Answer:
Step-by-step explanation:
Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.
From the question, we can tell it is a inversed-cone (upside down)
Volume of Cone = [tex]\pi r^{2} \frac{h}{3}[/tex]
a) Given Diameter , d = 15.5cm and Length , h = 350cm,
we first find the radius.
[tex]r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm[/tex]
We will now find the volume of the cone.
Volume of cone [tex]\pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}[/tex]
We know the density of ice is 0.93 grams per [tex]1cm^{3}[/tex]
[tex]1cm^{3} =0.93g\\\frac{168175\pi }{24} cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g[/tex](Nearest Gram)
b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm
and the new length, h = 350cm - 15cm = 335cm
Now we will find the volume of this newly-shaped cone.
Volume of cone = [tex]\pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}[/tex]
Volume of cone being melted = New Volume - Original volume
= [tex]\frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}[/tex]
c) Lets take the bucket as a round cylinder.
Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.
Volume of cylinder = [tex]\pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}[/tex]
To overflow the bucket, the volume of ice melted must be more than the bucket volume.
Volume of ice melted after 5 hours = [tex]5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}[/tex]
See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.
Volume of bucket - Volume of ice melted after 5 hours
= [tex]\frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}[/tex]
from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.
PLEASE HELP ME! I WILL AWARD BRAINLIEST TO WHOEVER ANSWERS THE QUESTION BEST!
Which of the following could be solution to the equation below?
[tex]cos(3x+4)=sin(2x+6)[/tex]
A. x = 2, sin 10° = cos 10°
B. x = 16, sin 52° = cos 38°
C. x = 34, sin 74° = cos 106°
D. x = 16, sin 38° = cos 52°
Using complementary angles, it is found that a solution to the given equation is:
D. x = 16, sin 38° = cos 52°.
What are complementary angles?
Two angles are called complementary if the sum of their measures is of 90º. If two angles A and B are complementary, we have that:
cos(A) = sin(B) and sin(A) = cos(B).
In this problem, the expression is:
cos(3x + 4) = sin(2x + 6).
Hence:
3x + 4 + 2x + 6 = 90
5x = 80
x = 16.
Then:
cos(3x + 4) = cos(52).sin(2x + 6) = sin(38).Which means that option D is correct.
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The following present value factors are provided for use in this problem.
Periods Present Value
of $1 at 8% Present Value of an
Annuity of $1 at 8%
1 0.9259 0.9259
2 0.8573 1.7833
3 0.7938 2.5771
4 0.7350 3.3121
Xavier Co. wants to purchase a machine for $37,500 with a four year life and a $1200 salvage value. Xavier requires an 8% return on investment. The expected year-end net cash flows are $12,500 in each of the four years. What is the machine's net present value?
$(3901).
$3901.
$4783.
$(4783).
$42,283.
The net present value of machine is $5982
What is investment?An investment is an asset or item acquired with the goal of generating income or appreciation.
As, 4th Year Cash Flow
= Salvage Value + Expected End Year Net Cash Flow
= $1,200 + $12,500
= $13,700
Year Cash flow ($) PVF at 8% Present value ($)
0 37,500 1.000 -36,300
1 12,500 0.9259 11573.75
2 12,500 0.8573 10716.25
3 12,500 0.7938 9922.5
4 13,700 0.7350 10069.5
Net value 5982
Hence, net present value of machine is $5982
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Which equation represents the line that passes through the points 7,8 and 3,-4
Answer:
y = 3x - 13
Step-by-step explanation:
We are given the points (7,8) and (3,-4)
We want to write an equation of the line that passes through those 2 points.
There are 3 ways to write the equation of the line:
Slope-intercept form, which is y=mx+b, where m is the slope and b is the value of y at the y intercept.Standard form, which is ax+by=c, where a, b, and c are free integer coefficients, but a and b cannot be 0 and a cannot be negative. Point-slope form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1 ,y_1)[/tex] is a point.Although while any one of these options work, the most common way is to use slope-intercept form, so let's do it that way.
First, we need to find the slope of the line.
The slope (m) can be found using this formula: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are points.
Even though we already have 2 points, let's label their values to avoid any confusion.
[tex]x_1=7\\y_1=8\\x_2=3\\y_2=-4[/tex]
Now substitute these values into the formula.
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{-4-8}{3-7}[/tex]
Subtract.
m=[tex]\frac{-12}{-4}[/tex]
Divide.
m = 3
The slope of the line is 3.
Here is the equation of the line so far:
y = 3x + b
We now need to find b.
As the equation passes through (7,8) and (3,-4), we can use either one of the points to help us solve for b.
Taking (7,8) for instance:
Substitute 7 as x and 8 as y in the equation.
8 = 3(7) + b
Multiply
8 = 21 + b
Subtract 21 from both sides
-13 = b
Substitute -13 as b in the equation.
y = 3x - 13
Topic: finding the equation of the line
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A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the line that passes through the points (7,8) and (3,-4) is y=3x-13.
What is the equation of a line?A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of line is given by,
y =mx + c
where,
x is the coordinate of the x-axis,
y is the coordinate of the y-axis,
m is the slope of the line, and
c is the y-intercept.
The slope of the equation will be,
Slope, m = (-4-8)/(3-7) = -12/-4 = 3
Substitute one of the points in the equation of the line,
-4 = 3(3) + C
C = -13
Hence, the equation of the line that passes through the points (7,8) and (3,-4) is y=3x-13.
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Compare A and B in three ways, where A = 1.8 million is the 2012 population of city X and B = 2.6 million is the 2012 population of city Y.
a. Find the ratio of A to B.
b. Find the ratio of B to A.
c. Complete the sentence: A is ____ percent of B.
The function g(x) = p sin x +q, where p>0, has a maximum value of 10 and a minimum value of -4. Find the value of p and of q.
Answer: [tex]p=7, q=3[/tex]
Step-by-step explanation:
The midline of the function is
[tex]\frac{10-4}{2}=3 \implies q=3[/tex]
This means that to obtain a maximum of 10, when [tex]\sin x[/tex] reaches it's maximum, 1, [tex]g(x)=p+q=10 \implies p=7[/tex]
Lily read 3 books in 4 months. What was her rate of reading in books per month? Express your answer in simplest form.
Answer:
1.33 repeating
Step-by-step explanation:
you just do 4 divided by 3.
Please mark as brianliest if i got it right
explain the error and solve the equation correctly. Be sure to use the equation editor to show your work
(x-3)(x+1)=5
The solution to the given linear equation are -4 and 2
Solving quadratic equationQuadratic equations are equations that has a leading degree of 2. Given the expression below
(x-3)(x+1)=5
Expand
x^2+x - 3x - 3 = 5
x^2 - 2x - 8 =0
Factorize
x^2 + 4x - 2x - 8= 0
x(x+4)-2(x+4) = 0
x = -4 and 2
Hence the solution to the given linear equation are -4 and 2
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A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be __________.
A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be 0 to -1. Then the correct option is A.
What is a correlation coefficient?A mathematical indicator of the degree of the association seen between fluctuation of 2 factors is the correlation coefficient.
A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be 0 to -1.
Then the correct option is A.
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z varies directly as x⎯⎯√ and inversely as y2. If z=182 when x=25 and y=8, find z if x=64 and y=3.
When x = 64 and y = 3, we will have:
z = 3,313.21
How to find the value of z?
First, we know that z varies directly with x and inversely with y², then we can write:
z = k*x/y^2
Where k is a constant.
We know that z = 182 when x = 25 and y = 8, replacing that we can find the value of k.
182 = k*25/(8²)
k = 182*8²/25 = 465.92
Now, we just need to evaluate the function in x = 64 and y = 3.
z = (465.92)*64/3² = 3,313.21
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18. In the diagram below, PQRS is a square Find the equation of the circle that will pass through the four vertices of the square
R(2, - 2)
S
P(- 2, 2)
Q
An equation of the circle that will pass through the four (4) vertices of the square is (x + 2)² + y² = 2².
How to find the equation of this circle?Mathematically, the general form of the equation of a circle is given by;
(x - h)² + (y - k)² = r²
Where:
h and k represents the coordinates at the center.r is the radius of a circle.Note: The center of a circle lies on the midpoint of the diagonal of a square, which is formed by joining its endpoints (opposite).
Midpoint on x-coordinate is given by:
Midpoint = (-2 - 2)/2
Midpoint = -4/2 = -2.
Midpoint on y-coordinate is given by:
Midpoint = (-2 + 2)/2
Midpoint = 0/2 = 0.
Thus, the center (h, k) = (-2, 0).
For the radius, we have:
r = √(-2)² + 0²
r = √4 = 2.
Substituting the parameters into the general equation, we have;
(x - (-2))² + (y - 0)² = 2²
(x + 2)² + y² = 2²
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cual es la ecuación de la recta que pasa por el punto (2;-1/2) y tiene de pendiente m=-2/3
Answer:
y = (-2/3)x + 5/6
Step-by-step explanation:
The general structure of a line in slope-intercept form is:
y = mx + b
In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m". To find the value of "b", you can plug the slope and the values from the point (2, -1/2) into the general equation.
m = -2/3
Point (2, -1/2):
x = 2 and y = -1/2
y = mx + b <----- Slope-intercept form
y = (-2/3)x + b <----- Insert -2/3 in "m"
-1/2 = (-2/3)(2) + b <----- Insert "x" and "y" values from point
-1/2 = -4/3 + b <----- Multiply -2/3 and 2
-3/6 = -8/6 + b <----- Give the fractions common denominators
5/6 = b <----- Add 8/6 to both sides
Thus, the equation of the line is:
y = (-2/3)x + 5/6
Given: Triangle ABC, mmBC=24 cm, line segment AL- < bisector
Find: AL
AL= __cm
Please answer in detail ASAP thank you so much it would help a lot <3
The value of line AL is 21. 51cm
How to determine the lengthTo find line AL,
Using
Sin α = opposite/ hypotenuse to find line AB
Sin 90 = x/ 24
1 = x/24
Cross multiply
x = 24cm
Now, let's find line AC
Sin angle B = line AC/24
Note that to find angle B
angle A + angle B + angle C = 180
But angle B = 2 Angle A
x + 2x + 90 = 180
3x + 90 = 180
3x = 180-90
x = 30°
Angle B = 2 × 30 = 60°
Sin 60 = x/ 24
0. 8660 = x/24
Cross multiply
x = 24 × 0. 8660
x = 20. 78cm
We have the angle of A in the given triangle to be divide into two by the bisector, angle A = 15°
To find line AL, we use
Cos = adjacent/ line AL
Cos 15 = 20. 78/ line AL
Line AL = 20. 78/ cos 15
Line AL = 20. 78 / 0. 9659
Line AL = 21. 51 cm
Thus, the value of line AL is 21. 51cm
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A shape is picked at random from this group. Which theoretical probabilities are exactly 3/4?
Check all that apply.
not picking a triangle
picking a square
picking a shape with only straight edges
not picking a circle
not picking a square
Probability helps us to know the chances of an event occurring. The correct option is D, not picking a circle.
What is Probability?Probability helps us to know the chances of an event occurring.
[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]
For the theoretical probability to be 3/4, the number of desired outcomes must be 6. Therefore, let's check the number of desired outcomes,
Not picking a triangle = 4
Picking a square = 3
Picking a shape with only straight edges = 0
Not picking a circle = 6
Not picking a square = 5
Hence, the correct option is D, not picking a circle.
The group of the shape is given in the below image.
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You are volunteering to help with the soccer team fundraiser for Valentine's Day. Your team promised to deliver one 16 ounce bag of nuts to students with at least 60% chocolate-covered nuts inside.
When you arrive, instead of a bag of plain nuts and chocolate nuts, you find there are two bags of mixed nuts. The first says it is 50/50 plain and chocolate covered. The second bag contains 80% chocolate covered nuts.
The team is dismayed, but you come up with a solution. You suggest combining
ounces* of the 50/50 bag of nuts with
ounces* of the 80% bag of nuts, to make it an approximately 60% mixture.
*estimate
Then another student on the team says, "Wait, we promised at least 60%. So if we just do half and half won't we be giving them at least 60%?" This student
correct.
The student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, is correct.
What is the implication of the phrase "at least"?The phrase "at least" means the minimum that is true or possible.
Mathematically, by "at least," we mean 'equal to or greater than.'
Data and Calculations:Since each bag of nuts contain 16 ounces,
The 1st bag contains x/2 ounces (50%) of plain nuts and x/2 ounces (50%) of chocolate-covered nuts.
The 2nd bag contains x/5 ounces (20%)of plain nuts and 4x/5 ounces (80%) of chocolate-covered nuts.
If half of the 1st bag is mixed with half of the 2nd bag, each bag will contain only 65% (that is, 25% (50%/2) from the 1st bag and 40% (80%/2) from the 2nd bag).
Thus, the student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, is correct since they will not be given less than 60% of chocolate-covered nuts inside.
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What is the quotient of startstartfraction 90 (cosine (startfraction pi over 4 endfraction) i sine (startfraction pi over 4 endfraction) ) overover 2 (cosine (startfraction pi over 12 endfraction) i sine (startfraction pi over 12 endfraction) ) endendfraction ?
The value of the quotient is [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]
How to determine the quotient?The expression is given as:
[tex]\frac{90\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{2\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]
Divide 90 by 2
[tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]
As a general rule, we have:
[tex]\frac{\cos(\frac{\pi}{A}) i\sin(\frac{\pi}{A})}{\cos(\frac{\pi}{B}) i\sin(\frac{\pi}{B})} = \cos(\frac{\pi}{2B/A}) + i\sin(\frac{\pi}{2B/A})[/tex]
The above means that:
A = 4 and B = 12
So, we have:
2B/A = 2 * 12/4
Evaluate
2B/A = 6
So, the equation becomes
[tex]\frac{\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = \cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6})[/tex]
Substitute [tex]\frac{\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = \cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6})[/tex] in [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]
[tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]
Hence, the value of the quotient is [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]
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Complete question
What is the quotient of [tex]\frac{90\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{2\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]
Please help!!!! For the exponential function...
Answer: b.) 40
Given that:
f(x) = 5 × 2ˣ
To find f(3), simplify insert [x = 3] in the given equation:
f(3) = 5 × 2³
f(3) = 5 × 2 × 2 × 2
f(3) = 40
These 3 points are on a parabola defining the edge of a ski:
(-4,1)
(-2,0.94)
(0,1)
The general form for the equation of a parabola is .
1.
Use the x- and y-values of 1 to build a linear equation with 3 variables: A, B, and C.
Repeat this process with the other 2 points to build a 2nd linear equation.
Record all three equations in the box below.
2.
Build a matrix equation that represents this system of equations. Record your matrix equation here.
3.
Use a graphing calculator or other graphing utility to find the inverse of the coefficient matrix. Record your result here.
4.
Use the inverse matrix to solve the system of equations. Record the equation of the parabola here.
The equation of the parabola is y = 0.015x^2 + 0.06x + 1
The linear equationsA parabola is represented as:
y = ax^2 + bx + c
The points are given as:
(-4,1), (-2,0.94) and (0,1)
When these points are substituted in y = ax^2 + bx + c, we have the following linear equations
16a - 4b + c = 1
4a - 2b + c = 0.94
c = 1
The matrix that represent the system of equationsIn (a), we have:
16a - 4b + c = 1
4a - 2b + c = 0.94
c = 1
Remove the variables (leaving the coefficients)
a b c
16 -4 1 1
4 -2 1 0.94
0 0 1 1
So, the matrix representation of the system of equations is:
[tex]\left[\begin{array}{ccc}16&-4&1\\4&-2&1\\0&0&1\end{array}\right] \left[\begin{array}{c}1&0.94&1\end{array}\right][/tex]
The inverse of the coefficient matrixUsing a graphing calculator, we have the inverse of the coefficient matrix to be
[tex]\left[\begin{array}{ccc}0.125&-0.25&0.125\\0.25&-1&0.75\\0&0&1\end{array}\right][/tex]
The solution to the system of equationsUsing a graphing calculator, we have the solution to the system of equations to be
a = 0.015
b = 0.06
c = 1
Recall that:
y = ax^2 + bx + c
So, we have:
y = 0.015x^2 + 0.06x + 1
Hence, the equation of the parabola is y = 0.015x^2 + 0.06x + 1
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A distributor has received an invoice of $13,190 dated April 12, terms 6/20, n/30 EOM, for a
shipment of coffee makers that arrived on May 25.
a) What is the last day for taking the cash discount?
b) How much is to be paid if the discount is taken? $
The last day for taking the cash discount is May 5 and discount is taken is: $12,398.6.
Cash discountSince the invoice was dated April 12, the last day for taking the cash discount is May 5.
Cash discount
Using this formula
Amount paid =Invoice amount × (1-rate)
Let plug in the formula
Amount paid=$13,190 ×(1-6%)
Amount paid=$13,190×0.94
Amount paid=$12,398.6
Therefore the last day for taking the cash discount is May 5 and the amount to be paid is: $12,398.6.
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Which amount of time is greater for the average person? The total time spent on his/her cell phone in a year’s time, or the total time spent waiting in line when shopping in a lifetime?
Consider it to be 2 separate problems and arrive at your conclusion.
You need to make assumptions, conversions, and math calculations to arrive at your answer. If you choose to research data for this project, that is fine but there is no need to site your references.
The total time spent on his/her cell phone in a year’s time is less than the total time spent waiting in line when shopping in a lifetime.
x= 1825 hrs
z=4929.4 hrs.
This is further explained below.
Which amount of time is greater for the average person?let's say on average a person spends 5 hours on a mobile phone.
Individual annual mobile phone use time.
x= 5x365
x= 1825 hrs
let's consider an average every day a person, spent 5 minutes in the queue when shopping.
Take the average person. 70-year life for a person.
Hence in a year, he spent
y=365x5 mints
y=1825 min
y=30.42 hrs
Hence lifetime time spent on line
z = 70 x 30.42
z=4929.4 hrs.
In conclusion, we estimate that the typical individual will spend z=4929.4 hours waiting in line for merchandise throughout the course of their lifetime.
z=4929.4 hrs.
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If 25% of a dozen egg were used to make
breakfast. how many eggs were left?
Answer: 9 eggs were left.
Step-by-step explanation:
A dozen eggs usually mean there are 12 eggs. We have two ways to solve the problems.
First way:
The egg used to make breakfast: 12 x 25% = 12 x 0.25 = 3
The eggs were left: 12 - 3 = 9
Second way:
12 x (1 - 0.25)
= 12 x 0.75
= 9
How much interest will Brian earn on $875 in his savings account after 3 months if the annual interest rate is 5.5%?
Answer:
$12.03
Step-by-step explanation:
I = prt
I = (875)(0.055)(3/12)
I = 12.03
Answer: $12.03
find x and y.
someone pls help !
Hello !
3y + 12 =2(y + 30)
⇔ 3y + 12 = 2y + 60
⇔ y + 12 = 60
⇔ y = 60 - 12
⇔ y = 48
Answer:
y = 48
Step-by-step explanation:
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
3y + 12 is an exterior angle of the triangle , so
3y + 12 = y + 30 + y + 30 ( base angles of an isosceles Δ are congruent )
3y + 12 = 2y + 60 ( subtract 2y from both sides )
y + 12 = 60 ( subtract 12 from both sides )
y = 48
Find the indicated function values for the function f(x) = 3x² + 2x - 6.
a. f(0)
b. f(2)
c. f(-4)
d. f(b)
e. f(4a)
a. f(0) =
(Simplify your answer.)
Answer:
a. f(0) = -6
b. f(2) =10
c. f(-4) = 32
d. f(b) = 3b^2+2b-6
e. f(4a) = 48a^2+8a-6
The function values for the function f(x) = 3x² + 2x - 6, for the values are:
a. f(0) = -6
b. f(2) = 10
c. f(-4) = 34
d. f(b) = 3b² + 2b - 6
e. f(4a) = 48a² + 8a - 6
How are function values calculated?To calculate function value f(k) for a function f(x), we substitute variable x = k, in the function f(x).
How to solve the question?In the question, we are asked to find the function value for the function f(x) = 3x² + 2x - 6 for:
a. f(0)
b. f(2)
c. f(-4)
d. f(b)
e. f(4a).
We calculate these in the following ways:-
a. f(0):
We substitute the value of x = 0 in the function f(x).
Therefore f(0) = 3(0)² + 2(0) - 6,
or, f(0) = 0 + 0 - 6 = -6.
Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is -6.
b. f(2):
We substitute the value of x = 2 in the function f(x).
Therefore f(2) = 3(2)² + 2(2) - 6,
or, f(2) = 12 + 4 - 6 = 10.
Therefore, the function value f(2) for the function f(x) = 3x² + 2x - 6 is 10.
c. f(-4):
We substitute the value of x = -4 in the function f(x).
Therefore f(-4) = 3(-4)² + 2(-4) - 6,
or, f(-4) = 48 - 8 - 6 = 34.
Therefore, the function value f(-4) for the function f(x) = 3x² + 2x - 6 is 34.
d. f(b):
We substitute the value of x = b in the function f(x).
Therefore f(b) = 3(b)² + 2(b) - 6,
or, f(b) = 3b² + 2b - 6.
Therefore, the function value f(b) for the function f(x) = 3x² + 2x - 6 is 3b² + 2b - 6.
e. f(4a):
We substitute the value of x = 4a in the function f(x).
Therefore f(4a) = 3(4a)² + 2(4a) - 6,
or, f(0) = 48a² + 8a - 6.
Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is 48a² + 8a - 6.
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Which of the following best describes the ordered pairs listed below? (-3, 4), (2, -6), (7, -16), (9, -20) A. function only B. both a relation and a function C. neither a relation nor a function D. relation only
Determine whether the events A and B are mutually exclusive. Explain your choice. A sample of 75 books is selected from a library. A: At least 10 of the authors are female: B: At least 10 of the books are fiction.
The events are not mutually exclusive.
What are Mutually exclusive events ?Two events that cannot occur at the same time are called Mutually exclusive event.
It is given that
A sample of 75 books is selected from a library.
Event A: At least 10 of the authors are female
Event B : At least 10 of the books are fiction.
Both can happen simultaneously
Therefore the events are not mutually exclusive.
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which expressionis equal to9(9MPLUS3t)
Answer:
81m + 27t
Step-by-step explanation:
Using distributive property, this expression can be solved.
So 9(9m + 3t) has operations in it.
9 would be multiplied by whatever is in the parenthesis followed by the variable.
So 9 * 9 = 81.
9 * 3 = 27.
So putting it together with the variables.
It would be:
⇒ 81m + 27t
Determine if
16
x
2
−
25
y
2
=
1
16
x
2
-
25
y
2
=
1
is a hyperbola and if it is, which type it is. The transverse axis is
what is A and B
The values of a and b are 1/4 and 1/5 respectively
How to determine the true statement?The function is given as:
16x^2 - 25y^2 = 1
The above function is a horizontal hyperbola.
A horizontal hyperbola that passes through the origin is represented as:
[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]
Rewrite 16x^2 - 25y^2 = 1 as
[tex]\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1[/tex]
By comparison, we have:
[tex]a^2 = \frac{1}{16}[/tex]
[tex]b^2 = \frac{1}{25}[/tex]
Solve for a and b
[tex]a = \frac{1}{4}[/tex]
[tex]b = \frac{1}{5}[/tex]
Hence, the values of a and b are 1/4 and 1/5 respectively
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HELP ASAP!!!!GIVING BRAINLIEST!!!!!!
If f(x)=2x^2+2 and g(x)=x^2-1, find (f-g)(x).
Answer: B. x^2 + 3
Step-by-step explanation:
2x^2 + 2 -(x^2 - 1)
2x^2 + 2 - x^2 + 1
x^2 + 3
If your piece of graph paper goes only 20 blocks above the x-axis, then where will the
function below first go off the page?
y = 2²
The function will go somewhere between x = 4 and x = 5
How to determine the location of the function?The function is given as:
y = 2^x
The question implies that:
If the maximum y value on a graph is x = 20; What is the maximum x value on the graph of y = 2^x
To do this, we start by setting y to 20.
So, we have:
2^x = 20
Take the logarithm of both sides
x log(2) = log(20)
Divide by log(2)
x = 4.32
4.32 is between 4 and 5
Hence, the function will go somewhere between x = 4 and x = 5
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what’s the answer to 3\4(8x + 12) = 3
Answer:
x = - 1
Step-by-step explanation:
[tex]\frac{3}{4}[/tex] (8x + 12) = 3 ( multiply both sides by 4 to clear the fraction )
3(8x + 12) = 12 ( divide both sides by 3 )
8x + 12 = 4 ( subtract 12 from both sides )
8x = - 8 ( divide both sides by 8 )
x = - 1