I need help please, i am stuck.

A particular solution will have the form (At^2 + Bt + C)e^(-3t), where A, B, and C are undetermined coefficients.

To determine the form of a particular solution for each differential equation, we need to consider the form of the nonhomogeneous term and choose a solution that has the same form, but with undetermined coefficients.

27. The nonhomogeneous term is 4t sin 3t, which is a product of a polynomial and a sine function. Therefore, a particular solution will have the form At^2 sin 3t + Bt cos 3t, where A and B are undetermined coefficients.

28. The nonhomogeneous term is 5te3, which is a product of a polynomial and an exponential function. Therefore, a particular solution will have the form (At^2 + Bt + C)e3t, where A, B, and C are undetermined coefficients.

29. The nonhomogeneous term is t4e, which is a product of a polynomial and an exponential function. Therefore, a particular solution will have the form (At^5 + Bt^4 + Ct^3 + Dt^2 + Et + F)e^t, where A, B, C, D, E, and F are undetermined coefficients.

30. The nonhomogeneous term is 7e^t cos t, which is a product of an exponential and a cosine function. Therefore, a particular solution will have the form (Acos t + Bsin t)e^t, where A and B are undetermined coefficients.

31. The nonhomogeneous term is 8t'e sin t, which is a product of a polynomial and a sine function. Therefore, a particular solution will have the form (At^2 + Bt + C)cos t + (Dt^2 + Et + F)sin t, where A, B, C, D, E, and F are undetermined coefficients.

32. The nonhomogeneous term is 2t^2 e^(-3t), which is a product of a polynomial and an exponential function. Therefore, a particular solution will have the form (At^2 + Bt + C)e^(-3t), where A, B, and C are undetermined coefficients.

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The two sets of possible dimensions (length and width) of the rectangular plot are:  Length = 21 meters, Width = 13 meters

                                    Length = 8.5 meters, Width = 38 meters

Let L be the length and W be the width of the rectangular plot. We know that the perimeter of the rectangular plot is 55 meters, which can be expressed as:

2L + W = 55

We also know that the area of the rectangular plot is 342 square meters, which can be expressed as:

L * W = 342

We can use these two equations to solve for L and W:

W = 55 - 2L

L * (55 - 2L) = 342

Expanding the left side of the equation and rearranging terms, we get:

2L² - 55L + 342 = 0

We can solve this quadratic equation for L using the quadratic formula:

L = (55 ± √(55² - 42342)) / (2*2)

L = (55 ± √(841)) / 4

L = (55 ± 29) / 4

L = 21 or L = 8.5

Substituting these values of L back into the equation 2L + W = 55, we can solve for the corresponding values of W:

When L = 21, W = 55 - 2L = 13

When L = 8.5, W = 55 - 2L = 38

Therefore, the two sets of possible dimensions (length and width) of the rectangular plot are:

Length = 21 meters, Width = 13 meters

Length = 8.5 meters, Width = 38 meters

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Therefore, s1 and s2 do not span the same subspace of R3.

To determine whether the sets s1 and s2 span the same subspace of R3, we need to check if one set can be obtained as a linear combination of the other set.

We can start by checking if the vectors in s2 can be obtained as a linear combination of the vectors in s1. We can set up the following system of equations:

[tex]a(1, 2, -1) + b (0, 1, 1) + c(2, 5, -1) = (-2, -6, 0)[/tex]

[tex]d(1, 2, -1) + e(0, 1, 1) + f(2, 5, -1) = (1, 1, -2)[/tex]

We can write this system in matrix form as follows:

[tex]\left[\begin{array}{ccc}1&0&2|-2\\2&1&5|-6\\-1&1&-1|0\end{array}\right]*\left[\begin{array}{ccc}1&0&2|1\\2&1&5|1\\-1&1&-1|-2\end{array}\right][/tex]

We can row reduce this augmented matrix to find the solutions for the system of equations:

[tex]\left[\begin{array}{ccc}1&0&2|-2\\0&1&1|2\\0&0&0|0\end{array}\right]*\left[\begin{array}{ccc}1&0&2|1\\2&1&5|1\\0&0&0|0\end{array}\right][/tex]

The matrix on the left represents the coefficients for the linear combinations of the vectors in s1 that would give us the vectors in s2. Since the matrix has a row of zeros, this means that we can't obtain the vectors in s2 as a linear combination of the vectors in s1.

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The simplified expression is [tex]\frac{2x}{x-1}[/tex].

Expression  - An expression or algebraic expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them.

To simplify the expression, we can factor out a 4x from the numerator and a 2 from the denominator, which gives:

[tex]=\frac{4x^2+4x}{2x^2-2}\\\\ = \frac{4x(x+1)}{2(x^2-1)} \\\\ = \frac{2\cdot 2x(x+1)}{2(x-1)(x+1)} \\\\ = \frac{2x}{x-1}[/tex]

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a. This statement is true. We can write b = ak and d = cl for some integers k and l. Then, b + d = ak + cl = a(k + l). Since a|b, we know a must divide ak and thus a also divides ak + cl. Therefore, a + d = a(k + l) is divisible by a.

b. This statement is also true. Similar to part a, we can write b = ak and d = cl for some integers k and l. Then, bd = akcl = (ac)(kl). Since a|b and c|d, we know that a and c must divide ak and cl respectively. Therefore, ac must divide akcl = bd.

c. This statement is false. Consider a = 2, b = 4, c = 2, and d = 6. We have a|b and b|c, but a does not divide c. Therefore, the statement does not hold for all integers a, b, c, and d.

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a. This statement is true. We can write b = ak and d = cl for some integers k and l. Then, b + d = ak + cl = a(k + l). Since a|b, we know a must divide ak and thus a also divides ak + cl. Therefore, a + d = a(k + l) is divisible by a.

b. This statement is also true. Similar to part a, we can write b = ak and d = cl for some integers k and l. Then, bd = akcl = (ac)(kl). Since a|b and c|d, we know that a and c must divide ak and cl respectively. Therefore, ac must divide akcl = bd.

c. This statement is false. Consider a = 2, b = 4, c = 2, and d = 6. We have a|b and b|c, but a does not divide c. Therefore, the statement does not hold for all integers a, b, c, and d.

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Answer:

C

Step-by-step explanation:

K^2 + 4

Answer:k^2+4

Step-by-step explanation:

We can use 740.8 grams of trans-cinnamic acid based on the m moles listed in the lab manual.  The lab manual, you would first need to know the molar mass of trans-cinnamic

To determine how many grams of trans-cinnamic acid should be used based on the m moles listed in the lab manual, we would first need to know the molar mass of trans-cinnamic acid. The molar mass of trans-cinnamic acid is 148.16 g/mol.

Next, you would need to determine the number of m moles of trans-cinnamic acid that the lab manual specifies. Let's say, for example, that the lab manual specifies using 5 m moles of trans-cinnamic acid.

To convert m moles to grams, you would use the following formula:

mass (g) = mmoles x molar mass

So, to find the mass of 5 m moles of trans-cinnamic acid:

mass (g) = 5 x 148.16
mass (g) = 740.8

Therefore, you would use 740.8 grams of trans-cinnamic acid based on the m moles listed in the lab manual.

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The height of the tree to the nearest hundredth is 29.65 ft.

The measure of the distance from the tree and the angle of elevation from the ground to the top of the tree is represented as follows:

Therefore, the height of the tree to the nearest hundredth can ne found as follows:

Therefore, using trigonometric ratios,

tan 56° = opposite / adjacent

tan 56° = h / 20

cross multiply

h = 20 tan 56°

h = 20 × 1.48256096851

h = 29.6512193703

h = 29.65 ft

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An expression that shows the total number of chairs in the auditorium is 9(6+4).

Given that, there are 54 green chairs and 36 red chairs in an auditorium.

To determine the number of green chairs and red chairs in each row, divide 54 and 36 by 9. This gives us 6 green chairs and 4 red chairs in each row.

The total number of chairs can be expressed as the product of 9 and the sum of the green chairs and red chairs in each row.

This is represented by the expression 9(6+4), which is equal to 90 chairs.

Therefore, an expression that shows the total number of chairs in the auditorium is 9(6+4).

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The required variance for the question is var (x - y) is 2.

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So the probability of drawing a card that is a queen or a club is 4/13.

There are 4 queens and 13 clubs in a standard deck of 52 playing cards. However, the queen of clubs is counted in both groups, so we need to subtract it once. Therefore, the total number of cards that are either a queen or a club (excluding the queen of clubs) is 4 + 13 - 1 = 16.

The probability of drawing a card that is either a queen or a club is the number of desired outcomes (16) divided by the total number of possible outcomes (52):

P(queen or club) = 16/52 = 4/13

So the probability of drawing a card that is a queen or a club is 4/13.

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At a 95% confidence level, the margin of error is approximately 0.762 (rounded to three decimal places).

To find the margin of error at a 95% confidence level, we need to first find the critical value associated with a sample size of 29 and a confidence level of 95%.

Using a t-distribution with n-1 degrees of freedom, we can find the critical value using a t-table or calculator. For n=29 and a confidence level of 95%, the critical value is approximately 2.045 (rounded to three decimal places).

The formula for the margin of error is:

Margin of error = critical value * (standard deviation / sqrt(sample size))

Plugging in the values we have:

Margin of error = 2.045 * (2 / sqrt(29))
Margin of error ≈ 0.762

Therefore, at a 95% confidence level, the margin of error is approximately 0.762 (rounded to three decimal places).

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Answer: 0.84375

Step-by-step explanation:

1. x = 5.4n

2. 5.4n + n = 5.4

3. n(6.4) = 5.4

4. n = 0.84375

DOUBLE CHECK

x = 5.4(0.84375)

x = 4.55625

4.55625 + 0.84375 = 5.4

0.84375 = 5.4 - 4.55625

0.84375 = 0.84375

The solution is, : for 0.84375 = N such that x+N=5.4 and x/n=5.4 are equivalent equations.

An equation is a  mathematical statement that is made up of two expressions connected by an equal sign.  In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here, we have,

the given equations are:

1. x = 5.4n

2. 5.4n + n = 5.4

3. n(6.4) = 5.4

4. n = 0.84375

DOUBLE CHECK

x = 5.4(0.84375)

x = 4.55625

4.55625 + 0.84375 = 5.4

0.84375 = 5.4 - 4.55625

0.84375 = 0.84375

Hence, The solution is, : for 0.84375 = N such that x+N=5.4 and x/n=5.4 are equivalent equations.

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To evaluate the iterated integral ∫∫∫ 2z ln(x) xe^(-y) dy dx dz over the limits 0 ≤ y ≤ 6, 0 ≤ x ≤ 8, and 0 ≤ z ≤ 1, we begin by integrating the innermost integral with respect to y first, then the middle integral with respect to x, and finally the outermost integral with respect to z.

So, integrating with respect to y first, we get:
∫∫∫ 2z ln(x) xe^(-y) dy dx dz = ∫∫∫ 2z ln(x) (-e^(-y) + C) dx dz
where C is the constant of integration.
Next, integrating with respect to x, we get:
∫∫∫ 2z ln(x) (-e^(-y) + C) dx dz = ∫∫ 2z (-ln(x)e^(-y) + Cx) |_0^8 dz
= ∫∫ 16z(ln(8)e^(-y) - C) dz
= 16(ln(8)e^(-y) - C)z^2/2 |_0^1
= 8(ln(8)e^(-y) - C)
Finally, integrating with respect to z, we get:
∫∫ 8(ln(8)e^(-y) - C) dz = (8/2)(ln(8)e^(-y) - C)(1^2 - 0^2)
= 4(ln(8)e^(-y) - C)
Therefore, the value of the iterated integral over the given limits is 4(ln(8)e^(-6) - C), where C is a constant of integration.

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Answer: this is how to do it

Step-by-step explanation: x=−3.

x=−4, y=−6

xy-3x=40, x=5

x(y-3)=40

y-3=(40/x)

y=(40/x)+3

y=(40/5)+3

y=8+3

y=11

[tex]\begin{cases} (x-1)^2-(x+2)^2=9y\\\\ (y-3)^2-(y+2)^2=5x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-1)^2-(x+2)^2=9y\implies (x^2-2x+1)-(x^2+4x+4)=9y \\\\\\ (x^2-2x+1)-x^2-4x-4=9y\implies -6x-3=9y\implies -3(2x+1)=9y \\\\\\ 2x+1=\cfrac{9y}{-3}\implies 2x+1=-3y\implies 2x=-3y-1\implies x=\cfrac{-3y-1}{2} \\\\[-0.35em] ~\dotfill\\\\ (y-3)^2-(y+2)^2=5x\implies (y^2-6y+9)-(y^2+4y+4)=5x \\\\\\ (y^2-6y+9)-y^2-4y-4=5x\implies -10y+5=5x[/tex]

[tex]\stackrel{\textit{substituting from above}}{-10y+5=5\left( \cfrac{-3y-1}{2} \right)}\implies -10y+5=\cfrac{-15y-5}{2} \\\\\\ -20y+10=-15y-5\implies 10=5y-5\implies 15=5y \\\\\\ \cfrac{15}{5}=y\implies \boxed{3=y} \\\\\\ \stackrel{\textit{since we know that}}{x=\cfrac{-3y-1}{2}}\implies x=\cfrac{-3(3)-1}{2}\implies \boxed{x=-5}[/tex]

As the Smaller photo: 10 cm  x 10 cm which equals to the dimension of wallet. Thus, the smaller photo will fit into Grace's wallet.

A quadrilateral featuring four right angles is a rectangle. As a result, a rectangle's angles are all equal (360°/4 = 90°). A rectangle also has parallel and equal opposite sides, and its diagonals cut it in half.

The three characteristics of a rectangle are as follows:

Given data:

Dimensions of  photo:

Dimensions of rectangle wallet :

The dimension of the smaller photo must be less than equal to width of the wallet to get fit inside it.

As the Smaller photo: 10 cm  x 10 cm which equals to the dimension of wallet. Thus, the smaller photo will fit into Grace's wallet.

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Complete question:

Grace had her photo printed in two different sizes. One is 11cm x 11 cm and second is 10cm x 10 cm  If her wallet is in the shape of a rectangle 11cm long and 10cm wide, can the smaller photo fit into her wallet?

The measure of the angle in radians is approximately 1.9099 radians and Where radian_angle represents the angle's measure in radians, degree_angle represents the angle's measure in degrees, and π (pi) is approximately 3.1416


a. To convert an angle of 110 degrees to radians, we can use the following conversion formula:

[tex]radians = \frac{(degrees × π) }{180}[/tex]

Step 1: Plug in the given angle (110 degrees) into the formula:
[tex]radians= \frac{110×π}{180}[/tex]

Step 2: Calculate the value:
[tex]radians= \frac{(110)(3.1416)}{180} = \frac{343.7756}{180} = 1.9000[/tex]

So, the measure of the angle in radians is approximately 1.9099 radians.

b. To write a general formula that expresses the radian angle measure of an angle, in terms of the degree measure of that angle, you can use the following formula:
[tex]radian angle= \frac{degree angle x π}{180}[/tex]

Where radian_angle represents the angle's measure in radians, degree_angle represents the angle's measure in degrees, and π (pi) is approximately 3.1416.

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The value of function f(1) = 1/16.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain. The usual way to refer to a function is as f(x), where x is the input. A function is typically represented as y = f(x).

To find f(1), we substitute x = 1 into the given expression for f(x):

f(1) = 4(1/4)⁽¹⁺²⁾ = 4(1/4)³ = 4(1/64) = 1/16

Therefore, f(1) = 1/16.

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Answer:

27.5%

Step-by-step explanation:

Let's denote the total marks of the exam as 'T'.

We know that Tarang got 25% marks and failed by 64 marks, so we can write an equation:

0.25T - 64 = 0 (since he failed)

Solving for T, we get:

T = 256

We also know that if Tarang had got 40% marks, he would have secured 32 marks more than the pass marks. So we can write another equation:

0.4T - Pass marks = 32

Substituting T = 256, we get:

0.4(256) - Pass marks = 32

102.4 - Pass marks = 32

Pass marks = 70.4

Therefore, to pass the exam, Tarang needs to get at least 70.4/T * 100% = 27.5% marks (rounded to one decimal place).

The dimension of the solution space is 2. Therefore, the answer is (B) 2.

The rank of a matrix A is defined as the maximum number of linearly independent rows or columns in A.

Therefore, if the rank of a 7 x 6 matrix A is 4, it means that there are 4 linearly independent rows or columns in A, and the other 3 rows or columns can be expressed as linear combinations of the 4 independent ones.

The equation Az = 0 represents a homogeneous system of linear equations, where z is a column vector of unknowns.

The dimension of the solution space of this system is equal to the number of unknowns minus the rank of the coefficient matrix A.

In this case, A has 6 columns and rank 4, so the number of unknowns is 6 and the dimension of the solution space is 6 - 4 = 2. Therefore, the answer is (B) 2.

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Answer: (x - y) = 13/6

Step-by-step explanation: To find the value of (x-y), we need to substitute the given values of x and y and then perform the subtraction.

So,

(x - y) = (5/3 - (-1/6))

We can simplify this expression by first converting the negative fraction to its equivalent positive fraction and then finding the common denominator.

(x - y) = (5/3 + 1/6) = ((10+3)/6) = 13/6

Therefore, (x - y) = 13/6.

Share Prompt

Answer:

11/6

Step-by-step explanation:

Use substitution.

x = 5/3

y = -1/6

Sub these values into (x-y):

[(5/3) - (-1/6)]

*Make sure to use brackets when subbing in values especially when there are negative signs or exponents

5/3 + 1/6 ⇒ two negatives become a positive

10/6 + 1/6 ⇒ make a common LCD

= 11/6

Answer: Brainliest?

Step-by-step explanation:

To prove the identity 1 + 2 + 3 + ... + n = (n+1)/2 combinatorially, we can use a simple argument involving counting the number of ways to arrange a certain set of objects.

Consider a set of (n+1) objects, consisting of n white balls and 1 black ball. We want to count the number of ways to arrange these objects in a row. Let's call this number N.

On the one hand, we can count N directly by considering the number of choices we have for the first ball, then the number of choices we have for the second ball, and so on, until we have made n choices for the n white balls, leaving only the black ball to be placed in the last position. Using the multiplication principle, we see that N is equal to the product of n consecutive integers, which we can write as:

N = n(n-1)(n-2)...(3)(2)(1)

On the other hand, we can count N indirectly by considering the number of ways to divide the (n+1) objects into two groups: the black ball by itself, and the remaining n white balls. Since there are (n+1) objects in total, there are (n+1) ways to choose which object will be the black ball. Once we have made this choice, the remaining n white balls can be arranged in any order, giving us n! possible arrangements. Thus, the total number of arrangements is:

N = (n+1) n!

Now, these two expressions for N must be equal, since they are both counting the same thing. Equating them, we get:

n(n-1)(n-2)...(3)(2)(1) = (n+1) n!

Simplifying, we obtain:

1 + 2 + 3 + ... + n = n(n+1)/2

which is the desired identity.

(a) (i) Another pair of polar coordinates for (1, π/2) with r > 0 and 2π < θ < 4π is (1, 5π/2).
(ii) Another pair of polar coordinates for (1, π/2) with r < 0 and 0 < θ < 2π is (-1, π/2).

(b) (i) Another pair of polar coordinates for (-2, π/4) with r > 0 and 2π < θ < 4π is (2, 9π/4).
(ii) Since there is a typo in the question, I assume you meant 0 < θ < 2π. In this case, another pair of polar coordinates for (-2, π/4) with r < 0 and 0 < θ < 2π is (-2, π/4).

(c) (i) Assuming the correct range for θ is 2π < θ < 4π, another pair of polar coordinates for (3, 2) with r > 0 and 2π < θ < 4π is (3, 2 + 2π).
(ii) Another pair of polar coordinates for (3, 2) with r < 0 and 0 < θ < 2π is (-3, 2 + π).

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(a) (i) Another pair of polar coordinates for (1, π/2) with r > 0 and 2π < θ < 4π is (1, 5π/2).
(ii) Another pair of polar coordinates for (1, π/2) with r < 0 and 0 < θ < 2π is (-1, π/2).

(b) (i) Another pair of polar coordinates for (-2, π/4) with r > 0 and 2π < θ < 4π is (2, 9π/4).
(ii) Since there is a typo in the question, I assume you meant 0 < θ < 2π. In this case, another pair of polar coordinates for (-2, π/4) with r < 0 and 0 < θ < 2π is (-2, π/4).

(c) (i) Assuming the correct range for θ is 2π < θ < 4π, another pair of polar coordinates for (3, 2) with r > 0 and 2π < θ < 4π is (3, 2 + 2π).
(ii) Another pair of polar coordinates for (3, 2) with r < 0 and 0 < θ < 2π is (-3, 2 + π).

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Therefore, the derivative (Use symbolic notation and fractions where needed). [tex]f'(x)=4x^3[/tex].

Using the Power Rule to compute the derivative:

[tex]f(x) = x^2 + 16x[/tex]

[tex]f'(x) = d/dx (x^2 + 16x)[/tex]

[tex]= d/dx (x^2) + d/dx (16x)[/tex](using the linearity property)

[tex]= 2x + 16[/tex] (using the Power Rule)

Therefore, [tex]f'(x) = 2x + 16.[/tex]

Computing f'(x) using the limit definition:

[tex]f(x) = x^2 + 16x[/tex]

[tex]f'(x) = lim(h - > 0) [(f(x+h) - f(x))/h][/tex]

[tex]= lim(h - > 0) [(x+h)^2 + 16(x+h) - (x^2 + 16x))/h][/tex]

[tex]= lim(h - > 0) [x^2 + 2xh + h^2 + 16x + 16h - x^2 - 16x]/h[/tex]

[tex]= 2x + 16[/tex]

Therefore, [tex]f'(x) = 2x + 16.[/tex]

Calculating the derivative using the product rule:

[tex]Q(r) = (1 - 4r)(6r + 5)[/tex]

[tex]Q'(r) = d/dx [(1 - 4r)(6r + 5)][/tex]

[tex]= (d/dx (1 - 4r))(6r + 5) + (1 - 4r)(d/dx (6r + 5))[/tex] (using the product rule)

[tex]= (-4)(6r + 5) + (1 - 4r)(6)[/tex] (taking the derivatives of the individual factors)

[tex]= -24r - 20 + 6 - 24r[/tex]

[tex]= -48r - 14[/tex]

Therefore, Q'(r) = -48r - 14.

Calculating the derivative:

[tex]f(x) = 12x^{(5/4)} + 3x^{(-3/12)}+ 5x[/tex]

[tex]f'(x) = d/dx (12x^{(5/4)} + 3x^{(-3/12)} + 5x)[/tex]

[tex]= 12(d/dx x^{(5/4))} + 3(d/dx x^{(-3/12))} + 5(d/dx x)[/tex] (using the linearity property)

[tex]= 12(5/4)x^{(1/4)} - 3(3/12)x^{(-15/12)} + 5[/tex](using the Power Rule and the Chain Rule)

[tex]= 15x^{(1/4)} - 9x^{(-5/4)} + 5[/tex]

Therefore,[tex]f'(x) = 15x^{(1/4)} - 9x^{(-5/4)} + 5.[/tex]

Calculating the derivative:

[tex]f(x) = 9y^2 + 30x^4/15[/tex]

[tex]f'(x) = d/dx (9y^2 + 30x^4/15)[/tex]

[tex]= 0 + 4x^3[/tex] (taking the derivative of the second term and simplifying)

[tex]= 4x^3[/tex]

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Answer:

It takes about 1 hour to read 30 pages at an average reading speed

Step-by-step explanation:

The probability of finding an electron between x = 0.1 nm and x = 0.2 nm is 0.1 nm.

The probability density function for finding an electron between two points in space is given by the square of the absolute value of the wave function, integrated over the given range.

Let's start by finding the normalization constant A for the given wave function:

∫|Ψ|^2 dx = 1

∫(2/√l)sin(2πx/l) dx = 1

Using integration by parts, we get:

A = √(l/2)

Now, the probability of finding the electron between x = 0.1 nm and x = 0.2 nm is given by:

P = ∫0.2nm 0.1nm |Ψ|^2 dx

P = A^2 ∫0.2nm 0.1nm (sin(2πx/l))^2 dx

P = (l/2) ∫0.2nm 0.1nm (sin(2πx/l))^2 dx

P = (10/2) ∫0.2nm 0.1nm (sin(2πx/10))^2 dx

P = 2 ∫0.2nm 0.1nm (sin(πx/5))^2 dx

Using the identity sin^2θ = (1/2)(1 - cos(2θ)), we can simplify this expression:

P = 2 ∫0.2nm 0.1nm (1/2)(1 - cos(2πx/5)) dx

P = ∫0.2nm 0.1nm (1 - cos(2πx/5)) dx

P = (∫0.2nm 0.1nm dx) - (∫0.2nm 0.1nm cos(2πx/5) dx)

The first integral is simply the length of the given interval:

∫0.2nm 0.1nm dx = 0.1nm

For the second integral, we can use the fact that the integral of cos(mx) from 0 to 2π is zero, unless m is equal to zero. In this case, m = 5, so we get:

∫0.2nm 0.1nm cos(2πx/5) dx = 0

Therefore, the probability of finding the electron between x = 0.1 nm and x = 0.2 nm is:

P = 0.1nm

So the probability of finding an electron between x = 0.1 nm and x = 0.2 nm is 0.1 nm.

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The possible zeros of the polynomial are -2, -3/2 and  4.

The zeros of the function is calculated as follows;

The zeros of the function are the values of x that will make the function equal to zero.

let x = -2

f(x) = 2x³ - x² - 22x - 24

f(-2) = 2(-2)³ - (-2)² - 22(-2) - 24

f(-2) = -16 - 4 + 44 - 24

f(-2) = 0

So, x + 2 is a factor of the polynomial, and other zeros of the polynomial is calculated as;

                       2x² - 5x - 12

                    ----------------------------------

         x + 2    √ 2x³ - x² - 22x  - 24

                  - (2x³ +  4x²)

                    ------------------------------------

                              -5x² - 22x -24

                            - (-5x² - 10x)

                       -------------------------------------

                                       -12x - 24

                                    - (-12x - 24)

                               -------------------------

                                              0

 2x² - 5x - 12 , so will factorize this quotient as follows;

= 2x² - 8x + 3x - 12

= 2x(x - 4) + 3(x - 4)

= (2x + 3)(x - 4)

2x + 3 = 0

or

x - 4 = 0

x = -3/2 or 4

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