Based on the law of conservation of mass, the expected yield of the decomposition reaction is 100% which is equal to the mass of the reactant.
What mass of products are formed when 1 mole of sodium bicarbonate is decomposed by heat?According to the law of conservation of mass, the mass of products formed when 1 mole of sodium bicarbonate is decomposed by heat will be equal to the mass of one mole of sodium bicarbonate.
The balanced equation of the reaction is given below:
2 NaHCO₃ (s) + Heat --> Na₂CO₃ (s) + H₂0 (g) + CO₂ (g)Molar mass of NaHCO₃ = 84. 0 g/mol
Molar mass of Na₂CO₃ = 106 g/mol
Molar mass of H₂0 = 18 g/mol
Molar mass of CO₂ = 44 g/mol
Based on the mole ratio as given in the equation of reaction,
mass of Na₂CO₃ produced = 1/2 * 106 = 53 g
mass of H₂O produced = 1/2 * 18 = 9 g
Mass of CO₂ produced = 1/2 * 44 g/mol = 22 g
Total mass of products = 53 + 9 + 22 = 84.0 g
Therefore, the yield of the decomposition reaction is equal to the mass of the reactant.
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if the rate of infusion
What's electrolysis
Answer:
electrolysis is the process by which electric current is passed through a substance to effect a chemical change
Calculate the mass of water produced by metabolism 84.0 g of glucose
The amount of water that will be produced is 50.36 grams
Stoichiometric problemsThe metabolism of glucose is represented by the following equation:
[tex]C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)[/tex]
The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
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Calculate the relative rate of diffusion of 1H2 (molar mass 2.0 g/mol) compared with 2H2 (molar mass 4.0 g/ mol) and the relative rate of diffusion of O2 (molar mass 32 g/mol) compared with O3 (molar mass 48 g/mol).
The ratio of diffusion rates of ¹H₂ to ²H₂ is 1.4 while the ratio of diffusion rates of O₂ to O₃ is 1.2.
What is Graham's law?Graham’s law states can be described as the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight of the gas.
According to this Law, molecules with lower molecular mass will diffuse faster than those with higher molecular mass molecules at constant pressure and temperature.
The mathematical formula is utilized to compare the rates of diffusion of two different gases at pressures and temperatures.
[tex]{\displaystyle \frac{R_1}{R_2} =\sqrt{\frac{M_2}{M_1} }[/tex]
Where M₁ and M₂ represent the molar mass of gas 1 and gas 2.
Given, the molar mass of ¹H₂ = 2.0 g/mol
The molar mass of to ²H₂ = 4.0 g/mol
The ratio of the rate of diffusion of ¹H₂ to ²H₂:
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{M_{^2H_2}}{M_{^1H_2}} }[/tex]
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{4}{2} }[/tex]
[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =1.4[/tex]
Given, the molar mass of O₂ = 32.0 g/mol
The molar mass of to O₃ = 48.0 g/mol
The ratio of the rate of diffusion of O₂ to O₃:
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{M_{O_3}}{M_{O_2}} }[/tex]
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{48}{32} }[/tex]
[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =1.2[/tex]
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The compound HBr can be decomposed to form H2 and Br2. This can be represented at the atomic level by a chemical equation:
2HBr H2 + Br2
According to the law of conservation of mass, if 29.5 grams of HBr decomposes and 0.4 grams of H2 is formed, how many grams of Br2 must simultaneously be formed?
The law of conservation of mass say that, in a chemical reaction, the mass of the reagents will always be equal to the mass of the products.
If we have 29.5 g of HBr, we must have 100 g of H2 and Br2 together, so:
29.5 = 0.4 + Br2Br2 = 29.1 gBehavior can best be defined as
A.
the response of an organism to its environment.
B.
the physical characteristics of a species.
C.
a sudden change in an organism's habitat.
D.
the geographic range of a species.
Calculate the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L.
The molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.
How to calculate molecular mass?The molecular mass can be calculated by first calculating the number of moles using the following formula:
PV = nRT
Where;
P = pressureV = volumen = no of molesR = gas law constantT = temperature1.112 × 0.7 = n × 0.0821 × 300
0.7784 = 24.63n
n = 0.032mol
molecular mass = 2.66g ÷ 0.032mol
molecular mass = 84.16g/mol
Therefore, the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.
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Based on the electron configuration of the two
atoms, predict the ratio of metal cationic (+) atom
to nonmetal anionic (-) atom in the compound.
1s²2s²2p63s²
1s²2s²2p63s²3p4
A. 1:1-
C. 2:1
Magnesium
Sulfur
B. 1:2
D. 3:1
Based on the electron configuration of the two atoms predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound hence the ratio is 1:1.
What does the octet rule say?The Octet Rule states that the atoms of the elements bond to each other in an attempt to complete their valence shell (the last shell of the electrosphere).
Basically, they obey the octet rule which states that the capacity of atoms (e.g. here Magnesium and Sulfur) to prefer to have 8 (eight) electrons (e-) in their respective valence shells. In this case, Magnesium is Mg (+2) and Sulfur is (-2) hence the ratio is 1:1.
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What do you see when the Moon is waning?
Answer:
The bright side of the moon will become less and less and will eventually be covered in complete darkness :)
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Help pls !!!
From first step to eighth, options are on the right !
Wastewater can be treated using series of eight steps which would be clarified below.
What are the steps of wastewater treatment?Wastewater is the type of water that is used for four different purposes in homes,offices, industries and factories.
These wastewater contain human waste, food scraps, oils, soaps and chemicals which can be treated and reused through the following means:
First Step: headworks, remove big objects.Second step: separate tiny solid particles and oil out of the water by settling (primary treatment).Third step: Pump up the water to secondary treatment level.Fourth step: Let solids settle and oil float again and let bacteria do de-nitrification without blowing any air (secondary treatment).Fifth step: Blow pure oxygen through the water and let bacteria eat the waste. Also let the bacteria perform de-nitrification (secondary de-nitrification).Sixth step: Filtration, disinfection, reverse osmosis filtration (tertiary treatment).Seventh step: send 6% of the water away from the tertiary treatment.Eight step: drop most of the water through a 5 mile pipe 200 feet deep into the ocean.Learn more about water treatment here:
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What are the magnetic quantum numbers possible for a 6s subshell and for a 4f subshell? Drag the correct numbers into each of the columns.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
6s Subshell 4f Subshell
For the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
What is the magnetic quantum number?The magnetic quantum number takes on values between 0 to (n - l). It gives the orientations of the sublevels. The four types of quantum numbers are;
Principal quantum numberAzimuthal quantum numberMagnetic quantum numberSpin quantum numberFor the 6s subshell, the magnetic quantum number is zero while for the 4f subshell we have -3, -2, -1, 0, 1, 2, 3.
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How does increasing the temperature of a liquid below the boiling point affect
the motion of the particles in the liquid?
OA. The particles move faster.
B. The motion of the particles overcomes the forces holding the
particles together.
OC. The motion of the particles strengthens the forces between the
particles.
D. The particles move slower.
Answer: A. The particles move faster
Explanation:
Increasing the temperature increases the kinetic energy of the particles, causing them to move faster.
What is technology ?
Answer:
Technology is the application of scientific knowledge for practical purposes especially in industry.
Alpha Decay
1. If an atom of Uranium-238 decays via alpha emission, what would be its daughter product? (You will need a periodic table.)
2. If an atom of Thorium -228 decayed via beta emission, what would be the daughter isotope?
Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
What are the products of Uranium-238 and Thorium -228?If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.
So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
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When aqueous solutions of calcium bromide and potassium carbonate are combined, solid calcium carbonate and a solution of potassium bromide are formed. The net ionic equation for this reaction is:
(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)
(screen shot is attached ) please help
[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.
What is an ionic equation?An ionic equation is a synthetic equation where electrolytes are composed as separated particles.
[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.
A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.
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which of the three minerals contain calcium carbonate?
A. salt
B. chalk
C. talcum
Answer:
Answer choices A, B, and C all contain a certain level (or amount, if you will) of Calcium Carbonate, but B. chalk contains the most amount out of all three.
Explanation:
I hope that this was helpful! (✿◠‿◠)
Thank you!
(ii) CH₂=C - CHCH3 Br,give the IUPAC name of the compound
Answer:
propene
Explanation:
According to the rules,the name of hydrocarbon:root word+suffix=prop+ene=propene
What volume of carbon dioxide in liters could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas (C5H12)?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)
(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")
Do not type units with your answer
589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ([tex]C_5H_{12}[/tex])
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
[tex]C_5H_{12}(g) + 8 O_2(g)[/tex] --->[tex]5 CO_2(g) + 6 H_2O(g)[/tex]
To find the volume, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
P = pressure (atm)
V = volume (L)
n = number of moles
R = constant (0.0821 L*atm/mol*K)
T = temperature (K)
To find the volume of water vapour, you need to (1) convert grams C₅H₁₂ to moles C₅H₁₂ (via molar mass), then (2) convert moles C₅H₁₂ to moles H₂O (via mole-to-mole ratio from reaction coefficients), then (3) calculate volume H₂O (via Ideal Gas Law). The final answer should have 3 sig figs.
Molar Mass (C₅H₁₂) =72.151 g/mol
1 C₅H₁₂ (g) + 8 O₂ (g) -----> 5 CO₂ (g) + 6 H₂O (g)
228.85 g C₅H₁₂ 1 mole 6 moles H₂O
----------------------- x ---------------- x ----------------------- = 19.03 moles H₂O
72.151 g 1 mole C₅H₁₂
Moles of H₂O= 19.03
P =0.96 atm
R = 0.0821 L x atm/mol x K
V = ?
T = 362 K
n = 19.03 moles
PV = nRT
(0.96 atm)V = ( 19.03 moles)(0.0821 Latm/molK)(362K)
(0.96 atm)V = 565.575406
V = 589L
Hence, 589L volume of carbon dioxide in litres could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen gas excess pentane gas ([tex]C_5H_{12}[/tex]).
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ssssssssssssssssssssssssssssss
Answer:
s
Explanation:
differenciate between adsorption and absorption.
[tex] \\ [/tex]
ty! ~
Answer:
Adsorption is the adhesion of atoms, ions or molecules from a gas, liquid or dissolved solid to a surface. This process creates a film of the adsorbate on the surface of the adsorbent. This process differs from absorption, in which a fluid is dissolved by or permeates a liquid or solid.
while ,
Absorption is a physical or chemical phenomenon or a process in which atoms, molecules or ions enter some bulk phase – liquid or solid material. This is a different process from adsorption, since molecules undergoing absorption are taken up by the volume, not by the surface
[tex] \\ [/tex]
-,-
How much heat would need to be removed to
cool 215.1 g of water from 25.6°C to -10.7°C?
Answer:
100 KJ
Explanation:
yep yep cool is that correct
How many molecules are in 84.7 grams?
The number of molecules will depend on the molar mass of the compound.
Number of moleculesAccording to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex].
To find the number of moles in a substance:
Mole = mass/molar mass.
In this case, we do not know the compound but we know the mass. Hence, we cannot know the molar mass.
Assuming the molar mass is X.
Mole = 84.7/X
Number of molecules in 84.7 grams of the compound =
84.7/X x 6.022 x [tex]10^{23}[/tex] molecules.
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57.A cofactor is a(an)
a. catalyst for chemical reactions in a living system.
b. protein molecule whose primary function is transport of insoluble molecules in the
bloodstream.
C.
d.
e.
molecule that is acted on by a catalyst.
biological molecule used for storage of energy.
organic or inorganic molecule or ion necessary for proper functioning of some
biological catalysts.
A cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts (option E).
What is a cofactor?A cofactor in biochemistry is a molecule that binds to and regulates the activity of a protein.
A cofactor is a metal or coenzyme responsible for the functioning of an enzyme and must be present.
Therefore, a cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts.
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Place the stages of a high-mass star's life cycle in the correct order, from a star's birth to its death.
supergiant
neutron star
protostar
nebula
supernova
Whether a living or non-living object, everyone has a particular life cycle. It starts right from the birth and ends upon the death of that object. Just like others, stars also have their own life cycle and that has different stages.
Nebula ⇒ Protostar ⇒ Supergiant ⇒ Supernova ⇒ Neutron Star
What is the life cycle of a high-mass star?In the initial stage, a star is in the form of a nebula. At this stage, it is a huge cloud of gas and dust. The changes occur in the star and the final size totally depends upon the size of that star.
In a massive star, the fuel is used very quickly because of its life span of a few hundred thousand years. The second stage is the Protostar.
The next stage is the Supergiant. At this stage, the nuclear reactions that occur because of the hydrogen will gradually run out and the star will enter the final phase of its life span. The bigger star will have more massiveness.
Following this, the star will enter the next stage, i.e., supernova, and after that, neutron star. In a supernova, the star will have a very energetic and violent end. In the last stage, when the dust particles clear, a neutron star will be visible.
For better understanding, an image is attached at the end.
Thus, the life cycle of a high-mass star is arranged from its birth to its death.
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The stages of a high-mass star's life cycle in the correct order, from a star's birth to its death are-
Nebula
Protostar
Supergiant
Supernova
Neutron star
The life cycle of a high-mass star begins with a nebula, a cloud of gas and dust in space. As gravity pulls the nebula together, it forms a protostar—a young, hot, and dense object. The protostar continues to gather mass and becomes a main-sequence star, burning hydrogen in its core.
Once the hydrogen is exhausted, the star expands into a supergiant and starts fusing helium into heavier elements. Eventually, it undergoes a supernova explosion, releasing an enormous amount of energy and leaving behind a dense core known as a neutron star. This process showcases the incredible transformations that high-mass stars undergo throughout their life cycle.
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if 185 g of wax c22h44 burns how many litres of oxygen gas were used up assume the conditions in the lab are 101kpa and 25 degree celcius
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 101kpa =0.996792 atm
V= ?
R=[tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=25 +273 =298 K
Moles =?
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{185 g }{308.6}[/tex]
Moles =0.56
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]0.56= \frac{0.996792\;atm\; X \; V }{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
13.73 L =V
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
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Find the pH of 0.0025M sodium benzoate
Hi, Can someone help me with this question, please! It's due tonight!
Given the balanced equation:
3 CO + 7 H2 C3H8 + 3 H2O,
how much C3H8 will be produced if 45.8 g CO reacts with 87.3 g H2?
Answer:
24.0 g C₃H₈
Explanation:
To find the mass of C₃H₈, you need to (1) convert grams CO/H₂ to moles CO/H₂ (via molar mass), then (2) convert moles CO/H₂ to moles C₃H₈ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles C₃H₈ to grams C₃H₈ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs in the given values.
Molar Mass (CO): 12.011 g/mol + 15.998 g/mol
Molar Mass (CO): 28.009 g/mol
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
Molar Mass (C₃H₈): 3(12.011 g/mol) + 8(1.008 g/mol)
Molar Mass (C₃H₈): 44.097 g/mol
3 CO + 7 H₂ ----> 1 C₃H₈ + 3 H₂O
^ ^ ^
45.8 g CO 1 mole 1 mole C₃H₈ 44.097 g
----------------- x ------------------ x -------------------- x ------------------ =
28.009 g 3 moles CO 1 mole
= 24.0 g C₃H₈
87.3 g H₂ 1 mole 1 mole C₃H₈ 44.097 g
---------------- x --------------- x --------------------- x ----------------- =
2.016 g 7 moles H₂ 1 mole
= 273 g C₃H₈
It was necessary to find the mass of the products from both of the reactants because you did not know which one was the limiting reagent. The limiting reagent is the reactant which is completely used up first. Because CO produced the smaller amount of product, it must be the limiting reagent. Therefore, the actual amount of C₃H₈ produced is 24.0 grams.
How many grams of N2o are formed if 0.46 mole of NH4No3 is used in the reaction
20.24 grams of [tex]N_2O[/tex] is formed if 0.46 mole of [tex]NH_4NO_3[/tex] is used in the reaction.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Balanced equation:
[tex]NH_4NO_3[/tex] → [tex]N_2O + 2H_2O[/tex].
1 mole [tex]NH_4NO_3[/tex] gives 1 mole of [tex]N_2O.[/tex]
0.46 mole of [tex]NH_4NO_3[/tex] gives [tex]\frac{ 1 mole}{ 1 mole}[/tex] x 0.46 mole [tex]N_2O[/tex].
0.46 mole [tex]N_2O[/tex] =[tex]\frac{mass}{44.013 g/mol}[/tex]
Mass= 0.46 x 44.013
Mass=20.24gram.
Hence, 20.24 grams of [tex]N_2O[/tex] is formed if 0.46 mole of [tex]NH_4NO_3[/tex] is used in the reaction.
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determine the number of moles of H in each sample
C. The number of moles of H in 0.109 mole of N₂H₄ is 0.436 mole
D. The number of moles of H in 34 moles of C₁₀H₂₂ is 748 moles
C. How to determine the number of mole of H in 0.109 mole of N₂H₄1 mole of N₂H₄ contains 4 moles of H
Therefore,
0.109 mole of N₂H₄ will contain = 0.109 × 4 = 0.436 mole of H
D. How to determine the number of mole of H in 34 mole of C₁₀H₂₂1 mole of C₁₀H₂₂ contains 22 moles of H
Therefore,
34 mole of C₁₀H₂₂ will contain = 34 × 22 = 748 mole of H
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A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section be? *
Each section would be 230 centimeters or 2.30 meters long.
Sectional divisionThe original wood pole is 12 meters long.
12 meters = 12 x 100 = 1200 centimeters
It is to be cut into 5 equal sections: 1200/5 = 240 centimeters
But each cut wastes 10 cm of the pole.
240 - 10 = 230 centimeters.
Thus, each section would be 230 centimeters or 2.30 meters long.
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