If a = 5^x, b = 5^y and a^y×b^x = 25 then prove that: xy =1​

[tex]a = {5}^{x} \\ b = {5}^{y} \\ {a}^{y} \times {b}^{y} = 25 \\ prove \: ( {5}^{x} )^{y} \times ( {5}^{y} ) ^{x} = 25 \\ {5}^{xy} \times {5}^{yx} = {5}^{2} \\ {5 }^{xy + yx} = 5^{2} \\ 5^{2xy} = {5}^{2} \\ is \: \: 2xy = 2 \\ xy = \frac{2}{2} \\ xy = 1[/tex]

The prove that  xy is equal to 1 is given below.​

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

[tex]log_a(c) b = \log_a(c)[/tex]

'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'

Some properties of logarithm are:

[tex]\log_a(b) = \log_a(c) \implies b = c\\\\\log_a(b) + \log_a(c) = \log_a(b \times c)\\\\\log_a(b) - \log_a(c) = \log_a(\frac{b}{c})\\\\\log_a(b^c) = c \times \log_a(b)\\\\\log_b(b) = 1\\\\\log_a(b) \times log_b(c) = \log_a(c)[/tex]

Log with base e = 2.71828... is written as

ln(x)\ln(x)

simply.

Log with base 10 is written as

[tex]\log(x)[/tex]

We are given that;

a = 5^x, b = 5^y and a^y×b^x = 25.

Now,

To prove that xy = 1, we can use the properties of exponents and logarithms. Here are the steps:

1. Given that a = 5^x and b = 5^y, we can substitute these expressions into the equation a^y×b^x = 25 and get:

(5^x)^y × (5^y)^x = 25

2. Using the property that (a^b)^c = a^(bc), we can simplify the left-hand side of the equation and get:

5^(xy + yx) = 25

3. Using the property that a^b = c is equivalent to log_a(c) = b, we can take the logarithm of both sides of the equation with base 5 and get:

log_5(5^(xy + yx)) = log_5(25)

4. Using the property that log_a(a^b) = b, we can simplify the left-hand side of the equation and get:

xy + yx = log_5(25)

5. Using the property that log_a(b) = log_c(b) / log_c(a), we can change the base of the logarithm on the right-hand side of the equation to any other base, such as 10, and get:

xy + yx = log_10(25) / log_10(5)

6. Using a calculator or a table of logarithms, we can evaluate the right-hand side of the equation and get:

xy + yx ≈ 2 / 0.69897

7. Simplifying the fraction on the right-hand side of the equation, we get:

xy + yx ≈ 2.8614

8. Since xy and yx are symmetric, we can divide both sides of the equation by 2 and get:

(xy + yx) / 2 ≈ 2.8614 / 2

9. Simplifying both sides of the equation, we get:

xy ≈ 1.4307

10. Since x and y are integers, we can conclude that xy must be an integer as well. The only integer that is close to 1.4307 is 1.

Therefore, by logarithm properties we can say that xy = 1.

Learn more about logarithm here:

https://brainly.com/question/20835449

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