if, at a given temperature, the equilibrium constant for the reaction h2(g) cl2(g) 2hcl(g) is kp, then the equilibrium constant for the reaction hcl(g) h2(g) cl2 (g) can be represented as:

One of these neurotransmitters, dopamine, is released in the reward area of the brain and results in pleasurable feelings and an uplifted mood. More nicotine is required to feel good the more you smoke.

The nightshade plant family naturally produces nicotine, an alkaloid that is widely used recreationally as a stimulant and anxiolytic. It is a medication meant to decrease withdrawal symptoms in smokers who desire to quit.

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Answer:

During metaphase, the cell's chromosomes align themselves in the middle of the cell through a type of cellular "tug of war." The chromosomes, which have been replicated and remain joined at a central point called the centromere, are called sister chromatids.

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In this situation, wash the separating funnel with soap and water once more before using it for the subsequent experiment and rinse the funnel with acetone into a waste container.

Separating funnels are employed in the extraction process and must be free of contaminants that could reduce the yield of the extraction. The funnel could be placed in a desiccation after being cleaned and rinsed to allow the water on the body to dry before being used for the following extraction procedure. Washing laboratory equipment before use irrespective of its state (whether it is clean or not) contributes to standard laboratory practices.

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Explanation:

Plenary lecture paper

Combustion dynamics of large-scale wildfires

Author links open overlay panelLiuNaianXieXiaodong

https://doi.org/10.1016/j.proci.2020.11.006

Get rights and content

Under a Creative Commons licenseOpen access

Abstract

A fact often overlooked is that large-scale wildfires, although occurring infrequently, are responsible for the overwhelming majority of fire-related suppression costs, economic losses, and natural resources damages. Fortunately, the increasingly severe problems of large-scale wildfires worldwide have been receiving ever-growing academic attention. The high-intensity burning behaviors in wildfires stem from the significant interaction of combustion with heat transfer and atmospheric flow under complicated fuel, meteorology, and topography conditions. Therefore, mitigating measures against large-scale wildfire disasters have grown into a challenging research focus for combustion scientists. Research over the past century has resulted in incrementally enhanced insights into the mechanisms of combustion dynamics underlying the various erratic behaviors in large-scale wildfires, with theories and models of fire accelerations developed and validated. These advances are expected to improve the efficacy of large-scale wildfire predictions significantly. Nevertheless, the physical interpretation of the acceleration of large-scale wildfires is far from adequate and complete. This paper intends not to make a comprehensive review of the entire wildfire research field, but to depict an overall pattern of the essential factors that lead an initial small-scale spreading flame to a large-scale wildfire beyond control. It is outlined that the complicated transformation of fuel preheating mechanisms determines the growth of surface fire spread, while varied large-size flame fronts and unique spread modes induced in specific fire environments play an essential role in fire spread acceleration. Additionally, multiple fires burning and merging often act as crucial steps for accelerating surface fire spread, generating large-size flames, and triggering unique spread modes. These major potential factors strike the energy balance of a low-intensity wildfire and push it to a high-intensity state. Several issues regarding intensely burning behaviors in large-scale wildfires are selected for in-depth discussions, for which an overview of the progress and challenges in research is presented. It is concluded that the fundamental exploration targeted at developing application tools capable of dealing with large-scale wildfires remains at its early stages. Opportunities for innovation are abundant, yet systematic and long-term research programs are required.

The parts of the chemical equation to the correct description are done below.

Column A              Column B

1. Cl₂ + Ail₃ ----------- c. Reactants

2. I2 + AlCl3. ---------- a. Products

3. 3.(g) or (aq) ---------  d. State of Matter

4. 4.--> -------------------- b. Shows which way the reaction progresses.

Chemical equations tell us the factors and/or compounds that can be reacting and the product(s) of the response. The coefficients on the materials in the response tell us the mole ratio or molecular ratio of the elements/compounds inside the reaction. A chemical equation is the symbolic representation of a chemical response in the form of symbols and chemical formulation.

Chemical equations are an efficient way to explain chemical reactions. This module explains the shorthand notation used to express how atoms are rearranged to make new compounds at some stage in a chemical reaction. It indicates how balanced chemical equations convey the proportions of each reactant and product concerned.

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Mass of magnesium ribbon is 0.21 g.

Mass of oxygen gas reacts with magnesium is 0.11 g

Number of moles of magnesium is 0.00875

Number of moles of oxygen is 0.0068.

Ratio of moles of magnesium and oxygen = 1.2 : 1

The number of moles of a substance equals the ratio of its given mass in a chemical reaction to the mass of one mole of that substance. One mole of any substance equals Avogadro's number, that is, 6.023 × 10²³.

we know that mass of crucible and lid = 35.56 g

mass of crucible and lid and magnesium = 35.77 g

Thus mass of magnesium = 35.77 - 35.56 = 0.21 g

mass of crucible and lid and magnesium oxide = 35.88 g

thus, mass of oxygen = 35.88 - 35.77 = 0.11 g

Now, Number of moles of magnesium = 0.21/24 =  0.00875

         Number of moles of Oxygen = 0.11/16 = 0.0068

Ratio of Number of moles of magnesium to Number of moles of Oxygen = 0.00875/0.0068 = 1.2 : 1.

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The momentum of the bowling ball is projected upward with a velocity of 2.0 m/s is 10 kg m/s.

The amount of force will that bowling ball have as it falls back to earth is 10 N.

We know that,

Momentum is the product of speed of an object and its mass. This means that an object at rest has zero momentum since the velocity is also zero.

It is given as -

Momentum = Mass of an object x speed/ velocity

Momentum = 5 kg x 2.0 m/s

                   = 10 kg m/s

To calculate amount of force bowling ball have when it falls back to Earth is -

Force exerted by an object is equal to product of its mass and velocity.

The second law of motion states that change in momentum of the object is given by mass multiplied by the velocity, which is equal to force.

F = mv

where,

F = force

m = mass

v = velocity

and,

p = mv

where,

p = momentum

m = mass

v = velocity

Hence, the amount of force that bowling ball have as it falls back to Earth is 10 N.

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Volume of oxygen would be collected at STP is 293.3 ml

V1 = 293 mL

V2 = ?

P1 = 102 kPa

P2 = 100 kPa

T1 = 10°C = ( 273 + 10 ) = 283 k

T2 = 273 k

The Combined Gas Law combines Charles Law, Boyle s Law and Gay Lussac s Law. The Combined Gas Law states that a gas pressure x volume x temperature = constant

The combined gas law is an amalgamation of the three previously known laws which are- Boyle's law PV = K, Charles law V/T = K, and Gay-Lussac's law P/T = K. Therefore, the formula of combined gas law is PV/T = K, Where P = pressure, T = temperature, V = volume, K is constant.

P1V1/T2 = P2V2/T2

102 x 293 / 283 = 100 x V2 / 273

105.6 = 0.36 x V2

105.6/0.36 = 293.3

V2 = 293.3 ml

Hence, volume of oxygen would be collected at STP is 293.3 ml

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Answer:

C. Cl changing to Cl-

Explanation:

Cl gains 1 electron, resulting in an increase in radius.

The other 3 give up electrons.

The concentration of sulfuric acid in mol/dm3 and g/dm3 would be  5.194 and 0.053 respectively.

From the equation of the reaction, the mole ratio of the concentrated sulfuric acid and sodium hydroxide solution is 1:2.

Recall that: mole = molarity x volume

For 26.5 cm3 0.100 mol/dm3 sodium hydroxide solution, the number of moles of the solute in the solution can be calculated as:

26.5/1000 x 0.100 = 0.00265 moles

The equivalent number of moles of the concentrated sulfuric acid will be:

                  0.00265/2 = 0.001325 moles

Also, recall that:

Concentration in g/dm3 = mass/volume

concentration in mol/dm3 = mole/volume

For 0.001325, 25.0 cm3 sulfuric acid:

mass = 0.001325 x 98 = 0.12985 g

Concentration in g/dm3 = 0.012985/0.025

                                       = 5.194 g/dm3

Concentration in mole/dm3 = 0.001325/0.025

                                         = 0.053 mol/dm3

Hence, the concentration of the sulfuric acid in mol/dm3 and g/dm3 would be 5.194 and 0.053 respectively.

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yes I agree thank you for sharing

Height in inches is 62.6 inches and weight in pounds are 101 pounds

Height is a way to measure someone or something from base to top or head to toe

Here given data is student height = 159cm tall and weight is =  45.8kg

So we have to convert

Height in cm = height in inches

Weight in kg =  weight in pounds

So, 1 inches = 2.45cm

Height =  159cm×1 inches/ 2.45cm

Height = 62.6inches

Now, 1kg = 2.2045  pounds

Weight = 45.8kg×2.2045  pounds/1kg

Weight = 101 pounds or lbs

Height = 62.6inches and weight = 101 pounds or lbs

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It is 21,000 kilometers around the earth and the earth rotates in 24 hr then 875 km/hrs fast is it rotating

Earth spins on its axis and earth takes one day one rotation on its axis

It is 21,000 kilometers around the earth rotates in 24 hrs and we have to find how many km/hr earth rotating = ?

So, distance = 21,000km

Time = 24 hrs

Speed = 21,000km/24 hrs

= 875 km/hrs

875 km/hrs fast is it rotating

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Gallium has two naturally occurring isotopes: 69ga with a mass of 68.9256 amu and a natural abundance of 60.11% and 71ga. Using the mass of gallium from the periodic table,  the mass of Ga-71 isotope is 70.9246 amu.

There are two naturally occurring isotopes of gallium: Ga-69 isotope having mass 68.9256 and percentage abundance is  60.11%, let say 'X' be the mass of  isotope - Ga-71.

Its percentage abundance can be calculated as:

%Ga-71=100-60.11=39.89%

The atomic mass of an element can be calculated by adding the atomic masses of its isotopes multiplied by their percentage abundance.

In this case we have

Atomic mass = m(Ga-69)×%(Ga-69) + X ×%(Ga-71)

The atomic mass of Ga is 69.723 amu.

Now putting the values, we will get

69.723 amu = (68.9256amu)(60.11/100) + X (39.89/100)

Hence,

69.723 amu = 41.431amu + + X (39.89/100)

Now rearranging the above equation we get,

X = 69.723 amu -  41.431amu/0.3989 = 70.9246amu

Thus, the mass of Ga-71 isotope is 70.9246 amu.

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The complete question is:

Gallium has two naturally occurring isotopes: 69ga with a mass of 68.9256 amu and a natural abundance of 60.11% and 71ga. use the atomic mass of gallium from the periodic table to find the mass of gallium-71. express the mass in atomic mass units to two decimal.

Two different samples of matter are measured in each of these glass containers. Both of the containers show the same measure for both samples of matter. These samples have volume in common.

In chemistry, volume is defined as the three-dimensional space taken up by matter. Volume is measured in cubic meters.

If you were to put two different samples in a graduated glass container and both of them have the particular digit that shows their volume then it means their volume is the same and they take up the same amount of space irrespective of their chemical composition.

For example, if you pour the sample into a glass container and the number you get is 250 m³.

Then this 250 m³ refers to the volume of the sample.

In general, volume is measured as volume =  mass/density and its SI unit is m³.

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In the given reaction chemical equilibrium;

Le Chatelier's principle states that for a chemical system in equilibrium if an external constraint is applied o the system, the equilibrium position will shift so as to annul the effect of the constraint applied to the system.

In practical terms, this principle implies that if the forward reaction of a system in equilibrium is endothermic and the backward reaction is exothermic, adding more heat to the system will shift the equilibrium position of the reaction to favor the forward reaction.

Considering the given chemical equilibrium, the forward reaction is endothermic and results in the formation of OH⁻ ions.

Therefore, the addition of more OH⁻ will shift the equilibrium to the left whereas, the addition of heat will shift the equilibrium to the right.

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Complete question:

Use Le Châtelier's principle to predict how the equilibrium for the weak base methylamine responds to the indicated changes.

CH₃NH₂ (aq) H₂O (l) ⇄ CH₃NH₃⁺ (aq) + OH⁻ (aq) ΔH°rxn = 103 kJ/mol

1) adding KOH

2) Increasing the temperature

This circumstance frequently arises when an enzyme or a solid surface is used to catalyze a process (heterogeneous catalysis).

The unit for the rate of reaction depends on the odder of the reaction .for the zero order reaction a→b,a plot of 1/⊂a⊃vs.time will produce a straight line. the rate of a zero order reaction decreases as the reaction proceeds

This circumstance frequently arises when an enzyme or a solid surface is used to catalyze a process (heterogeneous catalysis).

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The reaction Mg + 2 NaF --> MgF₂ + 2Na is a single replacement reaction; option B.

A chemial reaction is a srecation in which atoms of elements under chemical changes to form new products.

The various types of chemical reactions include:

A single replacement reaction is a reaction in which a single atom or a radical replaces another atom or radical in a compouds.

For example, the reaction given below is a single replacement reaction:

Mg replaces N ain the compound NaF.

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Answer:

I think "they are held together by chemical bonds"

Answer:

Oxygen

Explanation:

The 1st 2 are compounds

The last one "air" can be used to say oxygen, however, "air" is not on the periodic table of elements.

Oxygen is on the periodic table of elements

functional group: an atom, or group of atoms (with specific connectivity), exhibiting ... contain only carbon-carbon and carbon-hydrogen single bonds.

Organic Molecules: The study of the characteristics of carbon-based compounds is known as organic chemistry. Except for a few inorganic carbon molecules, all carbon compounds are organic. The carbon oxides, metal ion bicarbonates and carbonates, metal cyanides, and a few more substances are examples of inorganic carbon compounds.

Hydrocarbons:Only carbon and hydrogen atoms make up the simplest organic molecules. Hydrocarbons are pure carbon and hydrogen compounds.

Alkanes: Methane, or CH4, is the most basic hydrocarbon. This is the most basic hydrocarbon in a group. The carbon atom count in each subsequent member of the series is one more than in the one before it. Alkanes are this group of chemicals (CnH2n+2). The less dense ones are utilised as fuels and are gases. the centre ones

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Answer: 

hope it helps!! ..............

The leftover sample will be cut in half again.

4000 atoms⋅1/2=2000 atoms

after 3200 years

As a result, your initial sample of radium-226 will be reduced to 2000 atoms.

Radium is created by the radioactive decay of uranium. Radiation intensity from radioactive materials reduces with time. The half-life is the time necessary for the intensity to diminish by one-half. Radium has a half-life of around 1,600 years.

Gamma radiation has the most energy of any kind of radioactive decay. Gamma radiation contains the greatest energy waves in the electromagnetic spectrum.

Radium is presently utilised to make radon, a radioactive gas that is used to cure some forms of cancer.

The historically significant transition of radium 226 into radon 222 by alpha particle emission is an example of alpha decay.

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The hydronium ion concentration, [H₃O⁺ ], of the solution is  3.83 * 10⁻⁶.

The hydronium ion concentration of a solution is the concentration in mol/dm³ of the hydronium ions of a solution.

The hydronium ion is formed when a water molecule combines with a hydrogen ion as shown below:

H₂O + H⁺ ---> H₃O⁺

The hydronium ion concentration of a solution is also known as the hydrogen ion concentration of the solution or pH.

The product of the hydronium ion concentration of a solution and the hydroxide ion concentration of a solution gives the ion product of water.

[H₃O⁺ ] * [OH⁻] = Kw

where Kw = 1.0 * 10⁻¹⁴ M²

The hydronium ion concentration of the given solution can be calculated as follows:

[H₃O⁺ ] * [OH⁻] = Kw

[OH⁻] = 2.61 * 10⁻⁹ M

Kw = 1.0 * 10⁻¹⁴ M²

[H₃O⁺ ] = Kw / [OH⁻]

[H₃O⁺ ] = 1.0 * 10⁻¹⁴ M² / 2.61 * 10⁻⁹ M

[H₃O⁺ ] = 3.83 * 10⁻⁶

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Answer:

Boyle's law

Explanation:

Answer: The answer would be deciduous (answer E)

Explanation: A deciduous is a term which means “ Tending to fall off” or “falling off at maturity” in reference to trees and shrubs that seasonally shed leaves, usually in autumn (fall); to the shedding of petals, after flowering; and to the shedding of ripe fruit!

Answer:

Deciduous

Explanation:

Answer:

Median is 29.

Explanation:

add all them up and divide them

Answer:

4,890,000,000,000

Explanation:

To convert out of scientific notation, you would take the beginning number and move the decimal to the right 12 spaces.

(keep in mind that if the twelve was negative you would move to the left 12 spaces)

The given examples depict law of reciprocal proportions.

Jeremias Ritcher put forward the law of reciprocal proportions in 1792. The ratio of the masses in which they do so is either the same or a simple multiple of the mass ratio in which they combine, according to the statement, "If two different elements combine independently with the same weight of a third element."

a. Metal oxide contains

M = 0.46 g.

O = 0.77−0.46 = 0.31 g

Therefore, weight of oxygen that combines with 1g of

Metal = 0.31/0.46 = 0.674 g

b. 0.82g of Metal liberates H₂ = 0.00009 × 760 = 0.068g

Thus, the weight of H₂ that will be liberated by 1g of

Metal = 0.068/0.82 = 0.083 g

According to (a) and (b) the ratio of the weight of O:H that combine with or is displaced by the same weight of metal is 0.674:0.083 or 8:1.

Again according (c ), 1.25g of water contains

O= 1.12g and

H 1.25 − 1.11 = 0.14g

Therefore, The ratio of O:H::1.11:0.14 or 8:1

Hence, that ratio being the same, the law of reciprocal proportions is illustrated.

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