Step-by-step explanation:
Let the consecutive positive integer be x , x+1
now, we know that there product is less then 10000
so, x(x+1) = 10000
x² + x - 10000 = 0
On solving the quadractic equation,
we get the roots = (-100.50124999219 ), (99.501249992188)
since we are asked for less then 10000 we can approximate the answer to x = 99.5
Answer:
99.5
Step-by-step explanation:
Let the consecutive positive integer be n , n+1
now, we know that there product is less then 10000
so, n(n+1) = 10000
So, the question asked " Less than 10,000 " so, we get the roots = (-100.50124999219 ), (99.501249992188)
n² + n - 10000 = 0
Let's solve this equation together!
n approximate number is 99.5.
Please answer with everything needed i appreciate everyones help:)
Answer:
at 5 mins Holly traveled 2 miles. At 10 mins Holly traveled 4 miles. from there on she stayed there for 10 mins then went on her way. At 30 mins she traveled 5 1/2 miles. when she hit 35 mins she hit her destination then went back home.
Step-by-step explanation:
pretty simple
Please help me( ´人` )
The following diagram shows a quadrant OPQ in the sector ORST with centre O and a radius of 21 cm.
Given Q is the midpoint of OR, calculate the area, in cm², of the shaded region.
A 285.025
B 308.045
C 365.075
D 410.025
Answer:
D
Step-by-step explanation:
First let's list down the formulas we will be using.
Area of Quadrant = 1/4 x Area of Circle
= [tex]\frac{1}{4} \pi r^{2}[/tex]
Area of Part of a circle = (θ/360)[tex]\pi r^{2}[/tex]
First, we will find Angle QOT.
Angle QOT = 360 - 231 = 129
Area of ORST = [tex]\frac{129}{360} \pi (21)^{2} \\=\frac{6321}{40} \pi cm^{2}[/tex]
Next we know that, Q is midpoint of OR, therefore OQ = QR
and OQ = 0.5 * OR
OQ = 0.5 * 21 = 10.5cm = radius of Quadrant QOP
Area of Quadrant QOP = [tex]\frac{1}{4} \pi (10.5)^{2} \\=\frac{441}{16} \pi cm^{2}[/tex]
Lastly,
Area of Shaded Region = Area of ORST - Area of Quadrant QOP
= [tex]\frac{6321}{40} \pi -\frac{441}{16} \pi \\= 409.86cm^{2}[/tex]
Similar to the other question you asked, choose the closes answer as there might be some rounding differences. I kept it in fractions as it will ensure maximum precision.
Solve 56-10x≥ 20 + 8x.
O A. x≥ 2
OB. x2-2
OC. x≤2
OD. x≤-2
Answer:
[tex]\huge\boxed{\sf x\leq 2}[/tex]
Step-by-step explanation:
Given inequality:[tex]56-10x\geq 20+8x\\\\Subtract \ 20 \ from \ both \ sides\\\\56-20-10x\geq 8x\\\\36-10x\geq 8x\\\\Add \ 10x \ to \ both \ sides\\\\36\geq 8x+10x\\\\36\geq 18x\\\\Divide \ 18 \ to \ both \ sides\\\\2 \geq x\\\\OR\\\\x\leq 2\\\\\rule[225]{225}{2}[/tex]
[tex]\bf{56-10x\geq 20+8x }[/tex]
Subtract 8x on both sides.
[tex]\bf{56-10x-8x\geq 20 }[/tex]
Combine −10x and −8x to get −18x.
[tex]\bf{56-18x\geq 20 }[/tex]
Subtract 56 from both sides.
[tex]\bf{-18x\geq 20-56 }[/tex]
Subtract 56 from 20 to get −36.
[tex]\bf{-18x\geq -36 }[/tex]
Divide both sides by −18. Since −18 is <0, the inequality direction is changed.
[tex]\bf{x\leq \dfrac{-36}{-18} }[/tex]
Divide −36 by −18 to get 2.
[tex]\bf{x\leq 2 \ \ \to \ \ \ Answer}[/tex]
We conclude that the correct option is "C".
{ Pisces04 }[tex]3x+9+2x=x-2x-3[/tex]
Answer:
Step-by-step explanation:
Equation
3x + 9 + 2x = x - 2x - 3
Solution
Combine all the like terms.
3x+2x+9 = x - 2x - 3
5x + 9 = -x - 3 Add x to both sides of the equation
5x+x +9 = -x+x -3 Combine
6x + 9 = - 3 Subtract 9 from both sides of the equation
6x+9-9 = - 3-9 Combine
6x = -12 Divide both sides by 6
6x/6 = -12/6
x = - 2
Answer x = - 2
Triangle A C B is cut by bisector C D. The lengths of sides A C and C B are congruent.
CD bisects ∠ACB. Which statements must be true? Check all that apply.
AD = BD
AC = CD
m∠ACD = m∠BCD
m∠CDA = m∠CDB
m∠DCA = m∠DAC
The statements that are true are AD = BD , m∠ACD = m∠BCD , m∠CDA = m∠CDB , Option A , C and D
What is a Triangle ?A triangle is a polygon with three sides , angles and vertices.
It is given a Δ ACB
CD is the angle bisector of ∠ACB
AC ≅ CB
To determine which statement are true
First it has to be proved that Δ DCB is congruent to Δ ACD
In the triangles
AC = CB (Given )
∠ACD = ∠DCB (CD is the angle bisector of ∠ACB)
DC = DC ( Common side )
thus Δ DCB is congruent to Δ ACD
Therefore the following statements are true
AD = BD (CPCTC)
m∠ACD = m∠BCD (CPCTC)
m∠CDA = m∠CDB (CPCTC)
Therefore Option A , C and D are the statements that are true .
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Answer:
Step-by-step explanation:
a,c,d
There are 8 flavors of cupcakes on the dessert menu. You are asked to choose 3 flavors of cupcakes out of the 10 on the menu. How many differnet combinations of 3 cupcakes are there if order does not matter
There are 80 different combinations of 3 cupcakes are there if order does not matter
How to determine the combination?The given parameters are:
Flavors = 10
Flavors to choose = 3
The number of combination is calculated using:
[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]
This gives
[tex]^{10}C_3 = \frac{10!}{7!3!}[/tex]
Expand
[tex]^{10}C_3 = \frac{10 * 9 * 8 * 7!}{7!3 * 2 * 1}[/tex]
Evaluate quotient
[tex]^{10}C_3 = 80[/tex]
Hence, there are 80 different combinations of 3 cupcakes are there if order does not matter
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Given f(x) = 3x - 1, find f(2)
Answer:
5
Step-by-step explanation:
substitute in 2 for x
3(2) - 1 = 5
Quick algebra 1 question for 50 points!
Only answer if you know the answer, Tysm!
[tex]revenue = selling \: price \times quantity \: sold[/tex]
[tex]m(t) = 3t[/tex]
B)Since we only have 75 tickets to sell, the domain is:t ε [ 0 , 75 ]Range: (extra)m ε [ 0 , 225 ]#1
M(t)=3tBecause
revenue=sold price×no of items
#2
The restriction is of 75tickets and the tickets can't be negative
so
0≤t≤75Domain
[0,75]John plays a game where each question answered correctly is awarded 552 points. john answered 16 questions correctly. work out many points john has in total.
What reason represents the same ratio as for every 12 apples, 9 of them are green?
4: 3
6: 8
9:16
3: 4
Answer:
4:3
Step-by-step explanation:
If you divide both 12 and 9 by 3 (the smallest number they can both be divided by), you get 4 and 3. the ratio is for every 4 apples, 3 would be green. So 4:3
On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The number b varies directly with the number a. For example b = 2a equals negative 2 and StartFraction 3 Over 4 EndFraction. when a = –2a equals negative 2 and StartFraction 3 Over 4 EndFraction.. Which equation represents this direct variation between a and b?
b = –a
–b = –a
b – a = 0
b(–a) = 0
Option 1. The equation that represents the direct variation that exists between a and b is b = –a.
How to find the direct variation hereThe direct variation is of this form y ∝ x
This gives the equation
y = kx
The constant is k
From our question we have
b ∝ a so b = ka
b = [tex]2\frac{3}{4}[/tex]
a = [tex]-2\frac{3}{4}[/tex]
Remember that b = ka
[tex]2\frac{3}{4} = -2\frac{3}{4} k[/tex]
This would cancel out to
1 = -k
or k = -1
Hence the equation would be written as
b = -a
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i need help with this ASAP i've been stuck on this question for a while
Answer:
B. 8
Step-by-step explanation:
Triangle's weight is equal to the sphere's weight.
Total of 16 blocks. Since the triangle's weight is equal to the sphere's, the weight will be half of the blocks.
Divide 2 from 16.
16/2=8
The triangle's weight is equal to 8 blocks.
Hope this helps!
If not, I am sorry.
if a six-sided die is rolled find the odds that the number will be a multiple of 2?
What should be subtracted from 5/8 to make it -1
Answer:
13/8
Step-by-step explanation:
let the number be x
5/8 - x = -1
-x = -1 - 5/8
-x = - 13/8
x = 13/8
5/8- 13/8 = -1
Answer:
13/8
Step-by-step explanation:
5/8 - x = -1 where x is the number to be found.
- x = -1 - 5/8
x = 5/8 + 1
= 13/8.
What is the approximate value of x in the diagram below? (Hint: You will need
to use one of the trigonometric ratios given in the table.)
Answer:
B. 39.59
Step-by-step explanation:
So 43 degrees, you know the length of the opposite side (27) and the angle (43 degrees), the only unknown is the hypotenuse. So you're looking for a trigonometric ratio that uses the angle (all of them do, except technically the inverse don't), the opposite side, and the hypotenuse. Sine is defined as [tex]\frac{opposite}{hypotenuse}[/tex]. So let's plug in known values:
[tex]sin(43) = \frac{27}{x}[/tex]
Multiply both sides by x
[tex]sin(43) * x = 27[/tex]
divide both sides by sin(43)
[tex]x=\frac{27}{sin(43)}[/tex]
Normally I would use a calculator, but in this case I'll use the approximation given in the problem of 0.682
[tex]x=\frac{27}{0.682}[/tex]
simplify the fraction
[tex]x\approx39.59[/tex]
how many Jamaican dollars are equivalent to US $135 , if US =$1 - JA $87.50
11812.5 Jamaican dollars is equivalent to $135
How to determine the amount?The conversion rate is given as:
$1 = JA 87.50
Multiply both sides of the conversion rate by 135
135 * $1 = JA 87.50 * 135
Evaluate the product
$135 = JA 11812.5
Hence, 11812.5 Jamaican dollars is equivalent to $135
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Find the critical value or values of x² based on the given information.
H₁:0> 26.1
n = 9
a = 0.01
A) 20.090
B) 2.088
C) 1.646
D) 21.666
Using a calculator for the chi-square distribution, the critical value is given by:
A) 20.090
How to find the critical value of the chi-square distribution?For a chi-square critical value, three parameters are needed:
The number of degrees of freedom, which is one less than the sample size.The significance level.The tail.In this problem, we have a one-tailed test(as we are testing if the mean is greater than a value), with a significance level of 0.01 and 8 df, hence, using a calculator, the critical value is of 20.09, hence option A is correct.
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Construct a confidence interval for p1-p2 at the given level of confidence.
x1=30, n1=235, x2=39, n2=294, 90 % confidence
Using the z-distribution, the 90% confidence interval for the difference of proportions is given by: (-0.0534, 0.0434).
What is the mean and the standard error for the distribution of differences?For each sample, the mean and the standard error are given as follows:
[tex]p_1 = \frac{30}{235} = 0.1277, s_1 = \sqrt{\frac{0.1277(0.8723)}{235}} = 0.0218[/tex].[tex]p_2 = \frac{39}{294} = 0.1327, s_1 = \sqrt{\frac{0.1327(0.8673)}{294}} = 0.0198[/tex].For the distribution of differences, they are given by:
[tex]\overline{p} = p_1 - p_2 = 0.1277 - 0.1327 = -0.005[/tex].[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{0.0218^2 + 0.0198^2} = 0.0294[/tex]What is the confidence interval?The interval is given by:
[tex]\overline{p} \pm zs[/tex]
In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.
Hence the bounds of the interval are:
[tex]\overline{p} - zs = -0.005 - 1.645(0.0294) = -0.0534[/tex]
[tex]\overline{p} + zs = -0.005 + 1.645(0.0294) = 0.0434[/tex]
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During the two hours of the morning rush from 8 a.m. to 10 a.m., 100 customers per hour arrive at the coffee shop. The coffee shop has a capacity of 0.8 minutes per customers. What is the number of customers waiting at 10 a.m.
So, 40 Customers are waiting at 10 A.M.
According to statement
Number of customers arrives at coffee shop per hour = 100
Capacity of shop for per minute per customer = 0.8 minute
Capacity of shop for customers per hour = 80
Find number of customers are by
Queue growth rate = Demand - Capacity
Put the values in the formula and find the growth rate
So,
Queue growth rate= 100 - 80 = 20.
Length of queue at 10 a.m. = 2 × 20 = 40.
So, 40 Customers are waiting at 10 A.M.
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This linear function has the domain (-2, -1, 0, 1, 2). find the range or output of. h(x)=2x+3
The linear function h(x) = 2x + 3, with the domain {-2, -1, 0, 1, 2}, has the range {-1, 1, 3, 5, 7}.
To find the range, we substitute each value of the domain for x, in the linear function h(x) = 2x + 3, as follows:
For the domain value, x = -2:
h(-2) = 2(-2) + 3,
or, h(-2) = -4 + 3,
or, h(-2) = -1.
Therefore, for the domain value, x = -2, the range value h(-2) is -1.
For the domain value, x = -1:
h(-1) = 2(-1) + 3,
or, h(-1) = -2 + 3,
or, h(-1) = 1.
Therefore, for the domain value, x = -1, the range value h(-1) is 1.
For the domain value, x = 0:
h(0) = 2(0) + 3,
or, h(0) = 0 + 3,
or, h(0) = 3.
Therefore, for the domain value, x = 0, the range value h(0) is 3.
For the domain value, x = 1:
h(1) = 2(1) + 3,
or, h(1) = 2 + 3,
or, h(1) = 5.
Therefore, for the domain value, x = 1, the range value h(1) is 5.
For the domain value, x = 2:
h(2) = 2(2) + 3,
or, h(2) = 4 + 3,
or, h(2) = 7.
Therefore, for the domain value, x = 2, the range value h(2) is 7.
Therefore, the linear function h(x) = 2x + 3, with the domain {-2, -1, 0, 1, 2}, has the range {-1, 1, 3, 5, 7}.
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Solve for x -6x > 17 Give your answer as an improper fraction in its simplest form.
Answer:
Answer: x ≤ q - 17/6.
Step-by-step explanation:
Divide both sides of the inequality by the coefficient of variable
A shop sold white, pink and red T-shirts. 24% of the T-shirts were white. There were 198 more pink than white T-shirts. The remaining 114 T-shirts were red. How many pink T-shirts were there
Number of pink T-shirts was 342
How to solve it?Given: 24% of the T-shirts were white
Let, total number of T-shirts be x
According to question,
Total number of white T-shirts = 24x/100
Total number of pink T-shirt = 24x/100+ 198
Total number of red T-shirts = 114
According to the question:
24x/100+24x/100+ 198 + 114 = x
312 = x - 48x/100
312 = 52x/100
x = (312*100)/52
x = 600
so Number of pink T-shirts :
=(24*600)/100+198
= 144 + 198
= 342
Hence total Number of pink T-shirts was 342.
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Which statements could he include in his explanation? select two options. the domain of both functions is all real numbers. the domain of f(x) is x > 5. the domain of g(x) is x > 5. the range of f(x) is y > 0. the range of g(x) is y > 0.
The correct option is 'The domain of both functions is all real numbers'.
According to statement
Here, functions are f(x) = 5x and g(x) =5x
Since the domain of f(x) is, D= { x : x belongs to all real numbers.}
Therefore, Domain of f(x) is all real numbers.
Since f(x) and g(x) have the same value,
Therefore, Domain of g(x) is also the set of real numbers.
Now, range of f(x) is , R= { 5x : x belongs to all real numbers.}
Therefore, Range of f(x) is all real numbers.
Range of g(x) is also all real numbers.
So, we can say by the above explanation, only option (1) is correct.
DISCLAIMER: The question was incomplete. Please find the full content below.
QUESTION
Keshawn is asked to compare and contrast the domain and range for the two functions.
f(x) = 5x
g(x) = 5x
Which statements could he include in his explanation? Check all that apply.
1. The domain of both functions is all real numbers.
2. The domain of f(x) is x > 5.
3. The domain of g(x) is x > 5.
4. The range of both functions is y > 5.
5. The range of f(x) is y > 0.
6. The range of g(x) is y > 0.
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Write an equation of the line that passes through point (0,2) and is perpendicular to line y=1/2+1
can someone help me with this
Considering the given graph of the function, we have that:
Function Notation: f(1) = -3.Ordered pair: (1,-3).Verbal statement: If x is equal to -1, then the value of f(x) is equal to -3.How to find the numeric value of a function looking at it's graph?To find the numeric value of the function, we get a value of x(horizontal axis), and then look at the corresponding value y(vertical axis), then y = f(x).
In the graph of this function, we have that when x = 1, y = -3, hence:
Function Notation: f(1) = -3.Ordered pair: (1,-3).Verbal statement: If x is equal to -1, then the value of f(x) is equal to -3.More can be learned about functions at https://brainly.com/question/25537936
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(2 StartRoot 7 EndRoot + 3 StartRoot 6 EndRoot) (5 StartRoot 2 EndRoot + 4 StartRoot 3 EndRoot)
HELP HELP HELP
Just a quick question for 100 points! :)
Answer:
see attached graphs
Step-by-step explanation:
Transformations
For a > 0
[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]
[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]
[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]
[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]
[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]
[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]
[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]
[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]
Parent function: [tex]f(x) = x[/tex]
Each transformation is a transformation of the parent function only:
Translation of 4 units down
[tex]\implies f(x)-4=x-4[/tex]
[tex]\implies y=x-4[/tex]
A stretch by a factor of 3
[tex]\implies 3f(x)=3x[/tex]
[tex]\implies y=3x[/tex]
A reflection and a translation 1 unit up
[tex]\implies f(-x)+1=-x+1[/tex]
[tex]\implies y=-x+1[/tex]
a) If x and 125° are adjacent angles in linear pair, find xº [with proper process]
Answer:
x=55°
Step-by-step explanation:
x=180°-125°
x=55°
Can't seem to solve this one
Answer:
.88
Step-by-step explanation:
[tex] \sqrt{.7775} = .88[/tex]
The standard deviation is the square root of the variance.
Alicia walked 3 m east and then 6 m north. How far is she from the starting point?
Answer:
6.708 miles
Step-by-step explanation:
She walked 3 miles to the right, and 6 miles up. The shortest route she could take back to her starting point is a diagonal, which we can solve for using the Pythagorean theorem, a^2 + b^2 = c^2. We're solving for c.
9 + 36 = c^2
c^2 = 45
c = 6.708
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