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A graph of the function [tex]f(x) = 2^x[/tex] is shown in the image below.

If f(x) is translated 4 units down, the equation of the new function g(x) is [tex]g(x) = 2^x-4[/tex]

The transformed function g(x) is shown on the same grid below.

In Mathematics and Geometry, the vertical translation a geometric figure or graph downward simply means subtracting a digit from the value on the y-coordinate of the pre-image or function.

In Mathematics and Geometry, a horizontal translation to the right is modeled by this mathematical equation g(x) = f(x - N) while a vertical translation to the positive y-direction (downward) is modeled by this mathematical equation g(x) = f(x) - N.

Where:

In this scenario, we can logically deduce that the graph of the parent function f(x) was translated or shifted downward (vertically) by 4 units as shown below.

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p is a prime number

p^2 divides ab with gcd(a, b) = 1,

then p^2 divides a or p^2 divides b.

1. Since gcd(a, b) = 1, we know that a and b are coprime, meaning they have no common factors other than 1.

2. Given that p is a prime number and p^2 divides ab, this implies that p divides either a or b (or both) due to the Fundamental Theorem of Arithmetic.

3. Let's assume p divides a. Then, we can write a = pk for some integer k.

4. Now, we know that p^2 divides ab, which means ab = p^2m for some integer m.

Substitute a with pk from step 3: ab = (pk)b.

5. Thus, p^2m = pkb. Since p is a prime number, by Euclid's Lemma, we know that p must divide either kb or b itself. We already assumed p divides a, so p cannot divide b (as gcd(a, b) = 1). Therefore, p must divide kb.

6. As p divides a (a = pk) and p divides kb, we can conclude that p^2 divides a. So, p^2 divides a.

7. If we instead assumed p divides b, we would arrive at a similar conclusion: p^2 divides b.

In summary, if p is a prime number and p^2 divides ab with gcd(a, b) = 1, then either p^2 divides a or p^2 divides b.

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The given points (1,1,1), (1,2,3), and (2,1,3) do not lie on a plane that is parallel or perpendicular to any given plane, since they do not satisfy the necessary conditions for either case.

To determine whether the given points lie on a plane that is parallel or perpendicular to any given plane, we need to find the normal vector of the plane containing the given points.

Let the given points be A(1,1,1), B(1,2,3), and C(2,1,3). To find the normal vector of the plane containing these points, we can take the cross product of the vectors AB and AC:

AB = <1-1, 2-1, 3-1> = <0, 1, 2>

AC = <2-1, 1-1, 3-1> = <1, 0, 2>

Normal vector N = AB x AC

= <0, 1, 2> x <1, 0, 2>

= <-2, -2, 1>

Now, to determine if the plane containing the points is parallel or perpendicular to a given plane, we need to compare the normal vector of the plane to the normal vector of the given plane. However, we are not given a plane to compare to.

Therefore, we cannot determine whether the given points lie on a plane that is parallel or perpendicular to any given plane.

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Answer:

Step-by-step explanation:

The sets of natural numbers {1, 2, 3, 4, ...} and even numbers {2, 4, 6, 8, ...} have the same cardinality because there exists a bijective function between the two sets. A bijective function is a one-to-one correspondence that pairs each element in one set with exactly one element in the other set. In this case, the function f(n) = 2n pairs each natural number n with an even number 2n, ensuring that the two sets have the same cardinality.

The two sets, the set of natural numbers {1,2,3,4,...} and the set of even numbers {2, 4, 6, 8, . . .}, have the same cardinality because we can create a one-to-one correspondence between the two sets. To do this, we can simply map each natural number to its corresponding even number (i.e., 1 maps to 2, 2 maps to 4, 3 maps to 6, and so on). This mapping covers all elements of both sets, without skipping any, and without duplicating any. Thus, the two sets have the same number of elements, which means they have the same cardinality.

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Answer: 1/3

Step-by-step explanation:

First think of what is the GCF (greatest common factor of 6 and 18) the answer is 6. because the factors of 6 are 1,2,3,6. the factors of 18 are 1,2,3,6,9,18. they both share 1,2,3, and 6. so those are common. but GCF is asking for the greatest one, so 6 is the GCF.

Divide the top and bottom by 6:

[tex]\frac{6}{18} / 6 = \frac{1}{3}[/tex]

Numerator: 6/6 = 1

Denominator: 18/6 = 3

So the final answer is 1/3

The middle value between 26.27 and 26.89 is 26.58.

To find the middle value between 26.27 and 26.89, you can follow these steps:

1. Add the two numbers together: 26.27 + 26.89 = 53.16
2. Divide the sum by 2 to find the average: 53.16 ÷ 2 = 26.58

The middle value between 26.27 and 26.89 is 26.58.

The middle value of a set of numbers is commonly referred to as the "median". The median is a statistical measure of central tendency that represents the value that separates the lower and upper halves of a dataset.

To find the median of a set of numbers, the numbers must first be arranged in order from lowest to highest (or highest to lowest). If the dataset contains an odd number of values, the median is the middle value.

For example, if we have the set of numbers {1, 3, 5, 7, 9}, the median is 5, which is the value that separates the lower half {1, 3} from the upper half {7, 9}.

If the dataset contains an even number of values, the median is the average of the two middle values. For example, if we have the set of numbers {2, 4, 6, 8}, the median is (4 + 6) / 2 = 5, which is the average of the two middle values that separate the lower half {2, 4} from the upper half {6, 8}.

The median is a useful measure of central tendency because it is not affected by extreme values or outliers in the dataset, unlike the mean, which can be skewed by such values.

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A. There are 37 terms in the sum.

B. The sum of the given series is 7,696.

A. Using arithmetic sequences, We can observe that each term in the sum is obtained by adding 11 to the previous term. Therefore, the nth term can be expressed as:

[tex]a_n = 10 + 11(n-1)[/tex]

We want to find the number of terms in the sum up to [tex]a_n[/tex] = 406. Setting [tex]a_n[/tex]= 406 and solving for n, we get:

406 = 10 + 11(n-1)

396 = 11(n-1)

n = 37

Therefore, there are 37 terms in the sum.

B. We can use the formula for the sum of an arithmetic series:

[tex]S_n = n/2 * (a_1 + a_n)[/tex]

where [tex]S_n[/tex] is the sum of the first n terms, [tex]a_1[/tex] is the first term, and[tex]a_n[/tex] is the nth term.

In this case, we have:

[tex]a_1[/tex]= 10

[tex]a_n[/tex]= 406

n = 37

Substituting these values, we get:

[tex]S_{37}[/tex] = 37/2 * (10 + 406)

[tex]S_{37}[/tex] = 18.5 * 416

[tex]S_{37}[/tex] = 7,696

Therefore, the sum of the given series is 7,696.

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The solution of the expression after evaluation is 24.

The solution of the expression is calculated by simplifying the expression as follows;

The given expression; [ 28 - (-18)]/2  - [15-(-2)(-6)/-3]

The expression is simplified as follows;

[ 28 - (-18)]/2 = (28 + 18)/2 = (46/2) = 23

[15-(-2)(-6)/-3] = (15 - 12)/(-3) = (3)/(-3) = -1

The final solution of the expression is calculated as follows;

[ 28 - (-18)]/2  - [15-(-2)(-6)/-3] = 23 - (-1)

= 23 + 1

= 24

Thus, the final solution of the expression is determined by applying the rule of BODMAS.

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The area of the surface obtained by rotating the given curve about the x-axis is approximately 1182.45 square units.

The given curve is y = √(6x) where x ranges from 0 to 7. To obtain the surface of revolution when this curve is rotated about the x-axis, we can use the formula:

A = 2π ∫[a,b] y * ds

where a = 0, b = 7, y = √(6x), and ds = √(1 + [tex]y'^2[/tex]) dx.

To find y', we differentiate y with respect to x:

[tex]y' = d/dx (\sqrt(6x)) = (1/2) * (6x)^{(-1/2)} * 6 = 3/ \sqrt(6x) = \sqrt(2x)/2[/tex]

Substituting the given values, we have:

A = 2π ∫[0,7] [tex]\sqrt(6x) * \sqrt(1 + (\sqrt(2x)/2)^2) dx[/tex]

Simplifying the expression inside the integral:

[tex]1 + (\sqrt(2x)/2)^2 = 1 + 2x/4 = 1 + x/2[/tex]

√(6x) * √(1 + x/2) = √(3x(2 + x))

Substituting this expression and integrating, we get:

A = 2π ∫[0,7] √(3x(2 + x)) dx

[tex]= 2\pi * (12/5) * (77^{(5/2)} - 27^{(5/2)})[/tex]

≈ 1182.45

Therefore, the area of the surface obtained by rotating the given curve about the x-axis is approximately 1182.45 square units.

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The total number of ways to partition the set of n+1 distinct objects into k nonempty subsets is {n+1,k} = k{n,k} + {n,k-1}, as required.

To show that {n+1,k}=k{n,k}+{n,k-1}, we can use a combinatorial argument.

Consider a set of n+1 distinct objects. We want to partition this set into k nonempty subsets. We can do this in two ways

Choose one of the n+1 objects to be the "special" object. Then partition the remaining n objects into k-1 nonempty subsets. This can be done in {n,k-1} ways.

Partition the n+1 objects into k nonempty subsets, and then choose one of the subsets to be the subset that contains the special object. There are k ways to choose the subset that contains the special object, and once we have chosen it, we need to partition the remaining n objects into k-1 nonempty subsets. This can be done in {n,k-1} ways.

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The normal vector to the tangent plane is the opposite of this gradient, which is:

[tex]n = (-14e^{64}, 4, -1)[/tex]

The gradient of the surface is given by:

∇z = ( ∂z/∂x, ∂z/∂y, ∂z/∂z )

where ∂z/∂x and ∂z/∂y are the partial derivatives of z with respect to x and y, respectively.

The gradient of the surface at that point must first be determined before we can determine the normal vector to the tangent plane of the surface [tex]z=7e^{x^{2} } -4y[/tex] at the point (8, 16, 7).

Taking the partial derivatives, we get:

[tex]∂z/∂x = 14e^{x^{2} }[/tex]

∂z/∂y = -4

Plugging in the values x=8 and y=16, we get:

∂z/∂x = [tex]14e^{(8)^2} = 14e^{64}[/tex]

∂z/∂y = -4

Therefore, the gradient of the surface at the point (8, 16, 7) is:

∇z = ( [tex]14e^{64}, -4,[/tex]∂z/∂z )

The last component of the gradient (∂z/∂z) is always equal to 1, so we have:

∇z = ( [tex]14e^{64},[/tex] -4, 1 )

This gradient is perpendicular to the tangent plane of the surface at the point (8, 16, 7). Therefore, the normal vector to the tangent plane is the opposite of this gradient, which is:

n =[tex](-14e^{64}, 4, -1)[/tex]

The component of the normal vector in the z-direction is -1, as given in the problem statement.

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The graph is given in the image below:

To plot a full cycle of y = 7sin(6x), begin by dividing the period (2π) by six to obtain π/3, which is then used to mark every increment of π/6 along the x-axis.

Additionally, since y ranges from -7 to 7, label the y-axis in increments of either 1 or 2.

Plot the key points at (0,0), (π/12,7), (π/6,0), (π/4,-7), and (π/3,0), and finally connect them smoothly with a curve to complete the plot of one full cycle.

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The magnitude of the magnetic force experienced by the proton is sqrt(64t^2 + 36) N.

To find the magnitude of the magnetic force experienced by a proton moving in a magnetic field, we need to use the formula:

F = q(v x B)

where F is the magnetic force, q is the charge of the particle, v is its velocity and B is the magnetic field.

In this case, the proton has a charge of +1.602 x 10^-19 C, and its velocity is given by:

v = 6î - 4ĵ m/s

The magnetic field is given by:

B = î + 2ĵ - t

To calculate the cross product of v and B, we need to expand the determinant:

v x B =

| î ĵ k |

| 6 -4 0 |

| 1 2 -t |

= (-8t) î - 6k

where k is the unit vector in the z-direction.

So, the magnetic force experienced by the proton is:

F = q(v x B) = (1.602 x 10^-19 C)(-8t î - 6k)

To find the magnitude of this force, we need to take the magnitude of the vector (-8t î - 6k):

|F| = sqrt((-8t)^2 + (-6)^2) = sqrt(64t^2 + 36)

Therefore, the magnitude of the magnetic force experienced by the proton is sqrt(64t^2 + 36) N.

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Answer:

(the length of leg)^2=87^2-60^2=3969

so when take the root :

the length of leg=63ft

Answer:

A' = (-4, 4)

B' = (0, 0)

C' = (2, 5)

Step-by-step explanation:

When a point is reflected across the line y = -x, the x-coordinate becomes -y, and the y-coordinate becomes -x. Therefore, the mapping rule is:

Given vertices of triangle ABC:

Therefore, if we reflect the given points across the line y = -x, the coordinates of the reflected points are:

[tex]\begin{aligned}& \sf A = (-4, 4)& \implies\;\; \sf A'& =\sf (-4,-(-4))=(-4,4)\\& \sf B = (0, 0) &\implies\;\; \sf B' &= \sf (-0, -0)=(0,0)\\& \sf C = (-5, -2)& \implies\;\; \sf C' &= \sf (-(-2),-(-5))=(2,5)\end{aligned}[/tex]

The correct option is b. 118.5. The between-group mean square, that is, value in Cell (4) is 118.5.

To find the between-group mean square (value in Cell 4), you need to divide the between-group sum of squares by its degrees of freedom. In this case, the between-group sum of squares is 237 and the degrees of freedom is 2 (since there are 3 treatment groups - 1).

Here's the calculation:

Between-group mean square (Cell 4)

= Between-group sum of squares / Degrees of freedom
= 237 / 2
= 118.5

So the between-group mean square, or value in Cell 4, is b. 118.5.

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The absolute maximum and minimum of the function [tex]f(x) = (x - 3)(x - 15)^3 + 12[/tex] on the given intervals: (A) (0, 10): max = 11337, min = -1155, (B) [4, 16): max = 33792, min = -20099, and (C) [10, 17): max = 12, min = -11037.

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The function f (x) = 2x^(3/2) + (4/3)x^(5/2) + (17/3)

To find the function f(x), given that f'(x) = √x(3+10x) and f(1) = 9, follow these steps:

1. Integrate f'(x) with respect to x to find f(x).
∫(√x(3+10x)) dx

2. Perform a substitution to make the integration easier. Let u = x, then du = dx.
∫(u^(1/2)(3+10u)) du

3. Now, distribute the u^(1/2) term and integrate term by term:
∫(3u^(1/2) + 10u^(3/2)) du

4. Integrate each term:
[2u^(3/2) + (4/3)u^(5/2)] + C

5. Replace u with x:
f(x) = [2x^(3/2) + (4/3)x^(5/2)] + C

6. Use the given point f(1) = 9 to find the value of the constant C:
9 = [2(1)^(3/2) + (4/3)(1)^(5/2)] + C
9 = 2 + (4/3) + C
C = 9 - 2 - (4/3)
C = 7 - (4/3)
C = (17/3)

7. Plug the value of C back into f(x):
f(x) = [2x^(3/2) + (4/3)x^(5/2)] + (17/3)

So, the function f(x) is given by:
f(x) = 2x^(3/2) + (4/3)x^(5/2) + (17/3)

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a) The ratio of the photography students to the chess students is 2 : 1

b) The ratio of photography students to all students is 1 : 4

c) The ratio of chess students to all students is 1 : 8

Given data ,

Let the number of cooking students = 9

Let the number of chess students = 4

Let the number of photography students be = 8

Let the number of robotics students = 11

So , the total number of students = 32

a)

The ratio of the photography students to the chess students = 8 / 4

On simplifying the proportion , we get

The ratio of the photography students to the chess students = 2 : 1

b)

The ratio of photography students to all students = 8 / 32

The ratio of photography students to all students = 1 : 4

c)

The ratio of chess students to all students = 4 / 32

The ratio of chess students to all students = 1 : 8

Hence , the proportion is solved

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The complete question is attached below :

The table shows the number of students who signed up for different after school activities. Each student signed up for exactly one activity.

The period of the function represent the given context is (8.5, 2900).

The period of this function is 8.5 seconds, and it represents the time it takes for the person's lungs to fill up with air, then empty out again.

The graph shows that the volume of air in the person's lungs is at its maximum (2900 ml) at the start of each period, and then decreases over time until it reaches its minimum (1100 ml) at the end of each period.

Therefore, the period of the function represent the given context is (8.5, 2900).

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The null hypothesis (H0) for this probability would be that there is no effect of taking the vitamin on the chances of getting high blood pressure.

The alternative hypothesis (Ha) would be that taking the vitamin reduces the chances of getting high blood pressure.

Therefore, the hypotheses for this claim can be written as:

H0: The proportion of Americans with hypertension who take the vitamin is the same as the proportion of Americans with hypertension who do not take the vitamin.

Ha: The proportion of Americans with hypertension who take the vitamin is lower than the proportion of Americans with hypertension who do not take the vitamin.

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The implied null hypothesis when testing the hypothesized equality of two population means is h0: µ1 − µ2 = 0.

The null hypothesis (h0) is a statement that assumes there is no significant difference or relationship between variables being compared. In the context of testing the hypothesized equality of two population means, the null hypothesis states that the difference between the means of the two populations (µ1 and µ2) is equal to zero (µ1 − µ2 = 0). This implies that there is no significant difference in the means of the two populations being compared.

To test this null hypothesis, a statistical test, such as a t-test or a z-test, is typically used. The test statistic is calculated based on the sample data, and the resulting p-value is compared to a predetermined significance level (e.g., α = 0.05) to determine if there is enough evidence to reject or fail to reject the null hypothesis.

If the p-value is greater than the significance level, then there is not enough evidence to reject the null hypothesis, and it is concluded that there is no significant difference in the means of the two populations. On the other hand, if the p-value is less than the significance level, then there is enough evidence to reject the null hypothesis, and it is concluded that there is a significant difference in the means of the two populations.

Therefore, the implied null hypothesis when testing the hypothesized equality of two population means is h0: µ1 − µ2 = 0.

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To calculate the constrained minimum, we need to use the method of Lagrange multipliers. We define the Lagrangian function L as L(x,y,λ) = xy^2 - λ(d^2 - x^2 - y^2 - z^2), where d represents the distance between the origin and the nearest point on the curve.

Taking the partial derivatives of L with respect to x, y, and λ, we get:

dL/dx = y^2 + 2λx = 0
dL/dy = 2xy - 2λy = 0
dL/dλ = d^2 - x^2 - y^2 - z^2 = 0

Solving these equations simultaneously, we get:

x = ± 3√6, y = ± √6, and λ = 3/2

Therefore, the points on the curve xy^2 = 54 nearest to the origin are:

(3√6, √6) and (-3√6, -√6)

These points are the constrained minimum because they are the closest points on the curve to the origin.
To find the constrained minimum and the points on the curve xy^2 = 54 nearest to the origin, we can use the method of Lagrange multipliers. Let f(x, y) = x^2 + y^2 be the distance squared from the origin, and g(x, y) = xy^2 - 54 as the constraint.

First, calculate the gradients:
∇f(x, y) = (2x, 2y)
∇g(x, y) = (y^2, 2xy)

Now, set ∇f(x, y) = λ ∇g(x, y):
(2x, 2y) = λ(y^2, 2xy)

This gives us two equations:
1) 2x = λy^2
2) 2y = λ2xy

From equation (2), we can get:
λ = 1/y

Now, substitute λ into equation (1):
2x = (1/y)y^2
2x = y

Using the constraint equation g(x, y) = xy^2 - 54 = 0, we can substitute y = 2x:
2x(2x)^2 = 54
8x^3 = 54
x^3 = 27/4
x = ∛(27/4) = 3/√4 = 3/2

Now we can find y using y = 2x:
y = 2(3/2) = 3

Thus, the point nearest to the origin on the curve xy^2 = 54 is (3/2, 3).

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The points that lie on the line can be described by the vector (-1 + 2t, -1, -1 + 4t), where t is an element of the reals.

To describe the points that lie on the line passing through points A(-1, -1, -1) and B(1, -1, 3), we can use vector notation and parameter t. First, we need to find the direction vector of the line, which is the difference between the position vectors of A and B:

Direction vector = B - A = (1 - (-1), -1 - (-1), 3 - (-1)) = (2, 0, 4)

Now, let's use the position vector of point A and the direction vector to define the line in vector notation:

Line = A + t(Direction vector) = (-1, -1, -1) + t(2, 0, 4)

In component form:

x = -1 + 2t
y = -1
z = -1 + 4t

The points that lie on the line can be described by the vector (-1 + 2t, -1, -1 + 4t), where t is an element of the reals.

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The points that lie on the line can be described by the vector (-1 + 2t, -1, -1 + 4t), where t is an element of the reals.

To describe the points that lie on the line passing through points A(-1, -1, -1) and B(1, -1, 3), we can use vector notation and parameter t. First, we need to find the direction vector of the line, which is the difference between the position vectors of A and B:

Direction vector = B - A = (1 - (-1), -1 - (-1), 3 - (-1)) = (2, 0, 4)

Now, let's use the position vector of point A and the direction vector to define the line in vector notation:

Line = A + t(Direction vector) = (-1, -1, -1) + t(2, 0, 4)

In component form:

x = -1 + 2t
y = -1
z = -1 + 4t

The points that lie on the line can be described by the vector (-1 + 2t, -1, -1 + 4t), where t is an element of the reals.

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The critical values of the confidence intervals t are:

a) t* ≈ 1.711 (for a 90% confidence interval with df = 25)

b) t* ≈ 2.678 (for a 99% confidence interval with df = 52)

Given data,

To find the critical values of t for the given confidence intervals, we need to use a t-distribution table or a statistical calculator. The critical value of t depends on the desired confidence level and the degrees of freedom (df).

a) For a 90% confidence interval with df = 25:

Using a t-distribution table , we find the critical value of t for a 90% confidence level with df = 25 is approximately 1.711.

b) For a 99% confidence interval with df = 52:

Using a t-distribution table , we find the critical value of t for a 99% confidence level with df = 52 is approximately 2.678.

Hence , the confidence intervals are solved.

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This interpretation shows that the argument is invalid.

We are given that;

Predicate Logic Semantics =195

Now,

Under this interpretation, the first premise (∃x)(Ax ⋅ Bx) is true, because there exists a number that is both even and a multiple of 3, such as 6.

The second premise (∃x)(Bx ⋅ Cx) is also true, because there exists a number that is both a multiple of 3 and a multiple of 5, such as 15.

However, the conclusion (∃x)(Ax ⋅ Cx) is false, because there does not exist a number that is both even and a multiple of 5. Any such number would be a multiple of 10, but 10 is not in the domain.

Therefore, by the interpretation answer will be invalid.

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Answer: Macy will travel a distance of 226.20 feet if she swims around the pool 4 times.

Step-by-step explanation:

C = πd, where d is the diameter of the circle

C = πd = π(18 feet) = 56.55 feet (rounded to two decimal places)

If Macy swims around the pool 4 times, she will travel a total distance of:

4 × C = 4 × 56.55 feet = 226.20 feet (rounded to two decimal places)

Answer:

She traveled approximately 226.08 feet.

Step-by-step explanation:

c = 2[tex]\pi r[/tex]  Since she swims the pool 4 times, we will multiply this by 4

c = 4(2)[tex]\pi r[/tex]

c = 8(3.14)(9)  If the diameter is 18, then the radius is 9.  I used 3.14 for [tex]\pi[/tex]

c = 226.08

Helping in the name of Jesus.

The Euclidean distance between the two points (5,8,-2) and (-4,5,3) is approximately 10.72 (rounded to two decimal places).

Explanation: -

To calculate the Euclidean distance between two points (5,8,-2) and (-4,5,3), you can use the following formula:

Euclidean Distance = √((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

Here, (x1, y1, z1) = (5, 8, -2) and (x2, y2, z2) = (-4, 5, 3). Now, plug in the values:

Step 1. Calculate the differences between the co-ordinates;
  (x2 - x1) = (-4 - 5) = -9
  (y2 - y1) = (5 - 8) = -3
  (z2 - z1) = (3 - (-2)) = 5

Step 2. Square the differences:
  (-9)^2 = 81
  (-3)^2 = 9
  (5)^2 = 25

Step 3. Add the squared differences:
  81 + 9 + 25 = 115

Step 4. Take the square root:
  √115 ≈ 10.72

So, the Euclidean distance between the two points is approximately 10.72 (rounded to two decimal places).

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Answer:

x = -2 + sqrt(4 + 77c*m^2) cm.

Step-by-step explanation:

Let's denote the side of the square by "x".

When the strip of width 4 cm is attached to one side of the square, the resulting rectangle has dimensions of (x+4) cm by x cm.

The area of the rectangle is given by:

(x+4) * x = 77c * m^2

Expanding the left-hand side and simplifying, we get:

x^2 + 4x = 77c * m^2

Moving all the terms to one side, we get:

x^2 + 4x - 77c * m^2 = 0

Now we can use the quadratic formula to solve for x:

x = [-4 ± sqrt(4^2 - 41(-77cm^2))] / (21)

x = [-4 ± sqrt(16 + 308cm^2)] / 2

x = [-4 ± 2sqrt(4 + 77cm^2)] / 2

x = -2 ± sqrt(4 + 77c*m^2)

Since the length of a side of a square must be positive, we can discard the negative solution and get:

x = -2 + sqrt(4 + 77c*m^2)

Therefore, the length of the side of the square is x = -2 + sqrt(4 + 77c*m^2) cm.

The length of the side of the square is x = -2 + 2√(1 + 19c) cm.

The area of Rectangle is length times of width.

Let the side of the square be x cm.

When a strip of width 4 cm is attached to one side of the square, the resulting rectangle will have dimensions (x + 4) cm and x cm.

The area of the rectangle is given as 77c m² so we have:

(x + 4)x = 77c

Expanding the left side, we get:

x² + 4x = 77c

Bringing all the terms to one side, we have:

x² + 4x - 77c = 0

Now, we can use the quadratic formula to solve for x:

x = [-4 ± √(4² - 4(1)(-77c))] / 2(1)

x = [-4 ± √(16 + 308c)] / 2

x = [-4 ± √(16(1 + 19c))] / 2

x = [-4 ± 4√(1 + 19c)] / 2

x = -2 ± 2√(1 + 19c)

Since x must be positive, we take the positive root:

x = -2 + 2√(1 + 19c)

Therefore, the length of the side of the square is x = -2 + 2√(1 + 19c) cm.

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