Help please I need to find x and y

Help Please I Need To Find X And Y

Answers

Answer 1

Answer:

[tex]x=6\\y=12[/tex]

Step-by-step explanation:

To find the value of x you can use sin rule

[tex]sin(60)=\frac{oppoaite}{hypotenuse}\\\frac{\sqrt{3} }{2} =\frac{x}{4\sqrt{3} } \\[/tex]

Use cross multiplication

[tex]4*\sqrt{3} *\sqrt{3} =2x\\4*3=2x\\12=2x\\\frac{12}{2} =\frac{2x}{2} \\6 =x[/tex]

To find the value of y you have to use sin rule again

[tex]sin(30)=\frac{opposite}{hypotenuse}\\\frac{1}{2} =\frac{x}{y} \\\frac{1}{2} =\frac{6}{y} \\[/tex]

Use cross multiplication

[tex]y=6*2\\y=12[/tex]

Hope this helps you.

Let me know if you have any other questions :-)

Answer 2
Hey, so I got
x = 5.9 units (just round it to 6)
y= 11.8 units (round it to 12)

Steps:

1) Use Soh Cah Toa to identify the unknown sides.

The side across the angle is the opposite. Therefore, the x side is opposite.
4√5 = 6.9 ( this side is the hypotenuse).
So we have the opposite side and the hypotenuse side. Therefore, we will use sine

2) Sin theta = opp/hyp
Sin 60 = opp/6.9

Multiply both sides by 6.9

6.9(sin60) = opp
5.9 = opp

3) now that you have side x, we will use x to figure out side y.

Identify the sides first. Side x is opposite and side y is the hypotenuse. Use sine to solve for side y

Sin theta = opp/hyp
Sin 30 = 5.9/hyp
0.5 = 5.9/hyp

Divide 0.5 and bring it over to the other side.

= 5.9/ hyp ÷ 0.5/1
= 5.9/hyp x 1/0.5
= 5.9/0.5
= 11.8 units (side Y)
Help Please I Need To Find X And Y

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