heating curve shows temperature verses energy gain. Which parts of the curve represent a gain in potential energy?
100
Temperature (°C)
0
Increasing Energy

Answer:

Federal law is a law that may protect people from digital attacks such as cyberbullying.

Explanation:

Although it is mostly based on the situation, federal law does protect those who suffer from cyberbullying. The attackers may be charged with defamation, since cyberbullying consists of spreading false information about someone on the internet, that's when the law comes in.

Answer:

Easy my dude let me help you out

A.In

B.27

C.73

D.49

E.56

F.56

G.114

H.180

Also with protons and electrons they equal the same atomic number

Answer:

300m/s is the average molecular speed of Ne

Explanation:

Based on Graham's law, the ratio of speed of two gases under constant temperature is equal to the square root of the inverse of their molar masses. The equation is:

v1 / v2 = √m2 / √m1

Where v is the speed of the gas and m the molar mass of the gas

Assuming gas 1 is Argon and gas 2 is Neon:

v1 = 213m/s

v2 = ?

m2 = 20.18g/mol

m1 = 39.948g/mol

213m/s / v2 = √20.18g/mol / √39.948g/mol

v2 = 213m/s / 0.71074

v2 = 300m/s is the average molecular speed of Ne

Answer:

Both reactions are acid-base reactions

Explanation:

An acid base reaction is a reaction that occurs between an acid and a base. This reaction often leads to the formation of a salt in the process. The nature of the salt depends on the type of acid and base that reacted in the process.

Both HNO3 and H2SO4 are strong acids. However, ammonia is a weak base. The acid base reaction between ammonia and these strong acids is shown below;

HNO3(aq) + NH3(aq) ------>NH4NO3(aq)

H2SO4(aq) + 2NH3(aq) ----> (NH4)2SO4(aq)

Answer:

Electrolysis of water is the process of using electricity to decompose water into oxygen and hydrogen gas. Hydrogen gas released in this way can be used as hydrogen fuel, or remixed with the oxygen to create oxyhydrogen gas, which is used in welding and other applications.Ordinarily, the freezing point of water and melting point is 0 °C or 32 °F. The temperature may be lower if supercooling occurs or if there are impurities present in the water which could cause freezing point depression to occur. Under certain conditions, water may remain a liquid as cold as -40 to -42°

Explanation:

Answer:

compound light microscope

Answer:

0.1 M NaOH, 3 M NH3, 0.01 M CH3COOH, 0.01 M H2SO4, 0.1 M HCl

Explanation:

Strong acids are more acids than weak acids. In the same way, strong bases are more basic than weak bases that are in the same concentration.

Then, the more concentrated acid or base will be more acidic or basic.

CH3COOH. Weak acid

NaOH. Strong base

H2SO4. Strong acid

NH3. Weak base.

HCl. Strong acid

The less acid (More basic):

Strong base, weak base, weak acid, diluted strong acid, undiluted strong acid

Answer:

Assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid is 0.133 M.

Note: The volume of NaOH used isnot given and issp to be determined by titration.

Explanation:

The question is a lab activity. Therefore, the volume of 0.2 M NaOH required for the neutralization of 30.0 mL of hydrochloric acid of unknown concentration is to be determined from titration. However, assuming a certain volume of the base is used for the complete neutralization of the acid, the concentration of the acid can be calculated.

Assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid can be calculated thus:

Step 1: Balanced chemical equation of reaction:

HCl + NaOH ---> NaCl + H₂O

From the equation of the reaction, 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl and water.

Step 2: Determine the number of moles of NaOH in 20.0 mL of 0.200 M solution

Molarity = number of moles/volume in Litres

Number of moles = molarity × volume in litres

Volume of NaOH in litres = 20 ml × 1 litre/1000ml = 0.02 litres

Number of moles NaOH = 0.02 L × 0.2 M = 0.004 moles

Therefore, 0.00 M of NaOH reacted with 0.004 moles of HCl

Step 3: Determine concentration of HCl

Molarity or concentration = number of moles / volume in litres

Number of moles of HCl = 0.004 moles

Volume of HCl in litres = 30.0 mL × 1 L/1000 mL = 0.03 L

Concentration of HCl = 0.004 moles / 0.03 L = 0.133 M

Therefore, assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid is 0.133 M.

Answer:

[tex][Cl_2]=[Br_2]=0.856M[/tex]

[tex][BrCl]=0.229M[/tex]

Explanation:

Hello there!

In this case, for this chemical equilibrium problem, it turns out possible for us to solve for the equilibrium concentrations by firstly setting up the equilibrium expression:

[tex]Keq=\frac{[BrCl]^2}{[Cl_2][Br_2]}[/tex]

Thus, by plugging in an ICE chart, in terms of x (reaction extent), we can write:

[tex]7.20=\frac{(2x)^2}{(0.200-x)^2}[/tex]

And could be solved for x as follows:

[tex]\sqrt{7.20} =\sqrt{\frac{(2x)^2}{(0.200-x)^2} } \\\\2.68=\frac{2x}{0.200-x} \\\\x=0.1146M[/tex]

Therefore, the equilibrium concentrations turn out to be:

[tex][Cl_2]=[Br_2]=0.200M-0.1146M=0.856M[/tex]

[tex][BrCl]=2*0.1146M=0.229M[/tex]

Regards!

Answer:

A (True)

Explanation:

Because ibuprofen has a chiral carbon center (carbon bonded to 4 distinct groups of atoms).

This means that a mixture of ibuprofen can rotate plane-polarized light equally in both the clockwise and counterclockwise direction.

Answer:true

Explanation: ibuprofen is commonly used for most pain, aches ect

Answer: hello your question is poorly written below is the complete question

answer:

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Explanation:

Determining the type of orbital in which the lone pair on each N atom will reside.

From the configuration attached below we can determine the type of orbital and they are ;

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Answer:

n-hexane

2-methylpentane

3-methylpentane

2,2-dimethylbutane

2,3-dimethylbutane

Explanation:

There are 5 structural isomers of C6H14.

n-hexane

2-methylpentane

3-methylpentane

2,2-dimethylbutane

2,3-dimethylbutane

Answer:

Answer to number one

Explanation:

Polyethylene terephthalate (PET) is a plastic material used for milk packaging.

Answer:

[tex]pH = - log[H {}^{ + } ] \\ = - log(0.0000067) \\ pH = 5.17[/tex]

Answer:

[tex]1.74molNO_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:

[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]

Regards!

Answer: For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is K = [ H+] [NO2-] / [HNO2].

Explanation:

An expression that depicts the ratio of products and reactants raised to the power of their coefficients at equilibrium is called equilibrium constant.

An equilibrium constant is denoted by the symbol 'K'.

For example, the dissociation of nitrous acid in aqueous solution is as follows.

[tex]HNO_{2} \rightleftharpoons H^{+} + NO^{-}_{2}[/tex]

Hence, its expression for equilibrium constant is as follows.

[tex]K = \frac{[H^{+}][NO^{-}_{2}]}{[HNO_{2}]}[/tex]

Thus, we can conclude that for the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is K = [ H+] [NO2-] / [HNO2].

Answer:

C2H4I2

Explanation:

Viscosity of a fluid has to do with the internal friction between the internal layers of the fluid.

Molecular weight is found to be related to the viscosity of a fluid even though the relationship may not be strictly linear.

However, the greater the molecular weight of a substance, the greater the viscosity of the material.

Since C2H4I2 has the greatest molecular weight (281.86 g/mol), it is also expected to display the greatest viscosity among all the compounds listed in the question.

Answer:

pH = 3.68

Explanation:

We can solve this problem by using Henderson-Hasselbach's equation:

Assuming we have 1 L of the buffer solution then the molar concentrations of formate and formic acid would be:

We now have all required data to calculate the pH:

Answer:

(a) The molality of this solution is 0.0613[tex]\frac{moles}{kg}[/tex]

(b)The molality of this solution is 2.04[tex]\frac{moles}{kg}[/tex]

Explanation:

The molality (m) of a solution is defined as the number of moles of solute present per kg of solvent.

The Molality of a solution is determined by the expression:

[tex]Molality=\frac{number of moles of solute}{kilograms of solvent}[/tex]

Molality is expressed in units [tex]\frac{moles}{kg}[/tex]

(a) You have 14.3 g of sucrose (C₁₂H₂₂O₁₁), the solute. With the molar mass of sucrose being 342 [tex]\frac{g}{mole}[/tex], then 14.3 grams of the compound represents the following number of moles:

[tex]14.3 grams*\frac{1 mole}{342 grams} =[/tex] 0.042 moles

Having 685 g= 0.685 kg (being 1000 g= 1 kg) of water, the solvent, molality can be calculated as:

[tex]molality=\frac{0.042 moles}{0.685 kg}[/tex]

Solving:

molality= 0.0613[tex]\frac{moles}{kg}[/tex]

The molality of this solution is 0.0613[tex]\frac{moles}{kg}[/tex]

(b) In this case you have 7.15 moles of ethylene glycol (C₂H₆O₂), the solute, in 3505 g (equal to 3.505 kg) of water, the solvent, molality can be calculated as:

[tex]molality=\frac{7.15 moles}{3.505 kg}[/tex]

Solving:

molality= 2.04[tex]\frac{moles}{kg}[/tex]

The molality of this solution is 2.04[tex]\frac{moles}{kg}[/tex]

Answer:

[tex]x = 2[/tex]

Explanation:

General formula for alkanes

[tex]C _{n}H _{2n + 2}[/tex]

since H = 6

[tex]2n + 2 = 6 \\ 2n = 4 \\ n = 2 \\ since \: x = n\\ \therefore \: x = 2[/tex]

Answer:

x=2

Explanation:

Because alkanes have a general formula of CnH(2n+2).

We known that 2n+2=6, so we solve for n.

2n+2=6

2n=4

n=2

Thus, there are 2 carbon atoms.

Answer:

Atmospheric water generator is used in regions that have scarcity of water or have polluted water. These generators are reliable sources of clean and safe water and hence reduces dependency on bottled water.

Atmospheric water generator extract water from the air (humid air) through condensation. Extracted water then cools down to temperature below its dew point  thereby producing potable drinking water.

Explanation:

Atmospheric water generator is used in regions that have scarcity of water or have polluted water. These generators are reliable sources of clean and safe water and hence reduces dependency on bottled water.

Atmospheric water generator extract water from the air (humid air) through condensation. Extracted water then cools down to temperature below its dew point  thereby producing potable drinking water.

Answer:

A device that collects water from humid ambient air is known as an atmospheric water generator. Condensation is the process of extracting water vapor from the air by chilling it below its dew point, exposing it to desiccants, or pressurizing it. An AWG, unlike a dehumidifier, is meant to make the water drinkable. Because there is nearly always a little amount of water in the air that may be collected, AWGs are useful in situations where clean drinking water is difficult or impossible to get. Cooling and desiccants are the two most common ways used.

Explanation:

Answer:

The cation affects the intensity of the color more than the color of the solution.

Explanation:

According to Beer Lambert law, the intensity of the colour of the solution depends on the concentration of the specie responsible for the colour in the solution.

Let us recall that transition metal compounds are coloured in solution due to electronic transitions.

Therefore, the cation affects the intensity of the color more than the color of the solution.

Answer:

B. There is a very large percentage of C-12.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.

In such a way, the answer will be B. There is a very large percentage of C-12.

Regards!

Answer:

the melting process begins right away because the air temperature around the ice cubes is warmer than the temperature in the freezer

A colloid is a mixture in which one substance of microscopically dispersed insoluble particles are suspended throughout another substance. However, some definitions specify that the particles must be dispersed in a liquid, and others extend the definition to include substances like aerosols and gels.

The types of colloids includes sol, emulsion, foam, and aerosol.

Explanation:

everything can be found in the picture

Answer:

5.81 moles

Explanation:

To find the number of moles (n) in 3.5 x 10²⁴ molecules of methane gas, we divide the number of molecules by Avagadro's number (nA). That is,

n = number of molecules ÷ 6.02 × 10²³

According to this question, 3.5 x 10^24 molecules of methane gas was given, hence,

n = 3.5 × 10²⁴ ÷ 6.02 × 10²³

n = 3.5/6.02 × 10(24 - 23)

n = 0.5814 × 10¹

n = 5.81 moles

Answer:

A. Mass of KMnO₄ = 316.08 g

B. Mass of KMnO₄ = 41.49 g

C. Mass of KMnO₄ = 0.13 g.

Explanation:

A. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 1 L

Molarity = 2 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 2 × 1

Mole of KMnO₄ = 2 moles

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 2 moles

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 2 × 158.04

Mass of KMnO₄ = 316.08 g

B. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 350 mL = 350/1000 = 0.35 L

Molarity = 0.75 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 0.75 × 0.35

Mole of KMnO₄ = 0.2625 mole

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 0.2625 mole

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 0.2625 × 158.04

Mass of KMnO₄ = 41.49 g

C. Determination of the mass of KMnO₄

We'll begin by determining the number of mole of KMnO₄ in the solution. This can be obtained as follow:

Volume = 80 mL = 80/1000 = 0.08 L

Molarity = 0.01 M

Mole of KMnO₄ =?

Mole = Molarity × Volume

Mole of KMnO₄ = 0.01 × 0.08

Mole of KMnO₄ = 0.0008 mole

Finally, we shall determine the mass of KMnO₄. This can be obtained as follow:

Mole of KMnO₄ = 0.0008 mole

Molar mass of KMnO₄ = 158.04 g/mole

Mass of KMnO₄ =?

Mass = mole × molar mass

Mass of KMnO₄ = 0.0008 × 158.04

Mass of KMnO₄ = 0.13 g