Indium has a tetragonal unit cell for which the a and c lattice parameters are 0.459 and 0.495 nm, respectively. (a) If the atomic packing factor and atomic radius are 0.693 and 0.1625 nm, respectively, determine the number of atoms in each unit cell. (b) The atomic weight of indium is 114.82 g/mol; compute its theoretical density. (a) Enter your answer for part (a) in accordance to the question statement atoms/unit cell (b) Enter your answer for part (b) in accordance to the question statement g/cm3

Answer:

A) 2

Explanation:

Answer:

2, i got it right thanks to the other user :) <3

Explanation:

Answer:

The end products cannot be changed back in their original forms

Explanation:

Answer:

the first one

Explanation:

Answer:

a. without completing 2p stuff...electrons cant go to 3s. the correct configuration is

1s2, 2s2, 2p6, 3s1

b. after 4s, 3d comes not 4d. the correct configuration is 1s2, 2s2, 2p6, 3s2, 4s2, 3d6

c. after 4s, it is 3d and then 4p the correct configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6.

Hope it helps you ｡◕‿◕｡

Answer:

It causes erosion of the land and stones.

Explanation:

if the objects such as stones etc are present in the way of stream so the stones are eroded due to its fast flowing due to sloppy nature. If the stream is flat  then it little disturb the things present in its way because of its lower speed. If more rainfall occur the streams flows in higher speed and destroy everything that comes in its way and also affected the plains.

Answer:this is correct

Explanation:

Answer:

See explanation

Explanation:

For reaction 3;

Molecular equation

2Na3PO4(aq) + 3CuSO4(aq) -----> 3Na2SO4(aq) + Cu3(PO4)2(s)

Complete ionic equation;

6Na^+(aq) + 2PO4^3-(aq) + 3Cu^2+(aq) + 3SO4^2-(aq) ------> 6Na^+(aq) + 3SO4^2-(aq) + Cu3(PO4)2(s)

Net ionic equation;

3Cu^2+(aq) + 2PO4^3-(aq)  -----> Cu3(PO4)2(s)

Reaction 14

Molecular equation

2FeCl3(aq) + 6NH4OH(aq) ------>2Fe(OH)3(s) + 6NH4Cl

Complete ionic equation:

2Fe^2+(aq) + 6Cl^-(aq) + 6NH4^+(aq) + 6OH^-(aq) -----> 2Fe(OH)3(s) + 6NH4^+(aq) +  6Cl^-(aq)

Net ionic equation;

2Fe^2+(aq) +  6OH^-(aq)  -----> 2Fe(OH)3(s)

2.

Al(s) + 3Ag(CH3COO)(aq) ----->Al(CH3COO)3(aq) + 3Ag(s)

Zn(NO3)2(aq) +2LiCl(aq) ------> 2LiNO3(aq) + ZnCl2(aq)

2HBr(aq) + MgSO3(s) ------>MgBr2(aq) + H2O(l) + SO2(g)

RbOH(aq) + HClO4(aq) -----> RbClO4(aq) + H2O(l)

3Sn(s) + 4H3PO4(aq)----->Sn3(PO4)4(aq) + 6H2(g)

3Li2CrO4(aq) + 2AuI3(aq) -------> 6LiI(aq) + Au2(CrO4)3(s)

Answer:

Explanation:

it stays the same because the seeds or whatever in the bag was still the pop corn just not fully devloped

Answer:

D

Explanation:

i have no explanation ;-;

I checked it with my quiz doe UwU[tex]e[/tex]

Answer:

Zero

Explanation:

The complete reaction for this is as follows -

HBr + NaOH = NaBr + H2O

1 mole of NaOH reacts with 1 mole of HBr

m(HBr) = 57.4g and M(HBr) = 80.9g/mol

m(NaOH) = 16g and M(NaOH) = 40g/mol

Number of moles = m/M

Substituting the given values we get -

n(HBr) = 57.4 g/80.9 g/mol = 0.709

n(NaOH) = 16 g/40 g/mol = 0.4

n(H2O) = n(NaOH) = 0.40 mol

According to balanced equation

40 gram of NaOH reacts with 81 grams of HBr

41 gram of NaOH will react with 81/40 * 41 = 83.025 gram of HBr

We have only 57.4 g of HBr only hence, 0 HBr will be left.

its true

Potential energy is the stored or latent energy in an object at rest. It’s fundamental to many physics-related concepts because its laws hold true on any level, from the planetary to the atomic level. The potential energy of an object is measurable.

Answer:

Atom 1: Potassium (K)

Atom 2: Same thing

Explanation:

Potassium has an atomic number of 19 and mass number of 39.0983.

Answer:

See explanation

Explanation:

You see, all these materials we see around us are composed of elements. These elements are unique in their own ways!

Some of them are able to attract tiny negative particles called electrons close to their positive interior called the nucleus. This positive interior is so designated because it contains a positive particle called protons which attract these electrons.

Now, elements are broadly divided into metals and non metals. Protons in metallic elements are less able to pull electrons than protons in non metallic elements. As a result of this, non metals are mostly electronegative because they pull electrons towards themselves while metals are mostly electropositive because they give away their electrons easily. Fork is composed of metallic elements.

Since metals give away electrons easily, they can conduct electricity since electrons are the same charge carriers in electric circuits.

Also, in elements, there is a conduction band and a valence band. Electrons  occupy the valence band but also move into the conduction band. The gap between the valence band and the conduction band in nonmetals is large hence they do not conduct electricity. The gap between the valence band and the conduction band in metals is minimal hence metals conduct electricity.

So if you stick that fork into a toaster, electrons can flow right through the toaster circuit into your body and cause you to be electrocuted.

1s22s22p63s1. That's the ans

Answer:

Im pretty sure its B

Sorry if Im wrong

Explanation:

Have a wonderful day!!!<3

Answer:

The only answer that could apply to a gas is A

Explanation:

Answer:

269g

Explanation:

hope this helps you

A gray element that borders on the zigzag line of the periodic table, is ductile and malleable, but is not a very good conductor of heat or electricity is known as metalloid. The correct option is option C.

In chemistry, a periodic table is an orderly arrangement of each of the chemical elements along order of atomic number is, the total amount of protons inside the atomic nucleus.

Whenever the chemical elements stand grouped in this manner, there is a recurrent pattern in their characteristics known as the "periodic law," in which elements within a single column (group) exhibit comparable qualities. A gray element that borders on the zigzag line of the periodic table, is ductile and malleable, but is not a very good conductor of heat or electricity is known as metalloid.

Therefore, the correct option is option C.

To learn more about  periodic table, here:

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The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between freezing point depression and molality. With this last one, is possible to calculate molar mass or molar weight of a compound.

Freezing Point Depression occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

Molality or molal concentration is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

[tex]m=\frac{moles(solute)}{kg(solvent)}[/tex]

Freezing point depression and molal are related as the following:

[tex]\Delta T_{f}=K_{f}.m[/tex]

where

[tex]\Delta T_{f}[/tex] is freezing point depression of solution

[tex]K_{f}[/tex] is molal freezing point depression constant

m is molality

Now, to determine molar mass, first, find molality of the mixture:

[tex]\Delta T_{f}=K_{f}.m[/tex]

[tex]m=\frac{\Delta T_{f}}{K_{f}}[/tex]

For benzene, constant is 5.12°C/molal. Then

[tex]m=\frac{3.5}{5.12}[/tex]

m = 0.683 molal

Second, knowing the relationship between molal and moles of solute, determine the last one:

[tex]m=\frac{moles(solute)}{kg(solvent)}[/tex]

[tex]mol(solute)=m.kg(solvent)[/tex]

mol(solute) = 0.683(0.065)

mol(solute) = 0.044 mol

The definition for Molar mass is the mass in grams of 1 mol of substance:

[tex]n(moles)=\frac{m(g)}{MM(g/mol)}[/tex]

[tex]MM=\frac{m}{n}[/tex]

In the mixture, there are 0.044 moles of X, so its molecular mass is

[tex]MM=\frac{2.1}{0.044}[/tex]

MM = 47.30 g/mol

The molecular compound X has molecular mass of 47.30 g/mol.

Answer:

The minimum number of boxes of pencils to be ordered is 630 boxes.

Explanation:

Since a pupil uses averagely 9.3 pencils

and a box contains 12 pencils,

the school enrollment is also 812

school's enrollment x average use of pencil per student

__________________________________________

            number of pencils in a box

812 x 9.3 = 7551.6

7551.6 /12 = 629.3

Having a total number of 630 boxes of pencils to be ordered.

The final temperature : T₂=209.86 K = -63.1 °C

Given

V₁=568 cm³

T₁=25° C+ 273 = 298 K

V₂=400 cm³

Required

Final temperature(T2)

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

T₂=(V₂.T₁)/V₁

T₂=(400.298)/568

T₂=209.86 K = -63.1 °C

Answer:

Remove some water from the jar before adding the mixture.

Explanation:

She will speed it up when removing some water it will stay dry and not be sticky to separate the two ingredients

Answer: Remove a bit of water from the jar

Explanation:

Answer:

4

Explanation:

the one you ARE ON

Answer:

25.8 g/dL

Explanation:

A chemist prepares a solution of aluminum sulfate by weighing out 116.0 g of aluminum sulfate into a 450. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's aluminum sulfate solution. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Step 2: Convert "V" to dL

We will use the following conversion factors.

450. mL × 1 L/1000 mL × 10 dL/1 L = 4.50 dL

Step 3: Calculate the concentration (C) of aluminum sulfate if g/dL

We will use the following expression.

C = m/V = 116.0 g/4.50 dL = 25.8 g/dL

Answer:

1 mole of platinum (Pt).

Explanation:

From the question given above, the following data were obtained:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Number of mole of platinum =?

To obtain the number of mole of platinum present in the compound, we shall determine the empirical formula for the compound. The empirical formula for the compound can be obtained as follow:

Pt = 117.4 g

C = 28.91 g

N = 33.71 g

Divide by their molar mass

Pt = 117.4 /195 = 0.602

C = 28.91 /12 = 2.409

N = 33.71 /14 = 2.408

Divide by the smallest

Pt = 0.602 /0.602 = 1

C = 2.409 /0.602 = 4

N = 2.408 / 0.602 = 4

Therefore, the empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the empirical formula for the compound (i.e Pt(CN)₄) we can see that the compound contains 1 mole of platinum (Pt).

Answer:

a) the increase in internal energy is 3211.78 J

b) dU = 3854.14 J

c) dU[tex]_{T}[/tex] = 1927.06 J

Explanation:

Given the data in question;

Foe a diatomic gas, the degree of freedom are as follow;

lets consider the positional degree of freedom

transitional df = 3

rotational df = 2

vibrational ff = 1

now, the internal energy given by;

U = Nf × 1/2NKT = Nf×1/2×nRT

where Nf is the number of degree of freedom

N is Number of atoms or molecules

n = number of molecules

L is Boltzmann constant

R is universal gas constant

so change in internal energy , change in T is given by

dU =  Nf × 1/2 × nT dT

n = 2.37 moles

dT = 65.2 K

R = 8.314 J/mol.J

a)

Find the increase in internal energy if only translational and rotational motions are possible

since rotational and transitional motion are involved ;

Nf = 3(trasitional) + 2(rotational) = 5

so,

dU = 5 × 1/2  × nRdT

we substitute

dU = 5 × 0.5  × 2.37 × 8.314 × 65.2

dU = 3211.78 J

Therefore, the increase in internal energy is 3211.78 J

b)

Find the increase in internal energy if translational, rotational, and vibrational motions are possible.

Nf = 3 + 2 + 1 = 6

dU = 6 × 1/2  × nRdT

dU = 6 × 0.5  × 2.37 × 8.314× 65.2

dU = 3854.14 J

c)  

How much of the energy calculated in (a) and (b) is translational kinetic energy?

dU[tex]_{T}[/tex] = 3 × 0.5  × 2.37 × 8.314 × 65.2

dU[tex]_{T}[/tex] = 1927.06 J

The question is incomplete. The complete question is :

A 100.0 mL flask is filled with 0.065 moles of A and allowed to react to form B according to the reaction below. The following experimental data are obtained for the amount of A as the reaction proceeds. What is the average rate of appearance of B in units of M/s between t = 10 min. and t = 30 min.? Assume that the volume of the flask is constant. A(g) → B(g)

Time 0.0 10.0 20.0 30.0 40.0

Moles of A 0.065 0.051 0.042 0.036 0.031

Solution :

Consider the following reaction as follows :

[tex]$A \rightarrow B$[/tex]

The experiment data is given as follows :

Time (min) :   0.0        10.0       20.0        30.0       40.0

Moles of A :  0.065    0.051    0.042      0.036     0.031

According to the rate of reaction concept, the rate can be expressed as a consumption of the reactant and formation of the product as follows :

Average rate : [tex]$= -\frac{d[A]}{dt} = \frac{d[B]}{dt} $[/tex]

Now we have to calculate the average rate between 10.0 to 30.0 min w.r.t. A as follows :

Rate  [tex]$=-\frac{(0.051-0.036) mol \times \frac{1}{0.1 \ L}}{(30.0-10.0) mol \times \frac{60 \ s}{1 \ min}}$[/tex]

         [tex]$=\frac{0.15 \ M}{20 \ min \times \frac{60 \ s}{1 \ min}}$[/tex]

         [tex]$= 1.25 \times 10^{-4 }\ M/s$[/tex]

Therefore, the rate = [tex]$= 1.3 \times 10^{-4 }\ M/s$[/tex]

A 100.0-mL flask is filled with 0.065 moles of A and allowed to react to form B. Between 10.0 min and 30.0 min, the average rate of appearance of B is 1.3 × 10⁻⁴ M/s.

The rate of reaction is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time.

A(g) → B(g)

To calculate the rate of disappearance of A (rA) between 10.0 min and 30.0 min, we will use the following expression.

rA = -ΔnA / V. Δt = -(0.036 mol - 0.051 mol)/ (0.1000 L) (30.0 min - 10.0 min)

rA = 7.5 × 10⁻³ M/min

where,

The molar ratio of A to B is 1:1.

7.5 × 10⁻³ mol A/L.min × 1 mol B/1 mol A = 7.5 × 10⁻³ mol B/L.min

We will use the conversion factor 1 min = 60 s.

7.5 × 10⁻³ M/min × 1 min/60 s = 1.3 × 10⁻⁴ M/s

A 100.0-mL flask is filled with 0.065 moles of A and allowed to react to form B. Between 10.0 min and 30.0 min, the average rate of appearance of B is 1.3 × 10⁻⁴ M/s.

The question is incomplete. The complete question is:

A 100.0 mL flask is filled with 0.065 moles of A and allowed to react to form B according to the reaction below. The following experimental data are obtained for the amount of A as the reaction proceeds. What is the average rate of appearance of B in units of M/s between t = 10 min. and t = 30 min.? Assume that the volume of the flask is constant. A(g) → B(g)

Time (min)     0.0          10.0          20.0           30.0          40.0

Moles of A   0.065     0.051         0.042          0.036       0.031

Learn more about rates of reaction here: https://brainly.com/question/24795637

Answer:

b. A mole of chlorine gas contains 2 (6.02 * 10^23 ) atoms.

c. A mole of carbon dioxide contains two moles of oxygen molecules (CO2)

e. A mole consists of the number of particles in exactly 12g of naturally occurring carbon.

Explanation:

A mole of oxygen gas (O2) contains 2 (6.02 * 10^23) atoms

A mole of Ammonia gas (NH3) has a mass of 17.031g/mol

A mole is defined as the unit used in measurement of the amount of substances in the International System of Units.

A mole was initially defined as the number of particles in exactly 12g of naturally occurring carbon.

Therefore, options b, c and e are correct

Answer:

D. A water molecule

Explanation:

Answer:

A two energy levels K and L

B halogen are present in group 17

C in same group elements have same valence electrons

Explanation:

Answer:

11267.61 Kg/m³.

Explanation:

From the question given above, the following data were obtained:

Mass of lead = 32 g

Volume of lead = 2.84 cm³

Density of lead =.?

Next, we shall convert 32 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

32 g = 32 g × 1 Kg / 1000 g

32 g = 0.032 Kg

Next, we shall convert 2.84 cm³ to m³. This can be obtained as follow:

1 cm³ = 10¯⁶ m³

Therefore,

2.84 cm³ = 2.84 cm³ × 10¯⁶ m³ / 1 cm³

2.84 cm³ = 2.84×10¯⁶ m³

Finally, we shall determine the density of the piece of lead. This can be obtained as follow:

Mass of lead = 0.032 Kg

Volume of lead = 2.84×10¯⁶ m³

Density of lead =.?

Density = mass / volume

Density of lead = 0.032 / 2.84×10¯⁶

Density of lead = 11267.61 Kg/m³