I need help with questions b and d, that’s all.

Thank you.

Answer:

Displacement

Explanation:

The quantity 45m north is a typical example of displacement.

Displacement is the distance traveled by a body in a specific direction. Displacement is a vector quantity with both magnitude and direction.

Answer:

a) wooden floor  

      a = 3170.6 m / s²,    t = 1.03 10⁻³ s

the child's traumatic injury to the brain

b) the floor is carpeted

      a = 385 m / s²

no injuries are created in the child

Explanation:

To solve this exercise we can use the energy conservation relations, let's start by looking for the speed of the child when he is just reaching the ground

starting point. When you get out of bed

         Em₀ = U = m g h

final point. Just when it hits the floor

          [tex]Em_{f}[/tex] = K = ½ m v²

as there is no friction, energy is conserved

           Em₀ = Em_{f}

           mgh = ½ m v²

           v² = 2 gh

let's calculate

          v² = 2 9.8 0.55

          v² = 10.78

           v = 3.28 m / s

Now let's use the concepts of kinematics to find the deceleration. The case of the wooden floor, where the distance for the deceleration is

x = 1.7 mm = 0.0017 m

      v² = v₀² - 2 a y

as the child stops the final velocity is zero

      0 = v₀² - 2a y

      a = v₀² / 2y

let's calculate

      a = [tex]\frac{10.78}{2 \ 0.0017}[/tex]

      a = 3170.6 m / s²

Let's find the time that braking lasts

        v = v₀ - a t

         0 = v₀ - at

          t = v₀ / a

         t = 3.28 / 3170.6

         t = 1.03 10⁻³ s

hence the child's traumatic injury to the brain

second case the floor is carpeted, in this case the stopping distance is

x = 1.4 cm = 0.014 m

we look for acceleration

         a = v₀² / 2y

         a = [tex]\frac{10.78}{2 \ 0.014}[/tex]

         a = 385 m / s²

therefore no injuries are created in the child

In conclusion we see that with the wooden floor there is silence and with the carpeted floor there is no

Without friction, NO.

The speed at D depends only on the difference in height between A and D. Whatever happens between them doesn't matter.

The speed of the coaster car at point D will be affected if  the height of point C is changed.

Potencial Energy:

It is the enrgy in a body due to the position of differnt part of the object or system.

As we increase the the hight of the car the potetial enrgy increase, the gravitational acceleration on car will be more due to the high of the point C.

Therefore, the speed of the coaster car at point D will be affected if  the height of point C is changed.

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Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        [tex]F_{y} + F_{y} - W =0[/tex]

        2[tex]F_{y}[/tex] = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = [tex]\frac{ 800}{ 2sin 2.29}[/tex]

        T = 10010 N

Answer:

Explanation:

The same as its weight before adding the duck

Answer:

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Explanation:

Let A be the area of the capacitor plate

The capacitance of a capacitor is given as;

[tex]C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\[/tex]

where;

V is the potential difference between the plates

The charge on the plates is given as;

[tex]Q = \frac{V\epsilon _0 A}{d}[/tex]

The energy stored in the capacitor is given as;

[tex]E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2[/tex]

Thus, the physical variables listed that will change include;

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Answer:

To have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Explanation:

The general formula of kinetic energy is given as follows:

[tex]K.E = \frac{1}{2}mv^{2}[/tex]

where,

K.E = Kinetic Energy

m = mass of the object

v = speed of the object

So, for the marble and rock to have same kinetic energy, we can write:

[tex]K.E_{marble} = K.E_{rock}\\\\\frac{1}{2}m_{marble}v_{marble}^{2} = \frac{1}{2}m_{rock}v_{rock}^{2}\\\\(0.03\ kg)v_{marble}^{2} = (2.43\ kg)v_{rock}^{2}\\\\taking\ square\ root\ on\ both\ sides:\\v_{marble} = \sqrt{\frac{2.43\ kg}{0.03\ kg}}v_{rock}\\\\v_{marble} = 9\ v_{rock}[/tex]

Hence, to have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Answer:

i honestly think its 21

Explanation:

da memes

10 + 10 =21

Answer:

A system that includes the stone and the earth.

Explanation:

If the system of being dropped from the height of the cliff consists of just the stone alone, then it means that its momentum will certainly undergo changes as it falls freely. However, If the system is now expanded to include not only the stone but also the Earth, then it implies that the momentum of the stone which is in the downward direction will be equal and opposite to the momentum of the Earth in the upwards direction towards the stone. Therefore, the momentum will cancel out and net momentum will be zero.

A system of stone and earth can result to a net zero momentum.

The principle of conservation of linear momentum states that the sum of the initial momentum is equal to the sum of final momentum.

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2 v_2[/tex]

A system that consists a linear system of stone and earth can result to a net zero momentum.

Thus, a system of stone and earth can result to a net zero momentum.

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Answer:

a = 5 m/s^2

Explanation:

First, we look at Newton's 2nd Law:

F = ma

We now plug in the values,

10 N = 2 kg * a

10 N/2 kg = a

5 m/s^2 = a

Answer:

Explanation:

Momentum is mass multiplied by velocity, p = mv

Velocity is just speed but with a direction. So they can essentially be considered the same thing as long as you acknowledge this fact and understand where each is applied.

12)

First convert the grams to kilograms, those are the standard units us physicists use.

p = (1.25 kg)(17 m/s)

=21.25 kg*m/s

13)

p = mv

32,023.2 kg*m/s = (1,320 kg)(x m/s)

x = 24.26 m/s

The time of the day she spent walking is equal to 3.70 hrs.

Power can be explained as the rate of doing work in unit time. The SI unit of measurement of power is J/s or Watt (W). Power can be described as a time based quantity. The mathematical expression for power can be represented as mentioned below.

Power = work/time

P = W/t

Given, the energy spends part of her day walking, Ew = 280 W

The energy is spent by sitting in the class, Es = 100 W

The total energy spends, Et = 1.1 × 10⁷J

[tex]E_w \times t + E_s(24\times 60\times 60-t)= 1.1 \times 10^7J[/tex]

[tex]280 \times t + 100(24\times 60\times 60-t)= 1.1 \times 10^7[/tex]

280 t + 0.86 × 10⁷ - 100 t = 1.1 × 10⁷

180 t = 0.24 × 10⁷

t =  0.24 × 10⁷/180 × 3600

t = 3.70 hr

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Answer:

The response to this question is as follows:

Explanation:

The whole question and answer can be identified in the file attached, please find it.

The force diagram of all the forces acting on the snowball include the normal force acting upwards, the weight of the snowball acting downwards and the frictional force acting horizontal.

The given parameters;

The force diagram of all the forces acting on the snowball is calculated as follows;

                                     ↑ N

                                     ⊕  → F

                                      ↓ W

Where;

Thus, the force diagram of all the forces acting on the snowball include the normal force acting upwards, the weight of the snowball acting downwards and the frictional force acting horizontal.

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Answer:

The work done by the applied force is 259.22 J.

Explanation:

The work done by the applied force is given by:

[tex] W = F*d [/tex]

Where:

F: is the applied horizontal force = 108.915 N

d: is the distance = 2.38 m  

Hence, the work is:

[tex] W = F*d = 108.915 N*2.38 m = 259.22 J [/tex]

Therefore, the work done by the applied force is 259.22 J.

I hope it helps you!                                                

Answer:

33624.32 N

Explanation:

From second law of motion, thrust of engine can be computed as

F= Δp/ Δt

= m1 * Δv + m2 v(o)

F= m1 *[v(o) - v] + m2 *v(o).............eqn(1)

Where

v(o) = initial velocity of the gas when ejected= 487 m/s

v= final velocity=233 m/s

m1= initial rate The engine takes in air at =122 kg/s

m2= rate of burning fuel= 3.36 kg/s.

If we input the given values into eqn (1) we have

F= 122×[ 487-233] + [3.36×487]

F=30988+1636.33

=33624.32 N

Hence, the thrust of the jet engine is 33624.32 N

Answer:

Thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Explanation:

From the concept of Escape Velocity, derived from Newton's Law of Gravitation, definition of Work, Work-Energy Theorem and Principle of Energy Conservation, which is the minimum speed such that rocket can overcome gravitational forces exerted by the Earth, and according to the Tsiolkovski's Rocket Equation, which states that thrust done by the rocket is equal to the change in linear momentum of the rocket itself, we conclude that thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

[tex]v = f\lambda[/tex]

where,

v= speed of wave = ?

f = frequency of wave = [tex]\frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz[/tex]

Therefore,

[tex]v = (0.217\ Hz)(5.5\ m)\\[/tex]

v = 1.2 m/s

Answer:

the unloaded braking efficiency is 84.6 %

Explanation:

Given the data in the question;

by Ignoring aerodynamic resistance; we can find the theoretical stopping distance using the following formula

S = (Y[tex]_{b}[/tex]( V₁² - V₂²)) / ( 2g( ηbμ + [tex]f_{rl}[/tex] ± sin∅[tex]_{g}[/tex]))

now given that the tracked is levelled, ∅[tex]_{g}[/tex] = 0, also Y[tex]_{b}[/tex] = 1.04 for level or flat road

Speed V₁ = 60mil/hr = (60×5280)/(1×60×60) = 316800ft/3600s = 88ft/s

now, we substitute in our values to get the braking efficiency;

180ft = (1.04( (88ft/s)² - 0²)) / ( 2(32.2( (ηb/100)(0.80) + (0.018) ± sin(0°)))

180ft = 8053.76 / ( 64.4)(0.008ηb + 0.018)

180ft = 8053.76 / ( 0.5152ηb + 1.1592)

180( 0.5152ηb + 1.1592)  = 8053.76

( 0.5152ηb + 1.1592) = 8053.76 /180

0.5152ηb + 1.1592 = 44.7431

0.5152ηb = 44.7431 - 1.1592

0.5152ηb = 43.5839

ηb = 43.5839 / 0.5152

ηb = 84.596 ≈ 84.6 %

Therefore,  the unloaded braking efficiency is 84.6 %

Answer:

Barriers to and risks associated with an increasing use of nuclear energy include operational risks and the associated safety concerns, uranium mining risks, financial and regulatory risks, unresolved waste management issues, nuclear weapons proliferation concerns, and adverse public opinion.

Explanation:

All the objects are motionless, so kinetic energy of each object is zero after the collision.

The kinetic energy of an object is defined as the energy which is  possesses due to its motion. It is the work required to accelerate a body of a given mass from rest to its stated velocity. This energy is gained during its acceleration, the body maintains the kinetic energy as long as its momentum does not change.

Kinetic Energy can be expressed as

[tex]K.E.=[/tex] [tex]1/2 mv^2[/tex]

Where, m is the mass of the object

v is the velocity.

It is expressed in joules (J).

After the collision all the objects are at rest, therefore, the final kinetic energy is also zero which shows maximum loss of kinetic energy. Such collisions are called perfectly inelastic.

Thus, all the objects are motionless, so kinetic energy of each object is zero after the collision.

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Answer:

E = 1,720,779.221 or 1.720779221 * 10^ 6V/m

Explanation:

The electric field between the parallel conducting plates is given by

E =V / d

where V is the potential difference and d is the distance between the plates.

E = 26.5 kV/ 1.54 cm

Now we have to convert into proper units

26.5 kv= 26.5 * 1000 v=  26500 volts

1  kv= 1000 volts

1.54 cm = 1.54/ 100 m= 0.0154m

1m = 100cm

Now putting the values

E= 26500/0.0154 = 1,720,779.221 V/m

The Electric field is equal to E= 1,720,799.221 or 1.7220799221 * 10 ^6 Volts per meter.

In scientific notation this can be written as 1.7220799221 *10^6 V/m

Answer:

The MECHANICAL energy of the water is transformed into KINETIC ENERGY

Explanation:

In this exercise you are asked to complete the sentence so that it makes sense.

When the tap is opened, the water has a mechanical energy given by the potential energy due to the height and the energy accumulated by the pressure of the system inside the pipe.

Therefore the sentence must be completed with

The MECHANICAL energy of the water is transformed into KINETIC ENERGY from the moving tap that turns the turbine ...

Answer:

dawg this helped me

Explanation:

i had to do the exact same question thanks homie

A woman walks in a  straight line with the sun to her right at six o'clock in the morning.

The sun rises East of her, so the woman is walking toward the North pole.

A man walks in a straight line with the sun to his right at six o'clock in the  evening.

The sun sets West of him, so the man is walking toward the South pole.

The woman and the man are both walking along lines of constant longitude.

Answer:

[tex]a_2=24.5\ \text{m/s}^2[/tex] towards right

[tex]a_1=2.1875\ \text{m/s}^2[/tex] towards left

Explanation:

[tex]m_1[/tex] = Mass of skater = 56 kg

[tex]m_2[/tex] = Mass of ball = 5 kg

v = Final velocity of ball = 7 m/s

u = Initial velocity of ball = 0

s = Distance the ball moved in the hand of the skater = 1 m

Moving left is considered and moving right is considered positive.

From kinematic equations of motion we have

[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{7^2-0^2}{2\times 1}\\\Rightarrow a=24.5\ \text{m/s}^2[/tex]

So, the ball will move towards right with a magnitude of acceleration [tex]a_2=24.5\ \text{m/s}^2[/tex].

The force on the ball will be

[tex]F_2=m_2a_2\\\Rightarrow F_2=5\times 24.5\\\Rightarrow F_2=122.5\ \text{N}[/tex]

The force on the ball is [tex]122.5\ \text{N}[/tex]

The reaction force on the skater will be equal to the force on the ball but will have opposite direction.

[tex]-F_1=F_2\\\Rightarrow -m_1a_1=F_2\\\Rightarrow a_1=-\dfrac{122.5}{56}\\\Rightarrow a_1=-2.1875\ \text{m/s}^2[/tex]

So, the skater will move towards left with a magnitude of acceleration [tex]2.1875\ \text{m/s}^2[/tex]

After the ball is thrown, the skater will accelerate to the left at 2.19 m/s² while the ball will accelerate to the right at 24.5 m/s².

The given parameters

The acceleration of the ball as it leaves the skaters hand is calculated as follows;

[tex]v^2 = u^2 + 2as\\\\ v^2 = 0 + 2as\\\\ a = \frac{v^2}{2s} \\\\ a = \frac{7^2}{2(1)} \\\\ a = 24.5 \ m/s^2[/tex]

The force experienced by the ball is calculated as follows;

[tex]F = ma\\\\ F_b = 5 \times 24.5\\\\ F_b = 122.5 \ N[/tex]

The force experienced by the skater is equal in magnitude to that of the ball but opposite in direction.

[tex]F_s = -F_b\\\\ F_s = -122.5 \ N[/tex]

The acceleration of the skater after the ball was thrown is calculated as follows;

[tex]F = ma \\\\ a = \frac{F}{m} \\\\ a = \frac{-122.5 }{56} \\\\ a =-2.19 \ m/s^2[/tex]

Thus, after the ball is thrown, the skater will accelerate to the left at 2.19 m/s² while the ball will accelerate to the right at 24.5 m/s².

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Answer:

D

Explanation:

right edge 2022

Answer:

70 kg

Explanation:

divide it by 2

Hope this helped!

Answer:

63.502932 Kilograms

Explanation: