How to solve everything in Kotlin??

A) create a method that takes a string as a parameter and inverts it.

C) Create a car class that contains Brand, model, year of release and current speed. Use the primary constructor

B) create the main function, and create 4 objects of class car and store them in a vector and print them.

Answer:

2001:0db8:85a3:0000:0000:8a2e:0370:7334" and "2001:db8:85a3:0:0:8A2E:0370:7334" are valid IPv6 addresses, while "2001:0db8:85a3::8A2E:037j:7334

Explanation:

Answer:

1, 4, 5

Explanation:

parse2:

. In this case it's passing "r" as an argument, which really does absolutely nothing, because whenever you call open("file.txt") it defaults to reading mode, so all you're doing is explicitly passing the "r". So let's look at the first line. Whenever you call str.split() without any arguments, by default it splits it by empty text, and filters any empty text. So str.split() is not the same as str.split(" ") although it has similar behavior. "     ".split(" ") will output ['', '', '', '', '', ''], while "     ".split() will output []. So in this case the line.split() will split the string '10.1.2.1 - car [01/Mar/2022:13:05:05  +0900] "GET /python HTTP/1.0" 200 2222' into the list ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. As you can see the the data is split into two pieces of text, AND they include the brackets in both strings. So when it gets the 3 index and strips it of the "[]" it will have the incomplete date

parse3:

 In this instance the "r" does nothing as mentioned before the "r" is already defaulted whenever you call open("file.txt") so open("file.txt") is the same as open("file.txt", "r"). So in this case we won't be working left to right, we're going inside the brackets first, kind of like in math you don't don't work left to right in equation 3 + 3(2+3). You work in the brackets first (inside brackets you do left to right). So the first piece of code to run is the line.split("[" or "]"). I actually kind of misspoke here. Technically the "[" or "]" runs first because this doesn't do what you may think it does. The or will only return one value. this is not splitting the line by both "[" and "]". The, or will evaluate which is true from left to right, and if it is true, it returns that. Since strings are evaluated on their length to determine if they're true. the "[" will evaluate to true, because any string that is not empty is true, if a string is empty it's false. So the "[" will evaluate to true this the "[" or "]" will evaluate to "[". So after that the code will run line.split("[") which makes the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05  +0900] "GET /python HTTP/1.0" 200 2222']. Now the [3:5] will splice the list so that it returns a list with the elements at index 3 (including 3) to 5 (excluding 5). This returns the list: [], because the previous list only has 2 elements. There are no elements at index 3 to 5 (excluding 5). So when you join the list by " ", you'll get an empty string

parse4:

  So I'm actually a bit confused here, I thought the "r+" would open the file in read-writing mode, but maybe this is a different version of python I have no idea, so I'm going to assume it is reading/writing mode, which just means you can read and write to the file. Anyways when you split the line by doing line.split(), as mentioned before it will split by empty spaces and filter any empty spaces. This line will return: ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. and then you splice the list from indexes 3 to 5 (excluding 5). This will return the list: ['[01/Mar/2022:13:05:05', '+0900]'] which has the two pieces of information you need for the date. Now it joins them by a space which will output: '[01/Mar/2022:13:05:05 +0900]'. Now when you strip the "[]" you get the string: '01/Mar/2022:13:05:05 +0900' which is the correct output!

parse 5:

 So in this example it's using re.split. And the re.split is splitting by "[" or "]" which is what re.split can be used for, to split by multiple strings, which may be confused by string.split("[" or "]") which is not the same thing as explained above what the latter does. Also the reason there is a backslash in front of the [ and ] is to escape it, because normally those two characters would be used to define a set, but by using a \ in front of it, you're essentially telling regex to interpret it literally. So in splitting the string by "[" and "]" you'll get the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05  +0900', ' "GET /python HTTP/1.0" 200 2222'] which has 3 elements, since it was split by the [ and the ]. The second element has the date, so all you need to do is index the list using the index 1, which is exactly what the code does

Answer:

ansList =input().split() #get input and split it by space

ansList = [int(i) for i in ansList if int(i)>0] #turn string to integer,and get all positive integers

print(ansList)

Explanation: I think this would work for you. I leace comments in the answer.

The program that reads a list of integers into a list as long as the integers are greater than zero is coded in the source code.

Source code:

user_numbers = []

user_input = int(input("Enter an integer (enter a non-positive integer to stop): "))

while user_input > 0:

   user_numbers.append(user_input)

   user_input = int(input("Enter an integer (enter a non-positive integer to stop): "))

print(user_numbers)

In this program, we initialize an empty list user_numbers to store the integers entered by the user. We then use a while loop to repeatedly prompt the user to enter an integer.

If the entered integer is greater than 0, it is appended to the user_numbers list. If the entered integer is non-positive (less than or equal to 0), the loop terminates.

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The sample recursive Python Function is given below. See the definition of a Recursive Python Function.

A recursive function is one that defines itself in terms of itself using self-referential phrases.

This signifies that the function will keep calling itself and repeating its action until some condition is fulfilled and a result is returned.

Sample Recursive Python Function is:

def remove_all0(x,s):

   while s!=[]:

       if x == s[0]:

           ss = [s[1]] + remove_all0(x,s[2:])

           return ss

       else:

           s1 = [s[0]] + remove_all0(x, s[1:])

           return s1

   if s==[]:

       return s

print(remove_all0(3,[4,3,5,6,3,2,1]))

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The qubit in quantum computing are different from a regular bit in classical computing is multiple qubits can show quantum entanglement.

An important factor between qubits and normal bits is that a lot of qubits can show quantum entanglement.

Note that Quantum entanglement is said to be a form of nonlocal property that pertains to two or more qubits that gives room for a set of qubits to show higher correlation than is it was in any systems.

Therefore, The qubit in quantum computing are different from a regular bit in classical computing is multiple qubits can show quantum entanglement.

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Debugging a code involves locating the errors in a code segment, and fixing them.

When the program was run on GDB, the program give the following error

Main.java:62: error: reached end of file while parsing

This means that we need to add a closing brace to the end of the program.

A second run after fixing this error gives another set of errors:

Main.java:4: error: class Contribution is public, should be declared in a file named Contribution.java

It should be noted that GDB only allows you to create a program with the file name Main i.e. Main.java

This means that we change the Contribution keywords in the program to Main.

After this has been done, the program gives the following output:

It took 17 contributions to reach the goal.

The maximum contribution received was $189.0.

The minimum contribution received was $3.0

The average contribution amount was $60.0.

A total of $1012.0 was collected.

So, the corrected program is:

import java.io.*;

import java.util.*;

public class Main {

   public void fileOperation(String inputFile, String outputFile) {

       double max_contro = Double.MIN_VALUE;

       double min_contro = Double.MAX_VALUE;

       int total = 0;

       int goal = 1000;

       double current = 0.0;

       // Reading from the file

       try {

           File file = new File(inputFile);

           Scanner sc = new Scanner(file);

           while (sc.hasNextLine()) {

               double amt = Double.parseDouble(sc.nextLine());

               current += amt;

               total++;

               if (amt < min_contro) {

                   min_contro = amt;

               }

               if (amt > max_contro) {

                   max_contro = amt;

               }

               if (current > goal) {

                   break;

               }

           }

       } catch (Exception e) {

           System.out.println("Error processing the file!");

       }

       double average_contro = Math.round((double) current / total);

       // Writing to the file

       try {

           FileWriter writer = new FileWriter(outputFile, true);

           BufferedWriter out = new BufferedWriter(writer);

           out.write("It took " + total + " contributions to reach the goal.\nThe maximum contribution"

           + " received was $" + max_contro + ".\nThe minimum contribution"

           + " received was $" + min_contro + "\nThe average contribution amount was $"

           + average_contro + ".\nA total of $" + current + " was collected.");

           out.newLine();

           out.close();

       } catch (Exception e) {

           System.out.println("Error processing the file!");

       }

   }

   // Driver method to test the code

   public static void main(String[] args) {

       String inputFile = "input.in";

       String outputFile = "output.out";

       Main obj = new Main();

       obj.fileOperation(inputFile, outputFile);

   }

}

Note that the filename must be Main.java in GDB and the input file is input.in

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The major problem that BCC will face when it expands is the lack of digital coverage to all its branches because they are currently using only local area network that is connecting only on branch devices.

The three possible reasons for this problem is that:

The issues one need to look if opening a New Bank

Therefore, The major problem that BCC will face when it expands is the lack of digital coverage to all its branches because they are currently using only local area network that is connecting only on branch devices.

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In cell E5, enter a formula without using functions that multiples the actual hours (cell D5) by the billing rate (cell J2) to determine the actual dollar amount charged for general administrative services are L formulation are expressions used to orm computation.

What is excel?

Microsoft Excel allows customers to format, arrange and calculate statistics in a spreadsheet. By organizing statistics the use of software programs like Excel, statistics analysts and different customers could make facts less difficult to view as statistics is brought or changed. Excel includes a huge wide variety of bins referred to as cells which might be ordered in rows and columns.

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The study of quantum computing is concerned with the creation of computer-based technologies based on the ideas of quantum theory. The nature and behaviour of matter and energy at the quantum level are explained by quantum theory.

Technology is defined as computer-based technology that makes use of particular hardware, software, and microprocessing capabilities found on a computer or mobile device.

Computer based technology helps the people in reducing their time and strength by simplifying task. Some computer-based technology are-

Thus, creation of computer-based technologies based on the ideas of quantum theory.

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If the the total number of elements is N, the option that correctly compares the time complexity with respect to N of each function is f3 < f1 < f2.

Flattening lists is a term that connote the act of changing a multidimensional or any kind of nested list into  what we call a one-dimensional list.

Note that For example, the act of changing this list of [[1,2], [3,4]] list to [1,2,3,4] is known as flattening.

So, If the the total number of elements is N, the option that correctly compares the time complexity with respect to N of each function is f3 < f1 < f2.

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L is a decidable language because the Turing machine accepts it.

L is a recognizable language if  TM M recognizes it.

A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,

Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.

So,  L is a decidable language because the Turing machine accepts it.

L is a recognizable language if  TM M recognizes it.

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Explanation:

I would use a for loop cycling through the array and adding the arrays values into a variable, then keep track of how many items in the array you have. Finally divide the total by the amount of stock prices and output it.

The code that is used to count sheep aloud in Javascript is given as:

var countSheep = function (num){

 //start with a counter i = 1

 // increment i

 // stop until i == num

 // "interpolation" to insert variables

 // return joint array

   let smallArr = "";

   for (let x = 1; x <= num; x++)

   {

      smallArr += `${x} sheep...`

   }

   return smallArr;

};

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Method 1 :

Using If else statements: If the condition checks whether num1 is smaller than num2 if so it will print 'Smallest of these two integers is num1'.

else it will print 'Smallest of these two integers is num2'

Method 2:

Using the 'min' method: using the method min(num1,num2), the program finds the smallest value and prints it directly to the user.

Python Program using method 1

#PYTHON PROGRAM TO FIND SMALLEST INTEGER VALUE FROM TWO INPUTS FROM USER - Method 1

#Accepts inputs from user

num1 = int (input ("Enter your first number:")) #Gets the first integer input from user and stores in num1

num2 = int (input ("Enter your second number: ")) #Gets the second integer input from user and stores in num2

#Finding output by if else

#Checks num1 smaller than num2

if (num1 < num2):

#assign num1 to small

small = num1

else:

#assign num2 to small

small = num2

print ("Smallest of these two integers is", small)

Python Program using method 2

#PYTHON PROGRAM TO FIND SMALLEST INTEGER VALUE FROM TWO INPUTS FROM USER - Method 2

#Accepts inputs from user

num1 = int (input ("Enter your first number:")) #Gets the first integer input from user and stores in num1

num2 = int (input ("Enter your second number: ")) #Gets the second integer input from user and stores in num2

#Finding output using min method

print("\n Smallest of these two integers is",min(num1,num2)) #Prints output to user

Answer:num1 = int(input())

num2 = int(input())

num3 = int(input())

lowest = min(num1, num2, num3)

if num1 < num2 and num1 < num3:

   lowest = num1

elif num2 < num1 and num2 < num3:

   lowest = num2

elif num3 < num1 and num3 < num2:

   lowest = num3

print(lowest)

Explanation:

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

.data

sourceword:

.word 0xAB

wordmask:

.word 0xCF

operand:

.long 0xAA

.text

.globl _start

_start:

movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)

movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)

xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)

andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)

orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)

xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)

movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)

movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)

movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)

shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)

# 0x000000AA=00000000000000000000000010101010

# =>00000000000000000000010101010000=0x00000550.

rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)

# 0x000000AA=00000000000000000000000010101010

3 =>10100000000000000000000000001010= 0xA000000A.

sarl %ecx # here the count value to shift the bits not mentioned.

# It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.

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The option that are the primary components used in machine learning are:

The elements used in machine learning algorithm are::

Note that The option that are the primary components used in machine learning are:

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The four standard layers of a layered architecture are:

This refers to the architectural style that is used to show components with similar functions in horizontal layers that have specific roles.

Hence, we can see that no generic info system architecture was attached to the answer, so it would be impossible to create a layered architecture, so a general overview was given about layered architecture.

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~frestoripongetosarangeou

A consumer orders pizza for delivery via an app. The element of the data component covers how a customer interacts with an enterprise platform

A data component is a tool that provides information on the activities taking place on a certain enterprise platform. This application also aids in keeping track of the available inventory.

In this approach, customers place their orders through a smartphone app.

Therefore, while ordering pizza the consumer uses the data component.

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The  true statements about Python primitive types are:

What are the Python primitive types?

The Python is known to be made up of four primitive data types which are said to be:

Note therefore that The  true statements about Python primitive types are:

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Based on the above, the option that i will chose is option A.

Arithmetic coding is known to be a form of a kind of entropy encoding that is known to often make use of  lossless data compression.

Note that based on the image given,  the option that i will chose is option A as it is the best option that fit into the expression,

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Answer:

create a new folder when saving your document by using the Save As dialog box. With your document open, click File > Save As. Under Save As, select where you want to create your new folder. You might need to click Browse or Computer, and navigate to the location for your new folder. In the Save As dialog box that opens, click New Folder.

The Pseudocode for a program that performs the above function is given below.

Pseudocode is a fictitious and informal language that aids programmers in the development of algorithms.

Pseudocode is a detailed (algorithmic) design tool that is "text-based."

Pseudocode sample:

start

Declarations

InputFile customerData

OutputFile mailingLabels

string studentid

string firstName

string LastName

string streetAddress

housekeeping( )

while bothDone = "N"

mainLoop( )

endwhile

finishUp( )

stop

housekeeping( )

open customerData "VernonHillsMailOrderBoxes.txt"

open mailingLabels "CutomerMailingLabels.txt"

Jefferson( )

Audubon( )

if jeffId = 9999 then

if audId = 9999 then

bothDone = "Y"

endif

endif

return

Jefferson( )

if eof then

jeffId = 9999

endif

return

Audubon( )

if eof then

audId = 9999

endif

return

mainLoop( )

if jeffId > audId then

Audubon( )

else

Jefferson( )

endif

if jeffId = 9999 then

if audId = 9999 then

bothDone = "Y"

endif

endif

return

finishUp( )

close files

return

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The 3 files you need to have for a successful mail merge are:

This is known to be the act of carrying out  a Mail Merge and it is one where a person will need to use a Word document and a recipient list, that is an Excel workbook.

Files needed are:

The 3 files you need to have for a successful mail merge are:

Apple Contacts List or Text file, etc.

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Answer:

if n mod cell m5 >=4 then

and continue your programming

The formula that uses the IF function to test is:

IF(M5 >= 4, "Qualified", "Not Qualified")

In Excel, use the IF function to test whether the number of years of experience (cell M5) is greater than or equal to 4.

The formula would be:

=IF(M5 >= 4, "Qualified", "Not Qualified")

This formula will check if the value in cell M5 is greater than or equal to 4. If it is, the result will be "Qualified".

Otherwise, if it's less than 4, the result will be "Not Qualified".

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Answer:

B

Explanation:

When you initialize an instance of FunEvent(tags, year) and assign it to bc. The instance variables in this case are: self.tags = ["g", "ml"] and self.year = 2022. But then you alter tags, which will also change self.tags, since self.tags is a reference to the list you passed in as an argument. This is not the case when you do year=2023 because, first of all, integers are not mutable, and also because even if somehow integers were mutable, you're not changing the object in-place, you're simply changing the where the "variable" is pointing to. So for example if you did tags = ["g", "ml", "bc"] instead of tags.append("bc"), it would also not change the value of the instance variable "tags", because you wouldn't be changing the object in-place. So when you print(bc), the instance variables will be ["g", "ml", "bc"] and 2022. When you try to print an object, it call try to convert it into a string using the __str__  magic method. In this case it will return a string formatted as "Event(tags={self.tags}, year={self.year}) which will output "Event(tags=['g', 'ml', 'bc'], year=2022)" So the correct answer is B

Answer:

They would be faster than today's computer and it technology it would easy and usefu and it would be more advanced with artificial intelligence at a rapid pace with higher technology I can say that it would be faster and easy

Answer:

user_num = 9

while user_num > -1:

 print("Body")

 user_num = int(input())

print("Done")

If this answer helped consider rating and marking brainliest :)

Answer:

user_num >= 0 or 0 <= user_num

Explanation:

You want to use one of the comparison operators, to solve this problem, and in this case you're going to specifically use: >= or <=, which is "greater than or equal to" and "less than or equal to", either can be used, it just depends where you place the numbers, kind of like how 10 >= 3 and 3 <= 10 are both true.

So in this case it says "non negative" number, this means that the number is greater than or equal to 0, The reason the equal to is included is because 0 is not negative. this means that you want to include it as well. So don't do user_num > 0, since that would exclude 0, which is not negative. So you're solution for the while loop will be:

while user_num >= 0:

   # code

or you can do

while 0 <= user_num:

   # code

Although I would probably go with user_num >= 0, since it seems to be the most understandable at a glance, although both should work.

Answer:

I believe that everyone should have access to computers and the Internet, regardless of location, need, competency, or ability to pay. I think that it is a moral obligation to provide access to the Internet to everyone. The ‘have nots’ may well feel discriminated against or feel ‘socially excluded’ and are missing out on many life opportunities.

I think that the government should provide the services and education and pick up the tab. I think that it is the government’s responsibility to make sure that everyone has access to the Internet.

Explanation:

The different hardware used by local network are:

The hardware are tools that aids in the act of connecting a computer or device to any form of local area network (LAN).

Note that hardware components needed also are:

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