How to find minimum and maximum of this equation.

36 miles is the fewest number of miles she can walk in February

There are 28 days in February.

Every third day is 28/3 = 9.333 = 9 days of walking.

since she walks four miles,

9*4 = 36

Hence, 36 miles is the fewest number of miles she can walk in February

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Answer:

In the question, it is given that the fixed cost is $25000 and the expense to produce each doughnut is $0.25.

It is required to represent the cost C of the company as a function of x, the number of doughnuts produced.

To do so, multiply the expense of each doughnut by the number of doughnuts then add the fixed expenses of the doughnut selling company to find the total cost of the company.

Step-by-step explanation:

The expense of each doughnut is $0.25.

The expenses for x doughnuts are $0.25x.

The fixed cost is $25000.

The total cost of the company is the sum of fixed cost and the expenses for the doughnut, C = 0.25x + 25000.

The total cost of the company is, C = 0.25x + 25000.

Answer:

last option : vertex is 2, -1 . axis of symmetry is x = 2

Answer:

D

(2 -1)

*(^_^)*

...............

Answer:

Step-by-step explanation:

Let the distance between docks be d.

This is the opposite side to 45° angle of triangle with other sides 400 ft and 500 ft.

Use the law of cosines to find the value of d:

The polynomial is not a perfect square trinomial. This is false..

It should be noted that a perfect squares trinomial is the algebraic expression which has the form of ax² + bx + c.

The equation given is 9x² - 30x + 25. This will be expanded as:

9x² - 30x + 25.

9x² - 15x - 15x + 25

3x(3x - 5) - 5(3x - 5)

= (3x - 5)(3x - 5)

In this case, 9x² - 30x + 25 is a perfect square binomial of 3x - 5 and not a trinomial.

Therefore, the correct option is false.

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Answer:

20 sq in

Step-by-step explanation:

formula is (base * height)/2 so plug it in:

5*8=40

40/2=20

20 sq in

Yes, a point of inflection exists where f''(x) = DNE.

We know that the point of inflection, also known as the inflection point, is where the function's concavity changes. Changing the function from concave down to concave up, or vice versa, means that. In other words, an inflection point is a location at which the rate of slope change from an increasing to a decreasing manner, or vice versa, occurs. There is no doubt that those points are neither local maxima nor minima. They are called stationary points.

Let's take an example [tex]f(x) = x^{\frac{1}{3} }[/tex]

Here, [tex]f'(x)=\frac{1}{3x^{\frac{2}{3} } }[/tex]

and [tex]f''(x)=-\frac{2}{9x^{\frac{5}{3} } }[/tex]

Clearly f''(x) = DNE at x = 0. We are going to check if x = 0 is a point of inflection or not.

At x = -1, (left side of 0), [tex]f''(-1)=-\frac{2}{9(-1)^{\frac{5}{3} } }=\frac{2}{9} > 0[/tex] (concave up)

At x = 1, (right side of 0), [tex]f''(1)=-\frac{2}{9(1)^{\frac{5}{3} } }=-\frac{2}{9} < 0[/tex] (concave down)

Then by the definition, we can conclude that x = 0 is a point of inflection.

Therefore, a point of inflection exists where f''(x) = DNE.

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Step-by-step explanation:

so, let me get this straight :

s = sqrt(sa/6)

this is because the surface area of a cube consists of 6 squares (as everybody knows that dice have 6 equal sides).

and the area of a single square is side².

for a cube with sa = 180 m² we have

s = sqrt(180/6) = sqrt(30)

for a cube with sa = 120 m² we have

s = sqrt(120/6) = sqrt(20) = sqrt(4×5) = 2×sqrt(5)

so, the side length of the larger cube is

sqrt(30) - 2×sqrt(5) meters

longer than the side length of the smaller cube.

in other words, the difference between both side lengths.

Answer:

answer above is correct, its B

Step-by-step explanation:

Answer:

[tex]y=5[/tex]

Step-by-step explanation:

[tex]\textsf{If }y \textsf{ is \underline{inversely proportional} to the square root of }x, \textsf{ then}:[/tex]

[tex]y \propto\dfrac{1}{\sqrt{x}} \implies y=\dfrac{k}{\sqrt{x}}\quad \textsf{(where k is some constant)}[/tex]

[tex]\textsf{When }x=25, y = 3:[/tex]

[tex]\implies 3=\dfrac{k}{\sqrt{25}}[/tex]

[tex]\implies 3=\dfrac{k}{5}[/tex]

[tex]\implies k=15[/tex]

Inputting the found value of k into the equation:

[tex]\implies y=\dfrac{15}{\sqrt{x}}[/tex]

To find the value of y when x is 9, substitute x = 9 into the found equation:

[tex]\implies y=\dfrac{15}{\sqrt{9}}[/tex]

[tex]\implies y=\dfrac{15}{3}[/tex]

[tex]\implies y=5[/tex]

An isosceles triangle is one with two equal-length sides. The correct option is C.

An isosceles triangle is one with two equal-length sides. It is sometimes stated as having exactly two equal-length sides, and sometimes as having at least two equal-length sides, with the latter form containing the equilateral triangle as a particular case.

The diagram as per the given conditions is drawn below.

In ΔUTZ, since the sides UZ and TZ are equal because the point z is equidistance from T and U, therefore, the triangle is an isosceles triangle. Thus, ∠BTZ≅TZB.

Hence, the correct option is C.

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Answer:

B

Step-by-step explanation:

g(x)=(4-4)²

g(x) =0

and f(x)=x²

f(x)=0²

1. if we add something in x then it will also add up in value of y

2.  x by 5 times then y value increases by 3*5 = 15 times

3.  if x is added with 5 then y value increases by 8.

Algebra is the part of mathematics that helps represent problems or situations in the form of mathematical expressions.

As, per the first part

y=x

So, if we add something in x then it will also add up in value of x.

In second part,

y=3x

If x by 5 times then y value increases by 3*5 = 15 times

In third part, if x is added with 5 then y value increases by 8.

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Answer:

=================

We know that:

So the sum of the 8 exterior angles is:

Sum of both interior and exterior angles of 8 angles:

Sum of those 8 interior angles is:

Answer:

(8,3),(8,3),(-8,-3),(-8,-3)

Step-by-step explanation:

A function is defined as a relation in which each domain element (x-value) is paired with exactly one range element (y-value).

This means that each value we input for x must have only one possible output. If the same x-value yields more than one y-value, it is not a function.

The correct answer, as shown above, meets the criteria of a function, as each x-value is shown to produce exactly one y-value. In this set of ordered pairs, if x=8, then y=3, and if x=-8, then x=-3.

In the other sets of ordered pairs, however, one x-value has more than one possible y-value. Let's use the first set as an example:

(5,1),(5,2),(5,3),(5,4)

Inputting 5 as x produces four different y values; there is no one y value for the x-value. y could equal 1, 2, 3, or 4.

Assuming the salary is included in the job descriptions, then they all pay the same amount for the same length of time, meaning he will earn the same amount at any of the jobs. This looks like a trick question.

By the Central Limit Theorem, the best point estimate for the mean GPA for all residents of the local apartment complex is 1.7.

The Central Limit Theorem established that, for a normally distributed random variable X, with mean and standard deviation, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean  and standard deviation ;

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

The sample of 112 residents has a mean GPA of 1.7.

By the Central Limit Theorem, the best point estimate for the mean GPA for all residents of the local apartment complex is 1.7.

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The value of the stamp collection in terms of b is; 45b + 43 cents

We are given;

If there are x 3-cent stamps, then there are 4x number 10-cent stamps

So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x - 1, 2 cent stamps

Number of 2 cents stamps = b

Thus;  x - 1 = b

x = b + 1

The value of the stamp collection is as follows;

x number of 3 cents stamps = 3(b + 1) = 3b + 3 cents

4x number of 10 cents stamps = 10(4(b + 1)) = 10(4b + 4) = 40b + 40

The value of the 2 cents stamp = 2b cents

Total value is;

2b + 40b + 40 + 3b + 3 = (45b + 43) cents

Complete Question is;

I have 4 times as many 10-cent stamps as 3-cent stamps. I have one less 2-cent stamp than 3 cent stamp. If I have b2-cent stamps, what is the value of my stamp collection in terms of b ?

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Answer:

Projected height = (85 *21) / 35 = 51 cm

Step-by-step explanation:

Since the images are similar, we can set up the proportional equation like this:

Slide width / Slide height = Projected width / Projected height

35 mm / 21 mm = 85 cm / Projected height (in cm)

Projected height = (85 *21) / 35 = 51 cm

There are 1,86,78,66,560 possinbe passwords.

The easiest way to count the acceptable passwords is to note that there are 36^6 six-character strings made up of upper-case letters and digits, and 26^6 of them are made up entirely of letters, so there are 36^6 − 26^6 that include at least one digit.

⇒ 36^6 - 26^6

⇒ 2,17,67,82,336 - 30,89,15,776

⇒ 1,86,78,66,560

The answer is 1,86,78,66,560.

A password occasionally called a passcode, is a secret fact, generally a string of characters usually used to confirm a person's identity.

Historically, passwords we're expected to be memorized, but the large range of password-included offerings that common characters get entry to can make memorization of unique passwords for each service impractical.

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[tex]x^3-2x^2+x-1[/tex] is one of the prime factors of the polynomial

The question implies that we determine one of the prime factors of the polynomial.

The polynomial is given as:

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1[/tex]

Expand the polynomial by adding 0's in the form of +a - a

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^7 - 4x^6 +x^6 + 2x^5 -2x^5- 3x^4 + 4x^4 + 2x^3 -6x^3+2x^3- x^2 -3x^2 +4x^2-2x+2x-1[/tex]

Rearrange the terms

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^5 - 3x^4 + 2x^3 - x^2 + 2x^7 - 4x^6 + 4x^4 -6x^3+4x^2-2x+x^6-2x^5+2x^3-3x^2+2x-1[/tex]

Factorize the expression

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^2(x^6-2x^5+2x^3-3x^2+2x-1) + 2x(x^6-2x^5+2x^3-3x^2+2x-1) + 1(x^6-2x^5+2x^3-3x^2+2x-1)[/tex]

Factor out x^6-2x^5+2x^3-3x^2+2x-1

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x^2+2x + 1)(x^6-2x^5+2x^3-3x^2+2x-1)[/tex]

Express x^2 + 2x + 1 as a perfect square

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6-2x^5+2x^3-3x^2+2x-1)[/tex]

Expand the polynomial by adding 0's in the form of +a - a

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^4-x^3 +x^3-2x^3-x^2 -2x^2 +x+x - 1)[/tex]

Rearrange the terms

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^3-x^4-2x^3-x^2+x+x^3-2x^2 +x - 1)[/tex]

Factorize the expression

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3(x^3-2x^2+x-1) -x(x^3-2x^2+x-1)+1(x^3-2x^2+x-1))[/tex]

Factor out x^3-2x^2+x-1

[tex]x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3 -x+1)(x^3-2x^2+x-1)[/tex]

One of the factors of the above polynomial is [tex]x^3-2x^2+x-1[/tex].

This is the same as the option (c)

Hence, [tex]x^3-2x^2+x-1[/tex] is one of the prime factors of the polynomial

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Answer:

(x² + 2)(2x - 5)

Step-by-step explanation:

assuming the expression has to be factorised

2x³ - 5x² + 4x - 10 ← rearranging terms as indicated

= 2x³ + 4x - 5x² - 10 ( factor the first/second and third/fourth terms )

= 2x(x² + 2) - 5(x² + 2) ← factor out (x² + 2) from each term

= (x² + 2)(2x - 5) ← in factored form

The total amount paid by a customer who purchased a CD player at $142.00 and sales tax of 5.5% is $149.81

Amount of sales tax = 5.5% of $142.00

= 5.5/100 × 142

= 0.055 × 142

= $7.81

Total amount paid by customers = Cost of CD player + Amount of sales tax

= $142.00 + $7.81

= $149.81

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Answer:

32

Step-by-step explanation:

To find the mean of the data set, you find the sum of the data set, and divide it by how much data you have in the data set. In this case you have 18 people (amount of data in the data set) and the sum is 35+2+7+33+25+70+75+40+42+12+15+7+44+20+25+3+65+62 = 582. So divide these two values: [tex]\frac{582}{18} = 32.\overline{33} \approx 32[/tex]

Answer:

32.33

Step-by-step explanation:

Making 20 groups of 10 is the sampling strategy that can be used to select 200 sales representatives.

What is sampling?

Sampling is the phrase used to describe a statistical procedure in which a predetermined number of observations are chosen from a larger population. More precisely, sampling can be described as the process of choosing a portion of a statistical population in order to estimate the characteristics of the entire population. Samples that are representative of the population under study are sought for by statisticians.

Making 20 groups of 10 is the most effective way of sampling that can be employed here for the sales director to incorporate 200 sales representatives in this situation, with an equal amount of representatives from each region.

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The slope of line AB, BC, CD and AD are 1, -1/6, 2, -4/6 respectively. Quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C

Formula for slope is given as;

Slope = [tex]\frac{y2 -y1}{x2 -x1}[/tex]

A(-4 -1)

B(-1 2)

C(5 1)

D(1 -3)

a. Slope of line AB = [tex]\frac{2- (-1)}{-1 (-4)}[/tex] = [tex]\frac{2+ 1}{-1 + 4}[/tex] = [tex]\frac{3}{3}[/tex] = 1

b. Slope of line BC = [tex]\frac{1-2}{5-(-1)}[/tex] = [tex]\frac{-1}{6}[/tex]

c. Slope of line CD = [tex]\frac{-3 - 5}{1-5}[/tex] = [tex]\frac{-8}{-4}[/tex] = 2

d. Slope of line AD = [tex]\frac{-3 (-1)}{1 -(-4)}[/tex] = [tex]\frac{-4}{5}[/tex]

Quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C

Thus, the slope of line AB, BC, CD and AD are 1, -1/6, 2, -4/6 respectively.

and quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C

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Answer:

Step-by-step explanation:

You need to find the set of points that will yield a slope that is the negative reciprocal of the slope of Line L because perpendicular lines have negative reciprocal slopes. The negative reciprocal of 13/7 is -7/13. Which set of points will produce this result? The formula for finding the slope is:

m = (y2 - y1)/(x2 - x1)

Consider the second set of coordinates.

(2 - (-5))/(-7 - 6) = (2 + 5)/(-13) = -7/13

The second set of coordinates satisfy the condition.

Answer:

[tex](8n - 5)(n-1)[/tex]

Step-by-step explanation:

Hello!

We can factor this by grouping. We have to find two numbers that add up to -13 but multiply to 8 * 5 .

The two numbers that work are -8 and -5. Expand -13n to -8n and -5n.

The factored expression is [tex](8n - 5)(n-1)[/tex].

Answer: (99/13, 150/13)

Step-by-step explanation:

I'm too lazy to explain so here's a screen shot from desmos.

The 4-digit positive integers have four different digits where the leading digit is not zero, the integer is a multiple of 5, and 5 is the largest digit is 108.

[tex]5*4*3*1+4*4*3*1=60+28=108[/tex]

Positive integers are the numbers we use to depend: 1,2, 3,4, 1 , 2, three, four, and so forth. Numbers with a fractional component not identical to zero and poor numbers are excluded from a fixed of high-quality integers. The operations of addition, subtraction, multiplication, and division can be finished with tremendous integers.

Positive integers are definitely your counting numbers. wonderful integers are in reality a part of a larger institution of numbers referred to as integers. Integers are all of the whole numbers, each advantageous and poor. by complete numbers, we imply numbers without fractions or decimals.

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We make four cases based on where the multiple of the 5 digits (0 or5) is. The number has to end with either 5 or 0 since it's a multiple of5. In all but the last case, 5 and 0 are used at the end and in another spot that separates the cases.

Case 1: The first digit can't be 0 so it must be 5. There are 4.3 to choose the middle two digits. After that, the last digit has to be 0, so there are a total of 1.4.3.1=12 numbers.

Case 2: The second digit can be 5, leaving 2 choices. The first and third numbers can be chosen in 4.3 ways, like last time. The last digit has to be 0 or 5, but not the one we already used. There are a total of 4.2.3.1=24 numbers.

Case 3: There are the same choices, but the digits 0 and 5 are at the last and second-to-last spots. So there are 4.2.3.1 =24 numbers again.

Case 4: There are 4.3.2 ways to choose the first three numbers. There has to be a 5 in the number because the largest digit is 5. Coincidentally, there are 4.2.3.1 numbers again.

There are a total of 12 + 24.3= (D)84 numbers.

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