HEY CAN ANYONE PLS ANSWER DIS!!!!

Answer:

D

Explanation:

Splitting water into hydrogen and oxygen***

Answer:

[tex]D. \: Tyndall \: scattering.[/tex]

Answer:

the answer is b

Explanation:

Answer:

Hope this help

Explanation:

Specific heat capacity,c of a substance is the quantity of heat needed to raise the temperature of 1 kg mass of the substance by 1°C

Unit for c is J/kg/°C or J/kg/K

Answer:

S=5.83...

Explanation:

s=d/t

Speed=distance/time

s=35/10

s=5.83...

Answer:

Energy moves from one place to another through the wave. answer A

A wave is a disturbance that transmit energy. Thus, the correct statement is energy moves from one place to another through the wave.

A wave is a disturbance that transfers energy as it moves from one point to another.

Different terminologies are used to characterise a wave as it travels. Some of these include

Considering the question given above, we see clearly from the definition of wave that the energy is transferred as the wave is moving.

Thus, we can conclude that the correct answer to the question is energy moves from one place to another through the wave

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Answer:

umm.....the teachers and friends

The drama, and friends.

Answer:

100

Explanation:

my apologies if I am wrong

Answer:       false

Explanation: on edg

It is false that reviewing old tests and quizzes will not help you determine what will be on a test because teachers don’t like to give students hints about what could be on future tests.

A test review verifies whether or not the modifications made to the code, data, or documentation are accurate.

In other words, it is an evaluation of the degree to which the stated goals have been attained that has been done at a set period.

Exam analysis might provide insights that can help you become a more self-sufficient learner.

You can improve your performance the next time you are tested by revising your strategy after reviewing returned examinations to learn why you made mistakes.

Thus, the given statement is false.

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Answer:

Tissue paper

Explanation:

Tissue paper is made from a synthetic material

Answer:

The chef can make 8 casseroles

Explanation:

Units Conversion

We need to recall 1 gallon = 16 US cups.

A casserole needs 1 cup of milk, and the chef has 0.5 gallons of milk. Those 0.5 gallons are equivalent to 0.5*16 = 8 cups, thus the chef can make 8 casseroles.

Answer:

the answer is ms no soubtrack360 degree

Explanation:

as if we combine ms with the ful form of ns(no soundtrack) we get ms no soundtrack and a 360 which is 360 degree

Answer:

Probably not my guy

Explanation:

Answer:

272.727mph(miles per hour)

Explanation:

Answer:

it is  C. The kinetic energy is greater after a substance changes from a

gas to a plasma.

Explanation: The higher the temperature the higher the kinetic energy

pls vote for me

Answer:

They contain loosely packed atoms.

Explanation:

Answer:

A is the answer because if you multiply 8 and 2 the period of wave frequency is 16Hz long.

Explanation:

Answer:

B 0.125 its a simple conversion

Answer: C. Magnitude increases by 2

Explanation:

If the magnitudes of X and Y vectors are increased, then the resultant vector will increase by a factor of 2 but the direction does not changes. Hence, option c is correct.

A vector is a physical quantity having both magnitude and direction. For example, force, velocity, work done, momentum, velocity etc. are vector quantities. The quantities which does not have direction are called scalar quantity.

The resultant vector R of vectors in X and Y direction can be written as follows:

[tex]\rm R = \sqrt{x^{2} + y^{2}}[/tex]

If the x and y components are doubled to 2x and 2y then the resultant vector becomes,

[tex]\rm R = \sqrt{(2x)^{2} + (2y)^{2}}\\\\ R = \sqrt{4 (x^{2} + y^{2})\\\\\\ R = 2 \sqrt{x^{2} + y^{2} \\ \\ \\ \\[/tex]= 2R

Therefore, the resultant vector will increases by 2 times. However the direction will not change. Hence, option c is correct.

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Answer:

c. The magnitude of vertical velocity is at a maximum value.

Explanation:

I think this is correct I'm not entirely sure though

Answer:

Explanation: ns along perpendicular axes are independent and thus can be analyzed separately. This fact was discussed in Kinematics in Two Dimensions: An Introduction, where vertical and horizontal motions were seen to be independent. The key to analyzing two-dimensional projectile motion is to break it into two motions, one along the horizontal axis and the other along the vertical. (This choice of axes is the most sensible, because acceleration due to gravity is vertical—thus, there will be no acceleration along the horizontal axis when air resistance is negligible.) As is customary, we call the horizontal axis the x-axis and the vertical axis the y-axis. (Figure) illustrates the notation for displacement, where \mathbf{s} is defined to be the total displacement and \mathbf{x} and \mathbf{y} are its components along the horizontal and vertical axes, respectively. The magnitudes of these vectors are s, x, and y. (Note that in the last section we used the notation \mathbf{A} to represent a vector with components {\mathbf{A}}_{x} and {\mathbf{A}}_{y}. If we continued this format, we would call displacement \mathbf{s} with components {\mathbf{s}}_{x} and {\mathbf{s}}_{y}. However, to simplify the notation, we will simply represent the component vectors as \mathbf{x} and \mathbf{y}.)

Review of Kinematic Equations (constant a)

x={x}_{0}+\stackrel{-}{v}t

\stackrel{-}{v}=\frac{{v}_{0}+v}{2}

v={v}_{0}+\text{at}

x={x}_{0}+{v}_{0}t+\frac{1}{2}{\text{at}}^{2}

{v}^{2}={v}_{0}^{2}+2a\left(x-{x}_{0}\right)\text{.}

The total displacement \mathbf{s} of a soccer ball at a point along its path. The vector \mathbf{s} has components \mathbf{x} and \mathbf{y} along the horizontal and vertical axes. Its magnitude is s, and it makes an angle \theta with the horizontal.

A soccer player is kicking a soccer ball. The ball travels in a projectile motion and reaches a point whose vertical distance is y and horizontal distance is x. The displacement between the kicking point and the final point is s. The angle made by this displacement vector with x axis is theta.

Given these assumptions, the following steps are then used to analyze projectile motion:

Step 1.Resolve or break the motion into horizontal and vertical components along the x- and y-axes. These axes are perpendicular, so {A}_{x}=A\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {A}_{y}=A\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\theta are used. The magnitude of the components of displacement \mathbf{s} along these axes are x and \mathrm{y.} The magnitudes of the components of the velocity \mathbf{v} are {v}_{x}=v\phantom{\rule{0.25em}{0ex}}\text{cos}\phantom{\rule{0.25em}{0ex}}\theta and {v}_{y}=v\phantom{\rule{0.25em}{0ex}}\text{sin}\phantom{\rule{0.25em}{0ex}}\mathrm{\theta ,} where v is the magnitude of the velocity and \theta is its direction, as shown in (Figure). Initial values are denoted with a subscript 0, as usual.

Step 2.Treat the motion as two independent one-dimensional motions, one horizontal and the other vertical. The kinematic equations for horizontal and vertical motion take the following forms:

\text{Horizontal Motion}\left({a}_{x}=0\right)

x={x}_{0}+{v}_{x}t

{v}_{x}={v}_{0x}={v}_{x}=\text{velocity is a constant.}

\text{Vertical Motion}\left(\text{assuming positive is up}\phantom{\rule{0.25em}{0ex}}{a}_{y}=-g=-9.\text{80}{\text{m/s}}^{2}\right)

y={y}_{0}+\frac{1}{2}\left({v}_{0y}+{v}_{y}\right)t

{v}_{y}={v}_{0y}-\text{gt}

y={y}_{0}+{v}_{0y}t-\frac{1}{2}{\mathrm{gt}}^{2}

{v}_{y}^{2}={v}_{0y}^{2}-2g\left(y-{y}_{0}\right)\text{.}

Step 3. Solve for the unknowns in the two separate motions—one horizontal and one vertical. Note that the only common variable between the motions is time t. The problem solving procedures here are the same as for one-dimensional kinematics and are illustrated in the solved examples below.

Step 4.Recombine the two motions to find the total displacement\mathbf{\text{s}} and velocity \mathbf{\text{v}}. Because the x – and y -motions are perpendicular, we determine these vectors by using the techniques outlined in the Vector Addition and Subtraction: Analytical Methods and employing A=\sqrt{{A}_{x}^{2}+{A}_{y}^{2}} and \theta ={\text{tan}}^{-1}\left({A}_{y}/{A}_{x}\right) in the following form, where \theta is the direction of the displacement \mathbf{s} and {\theta }_{v} is the direction of the velocity \mathbf{v}:

Total displacement and velocity

s=\sqrt{{x}^{2}+{y}^{2}}

\theta ={\text{tan}}^{-1}\left(y/x\right)

v=\sqrt{{v}_{x}^{2}+{v}_{y}^{2}}

{\theta }_{v}={\text{tan}}^{-1}\left({v}_{y}/{v}_{x}\right)\text{.}

(a)

Answer:

The highest state of matter in energy is gas. The lowest is solid.

Explanation:

The reason why is because gas is the highest conductor of electricity (which is why we have lightning). However, solids don't conduct electricity very well.

Answer:

me too

Explanation:

Answer:

Explanation:

The circulatory system is made up of blood vessels that carry blood away from and towards the heart. Arteries carry blood away from the heart and veins carry blood back to the heart. The circulatory system carries oxygen, nutrients, and hormones to cells, and removes waste products, like carbon dioxide.

Answer:

Basketball has a mass of 0.1kg

m = 0.1 kg

The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero

a = 0m/s²

The constant speed is 6m/s

v = 6m/s

So, force to keep it moving with this constant speed can be calculated using Newton second law of motion

F = ma

F = m × 0

F = 0N

So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.

Answer:

In a position-time graph, the velocity of the moving object is represented by the slope, or steepness, of the graph line. If the graph line is horizontal, like the line after time = 5 seconds in Graph 2 in the Figure below, then the slope is zero and so is the velocity. The position of the object is not changing.

Explanation:

Answer:

1) The forces acting on the puck are the forces applied by the two players in their bid to push the puck in the opposite direction

2) The puck does not move because the forces applied by the two players are equal and opposite

3) A player can get the puck to move in the direction they want by increasing the force acting in the direction they want the puck to move

Explanation: