HELPP how many moles are there in each of the following??? Please this assignment is due today

atleast do one problem if you can

HELPP How Many Moles Are There In Each Of The Following??? Please This Assignment Is Due Today Atleast

Answers

Answer 1

a) 0.998 moles.

b) 0.498 moles.

c)  1.6264 × 10³ moles

d) 2.64 × 10⁻¹³ moles

What is no. of moles?

The mole is a unit of measurement or the starting point for determining the concentration of a chemical in a sample. Avogadro's constant, or 1 mole, is a quantity that is equal to 6.023 x 10²³ particles. Any species, such as atoms, molecules, electrons, protons, neutrons, etc., can make up these particles.

a)

As we know,

6.023 × 10²³ molecules of He = 1 mole

so, 6.013 × 10²³ molecules of He = (1/6.023 × 10²³) × (6.013 × 10²³)

                                                      = 0.998 moles.

b)

As we know,

6.023 × 10²³ molecules of Mg = 1 mole

so, 3.003 × 10²³ molecules of Mg = (1/6.023 × 10²³) × (3.003 × 10²³)

                                                      = 0.498 moles.

c)

Given that,

Mass (m) = 3.37 × 10⁵ gm

Molar mass of Pb (M) = 207.2

now, n = m/M

or, n = (3.37 × 10⁵) / 207.2

or, n = 1.6264 × 10³ moles

d)

Given that,

Mass (m) =4.23 × 10⁻¹² gm

Molar mass of O (M) = 15.999

now, n = m/M

or, n = (4.23 × 10⁻¹²) / 15.999

or, n = 2.64 × 10⁻¹³ moles.

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Related Questions

match each level of protein structure with the covalent/non-covalent interaction or entropic driving force that is featured in its construction.

Answers

Primary -- covalent/peptide bonds, Secondary --- Hydrogen bonds, Tertiary -- Hydrophobic effect, Quaternary -- Disulfide bonds.

A covalent bond is created among two or more atoms by the mutual sharing with one or more electron pairs. The 2 different atomic nuclei lure these charged particles at the same time. When the thing that is different in electronegativity values of two or more atoms is too slight for transfer of electrons to form ions, a polar covalent forms. A hydrogen bond (or H-bond) in science is a mainly electrostatic attraction between a hydrogen (H) atom tightly attached to an more electronegative "donor" atom or group (Dn) and then another electronegative atom carrying a solitary pair of electrons—the hydrogen bond acceptor (Ac). The hydrophobic effect relates to non-polar molecules and single - molecule sections in a water - soluble solution's tendency to avoid making interaction with molecules of water.

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look at the given synthesis and the provided reagents. fill in the blanks with the single letter code of the appropriate reagent, or the appropriate descriptive vocabulary word/phrase to complete the description. remember the computer is very literal so check your spelling carefully.

Answers

The reagent are used in the chemical reaction to cause the chemical reaction or the test performed if one occurred.

The reagents are the compounds or the mixture that are added to the chemical reaction in order to start the chemical reaction. The reagent is not necessarily be consumed during the chemical reaction. the reagent is used to identify the compound or to measure the substance if it is present in the reaction.

The  reagent is  the  initiator , solvent , catalyst etc. the example of the reagents are : Tollen's reagent , Fehling's reagent , Fenton's reagent and collins reagent etc.

The question is incomplete, I answer the question in general according to my knowledge.

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Which of the following compound(s) could be used as starting material(s) make an amide in just 1 step, using reactions we learned in Chapter 21? Select all that apply! O an ester O a carboxylic acid O a nitrile O an anhydride another amide O an acid chloride

Answers

The correct answer is carboxylic acid. Option B.

In a similar reaction, a coupling agent such as DCC can be used to prepare amides by the reaction of carboxylic acids with amines. Simple amides can be made by reacting acid anhydrides with amines. Finally, amides can be formed from the direct reaction of carboxylic acids and amines.

Amides are generally prepared by coupling a carboxylic acid with an amine using a coupling agent or by first converting the carboxylic acid to a derivative. Alternative methods include Staudinger ligation, aminocarbonylation of aryl halides, and oxidative amidation of aldehydes. Amides can be hydrolyzed in the presence of aqueous acids.

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please explain your answer and answer it correctly look at the image shown i put 100 points because i want to give whoever helps me with this a good amount. please refresh if you dont see image

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There can be release of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore, the given nuclear decay reaction is balanced.

What is nuclear decay?

It is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle.

So, according to our questions Uranium-238 is undergoing alpha emission. The balanced reaction can be written as

²³⁸U₉₂ [tex]\rightarrow[/tex]²³⁴ Th₉₀+⁴₂He

So, From above reaction we can see that the total mass on reactant side is equal to total mass on product side. So, this reaction is balanced.

Therefore, the given nuclear decay reaction is balanced.

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the rf of a compound on a tlc plate will likely increase as you increase the polarity of the developing solvent.

Answers

The Rf value of a compound is generally equal to the distance that is traveled by the compound divided by the distance traveled by the solvent front.

Thin layer chromatography (TLC) is a widely used separation technique for the quantitative and qualitative analysis. It uses a thin layer of a stationary phase that is coated on a glass, plastic, or also on aluminum plate. A liquid solvent that is called the mobile phase generally carries the sample and separates it as it moves across the plate. It offers the advantages of simplicity, sensitivity, and rapid analysis over other separation techniques.

The stronger a compound is bound to the adsorbent , the slower it moves on the TLC plate. Non-polar compounds move up the plate most rapidly because of the higher Rf value, whereas polar substances will travel up the TLC plate slowly or not at all due to the lower Rf value.

The Rf value is a ratio, and it represents the relative distance between the spot traveled compared to the distance it could have traveled if it was moved with the solvent front. An Rf of 0.55 means the spot moved 55% as far as the solvent front, or a little more than halfway.

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At constant T and P, 2.0 L of nitrogen gas are combined with 6.0 L of hydrogen gas to form ammonia. Which of the following statements correctly describe the outcome of the reaction, assuming it goes to completion? Select all that apply.
When the reaction is completed, only NH3 is present.
The product occupies a volume of 4.0 L under these conditions.
N2 combines with H2 in a 1:3 ratio.

Answers

The observations that are applied are as follows:

NH3 is present.

N2 combines with H2 in a 1:3 ratio.

When nitrogen reacts with hydrogen, it yields ammonia. The chemical equation can be expressed as follows:

N2(g) +3H2(g)---> 2 NH3(g)

The stochiometric ratio in which nitrogen and hydrogen reacts is the ratio 1:3. And the when the reaction is completed, only NH3 is present. At constant T and P, 2.0 L of nitrogen gas are combined with 6.0 L of hydrogen gas to form ammonia.

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at resting potential the ion distribution inside and outside of a neuron is such that ....... ions are most abundant on the outside of the cell while ........ ions are most abundant on the inside of the cell
sodium; potassium

Answers

In a neuron at resting potential, potassium ions are more prevalent inside the cell than sodium ions are, with sodium ions being more prevalent on the exterior of the cell.

The arrangement of charged ions throughout the cell membrane causes a difference in electrical potential between the inside of the cell and the surrounding area. Membrane potential is the name given to this. It takes energy to maintain the voltage differential across the cell membrane when it is quiescent. Continuously, the sodium-potassium pump removes three sodium ions from the cell for every two potassium ions it brings in.

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The volume of a gas in a flexible container changes from 4L to 40L. What happened to the temperature which caused this change in volume?
A. It dropped to 1/36 of the original Kelvin temperature.
B. It dropped tO 1/10th of the original Kelvin temperature.
C. It increased 36x.
D. It increased 10x.

Answers

Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the correct option is option D. Ideal gas is a hypothetical gas. Vanderwaal gas behave as ideal gas at low pressure and high temperature.

What is ideal gas equation?

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically,

PV=nRT

where,

P = pressure

V= volume

n =number of moles

T =temperature

R = Gas constant = 0.0821 L.atm/K.mol

From above relation, we can see that volume and temperature is directly proportional to temperature. On increasing volume, temperature will also increase with the same factor.  It will increased by 10x.

Therefore, the correct option is option D.

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in the following compound, how many lone pairs of electrons does the nitrogen atom bear? (enter answer as a number.)

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The nitrogen molecule's molecular formula is N2. The triple bonds that hold the nitrogen atoms together. They each possess a single pair of electrons as a result. Consequently, there are two lone pairs overall.

A lone pair and three covalent bonds commonly encircle nitrogen in its typical, no-formal charge configuration. In (a), the nitrogen atom shares three bonding pairs with another atom, has one lone pair, and has a total of five valence electrons. This brings us full circle back to the nitrogen atom. The nitrogen molecule's molecular formula is N2. The triple bonds that hold the nitrogen atoms together. They each possess a single pair of electrons as a result. Imine nitrogen's lone pair electrons are located in a sp2 hybrid orbital, whereas amine nitrogen's lone pair electrons are located in an sp3 hybrid orbital.

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as in top hat, draw the lewis structure of pf3 and answer the following questions! name the compound what is the number of valence electrons number the bonding pair of electrons around the central atom. number the number of single bonds.

Answers

There are a total of 26 valence electrons in the PF3 Lewis structure. The steric number of a single phosphorus trifluoride (PF3) molecule is four because it has three bonds (between the elements phosphorus and fluorine) and one empty pair of electrons.

The colorless and odorless gas phosphorus trifluoride (PF3) is poisonous in a manner similar to that of carbon monoxide. It spreads throughout the body by attaching to the iron in hemoglobin and preventing the blood from receiving oxygen. In a chemical process, PF3 acts as a nucleophile by donating two electrons. Hybridization, Molecular Geometry, and PF3 Lewis Structure.The number of valence electrons of an atom, which easily interact with the valence electrons of another atom to create a bond, is depicted in a Lewis diagram.

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Ocean waves pass through two small openings, 22 m apart, in a breakwater. You're in a boat 85m from the breakwater and initially midway between the openings, but the water is pretty rough. You row 39 m parallel to the breakwater and, for the second time, find yourself in relatively calm water.What is the wavelength of the ocean waves?

Answers

Answer:

22 m

Explanation:

The wavelength of the ocean waves is 22 m.

When ocean waves pass through two small openings in a breakwater, the distance between the openings, known as the waveguide, determines the wavelength of the waves. In this case, the distance between the openings is 22 m, so the wavelength of the waves is also 22 m.

The fact that you were initially midway between the two openings, and that you rowed 39 m parallel to the breakwater before finding yourself in relatively calm water again, does not affect the wavelength of the waves. The wavelength is determined solely by the distance between the openings in the breakwater.

2. Write Informative Texts What type of
change must occur for pure substances to
combine into new materials? Name a few
kinds of synthetic materials that can be
produced by this type of change

Answers

Answer:

Read below

Explanation:

In order for pure substances to combine into new materials, a chemical change must occur. This type of change involves the rearrangement and/or reorganization of the atoms in the substances, resulting in the formation of new substances with different chemical and physical properties.

Some examples of synthetic materials that can be produced through chemical changes include plastics, ceramics, and various types of composites. Plastics are synthetic polymers that can be molded into a variety of shapes and are known for their durability and versatility. Ceramics are inorganic, non-metallic materials that are made by heating and then cooling clay and other materials. Composites, on the other hand, are materials made from two or more different substances that are combined to create a material with improved properties, such as increased strength or durability.

What is the mass percentage of C in morphine, C₁7H19NOs? Provide an
answer to two decimal places.

Answers

The mass percentage of C in morphine would be 4.21%.

What is mass percentage?

The mass percentage of a composition in a compound is the mass of the composition relative to the mass of the entire compound. This can be mathematically expressed as:

Mass percentage = mass of component/mass of substance x 100%

In this case, we are looking for the mass percentage of C in [tex]C_{17}H_{19}NO_3[/tex].

Molar weight of C = 12 g/mol

Molar mass of  [tex]C_{17}H_{19}NO_3[/tex] = (12x17) + (1x19) + (14x1) + (16x3)

                                             = 285 g/mol

Mass percentage of C = 12/285

                                     = 4.21% to 2 decimal places.

In other words, the mass percentage of C in morphine is 4.21%.

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the half equivalence point is in the middle of the buffer region. in order to reach the half equivalence point in their titration, veronica needed to add 24.47 ml of koh to 50.00 ml of 0.368 m hf. what is the concentration of conjugate base at the half equivalence point? note: do not use scientific notation or units in your response. sig figs will not be graded in this question, enter your response to four decimal places. carmen may add or remove digits from your response, your submission will still be graded correctly if this happens.

Answers

The concentration of conjugate base at the half equivalence point should be 0.347 M.

Moles of HF = molarity × volume ( in L )

                     = 0.342 × 50/1000

                     = 0.0171 mol

Since, at half equivalence point, exactly half of the acid in the buffer solution has reacted with the titrants.

So, moles of KOH = 0.0171/2 mol

molarity of KOH = moles / volume (in L)

                           =  (0.0171 / 2 mol) / 24.63 L / 1000

                           = 0.0171 × 1000 / 2 × 24.63

                           = 0.347 M

Therefore, the concentration of conjugate base at the half equivalence point is 0.347 M.

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which of the following nuclides are most likely to decay via positron emission? na-26 i-121 ca-42 s-30 sb-122

Answers

The following nuclides are most likely to decay via positron emission is S - 30 because it has lowest value of the N/Z value.

The one which have the lowest N / Z value will undergo the positron emission. N is the number of the neutron and Z is the number of the proton.

1) Na - 26 = number of neutron / no. of proton

               = 15 / 11

              = 1.3

2) I -121  = 68 / 53

             = 1.2

3) Ca - 42 = 22 / 20

                = 1.1

4) S - 30 = 14 / 16

             = 0.8

5) Sb - 122 = 71 / 51

                  = 1.3

Thus , S - 30 has the lowest N/Z  value.

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Oxalic acid (HC2H2O4HC2H2O4) is a weak acid found in the leaves of rhubarb. Which of the following solutions will have the highest pH?
a) 0.00075 M H2C2O40.00075 M H2C2O4
b) 1.0×10−4 M1.0×10−4 M H2C2O4H2C2O4
c) 1.0 M H2C2O41.0 M H2C2O4
d) 0.5 M H2C2O4

Answers

b) 1.0×10−4 M1.0×10−4 M H2C2O4H2C2O4 will have the Highest pH among the solutions.

When compared to strong acid, does oxalic acid produce less H ions?

A weak acid is what oxalic acid is. It is not as strong as H3O+ ion (water). However, it is more potent than acids like acetic, sulfuric, nitrous, and benzoic. First of all, it is an organic substance, and organic substances are often not strong acids. Dicarboxylic acid is another name for oxalic acid.

How can you determine the pH of an amalgamation of weak bases and weak acids?

Similar to how the weak acid in the example was calculated, a weak base's solution can also be calculated to determine its pH. However, the concentration of the hydroxide ion will be represented by the variable x.

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g which of the following nuclides are most likely to decay via positron emission? na-26 i-121 ca-42 s-30 sb-122

Answers

In order to balance out nuclides with an unbalanced protons to neutrons ratio, decay is used.generating a neutrino and a positron (01e+) (v).

What results from the MG 23 positron decay?

There are 12 protons & 11 neutrons in magnesium-23.The ratio of neutrons to protons is 11:12, or 0.92:1.As a result of positron emission, sodium-23 is created.

What is the result of NA 22 emitting positrons?

A synthetic isotope called sodium-22 has a half-life about 2.6 years.It undergoes a steady neon-22 decay, producing a positron (+ decay).

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The standard emf for the cell using the overall cell reaction below is =2.20 V:
2Al(s) + 3I2(s) ? 2Al3+ (aq) + 6I- (aq)
The emf (voltage) generated by the cell when [Al3+] = 4.0 x 10-3 M and [I-] = 0.015 M
is_______ V

Answers

The cell produces an emf of 2.32 V. For this cell reaction at 25 degrees Celsius, use the Nernst equation. where n represents the number of electrons exchanged during the cellular process.

What is the typical EMF this cell produces?

According to measurements, the electromotive force (EMF) is 1.100 V. The standard condition is specified as a concentration of 1 M in an ideal solution, and as a result, 1.100 V is the standard electromotive force, DEo, or standard cell potential for the Zn–Cu galvanic cell.

How is the average Ecell determined?

Due to the larger standard reduction potential of the silver half-cell, the reduction will occur. The half-cell of tin will oxidize. The formula E0cell=E0red+E0oxid can be used to get the overall cell potential.

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prodrugs are an area of medicinal chemistry that has been extensively researched over the last several years. prodrugs are designed to be initially inactive until further activated into the active form of the drug (which could include also esterification or trans-esterification event). for example: aspirin is a prodrug that gets converted to salicylic acid. (a) draw a complete arrow-pushing mechanism showing how aspirin is converted into salicylic acid (say by the stomach acylating enzyme at low ph). a scheme of the overall transformati

Answers

This is a acid catalyzed reaction proceeds through carbocation as an intermediate forms in the first step by consumption of acid.

While aspirin is ingested, it's far broken right down to salicylic acid by way of the primary conditions within the small gut. it's miles then absorbed into the bloodstream. Aspirin can be made with the aid of reacting salicylic acid with acetic acid within the presence of an acid catalyst.

Aspirin is quite simply hydrolyzed to salicylic acid, each enzymatically and non-enzymatically. Salicylic acid undergoes conjugation reactions producing the essential metabolites salicyluric acid (apparently catalyzed by using an acyl-CoA N-acyltransferase) and glucuronides (gluc) (catalyzed through UGTs).

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According to simple valence bond theory (no promotion/hybridization), which of the following species would not form a bond with carbon? Consider the electronic configuration of the ground state of the element
(a) LiC
(b) BeC
(c) BC
(d) C2
(e) CN

Answers

BeC will will not form a pair because no free element is available with Be.

The elements given in the above question is as follow,

Now consider the ground state of given element we get,

[tex]Li=1s^2,2S^1\\Be=1s^2,2S^2\\B=1s^2,2S^2,2p^1\\C=1s^2,2S^2,2p^2\\N=1s^2,2S^2,2p^3[/tex]

Now, for balance bond theory,

Consider,

a) LiC

[tex]Li=1S^2,2S^1\\C=1S^2,2S^2,2P^2[/tex]

It will form a bond because unpaired electrons are present.

b)Bec

[tex]Be=1s^2,2S^2\\C=1s^2,2S^2,2p^2[/tex]

If will not form a pair because no free element is available with Be.

c)BC

[tex]B=1s^2,2S^2,2p^1\\C=1s^2,2S^2,2p^2[/tex]

It will form a bond because unpaired electrons are present in Boron and carbon.

d)[tex]C_2[/tex]

[tex]C=1s^2,2S^2,2p^2[/tex]

It will form a bond because unpaired electrons are present.

e)CN

[tex]C=1s^2,2S^2,2p^2\\N=1s^2,2S^2,2p^3[/tex]

It will form a bond because unpaired electrons are present.

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A solution of hydrochloric acid needs to be neutralized by barium solution. The beaker on top shows a hydrochloric acid solution.
Which of the beakers containing barium hydroxide will just neutralize the beaker of hydrochloric acid shown?

Answers

A solution of hydrochloric acid needs to be neutralized by barium solution -Beaker

The combination of H+ ions and OH- ions produces water in a neutralization reaction, which occurs when an acid and a base react to form water and salt. A strong acid and strong base neutralized by one another has a pH of 7.

For instance, sodium chloride and water are produced when HCl (hydrochloric acid), a powerful acid, reacts with NaOH, a powerful base.

Given A solution of hydrochloric acid needs to be neutralized by barium solution.

In the given beaker no of Cl- = 4 and H- = 4

For neutralizing, no. of [H+] in acid = no. of OH− in base.

If we go through the options

No. of  H+ in acid  in beaker = 4

Beaker B contains 4 OH− is.

So option(b) is correct.

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explain why ncl3ncl3 is a liquid at room temperature while nh3nh3 is a gas. explain why is a liquid at room temperature while is a gas. hydrogen bonding is present in ncl3ncl3 but not in nh3nh3 . ncl3ncl3 has greater dipole moment than nh3nh3 and thus the dipole-dipole forces in ncl3ncl3 are stronger. the dispersion forces are greater in ncl3ncl3 than in nh3nh3 . ncl3ncl3 partly dissociates to form ions and nh3nh3 does not. therefore, ion-dipole interactions are present in ncl3ncl3 but not in nh3nh3 .

Answers

NH₃ is gas while NCl₃ is liquid at room temperature due to the intermolecular bonding.

The chemical compound having the formula NCl₃ is known as trichloramine, or nitrogen trichloride. The most common way to encounter this explosive liquid is as a result of chemical interactions involving ammonia derivatives and chlorine. It is yellow, greasy, pungent-smelling, and explosive (for example, in swimming pools).

Ammonia, NH₃, is held together strongly by intermolecular hydrogen bonds. While the same group's hydrides contain van der Waal forces between molecules. Furthermore, hydrogen bonds are more powerful than van der Waal forces.

Because of this, NH₃ is a liquid while other hydrides in the same family are gases.

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a metabolic pathway capable of producing adenosine triphosphate (atp) rapidly without the involvement of o2 is termed .

Answers

Anaerobic glycolysis a metabolic pathway capable of producing adenosine triphosphate (atp) rapidly without the involvement of o2 is termed.

A vital "energy molecule" present in all living things is adenosine 5′-triphosphate, also known as ATP and typically written without the 5′-. In particular, it is a coenzyme that transfers energy to cells by releasing its phosphate groups when it interacts with enzymes like ATP triphosphatase. An adenine bicyclic system, a furanose ring, and a triphosphate chain make up the molecule.

The discovery of ATP was reported in 1929 by two research teams. It was isolated from mammalian muscle and liver by Cyrus H. Fiske and Yellapragada Subbarow at Harvard Medical School (Boston). Karl Lohmann discovered it in muscle tissues while working for the Kaiser Wilhelm Institutes in Berlin and Heidelberg. The principal energy source for critical biological processes such muscular contraction, nerve impulse transmission, and protein synthesis is ATP generated in mitochondria.

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. when the colors yellow and blue are combined, they produce a green color. which statement most likely describes the relative sizes of the yellow and blue food-coloring molecules in the diagram?

Answers

Check 3 and 4 for your answer

Draw the major organic product(s) of the following reactions including stereochemistry when it is appropriate. H2O/H2SO4 Hgo . Use the wedge/hash bond tools to indicate stereochemistry where it exists. If no reaction occurs, draw the organic starting material. - Separate multiple products using the + sign from the drop-down menu

Answers

The major organic product of the following reactions including stereochemistry when it is appropriate will be (2-methylallyl)benzene (Structure attached).

The keto-enol tautomerism will result in the formation of ketone upon hydration of the alkyne. To initiate the process of forming an enol, hydrogen and a hydroxy group is introduced across the triple bond. Enol undergoes tautomerism to produce ketone. The reaction that is described further down is facilitated by mercuric oxide. The major organic product of the given reactions including stereochemistry when it is appropriate will be (2-methylallyl)benzene. The structure of reactants and products along with the mechanism and the catalyst are given in the attached picture.

Complete question is attached.

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when 15.00 g co and 5 g of h2 are mixed and reacted in the following reaction, how many grams of methane gas are produced. 3h2 co --> ch4 h20

Answers

Considered are two simultaneous responses involving five species: (Reaction 1) CH4 + H2O CO + 3H2 CO + H2O CO2 + H2 (reaction 2) The water-gas shift (WGS) reaction is reaction number two.

Find the limiting reaction by what method?

By dividing the number of moles of each reactant by its stoichiometric coefficient in the balanced chemical equation, you may determine which reactant is the limiting one. Calculate the maximum number of moles of product that can be produced from the limiting reactant using mole ratios.

How do you identify the limiting and excess reactant?

The limiting reagent is the one that yields the least amount of the final product. The excess reagent is the reactant that yields more product than any other. Subtract the mass of excess reagent eaten from the total mass of excess reagent provided to determine the amount of surplus reactant that is still present.

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propose a chemical test that could be used to distinguish the presence of alkene in your product (hint: think about exp 08).

Answers

Alkane and alkene distinctions can be made using a straightforward test using bromine water. This enables us to differentiate between alkenes and alkanes using a straightforward chemical test.

The orange solution of bromine is called bromine water. Alkanes and alkenes can be distinguished using bromine water, an orange solution. Alkenes are typically checked for using bromine water. If you shake the test tube after adding an alkene to a sample of bromine water. Similar to how alkene passes through bromine water, bromine's yellow color is removed by colorless solution. A qualitative test for the presence of phenols, anilines, and unsaturated carbon is the bromine decolorization test.

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The goal of the VSEPR model is to arrange the position of the atoms and lone pairs surrounding the central atom in a manner that minimizes _____.

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The goal of the VSEPR model is to arrange the position of the atoms and lone pairs surrounding the central atom in a manner that minimizes repulsion.

What is VSEPR?

Based on the number of valence shell electron bond pairs between the atoms in a molecule or ion, the valence shell electron pair repulsion (VSEPR) theory is a model used to predict 3-D molecular shape. According to this hypothesis, electron pairs will position themselves to reduce the consequences of their mutual repulsion. Or to put it another way, the electron pairs are as far apart as they can be.

VSEPR Shapes:

For forecasting and visualizing molecular structures, use the VSEPR model. Linear, trigonal planar, angled, tetrahedral, trigonal pyramidal, trigonal bipyramidal, di-sphenoidal (seesaw), t-shaped, octahedral, square pyramidal, square planar, and pentagonal bipyramidal are the different types of structures.

The names of 3-D geometric shapes are used for the VSEPR structures, such as the trigonal bipyramidal as an example. The VSEPR model depicts a trigonal bipyramidal molecule, such as phosphorus pentachloride or PCl5, as two (bi) linked triangular-base pyramids, with each atom acting as the vertex or corner of a triangular face. PCl5 has five valence shell electron pairs and a central phosphorus atom.

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construct a multistep synthetic route for the synthesis of acetylene from ethane by identifying the reagents and products of each step. note that each bin will hold only one item, and not every given reagent or structure will be used. (stoichiometry is omitted.)

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Acetylene is made from ethane by the following synthetic process:

Reagent 1: Photobromination, Br2, and hv.

Reagent 2: Dehydrobromination using (CH3)3COK+.

Reagent 3: Bromination (Br2).

NaNH2, Elimination is Reagent 4.

What is the route for synthesis?

A synthetic pathway is the method utilised to produce a specific good. In order to study the precise components from which the desired product might be formed, chemists may need to be able to look backward.

(1) To convert ethane to bromoethane, Br2, h, and photobromination are needed as reagents.

(2) To convert bromoethane to ethene, the second necessary reagent is (CH3)3COK+, dehydrobromination.

(3) Ethene to 1,2-dibromoethane requires the following reagent:

Bromination, Br2.

(4) To convert 1,2-dibromoethane to ethyne, reagent 4 is needed.

NaNH2, eradication

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The complete question is :

Construct a multistep synthetic route for the synthesis of acetylene from ethane by identifying the reagents and products of each step. Note that each bin will hold only one item, and not every given reagent or structure will be used. (Stoichiometry is omitted.)

1. reagent 1  H3C—CH3

2. reagent 2 H-C=C—H(ethane) (acetylene)

3. reagent 3

4. reagent 4

accelerating hydrogen absorption and desorption rates in palladium nanocubes with an ultrathin surface modification

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An incredibly intriguing Palladium approach to high-rate energy storage and distribution is to take advantage of the high surface-area-to-volume ratio of nanomaterials by storing energy in the form of electrochemical alloys.

Palladium hydride at the nanoscale is a great model system for learning how characteristics at the nanoscale influence the absorption and desorption of energy-carrying equivalents. In shape-controlled Pd nanostructures, hydrogen absorption and desorption do not take place uniformly throughout the surface of the nanoparticles. Instead, high-activity spots at the corners and edges are used to selectively absorb and desorb hydrogen. With such a process, the benefits of shrinking the palladium's size to the nanoscale are significantly diminished. We alter the palladium surface with an incredibly thin platinum shell to resolve this. This alteration allows diffusion to occur across the entire Pd/Pt surface and practically eliminates the barrier to hydrogen absorption (89 kJ/mol without a Pt shell and 1.8 kJ/mol with a Pt shell).

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