HELP!!! IM BEING TIMED AND I RLLY NEED HELP

HELP!!! IM BEING TIMED AND I RLLY NEED HELP

Answers

Answer 1

Answer:

4.3446× 10^6

3.2156305×10^3

7.68841×10^-6

1.2153698×10^1

9.5677734

Explanation:


Related Questions

A typical galaxy contains about 100 billion stars, and there are approximately 100 billion galaxies in the observable universe. About how many stars are in the observable universe

Answers

Answer = (100 billion stars/galaxy) x (100 billion galaxies/universe)

Answer = (100 billion x 100 billion) stars

Answer = 10,000 billion billion stars

Answer = 10,000,000,000,000,000,000,000 stars

Answer = 10²² stars/observable universe

The number of stars in the observable universe is; 10²² stars/observable universe.

How many stars are in the observable universe?

Since there are about 100 billion stars in our galaxy; we can rewrite that to be;

100 billion stars/galaxy

However, there are about 100 billion galaxies in the observable universe.

Since our galaxy is one of the 10¹¹ observable galaxies in the universe; the number of stars in the observable universe is;

(100 billion stars/galaxy) x (100 billion galaxies/universe)

= (100 billion x 100 billion) stars

= 10,000 billion billion stars

= 10,000,000,000,000,000,000,000 stars

= 10²² stars/observable universe

Therefore, the number of stars in the observable universe is; 10²² stars/observable universe.

Read more the similar concept here;

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(100 POINTS AND BRAINLEIST) could you please help me with this ASAP!

Answers

The above are questions related to the formula of force F = m * a i.e. mass * accleration. It is defined by the Newton's second law of motion.

In the attachment, I can see that Question 1) and Question 2) are already done, So lemme start from Question 3[tex])[/tex]

3) Provided:-

Force applied = 7000 NOn a ball of mass = 0.5 kg

To FinD:-

Acceleration of the ball...?

By using formula,

⇛ F = ma

⇛ 7000 N = 0.5 kg × a

⇛ a = 7000 / 0.5 m/s²

⇛ a = 14000 m/s²

So, the ball acclerates at the rate of 14000 m/s².

4) Provided:-

Accleration of the truck = 10 m/s²On a truck of mass = 31200 kg

To FinD:-

Force applied on the truck..?

By using formula,

⇛ F = ma

⇛ F = 31200 kg × 10 m/s²

⇛ F = 312000 kg/m/s²

⇛ F = 312000 N

So, force on the truck = 312000 N

5) a) Force applied = 100 N

Mass applied = 5 kg

Then, Acceleration = 100 ÷ 5 = 20 m/s²

b) Force applied = 100 N

Mass applied = 10 kg

Then, Acceleration = 100 ÷ 10 = 10 m/s²

c) Force applied = 100 N

Mass applied = 20 kg

Then, Acceleration = 100 ÷ 20 = 5 m/s²

d) Force applied = 100 N

Mass applied = 50 kg

Then, Acceleration = 100 ÷ 5 = 2 m/s²

And we are done !!

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Answer: The answer are above :(

w
Trial
х
1
75.0 72.2
2
75.1
72.3
3
75.1 72.1
4
74.9
72.2
Which set of data is most likely the result of a systematic error?
Y
75.0
80.1
69.5
72.7
Z
86.2
86.7
71.5
70.8
w
Х
Z

Answers

Answer:

75

Explanation:

w

X

y

z.86.2,86.7,70.8

A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. What is its acceleration?

Answers

Answer:

80/2= 40 m/s^2.

Explanation:

A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s.  Its acceleration is 4 m/sec².

What is acceleration?

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = change in velocity / time

acceleration = 80 / 20

acceleration = 4 m/sec²

A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s.  Its acceleration is 4 m/sec².

To learn more about acceleration refer to the link:

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how water is constructed and how the matter is built-up?​

Answers

Answer:

How is water constructed ?A molecule of pure water is made of two hydrogen atoms bonded to an oxygen atom

How is matter built-up?The basic building blocks that make up matter are called atoms. (hope i could help :)

Explanation:

The displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t2, where t is the time in seconds. What is the instantaneous velocity of the block when t = 2.0 s?

Answers

Answer:

0.19m/s

Explanation:

velocity is the change in displacement of a body with respect to time. Given the displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t², where t is the time in seconds, instantaneous velocity is expressed by differentiating the displacement with respect to time

Velocity = dd/dt

Velocity = -0.65 + 2(0.21)t²⁻¹

Velocity = -0.65 + 0.42t

The instantaneous velocity of the block when t = 2.0 s can be gotten by substituting t = 2.0s into the expression above:

Velocity = -0.65 + 0.42(2)

Velocity = -0.65 + 0.84

Velocity = 0.19

Hence the instantaneous velocity of the block when t = 2.0 s is 0.19m/s

what is the momentum in Kg m/s of a 10 kg truck travelling at A) 5 m/s B) 20 cm/s C) 36 km/h?​

Answers

Answer:

A)   50 kg m/s

B)  2 kg m/s

C)  100 kg m/s

Explanation:

Recall that momentum is a physical quantity defined by the product of the object's mass times its velocity. Therefore, in our case the truck's momentum (p) is:

A)  p = m * v = 10 kg * 5 m/s = 50 kg m/s

B) p = m * v = 10 kg * 0.20 m/s = 2 kg m/s (notice that the velocity in cm/s was converted into m/s before multiplying)

C) the conversion from km/h to m/s is a little more involved, so we taclke it first:

since 1 km = 1000 m  and 1 hour = 3600 seconds, we convert 36 km/h by replacing each unit by its m and s expression as shown below:

[tex]36 \frac{km}{h} =36\,\frac{1000\,m}{3600\,\,s}=10\,\frac{m}{s}[/tex]

Then, the momentum is:  p = m * v = 10 kg * 10 m/s = 100 kg m/s

What happens to scientific laws if new, unexpected data is discovered? a They become scientific theories. b They are revised. c Nothing, the new data is ignored.

Answers

Answer:

revised

Explanation:

. Air moves up and down by convection. Molecules of air are spaced farther apart in rising warm air. What must the volume of cold air have more of than the same volume of warm air?

Answers

Answer:d

Explanation:tsssss

PLZ HELP TIMES TEST

When a person strikes and lights a match, potential energy in the match is transformed into which types of energy?

electrical and thermal
thermal and radiant
radiant and nuclear
nuclear and kinetic

Answers

Answer:

Thermal and Radiant

Explanation:

Thermal = Heat

Radiant = Light

Answer: B

Explanation:

A plant is moved from direct sunlight and placed into complete darkness.

Which structure in the plant's cells would be most affected by this change?

Choose 1 answer:

(Choice A)
A
Mitochondria

(Choice B)
B
Chloroplast

(Choice C)
C
Vacuole

(Choice D)
D
Golgi body

Answers

a,

Explanation:

because when its moved thats the sugar of it

Answer:

b. Chloroplast

Explanation:

What year was volleyball invented?
10 p
1889
1874
1895
1918
How many players are on each volleyball team?
Please help

Answers

volleyball was invented in the year 1895 by william G. morgan ! hope this helps !!

A speed skater moving to the left across frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadily, then continues on at 6.0 m/s. What is her acceleration on the rough ice?

Answers

Answer:

Acceleration, [tex]a=-2.8\ m/s^2[/tex]

Explanation:

It is given that,

The initial speed of a speed skater, u = 8 m/s

The final speed of a speed skater, v = 6 m/s

Width of patch of rough ice, s = 5 m

We need to find the acceleration on the rough ice. Acceleration can be calculated using third equation of motion as :

[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{(6)^2-(8)^2}{2\times 5}\\\\a=-2.8\ m/s^2[/tex]

So, the acceleration on the rough ice is [tex]2.8\ m/s^2[/tex]. Negative sign shows that its speed is decreased.

What type of microscope bends light and uses multiple lenses to magnify a cell?

Choose 1 answer:

(Choice A) A Transmission electron microscope

(Choice B) B Simple light microscope

(Choice C) C Compound light microscope

(Choice D) D Scanning electron microscope

Answers

C . Compound light microscope

. Explain how surface waves can have characteristics of both longitudinal waves and transverse waves.

Please use 3 content related sentences. (ref: p.388-393)

Answers

Answer:

This whole concept depends on the depends on the direction of propagation of the surface wave or displacement of wave such that if its in direction of wave velocity its said to features of longitudinal wave and if its in direction at 90° to wave velocity its said to have transverse features

I will give brainliest if right

Prokaryotes are structurally simple organisms that have existed for over two billion years.
Which of the following are prokaryotes?

Choose 1 answer:

(Choice A) A Animals

(Choice B) B Bacteria

(Choice C) C Plants

(Choice D) D Fungi

I will give brainliest if right

Answers

Answer:

Prokaryotic Cells are cells that lack Cell Nucleus so the answer is bacteria

Answer:

B Bacteria

Explanation:

Choice B because the prokaryotes are single-celled organism with no nucleus.

6. Amy spits watermelon seeds at 1.8 m/s. How far will the seed travel in 1.2 s?

Answers

Answer:

2.16 meters

Explanation:

We can find distance using the following formula.

[tex]d=s*t[/tex]

where [tex]s[/tex] is the speed and [tex]t[/tex] is the time.

The speed of the watermelon seed is 1.8 meters per second. The time is 1.2 seconds.

[tex]s= 1.8 m/s\\t=1.2 s[/tex]

Substitute the values into the formula.

[tex]d= 1.8 m/s * 1.2 s[/tex]

Multiply. When you multiply the 2 "s" that represent seconds will cancel out.

[tex]d= 1.8 m * 1.2[/tex]

[tex]d=2.16 m[/tex]

The watermelon seed with travel 2.16 meters in 1.2 seconds.

Car A of mass 1500 kg travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction. After collision, the velocity of car A becomes 20 m/s. Calculate the velocity of car B after collision.

Answers

Answer:

Apparently this has been asked a few years ago, so I copied this answer from deepikakvvk06 - - all credit goes to them!

velocity of car 'B' after collision is 22.5m/s. //it's a conservation of momentum question

Explanation:

Let ,

mass = m

initial velocity = u

final velocity = v

here ,

m₁= 1500 kg

m₂=1000 kg

u₁ = 25 m/s

u₂ = 15 m/s

v₁ = 20 m/s

we have to find v₂ !!

v₂ is the velocity after collision

Here is a formula relating the values given ,

m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂

m₁u₁+m₂u₂ = 1500 × 25 + 1000 ×15

= 37500 + 15000

= 52500

m₁v₁ + m₂+v₂ = 1500 × 20 + 1000 × v₂

= 30000 + 1000v₂

m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂

52500 = 3000 + 1000v₂

1000v₂ = 52500 - 30000

1000 v₂ = 22500

v₂ = 22500/1000

= 22.5 m/s

Thus, velocity of car 'B' after collision is 22.5m/s.

6)
Calculate the area of a body which experiences a pressure of 60000 Pa by a force of 120N

Answers

Answer:

area = force by pressure

or, a = 120N by 60000 Pa

or, a= 0.002 m²

what is one common electrostatic phenomenon​

Answers

Answer:

There are many examples of electrostatic phenomena, from those as simple as the attraction of the plastic wrap to one's hand after it is removed from a package to the apparently spontaneous explosion of grain silos, the damage of electronic components during manufacturing, and photocopier & laser printer operation

If a dog moves 3 meters due East and then 4 meters due North, what will be the dispalcement of the dog?

Answers

Answer:

5 m

Explanation:

Displacement is the diatnce moves in a specified direction. It is the shortest distance covered  by the dog. The displacement of the dog can be gotten by using the pythagoras theorem as shown;

According to the theorem, a²+b² = d² where d is the displacement

Substituting the given value into the fofrmula;

3²+4² = d²

9+16 = d²

d² = 25

square root both sides

√d² = √25

d = √25

d = 5 metres

Hence the displacement of the dog is 5metres

 

A 1.35 kgkg block is attached to a spring with spring constant 15.0 N/mN/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 34.0 cm/scm/s . What are

Answers

Given :

Mass of block , m = 1.35 kg .

Speed constant , k = 15 N/m .

Speed at centre , v = 34 cm/s = 0.34 m/s .

To Find :

The amplitude of oscillation .

Solution :

Now , we know total energy is conserved in SHM .

So , K.E at zero displacement :

[tex]K.E=\dfrac{mv^2}{2}\\\\K.E=\dfrac{1.35\times 0.34^2}{2}\\\\K.E=7.8\times 10^{-2}\ J[/tex]

Now , this K.E is equal to maximum P.E :

[tex]P.E=K.E=7.8\times 10^{-2}\ J[/tex] .

[tex]P.E=\dfrac{kA^2}{2}\\\\7.8\times 10^{-2}=\dfrac{kA^2}{2}\\\\A=\sqrt{\dfrac{2\times 7.8 \times 10^{-2}}{15}}\ m\\\\A=0.1019 \ m\\\\A=10.2\ cm[/tex]

Therefore , the amplitude is 10.2 cm .

Hence , this is the required solution .

A car starting from rest accelerates at a rate of 8 0 m/s/s. What is its final speed at the end of 40 seconda?
i have no idea what is if you know the answer, can you please answer it?

Answers

Answer:

you have to organize the data. a= acceleration vi=inicial velocity vf=final velocity  t=time.

a=80m/s

vi=0

vf=?

t=40 s

the formula you have to use is:

vf=vi+a*t  (final velocity= inicial velocity plus acceleration times time)

Explanation:

I was the best one at my class, hope it helped

Answer: 320 m/s

Explanation:  V initial = 0, V final= ?   Acceleration = 8m/s/s  t=40s

So at the end of V 40 sec=  v intial + acceleration x Δt  = 0 +8m/s² x 40s  = 320m/s

The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to slow to a final velocity of 2.0 m/s?

Answers

Answer:

t = 2.35s

Explanation:

Using one of the equation of motion expressed as v = u+at where;

v is the final velocity = 2.0m/s

u is the initial velocity = 25m/s

a is the acceleration = -a (since the acceleration is negative)

t is the time taken

Substituting the given parameters into the formula above;

2.0 = 25-9.81t

subtract 25 from both sides

2.0 - 25 = 25-9.81t - 25

-23 = -9.81t

Divide both sides by -9.81

-23/-9.81 = -9.81t/-9.81

t = 23.0/9.81

t = 2.35s

Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s

True or False: You walk across a carpet and accumulate a net negative charge on the soles of your shoes. When you touch your sister with your finger and give her a small zap, the charge that accumulated on your finger is due to charging by contact.

Answers

Answer:

True

Explanation:

Charging by conduction occurs when a charged conductor comes in contact with an uncharged conductor, leading to the sharing of charges between both conductors. Contact charging leads to a sharing and distribution of the same type of charges on the two conductors.

In this case, your entire body is charged by the sole of your feet coming in contact with the charged carpet on the floor, leading to a charge buildup all over your body.


A boy wishes to make
a catapults out of
a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band
he must use so that when the stretches it by 0.25
of its natural length and releases it, the velocity of the pebble of mass 0.0006kg is
30ms - Take the youngs modulus of the rubber
to be 4x10000000nm-2

Answers

I thinking is 2400000

If 2 different processes driven by heat transfer start at state 1 and end at state 2 BUT follow different paths, is the amount of energy transferred by heat the same for each path? Yes or no?

Answers

The answer yes I’m not sure

Conduction occurs when thermal energy is transferred by the movement of
a. Waves
b. molecules
c. liquids
d. fluids​

Answers

Answer: Molecules

Explanation:

Answer:

B. molecules

Explanation:

got 100% on the edge quiz

3. Daniel stands on a bridge over a river. He drops a coin and notes that the coin takes 3 s to reach the river below.

He must be standing

above the river.

A 10 m

B. 15 m

C. 30 m

D. 45 m

Answers

Answer:

45 m

Explanation:

Initial velocity of the coin = 0 m/s  (since he dropped it from his hands)

time spent in falling - 3 sec

distance s = ?

using

s = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

where

s is the distance the stone fell

u is the initial velocity

t is the time spent falling

g is acceleration due to gravity = 10 m/s^2 (positive downwards)

substituting values, we have

s = (0 x 3) +  [tex]\frac{1}{2}[/tex](10 x [tex]3^{2}[/tex])

s = 45 m

The _____ optical illusion contains a horizontal line terminating in inward- or outward-pointing arrowheads.

Answers

Answer:

Muller-Lyer optical illusion

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