if a domain is "all real numbers" can it be a function?

Answer:

d. -8x+102

Step-by-step explanation:

I also checked my answer, BTW. You can too, but i KNOW that it's correct. :)

Answer:

3.30=90

17/1=17

90+17=107

Step-by-step explanation:

Over 7 years, there would be 49% increase, so 600 (1.49) = 894

$894

Answer:

y=4x-2

Step-by-step explanation:

Answer:

EF+FG =EG

18 + FG =20

FG = 20-18

FG = 2

Answer:

[tex]ef \: + \: fg \: = eg \\ \\ 18 + fg = 20 \\ \\ fg = 20 - 18 \\ \\ fg \: = \: 2[/tex]

Answer:

-27/20

Step-by-step explanation:

i just went with the picture bc your question doesnt even match the picture, it shows adding not dividing. but change them to have common denominaators,  then add the negative numbers, -12/20 + (-15/20), which is -27/20.

Answer:

4/5

sorry for bad writing

Answer:

(4,0)

4 is the X intercept

Step-by-step explanation:

3y = -2x + 8

3y - 8 = -2x

-2/3y + 4 = x

Answer:

[tex]\huge\boxed{\sf x\° = 31.8\°}[/tex]

Step-by-step explanation:

Using one of the trigonometric ratios.

sin x° = opposite / hypotenuse

Where: opposite = 39, hypotenuse = 74

sin x° = 39/74

x° = sin⁻¹ 39 / 74

x° = 31.8°

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

use the EQUATION of Sine Cosine Tangent rule

Step-by-step explanation:1

1.Do the pythagoras  theorem

2.use the equation

i guess you can take it from here

Mark me as brainiest if you find this helpful a bit

The fomula is y=mx+b

The number before x is the slope! Rise over run.

The + __ number is the y-intersect. use this number to place a point on the Y line.

Answer:

[tex]5\sqrt{3}[/tex]

Step-by-step explanation:

simplify sqrt(12): [tex]\sqrt{12} = \sqrt{4 * 3} = \sqrt{4} * \sqrt{3} = 2 * \sqrt{3} = 2\sqrt{3}[/tex]

simplify sqrt(27): [tex]\sqrt{27} = \sqrt{9 * 3} = \sqrt{9} * \sqrt{3} = 3 * \sqrt{3} = 3\sqrt{3}[/tex]

substitute into original equation: [tex]\sqrt{12} + \sqrt{27} = 2\sqrt{3} + 3\sqrt{3}[/tex]

factor out sqrt(3): [tex]\sqrt{3} * (2 + 3)[/tex]

simplify: [tex]\sqrt{3} * 5 = 5\sqrt{3}[/tex]

Answer:

168 girls

Step-by-step explanation:

126 boys and 168 girls.

Answer:

The answer should be 168 female students.

Step-by-step explanation:

Since the ratio of males to females is 6:8 and there's 126 male students, by dividing 126 by 6 you can get 21 then using that 21 you can multiply it by 8 to find how many female students there are which is 168 and dividing 126:168 by 21 you can get 6:8.

126 divided by 21=6

168 divided by 21=8

Answer:

8

Step-by-step explanation:

f(x) = (x+2)(x-2)

Substituting x=1 into f(x):

f(1) = 3*-1

     = -3

Since -2 & 2 touch the x-axis, 1 has a negative y value, 2 has a y value of 0, and all values from 2, are positive.

Hence,

3, 4, 5, 6, 7, 8, 9, 10 are all positive. Therefore, the answer is 8

This can be confirmed with a graph, as attached below.

Feel free to mark this as brainliest! :D

Answer:

it would be 1000 because the last number is 7 which is greater than 5 so that rounds the 97 to the 100 and that would make to whole number altogether 1000!

Step-by-step explanation:

Hope this helps :)

Pls make brainliest :p

And have an amazing day <3

Answer:

Midpoint: (-1, -5)

Endpoint: (-3, -6)

Step-by-step explanation:

Midpoint:

(1-3)/2 and (-4-6)/2

(-1, -5)

The quantity of pounds of nuts and oats used by Paul is 20 and 10 pounds respectively.

According to the question:

The information above can be used to generate two equations as follows;

Consequently, by solving the equations simultaneously; we have;

Read more:

https://brainly.com/question/12413726

Answer:

Jamal should find the Length of each leg by Subtracting the x coordinates and the y-coordinates and y-coordinates.

Step-by-step explanation:

Ansewer for Edmentum:)

Jamal's next step is : Jamal should find the length of each leg by subtracting x coordinate and y coordinate

"It is a triangle whose one the angle measures 90°"

"In a right triangle [tex]c^{2} =a^{2} +b^{2}[/tex] where c is the hypotenuse and a, b are other two sides of right triangle."

"The distance between two points [tex](x_1,y_1),(x_2,y_2)[/tex] is given by [tex]s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] "

For given question,

Jamal wants to find the length of 'd'

For right triangle in the figure, 'd' is the hypotenuse.

Jamal should find the other two sides of the triangle.

And then using Pythagoras theorem, Jamal can find the length of 'd'

So, Jamal need to find the length of each leg by subtracting x coordinate and y coordinate.

Therefore, Jamal's next step is : Jamal should find the length of each leg by subtracting x coordinate and y coordinate

Learn more about distance here:

https://brainly.com/question/2287272

#SPJ3

Answer:

56

Step-by-step explanation:

Answer:

29000

Step-by-step explanation:

2000+900= 2900

2900x10= 29000

Answer:

hi

Step-by-step explanation:

I don't know it just makes sense

Step-by-step explanation:

3n+1/2n+4=4n+1

3n+4n+1/2n=4+1

7n+1/2n=5

7.5n=5

Divide both sides by 7.5

5 divided by 7.5=

0.666

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

1. Find Angle A :

Angle A :

2. Find Angle B :

Angle B :

Find Angle C :

Angle C :

Find Angle D :

Angle D :

And it's given :

Therefore, the answer will be " BAHE "

Answer:

6 apples

Step-by-step explanation:

Answer: x = 45 and y = 10

Step-by-step explanation: in the picture

Please give me a brainliest answer

Answer:

wouldn't it be 17 meters?

=========================================================

Explanation:

Draw a right triangle. The horizontal leg is 8 meters. The hypotenuse is 9 meters. The vertical height is unknown, so we'll call it x.

Apply the pythagorean theorem to solve for x

[tex]a^2 + b^2 = c^2\\\\8^2 + x^2 = 9^2\\\\64 + x^2 = 81\\\\x^2 = 81-64\\\\x^2 = 17\\\\x = \sqrt{17}\\\\x \approx 4.1231056\\\\x \approx 4.12\\\\[/tex]

The tree is approximately 4.12 meters tall

Check out the diagram below.

Explanation:

Start at the point (-1,-4). In order to move to (0,0), we must do the following two steps:

This indicates slope = rise/run = 4/1 = 4.

You could use the slope formula to get this same result.