanation:

Answer:

what do you mean?

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

the height of the person is y = 6 and the distance from the ladder is also 6 = x. To find the angle formed by the ladder we use [tex]arctan(\frac{y}{x})[/tex] which in this case is

[tex]arctan\frac{6}{6} = arctan(1)\\= 45 degrees[/tex]

now we know that the person is 9 feet away from wall and 6 feet away from the ladder so the total x distance is 9+6 = 15 = x

to find y we use tan(45) = [tex]\frac{y}{x}[/tex]

multiply both sides by x = 15 and simplify to get y = 15

Answer:

i think 2

Step-by-step explanation:

Answer:

Your question is Incomplete....

The zeros of the polynomial function f(x) = x^2 - 9x - 70 can be found by factoring or using the quadratic formula. The zeros are -5 and 14.

To find the zeros of the polynomial function f(x) = x^2 - 9x - 70, we can factor the expression or use the quadratic formula. Let's factor the expression:

f(x) = x^2 - 9x - 70

= (x - 14)(x + 5)

Setting each factor equal to zero, we get:

x - 14 = 0 --> x = 14

x + 5 = 0 --> x = -5

Therefore, the zeros of the polynomial function are x = -5 and x = 14. These values represent the x-coordinates where the function intersects the x-axis, indicating the points where the function equals zero.

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The expected number of matchings goes to infinity as N › [infinity].

Matching in Graph Theory:A matching in Graph Theory is a set of edges of a graph where no two edges share a common vertex. In other words, a matching is a set of independent edges of a graph. A perfect matching in a Graph Theory is a matching of size equal to half the number of vertices in a graph.The expected number of matchings goes to 0 as N › [infinity]:The expected number of matchings goes to zero as N › [infinity] when |E| = 3/N. It is because 3/N is a relatively dense number of edges that are independent of the number of vertices that can exist between A and B. The expected number of matchings is thus very small in comparison to the total number of matchings possible as N › [infinity].The expected number of matchings goes to infinity as N › [infinity]:The expected number of matchings goes to infinity as N › [infinity] when |E| = 4.V. It is because 4.V is a relatively large number of edges that are independent of the number of vertices that can exist between A and B. The expected number of matchings is thus very large in comparison to the total number of matchings possible as N › [infinity]. Hence the expected number of matchings goes to infinity as N › [infinity].

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A)the required formula is r(x) = -3x² + 24x + 15.B)the worker will be assembling 36 units per hour at 10:00 A.M.C)the worker will assemble 70 units between 10:00 A.M. and 11:00 A.M.

a) Derive a formula for the rate at which the worker will be assembling units after x hours. The worker assembles f(x)= −x³ + 12x² + 15x units in x hours.

To determine the formula for the rate at which the worker will be assembling units after x hours, we can differentiate the given function with respect to time t.

We can write this function as:f(x) = -x³ + 12x² + 15xf'(x) = -3x² + 24x + 15

On differentiating the given function, we get the rate at which the worker will be assembling units after x hours is:r(x) = -3x² + 24x + 15

Therefore, the required formula is r(x) = -3x² + 24x + 15.

b)The worker arrives at 9:00 A.M. and we want to determine the rate at which the worker will be assembling units at 10:00 A.M, which means the worker will be assembling units after 1 hour.

We can use the formula:r(x) = -3x² + 24x + 15

To find the answer:r(1) = -3(1)² + 24(1) + 15r(1) = -3 + 24 + 15r(1) = 36 units per hour

Therefore, the worker will be assembling 36 units per hour at 10:00 A.M.

c)To find the number of units assembled by the worker between 10:00 A.M. and 11:00 A.M., we need to integrate the function r(x) = -3x² + 24x + 15 with limits 1 and 2.

We can use the formula:Integral of r(x)dx = f(x)

Using the formula, we get:f(2) - f(1) = Integral of r(x)dx between 1 and 2f(x) = -x³ + 12x² + 15x

Substituting the limits, we get:

f(2) - f(1) = [-2³ + 12(2²) + 15(2)] - [-1³ + 12(1²) + 15(1)]f(2) - f(1) = [−8 + 48 + 30] - [−1 + 12 + 15]f(2) - f(1) = 70

Therefore, the worker will assemble 70 units between 10:00 A.M. and 11:00 A.M.

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To determine which functions are solutions of the given differential equation y'' + y = 3 sin(x), we need to check if plugging each function into the differential equation satisfies the equation. We will examine each option and identify the functions that satisfy the equation.

The differential equation y'' + y = 3 sin(x) represents a second-order linear homogeneous differential equation with a particular non-homogeneous term.
(a) Plugging y = 3 sin(x) into the differential equation gives 0 + 3 sin(x) ≠ 3 sin(x). Therefore, y = 3 sin(x) is not a solution.
(b) Plugging y = (3/2)x sin(x) into the differential equation gives (3/2) sin(x) + (3/2)x sin(x) = (3/2)(1 + x) sin(x), which is not equal to 3 sin(x). Therefore, y = (3/2)x sin(x) is not a solution.
c) Plugging y = 3x sin(x) - 4x cos(x) into the differential equation gives 6 cos(x) - 4 sin(x) + 3x sin(x) - 3x cos(x) = 3 sin(x), which satisfies the equation. Therefore, y = 3x sin(x) - 4x cos(x) is a solution.
(d) Plugging y = 3 cos(x) into  the differential equation gives -3 sin(x) + 3 cos(x) = 3 sin(x), which is not equal to 3 sin(x). Therefore, y = 3 cos(x) is not a solution.
(e) Plugging y = (-3/2)x cos(x) into the differential equation gives (3/2) sin(x) - (3/2)x cos(x) = (-3/2)(x cos(x) - sin(x)), which is not equal to 3 sin(x). Therefore, y = (-3/2)x cos(x) is not a solution.
Based on the analysis, the only function that is a solution to the given differential equation is y = 3x sin(x) - 4x cos(x) (option c).

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Answer:

I NEED HELP ON THE SAME QUESTION

Step-by-step explanation:

NO ONE INDERSTANDS JT FOR SOME REASON AND NEITHER DO I

A) 12 and 33 can be divided by 3 so 12:33 = 4:11

B= 20 and 5 can be divided by 5 so 20mm:5mm = 4mm:1mm

Answer:

A. 4: 11

B. 4: 1

Step-by-step explanation:

What are these? These are ratios, which show proportion. For example, for every two dogs, there is one cat. They can be written as words, fractions, or with colons, such as in these problems.

How to simplify: To simplify, think of the highest common factor. If you can't think of the highest, just think of a factor both numbers have in common and keep going until the numbers don't have any factors in common.

In this case, for A, the common factor was 3. 12/3=4 and 33/3=11. This cannot be simplified further because 11 is prime, which means it has no factors besides 1 and 11.

For B, the common factor was 4, so it is 4:1.

Answer:

It is based on history

Step-by-step explanation:

Answer: the answer is based on history

Step-by-step explanation:

Step-by-step explanation:

Answer:

When light strikes an object, its rays can be either absorbed or reflected. A solid black object absorbs almost all light, while a shiny smooth surface, such as a mirror, reflects almost all light back. When reflected off a flat mirror, light bounces off at an angle equal to the angle it struck the object.

Step-by-step explanation:

Answer:

One pair of socks is $370.

Step-by-step explanation:

Sean bought three pairs of the same socks and a shoe polish for $1450. If the

polish cost $340, how much is the cost of one pair of socks.

6x - 340 = 1450

6x = 1450 -340

6x = 1110

2x = 1110 / 3

2x = 370

Answer:

if you learned, PEMDAS then it be easier! soo I'll help.

Step-by-step explanation:

-2 ( 52- 4 ) is 48. 48 + 62= 110

if that's wrong, then I'm sorry!

1

62

48

——

110

Given that the sample mean is 100, the sample mean is 39, and the sample standard deviation is 13.

To find the 95% confidence interval for the population mean, we use the formula as follows:

Confidence Interval formula: CI = X ± Z* σ/√nWhere CI = Confidence IntervalX = Sample Mean

Z* = Z-Scoreσ = Standard Deviationn = Sample SizeHere, the sample size(n) is 100, the sample mean(X) is 39, and the sample standard deviation (σ) is 13.The formula for finding the Z-Score is:Z = 1 - α/2,

where α is the level of significance. α is the probability of the event not occurring, so we subtract it from one to get the probability of the event occurring.

Here, the level of significance is 0.05 since we need to find the 95% confidence interval.

Z = 1 - α/2 = 1 - 0.05/2 = 0.975Then we find the Z-Score from the Z-Score table, which is 1.96.

Therefore, the 95% confidence interval is:CI = X ± Z* σ/√n= 39 ± 1.96 (13/√100)= 39 ± 2.548Thus, the 95% confidence interval for the population mean is (36.452, 41.548).

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The 95% confidence interval for the population mean is

[tex]\[\large \left( 36.452,41.548 \right)\][/tex].

Sample size = 100

Sample mean = 39

Sample standard deviation = 13

Confidence level = 95%

To find the confidence interval, we use the formula given below:

Confidence interval formula is as follows:

[tex]\[\large \left( \overline{X}-z\frac{\sigma }{\sqrt{n}},\overline{X}+z\frac{\sigma }{\sqrt{n}} \right)\][/tex]

We are given, sample mean is 39

[tex]\(\overline{X}=39\)[/tex],

sample standard deviation is 13

[tex]\(\sigma=13\)[/tex],

sample size is 100

i.e. n=100, and confidence level is 95%

z=1.96 (From Z table)

By substituting all the given values in the formula, we get the confidence interval as,

[tex]\[\large \left( 39-1.96\frac{13}{\sqrt{100}},39+1.96\frac{13}{\sqrt{100}} \right)\][/tex]

Simplifying the above expression, we get,

[tex]\[\large \left( 39-2.548,39+2.548 \right)\][/tex]

Therefore, the 95% confidence interval for the population mean is

[tex]\[\large \left( 36.452,41.548 \right)\][/tex].

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Step-by-step explanation:

If x=10

2(10)²(10-5)

200 × 5

=1000

10x=10(10)

=100

The formula for C(x) is `C(x) = 4.75x + 500,000`.

The total cost of producing 100,000 items is $5,250,000.

The marginal cost of the items to be produced in this plant is $4.75.

Given, Company analysts have determined that a linear function is a reasonable estimation for the total cost C(x) in dollars of producing x items. They estimate the cost of producing 10,000 items as $547,500 and the cost of producing 50,000 items as $737,500.

(a) Find a formula for C(x)

For the given data, let C(x) be the cost of producing x items, we have the two points (10,000, 547,500) and (50,000, 737,500).

We have to find the slope of the line passing through these points.

slope of the line `

m = (y2 - y1) / (x2 - x1)`m = (737,500 - 547,500) / (50,000 - 10,000)m = 190,000 / 40,000m = 4.75

Formula for C(x) can be found by using the slope-intercept form of the equation of a line.

C(x) = mx + b

We know, m = 4.75

Using the point (10,000, 547,500), we get

547,500 = 4.75 (10,000) + b.b = 547,500 - 47,500

b = 500,000

Therefore, the formula for C(x) is `

C(x) = 4.75x + 500,000`

So, the formula for C(x) is `C(x) = 4.75x + 500,000`.

(b) Find the total cost of producing 100,000 items.

Total cost of producing 100,000 items is C(100,000).

C(x) = 4.75x + 500,000

C(100,000) = 4.75 (100,000) + 500,000= 4,750,000 + 500,000= 5,250,000

Therefore, the total cost of producing 100,000 items is $5,250,000.

(c) Find the marginal cost of the items to be produced in this plant.

Marginal cost is the cost incurred for producing one additional item. It can be found by taking the first derivative of the cost function with respect to x.

C(x) = 4.75x + 500,000 `

=>` `dC(x)/dx = 4.75`

The marginal cost of the items to be produced in this plant is $4.75.

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Answer:

148 feet squared

Step-by-step explanation:

Hope it's correct!<D

A = 2 (wl+hl+hw) = 2 x (4x6+5x6+5x4) = 148

Answer:

2 6/7 units

Step-by-step explanation:

You substitute 5/7 in for x

4(5/7) = 20/7 = 2 6/7 units

You can also add 5/7 + 5/7 + 5/7 + 5/7 to check your work

The ratio of the lateral area of the cone to the cylinder will be √(h²+r²)/2h.

The solid formed by two congruent closed curves in parallel planes along with the surface created by line segments connecting the corresponding points of the two curves is known as a cylinder.

A cylinder with a circular base is known as a circular cylinder. Based on the form of its base, a cone is given a name.

It is given that a cone and a cylinder have equal radii,r, and equal altitudes, h. The ratio of the lateral surface area of the cone to the cylinder will be calculated as below:-

The lateral area of the cone = πr√(h²+r²)

The lateral area of the cylinder = 2πrh

The ratio will be calculated as:-

R = πr√(h²+r²)  /   2πrh

R = √(h²+r²) / 2h

Therefore, the ratio of the lateral area of the cone to the cylinder will be √(h²+r²)/2h.

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The equation for the cosine function is given as;cos(x) = 3 cos(π/2 x) + 5

A cosine function is defined as follows;cos(x) = a cos(b(x - h)) + kwhere a is the amplitude, period is 2π/b, and k is the midline. The amplitude, period, and midline of a cosine function can be used to find its equation.In this case,

we have a cosine function that has a midline of y=5, an amplitude of 3 and a period of 4/π. Thus, the amplitude of the function is given as 3, the midline is given as 5, and the period is 4/π.

The amplitude is the vertical distance from the midline to the highest point on the curve and also to the lowest point on the curve. The period is the distance over which the cosine function completes one full oscillation, or cycle.

In this case, we have a period of 4/π, so we can find b by the formula b = 2π/period = 2π/(4/π) = π/2.To find the phase shift, h, we use the formula h = x₀ - (π/b), where x₀ is the x-coordinate of the maximum or minimum value of the cosine function.

Since the midline is y=5, the maximum value of the cosine function occurs when y=8 and the minimum value occurs when y=2. The maximum and minimum values occur when cos(b(x - h)) = 1 and cos(b(x - h)) = -1, respectively.

Therefore, we have;8 = 5 + 3, cos(b(x - h)) = 1when x - h = 0, so x₀ = h2 = 5 - 3, cos(b(x - h)) = -1when x - h = π/b

Thus, h = 0 for the maximum value, and h = π/2 for the minimum value. We choose the value of h that corresponds to the maximum value of the cosine function, so h = 0.

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Answer:

negative

positive

negative

zero

positive

Step-by-step explanation:

Situation 1: A football team's first play resulted in a loss of 15 yards.

negative

Situation 2: A store marks up the price of a calculator $5.20.

positive

Situation 3: Nina withdrew $50 from her bank account.

negative

Situation 4: A porpoise is swimming at sea level.

zero

Situation 5: Kylie scored 2 goals in yesterday's soccer game.​

positive

To find the 90% confidence interval for the true proportion of adults in the town with health insurance, we can use the formula:

[tex]\[\text{{Confidence Interval}} = \left( \hat{p} - Z \cdot \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}, \hat{p} + Z \cdot \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \right)\][/tex]

where:

- [tex]\(\hat{p}\)[/tex] is the sample proportion (69/88 in this case)

- [tex]\(Z\)[/tex] is the Z-score corresponding to the desired confidence level (90% corresponds to [tex]\(Z = 1.645\)[/tex] for a two-tailed test)

- \(n\) is the sample size (88 in this case)

Substituting the values into the formula, we have:

[tex]\[\text{{Confidence Interval}} = \left( \frac{69}{88} - 1.645 \cdot \sqrt{\frac{\frac{69}{88} \cdot \left(1-\frac{69}{88}\right)}{88}}, \frac{69}{88} + 1.645 \cdot \sqrt{\frac{\frac{69}{88} \cdot \left(1-\frac{69}{88}\right)}{88}} \right)\][/tex]

Evaluating the expression, we find the confidence interval to be approximately (0.742, 0.892).

The confidence interval is approximately (0.742, 0.892).

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Answer:

276 in^2

Step-by-step explanation:

2((6*6)/2) + 2(6*12) + (8*12) = 276 in^2

Answer:

the error is ( 4-17) is equal -13 not 13

so if she used - 13 the right answer is 17/34

Step-by-step explanation:

see attached

hope it helps

The correct option to the statements "1st statement: In an experimental study we can examine the association between the independent and dependent variable, and 2nd statement: In an experimental study we can examine the temporal relationship between the independent and dependent variable" is: a. Both statements are true.

An experimental study can be used to determine the relationship between two variables. It is also used to determine whether there is a cause-and-effect connection between two variables.

In an experimental study, two groups are compared. One group receives the independent variable, and the other group receives the dependent variable.

In an experimental study, the following two statements are true:

In an experimental study, we can examine the association between the independent and dependent variable. It is the correlation or connection between the two variables we are interested in exploring

In an experimental study, we can examine the temporal relationship between the independent and dependent variable. It refers to the timing or sequence of events that occurs between the two variables in question.

The study must include a time element that describes the order in which the dependent and independent variables were introduced to the subjects.

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Answer:

40

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

the lines on the very end are your subtrct the the lowest one from the highest one

The expected value of X(t), E{X(t)}, is 0, indicating that on average, the process X(t) fluctuates around the zero mean. The autocovariance function R(t₁, t₂) is given by R(t₁, t₂) = e^(-ω₀|t₁-t₂|), which signifies that the covariance between X(t₁) and X(t₂) decays exponentially with the difference in time values |t₁-t₂|.

To find E{X(t)}, we need to calculate the expected value of the given process X(t) = Acos(ω₀t) + Bsin(ω₀t), where A and B are independent random variables with mean 0.

E{X(t)} = E{Acos(ω₀t) + Bsin(ω₀t)}

Since E{A} = E{B} = 0, the expected value of each term is 0.

E{X(t)} = E{Acos(ω₀t)} + E{Bsin(ω₀t)}

          = 0 + 0

          = 0

Therefore, E{X(t)} = 0.

To find R(t₁, t₂), the autocovariance function of X(t), we need to calculate the covariance between X(t₁) and X(t₂).

R(t₁, t₂) = Cov[X(t₁), X(t₂)]

Since A and B are independent random variables with σ²_A = σ²_B = 1, the covariance term becomes:

R(t₁, t₂) = Cov[Acos(ω₀t₁) + Bsin(ω₀t₁), Acos(ω₀t₂) + Bsin(ω₀t₂)]

Using trigonometric identities, we can simplify this expression:

R(t₁, t₂) = Cov[Acos(ω₀t₁), Acos(ω₀t₂)] + Cov[Bsin(ω₀t₁), Bsin(ω₀t₂)] + Cov[Acos(ω₀t₁), Bsin(ω₀t₂)] + Cov[Bsin(ω₀t₁), Acos(ω₀t₂)]

Since A and B are independent, the covariance terms involving them are 0:

R(t₁, t₂) = Cov[Acos(ω₀t₁), Acos(ω₀t₂)] + Cov[Bsin(ω₀t₁), Bsin(ω₀t₂)]

Using trigonometric identities again, we can simplify further:

R(t₁, t₂) = cos(ω₀t₁)cos(ω₀t₂)Cov[A,A] + sin(ω₀t₁)sin(ω₀t₂)Cov[B,B]

Since Cov[A,A] = Var[A] = σ²_A = 1 and Cov[B,B] = Var[B] = σ²_B = 1, the expression becomes:

R(t₁, t₂) = cos(ω₀t₁)cos(ω₀t₂) + sin(ω₀t₁)sin(ω₀t₂)

          = cos(ω₀(t₁ - t₂))

Therefore, R(t₁, t₂) = e^(-ω₀|t₁-t₂|).

The expected value of X(t), E{X(t)}, is 0, indicating that on average, the process X(t) fluctuates around the zero mean. The autocovariance function R(t₁, t₂) is given by R(t₁, t₂) = e^(-ω₀|t₁-t₂|), which signifies that the covariance between X(t₁) and X(t₂) decays exponentially with the difference in time values |t₁-t₂|.

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