Answer:
60.0L of hydrogen are needed
Explanation:
Based on the reaction:
3H₂ + N₂ ⇄ 2NH₃
3 moles of hydrogen react 1 mole of nitrogen.
To solve this question we have to find the moles of nitrogen. With the moles of nitrogen we can find the moles of hydrogen. Using PV = nRT at STP conditions we can find the volume as follows:
Moles Nitrogen -Molar mass: 28g/mol-
25.0g N₂ * (1mol / 28g) = 0.893 moles N₂
Moles hydrogen:
0.893 moles N₂ * (3mol H₂ / 1mol N₂) = 2.679 moles H₂
Volume hydrogen:
PV = nRT
V = nRT / P
Where V is volume in liters,
n are moles of the gas: 2.679 moles
R is gas constant: 0.082atmL/molK
T is absolute temperature: 273.15K at STP
P is 1atm at STP
Replacing:
V = 2.679mol*0.082atmL/molK*273.15K / 1atm
V =
60.0L of hydrogen are needed
2. C + S → CS2
Reaction Type:
If I add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be? (convert mL to L and round answer to 3 decimals)
Answer:
0.75 M
Explanation:
M1 = 0.15 M
V1 = 125 mL or 0.125 L
M2 = Y
V2 = 25 mL or 0.025 L
0.15 M x 0.125 mL = Y x 0.025 L
Y = 0.15 M x 0.125 mL / 0.025 L
Cancel out the mL
Y = 0.01875M / 0.025 L
Y = 0.75M
Answer:
0.125 M
Explanation:
M₁V₁ = M₂V₂
125 mL / 1000 = 0.125 L = V₁
25 + 125 = 150 mL / 1000 = 0.150 L = V₂
0.15 M = M₁
M₁ × V₁ / V₂ = M₂
(0.15) × (0.125) / (0.150) = 0.125 M
0.125 M is the answer
Explain the term respiration and how this process increases the percentage of carbon dioxide in the atmosphere.
Answer:
Please find the explanation to this question below.
Explanation:
_______ are the paths of objects around the sun.
Answer:
Orbit
Explanation:
when something makes a complete path around the sun it is called an orbit
In order to expand agriculture and urban areas to meet increased demand for growing populations, water supplies often have to be diverted. In three to five sentences, construct a potential chain of consequences for what could happen when water is diverted from large bodies like lakes and rivers
Answer:
Decrease occur in the amount and flow of water bodies.
Explanation:
There is decrease in the amount and flow of water from water bodies such as rivers and lakes etc occur when the river is diverted from large water bodies because the water flows to the diverted sides and decrease occurs in the amount of water in the rivers and lakes. Those regions from where this river passes can also be negatively affected due to low amount of water they receives for their daily needs or for cultivation of crops so we can say that this diversion has adverse effect on other populations.
binigyan ang isang liham ng pasasalamat at gagawin ko rin siya ng kabutihan sa ibang pagkakataon
Answer:
what language do you speak?
A sample of sulfur dioxide occupies a volume of 6052 mL at 352 K and 892 mm Hg. What volume will the sulfur dioxide occupy at STP?
Answer:
5511.99 mL
Explanation:
Given data
Volume V1= 6052 mL
Temperature T1= 352K
Pressure P1= 892 mm Hg
At STP the parameters of gas are
Temperature T2= 273.15 K
Pressure P2= 760 mmHg
Applying the gas equation
P1V1/T1= P2V2/T2
Substitute to find V2 we have
892*6052/352= 760*V2/273.15
5398384/352= 760*V2/273.15
15336.31= 760*V2/273.15
Cross multiply
15336.31*273.15= 760*V2
4189113.0765= 760*V2
4189113.0765/760= V2
V2= 5511.99 mL
Hence the volume at STP is 5511.99 mL
What is the purpose of a buffer?
Answer: A buffer solution is a solution made to prevent the pH level of something from changing when you add a base or an acid to it. For example, if you put a buffer solution in a pool, and then you put chlorine in it, the chlorine's effect on the PH level will be suppressed.
if i put regular air into a ziplock bag does carbon dioxide come out?
53 points and brainliest no link pls : in the Contact Process, sulfur dioxide is converted into sulfur trioxide and the following equilibrium is set up: SO2 (g) + O2 (g)--> 2 SO3 (g) ∆H = -27 kJ a) If sulfur dioxide is added to the mixture, what happens to the position of the equilibrium? b) If a catalyst is added to the mixture, what happens to the position of the equilibrium? c) if the pressure was increased in the above reaction, what happens to the position of the equilibrium? *
Answer:
the equilibrium will start to react and give off a gas
the position will start to move
Explanation:
which two technologies use reflected sound waves
A. Ultrasound imaging B. Sonar C.Radar D. Solar panels
Answer: The answer is B.Sonar and C.Radar
Explanation:
They are both just like an echo which is the main things that uses reflected sound waves. They are basically like synonyms for echo.
How many mole ratios can be written for a chemical reaction involving four substances?
Answer:
12 and 20 moles ratios, respectively.
Explanation:
Note that the number of mole ratios you can write for a chemical reaction involving a total of n substances is (n)(n–1). Thus, for reactions involving four and five substances, you can write 12 and 20 moles ratios, respectively.
*** HOPE IT HELPS! :)
The difference between a conjugate acid/base pair is
+
o the conjugate acid
o the conjugate base
O one proton
one OH-
Answer:
hola no ablo inglés porfavor
What must be known to find an object's average speed?
*direction and time
*distance and time
*displacement and direction
Answer:
distance and time
Explanation:
total distance/ total time
What is the mass of Neon in a sign when the gas tubes have a total volume of 166 mL?
Suppose Earth was tilted much less on its axis. What effect would this have on the planet? Please help me !
Answer:
If Earth was tilted much less on its axis, it would lead to minor changes in precipitation and temperatures as Earth moves slightly towards and away from the sun.
Explanation:
If a planet tilts more, it leads to colder winters and warmer summers. However, if a planet tilts less, it leads to less severe seasons that is and milder winters and cooler summers.
If Earth was tilted much less on its axis, it would lead to minor changes in precipitation and temperatures as Earth moves slightly towards and away from the sun.
R is the ideal gas constant. We know it is equal to 0.0821. What is the unit for R?
L•atm/mol K
L•atm/mol · °C
mL • atm/mol. K
L• kPa/mol - K
Answer:
A. L•atm/mol K
Explanation:
The ideal gas law equation is given as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant
T = temperature (K)
As rightly stated in this question, R is the ideal gas constant, which can be different depending on the unit of the other components.
At STP;
V = 22.4L
P = 1 atm
T = 273 K
n = 1 mole
Hence, using PV = nRT
R = PV/nT
R = 1 × 22.4/1 × 273
R = 22.4/273
R = 0.08205
Approximately, R = 0.0821
With the units of P as atm, V as L, n as mol and T as K; R will be 0.0821 L•atm/mol K
You pour 25.0 mL of 6.70 M NaOH stock solution into your beaker. How much water will you have if it is diluted to 3.40 M
solution?
Calculate the freezing point of a nonionizing antifreeze solution containing 388 g ethylene glycol, C2H6O2, and 510 g of water.
Answer:
T° freezing solution = -22.8°C
Explanation:
To solve this problem we apply, the Freezing Point Depression. This is a colligative property which its formula is:
T° freezing pure solvent - T° freezing solution = Kf . molality . i
i = Van't Hoff factor.
We have been informed is a nonionizing solute, so i = 1
Our solute is ethylene glycol, so le'ts determine the moles to get molality
388 g . 1 mol / 62.07 g = 6.25 moles
molality (m) = moles of solute /kg of solvent
We convert mass of solvent, water, to kg → 510 g . 1kg /1000g = 0.510 kg
6.25 mol /0.510kg = 12.25 m
We replace at formula → 0°C - T° freezing solution = 1.86°C/m . 12.25 m . 1
T° freezing solution = -22.8°C
What happens to the pH of the solution as you add more substance to it?
Answer:
If it's a buffer solution, the pH remains unchanged.
If it's a normal solution, and an acidic substance is added to it, the pH lowers.
If a basic substance is added to it, the pH increases.
In a tug of war, the team on the left pulls with a force of 430 N and the team on the right pulls with a force of 420 N. What is the net force on the rope?
A. 10 N to the right
B. 10 N to the left
C. 420 N to the right
D. 430 N to the left
Answor
c
Explanation:
The half life of tritium is 12.3 years. How much sample will remain if you start with 425g of tritium that is found after 4 half lives?
Answer:
26.56g
Explanation:
The half life of an isotope decay is the time transcurred when the initial amount of the isotope decays to the half of its amount.
For the problem, when 1 half life transcur, the sample has a mass of:
425g / 2 = 212.5g
When 2 half lives transcur:
212.5g / 2 = 106.25g
3 half lives:
106.25/2 = 53.13g
And the amount that is found after 4 half lives is:
53.13/2 =
26.56gHow to search icse board books by name and their solution
Answer:
i really don't know
Explanation:
but if you got an answer please let me know ty:)
What is one disadvantage of hydroelectric energy?
What is the amount of moles of NaOH, if the solution molarity is .33 M NaOH in 0.75 L solution
Answer:
The amount of moles of NaOH is 0.0495
Explanation:
Molarity is a measure of concentration that is defined as the number of moles of solute that are dissolved in a given volume.
In symbolic form molarity is presented as:
[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case:
Molarity= 0.33 MNumber of moles of solute= ?Volume= 0.75 LReplacing in the definition of molarity:
[tex]0.33 M=\frac{number of moles of solute}{0.75 L}[/tex]
number of moles of solute= 0.33 M* 0.75 L
number of moles of solute= 0.0495 moles
The amount of moles of NaOH is 0.0495
Answer:
0.248 moles of NaOH
Explanation:
Concept of Molarity is mol/L
[x] = 1 M
1 mol of x contained in 1 L of solution. We write molar concentrations between []
M = mol/L then M . L = mol
Our solution is NaOH
0.33 M . 0.75L = mol
This solution contains 0.248 moles of NaOH
HELP ME PLS ASAP ILL GIVE BRAINLY
Whether you live in a tropical climate, a temperate climate, or a polar climate, you share something with the rest of the world- your climate is influenced by the latitude where you live. Which best describes why latitudes closer to the equator have warmer climates?
Latitudes closer to the equator are at lower elevations than latitudes away from the equator
Latitudes closer to the equator receive more solar energy than latitudes away from the equator
Latitudes closer to the equator are nearer to ocean currents than latitudes away from the equator
Latitudes closer to the equator get more wind carrying energy in the form of heat than latitudes away from the equator
Answer: Latitudes closer to the equator receive more solar energy than latitudes away from the equator
Explanation:
Calculate the number of molecules in a 45.6 gram sample of C2H4.
Answer: The number of molecules in a 45.6 gram sample of [tex]C_{2}H_{4}[/tex] are [tex]9.78 \times 10^{23}[/tex].
Explanation:
Given: Mass of [tex]C_{2}H_{4}[/tex] = 45.6 g
Molar mass of [tex]C_{2}H_{4}[/tex] is 28.05 g/mol.
Therefore, number of moles of [tex]C_{2}H_{4}[/tex] are calculated as follows.
[tex]No. of moles = \frac{mass}{molarmass}\\= \frac{45.6 g}{28.05 g/mol}\\= 1.62 mol[/tex]
According to the mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] molecules. Hence, number of molecules present in 1.62 mol are calculated as follows.
[tex]1.62 \times 6.022 \times 10^{23}\\= 9.78 \times 10^{23}[/tex]
Thus, we can conclude that the number of molecules in a 45.6 gram sample of [tex]C_{2}H_{4}[/tex] are [tex]9.78 \times 10^{23}[/tex].
different between:Electrovalent bond and covalent bond
Explanation:
electrovalent bond covers single bond.
Covalent bond covers double or more bonds.
when you rub your sock on carpet then touch a door what happens? what are the charges doing?
How much water should be added to 5.00 g of KCl to prepare a 0.500 m
solution? *
Molality = moles of solute
Kg of solvent
100 g
38g
500 g
134 g
Other
Answer:133.4
c
m
3
Explanation: Explanation:
Molarity is number of moles of solute divided by number of litres of solution.
M
=
n
V
Rearrange for V to give
V
=
n
M
Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.
Now plug in the numbers:
V
=
n
m
=
0.0667
0.5
=
0.1334
litres
So you need to add 0.1334 litres of 133.4
c
m
3
of water.
(NB: symbol for molarity is upper case M. m is metres).