_____________is the addition of wave energy as waves interact, producing larger waves and ____________ is the subtraction of wave energy as waves interact, producing smaller waves.

Answers

Answer 1

Constructive interference is the addition of wave energy as waves interact, producing larger waves and destructive interference is the subtraction of wave energy as waves interact, producing smaller waves.

To find the answer, we need to know about the interference of waves.

What's the interference of waves?Interference of waves is the result of superposition of waves (transverse or longitudinal) at a certain place. Interference is of two typesConstructive interferenceConstructive interferenceDestructive interferenceHow are the constructive and destructive interference formed?When two waves are superimposed within the phase, then constructive interference pattern is formed.When two waves are superimposed with out of phase, destructive interference pattern is found.

Thus, we can conclude that the constructive interference is the addition of wave energy and destructive interference is the subtraction of wave energy.

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Related Questions

Complete the statement below.
In a neutralization reaction,
and hydroxide iOns react to form.

Answers

Answer:

In a neutralization reaction, hydronium and hydroxide ions react to form water.

Explanation:

Acids/Bases and how they interact:

A Bronsted-Lowry base is a substance that tends to bond with and "steal" a hydrogen ion, while an acid is a molecule containing a hydrogen ion that prefers to dissociate. Acids "give up" their hydrogen ions to water molecules in water, resulting in the formation of a hydronium ion. The pH of a given solution is determined by the amount of hydronium ions present.

A quick neutralization reaction takes place when a base is added to an acid because bases want to "take" the hydrogen. We have the ideal combination of bases that want to "take" the hydrogen ion and acids that want to "give up" the hydrogen ion, which allows them to neutralize one another. A conjugate base is created when hydrogen separates from an acid; having had its hydrogen torn from the complex, it may now receive a hydrogen (i.e., acts as a base). Once the base has a hydrogen, it behaves as a conjugate acid; it may then "lose" that hydrogen and behave as an acid.

Depending on which form the molecule favors, the acid's potency varies. The fact that hydrochloric acid (HCl) fully dissociates in aqueous solutions makes it a powerful acid:

HCl + H₂O -> Cl- + H₃O+

That is to say that the reaction equation strongly favours the right side.

Acetic acid, on the other hand, is a weak acid because only a small part of it dissociates:

CH₃COOH + H₂O <--> CH₃COO- + H₃O+

In contrast to the bulk of the chemical, which is shown on the left in the uncharged state, only a minor portion of acetic acid dissociates.

This brief explanation of acids and bases anthropomorphizes chemical substances as aware creatures with specific preferences for certain actions. These so-called "preferences" are, in reality, rough summaries of the relative stabilities of the compounds (acid vs. its conjugate base), mostly as a result of electrical processes.

Answer:

hydrogen and water other answer is wrong

Explanation:

Horizontal angulation is: Group of answer choices the side-to-side angulation. different when using the paralleling and bisecting techniques. correct when the central ray is parallel to the curvature of the arch. determined by the Stabe bite-block.

Answers

Option A is correct as horizontal angulation is the side- to -side angulation.

When the dental X-ray tube head is positioned and the center ray is pointed in a horizontal, or side-to-side, plane, this is referred to as horizontal angulation.

It remains the same when using the paralleling and bisecting techniques.

The central ray should not be directed parallel to the curvature of the arch.

Instead, it is pointed perpendicular to the curve of the tooth arch and film to prevent errors in x-ray interpretation.

A radiograph with "open" contacts is the result of proper horizontal angulation.

A radiograph with "overlapped" contacts results from incorrect horizontal angulation.

Hence, option A is correct

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On its own, a tow truck has a maximum acceleration of 5.0 m/s2. What will be its maximum acceleration when the truck is using a light horizontal chain to tow a bus of three times its own mass

Answers

The maximum acceleration will be 1.6m/s^2

Let a1 = 5.0m/s^2

the maximum acceleration of the truck alone. The force produced by the engine to accelerate the truck in this situation is

F = ma1

with m being the mass of the truck alone.

If we attach a bus of twice the mass of the truck, now the whole system (truck+bus) has a mass of (m+2m)=3m. And in this case, the force produced by the engine is

F = 3ma2

with a2 being the new acceleration.

The engine is always the same, so the force produced is still the same, so we can equalize F written in the first equation and in the second equation:

ma1 = 3ma2

and find a2, the new acceleration

a2 = ma1/3

a2 = 5/3 m/s^2

Therefore a2 = 1.6m/s^2

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explain about 3 pulley sytem and 4 pulley system and both of their uses​.

Answers

Answer:

Fixed pulleys are a very common pulley. These pulleys are secured to a single spot. ...

Movable Pulleys are yet another type of pulley. ...

Compound Pulley Systems are a combination of both movable and fixed pulleys.

Explanation:

there are three different types of pulleys:

Fixed pulleys are a very common pulley. These pulleys are secured to a single spot. ...

Movable Pulleys are yet another type of pulley. ...

Compound Pulley Systems are a combination of both movable and fixed pulleys.

Two students push on a crate to slide it across the floor. One student exerts a force of 5 N to the east, and the second exerts a force of 4 N to the south. What is the magnitude of the net force the students exert on the crate

Answers

The magnitude of the net force the students exert on the crate is 6.40 N.

We have to apply the Pythagorean theorem so we have:

F= [tex]\sqrt{5^{2}+4^{2} }[/tex]

=[tex]\sqrt{25+16}\\[/tex]

=[tex]\sqrt{41}[/tex]

Finally, we have:

F = 6.40 N

In mathematics, the Pythagorean theorem, or Pythagoras' theorem, is an essential relation in Euclidean geometry some of the three sides of a right triangle. It states that the vicinity of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other aspects.

Pythagorean theorem, the geometric theorem that the sum of the squares at the legs of a right triangle is identical to the rectangular at the hypotenuse (the facet opposite the right perspective) or, in familiar algebraic notation, a2 + b2 = c2.

A Pythagorean triple consists of three fantastic integers a, b, and c, such that a2 + b2 = c2. this sort of triple is normally written (a, b, c), and an instance is (3, four, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any wonderful integer.

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You are working on a laboratory device that includes a small sphere with a large electric charge Q. Because of this charged sphere, there is a strong electric field surrounding your device. Other researchers in your laboratory are complaining that your electric field is affecting their equipment. You think about how you can obtain the large electric field that you need close to the sphere but prohibit the field from reaching your colleagues. You decide to surround your device with a spherical transparent plastic shell. The nonconducting shell is given a uniform charge distribution. (a) The shell is placed so that the small sphere is at the exact center of the shell. Determine the charge that must be placed on the shell to completely eliminate the electric field outside of the shell. (Use any variable or symbol stated above as necessary.) 9 = x Your argument should be based on the use of Gauss's law to ensure the absence of an electric field outside the combination.

Answers

a)  q_shell = -Q ,  b)  q_shell = -Q

a) We can solve this exercise using Gauss's law

Ф = ∫ E. dA =  /ε₀

For this we use a Gaussian surface that takes advantage of the symmetry of the problem, we select a sphere where this force of the spherical plastic shell.

In this case, the electric field lines coincide with the radii of the sphere and the scalar product reduces to the algebraic product, the area of ​​the sphere

     A = 4 π r²

fi = E 4π r² = q_{int} /ε₀

apply this formula to our case, we have that the charge inside the Gaussian sphere is

   q_{int} = q_sphere + q_shell

the charge of the sphere is Q and the requirement is that there is no electric field outside the Gaussian sphere, for this, the net charge inside it must be zero

      0 = Q + q_shell

      q_shell = -Q

b) In Gauss's law, only the charge inside the Gaussian surface matters, not its position, therefore if the charge is not in the center the result remains the same.

     q_shell = -Q

Please check the attached attachment for the detailed answer.

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A driver in a 2,000 kg SUV moving at 15 m/s crashes into a stopped car, causing it to be propelled forward and the truck to be slowed to 10 m/s. What is the work done on the SUV by the stopped car

Answers

The work done on the SUV by the stopped car is .

Given:- A driver in a 2,000 kg SUV moving at 15 m/s crashes into a stopped car and the truck to be slowed to 10 m/s.

To Find:- We have to find the work done on the SUV by the stopped car.

By using the concept of speed it will be solved.

According to the problem,

The work done on the SUV by the stopped car is .

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A baseball rolls along a flat parking lot in a straight line at a constant speed of 3.8 m/s. How
far will the baseball roll in 15s?

Answers

This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

DATA:V = 3.8 m/sD = ¿?T = 15 sec

To calculate the distance, multiply the speed by the time.

We apply the following formula: d = v * t

We clear our data in the formula:

[tex]\bf{d=3.8\dfrac{m}{\not{s}}*15 \not{s} }[/tex]

[tex]\bf{d=57 \ m}[/tex]

The baseball in 15 seconds will roll a distance of 57 meters.

{ Pisces04 }

Who challenged the traditional belief that the orbits of the planets were spherical, showing that the five known planets moved around the sun in elliptical paths

Answers

Answer: Johannes Kepler challenged the traditional belief that, the orbits of the planets were spherical, showing that the five known planets moved around the sun in elliptical paths.

Explanation: To find the correct explanation, we have to know more about the History of planetary motion and the Kepler's laws.

What is the history of planetary motion?In B.C 350, Aristotle-Universe was composed of 55 concentric rotating sphere, centered in Earth.Aristarchus- Sun and stars were fixed, and the planets rotated about the sun.Ptolemy-Planets moves around the earth, in small circle.Copernicus-Retrograde motion of planets as observed from earth.Galileo-Motion of moons orbiting Jupiter.Kepler- Planet moves in an elliptical orbit.What is Kepler's law of planetary motion?First law: Planet moves in an elliptical orbit with sun as one of the foci.2nd law: Planets sweeps equal area in equal interval of time.3rd law: The square of the time period of motion is proportional to the cube of its mean radius.

Thus, from the above explanation we can conclude that, Johannes Kepler challenged the traditional belief that, the orbits of the planets were spherical, showing that the five known planets moved around the sun in elliptical paths.

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An object is placed 10 cm from a convex lens of focal length 20 cm. What is the lateral magnification of the object?.

Answers

Answer:Solution

verified

Verified by Toppr

Given:u=−10cm               f=20cm        (convex lens)

To find: v and image's nature.

Solution: From lens formula

v

1

u

1

=

f

1

v

1

+

10

1

=

20

1

Explanation:

Which astronomer's laws of motion helped to explain the heliocentric model

Answers

Answer:

( Galileo )discovered evidence to support Copernicus' heliocentric theory when he observed four moons in orbit around Jupiter

What can you say about the drop in potential energy (per unit mass or volume) of water traveling through either pipe? What can you say about the drop in potential energy (per unit mass or volume) of water traveling through either pipe? The drop is greater for pipe L. The drop is greater for pipe S. The drop is the same for both pipes.

Answers

The drop is the same for both pipes.

The analogy between water pressure, water flow, voltage, and current:

Both the pressure created by the pump at the top of the pipes and the pressure at the bottom of the pipes are equal (taken to be zero). Since the fluxes vary, the pressure drop across each pipe is also variable. This circuit is an analog of parallel resistors, where the voltage for each resistor is the same, but the currents vary if the resistances are not equal.

When water flows from a small pipe to a large pipe, the flow (measured, for instance, in gallons per minute) is the same in both pipes, because the amount of water entering one pipe must equal the amount leaving the other. Otherwise, water would build up in the pipes. For the same reason, circuit components connected in series have a constant total electric current. Water pressure and total electric potential (voltage) are comparable, and a pump is comparable to a battery. Similar to how electricity going through a resistor decreases in voltage, water traveling through pipes lose pressure. In a battery, chemical reactions cause charges to flow against the average due to the pump's utilization of mechanical work to increase the potential energy of the water.

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When the number of turns in a solenoid and its length are both doubled, the ratio of the magnitude of the new magnetic field inside to the magnitude of the original magnetic field inside is:

Answers

If you double the number of turns and double the length, the value N/L remains the same and hence the magnitude of the magnetic field stays the same.

A solenoid is a device comprised of a coil of wire, the housing and a moveable plunger (armature). When an electrical current is introduced, a magnetic field forms around the coil which draws the plunger in.

The magnitude of the magnetic field in an infinite (L>>R) solenoid, is proportional to:

I*N/L

Where

I = current

N = number of turns

L = length of wire

So, if you double the number of turns and double the length, the value N/L remains the same and hence the magnitude of the magnetic field stays the same.

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Need help asap pls
An astronaut is stuck floating motionless in space and wants to get back to
her spaceship. By throwing objects in the opposite direction, she accelerates
enough to get back to the spaceship. The astronaut is using Newton's
law of motion.
O A. fourth
OB. third
O C. second
OD. first

Answers

b. third

for every action there is a reaction*

A bus decreases its speed from 80km/h to 60km/h in 5 seconds. find the acceleration of the bus.

Answers

The acceleration of the bus is 1.1 m/s²

What is acceleration?

Acceleration is defined as the change in the velocity of an object with time.

Acceleration = change in velocity/timeChange in velocity = Final velocity - initial velocity

Change in velocity of the bus = 60 - 80

Change in velocity of the bus  = -20 km/h = -5.5 m/s

Time = 5 seconds

Acceleration = -5.5/5

Acceleration = 1.1 m/s²

In conclusion, acceleration is the rate of change of velocity with time.

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Find the pressure exerted on the floor by a 100N box whose bottom area is 40cm x
50cm.

Answers

Answer:

Pressure exerted = 500 Pa

Explanation:

The formula for pressure is as follows:

[tex]Pressure = \frac{Force \space\ applied}{Area}[/tex]

In this case,

Force applied = 100N

Area = 40cm × 50cm = 2000cm² = 2000 × 10⁻⁴ = 0.2m²

Substituting these values into the formula:

Pressure = [tex]\frac{100}{0.2}[/tex]

⇒ Pressure = 500 Pa

Answer:

500Pa

Explanation:

Pressure = Force / Area where area is in [tex]m^{2}[/tex].

Firstly, lets convert both area dimensions into metrers.

40cm = 40/100 m = 0.4m

50cm = 50/100 m = 0.5m

Area of Bottom area of box = 0.4m x 0.5m = [tex]0.2m^{2}[/tex]

Pressure = [tex]\frac{100N}{0.2m^{2} }[/tex]

= 500Pa

If you run around a circular track with a radius of 10m, what is the displacement after 3 full laps back to the start line?

Answers

Displacement will be zero.

What is displacement and how is it different from distance?

Displacement:

It is the shortest distance between an object's beginning position and ending position.The quantity is a vector.It may be zero, positive, or negative.Displacement may be greater than or equal to distance.

In the given question, we start from one point and finish at the same point around the circular track. Therefore there is no distance between the initial and final points because they are the same. That's why the displacement is zero.

Distance:

It is the actual path or distance that an object takes to go from its starting point to its finishing point.The quantity is a scalar one.It cannot be 0 or negative; it must be positive. Displacement and distance may be equal.

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If the satellite has a mass of 3900 kg , a radius of 4.3 m , and the rockets each add a mass of 210 kg , what is the required steady force of each rocket if the satellite is to reach 30 rpm in 5.4 min , starting from rest?

Answers

Answer:

The required steady force of each rocket is 28.79 N

Explanation:

mass of the satellite, M=3900 kg

radius, r=4.3 m

mass of rocket, m=210 kg

time, t=5.4 min

Moment of Inertia:

I = 1/2 (Mr^2) + 4mr^2

I = 1/2 ( 3900* (4.3)^2) + 4 (210)*(4.3)^2

I = 51587.1 kg m^2

the angular acceleration is:

a= w/t

here w= 2*π*30

so,

a= 2*π*30 / 5.4* 3600

a=0.0096 rad/ s^2

the Torque becomes:

T=I*a = 4r*F

( 51587.1 )*(0.0096) = 4*4.3* F

F= 28.79 N

the required steady force of each rocket is 28.79 N

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true or false Immediately after the switch is closed, there is no current flowing through the resistor.

Answers

True. Immediately after the switch is closed, current only flows through the capacitor and not through the resistor. This is because the resistor offers resistance to the current flow while the capacitor acts as a short in the circuit.

What is a RC circuit?

Consider the circuit diagram shown below. This circuit is known as an RC circuit. In an RC circuit:

The capacitor C is connected in parallel with resistor R and potential V.When the switch is kept open, i.e. no potential is applied to the circuit for an extended period of time, the charge stored in the capacitor dissipates.This leads to the current to stop flowing thorough the other components of the circuit.Thus, when potential is applied across the capacitor (uncharged), the capacitor initially behaves as a closed wire and offers no resistance as the current flows through it whilst charging it.Once the capacitor has been charged for a long period of time, it acts as a break in the circuit wherein no current can flow through it.Now, when a switch is placed in the circuit, after the switch has been kept open for a long time, closing it causes the relative current and potential in the circuit to depend upon the state of charge in the capacitor at that instant.

Supposing that the capacitor has been kept uncharged for a long period of time, at this instant when the switch is closed, only the current flows through the capacitor and not through the resistor.

This is because the resistor offers resistance to current flow while the capacitor acts as a short in the circuit.

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8 The diagram shows four identical spheres placed between two wooden blocks on a ruler.
4
A
sphere
bo
0 5
What is the diameter of one sphere?
1.0 cm
B 2.0 cm

10
16
C 3.0cm
wooden block
15 cm
D 4.0cm
9
A length of cotton thread is measured between two points on a ruler as
shown in the figure below
When the length of the thread was wound closely around a pen, it goes round
six times as shown in the second figure below.

Answers

The diameter of the sphere is 2cm.

How to calculate the diameter?

From the diagram, the first sphere on the ruler is at 4cn and the last sphere is at 12cm.

Therefore, the length will be:

= 12 - 4.

= 8cm

The diameter of one sphere will be:

= Length / 4

= 8/4

= 2

Therefore, the diameter of the sphere is 2cm.

Note that the second question wasn't found online.

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Consider two pairs of protons, one pair moving toward each other at a speed of 1000 km/s and the other at a speed of 10 km/s. Which pair of protons will get closer together before they repel each other

Answers

The pair of protons with velocity 1000 km/s will get closer together before they repel each other.

To find the correct statement, we need to know about the motion of protons.

What's proton?Proton is a possibility charged subatomic particle.It resides within the nucleus.What's happened when a pair of protons moves towards each other?As a pair of protons are similarly charged, so they will be repelled when they are approach very close.Also, the closeness of approaching depends directly on the kinetic energy of these protons.So, more the velocity of the protons leads to more kinetic energy and more the closeness between them.

Thus, we can conclude that the pair of protons with velocity 1000 km/s will get closer together before they repel each other.

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Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density n = 910 wires/m and a current per wire of IL = 0.17 A in the +z direction. The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.17 A in the -z direction.
a) Calculate the y-components of the net magnetic field in the following places: x1 = -15 cm, x2 = 6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
b) Suppose the above configuration of currents is unchanged except that the direction of the current IR is reversed so that now IR also flows in the +z direction. (The magnitude remains the same.) Calculate the y-components of the net magnetic field at the same positions as in part a).
B(x1)y = T
B(x2)y = T
B(x3)y = T
c) Return to the configuration of part a). Suppose you want to have the region 0 < x < a able to confine electrons (qe- = -1.60 x 10-19 C, me- = 9.11 x 10-31 kg) that have been accelerated from rest through a 66 V electrostatic potential. If the electrons are to be stacked in circular orbits parallel to the x-z plane with centers on the plane x = a/2, what is the minimum current per wire required if IL and IR are equal in magnitude but opposite in direction?
IL = A

Answers

Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density of n = 910 wires/m and current per wire of IL = 0.14 A in the +zdirection.

The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.14 A in the -z-direction.

(a) Calculate the y-components of the net magnetic field in the following places:

x1 = -15 cm, x2 =6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)

B(x1)y = T

B(x2)y = T

B(x3)y = T

Please check the attached file for a detailed answer.

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A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Draw the image formation in this case.

Answers

Answer:

It is given that the image is formed at a distance of 50cm from the lens. And since the image is real, v = +50cm. This means that u = -50cm. Therefore, the needle must be placed at a distance of 50cm from the lens.

Explanation:

Which type of light is best for checking the security features of a california issued id or driver license?.

Answers

The type of light which best for checking the security features of a California issued id or driver license is a UV light.

What is a UV light?

This is referred to as an ultraviolet light and is an electromagnetic radiation which glows in the dark.

This is why it is referred to as blacklight image and helps to see the details of the ID under any condition.

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Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established. Please select the best answer from the choices provided T F

Answers

The statement 'establishing a high critical value in a statistical test is associated with more confidence' is TRUE.

What is statistical significance?

The statistical significance is a arbitrary value used to indicate that data collected can be used to confirm (or reject) my working hypothesis.

The most widely used value to measure the statistical significance is the p threshold.

In conclusion, the statement 'Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established' is TRUE.

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Answer:

The answer is F or false

Explanation:

correct edge 2023

An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 j of gravitational potential energy. how high did the hiker climb? round the answer to the nearest hundred. meters

Answers

Answer: An 80 kg hiker climbs to the top of a tall hill and builds up 470000J of gravitational potential energy. With this energy, he can climb up to 600m of Hight.

Explanation: To find the answer, we need to know about the Gravitational potential energy.

What is the gravitational potential energy?Gravitational potential energy can be defined as, the potential energy associated with a gravitational field.It has an expression,

                    [tex]U=mgh[/tex]

where,

U is the gravitational potential energy, m is the mass of the body, g is the acceleration due to gravity and h is the height.

How to solve the problem?As we know that the expression of height from the expression of gravitational potential energy as,

                      [tex]h=U/mg[/tex]

We have, [tex]m=80kg[/tex] , [tex]U=470000J[/tex] and [tex]g=9.8 m/s^{2}[/tex] .Substituting these into the equation, we get, height as,

                        [tex]h=470000/(80*9.8)=599.98=600 m[/tex]

Thus, from the above calculation, we can conclude that, he can climb up to 600m of Hight.

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Answer: 600 m

Explanation: Got correct on Edge

Moving a charge from point A, where the potential is 400 V, to point B, where the potential is 120 V, takes 4.3×10−4 J of work

What is the value of the charge?
Express your answer with the appropriate units.

Answers

The charge is obtained as 1.5 * 10^-5 C.

What is potential?

The electric potential is the work done in moving a unit charge from one point to another.

Now we have;

W = -QdV

W = Work done in joules

Q = charge

dV = voltage change

Hence;

4.3×10−4 =- Q( 120 - 400)

Q = 4.3×10−4/280

Q = 1.5 * 10^-5 C

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A cat with a mass of 5 kg sits on a branch that is 26 m off the ground. What is
its gravitational potential energy? The acceleration of gravity is 9.8 m/s².

Answers

Answer:

1274 J

Explanation:

PE = m g h

    = 5 * 9.8 * 26 = 1274 J

A wire of a given material has an electric field of 0.100 mV/m when a potential is applied. The wire has 8.49 x 1028 conduction electrons per cubic meter and a mean free time between collisions of 2.50 x 10-14 s. What is the uniform current density in the wire

Answers

The uniform current density in the wire is 5.43 x 10²⁷ A/m².

Current density in the wire

The uniform current density in the wire is calculated as follows;

J = total current / total area

The given parameters:

Conduction of the wire = 8.49 x 10²⁸ e/m²time, t = 2.5 x 10⁻¹⁴ s

[tex]J = \frac{I}{A} = \frac{Q}{At} \\\\J = \frac{8.49 \times 10^{28}e/m^3 \ \times \ 1.6 \times 10^{-19} \ C/e}{2.5 \times 10^{-14} \ s \ \times ( 0.1 \times 10^{-3} \ V/m)} \\\\J = 5.43 \times 10^{27} \ A/m^2[/tex]

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SOMEONE PLEASE HELP
A sealed pot is allowed to cool off. This is an example of
1)increasing energy of an open system.
2)decreasing energy of an open system.
3)increasing energy of a closed system.
4)decreasing energy of a closed system.

Answers

Answer:

4 decreasing energy of a closed system

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