Answers
Answer:
u can write ur answer and submit it
its a test
Related Questions
2.9030 has 4 significant digits.
TRUE OR FALSE
Answers
What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock ? The actual bounce takes 0.025 seconds
Answers
Answer:
[tex]a=100\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = -2 m/s
Final velocity, v = =.5 m/s
Time, t = 0.025 s
We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.5-(-2)}{0.025}\\\\a=100\ m/s^2[/tex]
So, the acceleration of the jet is [tex]100\ m/s^2[/tex].
answer
prove that p = d g h
Answers
Answer:
Proving LHS=RHS
Explanation:
Given
p=dgh
Multiplying by 0 on both sides of the equations
p×0=dgh×0
0=0
:- Hence proved
1)
You travel east at 50 km/hr and then north at 75 km/hr. What is your Resultant Velocity in km/h?
(Remember the angle) (5pts)
Answers
Answer:
15
Explanation:
15)
The Celsius temperature equal to 86° Fahrenheit is:
T(F) = 9/5T(C) + 32
T(C) = 5/9 ( T(F) - 32)
A)
16°C
B)
30°C
C)
212°C
D)
190°C
Answers
Answer:
letter b
Explanation:
30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest
What is the acceleration along the ground of a 18 kg wagon when it is pulled with a force of 91 N at an angle of 35° Above the horizontal?
Answers
Answer:
4.1 m/s²
Explanation:
Net force in the x direction equals the mass times the acceleration.
∑F = ma
91 cos 35° = (18 kg) a
a = 4.1 m/s²
Answer:
Explanation:
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The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2. 4 6 8 10 Column 2 5 10 15 20 25 30 O Column 1 should be titled "Time," and Column 2 should be titled "Velocity." O Column 1 should be titled "Velocity," and Column 2 should be titled "Time." O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."
Answers
Answer:
Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”
Explanation:
Are these bones axial, appendicular
or both?
Answers
Answer:
Axial and Appendicular Skeletons The axial skeleton forms the central axis of the body and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton consists of the pectoral and pelvic girdles, the limb bones, and the bones of the hands and feet. Figure 6.41.
Explanation:
A proposed space station includes living quarters in a circular ring 58.0 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth
Answers
Answer:
The angular speed [tex]w = 0.5813 \ rad/s[/tex]
Explanation:
From the question we are told that
The diameter is d = 58.0 m
Generally for the occupants feel that they have the same weight as they do on Earth then the centripetal acceleration of the circular ring must be equal to the acceleration due to gravity this can be mathematically represented as
[tex]a_c = g[/tex]
Here [tex]a_c[/tex] is the centripetal acceleration which is mathematically represented as
[tex]a_c = w^2 * r[/tex]
Here r is the radius of the circular ring
=> [tex]w^2 * r = g[/tex]
=> [tex]w = \sqrt{\frac{g}{r} }[/tex]
=> [tex]w = \sqrt{\frac{9.8}{ \frac{d}{2} } }[/tex]
=> [tex]w = \sqrt{\frac{9.8}{ \frac{58.0 }{2} } }[/tex]
=> [tex]w = 0.5813 \ rad/s[/tex]
Question 7
(01.01 MC)
What is the difference between a hypothesis and a theory?
Answers
Which statement is true of the electric field at a distance from the source charge?
A it is independent of the source charge
B It is directly proportional to the source charge
C it is inversely proportional to the source charge
D it is directly proportional to the distance
Answers
Answer:
It is directly proportional to the source charge.
Explanation:
I found it pretty sure it's right hit me up on my insta
desiignerjoe173
1) Which of the following is considered an effective treatment for someone with hearing loss based on nerve damage?
TAD
Cochlear implant
Hearing aid
OBI
No treatment available
2) Sylvester is dealing with hearing loss. The doctor informs him that his basilar membrane is damaged. What type of hearing loss is Sylvester experiencing?
Nerve deafness
Conduction hearing loss
Cochlear hearing loss
Conduction deafness
Sensory hearing loss
Answers
Answer:
For number 1 no treatment available , number 2 cochlear hearing loss
Explanation:
nerve damage is permanent
PLZ HELP!!!!!!! ILL GIVE U BRAINLIEST
Answers
Answer:
Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)
Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.
Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)
Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.
Answer:
Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)
Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.
Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)
Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.
When light waves hit ice, most of them bounce off and radiate back into space. Because of this, ice is best described as which kind of surface?
Answers
Answer:
Reflective surface
Explanation:
Ice is a reflective surface because most the of the light waves that hits on it bounces off.
When a surface is smooth and polish, it acts a reflector. When a surface is jagged and not smooth light does not readily reflect. Reflection is through the incident angle of the light waves.Therefore, snow is a reflective surface.
Please help me if you know physics
Answers
Answer:
19. down
20. True
Explanation:
The examples I saw were projectiles launched at different angles and speeds. In each case, the only acceleration was ...
19: down
20: due to gravity (true)
Which of the following is not a part of the appendicular skeleton
a. femur
b. scapula
c.phalanges
d.hyoid
Answers
Answer:
Hyoid
Explanation:
The hyoid is located in the neck area, not the limbs.
A microwave oven operates at 2.00 GHz . What is the wavelength of the radiation produced by this appliance?
Answers
Answer:
Wavelength = 0.15 m
Explanation:
The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].
We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
Where,
[tex]\lambda[/tex] is the wavelength
So,
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]
So, the wavelength of the radiation produced by this appliance is 0.15 m.
are there really dead stars in the sky?
Answers
Answer:
Yes
Explanation:
The star would have died over thousands of years ago but the light takes a long time for it to reach us on Earth.
Greg paid $3.60 for a package of 8 nails at the home store. John paid $3.18 for a package of 6 nails at the hardware store. How much more did John pay per nail than Greg?
(PLS HELP ( . *)^( . *)
Answers
Answer:
8 cents extra.
Explanation:
First find out how much one nail is for each of them. So, divide.
3.60 divided by 8 is 0.45.
3.18 divided by 6 is 0.53.
Subtract 0.45 from 0.53 and voila you have 0.08.
Answer:
5
Explanation:
76789967
Question 5 of 10
Two hockey pucks, each with a mass of 0.15 kg, slide across the ice and
collide. Before the collision, puck 1 is moving 14 m/s to the west and puck 2
is moving 10 m/s to the east. After the collision, puck 1 is moving at 10 m/s
to the east. What is the velocity of puck 2?
A. 14 m/s east
B. 10 m/s west
C. 10 m/s east
D. 14 m/s west
Answers
Answer: D. 14 m/s west
Explanation:
I just did it on A p e x
In a car's suspension system, each wheel is connected to a vertical spring; these springs absorb shocks when the car travels on bumpy roads. In one car, each spring has a spring constant of 4.6 × 10⁴ N/m.
If this 1300 kg car is driven at 23 m/s through the bottom of a circular dip in the road that has a radius of 600 m, by how much do these springs compress compared to when the car is driven on a flat road?
Answers
Answer:
6.23 mm
Explanation:
The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...
a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²
Then the force on the car (in addition to that required to counter gravity) is ...
F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N
The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...
((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm
The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.
_____
We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).
Answer:
Explanation:
Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,
its centrifugal acceleration = speed^2 / radius
= 23^2 / 600
= 0.8817 m/s^2
The centrifugal force in turn = mass * acceleration
= 1300 * 0.8817
= 1146.17 N
This force is absorbed by suspension springs of the four wheels.
Given spring constant of 4.6 x 10^4 N/m and 4 springs total,
the extra compression = Force / number of springs / spring constant
= 1146.17 / 4 / 4.6 x 10^4
= 0.006229 m
= 6.23 mm
Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.
A boy and a girl are pulling a heavy crate at the same time with 7 units of firce each. What is the net force acts on the ibject? Is the object balanced or unbalanced?
Answers
Answer:
Net force= 14 units
The object is unbalanced
Explanation:
The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.
This means that the force is in the same direction, hence, the net force will be:
F(N) = 7 + 7 = 14 unit
However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED
7. A 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. If the coefficient of kinetic friction is .23, find (A) The normal force exerted on it by the floor. (2 pts) (B) The acceleration on of the block (2 pts)
Answers
Answer:
A.) 17.04 N
B.) 10.76 m/s^2
Explanation:
Given that a 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. If the coefficient of kinetic friction is .23,
A.) To find the normal force exerted on it by the floor, we need to first calculate the vertical forces of the ropes.
The vertical force on F1 = 13 sin 30
F1 = -6.5 N
The vertical force on F2 = 11 sin 21
F2 = 3.94
The resultant force = - 6.5 + 3.94
Resultant force = - 2.56
The normal force = mg - 2.56
The normal force = 2 × 9.8 - 2.56
The normal force = 19.6 - 2.56
The normal force = 17.04 N
(B) The acceleration on of the block will be achieved by first calculating the horizontal force.
For F1 = 13Cos 30
F1 = 11.26N
For F2 = 11 cos 21
F2 = 10.27
the resultant force = 11.26 + 10.27
Horizontal force = 21.53N
Force = mass × acceleration
21.53 = 2 × a
a = 21.53 / 2
Acceleration a = 10.76 m/s^2
What is the final velocity of a running back that is moving with an initial velocity of 2 m/s and accelerates at a rate of 4 m/s$$ in 5 seconds as he moves toward the defensive line?
Answers
Answer:
Final velocity = 22
Explanation:
22-2/5= 4
20/5=4
so add to so it is not 18/5
Then you get your answer.
Answer:
4. A sound wave moves towards a building at 5 m/s for 22 seconds.
Explanation:
A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis
ball moving 22 m/s to the left. After the collision, the tennis ball is moving
32.7 m/s to the right. What is the velocity of the basketball after the collision?
Assume an elastic collision occurred.
A. 10.9 m/s to the right
B. 10.9 m/s to the left
C.3.6 m/s to the left
D. 3.6 m/s to the right
Answers
Answer:b
Explanation:
The final velocity of the basketball after it undergoes collision with the tennis ball is 6.49m/s.
What is Final velocity?The final velocity is a vector quantity which measures the speed and direction of a moving object after it has reached its maximum acceleration and distance.
Given data,
mass of basket ball (m₁) = 0.6kg
mass of tennis ball (m₂) = 0.04kg
velocity of basket ball (v₁) = 7.2m/s
velocity of tennis ball (v₂) = 22m/s
velocity of basket ball (v₃) =?
velocity of tennis ball (v₄) = 32.7m/s
We already know that the expression for elastic collision is given as
m₁v₁ +m₂v₂ = m₁v₃ + m₂v₄
Substituting these values, we get
0.6 × 7.2 + 0.04 × 22 = 0.6 × x + 0.04 × 32.7
4.32 + 0.88 = 0.6x + 1.308
Solving for x we have,
3.892 = 0.6x
x = 3.892 /0.6
x=6.49m/s
Therefore, the velocity of the basketball after the collision is 6.49m/s.
Learn more about Collision here:
https://brainly.com/question/13138178
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A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal and vertical components of the applied force?
Answers
Answer:
Fx = 32.14 [N]
Fy = 38.3 [N]
Explanation:
To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.
F = 50 [N]
Fx = 50*cos(50) = 32.14 [N]
Fy = 50*sin(50) = 38.3 [N]
We can verify this result using the Pythagorean theorem.
[tex]F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N][/tex]
An archer shoots an arrow with vertical velocity of 10 m/s and horizontal velocity of
30m/s. What is the maximum height the arrow reaches?
Answers
Answer:
5.1 m
Explanation:
Given in the y direction:
v₀ = 10 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (10 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 5.1 m
My question is on the picture
Answers
Answer:
Measure change in temperature after long call
Explanation:
The diagram below represents an electromagnetic wave. Please Help
Answers
Answer:
I'm pretty sure it's A
Explanation:
bc the crest is is the point on the wave
A mountain biker is climbing a steep 20° slope at a constant speed. The cyclist and bike have a combined weight of 800 N. What can you say about the magnitude of the normal force of the ground on the bike?
Answers
Answer:
Normal force = 751.75 N
Explanation:
It is given that,
The combined weight of the cyclist and the bike is 800 N
We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :
[tex]N=mg\cos\theta[/tex]
mg = W, combined weight of cyclist and bike
[tex]N=W\cos\theta\\\\N=800\times \cos(20)\\\\N=751.75\ N[/tex]
So, the magnitude of the normal force of the ground on the bike is 751.75 N.
The magnitude of the normal force of the ground on the bike is 751.752 N
The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:
[tex]N= Fcos \theta[/tex]
F is the combined weight
[tex]\theta[/tex] is the angle of inclination
Given the following paramters
F = 800 N
[tex]\theta[/tex] = 20 degrees
Substitute the given parameters into the formula:
[tex]N=800 \times cos20^0\\N=800 \times 0.9397\\N=751.752N[/tex]
Hence the magnitude of the normal force of the ground on the bike is 751.752 N
Learn more here: https://brainly.com/question/12408868