what is the formula for strontium chlorate

The substances would look as follows;

Let us recall that just like solids, the density of the solids is important in the determination of how the mixture of the substances would appear. The substances that are denser would tend to appear below while the substances that are less dense would tend to appear above.

Let us remind ourselves the densities of each of the substances as a hep to where we are going;

Water - 1 g/cm³

Mercury - 5.43 g/cm³

Kerosene - 0.82 g/cm³

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Answer:

6.15 moles

Explanation:

1 mole of C has 6.02 x 10^23 atoms

the number of mole in 3.7 x 10^24 is

(1 mole)(3.7 x 10^24)/(6.02 x 10^23)

= 6.15 moles

The theoretical yield of All3 obtain from the reaction is 121g.

2Al + 3I₂ —> 2AlI₃

Molar mass of I₂ = 2 × 127 = 254 g/mol

Molar mass of I₂ from the equilibrium equation = 3 × 254 = 762 g

Molar mass of AlI₃ = 27 + (3 × 127) = 408 g/mol

Mass of AlI3 from the equilibrium equation = 2 × 408 = 816 g

762 g I₂

From the balanced formula above,

762 g I 2 is The reaction produced by 816 g of All3.

From the balanced equation above,

gives 762 g of I2, which reacts to form 816 g of AlI3 121g.

Convert grams to moles using molar ratios to crosslink products and reactants and convert moles back to grams. Calculated on a stoichiometric basis. Actual yield is determined experimentally. The yield rate is determined by calculating the ratio of actual yield/theoretical yield.

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The Net force is 20.12 N  and acts in a direction 26.56° South of East.

A net force is a force that is the vector sum of all the forces acting on an object.

The net force is also known as the resultant force.

The net force produces the same effect as all the forces acting together on an object.

The net force of the given forces in the diagram is calculated as follows:

The forces acting on the object are an 18 N force acting in a direction to the east and a 9 N force acting vertically downward in a direction south of the object.

The two forces form two sides of a right angle triangle.

Net force is calculated using Pythagoras' rule:

Net force = √ (18² + 9²)

Net force = √ (324 + 81)

Net force = √ 405

Net force = 20.12 N

The direction of the Net force = tan⁻¹ (9 / 18)

The direction of the Net force = tan⁻¹ 0.5

The direction of the Net force = 26.56° South of East

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The maximum amount of sulfur dioxide (SO₂) that can be formed is 25.6 g.

The formula for the the limiting reagent is CO

The amount of excess reagent that remains after the reaction is 3.6 g.

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

The limiting reagent is determined by balancing the chemical equation as follows;

S + 2CO  --------> SO₂ +  2C

From the reaction above;

1 mole of sulfur = 2 mole of carbon monoxide = 1 mole of sulfur dioxide

56 g of carbon monoxide (CO)  = 64 g of sulfur dioxide (SO₂ )

22.4 g of CO = ? of SO₂

= (22.4 x 64)/56

= 25.6 g of SO₂

Thus, the maximum amount of sulfur dioxide (SO₂) that can be formed is 25.6 g.

The formula for the the limiting reagent is CO because it will be completely used up.

56 g of CO = 32

22.4  of CO  = ?

= (22.4 x 32)/56

= 12.8 g

Excess mass of the sulfur that remains = 16.4 g - 12.8 g = 3.6 g

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Taking into account the reaction stoichiometry, if 42.9 g of iron is reacted with 27.5 g of oxygen, 61.335 grams of iron(III) oxide are produced.

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 96 grams of O₂ reacts with 223.4 grams of Fe, 27.5 grams of O₂ reacts with how much mass of Fe?

mass of Fe= (27.5 grams of O₂× 223.4 grams of Fe)÷ 96 grams of O₂

mass of Fe= 63.995 grams

But 63.995 grams of Fe are not available, 42.9 grams are available. Since you have less mass than you need to react with 27.5 grams of O₂, Fe will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 223.4 grams of Fe form 319.4 grams of Fe₂O₃, 42.9 grams of Fe form how much mass of Fe₂O₃?

mass of Fe₂O₃= (42.9 grams of Fe×319.4 grams of Fe₂O₃)÷ 223.4 grams of Fe

mass of Fe₂O₃= 61.335 grams

Then, 61.335 grams of Fe₂O₃ are produced.

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The number of copper atoms are in 5.33mol CuCl2 =5.33 ​ × 6.023 × 1023 = 3.21 × 1024

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Answer:

1368.9 [gr].

Explanation:

1. the formula of the required mass is:

m=Mν, where M=[gr/mol] and ν=[moles];

2. M=M(NaCl)=M(Na)+M(Cl)=23+35.5=58.5 [gr/mol];

ν=23.4 [moles] according to the condition, then

3. the required mass:

m=23.4*58.5=1368.9 [gr].

Answer: what?

Explanation:

Answer: Huh?

Explanation:

Plastic items are not biodegradable and contaminate the environment, petroleum is a non-renewable resource, and processing and consuming petroleum emits toxins into the environment.

We refer to a substance as being biodegradable if it can be naturally broken down by living things in an environment. Simply explained, the term "biodegradable" refers to a substance that gradually deteriorates into smaller parts like gases and sugar. Microorganisms, such as fungi and bacteria or microbes to be reabsorbed by the surrounding environment, ideally without generating any pollutants, are responsible again for biodegradation.

Examples of biodegradable materials that microbes can break down include food and paper waste.

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The moles of SO₂ formed if you have 467.2 g of ZnS and excess O₂ is 4.79 moles.

The balanced chemical reaction of the give equation is-

2 ZnS(s) + 3 O₂(g) → 2 ZnO(s) + 2 SO₂(g)

What is mole?

Mole is defined as fundamental measurement unit which is used to measure the amount of substance.

Number of moles of ZnS = Given mass

                                             Molar mass

Moles of ZnS = 467.2 g

                          97.47 g/mol

Moles of ZnS = 4.79 moles

From the reaction, we know that

2 moles of ZnS forms 2 moles of SO₂

4.79 moles of ZnS forms 2 x 4.7 moles of SO₂

                                         2

Moles of SO₂ = 4.79 mol

Hence, the moles of SO₂ can be formed is 4.79 moles.

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The density of a solution with a mass of 5,780.1 ng and a volume of 995 gallons is calculated as 5.736. Grams per cubic centimeter can be stated as SI unit of measurement for density.

Either you have to measure the solid's dimensions or measure the liquid's volume using a measuring jug. To get a number in meters cubed, convert any necessary units.

Further in order to determine the mass of the object or material, place it on a scale.

Density is the mass of a material or substance that is calculated per unit volume. d = M/V, where d can be stated as density, M as mass, and V as volume, that is the formula for density.

The amount of "stuff" is contained in a specific quantity of space is determined by its density. For instance, a block of the harder, lighter element gold (Au) will be denser than a block of the heavier element lead (Pb) (Au).

Styrofoam blocks are less dense than bricks. Mass per unit volume is how it is defined.

Typically, there are two forms of density: absolute density and relative density. Relative

Density = m/v

= 5780.1/995

= 5.736

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The term mole concept is used here to determine the molar mass of an element. The molar mass of the element is 80.62 g/ mol.

One mole of a substance is that quantity of it which contains as many particles or entities as there are atoms in exactly 12 g of carbon -12. The equation which is used to calculate the number of moles is:

The mass of one mole of molecules of a substance is defined as the molar mass. It is generally expressed in g mol⁻¹

Number of moles = Given mass / Molar mass

Here the given mass of the element is 10.4 g. The number of moles of the element is 0.129 mole. Then the molar mass is:

Molar mass = Given mass / Number of moles

= 10.4 g / 0.129 mol

= 80.62 g/ mol

Thus the molar mass of element is 80.62 g/ mol.

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The following graph shows water solubility of some salts versus temperature curves on the chart shows the melt that has the largest solution temperature is the curve b

Water solubility is the because of its polarity and ability to form hydrogen bonds and also water makes an excellent solvent means it can dissolve so many kind of molecules

Here given graph shows water solubility of some salts versus temperature and in that curve a, c and d  show the low temperature but b curve show almost high temperature and that's why the melt that has the largest solution temperature and also has a positive sign and curve c and d are show constant water solubility and curve b shoe first high then low and then more high that's why the curve b has the largest temperature

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The molarity of a CaCl₂ solution that is prepared by dissolving 27.1 g of CaCl₂ in sufficient water to give 779 mL of solution is 0.31M.

Molarity is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

The molarity of a substance can be calculated by dividing the number of moles of the substance by the volume.

According to this question, 27.1 g of CaCl₂ is dissolved in sufficient water. The number of moles can be calculated as follows:

moles = 27.1g ÷ 110.98 g/mol

moles = 0.24mol

Molarity of CaCl₂ = 0.24mol ÷ 0.779L

Molarity of CaCl₂ = 0.31M

Therefore, 0.31M is the concentration required to prepare by dissolving 27.1 g of CaCl₂ in sufficient water.

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Answer:

Explanation:

i dont kow

The complete ionic equation and the net ionic equation for the reaction of aqueous ammonia and aluminum nitrate is written as follows:

[tex]Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)[/tex]

[tex]Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)[/tex]

In an ionic equation all the ions are charges are balanced to the proper stoichiometric ratio. The states of each species have to be written in the brackets.

The reaction of aluminum nitrate and aqueous ammonia is written as follows:

[tex]Al(NO_{3})_{3}(aq) + 3NH_{4}OH(aq)\rightarrow Al(OH)_{3}(s) +3NH_{4}NO_{3}(aq)[/tex]

The complete ionic equation is written below:

[tex]Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)[/tex]

From this complete ionic equation the net ionic equation can be written by cancelling same species from both side as below:

[tex]Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)[/tex]

Therefore, the net product aluminum hydroxide is precipitated and the net ionic equation is written as above.

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The engineer determining the effectiveness of a new machine that produces ammonia from hydrogen and nitrogen is an example of a) Manufacturing and testing a prototype.

Ammonia can be obtained using the process called Haber's process. In designing a machine for manufacturing ammonia, a series of steps are to be taken. The first step is to identify the problem and the second is to find solutions to the problem.

To make the solutions obtained to be in practice, the third step includes drafting a strategic plan and design. After obtaining the design the last step is to test the design for its efficiency.

In the case of the machine designed for manufacturing Ammonia, determining the effectiveness of the machine could be tested by manufacturing and testing a sample.

Hence, the correct option is a).

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The question requires us to balance a given reaction and then determine the excess reagent for this same reaction, given that 3.4 moles of Ca(NO3)2 and 2.4 moles of LiPO4 are used.

First, let's balance the equation so we can make the required calculations from it. A simple way to balance this reaction is to start with metals (Li and Ca) and consider the anions NO3 and PO4 instead of the isolated N, O and P atoms:

1) We write the given equation:

___Ca(NO3)2 + ____Li3PO4 --> ___LiNO3 + ____Ca3(PO4)2

2) We check the amount of Ca and Li on both sides of the reaction:

On the left side -> 1 Ca and 3 Li

On the right side -> 3 Ca and 1 Li

3) Then, we change the coefficients in order to have the same amount of Ca and Li on both sides:

3

4) Next, we check the amount of NO3 and PO4 anions:

Left side -> 3*2 NO3 = 6 NO3 and 1 PO4

Right side -> 3*1 NO3 = 3 and 2 PO4

4) We need to adjust some numbers in order to have the same amount of all considered species:

5) At last, we check again:

Left side -> 3 Ca, 6 NO3, 6 Li, 2 PO4

Right side -> 3 Ca, 6 NO3, 6 Li and 2 PO4

a) Then, the balanced reaction is:

1

b) Now that we know the stoichiometric coefficients, we can determine the excess reagent.

From the balanced reaction, we know that we need 3 moles of Ca(NO3)2 to react with 2 moles of Li3PO4. Then, we can write:

3 mol Ca(NO3)2 --------------- 2 mol Li3PO4

3.4 mol Ca(NO3)2 ------------ x

exexcesslimiting (more than 2.27 moles)

We can also determine the excess reactant from the following relation:

y ------------- 2.4 mol Li3PO4

In this case, solving for y, we have that we would need 3.6 moles of Ca(NO3)2 to react with 2.4 moles of Li3PO4, meaning that there is less than required of Ca(NO3)2, thus this is the limiting reactant while Li3PO4 is the excess reactant.

I fell confident that I can identify the different rates of chemicals.

This is known to be be a powerful diagnostic tool and it is called a reaction's rate. It is one that is seen when we can create methods to increase production by understanding how quickly items are made and what slows down reactions.

Therefore, reaction rate, in regards to chemistry, is seen as the speed with which a said or given chemical reaction moves or functions.

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In an aqueous solution of ethanol, C₂H₅OH, the molecules that would be present in the solution are ethanol molecules and water molecules.

Aqueous solutions are solutions containing water as the solvent of the solution.

An aqueous solution simply means dissolved in water.

When dissolved in water, ionic compounds dissociate to form ions in aqueous solutions.

Other polar solutes which are non-ionic will simply dissolve in water as a result of the interaction of the polar ends of the molecules. However, no ions will be formed by these polar non-ionic solutes.

For example, a solution of ethanol in water is a non-ionic aqueous solution.

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Answer:

Explanation:

6.78 kg

We can use the law of ideal gases to solve this question.

The law of ideal gases is represented by the following formula:

Where P is the pressure, v is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

The first step is to convert kPa to atm, °C to K and mL to L.

Now, we can use these values to find n, which is the amount of moles of the gas:

The answer is 0.00264 moles of chlorine are released.

Answer:

Guys’ search it up on math thank me later

Explanation:

dhsjdjsusysgtjghtd fjfhfhcchdh

Since Tricia is investigating a crime, the best form of remedy that Tricia can use to solve this  issue is option A. She should talk to witnesses who observed the crime.

A witness is said to be a term that is defined as a person who has observed an occurrence or who testifies to what they have observed.

Note that a person who witnesses a robbery as well as testifies in court about what they observed is an example of a witness and they are the best people to get accurate information regarding the crime from.

Hence, option A is correct.

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Answer:  A

Explanation:

Explanation:

Molality is the ratio of the amount of substance of a solute (in moles – n) to the mass in kilograms of the solvent (m).

The symbol for molality is usually W and it can be calculated by the following formula:

W = n/m

here, we need to calculate n of NaCl using the formula:

n = m/MM

where MM of NaCl is 58.5 g/mol

n = 120/58.5

n = 2.05 moles

W = 2.05/30

W = 0.068 mol/Kg

Answer: A) 0.068

Answer:

Explanation:

Here's a quick review of the types of reactions.
Synthesis:
Two or more chemicals combine to make a new one.
Ie: A+B => AB or A+B => C

Decomposition:
The opposite of synthesis.
Ie: AB => A+B, C => A+B

Combustion:
Usually something reacting with oxygen. That something usually being a carbohydrate.
Ie: CH4 + 2O2 => CO2 + 2H2O

Single replacement:
One atom or molecule of a compound is knocked out of place and replaced by another chemical
Ie: A+BC => AB + C (note how the bond between B and C break while a bond between A and B form)

Double replacement:
A little like a single replacement, but two bonds break and two new bonds form between two reactants.
Ie: AB+CD => AC+BD

The actual answer

The first equation (2C3H7OH + 9O2....)
Is a combustion reaction because it contains oxygen and the oxygen is oxidizing something.

The second equation (2Al + 3 ZnCl2...)
Is a single replacement reaction because only one type of bond is being broken (the Zn---Cl bond) and only another one type of bond is formed (The Al---Cl bond)

The third equation (NaCl + AgNO3...)
Is a double replacement reaction because two types of bonds are being broken (Na---Cl and Ag---NO3) and two new bonds are forming (Ag---Cl and Na---NO3)

The fourth equation (N2H8CO3...)
Is a decomposition reaction because there is only one reactant and it is splitting into multiple pieces

The fifth equation (2Al + 3Br2...)
Is a synthesis reaction because two elements/ compounds are being combined to make a singular new compound

a) The percentage of presence in nature of 1st 2nd and 3rd isotopes is 92.2% 4.7 %  and 3.1 %.

b) The chemical symbol for isotopes is ²⁸Si , ²⁹Si , ³⁰Si.

Element with atomic number 14 silicon . chemical symbol is Si.. Four isotopes of silicon's occur in natural environment-  ²⁸Si , ²⁹Si , ³⁰Si ³²Si. The ²⁸Si , ²⁹Si , ³⁰Si is stable isotopes. And the fourth one ³²Si is radiogenic. Silicon atom have mass of 28 amu. ²⁸Si is the most abundant isotope of silicon has percentage of 92.2% . ²⁹Si is 4.7 % and the third is ³⁰Si is 3.1 %.

Thus, An unknown element Y with atomic number 14 is found in nature as a mixture of three isotopes. isotopes 28 has percentage of 92.2 % and isotopes 29 which has percentage of 4.7 %.the third isotopes is 30.

a) The percentage of presence in nature of 1st 2nd and 3rd isotopes is 92.2% 4.7 %  and 3.1 %.

b) The chemical symbol for isotopes is ²⁸Si , ²⁹Si , ³⁰Si.

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