Answer:
According to second law of motion,the acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
So simply, it can be affected due to increasing force as there is close relationship between momentum.
Explanation:
The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion.
I hope it was helpful for you :)
You are raising up a big bucket of water from a 25.9 m deep well. The combined mass of the water and the bucket is 13.9 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 19.3 kg.
1. How much work do you perform during the lifting process?
2. If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?
1. The amount of work done during the lifting process is 8426.824 J
2. The average power used in the process is 80.26 Watts
1. How to determine the workdone Combine mass (m) = 13.9 + 19.3 = 33. 2 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 25.9 mWork done (Wd) =?Wd = mgh
Wd = 33. 2 × 9.8 × 25.9
Wd = 8426.824 J
2. How to determine the powerWork done (Wd) = 8426.824 JTime (t) = 1.75 mins = 1.75 × 60 = 105 sPower (P) =?P = Wd / t
P = 8426.824 / 105
P = 80.26 Watts
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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m.
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
How much energy was lost to air friction? The ball is kicked without a spin.
The amount of energy lost to air friction, given the data is 37.71 J
How to obtain the initial energyInitial velocity (u) = 15.1 m/sMass (m) = 450 g = 450 / 1000 = 0.45 KgInitial Energy (E₁) = ?
E₁ = ½mu²
E₁ = ½ × 0.45 × 15.1²
E₁ = 51.3 J
How to obtain the final energyFinal velocity (u) = 19.89 m/sMass (m) = 450 g = 450 / 1000 = 0.45 KgFinal Energy (E₂) = ?
E₂ = ½mv²
E₂ = ½ × 0.45 × 19.89²
E₂ = 89.01 J
How to determine the energy lostInitial Energy (E₁) = 51.3 JFinal Energy (E₂) = 89.01 JEnergy lost =?Energy lost = E₂ - E₁
Energy lost = 89.01 - 51.3
Energy lost = 37.71 J
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someone solvw this for me please
The velocity of the mass at time, t = 1 s, is determined as 20 m/s.
Magnitude of the force experienced by the body
The magnitude of the force experienced by the body is calculated as follows;
|F| = √(8² + 6²)
|F| = 10 N
Acceleration of the massFrom Newton's second law of motion;
F = ma
where;
m is massa is accelerationa = F/m
a = 10 /0.5
a = 20 m/s²
Velocity of the mass after 1 secondv = at
v = 20 x 1
v = 20 m/s
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A fish rests on the bottom of the bucket of water while the bucket is being weighed on a scale. When the fish begins to swim around, does the scale reading changed? Explain.
When the fish begins to swim around, the reading of the scale won't change because mass of the fish and the bucket is constant.
Weight of the fish and bucket
The weight of the fish inside the bucket depends on the mass of the bucket and fish.
W = mg
where;
m is mass of the bucket and fishg is acceleration due to gravityThus, when the fish begins to swim around, the reading of the scale won't change because mass of the fish and the bucket is constant.
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A planet X moves in an elliptical path as shown below. At which point does the planet moves faster. B Assume, Ethiopian institute of space science and technology, allows to launch a space station with you. While you are in orbit, you gets thirsty. The only thing in the space station were a cup of water. you go to the cup of water and pick it up, But unfortunately your hand is twisted and the cup is turned down. Because the cup is turned down, water pour on to the floor. How would you get water?
We can get water from the sweat and exhaled breath of the people present in the space station.
How would you get water?We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through condensation on the Space Station's walls.
So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.
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Calculate the x and y components for the vector below. Show all work. d = 43.2 m [43.0° W of N]
The x and y components of the vector is 31.59 m and 29.46 m respectively.
X component of the vector
The x component is calculated as follows;
v(x) = v cos(43)
v(x) = 43.2 m x cos(43) = 31.59 m
Y component of the vectorThe y component is calculated as follows;
v(y) = v sin(43)
v(y) = 43.2 m x sin(43) = 29.46 m
Thus, the x and y components of the vector is 31.59 m and 29.46 m respectively.
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Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m. What is the net force on particle q3?
The net force on particle q3 is 112.11 N
What is electrostatic force?The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.
F = kq₁q₂/r²
where k = 9 x 10⁹ N.m²/C²
The Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m.
The net force F3 = F13 + F23
Substitute the values, we get the force F on q3 as
F3 = 9 x 10⁹x53.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.5+0.95)² + 9 x 10⁹x105.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.95)²
F3 = 112.11 N
Thus, the magnitude of the force on charge q3 is 112.11 N.
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I need help asap!!!
Answer:
Probably competition with television news-
by 1953 television was becoming common in many houses and people could obtain news from television newscasts
6. (a) Suppose the earth is revolving round the sun in a circular orbit of radius one b astronomical unit (1.5% 10 km). Find the mass of the sun. G = 6.67 x 10" N m² kg 2. (b) If the mass of sun is 2 x 10" kg, distance of earth from the sun is 1.5 x 10¹ m and period of revolution of the former around the latter is 365.3 days, find the value of G.
Answer:
tough
ques
Explanation:
Which of the following would be the magnitude of the vector given a horizontal component of 30 and a
vertical component of 40?
Answer:
50
Explanation:
Use the Pythagorean theorem to find the length of the diagonal, or the hypotenuse of an imaginary triangle. 30^2 + 40^2 = 2500, which is 50^2. So, the magnitude is 50.
Brainliest, please :)
Select the option no explanation needed
Answer:
c
Explanation:
the formula Torque = Force X Distance. While distance is measured in meters and force is measured in newton so torque is measured in newton ⋅ meter
Ben, a psychology student, decides to examine masking behaviors, now that more people are vaccinated. He goes to his local grocery store, finds a specific spot to sit, and counts the number of people he sees with masks or without masks across 2 weeks. Ben is most likely conducting a(n) ____________________ study.
Ben as a psychology student is most likely conducting a behavioral study.
What is psychology?
Psychology can simply be defined as the study of human mind, conscious and unconscious, thoughts and feelings.
In conclusion, Ben as a psychology student is most likely conducting a behavioral study.
Some few branches of psychology are:
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1. Block A with a mass of 1 kg and block B with a mass of 2 kg lie on a smooth table. You wish to apply a horizontal force to each ball to give them the same horizontal acceleration (and you may safely ignore friction). Which of the following best describes the relative magnitude of the forces you must apply?
a) The magnitude of the force on block A must be twice as much as the force on block B.
b) The magnitude of the force on block B must be twice as much as the force on block A.
c) Both forces must have the same magnitude.
d) More information is needed to determine the relative magnitudes of the forces.
2. Block A has a mass of 1 kg and block B has a mass of 2 kg. Which of following best describes the relative magnitudes of the gravitational force (due to the Earth) on each block?
a)The gravitational force on block A is twice as much as the gravitational force on block B.
b)The gravitational force on block B is twice as much as the gravitational force on block A.
c)Both gravitational forces have the same magnitude.
d)More information is needed to determine the relative magnitudes of the forces.
3. You hold block A with a mass of 1 kg in one hand and block B with a mass of 2 kg in the other. You release them both from the same height above the ground at the same time. (Air resistance can safely be ignored as they fall.) Which of the following describes and explains the motion of the two objects after you release them?
a)Block A hits the ground before the block B. The same force of gravity acts on both objects, but because block A has a lower mass, it will have a larger acceleration.
b)Block B hits the ground before the block A. The larger force on block B causes it to have a greater acceleration than block A.
c)The two blocks hit the ground at the same time, because they both accelerate at the same rate while falling. The greater gravitational force on block B is compensated by its greater mass, giving it the same acceleration.
d)The two blocks hit the ground at the same time, because they both move at the same constant speed while falling. The forces on the blocks are irrelevant once they start falling.
The gravitational force on block B is twice as much as the gravitational force on block A.
What is Force?Force is the product of mass and acceleration. If the mass of A is 1Kg and the mass of B is 2Kg, In order to give the masses the same horizontal acceleration, the magnitude of the force on block B must be twice as much as the force on block A.
Given that the mass of A is 1Kg and the mass of B is 2Kg, the gravitational force on block B is twice as much as the gravitational force on block A.
If I hold block A with a mass of 1 kg in one hand and block B with a mass of 2 kg in the other and release both from the same height above the ground at the same time, the two blocks hit the ground at the same time, because they both accelerate at the same rate while falling. The greater gravitational force on block B is compensated by its greater mass, giving it the same acceleration.
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How long will it take a 50w motor to lift a 20 kg object 5 m?
Answer:
50+20=70
70÷5=14
Explanation:
50×20=1000
1000÷5=200
Answer:
Approximately [tex]20\; {\rm s}[/tex], assuming no energy loss and that [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex].
Explanation:
If the gravitational field strength is constantly [tex]g[/tex], lifting an object of mass [tex]m[/tex] by a height of [tex]\Delta h[/tex] would increase the gravitational potential energy ([tex]\text{GPE}[/tex]) of that object by [tex]m\, g\, \Delta h[/tex].
In this question, [tex]m = 20\; {\rm kg}[/tex] and [tex]\Delta h = 5\; {\rm m}[/tex]. Assume that [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex]. Hence, the [tex]\text{GPE}[/tex] that this object would eventual gain would be:
[tex]\begin{aligned}m\, g\, \Delta h &= 20\; {\rm kg} \times 10\; {\rm N \cdot kg^{-1}} \times 5\; {\rm m} \\ &= 1000\; {\rm N \cdot m} \\ &= 1000\; {\rm J}\end{aligned}[/tex].
Thus, this motor would need to do (at least) [tex]1000\; {\rm J}[/tex] of work to lift this object up by [tex]5\; {\rm m}[/tex]. The power rating of this motor, [tex]P = 50\; {\rm W} = 50\; {\rm J \cdot s^{-1}}[/tex], means that (assuming no energy loss) this motor could do [tex]50\; {\rm J}[/tex] of work every second.
The time it would take for this motor to do [tex]1000\; {\rm J}[/tex] of work under these assumptions would be:
[tex]\begin{aligned}t &= \frac{\text{work}}{\text{power}} \\ &= \frac{1000\; {\rm J}}{50\; {\rm J \cdot s^{-1}}} \\ &= 20\; {\rm s}\end{aligned}[/tex].
The figure below shows a man in a boat on a lake. The man's mass is 74 kg, and the boat's is 135 kg. The man and boat are initially at rest when the man throws a package of mass m = 15 kg horizontally to the right with a speed of vi = 5.0 m/s.
What is the velocity of the boat after the package is thrown? Neglect any resistance force from the water. (Give the magnitude in m/s, and select the correct direction from the options given.)
The velocity of the boat after the package is thrown is 0.36 m/s.
Final velocity of the boat
Apply the principle of conservation of linear momentum;
Pi = Pf
where;
Pi is initial momentumPf is final momentumv(74 + 135) = 15 x 5
v(209) = 75
v = 75/209
v = 0.36 m/s
Thus, the velocity of the boat after the package is thrown is 0.36 m/s.
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Who studied highly successful people and developed the hierarchy of needs?
A) Seligman
B) Rogers
C) Maslow
D) Zimbardo
Abraham Maslow was the person who studied highly successful people and developed the hierarchy of needs. Thus, option C is correct.
Who is Abraham Maslow?Abraham Maslow was one of the most influential psychologists of the twentieth century. His work on humanistic psychology and his development in the hierarchy of needs is very popular.
According to Abraham Maslow, humans have five tiers of needs and they are food and shelter, love and belonging, esteem, safety needs, and self-actualization.
The hierarchy of needs has five basic levels. The bottom level comprises the basic needs of people like food, and shelter. Top-level comprises esteem and self-actualization.
Maslow hierarchy of needs involves the model for understanding human behavior. Hence, Abraham Maslow developed the hierarchy of needs. Thus, the correct option is C.
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Which notation is commonly used on force diagrams to show forces acting on an object.
Answer: is F^D
The notation that is commonly used on force diagrams to show forces acting on an object is FD.
What is free body diagram ?A free body diagram is a diagram that contains all the forces acting on an object.
These forces acting on an object include the following :
Upward force (normal reaction due to weight of the object)Downward force (downward force due to weight of the object)Frictional force (force resisting the motion)Thus, the notation that is commonly used on force diagrams to show forces acting on an object is FD.
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All the forces we see and experience are the result of just a few so-called fundamental forces. What are the fundamental forces in nature? Provide a brief explanation of each and an example of how we ‘see’ the forces in action.
The fundamental forces in nature are strong force, weak force, electromagnetic force, and the gravitational force.
Fundamental forces
There are four fundamental forces at work in the universe. These fundamental forces include;
The strong force: this force has strong influence or impact on objects. The weak force: this force has little impact on objects.The electromagnetic force: force due to current flowing in a conductor placed in magnetic field.The gravitational force: this is force of attraction between two objects placed in the universe.Thus, the fundamental forces in nature are strong force, weak force, electromagnetic force, and the gravitational force.
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Which statement best explains the movement of electric current from the clouds to the ground during a lightning storm?
The statement that best explains the movement of electric current is that the ground is positively charged and the clouds are negatively charged.
What is lightning storm?Lightning storm can be defined as the electrical outlet that occurs due to unsteadiness of the storm clouds and the ground.
Lightning storm occurs when opposite charges build up enough in the air leading to rapid discharge of electricity.
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1. A supersonic airplane is flying horizontally at a speed of 2610 km/h. What is the centripetal acceleration of the airplane, if it turns from North to East on a circular path with a radius of 80.5 km?
2. How much time does the turn take?
3. How much distance does the airplane cover during the turn?
1)The centripetal acceleration will be 84622.360 km/h².
2)The time the turn take is 0.19 hour.
3)The distance the airplane cover during the turn is 505.54 km.
What is centripetal acceleration?The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.
The given data in the problem;
R is the radius= 80.5 m
v is the linear speed = 2610 km/h
a is the total acceleration.
1)
The centripetal acceleration is found by
[tex]\rm a_c = \frac{v^2}{R} \\\\ a_c = \frac{(2610 \ km/h)^2}{80.5} \\\\ a_c = 84622.360 \ km/h^2[/tex]
2)
The time the turn take is;
[tex]\rm a= \frac{4 \pi^2R}{T^2} \\\\\ 84622.360 = \frac{4 \times (3.14)^2 \times 80.5}{T^2} \\\\\ T = 0.19 \ hr[/tex]
3)
The distance the airplane cover during the turn is;
C= 2πR
C=2 × 3.14 × 80.5 km
C= 505.54 km
Hence centripetal acceleration, time the turn take, and distance the airplane cover during the turn will be 84622.360 km/h²,0.19 sec, and 505.54 km respectively.
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A prism of angle 60° is of a material of refractive index √√2. Calculate angles of minimum deviation and maximum deviation.
Answer:
i don't know if this helps but The refractive index of the material of the prism of an angle 60 degree is 1.62 for sodium light. there you go hope it helps
Explanation:
3.2 Define conservation of energy.
Answer:
A principle stating that energy cannot be created or destroyed, but can be altered from one form to another.
Explanation:
A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15 degrees above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?
Answer: See below
Explanation:
Given:
Mass of the Mercedes-Benz (m) = 1700 kg
Inclination of the road (θ) = 15.0
The free body diagram is shown in figure attached below
a) The normal force is equal to the cos component of the weight of the car.
[tex]\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}[/tex]
b) The static force will be equal to the weight's sin component.
[tex]\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}[/tex]
Help!!! Asap!!!
The arrows in the diagram show the direction of the magnetic fields of the
atoms that make up an object. Which material could the diagram represent?
A. Paper
B Steel
C Nickel
D Iron
Answer:
Probs paper cuz the rest are metals
the main source of this energy is
.
Answer:motion
Explanation:
kinetic energy of an object that it possess due to its motion.
There is a current of 0.83 A through a lightbulb in a 120 V circuit. What is the resistance of this lightbulb?
Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.
Definition of currentThe flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.
Definition of voltageThe driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.
Definition of resistanceResistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).
Ohm's lawOhm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.
This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.
Mathematically, Ohm's law is expressed as:
[tex]I=\frac{V}{R}[/tex]
Where:
I is the current measured in amps (A).V the voltage measured in volts (V).R the resistance that is measured in ohms (Ω).Resistance of the lightbulbIn this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.
Replacing in the Ohm's Law:
[tex]0.83A=\frac{120 V}{R}[/tex]
Solving:
0.83 A× R= 120 V
[tex]R=\frac{120 V}{0.83A}[/tex]
R= 144.58 Ω
Finally, the resistance of the lightbulb is 144.58 Ω.
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You cover the following displacements every day going to school: d1=50 m, E and d2=95 m, N. You do this for 12 minutes. a) What is your speed in m/s? b) What is your velocity in m/s?
The speeds and velcity will be 0.020 m/sec and 0.0149 m/sec.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.
Given data;
d1=50 m E
d2=95 m N
Time period,t = 12 min = 12 × 60 sec = 7200 sec
The displacement is the shortest distance found from the pythogorous theorem as;
Displacement = √[(50 )²+(95)²]
Displacement = 107.35 m
a)The speed is found as;
Speed = distance / time
Speed = 50 +95 / 7200
Speed = 0.020 m/sec
b)The velocity is found as;
Velocity = Displacement / time
Velocity = 107.35 / 7200
Velocity = 0.0149 m/sec
Hence the speed and the velcity will be 0.020 m/sec and 0.0149 m/sec.
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can you help me? please
Answer
Yes i will help u!
A transformer consists of 340. primary windings and 980. secondary windings. If the emf of the primary coil is 30.0 V, what is the emf across the secondary coil? 34.7 Ω
Answer:
86.47 V
Explanation:
It will be multiplied by the ratio of the windings
980/340 * 30 = 86.47 v
Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 10,600 kg. The thrust of its engines is 25,500 N. (Assume that the gravitational acceleration on the Moon is 1.67 m/s2.)
(a) Calculate its magnitude of acceleration in a vertical takeoff from the Moon.
m/s2
(b) Could it lift off from Earth? If not, why not?
Yes, the thrust of the module's engines is equal to its weight on Earth.
No, the thrust of the module's engines is equal to its weight on Earth.
No, the thrust of the module's engines is less than its weight on Earth.
Yes, the thrust of the module's engines is greater than its weight on Earth.
If it could, calculate the magnitude of its acceleration. (If not, enter NONE.)
m/s2
(a) The magnitude of acceleration in a vertical takeoff from the Moon will be 0.73 m/s².
(b)Option d is correct.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Given data;
Force, F =?
Mass of a fully loaded module,m = 10,600 kg
Acceleration due to gravity on moon,g = 1.67 m/s²
Thrust of its engines is,F= 25,500 N.
The net force is found as follows;
[tex]\rm F_{net} = F -W[/tex]
ma = F-W
(10,600) kg × a = 25,500 N - (10,600 kg )(1.67)
a = 0.73 m/s²
b)
Yes, it lifts off from Earth. Because the thrust of the module's engines is greater than its weight on Earth.
F>W
Hence option d is correct.
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