help please!!
Integrate the following:
[tex] \displaystyle \int {x}^{2} {e}^{x} dx[/tex]

Answers

Answer 1

Answer:

[tex] \rm \displaystyle \int x ^{2} \cdot {e}^{x} \: dx = {x}^{2} {e}^{x}- 2x {e}^{x} + 2 e^{x} + \rm C[/tex]

Step-by-step explanation:

we want to integrate the following integration:

[tex] \displaystyle \int {x}^{2} \cdot {e}^{x} dx[/tex]

notice that, the integrand is in the multiplication of two different function in that case we can consider integration by parts given by:

[tex] \rm \displaystyle \int u \cdot v \: dx = u \int vdx - \int u' \left( \int v dx \right)dx[/tex]

where u' can be defined by the differentiation of u

now we have to choose our u and v

which can be chosen by using the guideline:ILATE Inverse trig. , Logarithm, Algebraic expression, Trigonometry, Exponent.

since x comes first thus,

[tex] \displaystyle u = {x}^{2} \quad\text{and} \quad v = {e}^{x} [/tex]

by figuring out the defferentiation of u,we acquire:

[tex] \displaystyle u' = 2x[/tex]

altogether we get:

[tex] \rm \displaystyle \int {x}^{2} \cdot {e}^{x} \: dx = {x}^{2} \int {e}^{x} dx - \int 2x \left( \int {e}^{x} dx \right)dx[/tex]

by figuring out the parentheses integration

we get:

[tex] \rm \displaystyle \int x^2 \cdot {e}^{x} \: dx = {x}^{2} \int {e}^{x} dx - \int2x \cdot {e}^{x} dx[/tex]

now we again have integration of two different functions so let's choose our u and v once again which can be done using the guideline

[tex] \displaystyle u = 2x \quad\text{and} \quad v = {e}^{x} [/tex]

by figuring out the defferentiation of u

we acquire:

[tex] \displaystyle \: u' = 2[/tex]

altogether we get:

[tex] \rm \displaystyle \int x ^{2} \cdot {e}^{x} \: dx = {x}^{2} \int {e}^{x} dx - \left( 2x \int{e}^{x} dx- \int2 \left( \int{e}^{x}dx \right) dx \right)[/tex]

by solving parentheses we get

[tex] \rm \displaystyle \int x ^{2} \cdot {e}^{x} \: dx = {x}^{2} \int {e}^{x} dx - \left( 2x {e}^{x} - 2 e^{x} dx \right)[/tex]

by figuring out the integral we get:

[tex] \rm \displaystyle \int x ^{2} \cdot {e}^{x} \: dx = {x}^{2} {e}^{x}- \left( 2x {e}^{x} - 2 e^{x} \right)[/tex]

remove parentheses:

[tex] \rm \displaystyle \int x ^{2} \cdot {e}^{x} \: dx = {x}^{2} {e}^{x}- 2x {e}^{x} + 2 e^{x} [/tex]

at last we of course have to add constant of integration:

[tex] \rm \displaystyle \int x ^{2} \cdot {e}^{x} \: dx = {x}^{2} {e}^{x}- 2x {e}^{x} + 2 e^{x} + \rm C[/tex]

and we are done!

Answer 2

Answer:

[tex]\displaystyle \int {x^2e^x} \, dx = e^x(x^2 - 2x + 2) + C[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

IntegralsIndefinite IntegralsIntegration Constant C

Integration by Parts:                                                                                               [tex]\displaystyle \int {u} \, dv = uv - \int {v} \, du[/tex]

[IBP] LIPET: Logs, inverses, Polynomials, Exponentials, TrigTabular Integration

Step-by-step explanation:

*Note:

The answer below me is correct, but there is a simpler method of obtaining the answer.

Step 1: Define

Identify

[tex]\displaystyle \int {x^2e^x} \, dx[/tex]

Step 2: Integrate

Use tabular integration.

[Integrand] Differentiate/Integrate [Tabular Integration]:                           [tex]\displaystyle \\\begin{center}\begin{tabular}{ c | c }\line{u & dv} \\\cline{1 - 2} x^2 & e^x \\\ 2x & e^x \\\ 2 & e^x \\\ 0 & e^x\end{tabular}\end{center}[/tex]Write out expansion [Tabular Integration]:                                                 [tex]\displaystyle \int {x^2e^x} \, dx = x^2e^x - 2xe^x + 2e^x + C[/tex]Factor:                                                                                                           [tex]\displaystyle \int {x^2e^x} \, dx = e^x(x^2 - 2x + 2) + C[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e


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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

The distance Jeremy will need to travel between Point C and Point A 19.69 miles.

We have given that,

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2 x (6 divied 2 dived 8) - 4

Answers

Answer:

18

Step-by-step explanation:

6/2=3+8=11

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Use this to help you next time!

Paranthesis

Exponets

Multiplication

Divison

Add

Subtract

Hope this helps!

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Answers

area = ( top rule + bottom rule ) × height / 2

area = ( 2 + 3 ) × 4 / 2

area = 5 × 4 / 2

area = 20 / 2

area = 10

The area is 10. You can just count the squares and the half squares

An architect has designed a new hotel shaped like a giant rectangular pyramid. The base of the model for this hotel measures 20 inches by 30 inches, and is 25 in. tall. What is the volume of the pyramid?

Answers

Answer:

Volume of pyramid = 5000 cubic inches.

Step-by-step explanation:

Given the following data;

Length = 20 inches

Width = 30 inches

Height = 25 inches

To find the volume of pyramid;

Mathematically, the volume of a pyramid is given by the formula;

[tex] Volume = \frac {1}{3} * base \; area * height [/tex]

First of all, we would determine the base area;

Base area = length * width

Base area = 20 * 30

Base area = 600 in²

Substituting into the formula, we have;

[tex] Volume = \frac {1}{3} * 600 * 25 [/tex]

[tex] Volume = 200 * 25 [/tex]

Volume of pyramid = 5000 cubic inches.

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Answers

Answer:

Y= -5/2x+3

Step-by-step explanation:

A perpendicular slope is always opposite (meaning if the original is negative, then it is positive and vice versa) and reciprocal (meaning the numerator and denominator of the original are flipped).

The y intercept I found by applying the slope to the point given.

Perpendicular lines have opposite reciprocal lines.

y = mx + b
the m represents the slope
the opposite reciprocal of 2/5 is -5/2
y = -5/2x + b
to solve the rest of the problem, you will need to plug in your x and y coordinates.
-2 = -5/2(2) + b
-2 = -10/2 + b
-2 = -5 + b
Add 5 to both sides.
b = 3

This means your equation is...
y = -5/2x + 3
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