I'm extremely bad at doing these

I'm Extremely Bad At Doing These

Answers

Answer 1

The first few terms of a geometric sequence with first term [tex]a[/tex] and common ratio [tex]r[/tex] look like

[tex]a, ar , ar^2, ar^3, \ldots[/tex]

and so on. Notice that the [tex]n[/tex]-th term (where [tex]n[/tex] is a natural number) is [tex]ar^{n-1}[/tex].

For this particular sequence, the first term is

[tex]a=3[/tex]

and the fourth term is

[tex]ar^{4-1} = ar^3 = 1029[/tex]

Substitute [tex]a=3[/tex] into the second equation and solve for [tex]r[/tex].

[tex]3r^3 = 1029 \implies r^3 = 343 \implies r = \sqrt[3]{343} = \sqrt[3]{7^3} = 7[/tex]

Then the two terms between the 1st and 4th - i.e. the 2nd and 3rd terms - are

[tex]ar = 3\times7 = \boxed{21}[/tex]

and

[tex]ar^2 = 3\times7^2 = \boxed{147}[/tex]

Answer 2

Answer:

Term 2 is 21, and term 3 is 147.

Step-by-step explanation:

The geometric sequence is 3, 3r, 3r^2, 1029.

[tex]r = \sqrt[3]{ \frac{1029}{3} } [/tex]

[tex]r = \sqrt[3]{343} = 7[/tex]

So we have 3, 21, 147, 1029.


Related Questions

Solve this simultaneous equation.
[tex]x + y = 5 \\ \frac{1}{x} + \frac{1}{y} = \frac{9}{14} \\ [/tex]

Answers

Answer: x∈∅ (there is no decision).

Step-by-step explanation:

[tex]\left \{ {{x+y=5} \atop {\frac{1}{x} +\frac{1}{y}=\frac{9}{14} }} \right.\ \ \ \ \ \left \{ {{x+y=5} \atop {\frac{y+x}{x*y}=\frac{9}{14} \ |*14*x*y\ (x\neq 0;\ y\neq 0) }} \right. \ \ \ \ \left \{ {{x+y=5} \atop {14*(x+y)=9*x*y}} \right. \ \ \ \ \left \{ {{x+y=5} \atop {14*5=9*x*y}} \right.\ \ \ \ \left \{ {{x+y=5} \atop {9*x*y=70}} \right. \\[/tex]

[tex]\left \{ {{y=5-x} \atop {9*x*y=70\ |:9}} \right. \ \ \ \ \left \{ {{y=5-x} \atop {x*(5-x)=\frac{70}{9} }} \right.\ \ \ \ \left \{ {{y=5-x} \atop {5x-x^2=\frac{70}{9} }} \right. \ \ \ \ \left \{ {{y=5-x} \atop {x^2-5x+\frac{70}{9} =0\ |*9}} \right.\ \ \ \ \left \{ {{y=5-x} \atop {9x^2-45x+70=0}} \right.[/tex]

[tex]\left \{ {{y=5-x} \atop {D=-495}} \right. \ \ \ \ \Rightarrow\ \ \ \ x\in\varnothing.[/tex]

Suppose y varies inversely with x, and y = 25 when x = -15. What inverse variation equation relates x and y ?

a) y=5/x
b) y=-5/x
x) y=-5x
d) y=5x

Answers

The inverse variation equation is y = -5/x

What is equation?

Equation is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is equal

y varies inversely as x

Let variation constant = k

y = k/x, y = 25 and x = -15

25 = k/(-15),  k = -375 divded by 75 ,So k = -5

The inverse variation equation is y = -5/x

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6.
f(a+h)-f(a)
Determine
h
Of(a+h)-f(a)
h
Of(a+h)-f(a)
h
Of(a+h)-f(a)
h
=
for f(x) = x2 + 5x and simplify.
=
2a + h + 5
h
= 2a + 2h+5
2ah + h² - 5a
h
Of(a+h)-f(a) = 2a + h + 5
h

Answers

The value of the function operation f(a + h) - f(a) is; h² + 5h + 2ah

How to simplify functions?

We are given the function;

f(x) = x² + 5x

We want to find f(a + h) - f(a)

Let us first find f(a + h) to get;

f(a + h) = (a + h)² + 5(a + h)

⇒ a² + 2ah + h² + 5a + 5h

⇒ a² + 5a + h² + 5h + 2ah

Let us now find f(a) to get;

f(a) = a² + 5a

Thus, f(a + h) - f(a) = a² + 5a + h² + 5h + 2ah - a² - 5a

f(a + h) - f(a) = h² + 5h + 2ah

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Can someone pls help me with this problem?

Answers

For the first blank, since the output increases by 5 for each increase of 1 for the input, the answer is 13+2(5) = 23.For the second blank, since the output increased by 10 compared to 23, the input increased by 2. So, the answer is 5 + 2 = 7.We know the output is of the form 5x+b for some constant b. If we test input of 1 and an output of 3, we get an input of 1 gives 5+b, which is equal to 3, meaning b=-2. So, the answer is 5x-2.

can you help me i dont understand U_U

Answers

Answer:

$7.76

Step-by-step explanation:

So you can express the price in the slope-intercept form: y=mx+b where m is the slope, but in this context it's the price per km,  and b is the y-intercept, but in this context it's the base price (how much it costs even if the length is 0 km)

So it gives you the slope of $0.22 per km. so you now have the equation

y = 0.22x + b

To find the base amount or y-intercept, you can take some of the given points, the price will be y, and the length will be x.

I'll use the point (6, 4.68)

Plugging these values into the equation you get:

4.68 = 0.22(6) + b

multiply

[tex]4.68 = 1.32 + b[/tex]

subtract 1.32 from both sides

[tex]3.36 = b[/tex]

So now we have the full equation:

y = 0.22x + 3.36

Now to find the price if the length is 20km, simply plug in 20 as x

y = 0.22(20) + 3.36

Multiply

y = 4.4 + 3.36

Add

y=7.76

Find the area of the sector. Use π = 3.14.
120°
11 mi

Answers

Answer:

Step-by-step explanation:

Gisela would owe $15,500 in taxes each year if she were not eligible for any tax deductions.
This year, Gisela is eligible for tax deductions that reduce the amount of taxes she owes by
$2,325.00. If these tax deductions reduce the taxes Gisela owes this year by d%, what is the
value of d?

Answers

Answer:

15%

Step-by-step explanation:

$2325/$15500

Answer: 15

Step-by-step explanation: It’s given that the deductions reduce the original amount of taxes owed by $2,325.00. Since the deductions reduce the original amount of taxes owed by d%, the equation 2,32515,500=d100 can be used to find this percent decrease , d . Multiplying both sides of this equation by 100 yields 232,50015,500=d, or 15 = d. Thus, the tax deductions reduce the original amount of taxes owed by 15%.

6
4
2
0
A
2
4
C
6
8
What is the length of A"B"?
10 12
X
Triangle A'B'C' is created by dilating triangle with a scale factor centered at the origin

Answers

The length of A"B" is 20 units

How to determine the length of A'B'?

From the figure, we have:

A = (1, 4)

B = (4, 8)

The distance AB is:

[tex]AB = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]AB = \sqrt{(1 -4)^2 + (4-8)^2[/tex]

Evaluate

[tex]AB = \sqrt{25[/tex]

This gives

AB = 5

The scale factor of dilation is 4.

So, we have:

A'B' = 5 * 4

Evaluate

A'B' = 20

Hence, the length of A"B" is 20 units

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Assuming the world population growth rate is 1% and the current population is about 7 billion, next year the population will be:

Answers

Assuming the world population growth rate is 1% and the current population is about 7 billion, next year the population will be 7.01 billion.

To calculate the percentage increase rate, use the fundamental increase charge formulation: subtract the original from the brand new cost and divide the results by way of the original cost. to show that right into a percent boom, multiply the results by 100.

The population of a given area is described as the range of humans generally residing in that vicinity, measured on 1 January in a given 12 months. The supply can be the most latest population census.

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Triangle PQR is transformed to similar triangle P’Q’R’
What is the scale factor of dilation?

1/2
1/3
1/4
1/5

Answers

Scale factor = (image)/(preimage)

[tex]QR=3\\\\Q'R'=1[/tex]

So, the scale factor is 1/3

Points u, m, and d are collinear with m between u and d. given um=5x+30 md=3x+80 ud=10x+20

Answers

The lengths um, md and ud are 255 units, 215 units and 470 units respectively, when given that points u, m, and d are collinear with m between u and d and um=5x+30, md=3x+80, ud=10x+20. This can be obtained by adding um and md which is equal to ud. An equation is obtained and solve for x.

What is the required lengths ?

Given that, um=5x+30  

                  md=3x+80

                  ud=10x+20

We know that m is the midpoint of ud

Thus, um + md = ud

                 5x+30 + 3x+80 = 10x+20

                 5x+3x + 30+80 = 10x+20

                      8x + 110 = 10x+20 (taking terms with x to one side of equation)

                             10x - 8x = 110 - 20

                                     2x = 90

                                   ⇒ x = 45

Therefore the lengths,

um=5x+30 = 5(45)+30 = 225 + 30 = 255

md=3x+80 = 3(45)+80 = 135 + 80 = 215

ud=10x+20 = 10(45)+20 = 450 + 20 = 470

Hence the lengths um, md and ud are 255 units, 215 units and 470 units respectively, when given that points u, m, and d are collinear with m between u and d and um=5x+30, md=3x+80, ud=10x+20.

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What is the answer to thisss?

Answers

The value of x is 14

How to solve for x?

From the question, the lines from the center of the circle to the chords have equal measures of 9 units

This line divides a chord into equal segments, where each segment is 7 units

So, we have:

x = 7 + 7

Evaluate

x = 14

Hence, the value of x is 14

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Accordding to this function
What is:-

limf(x)
x approches 2⁺​

Answers

Answer:

Limit does not exist

Step-by-step explanation:

This is a piece-wise function, since we are finding the limit of f(x) when x is approaching 2 from the right, we know that x must be more than 2. However, based on the piece-wise function, there is no function that satisfy this condition, therefore the limit does not exist for this piece-wise function

If f = 36 when a = 9, find f when a = 8

Answers

Answer:

2=A

Step-by-step explanation:

We know that F is directly proportional to A then the equation relating them is

F = kA ← k is the constant of proportion

To find k use the condition F = 36 when A = 9, then

36 = 9k ( divide both sides by 9 )

4 = k

F = 4A ← equation of proportion

When F = 8, then

8 = 8A ( divide both sides by 4 )

2 = A

Each side of a square is increasing at a rate of 6 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 9 cm2

Answers

36 cm²s⁻¹ is the rate at which the area of the square is increasing.

Given each side of the square is increasing at a rate of 6cm/s

Area, A = s², s is the side length

=> [tex]\frac{dA}{dt} =\frac{dA}{ds}* \frac{ds}{dt} =2s*(\frac{ds}{dt} )[/tex] {chain rule of differentiation}

[tex]\frac{ds}{dt}[/tex] = 6 cm/s

When A = 9 cm² => 9 = s²

=> s = √(9) => s = 3 cm

Hence, [tex]\frac{dA}{dt}[/tex] = 2 × 3 × 6 = 36 cm²s⁻¹

Hence, 36 cm²s⁻¹ is the rate at which the area of the square increases

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8-2|4-5y|=4

| | stands for absolute value

Answers

Answer:

y = (2/5) OR y = (6/5)

Step-by-step explanation:

The first step is isolating the expression within the absolute value bars. The first thing we can do is subtract both sides by 8. If we do that, we get -2|4-5y| = -4. Now, to completely isolate the absolute value, we would have to divide by -2. This yields |4 - 5y| = 2. Finally, we can remove the absolute value bars. However, to do this, we need to first understand what an absolute value bar does to an equation. Lets say that |x| = 2. Absolute value describes the DISTANCE of some quantity from 0 (on the number line). Therefore, x (which is inside the absolute value bars) can be either positive or negative 2 (they are BOTH two units away from 0). Similarly, in this case, (4 - 5y) can either be 2 or -2 (because the absolute value of both is 2). Now we have two possible solutions to solve for:

4 - 5y = 2 OR 4 - 5y = -2

5y = 2 OR 5y = 6

y = (2/5) OR y = (6/5)

If we plug both of these answers back into the equation we can see that they both check out.

The graph could be divided up into three different periods of relatively consistent ticket price change: The years 1980 – 1988, 1989 – 1993 and 1994 – 2011. Can you find a typical rate of change in the price of a ticket for each of these time periods? In other words, on average, by how much did the price of a ticket increase by each year during each of these time periods?

Answers

In time period of 1980-1988 the rate of ticket price is $0.2 per year
Between time period 1989-1993 there is constant rate.
Between year 1994-2011 the increase in rate is same $0.2 per year

The graph could be divided up into three different periods of relatively consistent ticket price change: The years 1980 – 1988, 1989 – 1993 and 1994 – 2011.

What is Statistic?

The statistic is the study of mathematics which deal with relations between comprehensive data.

The graph is not available, in the question, so the graph could be as attached
For period 1980-1988
rate of change = 4.2-2.8/ 8 = 0.2
In time period of 1980-1988 the rate of ticket price is $0.2 per year

for period 1989-92 there is a straight line so,
Between time period 1989-1993 there at constant rate.

For period, 1994-2011

rate of change = 4.4-8/17 = 0.2
Between year 1994-2011 the increase in rate is same $0.2 per year

Thus, for the 3 Time period we have rate of change in ticket price is $0.2 per year, no change in ticket price, $0.2 per year respectively.

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b) In the last year, the average rainfall in Pokhara valley during the first 6 months was 150 mm and the average rainfall of the remaining months was 60 mm. Find the average rainfall of the whole year. The average selling of the first 4 days of a shop in the last week was c) Rs 425 and the average selling of the remaining days was Rs 250. Find the average selling of the shop in the whole week. a) Shashwat obtained an average marks of 15 in 3 subjects. When the marks obtained in another subject is also included, the average marks is increased by 1. Find the marks obtained in the fourth subject. b) The average marks of English, Nepali, Science and Social Studies obtained by Sunayana is 70. If the marks obtained in Mathematics is also included, the average marks is increased by 5. Find her marks in Mathematics. eative Section - B The a . b ) In the last year , the average rainfall in Pokhara valley during the first 6 months was 150 mm and the average rainfall of the remaining months was 60 mm . Find the average rainfall of the whole year . The average selling of the first 4 days of a shop in the last week was c ) Rs 425 and the average selling of the remaining days was Rs 250. Find the average selling of the shop in the whole week . a ) Shashwat obtained an average marks of 15 in 3 subjects . When the marks obtained in another subject is also included , the average marks is increased by 1. Find the marks obtained in the fourth subject . b ) The average marks of English , Nepali , Science and Social Studies obtained by Sunayana is 70. If the marks obtained in Mathematics is also included , the average marks is increased by 5. Find her marks in Mathematics .​

Answers

Answer:

For b), the answer is 105mm

Step-by-step explanation:

(150+60)/2

may someone help me please :)

Answers

Answer:

Answer is Similar-AA :D

Answer: Similar - AA  

Reason:

We're given these two angle congruences:

[tex]\angle P \cong \angle S\\\\\angle Q \cong \angle T[/tex]

These are the blue and red angles marked in the diagram below. Since we have two pairs of congruent angles, we can use the AA similarity theorem to prove the triangles are similar.

Similar triangles have the same shape, but are likely different sizes. Triangles with the same shape indicates the corresponding angles are congruent.

The info that PR = 12 and SU = 3 isn't used or needed. Your teacher may have put that in there as a distraction or filler.

what is the slope of line 2x-3y=19.

Answers

Answer:

[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Given Equation of line: y=mx+c,

where m = slope of line.

So, we will have to make y the subject to find the slope.

[tex]2x-3y=19\\2x-3y-2x=19-2x\\-3y=-2x+19\\y=\frac{-2x+19}{-3} \\y=\frac{2}{3} x-\frac{19}{3}[/tex]

From here, we can see the slope of the line is [tex]\frac{2}{3}[/tex].

Answer: 2/3

Step-by-step explanation:

2x-3y=19

minus 2x from both sides

-3y=-2x+19

divide both sides by -3

y=2/3x-19/3

slope is 2/3

rewrite the expression so that everything is under the same root sign and simplified
please please help :) GIVING BRAINLIEST

Answers

Step-by-step explanation:

[tex] \frac{2 {}^{4} }{3 \sqrt{xy} } [/tex]

[tex] \frac{2 { }^{4} }{ \sqrt{9xy} } [/tex]

[tex] \frac{1}{2 {}^{ - 4} \sqrt{9xy} } [/tex]

[tex] \frac{1}{ \frac{ \sqrt{9xy} }{16} } [/tex]

[tex] \frac{1}{ \frac{ \sqrt{9xy} }{ \sqrt{256} } } [/tex]

[tex] \frac{1}{ \sqrt{ \frac{9xy}{256} } } [/tex]

[tex]( \sqrt{ \frac{9xy}{256} } ) {}^{ - 1} [/tex]

Which statements about the angles of the triangle are true? check all that apply. a triangle has angles 6, 7, 8. angle 7 has an exterior angle of 1. a diagonal line extends from angle 8 to form angle 2. angle 6 has exterior angle 5. the line extends to form angles 3 and 4. angle 1 is an exterior angle. angle 2 is an exterior angle. angle 4 is an exterior angle. angle 7 is an adjacent interior angle. angle 6 is an adjacent interior angle. it is adjacent to the exterior angle 4. angles 6 and 8 are remote interior angles to the exterior angle 1. angles 6 and 7 are remote interior angles to the exterior angle 2. angles 7 and 8 are remote interior angles to the exterior angle 4.

Answers

All the statements are true about the triangle except

1. a diagonal line extends from angle 8 to form angle.

According to the statement

There is a triangle has angles 6, 7, 8 and there are also some statements are given that matched with the triangle.

But the statement

1. a diagonal line extends from angle 8 to form angle.

is not true because it is not possible to extend a diagonal line from angle 8.

So, All the statements are true about the triangle except

1. a diagonal line extends from angle 8 to form angle.

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If your player is Erik, write an inequality that shows all of the ways that Erik will win
if Nita chooses 7. If your player is Nita, write an inequality that shows all of the ways
that Nita will win if Erik chooses 17.

Answers

An inequality that shows all of the ways that Nita will win if Erik chooses 17 is

Eric will win if Nita chooses 7 and he chooses and number that is less than 17 (ex. n<17).Nita will win if Eric chooses 17 and she chooses a number less than 8 (ex. n<8).

What is an Inequality?

This refers to the relation in mathematics that makes an unequal comparison between two numbers or expressions.

Therefore, according to the rules of the game, they would have to make random selections from 0 to 20 and if the difference between their two numbers is less than 10, then Erik wins, the inequality that would show all of the ways that Nita will win if Erik chooses 17 are listed above.

Hence, we can see that the complete question goes thus:

"Erik and Nita are playing a game with numbers. In the game, they each think of a random number from zero to 20. If the difference between their two numbers is less than 10, then Erik wins. If the difference between their two numbers is greater than 10, then Nita wins.

Use what you know about inequalities and absolute values to better understand the game."

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What polynomial function could be represented by the graph below

(A). F(X)=x^2+x-2
(B). F(X)=2x^2+2x-4
(C). F(X)=x^2-x-2
(D). F(X)=2x^2-2x-4

Answers

Answer:

(B). F(X)=2x^2+2x-4

Step-by-step explanation:

-4 means it passes through -4 at the y axis

B and D have -4

graph passes thru x axis at -2 and 1

if you enter x = -2 or 1 in the formula

(B). F(X)=2x^2+2x-4

you get 0

it's not D because when you enter -2 or 1 for x

you don't get 0

you get 8 and -4

Answer: (B). F(x) = 2x² + 2x - 4

Step-by-step explanation:

      Let us think about the parent function F(x) = x² to pick our answer.

      Options A and C have only shifted 2 units down (showed by the "-2" at the end) and the function graphed is shifted four units down.

      Between options B and D, one is shifted 2 units to the right, and one is shifted 2 units to the left. We need the one shifted 2 units to the left. This is shown by the "+2x" in option B meaning it is our answer.

Need help with this!

Answers

Answer:

488

Step-by-step explanation:

Calculate 20% of their take-home pay

3600 * 0.20 = 720

They already pay 122 and 110 per month

720 - (122 + 110)

720 - 232

488

So the largest monthly car payment they can afford is 488

Complete the number pattern

Answers

Answer:

1, 4, 9, 16, 25, 36, 49, (....)

Use the Pythagorean identity
to find sin x.
COS X =
sin x =
8
17
?
Enter

Answers

Answer:

[tex]sin\ x = \frac{15}{17}[/tex]

Step-by-step explanation:

So in this case, it's similar to the previous question you asked, except this time you know cosine, and as you may know cosine is defined as: [tex]\frac{adjacent}{hypotenuse}[/tex] and sine is defined as: [tex]\frac{opposite}{hypotenuse}[/tex]. So all we need to solve for is the opposite side, but since we know two sides, we can solve for the other using the Pythagorean identity: [tex]a^2+b^2=c^2[/tex]

Plug in known values:
[tex]8^2 + b^2 = 17^2[/tex]

Simplify:

[tex]64 + b^2 = 289\\b^2 = 225\\b = 15[/tex]

So the opposite side is 15, and the hypotenuse is already given, in this case it's 17 (the denominator of cosine). So plugging this into the definition of sin gives you: [tex]\frac{15}{17}[/tex]

Answer:

[tex] \frac{15}{17} [/tex]

Step-by-step explanation:

[tex] { \sin(x) }^{2} + { \cos(x) }^{2} = 1[/tex]

[tex] \cos(x) = 8 \div 17[/tex]

[tex] \sin(x) = \sqrt{1 - { \cos(x) }^{2} } [/tex]

[tex] \sin(x) = \sqrt{1 - {(8 \div 17)}^{2} } [/tex]

[tex] \sin(x) = 15 \div 17[/tex]

help me i dont understand this

Answers

False

All functions are relations, but not all relations are functions

horizontally compress the exponential function f(x)=2^x by a factor of 3

Answers

The horizontally compress the exponential function f(x)=2^x by a factor of 3 is f(3x)=2^3x

When we compress a function y=f(x) by a scale factor of 'k', where k >1, then the function after compression will become :

y=f(x), where k>1

We have given the Exponential function.

What is the scale factor?

The scale factor is a measure for similar figures, that look the same but have different scales or measures. Suppose, two circle looks similar but they could have varying radii. The scale factor states the scale by which a figure is bigger or smaller than the original figure.

The scale factor of the compression (k): 5

Then after horizontal compression, the exponential function will become

f(3x)=2^3x

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what is the equation of the given line in the point -slope form

Answers

Answer:

E

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 1) and (x₂, y₂ ) = (3, 4) ← 2 points on the line

m = [tex]\frac{4-1}{3-0}[/tex] = [tex]\frac{3}{3}[/tex] = 1

using (a, b ) = (3, 4 ) , then

y - 4 = 1 (x - 3) → E

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