Answer:
11
Explanation:
From the question given above, the following data were obtained:
Electronic configuration => 1s²2s²2p⁶3s¹
Number of electrons =?
We must understand that the electronic configuration of an element is written based the number of electrons present in the atom of the element.
To obtain the number of electrons in the atom given in the question above, we simply add up the electrons in each orbital. This can be obtained as follow:
Electronic configuration => 1s²2s²2p⁶3s¹
Number of electrons =?
Number of electrons = 2 + 2 + 6 + 1
Number of electrons = 11
Thus , the number of electrons in the atom is 11
What is the atomic number?
pls help.
Answer:
8
Explanation:
Classify each as acidic or basic - pH 9 - pH 2.3 - pH 11 - pH 5 - solution where the concentration of hydronium ions [H ] is 0.0056 M - solution where the concentration of hydronium ions [H ] is 3.45 E-9 M.
Answer:
pH = 9: Basic; pH = 2.3: acidic; pH = 11: basic; pH = 5: Acidic; [H⁺] = 0.0056M: Acidic; [H⁺] = 3.45E-9M: Basic
Explanation:
A solution is defined as acidic when pH < 7 and as basic when pH > 7.
Also, pH = -log[H⁺].
Thus:
pH = 9: >7 → Basic
pH = 2.3: <7 → Acidic
pH = 11: >7 → Basic
pH = 5: <7 → Acidic
[H⁺] = 0.0056M, pH = -log0.0056M = 2.25: <7: Acidic
[H⁺] = 3.45E-9M, pH = 8.46: > 7: Basic
Name the energy store that two electrical
charges have when they attract or repel each
other.
Answer:
In contrast to the attractive force between two objects with opposite charges, two objects that are of like charge will repel each other. That is, a positively charged object will exert a repulsive force upon a second positively charged object.
Explanation:
Hope it has answered your questionYou want to clean a 500-ml flask that has been used to store a 0.9M solution. Each time the flask is emptied, 1.00 ml of solution adheres to the walls, and thus remains in the flask. For each rinse cycle, you pour 9.00 ml of solvent into the flask (to make 10.00 ml total), swirl to mix uniformly, and then empty it. What is the minimum number of such rinses necessary to reduce the residual concentration of 0.00001 M or below
Answer:
In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M
Explanation:
In each rinse cycle, the dilution that you are doing of the solution is from 1.00mL to 10.00mL, that is a dilution of 10
In the first rinse the concentration must be of 0.9M 10 = 0.09M
2nd = 0.009M
3rd = 0.0009M
4th = 0.00009M
5th = 0.000009M →
In the 5th cycle rinse, the residual concentration of the solution is < 0.00001MWHY IS IT IMPORTANT FOR A POPULATION TO NOT ALL BE IDENTICAL?
Answer:
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Explanation:
What kind of solid tends to have the lowest melting points?
Answer:
Molecular solids
Covalent compounds
Explanation:
vote me as the brainliest
what state of matter travels in straight lines
Answer:
light
Explanation:
light is plasma, which is a state of matter
Draw the organic product(s) of the following reactions, and include carbon dioxide if it is produced.
CH3CH2-C triple bond C-CH2CH3 rightarrow O3
You do not have to consider stereochemistry.
If a compound is formed more than once, add another sketcher and draw it again.
Draw carbon dioxide in its own sketcher if it is produced.
Separate multiple products using the + sign from the dropdown menu.
If no reaction occurs, draw the organic starting material.
Answer:
See picture below
Explanation:
In this case, is ocurring an ozonolysis reaction with alkines.
Alkines, unlike alkenes, when they undergo an ozonolysis reaction, the product formed is a carboxilic acid. In some cases it may produce CO₂, but that will happen only if the starting molecule has a terminal Hydrogen atom.
In other words the following:
CH₃CH₂C≡CH
In this case, it may produces the CO₂. However, it's not the case, so it will produce two molecules of carboxylic acid.
You can see the picture below for the final product.
Hope this helps.
Alkynes are subjected to ozonolysis to produce two ketones or acid anhydrides. The acid anhydride undergoes hydrolysis to produce two carboxylic acids if water is present in the process. Elastomer ozonolysis is also referred to as the ozone method.
Ozone (O₃), a reactive allotrope of oxygen, is used in ozonolysis, a process for oxidatively breaking alkenes or alkynes. The procedure enables the substitution of double or triple carbon-carbon bonds with double oxygen bonds. This reaction is frequently used to determine an unknown alkene's structure.
The products of the given reaction can be shown below:
To know more about ozonolysis, visit;
https://brainly.com/question/31980885
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I'll give you brainliest, if your answer is right :) Element A is in group 1A with a molar mass of 10 g/mol Element B is in group 7A with a molar mass of 30g/mol
a, A (solid) and B (gas) undergoes a combination reaction. Write the balanced chemical equation.
b, How many grams of B2 are needed to form a 2.5 M solution of AB with a volume of 250 mL?
Mass of B₂ = 18.75 g
Further explanationGiven
Element A and element B
Required
The reaction
mass of B₂
Solution
The balanced equation :
2A(s) + B₂(g) ⇒2AB(s)
mol AB :
= Molarity x Volume
= 2.5 M x 0.25 L
= 0.625
From the equation, mol ratio of B₂ : AB = 1 : 2, so mol B₂ :
= 1/2 x mol AB
= 1/2 x 0.625
= 0.3125
Mass B₂ (Molar mass = 2x30 g/mol=60 g/mol)
= mol x molar mass
= 0.3125 x 60 g/mol
= 18.75 g
URGENT!!! Compare the relative strength of the two forces A and B. Explain how you determined this comparison by identifying the forces
Answer:
A= Covalent bonding.
B = Dispersion forces.
Explanation:
This particular question wants to test our knowledge on chemical attractions in molecules. Kindly check the picture attached to get a glimpse of the two forces being compared here.
The force of attraction in B is known as the Dispersion forces. It is the kind of forces of attraction that happens when hydrogen bonds do not happen. Literarily, when Hydrogen atoms reacts with more electronegative atoms such as oxygen, Fluorine and Nitrogen, the kind of bond that will be formed will be an hydrogen bond. So, if hydrogen bond is not formed, then a weaker bond will be formed which is the Dispersion forces of attraction. Hence, B is the Dispersion forces.
Covalent bonds are the kind of bonds that involves that atoms shares electrons in order for chemical bonding to occur. Although, there is H2O which is a polar covalent bond. There are other compounds that are not polar such as CS2 and CH4. Therefore, the kind of attraction in A is covalent bonding.
1. Radiation with a frequency of 1.85 MHz, falls in the radio wave region. What is the wavelength (in nm) of this electromagnetic radiation?
(HINT: Hz is "cycles per second" and should be replaced by 1/s as a unit in the calculation. First convert MHz to Hz (106) also the final answer convert to nm. (10-9)
2. What is the frequency of visible light, which has a wavelength of 625 nm? What color is the wave?
(HINT: Notice for final answer that nm must be converted to m in order for the units to cancel properly)
Answer:
1. 1.62×10¹¹ nm
2. 4.8×10¹⁴ Hz
Explanation:
1. Determination of the wavelength.
We'll begin by converting 1.85 MHz to Hz. This can be obtained as follow:
1 MHz = 10⁶ Hz
Therefore,
1.85 MHz = 1.85 MHz × 10⁶ Hz / 1 MHz
1.85 MHz = 1.85×10⁶ Hz
Next, we shall determine the wavelength of the electromagnetic radiation. This can be obtained as follow:
Frequency (f) = 1.85×10⁶ Hz
Velocity of electromagnetic radiation (v) = 3×10⁸ m/s
Wavelength (λ) =?
v = λf
3×10⁸ = λ × 1.85×10⁶
Divide both side by 1.85×10⁶
λ = 3×10⁸ / 1.85×10⁶
λ = 162.16 m
Finally, we shall convert 162.16 m to nm. This can be obtained as follow:
1 m = 10⁹ nm
Therefore,
162.16 m = 162.16 m × 10⁹ nm / 1 m
162.16 m = 1.62×10¹¹ nm
Thus, the wavelength of the electromagnetic radiation is 1.62×10¹¹ nm
2. Determination of the frequency.
We'll begin by converting 625 nm to m. This can be obtained as follow:
1 nm = 10¯⁹ m
Therefore,
625 nm = 625 nm × 10¯⁹ m / 1 nm
625 nm = 6.25×10¯⁷ m
Finally, we shall determine the frequency the visible light as follow:
Wavelength (λ) = 6.25×10¯⁷ m
Velocity of light (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 6.25×10¯⁷ × f
Divide both side by 6.25×10¯⁷
f = 3×10⁸ / 6.25× 10¯⁷
f = 4.8×10¹⁴ Hz
Therefore, the frequency of the visible light is 4.8×10¹⁴ Hz
Ammonium phosphate is an important ingredient in many solid fertilizers. it can be made by reacting aqueous phosphoric acid with liquid ammonia. calculate the moles of ammonium phosphate produced by the reaction of 0.085 mol of ammonia. be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Answer:
0.028 mole of ammonium phosphate, (NH₄)₃PO₄.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H₃PO₄ + 3NH₃ —> (NH₄)₃PO₄
From the balanced equation above,
3 moles of NH₃ reacted to produce 1 mole of (NH₄)₃PO₄.
Finally, we shall determine the number of mole of (NH₄)₃PO₄ produced by the reaction of 0.085 mole of ammonia, NH₃. This can be obtained as follow:
From the balanced equation above,
3 moles of NH₃ reacted to produce 1 mole of (NH₄)₃PO₄.
Therefore, 0.085 mole of NH₃ will react to produce = (0.085 × 1)/3 = 0.028 mole of (NH₄)₃PO₄.
Thus, 0.028 mole of ammonium phosphate, (NH₄)₃PO₄ were obtained from the reaction.
Find the mass in grams of 1.38 moles of Sr
Answer:
116.78 grams.
Explanation:
1 mol of Strontium (Sr) = 87.62 grams
1.38 mol of Strontium = x
Cross Multiply
1 * x = 1.38 * 87.62
x = 116.78 grams
You can use solid, wedged, and dashed lines to better represent the 3D structure of molecules. The solid lines represent bonds in the plane of the paper, wedged lines represent a bond coming out of the plane, and the dashed line represents a bond going back behind the plane of the paper. Draw a representation of methane that better depicts its 3D structure.
Answer:
See explanation and image attached
Explanation:
Often times, there is a need for a three dimensional representation of a molecule on paper. These three dimensional representations give us an idea of what the molecule really looks like if we were to be looking at it physically.
In order to make a three dimensional representation, we use wedged and dashed bonds. The wedged bonds are coming out of the plane of the paper towards you while the dashed bonds are going into the plane of the paper away from you.
In the image attached, you will find the three dimensional representation of the methane molecule.
What is the structure formula of c10h18
Answer: I'm not 100% sure this is the formula but I hope it still helps! :)
Explanation:
Bornane; Cyclodecene; Decalin; Decynes. 1-Decyne; 2-Decyne; 3-Decyne; 4-Decyne; 5-Decyne, also known as dibutylethyne; Spirodecane
what are some sources of error associated with electroplating
Answer:
Cold Shuts. Cold shuts are one of the most common defects found in materials sent for electroplating.
Pitting
Sharp Edges
Cleavage Points
Unclean Manufacturing
Loss of Adhesion
Cracking After Plating — Hydrogen Cracking
Dull and Hazy Deposits in Plating.
Explanation:
A compound with molecular formula C5H10Br2 displays the following 13C NMR along with the DEPT-90 and DEPT-135 13CNMR spectra. What is the structure for this compound?
Answer:
Explanation:
The correct structure for the compound C5H10Br2 is:
Br -- CH₂ -- CH₂ -- CH₂ -- CH₂ -- CH₂ -- Br
1 2 3 4 5
The name of the required compound is 1,5-dibromopentane.
The DEPT spectroscopy is applied to differentiate between CH₃, CH₂, and CH groups.
Assuming the DEPT is up, this shows a positive peak which illustrates CH₃ group
Assuming the DEPT is down, this shows a negative peak which illustrates CH₂ or CH group
C-13 NMR with DEPT-135
The negative peak in DEPT at 26.77 ppm illustrates CH₂ or CHThe negative peak at 31.85 ppm illustrate CH₂ or CHThe negative peak at 33.24 ppm illustrate CH₂ or CHThe carbon analysis is:
Assign ppm
1 33.24
2 31.85
3 26.77
4 31.85
5 33.24
How much heat must be used to raise the
temperature of 180. g water from 19° C to 96°C?
The specific heat of water is 4.18 J/gºC.
Answer:
Q = 57934.8 J
Explanation:
Given data:
Mass of water = 180.0 g
Initial temperature = 19°C
Fina temperature = 96°C
Specific heat capacity of water = 4.18 J/g.°C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 96°C - 19°C
ΔT = 77°C
Q = 180.0 g×4.18 J/g.°C×77°C
Q = 57934.8 J
When a substance undergoes a chemical change, its identity does not change.
O True
O False
Answer:
False
Explanation:
Chemists make a distinction between two different types of changes that they study—physical changes and chemical changes. Physical changes are changes that do not alter the identity of a substance. Chemical changes are frequently harder to reverse than physical changes.
Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that liters per second of dinitrogen are consumed when the reaction is run at and the dinitrogen is supplied at . Calculate the rate at which ammonia is being produced. Give your answer in kilograms per second. Be sure your answer has the correct number of significant digits.
The question is incomplete. Here is the complete question.
In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 505. liters per second of dinitrogen are consumed when the reaction is run at 172.°C and 0.88 atm. Calculate the rate at which ammonia is being produced. Give your answer in kilogram per second. Be sure your answer has the correct number of significant digits.
Answer: Rate = 0.41 kg/s
Explanation: The balanced Haber reaction is
[tex]N_{2}+3H_{2}\rightarrow2NH_{3}[/tex]
As all the components are gases, we can use Ideal Gas Law, which relates Pressure (P), Volume (V), Temperature (T) and Moles (n) in the following formula:
PV = nRT
where
R is gas constant and, in this case, is R = 0.082 L.atm.K⁻¹mol⁻¹
T is in Kelvin
Converting Celsius in Kelvin:
T = 273 + 172
T = 445 K
Calculating moles
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{0.88(505)}{0.082(445)}[/tex]
n = 12.18 moles
According to the balanced equation, for 1 mol of dinitrogen gas consumed, 2 moles of ammonia is produced.
With 12.18 moles of dinitrogen, the reaction will result in
2(12.18) = 24.36 moles of ammonia
Molar mass of ammonia is M = 17.031 g/mol.
In 24.36 moles, there are
[tex]m=n.M[/tex]
m = 24.36.17.031
m = 414.87 grams
Since it's asking in kilograms: m = 0.41 kg.
In the beginning, it is said that dinitrogen gas is consumed at a rate of liters per second. So, the production rate of ammonia will be 0.41 kg/s.
Created when one substance is dissolved into another substance ? Is that a suspension. Solution or pure substance
Answer:
cemical change
Explanation:
Answer: A Solution
Explanation: A solution is made when a substance like salt is poured into water. The result would be a solution. Salt being a solid and water being a liquid.
How many moles are there in 24.0 grams of H2O
Answer:So, one mole of water has a mass of 16 +1+1 = 18 grams. So, if one mole has a mass of 18 grams, 25 grams would have a mass of 25 grams/ 18 grams per mole or 1.39 moles
Answer:
The answer would be 1.33
Explanation:
do you need an explanation?
P4+O2=P2O3
What’s the balance of this equation?
Explanation:
P₄+O₂=P₂O₃; non-balanced
P₄+O₂=2P₂O₃; to add '2' on the right side; non-balanced
P₄+3O₂=2P₂O₃. to add '3' before O₂ in the left side; balanced
Which nitrogen bases always pairs with thymine?
Answer:
The four different bases pair together in a way known as complementary pairing. Adenine always pairs with thymine, and cytosine always pairs with guanine.
Explanation:
To determine the concentration of citric acid, you will need to titrate this solution with 0.100 M NaOH. You are given a 1.00 M NaOH stock solution and will need to make enough 0.100 M NaOH to perform 3 titrations. For each titration, you will use 20.0 mL of 0.100 M NaOH solution.
Calculate the total volume (in mL) of the diluted solution you will need to prepare for the 3 titrations.
Determine the minimum volume (in mL) of 1.00 M NaOH stock solution needed to prepare the 0.100 M NaOH solution.
Answer:
60.0mL of the diluted solution are needed
6.00mL of the 1.00M NaOH stock solution is the minimum volume needed to prepare the diluted solution.
Explanation:
As in each titration we need to use 20.0mL of the diluted 0.100M solution. As there are 3 titration, the volume must be:
3 * 20.0mL = 60.0mL of the diluted solution are needed
Now, to prepare a 0.100M NaOH solution from a 1.00M NaOH stock solution the dilution must be of:
1.00M / 0.100M = 10 times must be diluted the solution.
As we need at least 60.0mL, the minimum volume of the stock solution must be:
60.0mL / 10 times =
6.00mL of the 1.00M NaOH stock solution is the minimum volume needed to prepare the diluted solution.The total thermal energy of a system depends jointly on the temperature, total number of in the system _______________, and the _______________of the material. *
1. Molecules/State
2. Molecules/Heat
3. Matter/Heat
4. Atoms/State
Answer:
Molecules/State
Explanation:
We know from the kinetic molecular theory that matter is made up of molecules. These molecules are in constant motion at various velocities and energies.
The total thermal energy refers to the total kinetic energies of these particles. It depends on the temperature of the system, the energies of the molecules present in the material and the arrangement of the object's molecules (states of matter).
How many cm 3 are in 0.014 in 3? (1 in = 2.54 cm)
Answer:
0.229 cm³.
Explanation:
The following data were obtained from the question:
Volume (in in³) = 0.014 in³
Volume (in cm³) =?
1 in = 2.54 cm
Next, we shall determine a conversion scale to convert from in³ to cm³. This can be obtained as follow:
1 in = 2.54 cm
Therefore,
1 in³ = 2.54³ cm³
1 in³ = 16.387 cm³
Finally, we shall convert 0.014 in³ to cm³. This can be obtained as follow:
1 in³ = 16.387 cm³
Therefore,
0.014 in³ = 0.014 in³ × 16.387 cm³ / 1 in³
0.014 in³ = 0.229 cm³
Thus, 0.014 in³ is equivalent to 0.229 cm³.
How many moles of hydrogen gas are present in 65.0 liters at STP?
1456 moles
1.45 moles
3.00 moles
2.90 moles
Answer:
2.9moles of hydrogen gas
Explanation:
convert liters to dm³
since 1liter= 1dm³
thus, 65.0liters = 65.0dm³
number of moles = volume given/22.4dm³
= 65.0/22.4
=2.9moles
Draw the kinetic and thermodynamic addition products formed when one equivalent of HBr reacts with the diene .
Answer:
See explanation and images attached
Explanation:
The addition of HBr to the diene could yield either a kinetic or thermodynamic product. The kinetic product is formed faster while the thermodynamic product is more stable and formed at equilibrium.
Recall that the alkene that is surrounded by more alkyl groups is more stable. Also, the carbocation undergoes rearrangement to form a more stable carbocation intermediate that ultimately leads to the formation of the thermodynamic (1,4) product which predominates.
The structures of the two products are shown in the image attached to this answer.
Can salt dissolve in hydrogen peroxide? Pls help me
Answer:
Yes it can!!
Explanation:
Hydrogen peroxide mixed with sodium is known as oxygen bleach. Add water and the compound releases an oxygen molecule to help it lift mold and stains from the surface of natural materials.