In an MO (molecular orbital) scheme for CH4, Group of answer choices ..there are three equivalent bonding MOs of equal energy and one unique bonding MO. ..there are four equivalent bonding MOs of equal energy. ..there are two sets of doubly degenerate bonding MOs. ..there are four bonding MOs, each of different energy.

Answer:

In advance

middle

lower

Explanation:

These are the safety precautions needed when carrying out duties in the fume hood.

When planning and preparing to work in a fume hood (a locally designed area to reduce exposure to hazardous fumes). It is advisable to make all equipment readily available at your disposal in advance to reduce and minimize the raising and lowering of the hood sash at intervals.

It is also pertinent to understand that working in the middle of the work surface helps to promote the movement of air and keeps the area neat and tidy.

However, if any case where there is a need to get a new tool or equipment during the process of working in a fume hood, it is advisable to lower the sash at that point in time.

Answer:

C)Grassland biomes contain mostly grasses.

Explanation:

The main differences between a savanna biome and a grassland is that grasslands biomes contain mostly grasses.

Savanna are made up of both grasses and shrubs.

Answer:

B

Explanation:

Answer:

Chemical,electrical,light,heat

Answer:

chemical electrical, light, heatExplanation:

Answer:

B.nitrogen

Explanation:

Nitrogen is a gas at room temperature.

Answer:

D. 14

Explanation:

This is a Carbon Atom which has an atomic number of 14. 6+8=14

Answer:

In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M

Explanation:

In each rinse cycle, the dilution that you are doing of the solution is from 1.00mL to 10.00mL, that is a dilution of 10

In the first rinse the concentration must be of 0.9M  10 = 0.09M

2nd = 0.009M

3rd = 0.0009M

4th = 0.00009M

5th = 0.000009M →

Answer:

8

Explanation:

Answer:

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Explanation:

Answer:

(a) 1s; has one orbital

(b) 4d; has five orbitals

(c) 3p; has three orbitals

(d) n=3 has nine orbitals

Explanation:

Electrons in an atom are always in constant motion, making it hard to predict there exact position. However, the most probable locations electrons can be be found are described with the terms shells, subshells and orbitals. A shell contains subshells and orbitals are found within subshells. The shells are given names such as K, L, M, N, which correspond to the principal quantum numbers, n = 1, 2, 3, and 4 respectively. There are 4 major types of subshells that can be found in a shell. They are named as s, p, d, f. Each subshell is composed of several orbitals.

a. 1s; the s subshell has only one orbital. Therefore, the 1s subshell has one orbital

b. 4d; the d subshell has five orbitals. Therefore, the 4d subshell has five orbitals

c. 3p; the p subshell has three orbitals. Therefore, the 3d subshell has  three orbitals

d. n = 3; the shell with n = 3 has the following subshells, 3s, 3p, 3d.the number of orbitals will be 1 + 3 + 5 = 9 orbitals. Therefore, the number of orbitals in n = 3 is nine orbitals

Answer:

See explanation

Explanation:

Poor irrigation: When too much water is used during irrigation or water is inefficiently used for irrigation purposes, there could be an overall decrease in the availability of water resources leading to vegetation loss and desertification. Therefore, water resources should be properly managed to avoid desertification.

Overgrazing: Overgrazing refers to excessive grazing of a grassland. When livestock are allowed to overgraze on a particular area, there is vegetation loss and consequent desertification. Grazing practices should be organized in such a way that grasslands are not subjected to overgrazing.

Poor tillage practices: Poor tillage practices such as continuous cropping makes the soil more porous and exposes the soil to erosion. There may be vegetation loss and finally desertification. Sustainable tillage practices such as shifting cultivation and bush fallowing should be adopted.

Answer:

a pressure of 10 Nm -2 is equal to ?​

1 atmosphere

Explanation:

A pressure of 10 N/m² is equal to 10 Pa and 9.86x10⁻⁵ atm.

Pressure (P) is the measure of the perpendicular force (F) applied to an object's surface area (A):

[tex] P = \frac{F}{A} [/tex]                          

Hence, the unit of the pressure is Newton per square meter (N/m²), which is defined as Pascal (Pa).

[tex] 1 Pa = 1 N/m^{2} [/tex]

Also, we have that 1 atm is equal to 101325 Pa, so:

[tex] P = 1 Pa*\frac{1 atm}{101325 Pa} =9.86 \cdot 10^{-6} atm [/tex]

So, in a pressure of 10 N/m² we have:

[tex] P = 10 N/m^{2} = 10 Pa = 9.86 \cdot 10^{-5} atm [/tex]

Therefore, a pressure of 10 N/m² is equal to 10 Pa and 9.86x10⁻⁵ atm.

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Answer:

i = 2.79

Explanation:

The excersise talks about the colligative property, freezing point depression.

Formula to calculate the freezing point of a solution is:

Freezing point of pure solvent - Freezing point of solution = m . Kf . i

Let's replace data given. (i = Van't Hoff factor, numbers of ions dissolved in solution)

48.1°C - 44°C = 0.15 m . 9.78°C/m . i

4.1°C / (0.15 m . 9.78°C/m) = i

i = 2.79

In this case, numbers of ions dissolved can decrease the freezing point of a solution, which is always lower than pure solvent.

Answer:

Circulatory

Explanation:

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

We have that for the Question "How many mg of mupirocin powder are required? "

It can be said that

From the question we are told

a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointment by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

Weight of standard package = 22g

mupirocin = 2%

Therefore,

Weight of mupirocin = [tex]\frac{2}{100}*22[/tex]

[tex]=0.44g[/tex]

Let amount of mupirocin to be added to prepare 3% w/w mupirocin ointment = X

Therefore,

Total weight of ointment = [tex](22 + X)g[/tex]

amount of mupirocin = [tex](0.44+X)g[/tex]

% of mupirocin in ointment = [tex]3\%[/tex]

therefore,

[tex]\frac{3}{100} = \frac{0.44+X}{22+X}\\\\66+3X = 44+100X\\\\X = 0.2268g[/tex]

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Answer:

TI c2h3o2 2 Name

Titanium(II) Acetate Ti(C2H3O2)2 Molecular Weight

Explanation:

Answer:

It replaces Br in MgBr2.

Explanation:

Hello!

In this case, when carrying out double displacement reactions, we need to take into account that cations and anions are switched; thus, when LiCl and MgBr2 react, since Li and Mg are the cations, Br and Cl switch as shown below:

[tex]2LiCl+MgBr_2\rightarrow 2LiBr+MgCl_2[/tex]

Thus, chlorine replace Br in MgBr2 to form MgCl2.

Best regards!

Answer:

V₂ = 104.76 mL

Explanation:

Given data:

Initial volume = 100.0 mL

Initial temperature = 21°C (21 + 273.15 K = 294.15 K)

Final temperature = 35°C (35 + 273.15 K = 308.15 k)

Final volume = ?

Solution:

Charles Law:

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ =100.0 mL × 308.15 K / 294.15 K

V₂ = 30815 mL.K /294.15 K

V₂ = 104.76 mL

Answer:

1. 1.62×10¹¹ nm

2. 4.8×10¹⁴ Hz

Explanation:

1. Determination of the wavelength.

We'll begin by converting 1.85 MHz to Hz. This can be obtained as follow:

1 MHz = 10⁶ Hz

Therefore,

1.85 MHz = 1.85 MHz × 10⁶ Hz / 1 MHz

1.85 MHz = 1.85×10⁶ Hz

Next, we shall determine the wavelength of the electromagnetic radiation. This can be obtained as follow:

Frequency (f) = 1.85×10⁶ Hz

Velocity of electromagnetic radiation (v) = 3×10⁸ m/s

Wavelength (λ) =?

v = λf

3×10⁸ = λ × 1.85×10⁶

Divide both side by 1.85×10⁶

λ = 3×10⁸ / 1.85×10⁶

λ = 162.16 m

Finally, we shall convert 162.16 m to nm. This can be obtained as follow:

1 m = 10⁹ nm

Therefore,

162.16 m = 162.16 m × 10⁹ nm / 1 m

162.16 m = 1.62×10¹¹ nm

Thus, the wavelength of the electromagnetic radiation is 1.62×10¹¹ nm

2. Determination of the frequency.

We'll begin by converting 625 nm to m. This can be obtained as follow:

1 nm = 10¯⁹ m

Therefore,

625 nm = 625 nm × 10¯⁹ m / 1 nm

625 nm = 6.25×10¯⁷ m

Finally, we shall determine the frequency the visible light as follow:

Wavelength (λ) = 6.25×10¯⁷ m

Velocity of light (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 6.25×10¯⁷ × f

Divide both side by 6.25×10¯⁷

f = 3×10⁸ / 6.25× 10¯⁷

f = 4.8×10¹⁴ Hz

Therefore, the frequency of the visible light is 4.8×10¹⁴ Hz

Answer:

yes...

Explanation:

wha

Answer:

See explanation and images attached

Explanation:

The addition of HBr to the diene could yield either a kinetic or thermodynamic product. The kinetic product is formed faster while the thermodynamic product is more stable and formed at equilibrium.

Recall that the alkene that is surrounded by more alkyl groups is more stable. Also, the carbocation undergoes rearrangement to form a more stable carbocation intermediate that ultimately leads to the formation of the thermodynamic (1,4) product which predominates.

The structures of the two products are shown in the image attached to this answer.

Answer:

0.028 mole of ammonium phosphate, (NH₄)₃PO₄.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₃PO₄ + 3NH₃ —> (NH₄)₃PO₄

From the balanced equation above,

3 moles of NH₃ reacted to produce 1 mole of (NH₄)₃PO₄.

Finally, we shall determine the number of mole of (NH₄)₃PO₄ produced by the reaction of 0.085 mole of ammonia, NH₃. This can be obtained as follow:

From the balanced equation above,

3 moles of NH₃ reacted to produce 1 mole of (NH₄)₃PO₄.

Therefore, 0.085 mole of NH₃ will react to produce = (0.085 × 1)/3 = 0.028 mole of (NH₄)₃PO₄.

Thus, 0.028 mole of ammonium phosphate, (NH₄)₃PO₄ were obtained from the reaction.

Answer:

Atomic theory originated as a philosophical concept in ancient India and Greece. ... In the fifth century BCE, Democritus proposed that matter consists of indestructible, indivisible units called atoms. The Roman poet Lucretius recorded the idea, so it survived through the Dark Ages for later consideration.

Answer:

2.9moles of hydrogen gas

Explanation:

convert liters to dm³

since 1liter= 1dm³

thus, 65.0liters = 65.0dm³

number of moles = volume given/22.4dm³

= 65.0/22.4

=2.9moles

Answer:

Explanation:

Nitric oxide is the gas NO, it reacts with oxygen as shown below;

2NO(g) + O2(g) -----> 2NO2(g)

Now the gas formed is the gas NO2 which is known to be reddish brown in colour.

A diagrammatic representation of this reaction is shown in the image attached to this answer.

Image credit: Chemlibretext

Answer:

They were made in unstable conditions

Explanation: Im smarty pants

Explanation:

P₄+O₂=P₂O₃; non-balanced

P₄+O₂=2P₂O₃; to add '2' on the right side; non-balanced

P₄+3O₂=2P₂O₃. to add '3' before O₂ in the left side; balanced