HELP!!! IM BEING TIMED AND I RLLY NEED HELP

Answer:

Muller-Lyer optical illusion

Answer:

80/2= 40 m/s^2.

Explanation:

A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s.  Its acceleration is 4 m/sec².

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = change in velocity / time

acceleration = 80 / 20

acceleration = 4 m/sec²

A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s.  Its acceleration is 4 m/sec².

To learn more about acceleration refer to the link:

brainly.com/question/12550364

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The above are questions related to the formula of force F = m * a i.e. mass * accleration. It is defined by the Newton's second law of motion.

In the attachment, I can see that Question 1) and Question 2) are already done, So lemme start from Question 3[tex])[/tex]

3) Provided:-

To FinD:-

By using formula,

⇛ F = ma

⇛ 7000 N = 0.5 kg × a

⇛ a = 7000 / 0.5 m/s²

⇛ a = 14000 m/s²

So, the ball acclerates at the rate of 14000 m/s².

4) Provided:-

To FinD:-

By using formula,

⇛ F = ma

⇛ F = 31200 kg × 10 m/s²

⇛ F = 312000 kg/m/s²

⇛ F = 312000 N

So, force on the truck = 312000 N

5) a) Force applied = 100 N

Mass applied = 5 kg

Then, Acceleration = 100 ÷ 5 = 20 m/s²

b) Force applied = 100 N

Mass applied = 10 kg

Then, Acceleration = 100 ÷ 10 = 10 m/s²

c) Force applied = 100 N

Mass applied = 20 kg

Then, Acceleration = 100 ÷ 20 = 5 m/s²

d) Force applied = 100 N

Mass applied = 50 kg

Then, Acceleration = 100 ÷ 5 = 2 m/s²

And we are done !!

#CarryOnLearning

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Answer: The answer are above :(

Answer: Molecules

Explanation:

Answer:

B. molecules

Explanation:

got 100% on the edge quiz

Answer:

True

Explanation:

Charging by conduction occurs when a charged conductor comes in contact with an uncharged conductor, leading to the sharing of charges between both conductors. Contact charging leads to a sharing and distribution of the same type of charges on the two conductors.

In this case, your entire body is charged by the sole of your feet coming in contact with the charged carpet on the floor, leading to a charge buildup all over your body.

Answer:d

Explanation:tsssss

Answer:

area = force by pressure

or, a = 120N by 60000 Pa

or, a= 0.002 m²

Answer:

Explanation:

Displacement is the diatnce moves in a specified direction. It is the shortest distance covered  by the dog. The displacement of the dog can be gotten by using the pythagoras theorem as shown;

According to the theorem, a²+b² = d² where d is the displacement

Substituting the given value into the fofrmula;

3²+4² = d²

9+16 = d²

d² = 25

square root both sides

√d² = √25

d = √25

d = 5 metres

Hence the displacement of the dog is 5metres

Answer:

2.16 meters

Explanation:

We can find distance using the following formula.

[tex]d=s*t[/tex]

where [tex]s[/tex] is the speed and [tex]t[/tex] is the time.

The speed of the watermelon seed is 1.8 meters per second. The time is 1.2 seconds.

[tex]s= 1.8 m/s\\t=1.2 s[/tex]

Substitute the values into the formula.

[tex]d= 1.8 m/s * 1.2 s[/tex]

Multiply. When you multiply the 2 "s" that represent seconds will cancel out.

[tex]d= 1.8 m * 1.2[/tex]

[tex]d=2.16 m[/tex]

The watermelon seed with travel 2.16 meters in 1.2 seconds.

Answer = (100 billion stars/galaxy) x (100 billion galaxies/universe)

Answer = (100 billion x 100 billion) stars

Answer = 10,000 billion billion stars

Answer = 10,000,000,000,000,000,000,000 stars

Answer = 10²² stars/observable universe

The number of stars in the observable universe is; 10²² stars/observable universe.

Since there are about 100 billion stars in our galaxy; we can rewrite that to be;

100 billion stars/galaxy

However, there are about 100 billion galaxies in the observable universe.

Since our galaxy is one of the 10¹¹ observable galaxies in the universe; the number of stars in the observable universe is;

(100 billion stars/galaxy) x (100 billion galaxies/universe)

= (100 billion x 100 billion) stars

= 10,000 billion billion stars

= 10,000,000,000,000,000,000,000 stars

= 10²² stars/observable universe

Therefore, the number of stars in the observable universe is; 10²² stars/observable universe.

Read more the similar concept here;

brainly.com/question/24291110

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Answer:

There are many examples of electrostatic phenomena, from those as simple as the attraction of the plastic wrap to one's hand after it is removed from a package to the apparently spontaneous explosion of grain silos, the damage of electronic components during manufacturing, and photocopier & laser printer operation

Answer:

75

Explanation:

w

X

y

z.86.2,86.7,70.8

Answer:

Thermal and Radiant

Explanation:

Thermal = Heat

Radiant = Light

Answer: B

Explanation:

Answer:

Prokaryotic Cells are cells that lack Cell Nucleus so the answer is bacteria

Answer:

B Bacteria

Explanation:

Choice B because the prokaryotes are single-celled organism with no nucleus.

Answer:

you have to organize the data. a= acceleration vi=inicial velocity vf=final velocity  t=time.

a=80m/s

vi=0

vf=?

t=40 s

the formula you have to use is:

vf=vi+a*t  (final velocity= inicial velocity plus acceleration times time)

Explanation:

I was the best one at my class, hope it helped

Answer: 320 m/s

Explanation:  V initial = 0, V final= ?   Acceleration = 8m/s/s  t=40s

Answer:

45 m

Explanation:

Initial velocity of the coin = 0 m/s  (since he dropped it from his hands)

time spent in falling - 3 sec

distance s = ?

using

s = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

where

s is the distance the stone fell

u is the initial velocity

t is the time spent falling

g is acceleration due to gravity = 10 m/s^2 (positive downwards)

substituting values, we have

s = (0 x 3) +  [tex]\frac{1}{2}[/tex](10 x [tex]3^{2}[/tex])

s = 45 m

Answer:

Acceleration, [tex]a=-2.8\ m/s^2[/tex]

Explanation:

It is given that,

The initial speed of a speed skater, u = 8 m/s

The final speed of a speed skater, v = 6 m/s

Width of patch of rough ice, s = 5 m

We need to find the acceleration on the rough ice. Acceleration can be calculated using third equation of motion as :

[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{(6)^2-(8)^2}{2\times 5}\\\\a=-2.8\ m/s^2[/tex]

So, the acceleration on the rough ice is [tex]2.8\ m/s^2[/tex]. Negative sign shows that its speed is decreased.

Answer:

revised

Explanation:

Answer:

A)   50 kg m/s

B)  2 kg m/s

C)  100 kg m/s

Explanation:

Recall that momentum is a physical quantity defined by the product of the object's mass times its velocity. Therefore, in our case the truck's momentum (p) is:

A)  p = m * v = 10 kg * 5 m/s = 50 kg m/s

B) p = m * v = 10 kg * 0.20 m/s = 2 kg m/s (notice that the velocity in cm/s was converted into m/s before multiplying)

C) the conversion from km/h to m/s is a little more involved, so we taclke it first:

since 1 km = 1000 m  and 1 hour = 3600 seconds, we convert 36 km/h by replacing each unit by its m and s expression as shown below:

[tex]36 \frac{km}{h} =36\,\frac{1000\,m}{3600\,\,s}=10\,\frac{m}{s}[/tex]

Then, the momentum is:  p = m * v = 10 kg * 10 m/s = 100 kg m/s

Answer:

Explanation:

Answer:

Explanation:

velocity is the change in displacement of a body with respect to time. Given the displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t², where t is the time in seconds, instantaneous velocity is expressed by differentiating the displacement with respect to time

Velocity = dd/dt

Velocity = -0.65 + 2(0.21)t²⁻¹

Velocity = -0.65 + 0.42t

The instantaneous velocity of the block when t = 2.0 s can be gotten by substituting t = 2.0s into the expression above:

Velocity = -0.65 + 0.42(2)

Velocity = -0.65 + 0.84

Velocity = 0.19

Hence the instantaneous velocity of the block when t = 2.0 s is 0.19m/s

a,

Explanation:

because when its moved thats the sugar of it

Answer:

b. Chloroplast

Explanation:

Given :

Mass of block , m = 1.35 kg .

Speed constant , k = 15 N/m .

Speed at centre , v = 34 cm/s = 0.34 m/s .

To Find :

The amplitude of oscillation .

Solution :

Now , we know total energy is conserved in SHM .

So , K.E at zero displacement :

[tex]K.E=\dfrac{mv^2}{2}\\\\K.E=\dfrac{1.35\times 0.34^2}{2}\\\\K.E=7.8\times 10^{-2}\ J[/tex]

Now , this K.E is equal to maximum P.E :

[tex]P.E=K.E=7.8\times 10^{-2}\ J[/tex] .

[tex]P.E=\dfrac{kA^2}{2}\\\\7.8\times 10^{-2}=\dfrac{kA^2}{2}\\\\A=\sqrt{\dfrac{2\times 7.8 \times 10^{-2}}{15}}\ m\\\\A=0.1019 \ m\\\\A=10.2\ cm[/tex]

Therefore , the amplitude is 10.2 cm .

Hence , this is the required solution .

Answer:

This whole concept depends on the depends on the direction of propagation of the surface wave or displacement of wave such that if its in direction of wave velocity its said to features of longitudinal wave and if its in direction at 90° to wave velocity its said to have transverse features

Answer:

Explanation:

Using one of the equation of motion expressed as v = u+at where;

v is the final velocity = 2.0m/s

u is the initial velocity = 25m/s

a is the acceleration = -a (since the acceleration is negative)

t is the time taken

Substituting the given parameters into the formula above;

2.0 = 25-9.81t

subtract 25 from both sides

2.0 - 25 = 25-9.81t - 25

-23 = -9.81t

Divide both sides by -9.81

-23/-9.81 = -9.81t/-9.81

t = 23.0/9.81

t = 2.35s

Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s

Answer:

Apparently this has been asked a few years ago, so I copied this answer from deepikakvvk06 - - all credit goes to them!

velocity of car 'B' after collision is 22.5m/s. //it's a conservation of momentum question

Explanation:

Let ,

mass = m

initial velocity = u

final velocity = v

here ,

m₁= 1500 kg

m₂=1000 kg

u₁ = 25 m/s

u₂ = 15 m/s

v₁ = 20 m/s

we have to find v₂ !!

v₂ is the velocity after collision

Here is a formula relating the values given ,

m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂

m₁u₁+m₂u₂ = 1500 × 25 + 1000 ×15

= 37500 + 15000

= 52500

m₁v₁ + m₂+v₂ = 1500 × 20 + 1000 × v₂

= 30000 + 1000v₂

m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂

52500 = 3000 + 1000v₂

1000v₂ = 52500 - 30000

1000 v₂ = 22500

v₂ = 22500/1000

= 22.5 m/s

Thus, velocity of car 'B' after collision is 22.5m/s.