If f(x) = 2x^2 +1, complete the following:
a. f(-4)
b. f(-2)
c. f(0)
d. f(2)
e. f(4)

This is a timed test please i need help!!

Answer:

[tex]Length =\frac{25}{4 + \pi}[/tex] and [tex]Width = \frac{50}{4+\pi}[/tex]

Step-by-step explanation:

This question is better understood with an attachment.

See attachment for illustration.

Given

Represent Perimeter with P

[tex]P = 25ft[/tex]

Required

Determine the dimension of the rectangle that maximizes the area

First, we calculate the perimeter of the rectangular part of the window.

From the attachment, the rectangle is not closed at the top.

So, The perimeter would be the sum of the three closed sides

Where

[tex]Width = 2x[/tex]

[tex]Length = y[/tex]

So:

[tex]P_{Rectangle} = y + y + 2x[/tex]

[tex]P_{Rectangle} = 2y + 2x[/tex]

Next, we determine the circumference of the semi circle.

Circumference of a semicircle is calculated as:

[tex]C = \frac{1}{2}\pi r[/tex]

From the attachment,

[tex]Radius (r) = x[/tex]

So, we have:

[tex]C = \frac{1}{2}2\pi * x[/tex]

[tex]C = \pi x[/tex]

So, the perimeter of the window is:

[tex]P = P_{Rectangle} + C[/tex]

[tex]P =2y + 2x + \pi x[/tex]

Recall that: [tex]P = 25[/tex]

So, we have:

[tex]25 =2y + 2x +\pi x[/tex]

Make 2y the subject

[tex]2y = 25 - 2x - \pi x[/tex]

Make y the subject:

[tex]y = \frac{25}{2} - \frac{2x}{2} - \frac{\pi x}{2}[/tex]

[tex]y = \frac{25}{2} - x - \frac{\pi x}{2}[/tex]

Next, we determine the area (A) of the window

A = Area of Rectangle + Area of Semicircle

[tex]A = 2x * y + \frac{1}{2}\pi r^2[/tex]

[tex]A = 2xy + \frac{1}{2}\pi r^2[/tex]

Recall that

[tex]Radius (r) = x[/tex]

[tex]A = 2xy + \frac{1}{2}\pi x^2[/tex]

Substitute [tex]\frac{25}{2} - x - \frac{\pi x}{2}[/tex] for y in [tex]A = 2xy + \frac{1}{2}\pi x^2[/tex]

[tex]A = 2x(\frac{25}{2} - x - \frac{\pi x}{2}) + \frac{1}{2}\pi x^2[/tex]

Open Bracket

[tex]A = 2x * \frac{25}{2} - 2x * x - 2x * \frac{\pi x}{2} + \frac{1}{2}\pi x^2[/tex]

[tex]A = 25x - 2x^2 - \pi x^2 + \frac{1}{2}\pi x^2[/tex]

[tex]A = 25x - 2x^2 - \frac{1}{2}\pi x^2[/tex]

To maximize area, we have to determine differentiate both sides and set A' = 0

Differentiate

[tex]A' = 25 - 4x - \pi x[/tex]

[tex]A' = 0[/tex]

So, we have:

[tex]0 = 25 - 4x - \pi x[/tex]

Factorize:

[tex]0 = 25 -x(4 + \pi)[/tex]

[tex]-25 =-x(4 + \pi)[/tex]

Solve for x

[tex]x = \frac{-25}{-(4+\pi)}[/tex]

[tex]x = \frac{25}{4+\pi}[/tex]

Recall that

[tex]Width = 2x[/tex]

[tex]Width = 2(\frac{25}{4+\pi})[/tex]

[tex]Width = \frac{50}{4+\pi}[/tex]

Recall that:

[tex]y = \frac{25}{2} - x - \frac{\pi x}{2}[/tex]

Substitute [tex]\frac{25}{4+\pi}[/tex] for x

[tex]y = \frac{25}{2} - (\frac{25}{4+\pi}) - \frac{\pi (\frac{25}{4+\pi})}{2}[/tex]

[tex]y = \frac{25}{2} - (\frac{25}{4+\pi}) - \frac{\frac{25\pi}{4+\pi}}{2}[/tex]

[tex]y = \frac{25}{2} - (\frac{25}{4+\pi}) - \frac{25\pi}{4+\pi} * \frac{1}{2}[/tex]

[tex]y = \frac{25}{2} - \frac{25}{4+\pi} - \frac{25\pi}{2(4+\pi)}[/tex]

[tex]y = \frac{25(4+\pi) - 25 * 2 - 25\pi}{2(4 + \pi)}[/tex]

[tex]y = \frac{100+25\pi - 50 - 25\pi}{2(4 + \pi)}[/tex]

[tex]y = \frac{100- 50+25\pi - 25\pi}{2(4 + \pi)}[/tex]

[tex]y = \frac{50}{2(4 + \pi)}[/tex]

[tex]y = \frac{25}{4 + \pi}[/tex]

Recall that:

[tex]Length = y[/tex]

So:

[tex]Length =\frac{25}{4 + \pi}[/tex]

Hence, the dimension of the rectangle is:

[tex]Length =\frac{25}{4 + \pi}[/tex] and [tex]Width = \frac{50}{4+\pi}[/tex]

Answer:

(ab)² = 36

Step-by-step explanation:

Plug in 2 for a and 3 for b:

(2·3)²

Multiply 2 and 3:

6²

Square the number:

36

Answer:

First, collect the like terms by one side

x/4=2+6

x/4=8

Then, criss-cross it, which means multiply 4 with 8

x=4×8

x=32

Step-by-step explanation:

I hope this is the answer to your question, if it helped you, please give me brainliest

Answer:

21/6 = 7/2 = 14/4

Step-by-step explanation:

Answer:

21:6 7:2 14:4

Step-by-step explanation:

Answer:

x  = Y /m  −  p /m +8

Step-by-step explanation:

Answer:

Step-by-step explanation:

The second card is influenced by the first only in that you have not replaced the first card. That makes a difference.

1/52 is the probability for the first card.

1/51 is the probability for the second card.

They are independent events. Drawing the 7 of diamonds does not make the chances of drawing the Ace of Spades other than the 7 came first and the probability of getting the Ace is slightly larger.

Step-by-step explanation:

The only way the second card is influenced by the first is if you did not swap out the first card. That alters everything.

The likelihood of getting the first card is 1/52.

The odds of getting the second card are 1/51.

They happen separately. Other than the fact that the 7 came first and the odds of receiving the Ace is a little bit higher, drawing the 7 of diamonds does not increase the chances of drawing the Ace of Spades.

The required offer is the least price per ounce of shampoo is $8 for 12 ounces of shampoo. Option C is correct.

Given that,
To determine the offer the least price per ounce of shampoo.

The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.

Here,
A) $6 for 8 ounces of shampoo
6 / 8 = $0.75 per ounces of shampoo

B) $4 for 5 ounces of shampoo
4/ 5 = $0.80 per ounces of shampoo

C) $8 for 12 ounces of shampoo
8/12 = $0.67 per ounce of shampoo

D) $12 for 16 ounces of shampoo
12/16 = $0.75 per ounce of shampoo

Thus, the required offer is the least price per ounce of shampoo is $8 for 12 ounces of shampoo. Option C is correct.

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Answer:

( [tex]\frac{6}{7}[/tex] - [tex]\frac{1}{3}[/tex] ) is closer to [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

[tex]\frac{2}{15}[/tex] + [tex]\frac{1}{3}[/tex] = [tex]\frac{2 + 5}{15}[/tex] = [tex]\frac{7}{15}[/tex]

[tex]\frac{6}{7}[/tex] - [tex]\frac{1}{3}[/tex] = [tex]\frac{18-7}{21}[/tex] = [tex]\frac{11}{21}[/tex]

[tex]\frac{7}{15}[/tex] , [tex]\frac{1}{2}[/tex] , [tex]\frac{11}{21}[/tex]

LCD (2, 15, 21) = 210

[tex]\frac{98}{210}[/tex] , [tex]\frac{105}{210}[/tex] , [tex]\frac{110}{210}[/tex]

105 - 98 = 7

110 - 105 = 5 ⇒ [tex]\frac{11}{21}[/tex] is closer to [tex]\frac{1}{2}[/tex] ⇒ ( [tex]\frac{6}{7}[/tex] - [tex]\frac{1}{3}[/tex] ) is closer to [tex]\frac{1}{2}[/tex]

Answer:

-2/15

Step-by-step explanation:

Answer:

y,x-7

Step-by-step explanation:

I think this is it

Answer:

y=x-7

Step-by-step explanation:

Answer:

The answer is 8 days.

Step-by-step explanation:

By applying the correct equations to Todd and Seth's balances for each day we end up with Todd and Seth having an equal balance in their accounts by day 8, alternatively, we can show that Todd and Seth have the same amount of money in their accounts by day 8 with this table

Day - Todd - Seth

1     -  95     - 130

2    -   90    - 120

3   -    85    -  110

4    -   80    -   100

5    -  75    -   90

6  -    70   -    80

7  -    65    -   70

8 -     60   -    60

Answer:

0.89%

Step-by-step explanation:

Given that :

Total number of raffle tickets = 1900

Total number of Clara's tickets (5 + 4 + 8) = 17

Probability that one of Clara's tickets will be picked :

Probability = (required outcome / Total possible outcomes)

Required outcome = total number of Clara's ticket

Total possible outcomes = total number of raffle tickets

Hence,

P(picking one of Clara's tickets) = 17 / 1900

17 / 1900 = 0.0089473

0.0089473 * 100%

= 0.8947%

= 0.89%

Answer:

the answer is 6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Hope this helps!!!!!!

Answer:

T_T said to 个_个: Hallo, I am so happee!!!

Step-by-step explanation:

Plz mark as Brainliest!

Answer:

30

Step-by-step explanation:

Solve for n: 0.22n = 6.6.

​

Answer:

its the first third and fith

Step-by-step explanation:

Answer:

2.Matrices and Linear Algebra. 2.1 Basics. Definition 2.1.1. A matrix is an m × n array ... aij = 0 i = j. (1b) A diagonal matrix A may be denoted by diag(d1,d2,... ,dn) ... space of A. With r1 (A),...,rm (A) denoting the rows of A the row space

4.Introduces reflections in the x- and y-axes. Demonstrates the ... This leaves us with the transformation for doing a reflection in the y-axis. For this transformation, I'll switch ... Many textbooks don't get any further than this. If these are all the rules ...

Answer:

c is wrong

Step-by-step explanation:

The given shape is a rhombus.

Hence the correct option is A.

Given is a shape we need to identify its type,

Since all the sides are congruent shown, so we can conclude that the shape is a Rhombus.

A rhombus is a quadrilateral (a polygon with four sides) in which all four sides have equal length. Additionally, the opposite sides of a rhombus are parallel to each other.

The rhombus is also a special type of parallelogram, as it has all the properties of a parallelogram, including opposite sides being equal in length, all the sides being equal and opposite angles being equal in measure.

Hence the correct option is A.

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Answer:

The solution of this differential system is [tex]y(x) = x\cdot e^{3\cdot x}[/tex].

Step-by-step explanation:

This second-order differential equation is homogeneous and linear of the form:

[tex]y'' + p\cdot y' +q\cdot y = 0[/tex] (1)

Where:

[tex]p[/tex] - First-order constant coefficient, dimensionless.

[tex]q[/tex] - Zero-order constant coefficient, dimensionless.

Whose characteristic polynomial is:

[tex]\lambda^{2}+p\cdot \lambda + q = 0[/tex] (2)

Where [tex]\lambda[/tex] contains the roots associated with the solution of the differential equation.

If we know that [tex]p = 6[/tex] and [tex]q = 9[/tex], the roots of the characteristic equation are, respectively:

[tex]\lambda^{2}+6\cdot \lambda + 9 = 0[/tex]

[tex](\lambda +3)\cdot (\lambda + 3) = 0[/tex]

Which means that [tex]\lambda_{1} = \lambda_{2} = 3[/tex] and the solution of the differential equation is of the form:

[tex]y(x) = e^{3\cdot x}\cdot (c_{1}+c_{2}\cdot x)[/tex] (3)

Where [tex]c_{1}[/tex] and [tex]c_{2}[/tex] are integration constants.

The first derivative of the equation above is:

[tex]y'(x) = 3\cdot e^{3\cdot x}\cdot (c_{1}+c_{2}\cdot x)+c_{2}\cdot e^{3\cdot x}[/tex] (4)

Now, if we get that [tex]y(0) = 0[/tex] and [tex]y'(0) = 1[/tex], then the system of equations to the solved is:

[tex]c_{1} = 0[/tex] (3b)

[tex]c_{1}+c_{2} = 1[/tex] (4b)

The solution of this system is: [tex]c_{1} = 0[/tex], [tex]c_{2} = 1[/tex]. Therefore, the solution of this differential system is [tex]y(x) = x\cdot e^{3\cdot x}[/tex].

Answer:

A.

Step-by-step explanation:

Sorry, just unexplainable thinking.

Answer:

The relationship is proportional.

The relationship is linear.

The equation of the line is y = –3x.

Step-by-step explanation:

The line in the question passes through origin and (4,-12).

The rate of change of the line is

[tex]m=\dfrac{-12-0}{4-0}\\\Rightarrow m=\dfrac{-12}{4}\\\Rightarrow m=-3[/tex]

The rate of change of the line or slope of the line is -3

Equation of the line is given by

[tex](y-0)=-3(x-0)\\\Rightarrow y=-3x[/tex]

This means that the relationship is linear.

If we take any value of x then there will be only one value of y this means that the relationship is proportional.

So the following statements are true

The relationship is proportional.

The relationship is linear.

The equation of the line is y = –3x.

Answer:

Step-by-step explanation:

Proportional

Linear

Equation of line is y=-3x

Answer:

d. 1 1/8

Step-by-step explanation:

-3 -1

---- ÷ -----

8. 3

Keep, Change, Flip.

-3/8 stays the same.

Division becomes multiplication.

-1/3 becomes -3/1

-3. -3. = 9

----- × ----- ------

8. 1. = 8

9/8 = 1 1/8

Answer:

D. 1 1/8

Step-by-step explanation:

The fraction of the students are boys who brought their lunch is 5/6.

It is required to find the fraction of the students are boys who brought their lunch.

A fraction having whole numbers for the numerator and denominator. A fraction is a number of the form: ab where a and b are integers and b≠0. It represents the division of two numbers.

Given:

At a certain school, students are boys =5/9

students  are boys brought their lunch=2/3

According to given question we have,

Divide 5/9 by 2/3

[tex]\frac{5/9}{2/3} \\\\\frac{5}{6}[/tex]

Therefore, the fraction of the students are boys who brought their lunch is 5/6.

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Answer:

all integers are whole numbers