The given expression rewritten in simplified exponential form is [tex]5x^{\frac{3}{2}}[/tex]
Simplifying an expressionFrom the question, we are to rewrite the given expression is simplified exponential form.
The given expression is
[tex]\sqrt{\sqrt{25^{2} x^{6} } }[/tex]
First, we will evaluate the inner square root
[tex]\sqrt{25^{\frac{2}{2} } x^{\frac{6}{2} } }[/tex]
[tex]\sqrt{25 x^{3 } }[/tex]
Simplifying further
[tex]\sqrt{25 } \times \sqrt{x^{3}}[/tex]
[tex]5\times x^{\frac{3}{2}}[/tex]
= [tex]5x^{\frac{3}{2}}[/tex]
Hence, the expression in simplified form is [tex]5 x^{\frac{3}{2}}[/tex]
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n is a negative number.
Which statement is correct?
Choose only one answer.
A n +8 is always positive
B
C
n +8 is always negative
n + 8 cannot be zero
D
n+ 8 could be positive or negative or zero
Required correct statement is n+ 8 could be positive or negative or zero.
What is a negative number?
A negative number is any number less than zero. For example, -8 is a number that is seven less than 0. It may seem odd to say that a number is less than 0. After all, we often think that zero means nothing.
Option A: n + 8 is always positive is not correct since n is negative and adding a positive number (8) to a negative number will give a negative or zero result.
Option B: n + 8 is always negative is not correct since adding a positive number (8) to a negative number will give a negative or zero result, not always negative.
Option C: n + 8 cannot be zero is a wrong statement, if we put value of n = -8 then we will get zero as answer.
Option D: n + 8 could be positive or negative or zero is correct since it depends on the value of n.
If n is a large negative number, n + 8 could still be negative. If n is a small negative number or zero, n + 8 could be positive or zero.
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Correct question is "n is a negative number.
Which statement is correct?
Choose only one answer.
A) n +8 is always positive
B) n +8 is always negative
C) n + 8 cannot be zero
D) n+ 8 could be positive or negative or zero"
the function that models the percent of children taking antidepressants from 2004 to 2009 is f(x)=-0.086x+2.92, where x is the number of years after 2000.
a. find the inverse of this function. what do the outputs of the inverse function represent?
b. use the inverse function to find when the percentage is 2.3%.
The evaluation of the inverse of the function, f(x) = -0.086·x + 2.92 are;
a. The inverse of the function is f⁻¹(x) = -11.63·x + 33.95
B. The inverse function gives the number of year after 2000 when the percentage of children taking antidepressants is equal to x
b. The percentage of children taking antidepressant is 2.3% in 2007
What is the inverse of a function?The inverse of a function is a function that gives the input from the output such that it undoes the function's effect.
The function that indicates the percentage of children taking that take antidepressants from from the year 2004 to the year 2009 is presented as follows;
f(x) = -0.086·x + 2.92
x = The number of years after the year 2000
The inverse of the function can be obtained by making x the subject of the function formula as follows;
f(x) = -0.086·x + 2.92
f(x) - 2.92 = -0.086·x
x = (f(x) - 2.92)/(-0.086) ≈ -11.63·f(x) + 33.95
x ≈ -11.63·f(x) + 33.95
Which through plugging in f⁻¹(x) = x, and f(x) = x,
Indicates;
f⁻¹(x) = -11.63·x + 33.95
In the inverse function, the argument is the percentage, while the output is the number of years, f⁻¹(x)
When x = 2.3,
f⁻¹(2.3) = -11.63×2.3 + 33.95 ≈ 7.2
The inverse when the percentage is 2.3% is 7.2 years
a. The inverse function is f⁻¹(x) = -11.63·x + 33.95
The output of the inverse function represents the number of years since 2000 when the percentage of the children taking antidepressants is x. The correct option is option B
b. The year in which the number of children taking antidepressant equals 2.3% is 2,000 + 7 = 2007
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a car uses 6 gallons of gas every 246 miles it drives. How many miles does it travel on 1 gallon
Answer: 41 miles per gallon
Step-by-step explanation: Divide 256 by 6 and you get 41
A farmer wants to construct a fence around an area of 2400 square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. What dimension should the fenced area have in order to minimize the length of fencing used?
Step-by-step explanation:
The lengths of the sides of the rectangular field should be 40 ft (smaller value) and 60 ft (larger value) respectively.
Let L = length of rectangle area and W = width of rectangle area.
Let the length of the side that divides the area be parallel to the width of the area.
The total length of fencing F = 2L + 2W + W
F = 2L + 3W
Since the area is a rectangle, its area is A = LW
Since the area = 2400 square feet,
LW = 2400 ft²
So, L = 2400/W
Substituting L into F, we have
F = 2L + 3W
F = 2(2400/W) + 3W
F = 4800/W + 3W
To find the value at which F is minimum, we differentiate F with respect to W.
So, dF/dW = d(4800/W + 3W)/dW
dF/dW = -4800/W² + 3
Equating dF/dW to zero, we have
-4800/W² + 3 = 0
-4800/W² = - 3
W² = -4800/-3
W² = 1600
W = √1600
W = 40 ft
To determine if this is a value that gives minimum F, we differentiate F twice to get
d²F/dW² = d(-4800/W² + 3)/dW
d²F/dW² = 14400/W³ + 0
d²F/dW² = 14400/W³
substituting W = 40 into the equation, we have
d²F/dW² = 14400/(40)³
d²F/dW² = 14400/64000
d²F/dW² = 0.225
Since d²F/dW² = 0.225 > 0, W = 40 is a minimum point for F
Since L = 2400/W
So, L = 2400/40
L = 60 ft
So, the lengths of the sides of the rectangular field should be 40 ft (smaller value) and 60 ft (larger value) respectively.
Jason solved the following equation to find the value for x. -8. 5x – 3. 5x = –78 x = 6. 5 describe how jason can check his answer.
Jason can check his answer isolate the variable, solving the operations and substituting the (x) value in the equation.
The clearance rules to solve the problem are the following:
What is adding goes to the other side of the equality by subtracting.What is multiplying goes to the other side of the equality by dividing.The sign rules to solve the problem are the following:
Two like signs add the values and keep the common sign.Two unlike signs subtract the values and use the highest value sign.Solving the equation we have:
-8. 5x – 3. 5x = –78
Two like signs add the values and keep the common sign.
-12x = -78
What is multiplying goes to the other side of the equality by dividing.
x = -78 / -12
x = 6.5
Substituting the (x) value in the equation we can check the answer and we get:
-8. 5x – 3. 5x = –78
-8.5(6.5) - 3.5(6.5) = -78
-55.25 - 22.75 = -78
- 78 = - 78
What is an equation?An equation is the equality between two algebraic expressions, which have at least one unknown or variable.
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if florist B increases the cost per roses to $5.20 for what number of roses is it less expensive to order from florist a? from florist b ?
Answer: florist a is cheaper than florist b
Step-by-step explanation: the price of florist B's flowers are 5.20$ more than florist A's
What's the value of the expression below?
40÷[20−4⋅(7−4)]
Answer:
5
Step-by-step explanation:
Answer:
The answer for the question is five!
helpl i have cookies
Answer:30
Step-by-step explanation:6 times 4 is24 and to the nearest 100 it will be 30
A rectangle is 2 feet 11 inches wide and 1 yard 2 feet 1 inch long. What is the perimeter of the
rectangle in feet?
A 8 feet
B 24 feet
C 16 feet
D 18 feet
The perimeter of the rectangle is 16 feet.
The correct answer is an option (C)
In this question, the length of the rectangle is,
l = 1 yard 2 feet 1 inch
l = 3 feet + 2 feet + 0.0833 feet
l = 5.0833 feet
And the width of the rectangle is,
w = 2 feet 11 inches
w = 2 feet + 0.9167 feet
w = 2.9167 feet
So, the perimeter of the rectangle would be,
P = 2(l + w)
P = 2 * (5.0833 + 2.9167)
P = 16 feet
Therefore, the perimeter of the rectangle is 16 feet.
The correct answer is an option (C)
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A population of beetles grows by 25% every month. If the beetle population starts with 1,600 beetles, which equation represents the population, P, after t months?
The equation which represents the population, P after t months is:
y = 1600(1+ 0.25)^t.
Given,
A population of beetles grows by 25% every month.
the beetle population starts with 1,600 beetles,
we are asked to determine the equation which represents the population, P after t months.
The equation for the population is:
Pf = Pi(1-r)^t
where pf = final value
pi = initial value
r = growth factor
t = time in years.
substitute the values in the equations.
let y represent the final population after t years.
r = 25%
convert percentage to decimal.
r = 0.25
y = 1600(1+ 0.25)^t
Hence we get the required answer.
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a student wanted to know if the bags of potato chips they were buying contained the correct weight of chips compared to the listed weight on the bag of 42.5 grams. the student collected a sample of 30 bags of chips and weighed each bag. the average weight of the bags they collected was 41 grams with a standard deviation of 1.6 grams. assume a 95% level of confidence.
According to the given standard deviation, the bag that the student brought has more than 1 gram of potato chip than the average chip bag.
Standard deviation:
Standard deviation refers the measure of how scattered the data is in relation to the mean.
Given,
The student wanted to know if the bags of potato chips they were buying contained the correct weight of chips compared to the listed weight on the bag of 42.5 grams.
And the student collected a sample of 30 bags of chips and weighed each bag. Here the average weight of the bags they collected was 41 grams with a standard deviation of 1.6 grams. assume a 95% level of confidence.
Now, we have to find the confidence interval for this situation.
From, the given details, we have obtained the following things,
Bag weight = 42.5 gram
Number of samples = 30
Average weight = 41 grams
Standard deviation = 1.6 grams
Confidence level = 95%
So, according to the formula of confidence interval,
The value of it is calculated as,
=> CI = x ± Z × s / √n
When we apply the values on the formula, then we get,
=> CI = 41 ± 1.9600 × 1.6 / √30
=> CI = 41 ± 0.573
Therefore, Confidence Interval 41 ±0.573 (±1.4%) [40.427 – 41.573].
While we compare this one with the given bag weight we get the difference of,
=> 42.5 - 41.5
=> 1
Therefore, the bag that the student brought has more than 1 gram of potato chip than the average chip bag.
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150 pupils in a sports centre are surveyed.
The pupils can only use the swimming pool, the gym and the tennis courts.
30 pupils use the swimming pool, the gym and the tennis courts.
43 pupils use the swimming pool and the gym.
40 pupils use the gym and the tennis courts.
49 pupils use the tennis courts and the swimming pool.
71 pupils use the swimming pool.
78 pupils use the gym.
92 pupils use the tennis courts.
Find the probability to select a pupil that uses the tennis courts only.
The probability that a pupil selected uses the tennis courts only is the fraction 11/50 or 0.22
What is probabilityThe probability of an event occurring is the ratio of the number of required outcome divided by the total number of possible outcomes.
From the question,
The pupils that uses only tennis courts = 92 - (30+19+10) { where 30 is the number of pupils that uses all three, 19 is the number of pupils that uses only swimming pool and 10 is the number of pupils that uses only gym and tennis court}
The pupils that uses only Tennis courts = 92 - 59
The pupils that uses only Tennis courts = 33
The probability of selecting a pupil who uses only the tennis court = 33/150
Therefore by simplification, the probability that only a pupil selected uses only the tennis court is the fraction 11/50
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a delivery driver has an average daily gasoline expense of $55.00. the standard deviation is $10.00. the owner takes a sample of 54 bills. what is the probability the mean of his sample will be between $45.00 and $65.00? enter all answers to the nearest tenth.
The probability the mean of his sample will be between $45.00 and $65.00 is 0.6826.
Given:
A delivery driver has an average daily gasoline expense of $55.00. the standard deviation is $10.00. the owner takes a sample of 54 bills.
n = 54
standard error = 10/[tex]\sqrt{54}[/tex]
= 2.205
when x = 45,
z score = 45 - 55 / 10
= -10/10
= -1
probability at z = -1 is 0.3413
z score for x = 65
z = 65 - 55 / 10
= 10/10
= 1
probability at z = 1 is 0.3413
Total probability = 0.3413+0.3413
= 0.6826
Therefore the probability the mean of his sample will be between $45.00 and $65.00 is 0.6826.
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Write the number as a square. 1c) 5 19/25
Answer:
5 19/25 = (12/5)² or (2 2/5)²Step-by-step explanation:
Given Number 5 19/25Write it as a square5 19/25 = (5*25 + 19) / 25 = 144 / 25 = 12² / 5² = (12/5)²or
(2 2/5)²Answer:
[tex]\left(\dfrac{12}{5}\right)^2=\left(2\frac{2}{5}\right)^2[/tex]
Step-by-step explanation:
Given mixed number:
[tex]5 \frac{19}{25}[/tex]
Rewrite the given mixed number as an improper fraction:
[tex]\implies 5 \frac{19}{25}=\dfrac{5 \times 25+19}{25}=\dfrac{125+19}{25}=\dfrac{144}{25}[/tex]
Rewrite 144 as 12² and 25 as 5²:
[tex]\implies \dfrac{144}{25}=\dfrac{12^2}{5^2}[/tex]
[tex]\textsf{Apply exponent rule} \quad \dfrac{a^c}{b^c}=\left(\dfrac{a}{b}\right)^c:[/tex]
[tex]\implies \dfrac{12^2}{5^2}=\left(\dfrac{12}{5}\right)^2[/tex]
Convert 12/5 to a mixed number:
[tex]\implies \left(\dfrac{12}{5}\right)^2=\left(\dfrac{10+2}{5}\right)^2=\left(\dfrac{10}{5}+\dfrac{2}{5}\right)^2=\left(2\frac{2}{5}\right)^2[/tex]
Raja manages a perfume store. She makes 0,4-ounce samples from a 2.8- ounce bottle of perfume. How many perfume samples cán Raja make?
Raja can make 7 perfume samples from a 2.8 ounce bottle of perfume.
According to the question,
We have the following information:
Raja manages a perfume store. She makes 0.4-ounce samples from a 2.8- ounce bottle of perfume.
So, we have the following expressions:
1 bottle of perfume sample = 0.4 ounce
Total ounces of perfume in the bottle = 2.8 ounce
Now, we can easily find the number of perfume samples that can be made from this perfume by dividing the total ounces of perfume in bottle by the ounces of perfume sample.
Number of perfume samples = 2.8/0.4
Number of perfume samples = 7
Hence, Raja can make 7 perfume samples from a 2.8 ounce bottle of perfume.
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7. passes through (-3,2)
Vertex (-5, -6)
Write the equation in vertex form
y = a(x-h)² + k
The equation in vertex form would be y = [tex]2(x+5)^{2}[/tex] -6
What is vertex of a curve?The vertex of a parabola is the point where the parabola crosses its axis of symmetry. If the coefficient of the x2 term is positive, the vertex will be the lowest point on the graph, the point at the bottom of the “ U ”-shape. If the coefficient of the x2 term is negative, the vertex will be the highest point on the graph, the point at the top of the “ U ”-shape.
The standard equation of a parabola is
y=a[tex]x^{2}[/tex]+bx+c .
But the equation for a parabola can also be written in "vertex form":
y= a(x-h)² +k
if the curve passes through (-3, 2) and the coordinates of vertex h = -5, K= -6, then we can find a by simple substitution
2 = a[tex](-3 + 5)^{2}[/tex] - 6
2 = a([tex]2^{2}[/tex]) - 6
2 = 4a - 6
collecting like terms
4a = 2 + 6
4a = 8
dividing both sides by 4
a = 8/4
a = 2.
So the equation of parabola in vertex form is y = 2[tex](x+5)^{2}[/tex] - 6
In conclusion, the equation of parabola in vertex form is 2[tex](x+5)^{2}[/tex] - 6
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Yesterday, the temperature dropped
27°F in h hours. The temperature
dropped the same number of degrees
each hour. Write an expression that can
be used to find the change in
temperature each hour.
The expression that can be used to find the change in temperature each hour would be 27 h.
How to find the change in temperature each hour?It is given that the temperature dropped 27°F in h hours. The temperature dropped the same number of degrees each hour.
We have to find the change in temperature each hour.
We can express this mathematically:
27 h
Then the equation would be 27 h.
Therefore, The temperature dropped the same number of degrees each hour would be 27 h.
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Exercises 5-22, a parametrization si given for a curve.
(a) Graph the curve. What are the initial and terminal
any? Indicate thedirection ni which the curvesi traced.
(b) Find a Cartesian equation for a curve that contains the parametrized curve. What portionofthe graph of the Cartesian equation istraced by het parametrized curve?
5.x=31, y=917, 0-<1<00 6. x= -Vi, y= 1, 120
7.x= ,1 y= Vi. 120
8 . x = ( s e c ? t ) - , 1 y = t a n t , - ” / 2 < 1 くm / 2
9.x=cost, y=sint, 0515 a
10. x= sin (2nt), y= cos (2mt), 0 ≤ 1≤ ,1
11. x= cos( T- t), y = sin( m- 0). 0 S i s T
12.x=4cost,y=2sint. 0≤1≤27 13. x= 4sint, y= 2cost, 0515 n
parameter interval that traces the c u r v e exactly 1. x= 3sin (21), y= 1.5 cos t
2. x= sni? ,1 y= cos',
3. x= 7sin /- sin (71),
4.x=21sint-3sin(61),
a()
once.
points, fi
)c(
5.12
(a) Va? = a (c) V4a? = a|2|
(b)Va?= at
'y= 7 cos
a) Refer to the attachment for graph:
The ellipse in counter clockwise direction starting from the point (1,0)
b) Cartesian equation for a curve that contains the parametrized curve is
x²+ y/4=1
What are trigonometric expressions?
Trigonometric identities are, by definition, reciprocal. These formulas show the connections between the sine/cosine functions and tangents.
a) Given: x= cost , y= 2 sin t, 0<t≤2π
y= 2 sin t,
sin t= y/2
we know that,
cos²t + sin²t=1
x²+ y/4=1
b) The point (x,y) moves on the ellipse x²+ y/4=1
t increases from 0 to 2π. The point (x,y) moves around the ellipse around the ellipse in counter clockwise direction starting from the point (1,0)
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HELPPP!!!
The park entrance is located at (-3,7). Emily want to know the distance from the entrance to the garden at point (3,-2). What is the distance?
The distance from the entrance which is located at (-3,7) to the garden at points (3,-2) is [tex]3\sqrt{13}[/tex].
First, let us understand the distance formula:
The distance formula is the measurement of the distance between 2 points. It calculates the straight line distance between the given points.
The distance formula is given by:
Distance = [tex]\sqrt{(a-c)^2+(b-d)^2}[/tex]
Where A(a, b) and B(c, d) are the coordinates.
We are given;
The park entrance is located at (-3, 7).
Another point at (3, -2).
We need to find the distance from the entrance to the garden at another given point.
Substitute the given values in the distance formula, we will get;
Distance = [tex]\sqrt{(a-c)^2+(b-d)^2}[/tex]
Distance = [tex]\sqrt{(-3-3)^2+(7-(-2))^2}[/tex]
Distance = [tex]\sqrt{(6)^2+(9)^2}[/tex]
Distance = [tex]\sqrt{36+81}[/tex]
Distance = [tex]\sqrt{117}[/tex]
Distance = [tex]3\sqrt{13}[/tex]
So, the distance between the given points is [tex]3\sqrt{13}[/tex].
Thus, the distance from the entrance which is located at (-3,7) to the garden at points (3,-2) is [tex]3\sqrt{13}[/tex].
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t(n)=120+12n
solve the equation for t(n)=500
Answer: n = 31.66666667
Step-by-step explanation:
Add '-12n' to each side of the equation.
500 + -12n = 120 + 12n + -12n
Combine like terms: 12n + -12n = 0
500 + -12n = 120 + 0
500 + -12n = 120
Add '-500' to each side of the equation.
500 + -500 + -12n = 120 + -500
Combine like terms: 500 + -500 = 0
0 + -12n = 120 + -500
-12n = 120 + -500
Combine like terms: 120 + -500 = -380
-12n = -380
Divide each side by '-12'.
n = 31.66666667
Simplifying
n = 31.66666667
A plant is 14 inches tal. If it grows 3 inches per year, how many years will it take to reach a height of 38 inches?
Finding Angle Measures When Parallel Lines Are Cut By a Transversal
Answer: Answer is below
Step-by-step explanation:
Angles 1 and 5 and 8 are the same.
Angles 2 and 3 and 6 and 7 are the same.
180-138=42 degrees
So the obtuse are 138 and the acute are 42.
Angle 1 is 138 degrees
Angle 2 is 42 degrees
Angle 3 is 42 degrees
Angle 5 is 138 degrees
Angle 7 is 42 degrees
Angle 8 is 138 degrees
Angle 6 is 42 degrees
Hope it helped and have a nice weekend!
Please rate!
Answer:
Angle 4 is 138 and opposite angles are the same! That makes angle 1, 5, and 8 the same as 4 which is 138!
We need to subtract to find the other 4 angles!
180 - 138 = 42 degrees
Angles 2, 3, 6 and 7 will be 42 degrees!
Have an amazing day!!
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the radius of a right circular cone is increasing at a rate of 2 inches per second and its height is decreasing at a rate of 5 inches per second. at what rate is the volume of the cone changing when the radius is 40 inches and the height is 40 inches?
Using the concepts of Application of derivative, we got that 1657.92inches³/sec rate of the volume of the cone changing when the radius is 40 inches and the height is 40 inches for a right circular cone.
We know that volume of right circular cone is given by =(1/3πr²h)
We are given rate of change of radius(dr/dt) and rate of change of the height(dh/dt)
Therefore ,differentiating the volume with respect to time and applying the chain rule.
dV/dt = [(1/3)πr²×(dh/dt)+ (1/3)π·2·r·(dr/dt)·h]
=>dV/dt=[(1/3)× π×r × [(r×dh/dt)+2h×(dr/dt)]]
We are given that dr/dt=2inc/sec and dh/dt= -5inc/sec
So, on putting the values, we get
=>dV/dt=[ ( (1/3)×3.14×40)×[40×(-5)+2×40×2]]
=>dV/dt=[0.33×3.14×40×[-200+160]
=>dV/dt=[0.33×3.14×40×(-40)]
=>dV/dt= -1657.92inches³/sec(negative sign denote volume is decreasing)
Hence, if the radius of a right circular cone is increasing at the rate of 2 inches per second and its height is decreasing at the rate of 5 inches per second. the rate of the volume of the cone changing when the radius is 40 inches and the height is 40 inches is 1657.92inches³/sec.
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I WILL GIVE 30 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS
Answer:
Step-by-step explanation:
Its the last two and the first one
in a data set with 20 variables, if 8% of the values, randomly spread across observations, are missing (blank), what is the probable percent of complete and usable observations?
The probable percentage of complete and usable observation is 18.87%
Probable percentage is probability of a certain event which can be written as percentage
Total number of variables in data set = 20 variables
percentage of randomly spread missing observation in data set = 8%
percentage of non missing observation in data set = 100% - 8%
= 92%
changing percentage into number = 92 / 100
= 0.92
Probable percentage of complete and usable observation =
(0.92)²⁰ × 100
solving the power
0.18869 × 100
= 18.87
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17. Represent and Connect The expression
-120 + 13.4m represents a submarine that
began at a depth of 120 feet below sea level and
ascended at a rate of 13.4 feet per minute. What
was the depth of the submarine after 6 minutes?
Please help me
Solve for y.
2/5(10y-5)-2y + -10
Solve for x.
− 3.28 = −5.34
The solution for y and x in the expressions given as 2/5(10y-5) =2y + -10 and x − 3.28 = −5.34 are y = 6 and x = -2.06, respectively
How to determine the solution to the variable x and y in the expressions?Variable y
From the question, the algebraic expression is given as
2/5(10y-5) =2y + -10
Open the brackets
This gives
4y - 2 = 2y + -10
Collect the like terms in the above equation
So, we have the following representation
4y - 2y = 10 + 2
Evaluate the like terms
2y = 12
Divide by 2
y = 6
Variable x
Here, we have
x − 3.28 = −5.34
There is a constant to add to or subtract from the expression
So, we add 3.28 to both sides
x = 3.28 − 5.34
Evaluate the like terms
x = -2.06
Hence, the solution is x = -2.06
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1
4
1 point
TYPE the expression below using the MathQuill function. (No simplifying or solving needed, just retype!)
2x³+42³-√49
The expression below using the MathQuill function is 2x^3+42^3-\sqrt\left(49\right).
Given expression:
= 2x³+42³-√49
Expression:
An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation. This math operation can be addition, subtraction, multiplication, or division.
After using MathQuill function:
2x³+42³-√49 = 2x^3+42^3-\sqrt\left(49\right).
Therefore The expression below using the MathQuill function is 2x^3+42^3-\sqrt\left(49\right).
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What is m Please help!
Answer:
Step-by-step explanation:
m just means measure. So the question is asking you what is the MEASURE of the ANGLE AEB.
Since angles AEB and CED are vertical angles, you can set the two expressions equal to each other and solve for X.
1) 3x + 54 = 7x - 30
2) 54 = 4x - 30
3) 84 = 4x
4) x = 21
Now that you know x, plug x into the expression for AEB, which is 3x + 54
3(21) + 54 = 117
m∠AEB = 117°
Please solve with explanation (High Points)
The equation of the transformed function is f(x)= -1/3[tex]\sqrt{2(x-6)}[/tex] -3.
Given that,
The f(x) = square root of X base function is transformed by a reflection in the x-axis, a vertical stretch by a factor of 3, a horizontal compression by a factor of 1/2, a vertical translation by a factor of 3, a vertical translation by a factor of 3 down, and then a horizontal translation by a factor of 6 right.
We have to verify the changed function's equation.
Take the function
f(x)=√x
The function reflection in the x-axis,
f(x)=-√x
The function is vertical stretch by a factor of 3.
f(x)= -1/3√x
The function is horizontal compression by a factor of 1/2.
f(x)= -1/3[tex]\sqrt{2x}[/tex]
The function is vertical translation by a factor of 3 down,
f(x)= -1/3[tex]\sqrt{2x}[/tex] -3
The function is horizontal translation by a factor of 6 right.
f(x)= -1/3[tex]\sqrt{2(x-6)}[/tex] -3
Therefore, The equation of the transformed function is f(x)= -1/3[tex]\sqrt{2(x-6)}[/tex] -3.
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