How do you graph this? y=−5x

Answer:116.886

Step-by-step explanation:multiply all the sides then devide by 1/2

Answer:

15.312

Step-by-step explanation:

Answer:

I think that it is...

Step-by-step explanation:

sorry

Answer:

there are 20

Step-by-step explanation:

there are 60/10 in 6

60/3=20

Answer:

20

Step-by-step explanation:

Answer:

0.81 & 0.83

Step-by-step explanation:

Answer:

sorrry but i need points

Step-by-step explanation:

Answer:

79

Step-by-step explanation:

3=1

4=2

3=101

1=101

2 and 4=180-101=79

Answer:

D

Step-by-step explanation:

the picture pretty much explain it step by step; hope this helped!

Answer:

the second one!

=

Step-by-step explanation:

Answer:

89 cents.

Step-by-step explanation:

hope this helps

Answer:

f(- 3) = - 16

Step-by-step explanation:

To evaluate f(- 3) with x = - 3 in the interval x ≤ - 2, then

f(- 3) = 5x - 1 = 5(- 3) - 1 = - 15 - 1 = - 16

Answer:

D A strait line with a hole because when you cancel you will leave a hole

Step-by-step explanation:

b

Graph the following:

y = (x^2 - x - 2) / (x - 2)

First I'll find any vertical asymptotes, by setting the denominator equal to zero and solving:

x – 2 = 0

x = 2

So I have a vertical asymptote

at x = 2.

I'll dash this in:

graph showing vertical asymptote

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Looking at the degrees of the numerator and denominator, I see that the numerator is a quadratic while the denominator is linear. Since the degree is one greater in the numerator, I know that I will have a slant asymptote. But I need to do the long division to find out what the equation of the slant asymptote is going to be.

long division: (x^2 - x - 2) ÷ (x - 2) = x + 1

Hmm... The slant asymptote is clearly y = x + 1, but there is no remainder; the division came out evenly. That's because the numerator happens to factor as (x – 2)(x + 1), so the x – 2 factor divides out evenly and there is no remainder.

In any case, the slant (not horizontal) asymptote is at y = x + 1:

graph showing slant asymptote

Now I'll find the intercepts: Copyright © Elizabeth Stapel 2003-2011 All Rights Reserved

x = 0: y = (0 – 0 – 2)/(0 – 2) = 1

y = 0: 0 = (x2 – x – 2) / (x – 2)

0 = x2 – x – 2

0 = (x – 2)(x + 1)

x = 2, x = –1

I know that I can't have x = 2, as an x-intercept, because this is actually the vertical asymptote. So I'll ignore that "solution" of the above equation.

The intercepts then are

(0, 1) and (–1, 0):

graph showing intercepts

Now I'll plot a few more points. However, since this example is actually a special case of slant-asymptote problem (and something of a trick question), I'll also show you the points for the slant asymptote only.

x y = (x2 – x – 2)/(x – 2) y = x + 1

–6 y = (36 + 6 – 2)/(–6 – 2) = –5 y = –5

–5 y = (25 + 5 – 2)/(–5 – 2) = –4 y = –4

–4 y = (16 + 4 – 2)/(–4 – 2) = –3 y = –3

–3 y = (9 + 3 – 2)/(–3 – 2) = –2 y = –2

–2 y = (4 + 2 – 2)/(–2 – 2) = –1 y = –1

–1 y = (1 + 1 – 2)/(–1 – 2) = 0 y = 0

0 y = (0 – 0 – 2)/(0 – 2) = 1 y = 1

1 y = (1 – 1 – 2)/(1 – 2) = 2 y = 2

2 — y is not defined — y = 3

3 y = (9 – 3 – 2)/(3 – 2) = 4 y = 4

4 y = (16 – 4 – 2)/(4 – 2) = 5 y = 5

Do you see how that, except for the one point where the rational function isn't defined (at x = 2), the two lines are the same? In general, this is not true for rationals. But in this special case — where the long division works out with no remainder — you don't actually even need the asyptote lines dashed in. Instead, you find the slant asymptote equation (in this case, y = x + 1), and you draw that in for the rational graph.

The only difference between the slant asymptote of the rational function and the rational function itself is that the rational function isn't defined at x = 2. To account for this, I leave a nice big open circle at the point where x = 2, showing that I know that this point is not actually included on the graph, because of the zero in the denominator of the rational.

graph of y = (x^2 - x - 2) / (x - 2)

Warning: This graph is not the norm for rationals. But you should expect to encounter one like this, perhaps on the test. I've only ever seen this done with slant asymptotes, but it could be done with horizontal asymptotes, too. Keep in mind that you can't just "cancel off" duplicate factors when graphing rationals; you still need to account for all the zeroes of the denominator.

Note that your calculator will probably not show this hole in the graph, and "TRACE" will probably miss it too, since it is unlikely that x = 2 will be exactly on the pixel that the calculator is processing. But even if the graph does not show the gap in the line, the calculator will show no value for y when x is two.

When I asked my calculator to evaluate y for x = 2, I got this:

screen shot showing apparently connected line

If it just so happens that the vertical asymptote falls on a pixel (rather than between two pixels), then the gap in the graph will display on the calculator's pretty picture.

For instance, when I changed the window settings on my graphing calculator so the x-values ran from –7 to 7 (rather than the default –10 to 10), the gap was (just barely) visible:

screen shot showing gap in graph

When you do these graphs, get in the habit of working methodically through all the steps (vertical asymptote(s), horizontal or slant asymptote, intercept(s), plotted points, and graph), so you can do the graphing easily when you get to the test. And, as you can see above, you will need to know this material well enough that your calculator doesn't mess you up.

Answer: it soo blurry I did not see it

Step-by-step explanation:

Given:

Kim picked 250 pounds of pears yesterday and 287 pounds of pears today.

To find:

The percentage increase of  amount of pears picked by Kim.

Solution:

We know that,

[tex]\%\text{ increase}=\dfrac{\text{New value - Initial value}}{\text{Initial value}}\times 100[/tex]

[tex]\%\text{ increase}=\dfrac{287-250}{250}\times 100[/tex]

[tex]\%\text{ increase}=\dfrac{37}{25}\times 10[/tex]

[tex]\%\text{ increase}=\dfrac{370}{25}[/tex]

[tex]\%\text{ increase}=14.8[/tex]

Therefore, the percentage increase of  amount of pears picked by Kim is 14.8%.

Answer:

12 and 14

Step-by-step explanation:

Let the even integers be x and x+2

three times the larger number is expressed as 3(x+2)

30 more than the smaller one is x + 30

Equating both expressions

3(x+2) = x +30

Find x

3x+6 = x+30

3x-x = 30-6

2x = 24

x = 12

The second integer is 12+2 = 14

Hence the required integers are 12 and 14

Answer:

The answer is B

Step-by-step explanation:

I just got it right on iready

Answer:

Step-by-step explanation:

Answer: 0.3 or 0.7 Im not sure.

Step-by-step explanation: But Correct me if i'm wrong :)

Answer:

3x^999000

Explantiotn

Answer:

20≤4x+2y

Step-by-step explanation:

Given data

maximum amount to spend= $20

Egg cake costs $4

Cream cake costs $2

let Egg cake be x

let Cream cake  be y

Hence the total is given by

20≤4x+2y

Answer:

im pretty sure the answer is eight!

Step-by-step explanation:

Answer:

x = -4/3

Step-by-step explanation:

[tex]3(x-4)=12x\\\\3x-12=12x\\\\3x-12+12=12x+12\\\\3x=12x+12\\\\3x-12x=12x-12x+12\\\\-9x=12\\\\\frac{-9x=12}{-9}\\\\\boxed{x=-\frac{4}{3}}[/tex]

Hope this helps!

Answer: slope =

-1/2

Step-by-step explanation:

Since they are parallel, they will never intersect. The only way this is possible is if they have the same slope. All you had to do was get y by itself and find the number next to the x. Subtract the ten and the 2y and pass them to their opposite sides that way it will be x-10= -2y. After that, divide the -2 by everything on the x side. The final equation is -1/2x -10= y.

Answer:

I answer should be 148 ft squared

hope this is right :)

Answer:

6x4x5 = that equals.......

Answer:

Step-by-step explanation:

plot an open circle on the 4 and a closed circle on the 10. Then draw a line that goes from 4 to 10.

Answer:

( -2 , -2 ) or ( 2 , 4 )

Step-by-step explanation:

Answer:

4-1/2-0 = 3/2

Step-by-step explanation:

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .