Answer:
The time spent in air by the car is 2.19 s
The height of the cliff is 58.5 m
Explanation:
Given;
initial velocity of the car, u = 16 m/s
horizontal distance traveled, R = 35 m
The horizontal distance or range of a projectile is given as;
R = vt
where;
t is the time spent in air by the projectile
t = R/v
t = 35 / 16
t = 2.19 s
The height of the cliff is given as;
h = ut + ¹/₂gt²
h = (16 x 2.19) + ¹/₂(9.8)(2.19)²
h = 58.5 m
The sixth grade teachers are planning a field trip. They want to divide the 192 students evenly on the four buses. How many students will ride each bus?
Answer:
48 students will ride on each bus.
Explanation:
192 students divided by 4 busses comes out to 48 students per bus.
Basically: 192/4=48
A 50 Kg football player is standing still when he experiences an inelastic collision with a 150 Kg football player who is traveling at 10 m/s. What is the velocity of the player immediately after the collision?
Answer:
V = 7.5 m/s
Explanation:
Given that,
Mass of player 1, m₁ = 50 kg
Mass of player 2, m₂ = 150 kg
50 kg player stands still and 150 kg player is traveling at 10 m/s
We need to find the velocity of the player immediately after the collision. As the inelastic collision occurs. The linear momentum will remain conserved. After the collision, let they move with a constant velocity say V.So,
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\=\dfrac{150\times 10}{(50+150)}\\\\=7.5\ m/s[/tex]
So, the velocity of the player immediately after the collision is 7.5 m/s.
4. A Ferrari travels 350km in 2 hours. What was it's
s speed?
A 2000 kg car is moving at 1.5 m/s. What is its kinetic energy?*
A. 0J
B. 3000J
C. 1500 J
D. 4500 J
E. 2250 J
Who else got stuck on a question and is NOT ready for test return at 2? its 1:58 AAAAAAA
A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?
Answer:
Explanation:
The force of static friction acting on the box is the frictional force;
Frictional force Ff = Wsin theta (force acting along the ramp)
W is the gravitational force known as the weight
Ff = 112.1sin42°
Ff = 112.1(0.6691)
Ff = 75.00N
Hence he force of static friction acting on the box if box has a gravitational force of 112.1 N id 75.00N
Answer:
75N i did test
Explanation:
A box is being pulled across a horizontal surface by a 20 N force to the right.
a. If the box moves at a constant velocity, what do you know about the forces acting on the object?
b. If the box moves at a constant velocity, how much force opposes the motion of the box?
c. If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, what is the net force on the box?
A) If the box moves at a constant velocity, what we know about the forces acting on the object is; the sum of the forces acting on the object must be zero.
B) If the box moves at a constant velocity, the force that opposes the motion of the box is; Frictional Force of -20 N
C) If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, the net force on the box is; F_net = 5 N
We are told that a box is being pulled across a horizontal surface by a 20N force to the right.
A) Newton's first law of motion states that an object will remain at rest or continue in motion unless an external force acts on it. This means that any object/body moving with constant velocity will have no net external force acting on it. Thus, the sum of the forces acting on the object must be zero. B) Since we are told that the box is moving at a constant velocity and that the sum of all forces must be zero. Then the force that will oppose the applied force of 20N to the right will be an equal but opposite force .In this case the opposing force will have to be the frictional force which will be -20 N to balance out the applied force.
C) We are told that a force of 15 N is acting to the left along with the 20 N force.Thus, the net force will be;
F_net = 20 - 15
F_net = 5 N
Read more at; https://brainly.com/question/20712983
A 55 kg boy running at 2.0 m/s jumps onto a 2.0 kg skateboard. Calculate the final velocity of the boy and the skateboard.
Answer:
The final velocity of the boy and the skateboard is 1.93 m/s.
Explanation:
We can find the final velocity of the boy and the skateboard by conservation of linear momentum:
[tex] P_{1} = P_{2} [/tex]
[tex] m_{b}v_{i_{b}} + m_{s}v_{i_{s}} = m_{b}v_{f_{b}} + m_{s}v_{f_{s}} [/tex] (1)
Where:
[tex]m_{b}[/tex]: is the boy's mass = 55 kg
[tex]m_{s}[/tex]: is the skateboard's mass = 2.0 kg
[tex]v_{i_{b}}[/tex]: is the initial speed of the boy = 2.0 m/s
[tex]v_{i_{s}}[/tex]: is the initial speed of the skateboard = 0
[tex]v_{f_{b}}[/tex]: is the final speed of the boy =?
[tex]v_{f_{s}}[/tex]: is the final speed of the skateboard =?
Since the boy and the skateboard will have the same final velocity by entering the above values into equation (1) we have:
[tex] 55 kg*2.0 m/s + 0 = v_{f}(55 kg + 2.0 kg) [/tex]
[tex] v_{f} = 1.93 m/s [/tex]
Therefore, the final velocity of the boy and the skateboard is 1.93 m/s.
I hope it helps you!
The final velocity of the boy and the skateboard is 1.93m/s
According to the law of conservation of momentum, the momentum of the bodies before the collision is equal to the momentum of the bodies after the collision.
Mathematically, [tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]
[tex]m_1 \ and \ m_2[/tex] are the masses of the object
[tex]u_1 \ and \ u_2[/tex] are the velocities of the object
v is the final velocity
Given the following parameters
m₁ = 55kg
u₁ = 2.0m/s
m₂ = 2.0kg
u₂ = 0m/s
Required
Final velocity "v"
Substitute the given parameters into the formula to have:
[tex]55(2)+2(0)=(55+2)v\\110=57v\\v=\frac{110}{57}\\v= 1.93m/s[/tex]
Hence the final velocity of the boy and the skateboard is 1.93m/s
Learn more here: https://brainly.com/question/22257327
What makes the yardstick test a direct measurement of reaction time?
A.
The further the yardstick falls, the slower the reaction time.
B.
Yardsticks have numerical markings for length.
C.
Yardsticks are designed to measure reaction time.
D.
all of the above
Please select the best answer from the choices provided.
A
B
C
D
Answer:
A. the further the yardsticks falls, the slower the reaction time.
Answer:
The further the yardstick falls, the slower the reaction time.
Explanation:
its A
which option lists materials in order by their ability to allow the flow of electrons, from most easily to least easily?
A. Conductor, semiconductor, insulator
B. Semiconductor, insulator, conductor
C. Insulator, semiconductor, conductor
D. Semiconductor, conductor, insulator
Help me pls!
Answer: Conductor, semiconductor, insulator
Explanation:
Just did the quiz
The correct option is option A.
The descending order in which electrons flow easily is:
Conductor, semiconductor, insulator
Conductivity and flow of electrons:The correct order for materials by their ability to allow the flow of electrons, from most easily to least easily is Conductor, semiconductor, insulator.
Conductors are generally metals, they have plenty of free electrons due to which the electron flow is easy. Also, the conduction band and valance band in a conductor overlap, so they can conduct at room temperature.
In the case of semiconductors, the band gap between the conduction band and valance band is almost 1eV, so a little energy is enough to make the flow of electrons possible
Whereas, in insulators, the band gap is quite high and electrons can not jump from the conduction band to the valence band due to which the flow of electrons is not possible.
Learn more about band gap:
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PLEASE HELP ME IM TIMED
Answer:
the answer is the core
Explanation:
the core is composed of iron and nickel
If you increase the frequency what happens to the distance between the waves (wavelength)?
The size of the waves stays the same
the distance increases (longer wavelength)
There is no way to tell.
the distance decreases (shorter wavelength)
Answer:
C)the distance decreases Shorter wavelength
Step by step Explanation:
how do you know the pole on the left is the south pole and the pole on the right is the north pole?
Answer:
Left is deciamled to the right [tex]x_{123}[/tex]
Explanation:
INEGRATED SCIENCE-8th grade science
report cards due dec.18
Please Help ASSSAAAAPPPP! PLEASEEEEEEE
Answer:
I do drink bottled water but not to often, I live about 2.8 miles away from its water source and if i did'nt drink bottled water and I had to found out how my drinking water is treated I would go ask the people that are taking care of the water.
Explanation:
hope this helps
What is power??????????
A stretched spring attached to two fixed points is compressed on one end and released, as shown. The resulting wave travels back and forth between the two fixed ends of the spring until it comes to a stop. This is an example of _____ .
a Transverse wave
b
longitudinal wave
c
surface wave
d
electromagnetic wave
Answer:
B. Longitudinal wave
Explanation:
It's the only option that makes sense. Hope this helped :)
What is thermodynamics?
the movement of energy
the classification of energy
the way energy changes
the movement of heat
Answer:
The movement of energy
Explanation:
Answer:
the movement of energy
2. The purpose of using ice on an injured area is... *
to increase blood flow.
O to hydrate an injury.
O to reduce blood flow.
O to dilate blood vessels.
A car decelerates uniformly from 54 m/s to 38 m/s in 8.0 seconds. How far does it travel dunng this time?
Answer:
368m
Explanation:
dx=vt
54+38/2=46
46*8=368m
Kayla is measuring how long it takes a ball to roll down a hill. The ball has a
starting velocity of 2.6 m/s. The ball rolls down the hill for 5.5 seconds, and
when it reaches the bottom, it has a velocity of 8.0 m/s. How far did the ball
roll during this time frame?
A) 44 meters
B) 14 meters
C) 29 meters
D) 58 meters
How do we obtain data about the properties of exoplanets and objects in our solar system?
Answer:
Doppler effect to analyze the motion and properties of the star and planet.
Explanation:
The radial velocity method invovles watching the spectral lines of a star as a planet orbits around the star. Because of the planets gravitational pull on the star, will wobble. This causes Doppler shifts in the spectral lines, allowing astronomers to infer the presence of the planets.
The density of an object is dependent upon the object’s mass and ---
Answer:Volume
Explanation:
Density = mass/ Volume
Answer:
Volume
Explanation:
Chemical reactions occur due to sharing or transferring of blank. Please help ASAP!!!!
Answer: valence electrons?
Explanation:
Please help
true or false? drag forces decrease when the density of a fluid increases
Answer:
Drag increases with the density of the fluid (ρ). More density means more mass, which means more inertia, which means more resistance to getting out of the way. The two quantities are directly proportional.
How much Tension force is required to pull a 1500 kg car (it is being towed) forward with an acceleration of 3 m/s^2 if the friction force on the towed car's tires is pulling backward with a force of 2500 N?
If the pull is done horizontally, then the net force on the car is
∑ F = T - f = (1500 kg) (3 m/s²)
where T is the magnitude of the tension in the towing cable, and f is the friction which points in the opposite direction. Then
T = f + (1500 kg) (3 m/s²)
T = 2500 N + 4500 N
T = 7000 N
100 points if u help me and get it right this needs to be done in 3 min hurry to get ur 100 points
Calculate the kinetic energy of a 50 kg cart moving at a speed of 6.9 m/s.
Answer:
35
Explanation:
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As we know, the moon is a satellite of our earth, what is the
theoretical period of the moon? The average radius of the
moon's orbit is 3.84 108 m and the mass of the earth is 5.97 x
1024 kg (in hours, G = 6.67 x 10-9 N (m/kg) 3).
Answer:c
Explanation:c
This question involves the concepts of the time period, orbital radius, and gravitational constant.
The theoretical period of the moon is "658 hr".
The theoretical time period of the moon around the earth can be found using the following formula:
[tex]\frac{T^2}{R^3}=\frac{4\pi^2}{GM}[/tex]
where,
T = Time Period of Moon = ?
R = Orbital Radius = 3.84 x 10⁸ m
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
Therefore,
[tex]\frac{T^2}{(3.84\ x\ 10^8\ m)^3}=\frac{4\pi^2}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}\\\\T^2=(9.91\ x\ 10^{-14}\ s^2/m^3)(56.62\ x\ 10^{24}\ m^3)\\\\T=\sqrt{561.34\ x\ 10^{10}\ s^2}[/tex]
T = 2.37 x 10⁶ s[tex](\frac{1\ h}{3600\ s})[/tex]
T = 658 hr
Learn more about the orbital time period here:
https://brainly.com/question/14494804?referrer=searchResults
The attached picture shows the derivation of the formula for orbital speed.
Integrated Science- 8th grade science
Please Help ASAP!
Its almost the end of semester And I need to fix my grade for science so PLEASE help!
its almost report cards time!
Answer:
A. a rigorously tested explanation
Explanation:
B. and D. are out - theories are not opinionated, they are factualC. is out - not all theories are mathematicalA. is the best choiceAnswer:
The answer is option letter B
If you can run at a speed of 30 miles per hour and run a distance of 15
miles, how long did it take you to run that distance?
Answer:
30 mins
Explanation:
speee=distance/time
300m/h=15m/time
time=15miles/300miles/hous=1/2 hours=30 mins
Answer:
30 minutes.
Explanation:
If it takes you an hour to run 30 miles but you only need to run 15 miles then you split that hour in half, which results in half an hour or 30 minutes.