The value of function (f+g)(x) is x²-3x+7, (f-g)(x) is 3x²-3x+7, (fg)(x) is -2x⁴+3x³-7x² and (f/g)(x) is -2x²+3x-7/x²
What is a function?A relation is a function if it has only One y-value for each x-value.
The given two functions are
f(x)=3x-2 and g(x)=4+x
at x=-1
f(-1)=-5, g(-1)=3
at x=2,
f(2)=4, g(2)=6
at x=5,
f(5)=13, g(5)=9
Now the functions are f(x)=2x²-3x+7 and g(x)=-x².
We need to find (f+g)(x)
f(x)+g(x)
2x²-3x+7-x².
x²-3x+7
(f-g)(x)
f(x)-g(x)
2x²-3x+7+x²
3x²-3x+7
(fg)(x)
(2x²-3x+7)(-x²)
-2x⁴+3x³-7x²
f/g(x)=-2x²+3x-7/x²
Hence, the functions (f+g)(x)=x²-3x+7, (f-g)(x)=3x²-3x+7, (fg)(x)=-2x⁴+3x³-7x² and (f/g)(x)=-2x²+3x-7/x²
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i need help desperately please don’t ignore!! :(
LN= 5x-8
NM= 12
m
find the value of x
The value of the missing part which is x is; x = 8
How to find the missing part of a triangle?
From the given triangle, we are told that;
LN = 5x - 8
NM = 12
∠KNL = (13x - 14)°
Now, since KN is an altitude in ΔKLM, it means that KN is perpendicular to LM and as such ∠KNL is a right angle which is 90 degrees. Thus;
(13x - 14)° = 90
1x = 90 + 14
13x = 104
x = 104/13
x = 8
This is the value of the missing value
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Madion went out to eat and pent $13. Thi wa 3/5 of the amount that he received. How much money did he receive?
The total money received by madison was $ 21.6 from which she spent $13 when she went out.
We are given that -
Madison spent $13 in all when she went out.
Also, this was 3/5 of the amount that she had received.
Now let us find the total money she received as follows -
Money spent by madison = 3/5 of the total money received by madison
i.e. 13 = 3/5 x (total money received by madison)
or we can say that total money received by madison = (5/3) x 13
= 65/3
= 21.6
Hence, the total money received by madison was $ 21.6
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Find the value of x for {(-2/5)^2}^x*(-5/2)^-1=-8/125
Answer: x=1
Step-by-step explanation:
[tex][(-\frac{2}{5})^2] ^x*(-\frac{5}{2}) ^{-1}=-\frac{8}{125} \\\\(-\frac{2}{5})^{2*x}*(-\frac{2}{5})^1 =-\frac{2^3}{5^3} \\\\(-\frac{2}{5} )^{2x+1}=(-\frac{2}{5})^3 \\\\Hence,\\\\2x+1=3\\\\2x+1-1=3-1\\\\2x=2[/tex]
Divide both parts of the equation by 2:
[tex]x=1[/tex]
Vivian and her friends are planning a superhero movie marathon. Vivian is in charge of the
popcorn, so she buys a 2-pound jar of unpopped kernels. The jar's label says that 1 ounce of
kernels will make 1 quart of popcorn. How many cups of popcorn will her jar make?
If the jar level says that 1 ounce of kernels will make 1 quart of popcorn then 128 cups of popcorns will her jar make the popcorns.
The term ounce is a unit of measurement used in the Imperial system. It is mostly used in the United States. Ounces can be used to measure either liquid or dried goods. There are 32 ounces in one quart using the Imperial System of measurement. There are 4 cups in one quart. 1 quart is same as 32 ounces. Vivian and her friends are planning a superhero movie marathon. if Vivian buys 2 pound jar of unpropped kernels. then it will make 128 cups of popcorn. we know that 1 pound is equal to the 16 ounces so Vivian will make 32 ounces in 2 pound. A quart represented is a measuring unit used in the Imperial system and United States to measure liquids and dried goods. As per the leveling of the jar it will make 32 ounces in 32 quartz. then in 32 quartz it will make 128 cups of popcorn.
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The catter plot how the number of people at a fair baed on the outide temperature. How many fewer people would be predicted to be at the fair on a 100 f day then on a 75 f
The difference between the two numbers is the number of fewer people that would be predicted to be at the fair on a 100°F day than on a 75°F day.The answer will depend on the specific data from the catter plot.
1. Look at the catter plot and identify the points that correspond to the temperatures of 75°F and 100°F.
2. Note the number of people at the fair for each temperature.
3. Subtract the number of people at the fair in the 75°F point from the number of people at the fair in the 100°F point.
The difference between the two numbers is the number of fewer people that would be predicted to be at the fair on a 100°F day than on a 75°F day.
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Find the value of x and show your work.
5x+10
7x-6
im gussing you mean 5x+10=7x-6
if so
5x+10=7x-6
-5x = -5x
10=2x-6
+6=+6
16=2x
/2=/2
8=x
The value of x = 8
here, 5x+10 is the 1st Equation
and 7x-6 is the 2nd Equation
We have to form an equation
5x+10=7x-6
To solve for x, we need to isolate it on one side of the equation. To do this, we need to use inverse operations.
put the variable term on one side and the numerical term on the other side of the equal to sign, and while doing this change the sign from
plus with minus and vice versa
multiply with divide and vice versa
5x+10=7x-6
5x-7x=10+6
2x=16
x=[tex]\frac{16}{2}[/tex]
x=8
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Is this a function or not a function?
keeping in mind that a function does not have any X-Repeats, that is, the 1st coordinate in every pair never repeats, Check the picture below.
it took samantha 6 years to double the money in her account. what interest rate was samantha receiving on her account?
Samantha was receiving an interest rate of 12% on her account.
What is Present value ?Present value is the present value of future cash flows discounted at a certain rate. Present value is based on the concept of the time value of money, where a dollar today is worth more than a dollar in the future.
PV = FV /(1 + r )ⁿ
Information provided to us ,
time period , n = 6 years
let " $x " be the present value of Samantha's account money.
After 6 years it becomes double that is
future value, F = $2x
let "r" be rate of interest was Samantha receiving on her account.
plugging all known values in above formula,
$x = $2x /(1+r)⁶
=> (1+r)^6 = 2
=> 1 + r = (2)^1/6 = 1.122
=> r = 1.122 - 1 = 0.122
=> r = 12%
So, rate of interest is 12% .
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Calculate the double integral. {8x}/{1 + xy} dA ; R = 0, 8 0, 1
The value of the double integral ∫∫ (8x)/(1 + xy) dA ; R = [0, 8] x [0, 1] is 11.77
In this question we need to calculate the double integral. {8x}/{1 + xy} dA ; R = 0, 8 0, 1
i.e., to find ∫∫ (8x)/(1 + xy) dA ; R = [0, 8] x [0, 1]
First we integrate the function (8x)/(1 + xy) as a function of y, treating the variable x as a constant.
G(x) = ∫_[0, 8] ((8x)/(1 + xy) ) dy
G(x) = 8 ln(8x + 1)
Now we calculate the integral of the previous result as a function of x.
i.e., ∫_[0, 1] G(x) dx
= ∫_[0, 1] [8 ln(8x + 1)] dx
= 9 ln(9) - 8
= 11.77
Therefore, the solution to the double integral (8x)/(1 + xy) dA ; R = [0, 8] x [0, 1] is 11.77
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part of a regression output is provided below. some of the information has been omitted. source of variation ss df ms f regression 3177.17 2 1588.6 residual 17 17.717 total 3478.36 19 the ss (residual) is a. 3177.17. b. 301.19. c. impossible to determine. d. 17.71.
The SS(residual) is - 301.19. Option (b) is the correct answer.
Given the table :
Source of Variation - - SS - - - df - - - MS - - - - F
Regression - - - - - -3177.17 - - -2 - - 1588.6
Residual - - - - - - - - ______ --17 - - -17.717
Total - - - - - - - - - - 3478.36 - - 19
Calculate the SSR, the Sum of the Square residual.
The Sum of Square RESIDUAL (SSR), Mean Square Residual (MSR), and Degree of Freedom RESIDUAL (DFR) are related by the formula :
MSR = SSR / DFR
Hence,
SSR = MSR × DFR
For the table ;
MSR = 17.717 ; DFR = 17
SSR = (17.717 × 17)
SSR = 301.19
So, the SS(residual) is - 301.19.
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Consider the function below. (If an answer does not exist, enter DNE.)h(x) = 5x3 − 3x5(a) Find the interval of increase. (Enter your answer using interval notation.)(−1,0)∪(0,1)
The interval in which the function h(x) = 5x³ - 3x^5 is increasing is given as follows:
(−1,0)∪(0,1).
How to obtain the intervals in which the function is increasing?The function in this problem is defined as follows:
h(x) = 5x³ - 3x^5.
To obtain the intervals for increase of decrease, the critical points of the function need to be obtained, which are the values of x for which the derivative is of zero.
The derivative of the function in this problem is given as follows:
h'(x) = 15x² - 15x^4.
Hence the critical points of the function are given as follows:
15x² - 15x^4 = 0
15x²(1 - x²) = 0.
Hence:
15x² = 0 -> x = 0.1 - x² = 0 -> x² = 1 -> x = -1, x = 1.Then the signals of the derivative in each interval is given as follows:
x less than -1: negative, as (1 - x²) < 0.x between -1 and 0: positive, as (1 - x²) > 0.x between 0 and 1: positive, as (1 - x²) > 0.x greater than 1: negative, as (1 - x²) < 0.The function is increasing when the derivative is positive, hence the interval is given as follows:
(−1,0)∪(0,1).
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Simplify this expression
Distribute first in the box below
2 (3x − 6) (2x + 1)
Answer: [tex]12x^{2} -18x-12[/tex]
Step-by-step explanation:
(6x-12)(2x+1)
Foil method
6x*2x
6x*1
-12*2x
-12*1
add them up
[tex]12x^{2} -18x-12[/tex]
Write an equation in the form of y= mx for the proportional relationhip that pae through the point (2, -5) and (6, -45)
y=-10x+15 is the equation passing through the point which is in the form of y=mx+b
The equation of a line y = mx+b is called a straight line.
Where:
m is the slope, and b is the y-intercept.
given points are (2,-5) and (6,-45) consider these points as (x1,y1) and (x2,y2)
we have to find m: the slope of the line...
[tex]m=\frac{y2-y1}{x2-x1}[/tex]------------(1)
Now, plug the values into the formula of equation(1):
[tex]m=\frac{-45-(-5)}{6-2} \\\\m=\frac{-40}{4}[/tex]
m=-10
y=mx+b will become y=-10x+b
To find the b values:
for point(2,-5) consider x as 2,y as -5 and substitute in y=mx+b-5=-10*2+b
b=15
for point(6,-45) consider x as 6,y as -45 and substitute in y=mx+b-45=-10*6+b
b=15
so the final equation is y=-10x+15
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The graph of the parent function f(x) = |x| is dashed and the graph of the transformed function g(x) = |x – h| is solid.
Use the slider to change the value of h. How does changing the value of h affect the vertex?
Positive values of h shift the graph
.
Negative values of h shift the graph
.
Answer:
Step-by-step explanation:
The graph of the parent function f(x) = |x|
transformed function g(x) = |x – h|
To Find : How does changing the value of h affect the vertex?
Positive values of h shift the graph
Negative values of h shift the graph
Solution:
f(x) = |x|
is f(x) = x for x ≥ 0
f(x) = -x for x < 0
g(x) = |x – h|
Positive values of h shift the graph to the right
f(x) = x - h for x ≥ 0
f(x) = h - x for x < h
As values of h increase graph keep shifting to right
Vertex is ( h , 0) Vertex keep shifting to right with increases value of h
g(x) = |x – h|
Negative value of h shift the graph to the left
f(x) = x - h for x ≥ 0
f(x) = h - x for x < h
Vertex is ( h , 0) Vertex keep shifting to left with increases magnitude of negative h
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The linear functions f(x) and g(x) are represented on the graph ...
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The linear functions f(x) and g(x) are represented on the graph ...
Solve for x. Round to the nearest tenth.
X= type your answer...
X
28
32
The value x is 28. By using Pythagorean theorem on the given triangle.
What is the meaning of the nearest tenth?
To write a decimal number up to one decimal place, round it to the nearest tenth. This is done in a way that leaves one digit after the decimal point after rounding.
Given that,
DC = 28
BC = 32
Assume that, AB = a and AD = b
Applying Pythagorean theorem on △BCD:
BC² = DC² + DB²
Putting BC = 32 and DC = 28 in the above equation:
32² = 28² + DB²
DB² = 32² - 28²
DB² = 32² - 28²
DB² = 240
The length of AC is CD + DA = 28 + b.
Now applying Pythagorean theorem on △ABC:
BC² = AB² + AC²
32² = a² + (28 + b)²
a² = 32² - (28 + b)² .....(i)
Now applying Pythagorean theorem on △ABD:
AB² = AD² + BD²
a² = b² + 240 ....(ii)
Now comparing equation (i) and equation (ii)
32² - (28 + b)² = b² + 240
1024 - (28² + 56b + b²) = b² + 240
1024 - 784 - 56b - b² = b² + 240
b² + 240 - 1024 + 784 + 56b + b² = 0
2b² + 56b = 0
2b(b + 28) = 0
Either,
2b = 0, b + 28 =0
b = 0, b = -28
Since the value of b can't be negative. Thus b = 0.
The length of AC is CD + DA = 28 + b = 28.
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The weight for newborn babie i approximately normally ditributed with a mean of 6. 6 pound and a tandard deviation of 1. 2 pound. Conider a group of 900 newborn babie:
1. How many would you expect to weigh between 3 and 8 pound?
2. How many would you expect to weigh le than 7 pound?
3. How many would you expect to weigh more than 6 pound?
4. How many would you expect to weigh between 6. 6 and 9 pound?
Approximately 795 newborn babies (88.3% of the 900 newborn babies) would be expected to weigh less than 7 pounds.
1. Approximately 728 newborn babies (81.3% of the 900 newborn babies) would be expected to weigh between 3 and 8 pounds.
2. Approximately 795 newborn babies (88.3% of the 900 newborn babies) would be expected to weigh less than 7 pounds.
3. Approximately 450 newborn babies (50% of the 900 newborn babies) would be expected to weigh more than 6 pounds.
4. Approximately 645 newborn babies (71.7% of the 900 newborn babies) would be expected to weigh between 6.6 and 9 pounds.
• Between 3 and 8 pounds: 0.6826*900 = 613.4 + 0.95*900 = 814.5 = 728
• Less than 7 pounds: 0.9545*900 = 859.05 = 795
• More than 6 pounds: 0.5*900 = 450
• Between 6.6 and 9 pounds: 0.6826*900 = 613.4 + 0.3413*900 = 306.17 = 64
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9/2 * -(8/3) pls answer fast!...step by step explanation plss
Answer:
9 * -8
____ =-72/6
2 * 3
A rectangular aquarium is 12 inches tall. The perimeter of the base is 80 inches. The length of the base is 4 times the width of the base. Enter the volume, in cubic inches, of the aquarium.
Answer:
Step-by-step explanation:
Okay so you have to multiple 12 x 80 which gives you 960, then you mulitply 960 x 4 to get your final answer which is 3840 cubic inches
Martin climbs 3 meters in the first 10 minutes How many meters does Martin climb in 60 minutes? Hint: Either multiply 3 by 6 or set up this proportion and solve for x 3/10 = x/60
The distance Martin climbs in 60 minutes is 18 meters
Calculating Distance climbedFrom the question, we are to determine how many meters Martin can climb in 60 minutes
Let the distance he climbs in 60 minutes be x
From the given information,
Martin climbs 3 meters in the first 10 minutes
If Martin climbs 3 meters in 10 minutes
Then,
Martin will climb x meters in 60 minutes
Thus,
x × 10 = 3 × 60
Solve for x
10x = 180
x = 180/10
x = 18
Hence, the distance is 18 meters
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Given: AB = CD
Prove: AC = BD
What reason can be used to justify statement 3 in the proof above?
the addition property the subtraction property the division property the substitution property
To prove that AC = BD, we can use the symmetric property. The symmetric property states that if two quantities are equal, then their opposites are also equal.
In this case, we are given that AB = CD. Since AB and CD are opposite quantities (they are the lengths of the diagonals of a rectangle), we can use the symmetric property to conclude that AC = BD.
Therefore, the reason that can be used to justify statement 4 in the proof is the symmetric property.
The cost C in dollars of manufacturing x bicycles at a production plant is given by the function shown below.
C(x) = 5x²-1500x + 125,000
a. Find the number of bicycles that must be manufactured to minimize the cost.
b. Find the minimum cost.
a. How many bicycles must be manufactured to minimize the cost?
bicycles
Given function:
C(x) = 5x² - 1500x + 125000It has a positive leading coefficient, hence the parabola opens up. It means it has the minimum point at vertex.
The x-coordinate of the vertex is:
x = - b/(2a) = - (-1500)/(2*5) = 150The minimum cost is:
C(150) = 5(150)² - 1500(150) + 125000 = 12500Answer:
a) The minimum number of bicycles is the x-coordinate of the vertex, 150,b) The minimum cost is the value of C when x is 150, this is $12500.Draw a line l, and take two point A and B on it. Through A and B, draw line L2 and L3 perpendicular to L1. On L2, mark a point C at a ditance 4cm from L1 and draw a line L4 parrallel to L1 through C. If L4 interect L3 at D , what type of quadrilateral i ABDC?
ABDC is a quadrilateral with two non-parallel sides. It has two pairs of opposite sides which are parallel. It is also known as a trapezoid.
ABDC is a four-sided figure with two pairs of opposite sides that are parallel. This type of quadrilateral is also known as a trapezoid. A trapezoid has two non-parallel sides, while the other two sides are parallel to each other. In this case, the two parallel lines are L1 and L4, while L2 and L3 are the two non-parallel sides. We can see that the point C on L2 is a distance of 4cm from L1, and L4 is a line that is parallel to L1 and passes through C. Finally, L4 intersects L3 at the point D, which completes the trapezoid ABDC.
The length of AB can be determined by using the Pythagorean Theorem. We know that the length of L1 is 8 cm, so the length of AB is 3 cm.
example
AB = √(8^2 - 4^2) = √64 - 16 = √48 = 6 cm
The length of BD can also be determined by using the Pythagorean Theorem. We know that the length of L2 is 4 cm, so the length of BD is 3 cm.
BD = √(4^2 - 4^2) = √16 - 16 = 0 cm
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Problem-solving
a How many codes can Eddie create using
Eddie needs to choose a 6-digit code for his computer password.
i 6 numbers
ii 4 numbers followed by 2 letters
iii 1 number followed by 5 letters?
Eddie decides that he does not want to repeat a digit or a letter.
b How many ways are possible in parts i to iii now?
Answer:
a) i) 6 numbers = 10^6=1000000
ii) 4 numbers followed by 2 letters= 10^4*26^2=6760000
iii)1 number followed by 5 letters : 10^1*26^5= 118,813,760
b)...
a) If Eddie repeat a digit or a letter:
i) The number of codes he can create with 6 numbers is 1,000,000.
ii) The number of codes he can create with 4 numbers followed by 2 letters is 67,600.
iii) The number of codes he can create with 1 number followed by 5 letters is 11,881,376.
b) If Eddie does not want to repeat a digit or a letter:
i) The number of codes he can create with 6 numbers is 15,120.
ii) The number of codes he can create with 4 numbers followed by 2 letters is 1,092,000.
iii) The number of codes he can create with 1 number followed by 5 letters is 7,893,600.
a) To calculate the number of codes Eddie can create for each scenario:
i) For a 6-digit code using only numbers, each digit can take on any value from 0 to 9 (10 options for each digit). So, the total number of codes is 10⁶ = 1,000,000.
ii) For a code with 4 numbers followed by 2 letters, there are 10 options for each digit and 26 options for each letter (assuming only uppercase letters). The total number of codes is 10⁴ * 26² = 67,600.
iii) For a code with 1 number followed by 5 letters, there are 10 options for the number and 26 options for each letter. The total number of codes is 10 * 26⁵ = 11,881,376.
b) If Eddie decides not to repeat a digit or a letter, the number of possibilities changes for each scenario:
i) Since he cannot repeat a digit, the first digit can be any of the 10 options. The second digit has only 9 options left, the third digit has 8 options, and so on. So, the total number of codes becomes 10 * 9 * 8 * 7 * 6 * 5 = 15,120.
ii) In this case, he cannot repeat any digit or letter. So, for the 4 numbers, there are 10 options for the first, 9 options for the second, 8 options for the third, and 7 options for the fourth. For the 2 letters, there are 26 options for the first and 25 options for the second (since no repetition is allowed). The total number of codes becomes 10 * 9 * 8 * 7 * 26 * 25 = 1,092,000.
iii) For the code with 1 number and 5 letters, the number has 10 options, and the first letter has 26 options. However, he cannot repeat any letter after the first, so the second letter has 25 options, the third has 24 options, and so on. The total number of codes becomes 10 * 26 * 25 * 24 * 23 * 22 = 7,893,600.
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If
m
⌢
=
21
6
∘
m
UPE
⌢
=216
∘
and
m
⌢
=
5
8
∘
m
LS
⌢
=58
∘
, find
m
∠
L
B
S
m∠LBS.
Answer:
use the way I told u down
Step-by-step explanation:
Angle ABC is a straight angle.
Angles ABD and DBC are right angles.
Angles CBE and DBE are acute angles.
Angle ABE is an obtuse angle.
Angles
The sum of the three angles in any triangle is always 180°.
a + b + c = 180°
Knowing that the sum of the angles of triangle is 180° can help you to solve problems about triangles.
Angles
In this triangle, angle b is a right angle and angle c = 40°. What is the measure of angle a?
a + b + c = 180°
Since b is a right angle, b = 90°.
The problem states that c = 40°.
Therefore, a + 90° + 40° = 180°
a + 130° = 180°
a + 130° − 130° = 180° − 130°
a = 50°
Angle a measures 50°.
Angles
Click on the figure that matches this description.
An obtuse angle
Question 1 of 8
This is an acute angle. It measures less than 90°. Try again
This is a right angle. The square in the corner shows that it measures 90°. Try again
This is a straight angle. It measures 180°. Try again.
This angle is obtuse. It is greater than 90° and less than 180°.
One of these figures is an obtuse angle. Try again.
An obtuse angle is larger then a right angle and smaller then a straight angle.
Angles
Click on the figure that matches this description.
An acute angle
Question 2 of 8
This is an acute angle. It measures less than 90°.
This is a right angle. The square in the corner shows that it measures 90°. Try again
This is a straight angle. It measures 180°. Try again.
This angle is obtuse. It is greater than 90° and less than 180°. Try again.
One of these figures is an acute angle. Try again.
An acute angle is smaller then a right angle.
Angles
Click on the figure that matches this description.
A right angle
Question 3 of 8
This is an acute angle. It measures less than 90°. Try again
This is a straight angle. It measures 180°. Try again.
This angle is an obtuse angle. It measures more than 90° and less than 180°. Try again.
This is an acute angle. It measures less than 90°. Try again.
A right angle looks like a square corner and measures 90°.
A right angle measures 90°.
Angles
There are five question remaining. In each of these question, you will be asked to find the size of a missing angle.
Angles
Click on the correct answer.
Angle ABC is a right angle. If angle n is 40°, how large is angle m?
50°
140°
90°
60°
None of these
Question 4 of 8
90° − 40° = 50°
Angle m is 50°.
Angle ABC is 90° , and angle m is only part of this right angle. It is less than 90°. Try again.
Angle ABC is 90°, and angle m is only part of this right angle. Try again.
Angle m and n together from a 90° angle. Subtract 40° from 90° .Try again.
One of these is size of angle m. Try again.
Since angle ABC is a straight angle, angle m + angle n = 90°.
suppose that a box contains 6 cameras and that 5 of them are defective. a sample of 2 cameras is selected at random ( without replacement). define the random variable x as the number of defective cameras in the sample. write the probability distribution for x .write your answer in fraction form or round to 3 decimal places.
If x is the number of defective cameras in the 2-size sample, that means that:
P(x = 0) = 0 (since there are no 2 cameras that can be selected without replacement that are not defective)
P(x = 1) = 5/15 = 1/3 (since there are 15 total ways to select a distinct sample and only 5 of these would have the non-defective one in them)
P(x = 2) = 10/15 = 2/3 (since there are 15 total ways to select a distinct sample and 10 of these would NOT have the non-defective one in them)
pls help me in this homework id really appreciate it <3
Write the expression using exponents.
5.2 x y x y x y
The ( X ) stands for multiplication. So 5.2 times Y times Y times Y.
12. Juan is a programmer going to school at
night to earn a higher degree. He starts the
month with $500 in his savings account. His
income is $4750. Each month he currently
spends $750 on food; $400 on clothes; $530
on video games and movies. His classes cost
$500 each month. His essential expenses
(rent, medical costs, insurance, tax) total
$2800. How much does Juan have for his Net
Cash Flow and Ending Cash at the end of the
month?
[A]Net Cash Flow: -$230
Ending Cash: $730
[B] Net Cash Flow: $2,570
Ending Cash: $3,070
[C] Net Cash Flow: -$230
Ending Cash: $270
[D] Net Cash Flow:-$270
Ending Cash: $230
[E] Net Cash Flow: $270
Ending Cash: -$770
Juan's Net Cash Flow at the end of the month is -$230 and his Ending Cash is $270.
To calculate Juan's Net Cash Flow and Ending Cash, you need to subtract his expenses from his income.
Juan's income is $4750 per month. His essential expenses, including rent, medical costs, insurance, and tax, total $2800 per month. He also spends $750 on food, $400 on clothes, and $530 on video games and movies, for a total of $2680 in non-essential expenses.
Therefore, his total expenses are $2800 + $2680 = $5480.
His Net Cash Flow is his income minus his expenses, which is $4750 - $5480 = -$730.
His Ending Cash is his Net Cash Flow plus his starting balance of $500, which is -$730 + $500 = $270.
Therefore, the correct answer is option C: Net Cash Flow: -$230, Ending Cash: $270.
Describe all the
positive integers that would make (32)x greater than 39. Explain your reasoning
The positive integers that will make (32)x greater than 39 must be greater than 39/32
How to find positive integers that will make (32)x greater than 39A whole number that is greater than zero is what is meant by the term "positive integer."
All counting numbers are included in the set of positive integers (that is, the natural numbers)
In the problem, the given expression is (32)x greater than 39 rewriting gives
(32)x > 39
solving for x
x > 39/32
the integer must be greater than 39/32
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ella purchased a new car in 2000 for $27,600. the value of the car has been depreciating exponentially at a constant rate. if the value of the car was $8,300 in the year 2004, then what would be the predicted value of the car in the year 2009, to the nearest dollar?
The predicted value of the car in 2009, to the nearest dollar, is $14,800.
The value of an exponentially depreciating asset can be calculated using the equation:
V = V_0 × [tex]e^{(-r*t)}[/tex]
where V is the current value of the asset, V_0 is the initial value of the asset, r is the rate of depreciation, and t is the time elapsed since the asset was purchased.
In this case, the initial value of the car was $27,600, the value in 2004 was $8,300, and the time elapsed since the car was purchased is 4 years.
To determine the predicted value of the car in 2009, we can set t equal to 9 years and solve for V:
V = 27,600 × [tex]e^{(-r*9)}[/tex] = 8,300
Solving for r gives us:
r = ln(8,300/27,600) / -9
= -0.069
To determine the predicted value of the car in 2009, we can plug the value for r into the equation and solve for V:
V = 27,600 × [tex]e^{(-0.069*9)}[/tex] = 14,800
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